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• Can I automatically add a new host to known_hosts ?

  - by gareth_bowles

  Here's my situation; I'm setting up a test harness that will, from a central client, launch a number of virtual machine instances and then execute commands on them via SSH. The virtual machines will have previously unused hostnames and IP addresses, so they won't be in the ~/.ssh/known_hosts file on the central client. The problem I'm having is that the first SSH command run against a new virtual instance always comes up with an interactive prompt: The authenticity of host '[hostname] ([IP address])' can't be established. RSA key fingerprint is [key fingerprint]. Are you sure you want to continue connecting (yes/no)? Is there a way that I can bypass this and get the new host to be already known to the client machine, maybe by using a public key that's already baked into the virtual machine image ? I'd really like to avoid having to use Expect or whatever to answer the interactive prompt if I can.

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• Why does PsExec hang after successfully running a powershell script?

  - by Matt

  The script is fairly straight forward. Simply tries to start a bunch of windows services. Execution locally works fine when on the target machine. The script is actually executing fine as well when done via PsExec, it just never returns until I hit the "enter" key on my CMD prompt. This is a problem, because this is being called from TeamCity, and it makes the Agent hang waiting for PsExec to return. I've tried the following: Adding an exit and exit 0 at the end of the Powershell script Adding a < NUL to the end of the PsExec call, per the answer in this SF question Adding a > stdout redirect This is how I am actually calling psexec: psexec \\target -u domain\username -p password powershell c:\path\script.ps1 No matter what I do, it hangs until I the locally on the cmd prompt. After I hit enter, I get the message: powershell exited on target with error code 0.

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• How to print TIFF files using MSFT Office Document imaging?

  - by Think Floyd

  OS: Vista and Windows7 I have Microsoft Office Document Imaging installed. .tif and .tiff files association is set to " Microsoft Office Document Imaging" When I open a TIFF file, it opens in " Microsoft Office Document Imaging". Good so far. However, when I right-click on the TIFF file and invoke print, I see a "Print Pictures" dialog, ("How do you want to print your pictures?") I have some applications installed on my machine that print incoming TIFF files on the printer. They work fine on XP. However, on Vista and Windows7, I get this "Print pictures" prompt requiring an user intervention (i.e, click on Print button). How do I get rid of this "Print Pictures" prompt?

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• Rails destroy confirm with Jquery AJAX

  - by Mike

  I have got this working for the most part. My rails link is: <%= link_to(image_tag('/images/bin.png', :alt => 'Remove'), @business, :class => 'delete', :confirm => 'Are you sure?', :id => 'trash') %> :class = "delete" is calling an ajax function so that it is deleted and the page isn't refreshed that works great. But because the page doesn't refresh, it is still there. So my id trash is calling this jquery function: $('[id^=trash]').click(function(){ var row = $(this).closest("tr").get(0); $(row).hide(); return false; }); Which is hiding the row of whatever trash icon i clicked on. This also works great. I thought I had it all worked out and then I hit this problem. When you click on my trash can I have this confirm box pop up to ask you if you are sure. Regardless of whether you choose cancel or accept, the jquery fires and it hides the row. It isn't deleted, only hidden till you refresh the page. I tried changing it so that the prompt is done through jquery, but then rails was deleteing the row regardless of what i choose in my prompt because the .destroy function was being called when the prompt was being called. My question really is how can i get the value to cancel or accept from the rails confirm pop up so that in my jquery I can have an if statement that hides if they click accept and does nothing if they click cancel. EDIT: Answering Question below. That did not work. I tried changing my link to: <%= link_to(image_tag('/images/bin.png', :alt => 'Remove'), @business, :class => "delete", :onclick => "trash") %> and putting this in my jquery function trash(){ if(confirm("Are you sure?")){ var row = $(this).closest("tr").get(0); $(row).hide(); return false; } else { //they clicked no. } } But the function was never called. It just deletes it with no prompt and doesn't hide it. But that gave me an idea. I took the delete function that ajax was calling $('a.delete').click (function(){ $.post(this.href, {_method:'delete'}, null, "script"); $(row).hide(); }); And modified it implementing your code: remove :confirm = 'Are you sure?' $('a.delete').click (function(){ if(confirm("Are you sure?")){ var row = $(this).closest("tr").get(0); $.post(this.href, {_method:'delete'}, null, "script"); $(row).hide(); return false; } else { //they clicked no. return false; } }); Which does the trick.

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• Creating a really public Windows network share

  - by Timur Aydin

  I want to create a shared folder under Windows (actually, Windows XP, Vista, and Win 7) which can be mounted from a linux system without prompting for a username/password. But before attempting this, I first wanted to establish that this works between two Windows 7 machines. So, on machine A (The server that will hold the public share), I created a folder and set its permissions such that Everyone has read/write access. Then I visited Control Panel - Network and Sharing Center - Advanced Sharing Settings and then selected "Turn off password protected sharing". Then, on machine B (The client that wants to access the public share with no username/password prompt), I tried to "map network driver" and I was immediately prompted by a password prompt. Some search on google suggested changing "Acconts: Limit local account use of blank passwords to console logon only" to "Disabled". Tried that, no luck, still getting username/password prompt. If I enter the username/password, I am not prompted for it again and can use the share as long as the session is active. But still, I really need to access the share without any username/password transaction whatsoever and this is not just a convenience related thing. Here is the actual reason: The device that will access this windows network share is an embedded system running uclinux. It will mount this share locally and then play media files. Its only user interface is a javascript based web page. So, if there is going to be any username/password transaction, I would have to ask the user to enter them over the web page, which will be ridiculously insecure and completely exposed to packet sniffing. After hours of doing experiments, I have found one way to make this happen, but I am not really very fond of it... I first create a new user (shareuser) and give it a password (sharepass). Then I open Group Policy Editor and set "Deny log on locally" to "A\shareuser". Then, I create a folder on A and share it so that shareuser has Read access to it. This way, shareuser cannot login to A, but can access the shared folder. And, if someone discovers the shareuser/sharepass through network sniffing, they can just access the shared folder, but can't logon to A. The same thing can be achieved by enabling the Guest user and then going to Group Policy Editor and deleting the "Guest" from the "Deny access to this computer from the network" setting. Again, Guest can mount the public share, but logging in to A as Guest won't be possible, because Guest is already not allowed to log in by default. So my question would be, how can I create a network share that is truly public, so that it can be mounted from a linux machine without requiring a password? Sorry for the long question, but I wanted to explain the reason for really needing this...

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• How to inherit the current path when invoking Maven's exec-maven-plugin?

  - by wishihadabettername

  I have an <exec-maven-plugin> which calls an external command (in this case, svnversion). The command is in the path for the current user. However, when a separate shell is spawned by the plugin, the path is not initialized. I don't want to hardcode or define a variable for each external command (there would be too much to maintain, especially that there are both Windows and *nix users). My pom.xml contains the following: <plugin> <groupId>org.codehaus.mojo</groupId> <artifactId>exec-maven-plugin</artifactId> <version>1.1</version> <executions> <execution> <id>svnversion-exec</id> <phase>process-resources</phase> <goals> <goal>exec</goal> </goals> <configuration> <executable>svnversion</executable> <arguments> <argument><![CDATA[ >version.txt ]]></argument> </arguments> </configuration> </execution> </executions> </plugin> Currently I get the following output: [INFO] [exec:exec {execution: svnversion-exec}] 'svnversion' is not recognized as an internal or external command, operable program or batch file. [ERROR] BUILD ERROR: Result of cmd.exe /X /C "svnversion >version.txt" execution is: '1'. Thank you!

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• SSH authentication working unless ran from script??

  - by awright418

  I have set up my server to allow key/pair authentication by following instructions similar to what is found in this post. As far as I can tell that is working correctly. If I do the following, for example, it works correctly: ssh [email protected] It will NOT prompt me for a password. This is what I want to happen. However if I write a small bash script like this: #!/bin/bash -x ssh [email protected] and execute with: sudo ./mytestscript.sh ...it will prompt me with: [email protected]'s password: What am I doing wrong? I need to be able to login from within my script without being prompted for a password!

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• Server goes offline. What to look for?

  - by Jonathan Sampson

  I'm using a new virtual server through GoDaddy, and this morning I received a call from the powers that be informing me our website was offline. After confirming this, I requested a power cycle through our GoDaddy control panel, and within a minute or two the server was back online. I made the call, and reported the news that we're back up. Of course, a couple minutes later we're down again. I tried connecting through PuTTy, and it takes forever to prompt me for a username, and each successive prompt takes a long time to come up. I'm using CentOS. So my questions are: How can I determine the cause? What types of things can I do to prevent this in the future? One interesting, and perhaps relevant, observation is that yesterday our bandwidth consumption was about 20% greater than our top figures from the past month.

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• how to let the parser print help message rather than error and exit

  - by fluter

  Hi, I am using argparse to handle cmd args, I wanna if there is no args specified, then print the help message, but now the parse will output a error, and then exit. my code is: def main(): print "in abing/start/main" parser = argparse.ArgumentParser(prog="abing")#, usage="%(prog)s <command> [args] [--help]") parser.add_argument("-v", "--verbose", action="store_true", default=False, help="show verbose output") subparsers = parser.add_subparsers(title="commands") bkr_subparser = subparsers.add_parser("beaker", help="beaker inspection") bkr_subparser.set_defaults(command=beaker_command) bkr_subparser.add_argument("-m", "--max", action="store", default=3, type=int, help="max resubmit count") bkr_subparser.add_argument("-g", "--grain", action="store", default="J", choices=["J", "RS", "R", "T", "job", "recipeset", "recipe", "task"], type=str, help="resubmit selection granularity") bkr_subparser.add_argument("job_ids", nargs=1, action="store", help="list of job id to be monitored") et_subparser = subparsers.add_parser("errata", help="errata inspection") et_subparser.set_defaults(command=errata_command) et_subparser.add_argument("-w", "--workflows", action="store_true", help="generate workflows for the erratum") et_subparser.add_argument("-r", "--run", action="store_true", help="generate workflows, and run for the erratum") et_subparser.add_argument("-s", "--start-monitor", action="store_true", help="start monitor the errata system") et_subparser.add_argument("-d", "--daemon", action="store_true", help="run monitor into daemon mode") et_subparser.add_argument("erratum", action="store", nargs=1, metavar="ERRATUM", help="erratum id") if len(sys.argv) == 1: parser.print_help() return args = parser.parse_args() args.command(args) return how can I do that? thanks.

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• Change Win7 taskbar position (overriding GPO, Registry Editor, Admin. Rights)

  - by diegocavazos53

  I run the computer center of my Faculty and the problem is that users manage to change the Win7 taskbar position. I don't really know how they do this as far as I have applied many group policies that are specific to the taskbar (like locking it). I have also disallowed users from entering new registry keys or executing the command prompt (or employing scripts). They have regular user rights and many Win7 tweaking programs need administrator rights to make changes to the GUI. So in other words, the taskbar is locked, there is a policy that sets its position to the lower part of the screen, users can't see the control panel, add registry keys, use the command prompt and don't have admin. rights. How do they keep moving the taskbar position to the upper part of the screen? Any ideas would be greatly appreciated. Thank you.

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• Windows XP Pro 'Connect to' logon box greyed out with Guest

  - by HaydnWVN

  Have a machine i've just nuked and paved to be used in a public enviroment, yet still connected to a Workgroup. Would like it to prompt for a logon when accessing any of the network shares as different departments will be using it. It does prompt for a login but the username field is greyed out. Have disabled simple file sharing, disabled guest account, changed Local Security Policies (Network access Sharing and Security model to 'classic') all to no avail. A google around has lots of other people with the same issues, lots of 'fixes' with very few feedback. Of course none of these work for me! :)

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• SSH only works after intentionally failed password

  - by pyraz

  So, I'm having a rather weird problem. I have a server, that when I try to SSH into, immediately closes the connection if I type in the correct password on the first attempt. However, if I purposefully enter a wrong password on the first attempt, and then enter a correct password at the second or third prompt, it successfully logs me into the computer. Similarly, when I try to use public key authentication, I get an immediate closed connection. If, however, I enter a wrong password for my key file, followed by another wrong password once it reverts to password authentication, I can successfully log in as long as I provide the correct password at the second or third prompt. The machine is running Red Hat Enterprise Linux Server release 6.2 (Santiago), and is using LDAP and PAM for authentication. Any ideas on where to start debugging this one? Let me know what config files I need to provide and I'll be happy to do so.

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• How to create view in RoR if skipped during controller generation

  - by swapnesh

  When I run this: rails generate controller hello index it no doubt generates hello controller, but accidentally when I run another command like this: rails generate controller world it creates the world controller successfully, but missed the Route "world/index" like as "hello/index". For this mistake I need to use destroy controller and then generate it once more, is thr some kind of mid way command that I can generate if forgotten something rather than destroying and creating every time. This command rails generate controller contact-us index creates a route as contact_us/index or contact_us after changing routes.rb under config folder. How could I create a more SEO friendly URL in RoR? Like localhost:3000/contact-us? I am working on some very basic rules to follow RoR..like 3 static pages (Home, About us, Contact Us) Just simple html content to understand more, will certainly add more features to it as well. localhost:3000/home localhost:3000/About_us localhost:3000/contact_us I created this via creating home, About_us, contact_us controller command and then changed html in views. Since I am on an initial phase, I read somewhere for static pages we can create this in our public like what we have error pages there in the folder or the approach im using is correct?

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• Getting directory's permissions via FTP

  - by Gotys

  I am trying to get permissions of a directory via FTP command "STAT" like this: $directory_list = ftp_raw($conn_id,'STAT '.$path); The above command lists entire directory contents , including files and subdirs. I then search the returned data array for the directory i need to check, and retrieve something like: drwxr-xr-x 3 user group 77824 May 13 10:15 Targetdir This will let me parse the drwxr-xr-x string to find out that the chmod of the Targetdir is 0755. Problem is, when the containing directory has 5000 files. A) It takes a very long time, and B) the ftp_raw function just returns empty array 1 in 10 runs. I don't know if it's timing out or what exactely is the problem. Is there are a better way to find directory's permissions ? Is there a way to limit number of retrieved fiels in "STAT" command ? I really need just the top 5 , no need for the other 4995 files. Does anyone know, why would my command NOT run 100% of the time? Why would it break ? I cannot even reproduce my error, it happens randomly.

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• Why are my log in times taking so long in Linux?

  - by Jamie

  In recent weeks, login times on my Ubuntu server have started timing out; both through SSH and the local command line console. Examination of the /var/auth.log yields nothing interesting. How can I diagnose long log in times on my Ubuntu server? I should mention, also, that no updates have been performed since the problem has started, and that the /, /boot/ and /usr/ file systems are mounted as readonly. [Edit] This is a stand alone machine, so it doesn't authenticate with Active Directory, LDAP etc. Also, the login prompt is responsive, as is the password prompt. Upon typing the password then CR, I'll timeout. After four a five tries, I will be able to login, although I'm worried this will start taking longer.

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• Timeout ssh sessions after inactivity?

  - by Insyte

  PCI requirement 8.5.15 states: "If a session has been idle for more than 15 minutes, require the user to re-enter the password to re-activate the terminal." The first, and most obvious, way to deal with ssh sessions that are idling at the bash prompt is by enforcing a read-only, global $TMOUT of 900. Unfortunately, that only covers sessions sitting at the bash prompt. The spirit of the PCI spec would also require killing sessions running top/vim/etc. I've considered writing a */1 cron job that parses the output of "/usr/bin/w" and kills the associated shell, but that seems like a blunt instrument. Any ideas for something that would actually do what the spec requires and just lock the terminal? I've looked at away and vlock; they both seem great for voluntarily locking your terminal, but I need a cron/daemon task that will enforce locking.

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• automatically change the gnome-terminal "title" for the window

  - by tom

  Hi. Trying to change the title of a current gnome-terminal (similar to the "set title" that you can do manually") The system is running Fedora 9. The HowTo Xterm-Title discusses how to set the prompt, for an xterm. Tried to implement the escape sequences with no luck. (might be something weird..) Tried to use the gconftool to dump/change/load the changed conf attributes, and again, no luck. Also, set the PROMPT_COMMAND just in case the prompt command was somehow changing the title back (which is highly doubtful) Searching the 'net indicates that a few people have tried to solve this with no luck... I'd also like to figure out how to create a new gnome-terminal with a unique specified title... once this is solved, i'l gladly create a quick writeup/post onn how to accomplish this for others... thanks

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• how to uninstall the jdk 1.7.0 in the ubuntu

  - by kaiwii ho

  i encounter a very strange problem,and here is the detail: i'm going to uninstall the jdk 1.7.0.but when i use the rpm to check the appropriate name of the package,it prompt nothing.Anyway,when i use the command java -version,it will prompt the detail of the jdk 1.7.0. below is the detail: root@kaiwiiho:/usr/java# rpm -qa|grep jdk root@kaiwiiho:/usr/java# java -version java version "1.7.0" Java(TM) SE Runtime Environment (build 1.7.0-b147) Java HotSpot(TM) Server VM (build 21.0-b17, mixed mode) root@kaiwiiho:/usr/java# rpm -qa|grep jdk root@kaiwiiho:/usr/java# so what happen?And how can i uninstall it?thx

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• How to hide helper functions from public API in c

  - by emge

  I'm working on a project and I need to create an API. I am using sockets to communicate between the server (my application) and the clients (the other applications using my API). This project is in c not C++ I come from a linux background and this is my first project using Windows, Visual Studio 2008, and dll libraries. I have communication working between the client and server, but I have some that is duplicated on both projects. I would like to create a library (probably a dll file), that both projects can link to so I don't have to maintain extra code. I also have to create the library that has the API that I need to make available for my clients. Within the API functions that I want public are the calls to these helper functions that are "duplicated code", I don't want to expose these functions to my client, but I do want my server to be able to use those functions. How can I do this? I will try to clarify with an example. This is what I started with. Server Project: int Server_GetPacket(SOCKET sd); int ReceiveAll(SOCKET sd, char *buf, int len); int VerifyLen(char *buf); Client Project: int Client_SendCommand(int command); int Client_GetData(int command, char *buf, int len); int ReceiveAll(SOCKET sd, char *buf, int len); int VerifyLen(char *buf); This is kind of what I would like to end up with: //Server Project: int Server_GetPacket(SOCKET sd); // library with public and private types // private API (not exposed to my client) int ReceiveAll(SOCKET sd, char *buf, int len); int VerifyLen(char *buf); // public API (header file available for client) int Client_SendCommand(int command); int Client_GetData(int command, char *buf, int len); Thanks any help would be appreciated.

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• Application process never terminates on each run

  - by rockyurock

  I am seeing an application always remains live even after closing the application using my Perl script below. Also, for the subsequent runs, it always says that "The process cannot access the file because it is being used by another process. iperf.exe -u -s -p 5001 successful. Output was:" So every time I have to change the file name $file used in script or I have to kill the iperf.exe process in the Task Manager. Could anybody please let me know the way to get rid of it? Here is the code I am using ... my @command_output; eval { my $file = "abc6.txt"; $command = "iperf.exe -u -s -p 5001"; alarm 10; system("$command > $file"); alarm 0; close $file; }; if ($@) { warn "$command timed out.\n"; } else { print "$command successful. Output was:\n", $file; } unlink $file;

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• How to reset/delete my glassfish password?

  - by Paul Tomblin

  I'm trying to install GlassFish v2 on my Macintosh. The installation instructions say that it should prompt for an admin password, but it doesn't, and now I can't log into the admin console on localhost:4848. And I can't change it with asadmin change-admin-password because it needs the old one. I think I installed GlassFish with NetBeans a few months ago and might have started it up once or twice, but I don't remember what password I used back then. Is there a command I can give or a file I can delete to make it forget that old password and prompt me for a new one?

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• Robotlegs: Warning: Injector already has a rule for type

  - by MikeW

  I have a bunch of warning messages like this appear when using Robotlegs/Signals. Everytime this command class executes, which is every 2-3 seconds ..this message displays below If you have overwritten this mapping intentionally you can use "injector.unmap()" prior to your replacement mapping in order to avoid seeing this message. Warning: Injector already has a rule for type "mx.messaging.messages::IMessage", named "". The command functions fine otherwise but I think I'm doing something wrong anyhow. public class MessageReceivedCommand extends SignalCommand { [Inject] public var message:IMessage; ...etc.. do something with message.. } the application context doesnt map IMessage to this command, as I only see an option to mapSignalClass , besides the payload is received fine. Wonder if anyone knows how I might either fix or suppress this message. I've tried calling this as the warning suggests injector.unmap(IMessage, "") but I receive an error - no mapping found for ::IMessage named "". Thanks Edit: A bit more info about the error Here is the signal that I dispatch to the command public class GameMessageSignal extends Signal { public function GameMessageSignal() { super(IMessage); } } which is dispatched from a IPushDataService class gameMessage.dispatch(message.message); and the implementation is wired up in the app context via injector.mapClass(IPushDataService, PushDataService); along with the signal signalCommandMap.mapSignalClass(GameMessageSignal, MessageReceivedCommand); Edit #2: Probably good to point out also I inject an instance of GameMessageSignal into IPushDataService public class PushDataService extends BaseDataService implements IPushDataService { [Inject] public var gameMessage:GameMessageSignal; //then private function processMessage(message:MessageEvent):void { gameMessage.dispatch(message.message); } } Edit:3 The mappings i set up in the SignalContext: injector.mapSingleton(IPushDataService); injector.mapClass(IPushDataService, PushDataService);

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• How to set buffer size in client-server app using sockets?

  - by nelly

  First of all i am new to networking so i may say dumb thing in here. Considering a client-server application using sockets(.net with c# if that matters). The client sends some data, the server process it and sends back a string. The client sends some other data, the serve process it, queries the db and sends back several hundreds of items from the database The client sends some other type of data and the server notifies some other clients . My question is how to set the buffer size correctly for reading/writing operation. Should i do something like this: byte[] buff = new byte[client.ReceiveBufferSize] ? I am thinking of something like this: Client sends data to the server(and the server will follow the same pattern) byte[] bytesToSend=new byte[2048] //2048 to be standard for any command send by the client bytes 0..1 ->command type bytes 1..2047 ->command parameters byte[] bytesToReceive=new byte[8]/byte[64]/byte[8192] //switch(command type) But..what is happening when a client is notified by the server without sending data? What is the correct way to accomplish what i am trying to do? Thanks for reading.

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• Could not launch console app with xCode 4.4

  - by lp1756

  I have a project with two targets -- an iOS app and an OSX console app. The latter was created using Xcode File-New Target and selecting "Command Line Tool". This console app is used to prep a default database needed by the iOS app -- using CoreData. This has been working fine until I upgraded to Mountain Lion and xCode 4.4. Now when I try to run the command line tool I get a "Could Not Launch -- permission denied" error. I have tried playing around with signing certificates, to no avail. Interestingly if I create a new "hello, world" command line tool in a new project it works just fine -- and it is not signed at all. I checked the file and it has -rwxr-xr-x permission. In the debugger the app fails on startup even before it tries to access the moms. If I try to run this outside of the debugger at the command line, it ends with a kill 9 message. Any ideas would be greatly appreciated.

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• please help me for performing serch in my program

  - by Abid

  i want to perform searching in my programe.. i have my class in which i have made a function i.e. public DataTable Search() { string SQL = "Select * from Customer where " + mField + " like '%" + mValue + "%'"; DataTable dt = new DataTable(); dt = dm.GetData(SQL); return (dt); } in which i have made setters and getters for mField and mValue.. where dm is the object of class Datamanagement in which i have made a function GetData i.e. public DataTable GetData(string SQL) { SqlCommand command = new SqlCommand(); SqlDataAdapter dbAdapter = new SqlDataAdapter(); DataTable DataTable = new DataTable(); command.Connection = clsConnection.GetConnection(); command.CommandText = SQL; dbAdapter.SelectCommand = command; dbAdapter.Fill(DataTable); return (DataTable); } and behind the search button, i have written.. private void btnfind_Click(object sender, EventArgs e) { //cust is the object of class customer// if (tbCustName.Text != "") { cust.Field="CustName"; cust.Value = tbCustName.Text; } else if (tbAddress.Text != "") { cust.Value = tbAddress.Text; cust.Field="Address"; } else if (tbEmail.Text != "") { cust.Value = tbEmail.Text; cust.Field="Email"; } else if (tbCell.Text != "") { cust.Value = tbCell.Text; cust.Field = "Cell"; } DataTable dt = new DataTable(); dt = cust.Search(); dgCustomer.DataSource = dt; RefreshGrid(); } where my referesh grid fuction does that : private void RefreshGrid() { DataTable dt = new DataTable(); dt = cust.GetCustomers(); dgCustomer.DataSource = dt; } but this is not working.. i dont knw y.. please help..

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