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  • Two '==' equality operators in same 'if' condition are not working as intended.

    - by Manav MN
    I am trying to establish equality of three equal variables, but the following code is not printing the obvious true answer which it should print. Can someone explain, how the compiler is parsing the given if condition internally? #include<stdio.h> int main() { int i = 123, j = 123, k = 123; if ( i == j == k) printf("Equal\n"); else printf("NOT Equal\n"); return 0; } Output: manav@workstation:~$ gcc -Wall -pedantic calc.c calc.c: In function ‘main’: calc.c:5: warning: suggest parentheses around comparison in operand of ‘==’ manav@workstation:~$ ./a.out NOT Equal manav@workstation:~$ EDIT: Going by the answers given below, is the following statement okay to check above equality? if ( (i==j) == (j==k))

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  • Changing Base Path In PHP

    - by Joshua
    I need to change the folder that "relative include paths" are based on. I might currently be "in" this folder: C:\ABC\XYZ\123\ZZZ And in this case, the path "../../Source/SomeCode.php" would actually be in this folder: C:\ABC\XYZ\Source And realpath('.') would = 'C:\ABC\XYZ\123\ZZZ'; If however, realpath('.') were "C:\Some\Other\Folder" Then in this case, the path "../../Source/SomeCode.php" would actually be in this folder: C:\Some\Source How do I change what folder is represented by '.' in realpath()? Like this: echo ('BEFORE = '.realpath('.')); // BEFORE = C:\ABC\XYZ\123\ZZZ // Some PHP code here... echo ('AFTER = '.realpath('.')); // AFTER = C:\Some\Other\Folder How can I change the folder represented by '.', as seen by realpath()?

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  • How do I use a ListProperty(users.user) in a djangoforms.ModelForm on Google AppEngine?

    - by Gabriel
    I have been looking around a bit for info on how to do this. Essentially I have a Model: class SharableUserAsset(db.Model): name = StringProperty() users = ListProperty(users.User) My questions are: What is the best way to associate users to this value where they are not authenticated, visa vi invite from contacts list etc.? Is there a reasonable way to present a list control easily in a djangoforms.ModelForm? Once a user logs in I want to be able to check if that user is in the list for any number of SharableUserAsset class "records", how do I do that? Does user evaluate as a match to an email address or is there a way to look up a valid user against an email address?

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  • Handling data update/freshness issue in web-app in general (or GWT specifically)

    - by edwin.nathaniel
    In general, how do you guys handle user update/data freshness interaction with the user (UI issue) in web-apps? For example: Multi-users web-app (like project management) Login to a "virtual" space People can update project names, etc How to handle a situation such that: user-A and user-B load a project with title "Project StackOverflow" user-B updates the title to "Project StackExchange" user-A updates the title after user-B update operation to "Project Basecamp" The question I'm asking is from the user perspective (UI) and not about transactional operation. What do most people do in this situation? What would you do after user-B updates the title in user-A screen/view? What happened when user-A tries to update the title after user-B finished his/her update operation? do you inform user-A that the title has changed and he/she has to reload the page? do you go ahead and change the title and let user-B has old data? Do you do some sort of application-level "locking" mechanism? (if someone is updating, nobody else can?) Or fix the application workflow? (who has the access to be able to change things, etc). What would be the simplest solution, but at the same time not annoy the user with more dialog/warning messages. I've encountered this particular problem frequently in a GWT app specifically where domain models are being passed around and refreshing the whole app/client-side isn't the optimal solution in my mind (since it means the whole "loading"/initialization phase must be executed again in this specific environment). Maybe the answer is to stay away from GWT? :) Love to hear options, solutions, and advises from you guys. Thanks

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  • backbone.js Model.get() returns undefined, scope using coffeescript + coffee toaster?

    - by benipsen
    I'm writing an app using coffeescript with coffee toaster (an awesome NPM module for stitching) that builds my app.js file. Lots of my application classes and templates require info about the current user so I have an instance of class User (extends Backbone.Model) stored as a property of my main Application class (extends Backbone.Router). As part of the initialization routine I grab the user from the server (which takes care of authentication, roles, account switching etc.). Here's that coffeescript: @user = new models.User @user.fetch() console.log(@user) console.log(@user.get('email')) The first logging statement outputs the correct Backbone.Model attributes object in the console just as it should: User _changing: false _escapedAttributes: Object _pending: Object _previousAttributes: Object _silent: Object attributes: Object account: Object created_on: "1983-12-13 00:00:00" email: "[email protected]" icon: "0" id: "1" last_login: "2012-06-07 02:31:38" name: "Ben Ipsen" roles: Object __proto__: Object changed: Object cid: "c0" id: "1" __proto__: ctor app.js:228 However, the second returns undefined despite the model attributes clearly being there in the console when logged. And just to make things even more interesting, typing "window.app.user.get('email')" into the console manually returns the expected value of "[email protected]"... ? Just for reference, here's how the initialize method compiles into my app.js file: Application.prototype.initialize = function() { var isMobile; isMobile = navigator.userAgent.match(/(iPhone|iPod|iPad|Android|BlackBerry)/); this.helpers = new views.DOMHelpers().initialize().setup_viewport(isMobile); this.user = new models.User(); this.user.fetch(); console.log(this.user); console.log(this.user.get('email')); return this; }; I initialize the Application controller in my static HTML like so: jQuery(document).ready(function(){ window.app = new controllers.Application(); }); Suggestions please and thank you!

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  • "Attach or Add an entity that is not new...loaded from another DataContext. This is not supported."

    - by sah302
    Similar error as other questions, but not quite the same, I am not trying to attach anything. What I am trying to do is insert a new row into a linking table, specifically UserAccomplishment. Relations are set in LINQ to User and Accomplishment Tables. I have a generic insert function: Public Function insertRow(ByVal entity As ImplementationType) As Boolean If entity IsNot Nothing Then Dim lcfdatacontext As New LCFDataContext() Try lcfdatacontext.GetTable(Of ImplementationType)().InsertOnSubmit(entity) lcfdatacontext.SubmitChanges() lcfdatacontext.Dispose() Return True Catch ex As Exception Return False End Try Else Return False End If End Function If you try and give UserAccomplishment the two appropriate objects this will naturally crap out if either the User or Accomplishment already exist. It only works when both user and accomplishment don't exist. I expected this behavior. What does work is simply giving the userAccomplishment object a user.id and accomplishment.id and populating the rest of the fields. This works but is kind of awkward to use in my app, it would be much easier to simply pass in both objects and have it work out what already exists and what doesn't. Okay so I made the following (please ignore the fact that this is horribly inefficient because I know it is): Public Class UserAccomplishmentDao Inherits EntityDao(Of UserAccomplishment) Public Function insertLinkerObjectRow(ByVal userAccomplishment As UserAccomplishment) Dim insertSuccess As Boolean = False If Not userAccomplishment Is Nothing Then Dim userDao As New UserDao() Dim accomplishmentDao As New AccomplishmentDao() Dim user As New User() Dim accomplishment As New Accomplishment() 'see if either object already exists in db' user = userDao.getOneByValueOfProperty("Id", userAccomplishment.User.Id) accomplishment = accomplishmentDao.getOneByValueOfProperty("Id", userAccomplishment.Accomplishment.Id) If user Is Nothing And accomplishment Is Nothing Then 'neither the user or the accomplishment exist, both are new so insert them both, typical insert' insertSuccess = Me.insertRow(userAccomplishment) ElseIf user Is Nothing And Not accomplishment Is Nothing Then 'user is new, accomplishment is not new, so just insert the user, and the relation in userAccomplishment' Dim userWithExistingAccomplishment As New UserAccomplishment(userAccomplishment.User, userAccomplishment.Accomplishment.Id, userAccomplishment.LastUpdatedBy) insertSuccess = Me.insertRow(userWithExistingAccomplishment) ElseIf Not user Is Nothing And accomplishment Is Nothing Then 'user is not new, accomplishment is new, so just insert the accomplishment, and the relation in userAccomplishment' Dim existingUserWithAccomplishment As New UserAccomplishment(userAccomplishment.UserId, userAccomplishment.Accomplishment, userAccomplishment.LastUpdatedBy) insertSuccess = Me.insertRow(existingUserWithAccomplishment) Else 'both are not new, just add the relation' Dim userAccomplishmentBothExist As New UserAccomplishment(userAccomplishment.User.Id, userAccomplishment.Accomplishment.Id, userAccomplishment.LastUpdatedBy) insertSuccess = Me.insertRow(userAccomplishmentBothExist) End If End If Return insertSuccess End Function End Class Alright, here I basically check if the supplied user and accomplishment already exists in the db, and if so call an appropriate constructor that will leave whatever already exists empty, but supply the rest of the information so the insert can succeed. However, upon trying an insert: Dim result As Boolean = Me.userAccomplishmentDao.insertLinkerObjectRow(userAccomplishment) In which the user already exists, but the accomplishment does not (the 99% typical scenario) I get the error: "An attempt has been made to Attach or Add an entity that is not new, perhaps having been loaded from another DataContext. This is not supported." I have debugged this multiple times now and am not sure why this is occuring, if either User or Accomplishment exist, I am not including it in the final object to try to insert. So nothing appears to be attempted to be added. Even in debug, upon insert, the object was set to empty. So the accomplishment is new and the user is empty. 1) Why is it still saying that and how can I fix it ..using my current structure 2) Pre-emptive 'use repository pattern answers' - I know this way kind of sucks in general and I should be using the repository pattern. However, I can't use that in the current project because I don't have time to refactor that due to my non existence knowledge of it and time constraints. The usage of the app is going to so small that the inefficient use of datacontext's and what have you won't matter so much. I can refactor it once it's up and running, but for now I just need to 'push through' with my current structure. Edit: I also just tested this when having both already exists, and only insert each object's IDs into the table, that works. So I guess I could manually insert whichever object doesn't exist as a single insert, then put the ids only into the linking table, but I still don't know why when one object exists, and I make it empty, it doens't work.

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  • What are potential reasons a user could be connected to a home network, but not to the internet?

    - by Matthew
    I have a friend that recently started using Ubuntu, and I've been answering his questions via the internet. However, I'm stuck on this one. He bought Linksys WPC11 wireless card, and says he was able to create a network connection, but was unable to ping or use a browser. I'm not quite sure where to start in figuring this out--what are some common causes of this sort of problem?

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  • Ubuntu - Automatically mount external drives to /media/LABEL on boot without a user logged in?

    - by endolith
    This question is similar, but kind of the opposite of what I want. I want external USB drives to be mounted automatically at boot, without anyone logged in, to locations like /media/<label>. I don't want to have to enter all the data into fstab, partially because it's tedious and annoying, but mostly because I can't predict what I'll be plugging into it or how the partitions will change in the future. I want the drives to be accessible to things like MPD, and available when I log in with SSH. gnome-mount seems to only mount things when you are locally logged into a Gnome graphical session.

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  • Can I stop the page from 'scrolling' back to the top when a user clicks on a tab (with Rails not Jav

    - by Jake
    Ive built a webpage with 'tabs' using rails. When a user clicks a tab, a new page loads. I want to format it so the tabs are always in the same place on the page as a user clicks them. This happens as long as the user has not scrolled down on the page. If a user has scrolled down, clicking on the tab will refresh the page and it is no longer scrolled down - which make clicking the tabs look bad. Is there a way to keep the spot on the page where the user has scrolled down, without using Javascript? If it must be done with Javascript, any suggestions? T

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  • How to rename dir under Mac (10.6.4) via super user?

    - by user56990
    This is my dir list on my NFS: macbook-pro-andrey-k:Download Andrey$ ls 1289816143_PL_t1181913 1289816171_PL_t1183807 1290117075_BFD_DVD02(Drums) I can't delete "1290117075_BFD_DVD02(Drums)" using sudo rm -Rf 1290117075_BFD_DVD02(Drums) because I get error message -bash: syntax error near unexpected token `(' Hlp plz, how can I either rename the dir so that the error message would not show up or delete the dir right away omitting rename procedure? Thank you.

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  • Dynamic table design (common lookup table), need a nice query to get the values

    - by Swoosh
    sql2005 This is my simplified example: (in reality there are 40+ tables in here, I only showed 2) I got a table called tb_modules, with 3 columns (id, description, tablename as varchar): 1, UserType, tb_usertype 2, Religion, tb_religion (Last column is actually the name of a different table) I got an other table that looks like this: tb_value (columns:id, tb_modules_ID, usertype_OR_religion_ID) values: 1111, 1, 45 1112, 1, 55 1113, 2, 123 1114, 2, 234 so, I mean 45, 55, 123, 234 are usertype OR religion ID's (45, 55 usertype, 123, 234 religion ID`s) Don't judge, I didn't design the database Question How can I make a select, showing * from tb_value, plus one column That one column would be TITLE from the tb_usertype or RELIGIONNAME from the tb_religion table I would like to make a general thing. Was thinking initially about maybe a SQL function that returns a string, but I think I would need dynamic SQL, which is not ok in a function. Anyone a better idea ?

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  • Knowledge and user generated content management system to track files, research, proposals, etc.?

    - by Eshwar
    I'll try keep it short. Here's the scenario: We have employees all over the world performing similar work i.e. research, generating powerpoint slides, word documents, graphics, etc. Many times a lot of this previous work can be reused for another future project. The current arrangement is email and phone calls which as you would agree is quick if you know where to look but otherwise archaic and very very inefficient. So I am looking for software that will allow me to do the following: Tag files e.g. an investor presentation on cellphone usage in kenya would be tagged investor, cellphone, kenya Manage references e.g. if we read something on the internet, should be able to paste that link in some fashion and tag it as above. Preferably cloud based so that it can be accessed by anybody and additionally would be nice (though NOT must) to have access levels (director, manager, everyone) A nice interface that non technically savvy folks can warm up to ;) A desktop app would be handy so that people don't always have to click upload or something A tree based system is inefficient in this case because content is usually linked across branches and also people might not quite agree on one format of a tree. Tagging works around this very nicely. What I have considered so far: Evernote (for its more professional look) Springpad (for its versatility with content) Mendeley (this is a research manager and in some ways ideal, but i fear its limited to PDFs) The goal is that when somebody wants to look for a document, they don't have to ask a colleague, they can just search with keywords and all relevant information shows up. Thanks!

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  • How do you deal with duplicate street suffixes?

    - by Matt
    I have a system where users need to enter addresses. I am trying to limit duplicates of course and something I started noticing was becoming a big problem was some users putting in "Road" and others "Rd", therefore duplicates were creeping in. I looked up the list of USPS street suffix abbreviations but I still have a question which I can't find an answer to. Can I replace all words in a street address with the USPS standard abbreviation? An example would be "123 Forest Hill Road". If I were to replace it with the abbreviations it would then be "123 Frst Hl Rd" or does the "street suffix" that USPS is referring to mean they only want you to make go as far as "123 Forest Hill Rd"?

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  • Is there any user-friendly way to deliver an In-app purchase subscription to multiple devices?

    - by mkvakin
    Hi everybody, Apple requires an in-app purchase subscription purchased on one device to be available on all devices associated with the user: “...subscriptions must be provided on all devices associated with a user. In App Purchase expects subscriptions to be delivered through an external server that you will provide. You must provide infrastructure to deliver subscriptions to multiple devices.” Is there any way to propagate a subscription to another device transparently without user having to create a server side user account and log in each time he needs to enable the subscription on another device? E.g. by reading a username from some kind of API and using it as a key on a server to store information about subscriptions. I tried to find an API for retrieving user account info but couldn't find any.

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  • Is Family Tree Maker 2011 the right upgrade for a FTM 11 user?

    - by bill weaver
    My father has used Family Tree Maker for years, but hasn't upgraded since version 11. It is difficult to tell from reviews at Amazon and other places whether upgrading to FTM 2011 is a good choice. File incompatibilities and upgrade woes sound like customer service is lacking, and i've read reports of it uploading your data to their database but then trying to sell you a download of data. Looking at the ancestry.com site makes me think it's solely about selling add-ons and upgrades. On the other hand, the feature set seems fairly rich and the software has a pretty strong following. I was able to get Gramps working on my system, but that's not going to work for my dad. Any advice on a good upgrade path?

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  • mysql subquery strangely slow

    - by aviv
    I have a query to select from another sub-query select. While the two queries look almost the same the second query (in this sample) runs much slower: SELECT user.id ,user.first_name -- user.* FROM user WHERE user.id IN (SELECT ref_id FROM education WHERE ref_type='user' AND education.institute_id='58' AND education.institute_type='1' ); This query takes 1.2s Explain on this query results: id select_type table type possible_keys key key_len ref rows Extra 1 PRIMARY user index first_name 152 141192 Using where; Using index 2 DEPENDENT SUBQUERY education index_subquery ref_type,ref_id,institute_id,institute_type,ref_type_2 ref_id 4 func 1 Using where The second query: SELECT -- user.id -- user.first_name user.* FROM user WHERE user.id IN (SELECT ref_id FROM education WHERE ref_type='user' AND education.institute_id='58' AND education.institute_type='1' ); Takes 45sec to run, with explain: id select_type table type possible_keys key key_len ref rows Extra 1 PRIMARY user ALL 141192 Using where 2 DEPENDENT SUBQUERY education index_subquery ref_type,ref_id,institute_id,institute_type,ref_type_2 ref_id 4 func 1 Using where Why is it slower if i query only by index fields? Why both queries scans the full length of the user table? Any ideas how to improve? Thanks.

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  • Creating Dynamic variables from json response

    - by c0mrade
    My JSON response looks like this : {"sample":[{"id":"2","name":"branch name"},{"id":"3","name":"branch name 2"}]} My function looks like this : function getJSONObjects(){ $.getJSON("http://localhost/api/branches", function(data){ $.each(data.sample, function(i,item){ var loc = "branch"; eval("var " + loc + item.id + "=123;"); alert(loc + item.id); }); }); } The idea is to create branch + id object so I can do something with it(create marker on a map), so I tried to assign it any value to see if this was working. I wanted both branch2 and branch3 to alert 123 so I have something to start with. But currently this alerts branch2 and branch3 instead of 123. I have little experience with creating dynamic variables/objects can someone tell me what I'm doing wrong or maybe another approach towards solving this?

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  • SQLAlchemy & Complex Queries

    - by user356594
    I have to implement ACL for an existing application. So I added the a user, group and groupmembers table to the database. I defined a ManyToMany relationship between user and group via the association table groupmembers. In order to protect some ressources of the app (i..e item) I added a additional association table auth_items which should be used as an association table for the ManyToMany relationship between groups/users and the specific item. item has following columns: user_id -- user table group_id -- group table item_id -- item table at least on of user_id and group_id columns are set. So it's possible to define access for a group or for a user to a specific item. I have used the AssociationProxy to define the relationship between users/groups and items. I now want to display all items which the user has access to and I have a really hard time doing that. Following criteria are used: All items which are owned by the user should be shown (item.owner_id = user.id) All public items should be shown (item.access = public) All items which the user has access to should be shown (auth_item.user_id = user.id) All items which the group of the user has access to should be shown. The first two criteria are quite straightforward, but I have a hard time doing the 3rd one. Here is my approach: clause = and_(item.access == 'public') if user is not None: clause = or_(clause,item.owner == user,item.users.contains(user),item.groups.contains(group for group in user.groups)) The third criteria produces an error. item.groups.contains(group for group in user.groups) I am actually not sure if this is a good approach at all. What is the best approach when filtering manytomany relationships? How I can filter a manytomany relationship based on another list/relationship? Btw I am using the latest sqlalchemy (6.0) and elixir version Thanks for any insights.

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  • Property value of a String object in JavaScript

    - by naivists
    As far as I understand, every string is an object in Javascript. Still, it "does not work" as I expect it to be: var a="abc"; //here we get a new string object a.b = 123; //I seem to declare a property "b" of that object alert(a.b); //alerts "undefined" However, if I try to define a string in the "wrong way", everything works as expected var a=new String("abc"); // a.b = 123; alert(a.b); //alerts "123" Why is that so?

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  • User not in the sudoers file. This incident will be reported

    - by Sergiy Byelozyorov
    I need to install a package. For that I need root access. However the system says that I am not in sudoers file. When trying to edit one, it complains alike! How I am supposed to add myself to the sudoers file if I don't have the right to edit one? I have installed this system and only administrator. What can I do? Edit: I have tried visudo already. It requires me to be in sudoers in the first place. amarzaya@linux-debian-gnu:/$ sudo /usr/sbin/visudo We trust you have received the usual lecture from the local System Administrator. It usually boils down to these three things: #1) Respect the privacy of others. #2) Think before you type. #3) With great power comes great responsibility. [sudo] password for amarzaya: amarzaya is not in the sudoers file. This incident will be reported. amarzaya@linux-debian-gnu:/$

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