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  • after assembling jar - No Persistence provider for EntityManager named ....

    - by alabalaa
    im developing a standalone application and it works fine when starting it from my ide(intellij idea), but after creating an uberjar and start the application from it javax.persistence.spi.PersistenceProvider is thrown saying "No Persistence provider for EntityManager named testPU" here is my persistence.xml which is placed under meta-inf directory: <persistence-unit name="testPU" transaction-type="RESOURCE_LOCAL"> <provider>org.hibernate.ejb.HibernatePersistence</provider> <class>test.model.Configuration</class> <properties> <property name="hibernate.connection.username" value="root"/> <property name="hibernate.connection.driver_class" value="com.mysql.jdbc.Driver"/> <property name="hibernate.connection.password" value="root"/> <property name="hibernate.connection.url" value="jdbc:mysql://localhost:3306/test"/> <property name="hibernate.show_sql" value="true"/> <property name="hibernate.dialect" value="org.hibernate.dialect.MySQLInnoDBDialect"/> <property name="hibernate.c3p0.timeout" value="300"/> <property name="hibernate.hbm2ddl.auto" value="update"/> </properties> </persistence-unit> and here is how im creating the entity manager factory: emf = Persistence.createEntityManagerFactory("testPU"); im using maven and tried the assembly plug-in with the default configuration fot it, i dont have much experience with assembling jars and i dont know if im missing something, so if u have any ideas ill be glad to hear them

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  • public class ImageHandler : IHttpHandler

    - by Ken
    cmd.Parameters.AddWithValue("@id", new system.Guid (imageid)); What using System reference would this require? Here is the handler: using System; using System.Collections.Specialized; using System.Web; using System.Web.Configuration; using System.Web.Security; using System.Globalization; using System.Configuration; using System.Data.SqlClient; using System.Data; using System.IO; using System.Web.Profile; using System.Drawing; public class ImageHandler : IHttpHandler { public void ProcessRequest(HttpContext context) { string imageid; if (context.Request.QueryString["id"] != null) imageid = (context.Request.QueryString["id"]); else throw new ArgumentException("No parameter specified"); context.Response.ContentType = "image/jpeg"; Stream strm = ShowProfileImage(imageid.ToString()); byte[] buffer = new byte[8192]; int byteSeq = strm.Read(buffer, 0, 8192); while (byteSeq > 0) { context.Response.OutputStream.Write(buffer, 0, byteSeq); byteSeq = strm.Read(buffer, 0, 8192); } //context.Response.BinaryWrite(buffer); } public Stream ShowProfileImage(String imageid) { string conn = ConfigurationManager.ConnectionStrings["MyConnectionString1"].ConnectionString; SqlConnection connection = new SqlConnection(conn); string sql = "SELECT image FROM Profile WHERE UserId = @id"; SqlCommand cmd = new SqlCommand(sql, connection); cmd.CommandType = CommandType.Text; cmd.Parameters.AddWithValue("@id", new system.Guid (imageid));//Failing Here!!!! connection.Open(); object img = cmd.ExecuteScalar(); try { return new MemoryStream((byte[])img); } catch { return null; } finally { connection.Close(); } } public bool IsReusable { get { return false; } } }

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  • C++ MFC server app with sockets crashes and I cannot find the fault, help!

    - by usermeister
    My program has one dialog and two sockets. Both sockets are derived from CAsyncSocket, one is for listening, other is for receiving data from client. My program crashes when client tries to connect to server application and server needs to initialize receiving socket. This is my MFC dialog class. class CFileTransferServerDlg : public CDialog { ... ListeningSocket ListenSock; ReceivingSocket* RecvSock; void OnAccept(); // called when ListenSock gets connection attempt ... }; This is my derived socket class for receiving data that calls parent dialogs method when event is signaled. class ReceivingSocket : public CAsyncSocket { CFileTransferServerDlg* m_pDlg; // for accessing parent dialogs controls virtual void OnReceive(int nErrorCode); } ReceivingSocket::ReceivingSocket() { } This is dialogs function that handles incoming connection attempt when listening socket gets event notification. This is where the crash happens. void CFileTransferServerDlg::OnAccept() { RecvSock = new ReceivingSocket; /* CRASH */ } OR void CFileTransferServerDlg::OnAccept() { ReceivingSocket* tmpSock = new ReceivingSocket; tmpSock->SetParentDlg(this); CString message; if( ListenSock.Accept(*tmpSock) ) /* CRASH */ { message.LoadStringW(IDS_CLIENT_CONNECTED); m_txtStatus.SetWindowTextW(message); RecvSock = tmpSock; } } My program crashes when I try to create a socket for receiving file sent from client application. OnAccept starts when Listening socket signals incoming connection attempt, but my application then crashes. I've tried running it on another computer and connection attempt was succesful. What could be wrong? Error in debug mode: Unhandled exception at 0x009c30e1 in FileTransferServer.exe: 0xC0000005: Access violation reading location 0xccccce58.

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  • Facebook, Flash and maintaining state

    - by Myk
    So here's the situation: I have a Flash application I'm deploying to facebook as a canvas app. There are various states within this app - different "pages", sort of. I want to be able to share this app with other users using Facebook's baked-in sharing mechanism. However, I want each state to have its own share button. That way when someone clicks Share on page 3 they are actually sharing page 3, not the root of the whole application. Does anyone know if Facebook exposes some mechanism by which this could be possible? It would be as simple as passing a string into the iFrame that holds the canvas app, so I could load it in as a FlashVar and work from there. I'm kind of beating my head against the wall - does this request make sense, and has anyone tackled anything like this before? Thanks!

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  • Faster Insertion of Records into a Table with SQLAlchemy

    - by Kyle Brandt
    I am parsing a log and inserting it into either MySQL or SQLite using SQLAlchemy and Python. Right now I open a connection to the DB, and as I loop over each line, I insert it after it is parsed (This is just one big table right now, not very experienced with SQL). I then close the connection when the loop is done. The summarized code is: log_table = schema.Table('log_table', metadata, schema.Column('id', types.Integer, primary_key=True), schema.Column('time', types.DateTime), schema.Column('ip', types.String(length=15)) .... engine = create_engine(...) metadata.bind = engine connection = engine.connect() .... for line in file_to_parse: m = line_regex.match(line) if m: fields = m.groupdict() pythonified = pythoninfy_log(fields) #Turn them into ints, datatimes, etc if use_sql: ins = log_table.insert(values=pythonified) connection.execute(ins) parsed += 1 My two questions are: Is there a way to speed up the inserts within this basic framework? Maybe have a Queue of inserts and some insertion threads, some sort of bulk inserts, etc? When I used MySQL, for about ~1.2 million records the insert time was 15 minutes. With SQLite, the insert time was a little over an hour. Does that time difference between the db engines seem about right, or does it mean I am doing something very wrong?

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  • NHibernate / multiple sessions and nested objects

    - by bernhardrusch
    We are using NHibernate in a rich client application. It is a pretty open application (the user searches for a dataset or creates a new one, changes the data and saves the data set. We leave the session open, because sometimes we have to lazy load some properties of the object (nested object structure). This means one big problem if we leave the session open, the db (MySQL) closes the connection and we are not able to find this out and it throws an exception (socket communication error) when accessing the database (we are thinking about testing the db connection before accessing the object - but this is not really optimal neither, the other option would be to set back the timeout of the db connection , but this just doesn't seem to well). So - is it possible to reconnect the session to a new database connection ? Another problem is it possible to get an object from one session and then re-attach it to another session ? (I often hear that session.lock should work for this - but this doesn't work so well in our application - so I ended up getting a "fresh" object from the session and copy the data over manually - which is a little bit cumbersome) Any ideas for this ?

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  • facebook meta tag description not updating

    - by wazzz
    3 days ago I updated description within the meta tag of facebook, but change does not reflect when sharing link on facebook. Instead old description still appears. According to Facebook, it scrapes your page every 24 hours to ensure the description (and other share data) are up to date. However, one can manually refresh it by entering the post URL into the Facebook URL Linter I did manually refresh it as well as now waited for 3 days. When i see debugging output from linter, it shows the correct up-to-date description, but old description still shown when sharing a link. How to reproduce: This is our website: https://www.tradeinsports.se/#tis1 (It's in swedish so bear with me please). If you go to above link and click on any of the two available products, and then share on facebook, you can see the difference in description from the one which appears in linter debugging output. Any help would be appreciated.

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  • How to force Share Intent to open a specific app?

    - by AndroidUser99
    I like share intent, it is perfect to open sharing apps with image and text parameters. But now i'm researching the way to force share intent to open a specific app from the list, with the paramters given to the share intent. This is my actual code, it shows the list of sharing apps installed on the phone. Please, can somedone tell me what i should add to the code to force for example official twitter app? and official faccebok app? Intent sharingIntent = new Intent(Intent.ACTION_SEND); Uri screenshotUri = Uri.parse("file:///sdcard/test.jpg"); sharingIntent.setType("image/*"); sharingIntent.putExtra(Intent.EXTRA_TEXT, "body text"); sharingIntent.putExtra(Intent.EXTRA_STREAM, screenshotUri); startActivity(Intent.createChooser(sharingIntent, "Share image using")); Thanks

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  • How can I dial GPRS/EDGE in Win CE

    - by brontes
    Hello all. I am developing application in python on Windows CE which needs connection to the internet (via GPRS/EDGE). When I turn on the device, the internet connection is not active. It becomes active if I open internet explorer. I would like to activate connection in my application. I'm trying to do this with RasDial function over ctypes library, but I can't get it to work. Is this the right way or I should do something else? Below is my current code. The ResDial function keeps returning error 87 – Invalid parameter. I don't know anymore what is wrong with it. I would really appreciate any kind of help. Thanks in advance. encoding: utf-8 import ppygui as gui from ctypes import * import os class MainFrame(gui.CeFrame): def init(self, parent = None): gui.CeFrame.init(self, title=u"Zgodovina dokumentov", menu="Menu") DWORD = c_ulong TCHAR = c_wchar ULONG_PTR = c_ulong class RASDIALPARAMS(Structure): _fields_ = [("dwSize", DWORD), ("szEntryName", TCHAR*21), ("szPhoneNumber", TCHAR*129), ("szCallbackNumber", TCHAR*49), ("szUserName", TCHAR*257), ("szPassword", TCHAR*257), ("szDomain", TCHAR*16), ] try: param = RASDIALPARAMS() param.dwSize = 1462 # also tried 1464 and sizeof(RASDIALPARAMS()). Makes no difference. param.szEntryName = u"My Connection" param.szPhoneNumber = u"0" param.szCallbackNumber = u"0" param.szUserName = u"0" param.szPassword = u"0" param.szDomain = u"0" iNasConn = c_ulong(0) ras = windll.coredll.RasDial(None, None, param, c_ulong(0xFFFFFFFF), c_voidp(self._w32_hWnd), byref(iNasConn)) print ras, repr(iNasConn) #this prints 87 c_ulong(0L) except Exception, e: print "Error" print e if name == 'main': app = gui.Application(MainFrame(None)) # create an application bound to our main frame instance app.run() #launch the app !

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  • Free PHP framework/library for single-sign on / cross domain login

    - by Dennis Cheung
    I am looking for free (non GPL is better) SSO framework/library implementation or code samples. There are many kind of SSO implementation. Sharing cookie, sharing session, one time token, associative accounts, etc, etc. (BTW, any good article compare them?) Is there any keyword I should google and reuse before before I start to implement our own wheel. I know OpenID, but which is too much and it is not our need. We rather keep it KISS. We just want share the credentials of user that could save users from another login form.

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  • TCP/IP RST being sent differently in different browsers.

    - by Brian
    On Mac OS X (10.6), if I start a YouTube video download and pull the Ethernet cable for 5 or so seconds, then plug it back in, I get varying results depending on the browser. With Opera and Chrome, after I plug the cable back in the video continues to load. But with Safari and Firefox, it never does. Using Wireshark to look at the traffic, I found that Opera and Chrome simply ACK the first packet from YouTube after the cable has been plugged back in, but Safari and Firefox set the RST flag (0x4) in the TCP header and no more traffic follows. I can put a HUB in between the machine and the internet connection, the problem goes away and all four browsers continue loading the video when the cable is plugged back into the HUB. Again, looking at the Wireshark logs, it's evident that the machine doesn't see the Mulitcast connection close and there is simply a delay in the packets flowing through. So it seems that if Safari and Firefox sees a Multicast connection close, and then later see data on that same connection, they will send a RST. My question is why? What is the correct course of action, and why are 2/4 browsers doing it one way, while the other 2/4 are doing it another way? Is there somewhere in the code that I can see where this is happening in Firefox, for instance? Thank you very much.

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  • How to "End Task" not "Kill" or "Terminate"?

    - by Luiscencio
    Hi community. I have a 3G card to provide internet to a remote computer... I have to run a program(provided with the card) to establish the connection... since connections suddenly is lost I wrote a script that Kills the program and reopens it so that the connection is reestablished, there are certain versions of this program that don't kill the connection when killed/terminated, just when closed properly. so I am looking for a script or program that "Properly Closes" a window so I can close it and reopen it in case the connection is lost. this is the code that kills the program Option Explicit Dim objWMIService, objProcess, colProcess Dim strComputer, strProcessKill strComputer = "." strProcessKill = "'Telcel3G.exe'" Set objWMIService = GetObject("winmgmts:" _ & "{impersonationLevel=impersonate}!\\" _ & strComputer & "\root\cimv2") Set colProcess = objWMIService.ExecQuery _ ("Select * from Win32_Process Where Name = " & strProcessKill ) For Each objProcess in colProcess objProcess.Terminate() Next WSCript.Echo "Just killed process " & strProcessKill _ & " on " & strComputer WScript.Quit

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  • How to detect time on a playing Flash video

    - by 6bytes
    Hi I have a video playing on my page. I want to show and hide some div's when the video reaches a certain point. Lets say hide something on 10th second and show it again on 20th second. I can easily do it in HTML5 with video tag and currentTime attribute but for IE I have to create the same functionality and I think with flash based videos (from YouTube or something like that). Is there a way to detect the current time of a video playing on my website, embeded from YouTube, Metacafe or any other video sharing site? I know I could detect it in flash and make it run some JavaScript function but I don't have flash nor have the skills to do it in AS3. Is it possible to do it from JavaScript level or does any video sharing website out there provides this kind of functionality for their videos?

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  • Insert not working

    - by user1642318
    I've searched evreywhere and tried all suggestions but still no luck when running the following code. Note that some code is commented out. Thats just me trying different things. SqlConnection connection = new SqlConnection("Data Source=URB900-PC\SQLEXPRESS;Initial Catalog=usersSQL;Integrated Security=True"); string password = PasswordTextBox.Text; string email = EmailTextBox.Text; string firstname = FirstNameTextBox.Text; string lastname = SurnameTextBox.Text; //command.Parameters.AddWithValue("@UserName", username); //command.Parameters.AddWithValue("@Password", password); //command.Parameters.AddWithValue("@Email", email); //command.Parameters.AddWithValue("@FirstName", firstname); //command.Parameters.AddWithValue("@LastName", lastname); command.Parameters.Add("@UserName", SqlDbType.VarChar); command.Parameters["@UserName"].Value = username; command.Parameters.Add("@Password", SqlDbType.VarChar); command.Parameters["@Password"].Value = password; command.Parameters.Add("@Email", SqlDbType.VarChar); command.Parameters["@Email"].Value = email; command.Parameters.Add("@FirstName", SqlDbType.VarChar); command.Parameters["@FirstName"].Value = firstname; command.Parameters.Add("@LasttName", SqlDbType.VarChar); command.Parameters["@LasttName"].Value = lastname; SqlCommand command2 = new SqlCommand("INSERT INTO users (UserName, Password, UserEmail, FirstName, LastName)" + "values (@UserName, @Password, @Email, @FirstName, @LastName)", connection); connection.Open(); command2.ExecuteNonQuery(); //command2.ExecuteScalar(); connection.Close(); When I run this, fill in the textboxes and hit the button I get...... Must declare the scalar variable "@UserName". Any help would be greatly appreciated. Thanks.

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  • How do to check to see if the user has a Google account.

    - by skrat
    Is there any safe way to detect, on a web page, client side (JS), whether user has an Google/Yahoo/Live/? account? I know about some suspicious ways to do this by styling visited links and then sneaking on computed style attribute, but it's more of a hack, Mozilla and maybe other are planning to crack down on this, as it might be abused. But I need this to allow users more integration with their identity providers, like: Have a Google account? ~ load contacts for sharing from Google Contacts API Have an Yahoo account? ~ load contacts for sharing from Yahoo Contacts API none of the above? show no link I don't want to provide all these options to all visitors, would be nice if I can detect the account, and provide integration only in that case.

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  • Java program will read from database, but not write to it

    - by ck1221
    I have a Java program that successfully connects to a mysql database that is hosted on godaddy's server. I can read from that db with out issue, however, when I try to write to it with INSERT or UPDATE for example, the query does not execute. I am using the 'admin' account that I set up through godaddy, I realize this is not the root account. I have checked and verified that the connection is not read only, and have logged out of phpmyadmin while the query ran. I'm not sure what else I can try or if anyone has experienced this issue. Maybe a setting to the connection I have failed to set? Or maybe its not possible since the db is hosted on godaddy's servers? Any help is great! Thanks. Here is some relevant code: Connection to db: Connection con; public DBconnection(String url, String user, String pass) { try { Class.forName("com.mysql.jdbc.Driver").newInstance(); con = DriverManager.getConnection (url,user,pass); if(!con.isClosed()) System.out.println("connecton open"); } catch (InstantiationException e) {e.printStackTrace();} catch (IllegalAccessException e) {e.printStackTrace();} catch (ClassNotFoundException e) {e.printStackTrace();} catch (SQLException e) {e.printStackTrace();} } Send Query: public ResultSet executeQuery(String query) { ResultSet rs = null; try { Statement stmt = (Statement) con.createStatement(); rs = stmt.executeQuery(query); //while(rs.next()) //System.out.println(rs.getString("ticket_num")); } catch (SQLException e) {} return rs; } Insert Query (works in phpmyadmin): conn.executeQuery("INSERT INTO tickets VALUES(55555,'12/01/2012','me','reports','test','','','0','Nope')");

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  • In XHR, is it possible to distinguish network errors from cross-origin errors?

    - by greim
    http://www.w3.org/TR/access-control/ Reading the CORS spec linked above, it seems to be the case that it's impossible to reliably distinguish between a generic "network error" and a cross-origin access denied error. From the spec: If there is a network error Apply the network error steps. Perform a resource sharing check. If it returns fail, apply the network error steps. http://www.w3.org/TR/access-control/#simple-cross-origin-request0 In my testing, I couldn't locate any features of Firefox's implementation that seem to indicate that the resource sharing check definitely failed. It just switches readyState to 4 and sets status to 0. Ultimately I'd like the ability to pass a success callback, a general fail callback, and an optional cross-origin fail callback, to my function. Thanks for any help or insight.

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  • MySQLDB query not returning all rows

    - by RBK
    I am trying to do a simple fetch using MySQLDB in Python. I have 2 tables(Accounts & Products). I have to look up Accounts table, get acc_id from it & query the Products table using it. The Products tables has more than 10 rows. But when I run this code it randomly returns between 0 & 6 rows each time I run it. Here's the code snippet: # Set up connection con = mdb.connect('db.xxxxx.com', 'user', 'password', 'mydb') # Create cursor cur = con.cursor() # Execute query cur.execute("SELECT acc_id FROM Accounts WHERE ext_acc = '%s'" % account_num ) # account_num is alpha-numberic and is got from preceding part of the program # A tuple is returned, so get the 0th item from it acc_id = cur.fetchone()[0] print "account_id = ", acc_id # Close the cursor - I was not sure if I can reuse it cur.close() # Reopen the cursor cur = con.cursor() # Second query cur.execute("SELECT * FROM Products WHERE account_id = %d" % acc_id) keys = cur.fetchall() print cur.rowcount # This prints incorrect row count for key in keys: # Does not print all rows. Tried to directly print keys instead of iterating - same result :( print key # Closing the cursor & connection cur.close() con.close() The weird part is, I tried to step through the code using a debugger(PyDev on Eclipse) and it correctly gets all rows(both the value stored in the variable 'keys' as well as console output are correct). I am sure my DB has correct data since I ran the same SQL on MySQL console & got the correct result. Just to be sure I was not improperly closing the connection, I tried using with con instead of manually closing the connection and it's the same result. I did RTFM but I couldn't find much in it to help me with this issue. Where am I going wrong? Thank you. EDIT: I noticed another weird thing now. In the line cur.execute("SELECT * FROM Products WHERE account_id = %d" % acc_id), I hard-coded the acc_id value, i.e made it cur.execute("SELECT * FROM Products WHERE account_id = %d" % 322) and it returns all rows

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  • How to executing the following command in Android?

    - by Aung Pyae
    I would like to create a new App Linking object for the sharing posts of my android application to facebook sdk. I look around and I found this. My App is "Mobile-Only". So, it seems I supposed to send this command to facebook. How can I send this ? FYI; I have set-up Facebook App and successfully integrated "Sharing Post on Facebook via Android App". Seems I am quite new on Graph API of Facebook SDK. Thanks. curl https://graph.facebook.com/app/app_link_hosts \ -F access_token="APP_ACCESS_TOKEN" \ -F name="Android App Link Object Example" \ -F android=' [ { "url" : "sharesample://story/1234", "package" : "com.facebook.samples.sharesample", "app_name" : "ShareSample", }, ]' \ -F web=' { "should_fallback" : false, }'

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  • How do I ignore an "invalid" SSL certificate in Objective-C?

    - by ipwnstuff
    Currently I have: NSArray* array = [NSArray arrayWithObjects:@"auth.login",@"username",@"password", nil]; NSData* packed_array = [array messagePack]; NSURL* url = [NSURL URLWithString:@"https://192.168.1.149:3790/api/1.0"]; NSMutableURLRequest* request = [NSMutableURLRequest requestWithURL:url]; [request setHTTPMethod:@"POST"]; [request setValue:@"RPC Server" forHTTPHeaderField:@"Host"]; [request setValue:@"binary/message-pack" forHTTPHeaderField:@"Content-Type"]; [request setValue:[NSString stringWithFormat:@"%d",[packed_array length]] forHTTPHeaderField:@"Content-Length"]; [request setHTTPBody:packed_array]; NSURLResponse *response; NSError *error; responseData = [NSMutableData dataWithData:[NSURLConnection sendSynchronousRequest:request returningResponse:&response error:&error]]; NSLog(@"response data: %@",[responseData messagePackParse]); NSLog(@"error: %@",error); - (BOOL)connection:(NSURLConnection *)connection canAuthenticateAgainstProtectionSpace:(NSURLProtectionSpace *)protectionSpace { NSLog(@"called canAuthenticateAgainstProtectionSpace"); return [protectionSpace.authenticationMethod isEqualToString:NSURLAuthenticationMethodServerTrust]; } - (void)connection:(NSURLConnection *)connection didReceiveAuthenticationChallenge:(NSURLAuthenticationChallenge *)challenge { NSLog(@"called didReceiveAuthenticationChallenge"); [challenge.sender useCredential:[NSURLCredential credentialForTrust:challenge.protectionSpace.serverTrust] forAuthenticationChallenge:challenge]; } Which returns "Error Domain=NSURLErrorDomain Code=-1202 "The certificate for this server is invalid"…" How should I be implementing the answer from this question?

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  • PHP transfer files from server to server in LAN

    - by cheapez
    So, I have 5-6 pages of requirements. I'm trying to build this application in PHP based on the requirements. I want to transfer files from one server to the other server in LAN, and then send a shell command to the other server to find out if the file has been transferred successfully. In php, I can transfer files using FTP, and send shell commands using SSH. Using the methods above, I will need to open connection to the server first, but I don't know the ftp server name, domain name, ip address, or anything like that. I only know the the server ID (I'm not sure what this ID is, but I guess it is like the computer's name). An example of the server ID is: "c23bap234" How do I open a connection with just that server ID? These servers are in the same building, have LAN connection, don't have connection to the outside world. These machines have PHP, Apache, ... installed. If my post doesn't make sense to you, it's because I'm a learner. I hope someone can help me on this. Thanks in advance.

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  • Sending an HTTP POST request through the android emulator doesn't work

    - by Sotirios Delimanolis
    I'm running a tomcat servlet on my local machine and an Android emulator with an app that makes a post request to the servlet. The code for the POST is below (without exceptions and the like): String strUrl = "http://10.0.2.2:8080/DeviceDiscoveryServer/server/devices/"; Device device = Device.getUniqueInstance(); urlParameters += URLEncoder.encode("user", "UTF-8") + "=" + URLEncoder.encode(device.getUser(), "UTF-8"); urlParameters += "&" + URLEncoder.encode("port", "UTF-8") + "=" + URLEncoder.encode(new Integer(Device.PORT).toString(), "UTF-8"); urlParameters += "&" + URLEncoder.encode("address", "UTF-8") + "=" + URLEncoder.encode(device.getAddress().getHostAddress(), "UTF-8"); URL url = new URL(strUrl); HttpURLConnection connection = (HttpURLConnection) url.openConnection(); connection.setDoOutput(true); connection.setRequestMethod("POST"); OutputStreamWriter wr = new OutputStreamWriter(connection.getOutputStream()); wr.write(urlParameters); wr.flush(); wr.close(); Whenever this code is executed, the servlet isn't called. However if I change the type of the request to 'GET' and don't write anything to the outputstream, the servlet gets called and everything works fine. Am I just not making the POST correctly or is there some other error?

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  • How to get values from SQL query made by php?

    - by Ole Jak
    So I made a query like this global $connection; $query = "SELECT * FROM streams "; $streams_set = mysql_query($query, $connection); confirm_query($streams_set); in my DB there are filds ID, UID, SID, TIME (all INT type exept time) So I am triing to print query relult into form <form> <select class="multiselect" multiple="multiple" name="SIDs"> <?php global $connection; $query = "SELECT * FROM streams "; $streams_set = mysql_query($query, $connection); confirm_query($streams_set); $streams_count = mysql_num_rows($streams_set); for ($count=1; $count <= $streams_count; $count++) { echo "<option value=\"{$count}\""; echo ">{$count}</option>"; } ?> </select> <br/> <input type="submit" value="Submit Form"/> </form> How to print out as "option" "values" SID's from my sql query?

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  • Transfering data from Excel to dataGridView

    - by Panecillo
    I have a problem when I want to transfer data from Excel to dataGridView in C#. My Excel's column has numeric and alphanumeric values. But for example, if the column has 3 numbers and 2 alphanumeric values then only the numbers are shown in the dataGridView, and vice versa. Why aren't all the values shown? The next is what happen: Excel's Column: DataGridView's Column: 45654 45654 P745K 31233 31233 23111 23111 45X2Y Here is my code to load the dataGridView: string connectionString = @"Provider=Microsoft.Jet.OLEDB.4.0;Data Source=D:\test.xls;Extended Properties=""Excel 8.0;HDR=YES;"""; DbProviderFactory factory = DbProviderFactories.GetFactory("System.Data.OleDb"); DbDataAdapter adapter = factory.CreateDataAdapter(); DbCommand selectCommand = factory.CreateCommand(); selectCommand.CommandText = "SELECT * FROM [sheet1$]"; DbConnection connection = factory.CreateConnection(); connection.ConnectionString = connectionString; selectCommand.Connection = connection; adapter.SelectCommand = selectCommand; data = new DataSet(); adapter.Fill(data); dataGridView1.DataSource = data.Tables[0].DefaultView; I hope I explained it well. Sorry my bad english. Thanks.

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  • why my pagination link doesnt appear ?

    - by udaya
    This is my script which i have used to paginate ,,The datas are restricted to 4 but the pagination link doesn't appear <? require_once ('Pager/Pager.php'); $connection = mysql_connect( "localhost" , "root" , "" ); mysql_select_db( "ssit",$connection); $result=mysql_query("SELECT dFrindName FROM tbl_friendslist", $connection); $row = mysql_fetch_array($result); $totalItems = $row['total']; $pager_options = array( 'mode' => 'Sliding', // Sliding or Jumping mode. See below. 'perPage' => 4, // Total rows to show per page 'delta' => 4, // See below 'totalItems' => $totalItems, ); $pager = Pager::factory($pager_options); echo $pager->links; list($from, $to) = $pager->getOffsetByPageId(); $from = $from - 1; $perPage = $pager_options['perPage']; $result = mysql_query("SELECT * FROM tbl_friendslist LIMIT 5 , $perPage",$connection); while($row = mysql_fetch_array($result)) { echo $row['dFrindName'].'</br>'; } ?>

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