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  • Django refresh page if change data by other user

    - by Fran Sobrino
    I have a test django app. In one page the test show the same question to all users. I'd like that when a user answers correctly, send a signal to other active user's browser to refresh to the next question. I have been learning about signals in django I learning work with them but I don't now how send the "refresh signal" to client browser. I think that it can do with a javascript code that check if a certain value (actual question) change and if change reload the page but I don't know this language and the information that I find was confused. Can anybody help me? Many Thanks.

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  • app_label in an abstract Django model

    - by rayan
    Hi all, I'm trying to get an abstract model working in Django and I hit a brick wall trying to set the related_name per the recommendation here: http://docs.djangoproject.com/en/dev/topics/db/models/#be-careful-with-related-name This is what my abstract model looks like: class CommonModel(models.Model): created_on = models.DateTimeField(editable=False) creared_by = models.ForeignKey(User, related_name="%(app_label)s_%(class)s_created", editable=False) updated_on = models.DateTimeField(editable=False) updated_by = models.ForeignKey(User, related_name="%(app_label)s_%(class)s_updated", editable=False) def save(self): if not self.id: self.created_on = datetime.now() self.created_by = user.id self.updated_on = datetime.now() self.updated_by = user.id super(CommonModel, self).save() class Meta: abstract = True My common model is in [project_root]/models.py. It is the parent object of this model, which is located in an app called Feedback [project_root]/feedback/models.py: from django.db import models from mediasharks.models import CommonModel class Feedback(CommonModel): message = models.CharField(max_length=255) request_uri = models.CharField(max_length=255) domain = models.CharField(max_length=255) feedback_type = models.IntegerField() Basically I'm trying to set up a common model so that I'll always be able to tell when and by whom database entries were created. When I run "python manage.py validate" I get this error message: KeyError: 'app_label' Am I missing something here?

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  • Django startup importing causes reverse to happen

    - by nicknack
    This might be an isolated problem, but figured I'd ask in case someone has thoughts on a graceful approach to address it. Here's the setup: -------- views.py -------- from django.http import HttpResponse import shortcuts def mood_dispatcher(request): mood = magic_function_to_guess_my_mood(request) return HttpResponse('Please go to %s' % shortcuts.MOODS.get(mood, somedefault)) ------------ shortcuts.py ------------ MOODS = # expensive load that causes a reverse to happen The issue is that shortcuts.py causes an exception to be thrown when a reverse is attempted before django is done building the urls. However, views.py doesn't yet need to import shortcuts.py (used only when mood_dispatcher is actually called). Obvious initial solutions are: 1) Import shortcuts inline (just not very nice stylistically) 2) Make shortcuts.py build MOODS lazily (just more work) What I ideally would like is to be able to say, at the top of views.py, "import shortcuts except when loading urls"

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  • how to do server side form validation for dynamic inputs with Django

    - by Satoru.Logic
    Hi, all. I am using django.forms.Form to validate form data in a survey applications. In a survey-creating form, a user can submit multiple questions that belong to the survey being created. Names for the question inputs are in the form of 'question_seq' , where seq is maintained using Javascript. Back in the server side, my code doesn't know before hand how many such questions will be submitted. Is there any way to do this with Django form so that the form can automatically recognizes the questions and validate them?

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  • Django - how to make ImageField/FileField optional?

    - by ilya
    class Product(models.Model): ... image = models.ImageField(upload_to = generate_filename, blank = True) When I use ImageField (blank=True) and do not select image into admin form, exception occures. In django code you can see this: class FieldFile(File): .... def _require_file(self): if not self: raise ValueError("The '%s' attribute has no file associated with it." % self.field.name) def _get_file(self): self._require_file() ... Django trac has ticket #13327 about this problem, but seems it can't be fixed soon. How to make these field optional?

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  • Django: Data corrupted after loading? (possible programmer error)

    - by Rosarch
    I may be loading data the wrong way. excerpt of data.json: { "pk": "1", "model": "myapp.Course", "fields": { "name": "Introduction to Web Design", "requiredFor": [9], "offeringSchool": 1, "pre_reqs": [], "offeredIn": [1, 5, 9] } }, I run python manage.py loaddata -v2 data: Installed 36 object(s) from 1 fixture(s) Then, I go to check the above object using the Django shell: >>> info = Course.objects.filter(id=1) >>> info.get().pre_reqs.all() [<Course: Intermediate Web Programming>] # WRONG! There should be no pre-reqs >>> from django.core import serializers >>> serializers.serialize("json", info) '[{"pk": 1, "model": "Apollo.course", "fields": {"pre_reqs": [11], "offeredIn": [1, 5, 9], "offeringSchool": 1, "name": "Introduction to Web Design", "requiredFor": [9]}}]' The serialized output of the model is not the same as the input that was given to loaddata. The output has a non-empty pre_req list, whereas the input's pre_reqs field is empty. What am I doing wrong?

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  • Sorting related objects in the Django Admin form interface

    - by Carver
    I am looking to sort the related objects that show up when editing an object using the admin form. So for example, I would like to take the following object: class Person(models.Model): first_name = models.CharField( ... ) last_name = models.CharField( ... ) hero = models.ForeignKey( 'self', null=True, blank=True ) and edit the first name, last name and hero using the admin interface. I want to sort the objects as they show up in the drop down by last name, first name (ascending). How do I do that? Context I'm using Django v1.1. I started by looking for help in the django admin docs, but didn't find the solution As you can see in the example, the foreign key is pointing to itself, but I expect it would be the same as pointing to a different model object. Bonus points for being able to filter the related objects, too (eg~ only allow selecting a hero with the same first name)

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  • Django: Why Doesn't the Current URL Match any Patterns in urls.py

    - by austin_sherron
    I've found a few questions here related to my issue, but I haven't found anything that has helped me resolve my issue. I'm using Python 2.7.5 and Django 1.8.dev20140627143448. I have a view that's interacting with my database to delete objects, and it takes two arguments in addition to a request: def delete_data_item(request, dataclass_id, dataitem_id): form = AddDataItemForm(request.POST) data_set = get_object_or_404(DataClass, pk=dataclass_id) context = {'data_set': data_set, 'form': form} data_item = get_object_or_404(DataItem, pk=dataitem_id) data_item.delete() data_set.save() return HttpResponseRedirect(reverse('detail', args=(dataclass_id,))) The URL in myapp.urls.py looks something like this: url(r'^(?P<dataclass_id>[0-9]+)/(?P<dataitem_id>[0-9]+)/delete_data_item/$', views.delete_data_item, name='delete_data_item') and the portion of my template relevant to the view is: <a href="{% url 'delete_data_item' data_set.id data_item.id %}">DELETE</a> Whenever I click on the DELETE link, django tells me that the request URL: http://127.0.0.1:8000/myapp/5/%7B%%20url%20'delete_data_item'%20data_set.id%20data_item.id%20%%7D doesn't match any of my URL patterns. What am I missing? The URL on which the DELETE links exist is myapp/(<dataclass_id>[0-9]+)/

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  • Getting a KeyError in DB backend of django-digest

    - by rtmie
    I have just started to integrate django_digest into my app. As a start I have added the @httpdigest decorator to one of my views. If I try to connect to it I get a KeyError exception thrown in django_digest/backend/db.py . Depending on which db I configure I get a different KeyError in a different location. I am using Django 1.2.1, with MySql (also tested with sqlite). I am using the default values for all the settings options. As far as I can see I have followed all instructions but am struggling all day with this. I am using the repository versions of django-digest and python-digest. Any steer would be greatly appreciated. Tracebacks for sqlite and mysql below: with sqlite: Traceback (most recent call last): File "/home/robm/projects/gcs/server/gcs2.5/lib/python2.5/site-packages/django/core/servers/basehttp.py", line 674, in __call__ return self.application(environ, start_response) File "/home/robm/projects/gcs/server/gcs2.5/lib/python2.5/site-packages/django/core/handlers/wsgi.py", line 248, in __call__ signals.request_finished.send(sender=self.__class__) File "/home/robm/projects/gcs/server/gcs2.5/lib/python2.5/site-packages/django/dispatch/dispatcher.py", line 162, in send response = receiver(signal=self, sender=sender, **named) File "/home/robm/projects/gcs/server/gcs2.5/lib/python2.5/site-packages/django_digest-1.8-py2.5.egg/django_digest/backend/db.py", line 16, in close_connection _connection.close() File "/home/robm/projects/gcs/server/gcs2.5/lib/python2.5/site-packages/django/db/backends/sqlite3/base.py", line 186, in close if self.settings_dict['NAME'] != ":memory:": KeyError: 'NAME' with mysql: Traceback (most recent call last): File "/home/robm/projects/gcs/server/gcs2.5/lib/python2.5/site-packages/django/core/servers/basehttp.py", line 674, in __call__ return self.application(environ, start_response) File "/home/robm/projects/gcs/server/gcs2.5/lib/python2.5/site-packages/django/core/handlers/wsgi.py", line 241, in __call__ response = self.get_response(request) File "/home/robm/projects/gcs/server/gcs2.5/lib/python2.5/site-packages/django/core/handlers/base.py", line 142, in get_response return self.handle_uncaught_exception(request, resolver, exc_info) File "/home/robm/projects/gcs/server/gcs2.5/lib/python2.5/site-packages/django/core/handlers/base.py", line 166, in handle_uncaught_exception return debug.technical_500_response(request, *exc_info) File "/home/robm/projects/gcs/server/gcs2.5/lib/python2.5/site-packages/django/core/handlers/base.py", line 80, in get_response response = middleware_method(request) File "/home/robm/projects/gcs/server/gcs2.5/lib/python2.5/site-packages/django_digest-1.8-py2.5.egg/django_digest/middleware.py", line 13, in process_request if (not self._authenticator.authenticate(request) and File "/home/robm/projects/gcs/server/gcs2.5/lib/python2.5/site-packages/django_digest-1.8-py2.5.egg/django_digest/__init__.py", line 86, in authenticate partial_digest = self._account_storage.get_partial_digest(digest_response.username) File "/home/robm/projects/gcs/server/gcs2.5/lib/python2.5/site-packages/django_digest-1.8-py2.5.egg/django_digest/backend/db.py", line 97, in get_partial_digest cursor = get_connection().cursor() File "/home/robm/projects/gcs/server/gcs2.5/lib/python2.5/site-packages/django/db/backends/__init__.py", line 75, in cursor cursor = self._cursor() File "/home/robm/projects/gcs/server/gcs2.5/lib/python2.5/site-packages/django/db/backends/mysql/base.py", line 281, in _cursor if settings_dict['USER']: KeyError: 'USER'

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  • Google App Engine with local Django 1.1 gets Intermittent Failures

    - by Jon Watte
    I'm using the Windows Launcher development environment for Google App Engine. I have downloaded Django 1.1.2 source, and un-tarrred the "django" subdirectory to live within my application directory (a peer of app.yaml) At the top of each .py source file, I do this: import settings import os os.environ["DJANGO_SETTINGS_MODULE"] = 'settings' In my file settings.py (which lives at the root of the app directory, as well), I do this: DEBUG = True TEMPLATE_DIRS = ('html') INSTALLED_APPS = ('filters') import os os.environ["DJANGO_SETTINGS_MODULE"] = 'settings' from google.appengine.dist import use_library use_library('django', '1.1') from django.template import loader Yes, this looks a bit like overkill, doesn't it? I only use django.template. I don't explicitly use any other part of django. However, intermittently I get one of two errors: 1) Django complains that DJANGO_SETTINGS_MODULE is not defined. 2) Django complains that common.html (a template I'm extending in other templates) doesn't exist. 95% of the time, these errors are not encountered, and they randomly just start happening. Once in that state, the local server seems "wedged" and re-booting it generally fixes it. What's causing this to happen, and what can I do about it? How can I even debug it? Here is the traceback from the error: Traceback (most recent call last): File "C:\code\kwbudget\edit_budget.py", line 34, in get self.response.out.write(t.render(template.Context(values))) File "C:\code\kwbudget\django\template\__init__.py", line 165, in render return self.nodelist.render(context) File "C:\code\kwbudget\django\template\__init__.py", line 784, in render bits.append(self.render_node(node, context)) File "C:\code\kwbudget\django\template\__init__.py", line 797, in render_node return node.render(context) File "C:\code\kwbudget\django\template\loader_tags.py", line 71, in render compiled_parent = self.get_parent(context) File "C:\code\kwbudget\django\template\loader_tags.py", line 66, in get_parent raise TemplateSyntaxError, "Template %r cannot be extended, because it doesn't exist" % parent TemplateSyntaxError: Template u'common.html' cannot be extended, because it doesn't exist And edit_budget.py starts with exactly the lines that I included up top. All templates live in a directory named "html" in my root directory, and "html/common.html" exists. I know the template engine finds them, because I start out with "html/edit_budget.html" which extends common.html. It looks as if the settings module somehow isn't applied (because that's what adds html to the search path for templates).

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  • End user query syntax?

    - by weberc2
    I'm making a command line tool that allows end users to query a statically-schemed database; however, I want users to be able to specify boolean matchers in their query (effectively things like "get rows where (field1=abcd && field2=efgh) || field3=1234"). I did Googling a solution, but I couldn't find anything suitable for end users--still, this seems like it would be a very common problem so I suspect there is a standard solution. So: What (if any) standard query "languages" are there that might be appropriate for end users? What (if any) de facto standards are there (for example, Unix tools that solve similar problems). Failing the previous two options, can you suggest a syntax that would be simple, concise, and easy to validate?

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  • Joining two queries into one query or making a sub-query

    - by gary A.K.A. G4
    I am having some trouble with the following queries originally done for some Access forms: SELECT qry1.TCKYEAR AS Yr, COUNT(qry1.SID) AS STUDID, qry1.SID AS MID, table_tckt.tckt_tick_no FROM table_tckt INNER JOIN qry1 ON table_tckt.tckt_SID = qry1.SID GROUP BY qry1.TCKYEAR, qry1.SID, table_tckt.tckt_tick_no HAVING (((table_tckt.tick_no)=[forms]![frmNAME]![cboNAME])); SELECT table_tckt.sid, FORMAT([tckt_iss_date], 'yyyy') AS TCKYEAR, table_tckt.tckt_tick_no, table_tckt.licstate FROM table_tckt WHERE (((table_tckt.licstate)<>"NA")); I am no longer working with Access, but JSP for the forms. I need to somehow either combine these two queries into one query or find another way to have a query 'query' another one.

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  • Help with SQL query (list strings and count in same query)

    - by Mestika
    Hi everybody, I’m working on a small kind of log system to a webpage, and I’m having some difficulties with a query I want to do multiple things. I have tried to do some nested / subqueries but can’t seem to get it right. I’ve two tables: User = {userid: int, username} Registered = {userid: int, favoriteid: int} What I need is a query to list all the userid’s and the usernames of each user. In addition, I also need to count the total number of favoriteid’s the user is registered with. A user who is not registered for any favorite must also be listed, but with the favorite count shown as zero. I hope that I have explained my request probably but otherwise please write back so I can elaborate. By the way, the query I’ve tried with look like this: SELECT user.userid, user.username FROM user,registered WHERE user.userid = registered.userid(SELECT COUNT(favoriteid) FROM registered) However, it doesn’t do the trick, unfortunately Kind regards Mestika

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  • Django adminsite customize search_fields query

    - by dArignac
    Howdy! In the django admin you can set the search_fields for the ModelAdmin to be able to search over the properties given there. My model class has a property that is not a real model property, means it is not within the database table. The property relates to another database table that is not tied to the current model through relations. But I want to be able to search over it, so I have to somehow customize the query the admin site creates to do the filtering when the search field was filled - is this possible and if, how? I can query the database table of my custom property and it then returns the ids of the model classes fitting the search. This then, as I said, has to flow into the admin site search query. Thanks!

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  • django & postgres linux hosting (with SSH access) recommendations

    - by Justin Grant
    We're looking for a good place to host our custom Django app (a fork of OSQA) and its postgresql backend. Requirements include: Linux Python 2.6 or (ideally) Python 2.7 Django 1.2 Postgres 8.4 or later DB backup/restore handled by the hoster, not us OS & dev-platform-stack patching/maintenance handled by the hoster, not us SSH access (so we can pull source code from GitHub, so we can install python eggs, etc.) ability to set up cron jobs (e.g. to send out dail email updates) ability to send up to 10K emails/day good performance (not ganged up with a zillion other sites on one CPU, not starved for RAM) FTP or SCP access to web logs dedicated public IP SSL support Costs under $1000/month for a relatively small site (<5M pageviews/month) Good customer service We already have a prototype site running on EC2 on top of a Bitnami DjangoStack. The problem is that we have to patch the OS, patch postgres, etc. We'd really prefer a platform-as-a-service (PaaS) offering, like Heroku offers for Rails apps, where all we need to worry about is deploying our code instead of worrying about system software patching and maintenance. Google App Engine is closest to what we're looking for, but they don't offer relational DB access (not yet at least). Anyone have a recommendation?

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  • Django running on Apache+WSGI and apache SSL proxying

    - by Lessfoe
    Hi all, I'm trying to rewrite all requests for my Django server running on apache+WSGI ( inside my local network) and configured as the WSGI's wiki how to, except that I set a virtualhost for it. The server which from I want to rewrite requests is another apache server listening on port 80. I can manage it to work well if I don't try to enable SSL connection as the required way to connect. But I need all requests to Django server encrypted with SSL so I generally used this directive to achieve this ( on my public webserver ): Alias /dirname "/var/www/dirname" SSLVerifyClient none SSLOptions +FakeBasicAuth SSLRequireSSL AuthName "stuff name" AuthType Basic AuthUserFile /etc/httpd/djangoserver.passwd require valid-user # redirect all request to django.test:80 RewriteEngine On RewriteRule (.*)$ http://django.test/$1 [P] This configuration works if I try to load a specific page trough the external server from my browser. It is not working clicking my django application urls ( even tough the url seems correct when I put my mouse over). The url my public server is trying to serve use http ( instead of https ) and the directory "dirname" I specified on my apache configuration disappear, so it says that the page was not found. I think it depends on Django and its WSGI handler . Does anybody went trough my same problem? PS: I have already tried to modify the WSGI script . I'm Using Django 1.0.3, Apache 2.2 on a Fedora10 (inside), Apache 2.2 on the public server. Thanks in advance for your help. Fab

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  • 'NoneType' object has no attribute 'day'

    - by Asinox
    Hi guy, i dont know where is my error, but Django 1.2.1 is give this error: 'NoneType' object has no attribute 'day' when i try to save form from the Administrator Area models.py from django.db import models from django.contrib.auth.models import User class Editorial(models.Model): titulo = models.CharField(max_length=250,help_text='Titulo del editorial') editorial = models.TextField(help_text='Editorial') slug = models.SlugField(unique_for_date='pub_date') autor = models.ForeignKey(User) pub_date = models.DateTimeField(auto_now_add=True) activa = models.BooleanField(verbose_name="Activa") enable_comments = models.BooleanField(verbose_name="Aceptar Comentarios",default=False) editorial_html = models.TextField(editable=False,blank=True) def __unicode__(self): return unicode(self.titulo) def get_absolute_url(self): return "/editorial/%s/%s/" % (self.pub_date.strftime("%Y/%b/%d").lower(), self.slug) class Meta: ordering=['-pub_date'] verbose_name_plural ='Editoriales' def save(self,force_insert=False, force_update=False): from markdown import markdown if self.editorial: self.editorial_html = markdown(self.editorial) super(Editorial,self).save(force_insert,force_update) i dont know why this error, thanks guys sorry with my English

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  • Best way to optimize queries like this in Django

    - by chris
    I am trying to lower the amount of queries that my django app is using, but I am a little confused on how to do it. I would like to get a query set with one hit to the database and then filter items from that set. I have tried a couple of things, but I always get queries for each set. let's say I want to get all names from my DB, but also separate out the people just named Ted. Both the names and the ted set will be used in the template. This will give me two sets, one with all names and one with Ted.. but also hits the database twice: namelist = People.objects.all() tedList = namelist.filter(name='ted') Is there a way to filter the first set without hitting the data base again?

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  • Can this sql query be simplified?

    - by Bas
    I have the following tables: Person, {"Id", "Name", "LastName"} Sports, {"Id" "Name", "Type"} SportsPerPerson, {"Id", "PersonId", "SportsId"} For my query I want to get all the Persons that excersise a specific Sport whereas I only have the Sports "Name" attribute at my disposal. To retrieve the correct rows I've figured out the following queries: SELECT * FROM Person WHERE Person.Id in ( SELECT SportsPerPerson.PersonId FROM SportsPerPerson INNER JOIN Sports on SportsPerPerson.SportsId = Sports.Id WHERE Sports.Name = 'Tennis' ) AND Person.Id in ( SELECT SportsPerPerson.PersonId FROM SportsPerPerson INNER JOIN Sports on SportsPerPerson.SportsId = Sports.Id WHERE Sports.Name = 'Soccer' ) OR SELECT * FROM Person WHERE Id IN (SELECT PersonId FROM SportsPerPerson WHERE SportsId IN (SELECT Id FROM Sports WHERE Name = 'Tennis')) AND Id IN (SELECT PersonId FROM SportsPerPerson WHERE SportsId IN (SELECT Id FROM Sports WHERE Name = 'Soccer')) Now my question is, isn't there an easier way to write this query? Using just OR won't work because I need the person who play 'Tennis' AND 'Soccer'. But using AND also doesn't work because the values aren't on the same row.

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  • How to make this sub-sub-query work?

    - by Josh Weissbock
    I am trying to do this in one query. I asked a similar question a few days ago but my personal requirements have changed. I have a game type website where users can attend "classes". There are three tables in my DB. I am using MySQL. I have four tables: hl_classes (int id, int professor, varchar class, text description) hl_classes_lessons (int id, int class_id, varchar lessonTitle, varchar lexiconLink, text lessonData) hl_classes_answers (int id, int lesson_id, int student, text submit_answer, int percent) hl_classes stores all of the classes on the website. The lessons are the individual lessons for each class. A class can have infinite lessons. Each lesson is available in a specific term. hl_classes_terms stores a list of all the terms and the current term has the field active = '1'. When a user submits their answers to a lesson it is stored in hl_classes_answers. A user can only answer each lesson once. Lessons have to be answered sequentially. All users attend all "classes". What I am trying to do is grab the next lesson for each user to do in each class. When the users start they are in term 1. When they complete all 10 lessons in each class they move on to term 2. When they finish lesson 20 for each class they move on to term 3. Let's say we know the term the user is in by the PHP variable $term. So this is my query I am currently trying to massage out but it doesn't work. Specifically because of the hC.id is unknown in the WHERE clause SELECT hC.id, hC.class, (SELECT MIN(output.id) as nextLessonID FROM ( SELECT id, class_id FROM hl_classes_lessons hL WHERE hL.class_id = hC.id ORDER BY hL.id LIMIT $term,10 ) as output WHERE output.id NOT IN (SELECT lesson_id FROM hl_classes_answers WHERE student = $USER_ID)) as nextLessonID FROM hl_classes hC My logic behind this query is first to For each class; select all of the lessons in the term the current user is in. From this sort out the lessons the user has already done and grab the MINIMUM id of the lessons yet to be done. This will be the lesson the user has to do. I hope I have made my question clear enough.

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  • Returning user data for forms that have errors in when using ModelForms

    - by Sevenearths
    forms.py from django.forms import ModelForm from client.models import ClientDetails, ClientAddress, ClientPhone from snippets.UKPhoneNumberForm import UKPhoneNumberField class ClientDetailsForm(ModelForm): class Meta: model = ClientDetails class ClientAddressForm(ModelForm): class Meta: model = ClientAddress class ClientPhoneForm(ModelForm): number = UKPhoneNumberField() class Meta: model = ClientPhone views.py from django.shortcuts import render_to_response, redirect from django.template import RequestContext from client.forms import ClientDetailsForm, ClientAddressForm, ClientPhoneForm def new_client_view(request): formDetails = ClientDetailsForm(initial={'marital_status':'u'}) formAddress = ClientAddressForm() formHomePhone = ClientPhoneForm(initial={'phone_type':'home'}) formWorkPhone = ClientPhoneForm(initial={'phone_type':'work'}) formMobilePhone = ClientPhoneForm(initial={'phone_type':'mobi'}) return render_to_response('client/new_client.html', {'formDetails': formDetails, 'formAddress': formAddress, 'formHomePhone': formHomePhone, 'formWorkPhone': formWorkPhone, 'formMobilePhone': formMobilePhone}, context_instance=RequestContext(request)) (the new_client.html is nothing special) How should I write views.py so that if the user's data raises an error, instead of showing them the form again with the errors in but none of their original data, it shows them the form again with the errors AND their original data?

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  • Date/time query from Access table ( last month)

    - by chupeman
    Hello, I am using the query builder from Visual Studio 2008 to extract data from an Access mdb ( 2003), but I can't make it to work with a datetime field. When I run it with a third party query app I have works fine, but when I try to implement it into visual studio I can't do it. What is the correct way to extract last month data? This is what I have: SELECT [Datos].[ID], [Datos].[E-mail Address], [Datos].[ZIP/Postal Code], [Datos].[Store], [Datos].[date], [Datos].[gender], [Datos].[age] FROM [Datos] WHERE ([Datos].[date] =<|Last month|>) Any help is appreciated. Thank you

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  • building SQL Query From another Query in php

    - by Nina
    Hello when I Try to built Query from another Query in php code I Faced some problem can you tell me why? :( code : $First="SELECT ro.RoomID,ro.RoomName,ro.RoomLogo,jr.RoomID,jr.MemberID,ro.RoomDescription FROM joinroom jr,rooms ro where (ro.RoomID=jr.RoomID)AND jr.MemberID = '1' "; $sql1 = mysql_query($First); $constract .= "ro.RoomName LIKE '%$search_each%'"; $constract="SELECT * FROM $sql1 WHERE $constract ";// This statment is Make error

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  • Convert this Linq query from query syntax to lambda expression

    - by Jinkinz
    I'm not sure I like linq query syntax...its just not my preference. But I don't know what this query would look like using lambda expressions, can someone help? from securityRoles in user.SecurityRoles from permissions in securityRoles.Permissions where permissions.SecurableEntity.Name == "Unit" && permissions.PermissionType.Name == "Read" orderby permissions.PermissionLevel.Value descending select permissions There is a many-to-many relationship between users and security roles that makes this extra confusing. Thanks! Kelly

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  • EF query to fluent nhibernate query

    - by Shlomi Levi
    I have EF Query: IEnumerable<Account> accounts = (from a in dc.Accounts join m in dc.GroupMembers on a.AccountID equals m.AccountID where m.GroupID == GroupID && m.IsApproved select a).Skip((_configuration.NumberOfRecordsInPage * (PageNumber - 1))) .Take(_configuration.NumberOfRecordsInPage); How to write it in fluent nhibernate query with Session.CreateCriteria<? (My problem is with Join) Regards,

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