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  • input_formats in django admin has no effect

    - by pablo
    I'm trying to use input_foramts in the admin but it has no effect. What am I doing wrong? # model class Feedback(models.Model): created_at = models.DateTimeField(auto_now_add=True) # admin form class FeedbackAdminForm(forms.ModelForm): created_at = forms.DateTimeField(input_formats=('%d/%m/%Y',)) class Meta: model = Feedback # admin class FeedbackAdmin(admin.ModelAdmin): form = FeedbackAdminForm admin.site.register(Feedback, FeedbackAdmin) Thanks

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  • VM Build XML file fails to validate against OVF 1.0 schema

    - by siddharthgod
    For our product, we were trying to generate VM / vApp build XML from java code. For this purpose, we were using XML Beans. When we tried to generate JAVA classes for OVF envelope for 0.9 (ovf-envelope.xsd in schemas/ovf) it was successful. However these schemas does not allow us to add IPassignment section which is available in OVF 1.0. When we tried to compile 1.0 schema (ovfenv-vmware.xsd in schemas/ovf1.0.0e/vmware folder), we get validation errors. When we loaded this schema in schema editor we could see some validation errors. First error we saw was following: When we loaded ovfenv-vmware.xsd in XMLspy we could see following validation error in dsp8027.xsd - "cos-nonambig: makes the content model non-deterministic against . Possible causes: name equality, overlapping occurrence or substitution groups." Same error was also thrown by xmlbean while generating java classes from ovfenv-vmware.xsd. Is there any workaround for this problem?

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  • Django adminsite customize search_fields query

    - by dArignac
    Howdy! In the django admin you can set the search_fields for the ModelAdmin to be able to search over the properties given there. My model class has a property that is not a real model property, means it is not within the database table. The property relates to another database table that is not tied to the current model through relations. But I want to be able to search over it, so I have to somehow customize the query the admin site creates to do the filtering when the search field was filled - is this possible and if, how? I can query the database table of my custom property and it then returns the ids of the model classes fitting the search. This then, as I said, has to flow into the admin site search query. Thanks!

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  • Django models & Python class attributes

    - by Geo
    The tutorial on the django website shows this code for the models: from django.db import models class Poll(models.Model): question = models.CharField(max_length=200) pub_date = models.DateTimeField('date published') class Choice(models.Model): poll = models.ForeignKey(Poll) choice = models.CharField(max_length=200) votes = models.IntegerField() Now, each of those attribute, is a class attribute, right? So, the same attribute should be shared by all instances of the class. A bit later, they present this code: class Poll(models.Model): # ... def __unicode__(self): return self.question class Choice(models.Model): # ... def __unicode__(self): return self.choice How did they turn from class attributes into instance attributes? Did I get class attributes wrong?

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  • To handle Window.open in request Scope in jsf

    - by santhana sankar
    I am using JSF 1.2 here i have a managed bean in request scope, my scenario is to open a seperate window. After action is performed oncomplete i am opening a new window since the managed bean in request scopes the values are not populated in new window. Because new object is being created while opening a new window. i can use session scope but that is restricted. kindly help me in resolving this.

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  • Creating a Group of Groups in Django

    - by Greg
    I'm creating my own Group model; I'm not referring to the builtin Group model. I want each hroup to be a member of another group (it's parent), but there is the one "top" group that doesn't have a parent group. The admin interface won't let me create a group without entering a parent. I get the error personnel_group.parent_id may not be NULL. My Group model looks like this: class Group(models.Model): name = models.CharField(max_length=50) parent = models.ForeignKey('self', blank=True, null=True) order = models.IntegerField() icon = models.ImageField(upload_to='groups', blank=True, null=True) description = models.TextField(blank=True, null=True) How can I accomplish this? Thanks.

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  • How do I restrict foreign keys choices to related objects only in django

    - by Jeff Mc
    I have a two way foreign relation similar to the following class Parent(models.Model): name = models.CharField(max_length=255) favoritechild = models.ForeignKey("Child", blank=True, null=True) class Child(models.Model): name = models.CharField(max_length=255) myparent = models.ForeignKey(Parent) How do I restrict the choices for Parent.favoritechild to only children whose parent is itself? I tried class Parent(models.Model): name = models.CharField(max_length=255) favoritechild = models.ForeignKey("Child", blank=True, null=True, limit_choices_to = {"myparent": "self"}) but that causes the admin interface to not list any children.

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  • How do you set the default source for the Output window in Visual Studio?

    - by Grank
    We added a SharePoint BDC model project to a solution in Visual Studio 2010. Ever since, whenever the solution is built, instead of showing the Build output in the Output window, it insists on having "SharePoint Tools" selected in the "Show Output from:" drop-down, just to say "Model validation started ... Model validation completed with no errors." Short of shutting off any SharePoint projects in the build configuration, can this behavior be overridden?

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  • my jComboBox does not react to my keyListener and actionPerform perfroms weired stuff

    - by aladdin
    hi I am trying to search for UserName and return values onto jComboBox, here is the code public void actionPerformed(java.awt.event.ActionEvent e) { sr = new Search(((String) jComboBoxReceiver.getSelectedItem())); usrList = sr.searchUser(); String[] userList = new String[usrList.size()] ; for(int i=0;i<usrList.size();i++){ userList[i]= usrList.get(i).getUserName(); } model = new DefaultComboBoxModel(userList); jComboBoxReceiver.setModel(model); } However, if i do that, it does perform correctly, however, it will go search for the first item again, which is very confusing... then i tried using key Pressed if(e.getKeyCode()==13){ sr = new Search(((String) jComboBoxReceiver.getSelectedItem())); usrList = sr.searchUser(); String[] userList = new String[usrList.size()] ; for(int i=0;i<usrList.size();i++){ userList[i]= usrList.get(i).getUserName(); } model = new DefaultComboBoxModel(userList); jComboBoxReceiver.setModel(model); } And this one does not react at all ...

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  • Can this django query be improved?

    - by Hobhouse
    Given a model structure like this: class Book(models.Model): user = models.ForeignKey(User) class Readingdate(models.Model): book = models.ForeignKey(Book) date = models.DateField() One book may have several readingdates. How do I list books having at least one readingdate within a specific year? I can do this: from_date = datetime.date(2010,1,1) to_date = datetime.date(2010,12,31) book_ids = Readingdate.objects\ .filter(date__range=(from_date,to_date))\ .values_list('book_id', flat=True) books_read_2010 = Book.objects.filter(id__in=book_ids) Is it possible to do this with one queryset, or is this the best way?

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  • Returning a local object from a function

    - by pocoa
    Is this the right way to return an object from a function? Car getCar(string model, int year) { Car c(model, year); return c; } void displayCar(Car &car) { cout << car.getModel() << ", " << car.getYear() << endl; } displayCar(getCar("Honda", 1999)); I'm getting an error, "taking address of temporary". Should I use this way: Car &getCar(string model, int year) { Car c(model, year); return c; }

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  • Why does JPA require a no-arg constructor for domain objects ?

    - by Jacques René Mesrine
    Why does JPA require a no-arg constructor for domain objects ? I am using eclipselink and just got this exception during deployment. Exception [EclipseLink-63] (Eclipse Persistence Services-1.1.0.r3639-SNAPSHOT): org.eclipse.persistence.exceptions.DescriptorException Exception Description: The instance creation method [com.me.model.UserVO.<Default Constructor>], with no parameters, does not exist, or is not accessible. Internal Exception: java.lang.NoSuchMethodException: com.me.model.UserVO.<init>() Descriptor: RelationalDescriptor(com.me.model.UserVO --> [DatabaseTable(user)])

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  • I am confused about how to use @SessionAttributes

    - by yusaku
    I am trying to understand architecture of Spring MVC. However, I am completely confused by behavior of @SessionAttributes. Please look at SampleController below , it is handling post method by SuperForm class. In fact, just field of SuperForm class is only binding as I expected. However, After I put @SessionAttributes in Controller, handling method is binding as SubAForm. Can anybody explain me what happened in this binding. ------------------------------------------------------- @Controller @SessionAttributes("form") @RequestMapping(value = "/sample") public class SampleController { @RequestMapping(method = RequestMethod.GET) public String getCreateForm(Model model) { model.addAttribute("form", new SubAForm()); return "sample/input"; } @RequestMapping(method = RequestMethod.POST) public String register(@ModelAttribute("form") SuperForm form, Model model) { return "sample/input"; } } ------------------------------------------------------- public class SuperForm { private Long superId; public Long getSuperId() { return superId; } public void setSuperId(Long superId) { this.superId = superId; } } ------------------------------------------------------- public class SubAForm extends SuperForm { private Long subAId; public Long getSubAId() { return subAId; } public void setSubAId(Long subAId) { this.subAId = subAId; } } ------------------------------------------------------- <form:form modelAttribute="form" method="post"> <fieldset> <legend>SUPER FIELD</legend> <p> SUPER ID:<form:input path="superId" /> </p> </fieldset> <fieldset> <legend>SUB A FIELD</legend> <p> SUB A ID:<form:input path="subAId" /> </p> </fieldset> <p> <input type="submit" value="register" /> </p> </form:form>

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  • ServeletException, Property <variable name> not found

    - by k9yosh
    What i'm trying to do is add a new variable to this previously created Managed Bean Hello.java and use it in my xhtml file binding to a text field. But it seems that it is not being found when i run it on the server. So it throws a "ServeletException" and says that the "property 'lname'(my variable) is not found". How do i solve this and why is this happening? This is my managed bean, package stack.tute.malinda.model; import javax.faces.bean.ManagedBean; import javax.faces.bean.RequestScoped; @ManagedBean @RequestScoped public class Hello { private String fname; private String message; private String lname; //trying to add this new variable and use it in my xhtml file in a text field. public String getLname() { return lname; } public void setLname(String lname) { this.lname = lname; } public String getName() { return fname; } public String createMessage() { message="Hello " + fname + ""+ lname +"!"; return null; } public void setName(String fname) { this.fname=fname; } public String getMessage() { return message; } } This is my xhtml code, <h:body> <fieldset style="padding: 1em; float:left; margin-right:0.5em; padding-top:0.2em; text-align:left; border:1px solid green; font-weight:bold;"> <legend>Personal Details</legend> <h:form> <h:outputLabel for="name" value="First Name :" required="true"/> <h:inputText id="name" value="#{hello.name}"/> <br/> //Trying to access that variable here. <h:outputLabel for="name1" value="Last Name :" required="true"/> <h:inputText id="name1" value="#{hello.lname}"/> <h:message for="name"/> <br/> <h:commandButton value="Say hello" action="#{hello.createMessage}"> <f:ajax execute="@form" render="@form"/> </h:commandButton> <br/> <h:outputText value="#{hello.message}"/> </h:form> </fieldset>

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  • What does the MVC Controller.UpdateModel<T>(T) actually try to do?

    - by unanswered
    When I submit my MVC Page I get an IvalidOperationException from System.Web.Mvc Controller object in the UpdateModel method. the MSDN documentation states that this method does the following: Updates the specified model instance using values from the controller's current value provider. Is the value provider referencing the current Request object? Or where exactly does it get the values that it is using to update the model? And what specifically does the UpdateModel method check and what does it 'mean' when it says that The model of type 'abcXYZ' was not successfully updated Thanks

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  • how to get SOURCE

    - by laknath27
    i do some development with jena ontology API.my ontology file in my local machine..when i'm going to read the model.. there is an error.. and i made ontology with protege and tried to read that file. String SOURCE = "http://www.owl-ontologies.com/Ontology1275995702";(it's XML:base value) //String NS = SOURCE + "#"; //InputStream in = FileManager.get().open("tourism.owl"); OntModel model = ModelFactory.createOntologyModel(OntModelSpec.OWL_MEM); model.read(SOURCE,"RDF/XML"); OntClass paper = model.getOntClass( SOURCE + "srilanka" ); how can i fix this?

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  • ASP.NET MVC. Hot to guess autogenerated id value ?

    - by Andrew Florko
    My web form contains list of dynamic fields that are generated like this: <% for (int i = 0; i < Model.Options.Count; i++) { %> ... <%= Html.Hidden("Options[" + i + "].Id", Model.Options[i].Id)%> <%= Html.CheckBox("Options[" + i + "].Selected", Model.Options[i].Selected)%> ... This maps perfectly on array of controller method parameters as described in Model Binding To A List article. I want to add label for checkboxes to title them, but I have to guess their ids in hmtl layout. Options[" + i + "].Selected turns into Options_0__Selected How can I avoid hardcoding Id generation in-built asp.net mvc rules? Thank you advance.

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  • django access to parent

    - by SledgehammerPL
    model: class Product(models.Model): name = models.CharField(max_length = 128) (...) def __unicode__(self): return self.name class Receipt(models.Model): name = models.CharField(max_length=128) (...) components = models.ManyToManyField(Product, through='ReceiptComponent') def __unicode__(self): return self.name class ReceiptComponent(models.Model): product = models.ForeignKey(Product) receipt = models.ForeignKey(Receipt) quantity = models.FloatField(max_length=9) unit = models.ForeignKey(Unit) def __unicode__(self): return unicode(self.quantity!=0 and self.quantity or '') + ' ' + unicode(self.unit) + ' ' + self.product.genitive And now I'd like to get list of the most often useable products: ReceiptComponent.objects.values('product').annotate(Count('product')).order_by('-product__count' the example result: [{'product': 3, 'product__count': 5}, {'product': 6, 'product__count': 4}, {'product': 5, 'product__count': 3}, {'product': 7, 'product__count': 2}, {'product': 1, 'product__count': 2}, {'product': 11, 'product__count': 1}, {'product': 8, 'product__count': 1}, {'product': 4, 'product__count': 1}, {'product': 9, 'product__count': 1}] It's almost what I need. But I'd prefer having Product object not product value, because I'd like to use this in views.py for generating list.

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  • Rails, destroy if blank

    - by Joseph Silvashy
    This might sound odd, but is there a 'Rails way' to have a model destroyed if a certain attribute is blank? Say I have a model like tags with just a name attribute or something, if the user edits the tag and deletes all the text out of the name field in the form I'd like the model to just be deleted. I'm aware of the reject_if method, but that doesn't seem to work.

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  • Is there a way to undo Mocha stubbing of any_instance?

    - by Steve Weet
    Within my controller specs I am stubbing out valid? for some routing tests, (based on Ryan Bates nifty_scaffold) as follows :- it "create action should render new template when model is invalid" do Company.any_instance.stubs(:valid?).returns(false) post :create response.should render_template(:new) end This is fine when I test the controllers in isolation. I also have the following in my model spec it "is valid with valid attributes" do @company.should be_valid end Again this works fine when tested in isolation. The problem comes if I run spec for both models and controllers. The model test always fails as the valid? method has been stubbed out. Is there a way for me to remove the stubbing of any_instance when the controller test is torn down. I have got around the problem by running the tests in reverse alphabetic sequence to ensure the model tests run before the controllers but I really don't like my tests being sequence dependant.

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  • Accessing ArrayList in Javascript - ASP.Net MVC2

    - by Shrikant
    Hi I have ArrayList in my Model and want to iterate through it in my javascript. I am using following code but its giving me error : CS0103: The name 'i' does not exist in the current context for(var i=0; i <= <%=Model.KeyList.Count%>; i++) { alert('<%=Model.KeyList[i]%>'); } How to get rid of this. its urgent...Please.

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  • dynamic searchable fields, best practice?

    - by boblu
    I have a Lexicon model, and I want user to be able to create dynamic feature to every lexicon. And I have a complicate search interface that let user search on every single feature (including the dynamic ones) belonged to Lexicon model. I could have used a serialized text field to save all the dynamic information if they are not for searching. In case I want to let user search on all fields, I have created a DynamicField Model to hold all dynamically created features. But imagine I have 1,000,000,000 lexicon, and if one create a dynamic feature for every lexicon, this will result creating 1,000,000,000 rows in DynamicField model. So the sql search function will become quite inefficient while a lot of dynamic features created. Is there a better solution for this situation? Which way should I take? searching for a better db design for dynamic fields try to tuning mysql(add cache fields, add index ...) with current db design

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  • Django: Set foreign key using integer?

    - by User
    Is there a way to set foreign key relationship using the integer id of a model? This would be for optimization purposes. For example, suppose I have an Employee model: class Employee(models.Model): first_name = models.CharField(max_length=100) last_name = models.CharField(max_length=100) type = models.ForeignKey('EmployeeType') and EmployeeType(models.Model): type = models.CharField(max_length=100) I want the flexibility of having unlimited employee types, but in the deployed application there will likely be only a single type so I'm wondering if there is a way to hardcode the id and set the relationship this way. This way I can avoid a db call to get the EmployeeType object first.

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  • Django Aggregation Across Reverse Relationship

    - by Tom
    Given these two models: class Profile(models.Model): user = models.ForeignKey(User, unique=True, verbose_name=_('user')) about = models.TextField(_('about'), blank=True) zip = models.CharField(max_length=10, verbose_name='zip code', blank=True) website = models.URLField(_('website'), blank=True, verify_exists=False) class ProfileView(models.Model): profile = models.ForeignKey(Profile) viewer = models.ForeignKey(User, blank=True, null=True) created = models.DateTimeField(auto_now_add=True) I want to get all profiles sorted by total views. I can get a list of profile ids sorted by total views with: ProfileView.objects.values('profile').annotate(Count('profile')).order_by('-profile__count') But that's just a dictionary of profile ids, which means I then have to loop over it and put together a list of profile objects. Which is a number of additional queries and still doesn't result in a QuerySet. At that point, I might as well drop to raw SQL. Before I do, is there a way to do this from the Profile model? ProfileViews are related via a ForeignKey field, but it's not as though the Profile model knows that, so I'm not sure how to tie the two together. As an aside, I realize I could just store views as a property on the Profile model and that may turn out to be what I do here, but I'm still interested in learning how to better use the Aggregation functions.

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