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  • Filtering out unique rows in MySQL

    - by jpatokal
    So I've got a large amount of SQL data that looks basically like this: user | src | dst 1 | 1 | 1 1 | 1 | 1 1 | 1 | 2 1 | 1 | 2 2 | 1 | 1 2 | 1 | 3 I want to filter out pairs of (src,dst) that are unique to one user (even if that user has duplicates), leaving behind only those pairs belonging to more than one user: user | src | dst 1 | 1 | 1 1 | 1 | 1 2 | 1 | 1 In other words, pair (1,2) is unique to user 1 and pair (1,3) to user 2, so they're dropped, leaving behind only all instances of pair (1,1). Any ideas? The answers to the question below can find the non-unique pairs, but my SQL-fu doesn't suffice to handle the complication of requiring that they belong to multiple users as well. [SQL question] How to select non "unique" rows

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  • php array into mysql

    - by mckenzie
    Hello, $sql_where = ''; $exclude = '30,35,36,122,123,124,125'; if($exclude != '') { $exclude_forums = explode(',', $exclude); foreach ($exclude_forums as $id) { if ($id > 0) { $sql_where = ' AND forum_id <> ' . trim($id); } } } $sql = 'SELECT topic_title, forum_id, topic_id, topic_type, topic_last_poster_id, topic_last_poster_name, topic_last_poster_colour, topic_last_post_time FROM ' . TOPICS_TABLE . ' WHERE topic_status <> 2 AND topic_approved = 1 ' . $sql_where . ' ORDER BY topic_time DESC'; The above code i use to exclude the id of forum to be displayed on sql queries. Why doesn't it work and still display it? Any solution

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  • Dynamically Insert Variables into DB Table using PreparedStatement

    - by gran_profaci
    I was working with PreparedStatement today and noticed that it used setString() setTimestamp() etc. to insert variables into the DB. I basically have 20 tables each with at least 15 columns and it would not be feasible for me to manuallt write down all the setters. Considering that I have an ArrayList "Vals" which contains all the variables to be inputted in String format (obtained by getString() using PreparedStatement itself), is there any way I can do an insert without using expressly using the Setters? That would save me a lot of time.

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  • Casting a Calculated Column in a MySQL view.

    - by Chris Brent
    I have a view that contains a calculated column. Is there are a way to cast it as a CHAR or VARCHAR rather than a VARBINARY ? Obviously, I have tried using CAST(... as CHAR) but it gives an error. Here is a simple replicable example. CREATE VIEW view_example AS SELECT concat_ws('_', lpad(9, 3,'0'), lpad(1,3,'0'), date_format(now(),'%Y%m%d%H%i%S')) AS calculated_field_id; This is how my view is created: describe view_example; +---------------------+---------------+------+-----+---------+-------+ | Field | Type | Null | Key | Default | Extra | +---------------------+---------------+------+-----+---------+-------+ | calculated_field_id | varbinary(27) | YES | | NULL | | +---------------------+---------------+------+-----+---------+-------+ select version(); +-----------------------+ | version() | +-----------------------+ | 5.0.51a-community-log | +-----------------------+

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  • mysql query if else statemnet?

    - by user253530
    I have this sql query: SELECT S.SEARCH, S.STATUS, C.TITLE AS CategoryName, E.SEARCH_ENGINES AS Engine, S.RESULTS, S.DATE, S.TOTAL_RESULTS AS Total, S.ID FROM PLD_SEARCHES AS S Join PLD_CATEGORY AS C ON C.ID = S.CATEGORY_ID Join PLD_SEARCH_ENGINES AS E ON S.SEARCH_ENGINES_ID = E.ID ORDER BY S.DATE ASC I want to identify if S.STATUS is either 1 or 0 and according to those values to return COMPLETE or PENDING in the query results

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  • Which mysql construct is faster?

    - by Olaseni
    SELECT ..WHERE COL IN(A,B) or SELECT ... WHERE (COL = A or COL = B) I'm trying to find out what are the differences between the two constructs? Would there be significant performance gains either way if utilized on resultsets that are nearing the 1 million mark?

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  • An array of MySQL results...

    - by Michael Falk
    What am I doing wrong here? I am attempting to return a json object and I can't seem to get past the array... I've built hundreds of regular array and returned them as a json object but I am having a hard time wrapping my head around this one. $rows = array(); $post_array = array(); $i = 0; $result = mysql_query(" SELECT * FROM forum_posts WHERE permalink = '$permalink' AND LOWER(raw_text) LIKE '%$str%' " ); while($row = mysql_fetch_assoc($result)) { $post_array[$i] = $rows[ "id" => htmlentities($row["id"]), "post_content" => htmlentities($row["content"]), "author" => $row["author"], "last_updated" => $row["last_updated"], "author_id" => $row["author_id"], "editing_author" => $row["editing_author"], "date" => $outputQuoteDate ]; $i++; }

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  • mysql update enums

    - by FFish
    I have a field with enums: 'preview','active','closed' When I query like this: $query = "UPDATE albums SET album_active = preview WHERE album_id = 3"; $result = mysql_query($query); if (!$result) die('Invalid query: ' . mysql_error()); I get : Invalid query: Unknown column 'preview' in 'field list

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  • Proper html markup of table tags?

    - by Gazow
    kind of a silly question, but ive been seeing things such as tbody and thead/tfood tags in other peoples tables are these required even if they're empty for good markup? or can i just leave them out? thanks

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  • Preventing entire JOINed MYSQL query from failing when one field is missing within a WHERE clause

    - by filip o
    I am doing a couple of joins with a variable in the WHERE clause. I'm not sure if I am doing everything as efficiently as I could, or even using the best practices but my issue is that half my tables have data for when tableC.type=500, and the other half don't resulting in the entire query failing. SELECT tableA.value1 , tableB.value2, tableC.value3 FROM tableA JOIN tableB ON tableB.id=tableA.id JOIN tableC ON tableC.id=tableB.id WHERE tableA.category=$var && tableC.type=500; What I would like to happen is to still get tableA.value1 and tableB.value2 even if there is no field in tableC with a type=500. any thoughts? i'm totally stumped as how to approach this...

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  • Average of a Sum in Mysql query

    - by chupeman
    I am having some problems creating a query that gives me the average of a sum. I read a few examples here in stackoverflow and couldn't do it. Can anyone help me to understand how to do this please? This is the data I have: Basically I need the average transaction value by cashier. I can't run a basic avg because it will take all rows but each transaction can have multiple rows. At the end I want to have: Cashier| Average| 131 | 44.31 |(Which comes from the sum divided by 3 transactions not 5 rows) 130 | 33.15 | etc. This is the query I have to SUM the transactions but don't know how or where to include the AVG function. SELECT `products`.`Transaction_x0020_Number`, Sum(`products`.`Sales_x0020_Value`) AS `SUM of Sales_x0020_Value`, `products`.`Cashier` FROM `products` GROUP BY `products`.`Transaction_x0020_Number`, `products`.`Date`, `products`.`Cashier` HAVING (`products`.`Date` ={d'2010-06-04'}) Any help is appreciated.

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  • Zend Framework Multiple Table Query

    - by Jeff
    I am looking to execute this statement via Zend Framework. As I understand it, I can use Zend_Db_Select. Is it possible to use Zend_Db_Table? Three tables: classes, students, and class_students select classes.name, students.student_id, students.fname, students.lname from students, classes, class_students where class_students.student_id=students.student_id AND class_students.class_id=classes.class_id;

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  • Retrieving specific tuples using Mysql

    - by Narayanan
    Hi, I have some problems retrieving specific tuples. I am actually a student trying to build a Room management system. I have two tables: Room(roomID,hotelname,rate) and Reservation(resID,arriveDate,departDate,roomID). I am not sure how to retrieve the rooms that are available between 2 specific dates. This was the query that i used. SELECT Room.roomID,hotelname,rate FROM Room LEFT JOIN Reservation on ( Room.roomID=Reservation.resID and arriveDate >='2010-02-16' and departDate <='2010-02-20' ) GROUP BY roomID,hotelname,rate HAVING count(*)=0;' but it returns an empty set. Can any1 be kind enough to tell me what mistake i am doing??

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  • MySQL subquery and bracketing

    - by text
    Here are my tables respondents: field sample value respondentid : 1 age : 2 gender : male survey_questions: id : 1 question : Q1 answer : sample answer answers: respondentid : 1 question : Q1 answer : 1 --id of survey question I want to display all respondents who answered the certain survey, display all answers and total all the answer and group them according to the age bracket. I tried using this query: SELECT res.Age, res.Gender, answer.id, answer.respondentid, SUM(CASE WHEN res.Gender='Male' THEN 1 else 0 END) AS males, SUM(CASE WHEN res.Gender='Female' THEN 1 else 0 END) AS females, CASE WHEN res.Age < 1 THEN 'age1' WHEN res.Age BETWEEN 1 AND 4 THEN 'age2' WHEN res.Age BETWEEN 4 AND 9 THEN 'age3' WHEN res.Age BETWEEN 10 AND 14 THEN 'age4' WHEN res.Age BETWEEN 15 AND 19 THEN 'age5' WHEN res.Age BETWEEN 20 AND 29 THEN 'age6' WHEN res.Age BETWEEN 30 AND 39 THEN 'age7' WHEN res.Age BETWEEN 40 AND 49 THEN 'age8' ELSE 'age9' END AS ageband FROM Respondents AS res INNER JOIN Answers as answer ON answer.respondentid=res.respondentid INNER JOIN Questions as question ON answer.Answer=question.id WHERE answer.Question='Q1' GROUP BY ageband ORDER BY res.Age ASC I was able to get the data but the listing of all answers are not present. Do I have to subquery SELECT into my current SELECT statement to show the answers? I want to produce something like this: ex: # of Respondents is 3 ages: 2,3 and 6 Question: what are your favorite subjects? Ages 1-4: subject 1: 1 subject 2: 2 subject 3: 2 total respondents for ages 1-4 : 2 Ages 5-10: subject 1: 1 subject 2: 1 subject 3: 0 total respondents for ages 5-10 : 1

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  • Can't connect to MySQL database hosted in CloudBees

    - by user3692698
    I have a free CloudBees account and created a free ClearDB database using their wizards. My trouble is when I use their connection information (whether I try to connect from my Java app, or an outside tool - SQLyog to be exact) I take the error: Access denied for user 'b51dbc5757d79f'@'%' to database 'mywiki. The username provided by CloudBees does not contain those extra characters that the error message is displaying which seems like it would be a problem, but I'm not sure there is anything I can do about that since everything is configured for me. The username I am given is: b51dbc5757d79f - which I can delete and rebuild after sharing here :)

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  • mysql twitter/facebook like status feed

    - by barjonah
    Hi, I have two tables. One named status like this... user_id | status --------+----------- 1 | random status from user 1 2 | random status from user 2 3 | random message from user 3 4 | staus from user 4 1 | second status for user1 etc... and another named users_following like this... user_id | is_following --------+----------- 1 | 2 1 | 3 2 | 1 3 | 2 meaning that user 1 is following both users 2 and 3 etc... So, let's say I chose user 1. What is the best query (performance wise) to show the status updates of users that user 1 is following, in this case users 2 and 3 currently I have something like SELECT * from status WHERE user_id IN(SELECT is_following FROM users_following WHERE user_id='1') LIMIT 0,5 but I don't think this is good for performance if a user was following thousands+ of users

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  • How to output items in Order in MySQL?

    - by RailsRor
    I have a column called "menu_order" which has no default value. When I select the contents of this column using the following select statement: SELECT * FROM categories ORDER BY menu_order ASC It lists the category items that have nothing as their menu order first and then the one's that have 1's and 2's and 3's. Is there any way to prevent SQL from take nothing to come before numbers when I am trying to list things in order? So for example, if I have: cat_name | menu_order ---------------------- Lunch | 1 Dinner | And I perform my query, the output should be: Lunch Dinner Not: Dinner Lunch

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  • mysql to xls sheet genration problemI(getting html code along with records ,unable get column names)

    - by pmms
    <?php if($_POST['Submit']=='Generatexml') { $tblname=$_GET['genratexml']; //mysql_connect("localhost","root",""); //mysql_select_db("hitnrunf_db"); global $obj_mysql; $result = mysql_query("SELECT * FROM tbl_js_login"); while($row = mysql_fetch_array($result)) { $csv_output .= "$row[fld_id],$row[fld_fname],$row[fld_lname]"; $csv_output .="\015\012"; } header("Content-type: application/vnd.ms-excel"); header("Content-disposition: csv; filename= Student_Data_". date("Y-m-d") . ".csv"); print $csv_output; exit; } include_once $path."includes/jobseeker_form.php"; ?> In the above we are getting html code along wtih id, firstname, lastname columns. we are unable to get the heading of the columns also How to remove Html code from xls file also need to get headers

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  • MySQL: Order by time (MM:SS)?

    - by Shpigford
    I'm currently storing various metadata about videos and one of those bits of data is the length of a video. So if a video is 10 minutes 35 seconds long, it's saved as "10:35" in the database. But what I'd like to do is retrieve a listing of videos by length (longest first, shortest last). The problem I'm having is that if a video is "2:56", it's coming up as longest because the number 2 is more than the number 1 in. So, how can I order data based on that length field so that "10:35" is recognized as being longer than "2:56" (as per my example)?

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  • MySQL customized join query using multiple tables

    - by itgeek
    I am searching one student from each class from one group. There are different class groups and every group has different classes and every class has multiple students. See below: Group1 --> Class1, Class2 etc Class1 --> GreenStudent1, GreenStudent2 etc Class2 --> RedStudent1, RedStudent2 etc ------------------------------------------------------ SELECT table1.id, table1.myname, table1.marks table2.studentid, table2.studentname FROM table1 INNER JOIN table3 ON table1.oldid = table3.id INNER JOIN table2 ON table2.studentid = table3.newid WHERE table1.classgroup = 'SCI79' GROUP BY table1.oldid ORDER BY table1.marks DESC There are different joins applied in the query. Above mentioned query giving me correct results but I need little modification in it. Current query returning me one student from each class. What I need? I need one student from each class but only that student who has MAXIMUM table1.marks So I should have one student from each class who has maximum number in their relevant classes. Can anyone suggest some solution or rewrite this query? Thanks :)

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  • MySQL count statements error - operand should contain 1 column(s)

    - by jason
    I am trying to do multiple counts everyone was working accept the first sub select (list1) I get an error that reads "Operand should contain 1 column(s)" i'm guessing it has something to do with the AND, but i'm not sure how I would fix this one. Select Count(list0.ustatus) AS finished_count, (Select list1.ustatus, Count(*) From listofupdates list1 Where list1.ustarted != '0000-00-00 00:00:00' AND list1.ustatus != 1) AS start_count, (Select Count(list2.udifficulty) From listofupdates list2 Where list2.udifficulty = 2) AS recheck_count, (Select Count(list3.udifficulty) From listofupdates list3 Where list3.udifficulty = 4) AS question_count From listofupdates list0 Where list0.ustatus = 1

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  • PHP & MySQL Pagination Update Help

    - by TaG
    Its been a while since I updated my pagination on my web page and I'm trying to add First and Last Links to my pagination as well as the ... when the search results are to long. For example I'm trying to achieve the following in the example below. Can some one help me fix my code so I can update my site. Thanks Previous First 1 2 3 4 5 6 7 ... 199 200 Last Next I currently have the following displayed using my code. Previous 1 2 3 4 5 6 7 Next Here is the part of my pagination code that displays the links. if ($pages > 1) { echo '<br /><p>'; $current_page = ($start/$display) + 1; if ($current_page != 1) { echo '<a href="index.php?s=' . ($start - $display) . '&p=' . $pages . '">Previous</a> '; } for ($i = 1; $i <= $pages; $i++) { if ($i != $current_page) { echo '<a href="index.php?s=' . (($display * ($i - 1))) . '&p=' . $pages . '">' . $i . '</a> '; } else { echo '<span>' . $i . '</span> '; } } if ($current_page != $pages) { echo '<a href="index.php?s=' . ($start + $display) . '&p=' . $pages . '">Next</a>'; } echo '</p>'; }

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