Search Results

Search found 6498 results on 260 pages for 'indexed views'.

Page 231/260 | < Previous Page | 227 228 229 230 231 232 233 234 235 236 237 238  | Next Page >

  • jQuery: If, Else with buttons error

    - by Wipqozn
    I'm running into an odd error. I'm working in Django 1.2, and have implemented the commenting framework. I'm trying to attach a hide/show button to each comment field, but whenever click on a hide/show button, it behaves as if each hide/show button beneath it on the page was clicked. Here's the jQuery code: <input type="Button" id="hideShow" name="hide/show" value="Hide"></input> <script> $("#hideShow").click(function() { if($(this).val() == "Hide") { $("textarea").hide("fast"); $(this).val("Show"); } else { $("textarea").show("fast"); $(this).val( "Hide"); } }); </script> So, when I click the Hide/show button, it will perform the action for each button beneath the clicked button + once for the button itself. So If I click a button, and there are two buttons beneath it, and value=hide it will first hide the 'textarea', than show the text area, than finally hide it again. I'm new to jQuery (although I do have experience in other languages), and I have an -idea- why it's not working: that whenever an action is performed jQuery jumps to the first one, than continues down the page looking for any other actions performed, and responds to each one. So it comes to my first button, sets it as being clicked, and so when jQuery comes across the other buttons it views them all as being 'clicked' and performs actions accordingly. I've thought of a semi-solution to my problem, putting in a variable which tracks how many times it has gone through, and than acting based on -that- action. But I would rather not do that, since it's not really a solution to the problem at hand but a work around. Any input is appreciated.

    Read the article

  • "reset" cells after changing orientation

    - by Christian
    Hi, I added the interfaceOrientation to my app. It works fine concerning the views. Some of the table-cells I defined by CGRects to position the text in the cell. In portrait-mode the cell is 300px long, in landscape-mode 420px. I use the following code to change the CGRects depending the orientation: - (UITableViewCell *)tableView:(UITableView *)tableView cellForRowAtIndexPath:(NSIndexPath *)indexPath { if (self.interfaceOrientation == UIDeviceOrientationPortrait) { NSString *currentLanguage = [[NSString alloc] initWithContentsOfFile:[NSHomeDirectory() stringByAppendingPathComponent:@"/Documents/sprache.txt"]]; static NSString *TableViewTableCellIdentifier = @"TableViewTableCellIdentifier"; UITableViewCell *cell = (UITableViewCell *) [tableView dequeueReusableCellWithIdentifier:TableViewTableCellIdentifier]; CGRect cellRect = CGRectMake(0, 0, 300, 175); cell.backgroundColor = [UIColor darkGrayColor]; cell = [[[UITableViewCell alloc] initWithFrame:cellRect reuseIdentifier:TableViewTableCellIdentifier] autorelease]; CGRect keyLabelRect = CGRectMake(0, 5, 5, 20); UILabel *keyLabel = [[UILabel alloc]initWithFrame:keyLabelRect]; keyLabel.tag = 100;......... } else { NSString *currentLanguage = [[NSString alloc] initWithContentsOfFile:[NSHomeDirectory() stringByAppendingPathComponent:@"/Documents/sprache.txt"]]; static NSString *TableViewTableCellIdentifier = @"TableViewTableCellIdentifier"; UITableViewCell *cell = (UITableViewCell *) [tableView dequeueReusableCellWithIdentifier:TableViewTableCellIdentifier]; CGRect cellRect = CGRectMake(0, 0, 450, 175); cell.backgroundColor = [UIColor darkGrayColor]; cell = [[[UITableViewCell alloc] initWithFrame:cellRect reuseIdentifier:TableViewTableCellIdentifier] autorelease]; CGRect keyLabelRect = CGRectMake(0, 5, 5, 20); UILabel *keyLabel = [[UILabel alloc]..... My problem is, when the table is visible and the orientation is changed, I need to scroll to see the new "layout". How can I manage to "reload" the view after changing the orientation?

    Read the article

  • How should I link two items with MouseMovementListeners?

    - by user1708810
    I'm working on a program that will display two "views" of the same set of items. So I need to have something set up so that when the top down view is changed, the side view is updated (and vice versa). Here's a brief outline of the relevant code so you can get an idea of my structure so far: public class DraggableComponent extends JComponent { //Contains code for MouseMovementListener that makes the item draggable } public class ItemGraphic extends DraggableComponent { //Code to render the graphic } public class Item { private ItemGraphic topGraphic; private ItemGraphic sideGraphic; } I'm able to get each graphic to display fine in my GUI. I can also independently drag each graphic. I'm missing the "linking." Some ideas I've been thinking about: Have one listener for the whole GUI. Loop through each Item and if the cursor is within the bounds of either graphic, move the other graphic. I'm concerned about the efficiency of this method. Multiple "paired" listeners (not quite sure how this would work, but the idea is that each graphic would have a listener for the other paired graphic)

    Read the article

  • Celery / Django Single Tasks being run multiple times

    - by felix001
    I'm facing an issue where I'm placing a task into the queue and it is being run multiple times. From the celery logs I can see that the same worker is running the task ... [2014-06-06 15:12:20,731: INFO/MainProcess] Received task: input.tasks.add_queue [2014-06-06 15:12:20,750: INFO/Worker-2] starting runner.. [2014-06-06 15:12:20,759: INFO/Worker-2] collection started [2014-06-06 15:13:32,828: INFO/Worker-2] collection complete [2014-06-06 15:13:32,836: INFO/Worker-2] generation of steps complete [2014-06-06 15:13:32,836: INFO/Worker-2] update created [2014-06-06 15:13:33,655: INFO/Worker-2] email sent [2014-06-06 15:13:33,656: INFO/Worker-2] update created [2014-06-06 15:13:34,420: INFO/Worker-2] email sent [2014-06-06 15:13:34,421: INFO/Worker-2] FINISH - Success However when I view the actual logs of the application it is showing 5-6 log lines for each step (??). Im using Django 1.6 with RabbitMQ. The method for placing into the queue is via placing a delay on a function. This function (task decorator is added( then calls a class which is run. Has anyone any idea on the best way to troubleshoot this ? Edit : As requested heres the code, views.py In my view im sending my data to the queue via ... from input.tasks import add_queue_project add_queue_project.delay(data) tasks.py from celery.decorators import task @task() def add_queue_project(data): """ run project """ logger = logging_setup(app="project") logger.info("starting project runner..") f = project_runner(data) f.main() class project_runner(): """ main project runner """ def __init__(self,data): self.data = data self.logger = logging_setup(app="project") def self.main(self): .... Code settings.py THIRD_PARTY_APPS = ( 'south', # Database migration helpers: 'crispy_forms', # Form layouts 'rest_framework', 'djcelery', ) import djcelery djcelery.setup_loader() BROKER_HOST = "127.0.0.1" BROKER_PORT = 5672 # default RabbitMQ listening port BROKER_USER = "test" BROKER_PASSWORD = "test" BROKER_VHOST = "test" CELERY_BACKEND = "amqp" # telling Celery to report the results back to RabbitMQ CELERY_RESULT_DBURI = "" CELERY_IMPORTS = ("input.tasks", ) celeryd The line im running is to start celery, python2.7 manage.py celeryd -l info Thanks,

    Read the article

  • Knowing which annotation is selected and accessing properties of it.

    - by kevin Mendoza
    So far my program can display a database of custom annotation views. Eventually I want my program to be able to display extra information after a button on the annotation bubble is clicked. Each element in the database has a unique entry Number, so I thought it would be a good idea to add this entry number as a property of the custom annotation. The problem I am having is that after the button is clicked and the program switches to a new view I am unable to retrieve the entry number of the annotation I selected. Below is the code that assigns the entry Number property to the annotation: for (id mine in mines) { workingCoordinate.latitude = [[mine latitudeInitial] doubleValue]; workingCoordinate.longitude = [[mine longitudeInitial] doubleValue]; iProspectAnnotation *tempMine = [[iProspectAnnotation alloc] initWithCoordinate:workingCoordinate]; [tempMine setTitle:[mine mineName]]; [tempMine setAnnotationEntryNumber:[mine entryNumber]]; } [mines dealloc]; When the button on an annotation is selected, this is the code that initializes the new view: - (void)mapView:(MKMapView *)mapView annotationView:(MKAnnotationView *)view calloutAccessoryControlTapped:(UIControl *)control { mineInformationController *controller = [[mineInformationController alloc] initWithNibName:@"mineInformationController" bundle:nil]; controller.modalTransitionStyle = UIModalTransitionStyleCrossDissolve; [self presentModalViewController:controller animated:YES]; [controller release]; } and lastly is my attempt at retrieving the entryNumber property from the new view so that I can compare it to the mines database and retrieve more information on the array element. iProspectFresno_LiteAppDelegate *appDelegate = (iProspectFresno_LiteAppDelegate *)[[UIApplication sharedApplication] delegate]; NSMutableArray* mines = [[NSMutableArray alloc] initWithArray:(NSMutableArray *)appDelegate.mines]; for(id mine in mines) { if ([[mine entryNumber] isEqualToNumber: /*the entry Number of the selected annotation*/]) { /* display the information in the mine object */ } } So how do I access this entry number property in this new view controller?

    Read the article

  • Nhibernate + Gridview + TargetInvocationException

    - by Scott
    For our grid views, we're setting the data sources as a list of results from an Nhibernate query. We're using lazy loading, so the objects are actually proxied... most of the time. In some instances the list will consist of types of Student and Composition_Aop_Proxy_jklasjdkl31231, which implements the same members as the Student class. We've still got the session open, so the lazy loading would resolve fine, if GridView didn't throw an error about the different types in the gridview. Our current workaround is to clone the object, which results in fetching all of the data that can be lazily loaded, even though most of it won't be accessed.. ever. This, however, converts the proxy into an actual object and the grid view is happy. The performance implications kind of scare me as we're getting closer to rolling the code out as is. I've tried evicting the object after a save, which should ensure that everything is a proxy, but this doesn't seem like a good idea either. Does anyone have any suggestions/workarounds?

    Read the article

  • Generating jquery 'rules' from business model to UI in asp.net mvc

    - by jim
    Hi all, I've had a good look around and am certain that there's no matching question on SO, so here goes. Has anyone created a 'helper' method on their model that generates jquery (or plain javascript) rules validation dynamically, based on the criteria/rules that are contained within the object and taken from a repository (i.e. DB). What i'm thinking of is a discrete set of partial views (and associated models) that have rules at the business logic 'level' and rather than (or in combination with) validating the rule(s) at postback, translating the same rules into tightly focussed jquery methods that work identically at client (js) and server (c#) levels. I can see benefits here re performance. Also, the rules definitions could be created in a single place (in c#) and the jquery generated off of that, thus allowing single edits to update both code streams. I appreciate that there would be limitations imposed by language specific contstraints but the general principle could be quite interesting if used appropriately. I'm also aware that testibility could be an issue when using two different language structures and hoping to achieve similar test outcomes - but those aside... any thoughts or experiences of similar out there?? cheers jimi

    Read the article

  • Android Dev: The constructor Intent(new View.OnClickListener(){}, Class<DrinksTwitter>) is undefined

    - by Malcolm Woods Spark
    package com.android.drinksonme; import android.app.Activity; import android.content.Intent; import android.os.Bundle; import android.view.View; import android.view.View.OnClickListener; import android.widget.Button; import android.widget.EditText; import android.widget.TextView; public class Screen2 extends Activity { // Declare our Views, so we can access them later private EditText etUsername; private EditText etPassword; private Button btnLogin; private Button btnSignUp; private TextView lblResult; @Override public void onCreate(Bundle savedInstanceState) { super.onCreate(savedInstanceState); setContentView(R.layout.main); // Get the EditText and Button References etUsername = (EditText)findViewById(R.id.username); etPassword = (EditText)findViewById(R.id.password); btnLogin = (Button)findViewById(R.id.login_button); btnSignUp = (Button)findViewById(R.id.signup_button); lblResult = (TextView)findViewById(R.id.result); // Set Click Listener btnLogin.setOnClickListener(new OnClickListener() { @Override public void onClick(View v) { // Check Login String username = etUsername.getText().toString(); String password = etPassword.getText().toString(); if(username.equals("test") && password.equals("test")){ final Intent i = new Intent(this, DrinksTwitter.class); //error on this line startActivity(i); // lblResult.setText("Login successful."); } else { lblResult.setText("Invalid username or password."); } } }); final Intent k = new Intent(Screen2.this, SignUp.class); btnSignUp.setOnClickListener(new OnClickListener() { public void onClick(View v) { startActivity(k); } }); } }

    Read the article

  • Asp.net mvc inheritance controllers

    - by Ris90
    Hi, I'm studing asp.net mvc and in my test project I have some problems with inheritance: In my model I use inheritanse in few entities: public class Employee:Entity { /* few public properties */ } It is the base class. And descendants: public class RecruitmentOfficeEmployee: Employee { public virtual RecruitmentOffice AssignedOnRecruitmentOffice { get; set; } } public class ResearchInstituteEmployee: Employee { public virtual ResearchInstitute AssignedOnResearchInstitute { get; set; } } I want to implement a simple CRUD operations to every descedant. What is the better way to inplement controllers and views in descendants: - One controller per every descendant; - Controller inheritance; - Generic controller; - Generic methods in one controller. Or maybe there is an another way? My ORM is NHibernate, I have a generic base repository and every repository is its descedant. Using generic controller, I think, is the best way, but in it I will use only generic base repository and extensibility of the system will be not very good. Please, help the newbie)

    Read the article

  • ORDER BY in a Sql Server 2008 view

    - by eidylon
    Hi all... we have a view in our database which has an ORDER BY in it. Now, I realize views generally don't order, because different people may use it for different things, and want it differently ordered. This view however is used for a VERY SPECIFIC use-case which demands a certain order. (It is team standings for a soccer league.) The database is Sql Server 2008 Express, v.10.0.1763.0 on a Windows Server 2003 R2 box. The view is defined as such: CREATE VIEW season.CurrentStandingsOrdered AS SELECT TOP 100 PERCENT *, season.GetRanking(TEAMID) RANKING FROM season.CurrentStandings ORDER BY GENDER, TEAMYEAR, CODE, POINTS DESC, FORFEITS, GOALS_AGAINST, GOALS_FOR DESC, DIFFERENTIAL, RANKING It returns: GENDER, TEAMYEAR, CODE, TEAMID, CLUB, NAME, WINS, LOSSES, TIES, GOALS_FOR, GOALS_AGAINST, DIFFERENTIAL, POINTS, FORFEITS, RANKING Now, when I run a SELECT against the view, it orders the results by GENDER, TEAMYEAR, CODE, TEAMID. Notice that it is ordering by TEAMID instead of POINTS as the order by clause specifies. However, if I copy the SQL statement and run it exactly as is in a new query window, it orders correctly as specified by the ORDER BY clause.

    Read the article

  • Passing models between controllers in MVC4

    - by wtfsven
    I'm in the middle of my first foray into web development with MVC4, and I've run into a problem that I just know is one of the core issues in web development in general, but can't seem to wrap my mind around it. So I have two models: Employee and Company. Employee has a Company, therefore /Employee/Create contains a field that is either a dropdown list for selecting an existing Company, or an ActionLink to /Company/Create if none exists. But here's the issue: If a user has to create a Company, I need to preserve the existing Employee model across both Views--over to /Company/Create, then back to /Employee/Create. So my first approach was to pass the Employee model to /Company/Create with a @Html.ActionLink("Add...", "Create", "Organization", Model , null), but then when I get to Company's Create(Employee emp), all of emp's values are null. The second problem is that if I try to come back to /Employee/Create, I'd be passing back an Employee, which would resolve to the POST Action. Basically, the whole idea is to save the state of the /Employee/Create page, jump over to /Company/Create to create a Company record, then back to /Employee/Create to finish creating the Employee. I know there is a well understood solution to this because , but I can't seem to phase it well enough to get a good Google result out of it. I've though about using Session, but it seems like doing so would be a bit of a kludge. I'd really like an elegant solution to this.

    Read the article

  • KO3: How to deal with stylesheets and scriptfiles

    - by Svish
    I'm using Kohana 3 and it's template controller. My main site template controller currently looks something like this: <?php defined('SYSPATH') or die('No direct script access.'); abstract class Controller_SiteTemplate extends Controller_Template { public function before() { parent::before(); // Initialize default template variables $this->template->styles = Kohana::config('site.styles'); $this->template->scripts = Kohana::config('site.scripts'); $this->template->title = ''; $this->template->content = ''; } } And then in my template view I do: <?php # Styles foreach($styles as $file => $media) echo HTML::style($file, array('media' => $media)).PHP_EOL ?> <?php # Scripts foreach($scripts as $file) echo HTML::script($file).PHP_EOL ?> This works alright. The problem is that it requires the style- and script files to be added in the controller, which shouldn't really have to care about those. It also makes it a hassle if the views are done by someone else than me since they would have to fool around with the controller just to add a new stylesheet or a new script file. How can this be done in a better way? Just to clearify, what I am wondering is how to deal with page specific stylesheets and scripts. The default and site-wide ones I have no problem with fetching from a config file or just put directly in the template view. My issue is how to add custom ones for specific pages in a good way.

    Read the article

  • ServiceStack razor default page

    - by Tom
    Say I have 2 pages /NotADefault.cshtml /Views/Default.cshtml Question 1. Now I run it, page A always gets called implicitly as start-up default page no matter what I name it. Page B will only be called when I explicitly call localhost/View/Default. How do I make page B (the one in View folder) my default page? Question 2. I also have NotADefaultService.cs and DefaultService.cs. I give each page a Service class at the back. However, when page A is called NotADefaultService.cs never gets called. Only DefaultService.cs gets called when page B is called... My observation is that only the pages in the View folder will get their back-end service class working. Outside of View folder it doesn't work. Combining Q1 and Q2. How do I: Option 1. get the backend service class working under / root outside "View" folder? OR Option 2. appoint /View/Default.schtml as my default at start-up where the service class can be hit?

    Read the article

  • How can I abstract out the core functionality of several Rails applications?

    - by hornairs
    I'd like to develop a number of non-trivial Rails applications which all implement a core set of functionality but each have certain particular customizations, extensions, and aesthetic differences. How can I pull the core functionality (models, controllers, helpers, support classes, tests) common to all these systems out in such a way that updating the core will benefit every application based upon it? I've seen Rails Engines but they seem to be too detached, almost too abstracted to be built upon. I can seem them being useful for adding one component to an existing app, for example bolting on a blog engine to your existing e-commerce site. Since engines seem to be mostly self contained, it seems difficult and inconvenient to override their functionality and views while keeping DRY. I've also considered abstracting the code into a gem, but this seems a little odd. Do I make the gem depend on the Rails gems, and the define models & controllers inside it, and then subclass them in my various applications? Or do I define many modules inside the gem that I include in the different spots inside my various applications? How do I test the gem and then test the set of customizations and overridden functionality on top of it? I'm also concerned with how I'll develop the gem and the Rails apps in tandem, can I vendor a git repository of the gem into the app and push from that so I don't have to build a new gem every iteration? Also, are there private gem hosts/can I set my own gem source up? Also, any general suggestions for this kind of undertaking? Abstraction paradigms to adhere to? Required reading? Comments from the wise who have done this before? Thanks!

    Read the article

  • How to check at runtime if a class implements certain interface?

    - by mare
    Let's say I have some content classes like Page, TabGroup, Tab, etc. Certain of those will be implementing my IWidgetContainer interface - it means they will geet an additional field named ContainedItems from the interface and some methods for manipulating this field. Now I need to reflect the fact that some class implements this interface by rendering out some special custom controls in my ASP.NET MVC Views (like jQuery Add/Remove/Move/Reorder buttons). For instance, TabGroup will implement IWidgetContainer because it will contain tabs but a tab will not implement it because it won't have the ability to contain anything. So I have to somehow check in my view, when I render my content objects (The problem is, I use my base class as strong type in my view not concrete classes), whether it implements IWidgetContainer. How is that possible or have I completely missed something? To rephrase the question, how do you reflect some special properties of a class (like interface implementation) in the UI in general (not necessarily ASP.NET MVC)? Here's my code so far: [DataContract] public class ContentClass { [DataMember] public string Slug; [DataMember] public string Title; [DataMember] protected ContentType Type; } [DataContract] public class Group : ContentClass, IWidgetContainer { public Group() { Type = ContentType.TabGroup; } public ContentList ContainedItems { get; set; } public void AddContent(ContentListItem toAdd) { throw new NotImplementedException(); } public void RemoveContent(ContentListItem toRemove) { throw new NotImplementedException(); } } [DataContract] public class GroupElement : ContentClass { public GroupElement() { Type = ContentType.Tab; } } Interface: interface IWidgetContainer { [DataMember] ContentList ContainedItems { get; set; } void AddContent(ContentListItem toAdd); void RemoveContent(ContentListItem toRemove); }

    Read the article

  • Parameter meaning of CBasePin::GetMediaType(int iPosition, ...) method

    - by user325320
    Thanks to everyone who views my question. http://msdn.microsoft.com/en-us/library/windows/desktop/dd368709(v=vs.85).aspx It is not very clear from the documentation regarding the iPosition parameter for virtual HRESULT GetMediaType( int iPosition, CMediaType *pMediaType ); It is said "Zero-based index value.", but what kind of index it is? the index of the samples? I have a source filter sending the H.264 NALU flows (MEDIASUBTYPE_AVC1) and it works very well except that the SPS/PPS may be changed after the video is played for a while. The SPS and PPS are appended to the MPEG2VIDEOINFO structure, which is passed in CMediaType::SetFormat method when GetMediaType method is called. and there is another version of GetMediaType which accepts the iPosition parameter. It seems I can use this method to update the SPS / PPS. My question is: What does the iPosition param mean, and how does Decoder Filter know which SPS/PPS are assigned for each NALU sample. HRESULT GetMediaType(int iPosition, CMediaType *pMediaType) { ATLTRACE( "\nGetMediaType( iPosition = %d ) ", iPosition); CheckPointer(pMediaType,E_POINTER); CAutoLock lock(m_pFilter->pStateLock()); if (iPosition < 0) { return E_INVALIDARG; } if (iPosition == 0) { pMediaType->InitMediaType(); pMediaType->SetType(&MEDIATYPE_Video); pMediaType->SetFormatType(&FORMAT_MPEG2Video); pMediaType->SetSubtype(&MEDIASUBTYPE_AVC1); pMediaType->SetVariableSize(); } int nCurrentSampleID; DWORD dwSize = m_pFlvFile->GetVideoFormatBufferSize(nCurrentSampleID); LPBYTE pBuffer = pMediaType->ReallocFormatBuffer(dwSize); memcpy( pBuffer, m_pFlvFile->GetVideoFormatBuffer(nCurrentSampleID), dwSize); pMediaType->SetFormat(pBuffer, dwSize); return S_OK; }

    Read the article

  • Defining and using controller methods in ember.js

    - by OriginalEXE
    first of all, I am total noob when it comes to OOP in JS, this is new to me so treat me like a noob. I am building my first ember.js application and I am stuck (not the first time but I would get unstuck by myself, this is a tough one though). I have two models: forms entries Entries is of course in (one to many) relationship to forms, so each form can have as many properties. Form properties: id : DS.attr( 'number' ), title : DS.attr( 'string' ), views : DS.attr( 'number' ), conversion : DS.attr( 'number' ), entries : DS.hasMany( 'entry' ) Entry properties: id : DS.attr( 'number' ), parent_id: DS.belongsTo( 'form' ) Now, I have forms route that displays all forms in tabled view, and each table row has some info like form id, name etc. and that works great. What I wanted to do is display the number of entries each form has. I figured I should do that via controller, so here is my controller now: // Form controller App.FormController = Ember.ObjectController.extend({ entriescount: function() { var entries = this.get( 'store').find( 'entry' ); return entries.filterBy( 'parent_id', this.get( 'id' ) ).get( 'length' ); }.property( '[email protected]_id') }); Now for some reason, when I use {{entriescount}} in {{#each}} loop, this returns nothing. It also returns nothing in single form route. Note that in both cases, {{title}} for example works. I am wondering, am I going the right way by using controller for this, and how do I get controller to output the data. Thanks

    Read the article

  • Django Model Formset Pre-Filled Value Problem

    - by user552377
    Hi, i'm trying to use model formsets with Django. When i load forms template, i see that it's filled-up with previous values. Is there a caching mechanism that i should stop, or what? Thanks for your help, here is my code: models.py class FooModel( models.Model ): a_field = models.FloatField() b_field = models.FloatField() def __unicode__( self ): return self.a_field forms.py from django.forms.models import modelformset_factory FooFormSet = modelformset_factory(FooModel) views.py def foo_func(request): if request.method == 'POST': formset = FooFormSet(request.POST, request.FILES, prefix='foo_prefix' ) if formset.is_valid(): formset.save() return HttpResponseRedirect( '/true/' ) else: return HttpResponseRedirect( '/false/' ) else: formset = FooFormSet(prefix='foo_prefix') variables = RequestContext( request , { 'formset':formset , } ) return render_to_response('footemplate.html' , variables ) template: <form method="post" action="."> {% csrf_token %} <input type="submit" value="Submit" /> <table id="FormsetTable" border="0" cellpadding="0" cellspacing="0"> <tbody> {% for form in formset.forms %} <tr> <td>{{ form.a_field }}</td> <td>{{ form.b_field }}</td> </tr> {% endfor %} </tbody> </table> {{ formset.management_form }} </form>

    Read the article

  • Ajax and JSF 1.1 using hidden iframe with "proxy forms", what do you think about this development st

    - by Steel Plume
    Hi, currently I am using yet 1.1 specs, so I am trying to make simple what is too complex for me :p, managing backing beans with conflicting navigation rules, external params breaking rules and so on... for example when I need a backing bean used by other "views" simply I call it using FacesContext inside other backing beans, but often it's too wired up to JSF navigation/initialization rules to be really usable, and of course more simple is more useful become the FacesContext. So with only a bit of cross browser Javascript (simply a form copy and a read-write on a "proxy" form), I create a sort of proxy form inside the main user page (totally disassociated from JSF navigation rules, but using JSF taglibs). Ajax gives me flexibility on the user interaction, but data is always managed by JSF. Pratically I demand all "fictious" user actions to an hidden "iframe" which build up all needed forms according JSF rules, then a javascript simply clone its form output and put it into the user view level (CSS for showing/hiding real command buttons and making pretty), the user plays around and when he click submit, a script copies all "proxied" form values into the real JSF form inside the "iframe" that invokes the real submit of the form, what it returns is obviously dependent by your choice. Now JSF is really a pleasure :-p My real interest is to know what are your alternative strategy for using pure Ajax and JSF 1.1 without adopting middle layer like ajax4jsf and others, all good choices but too much "plugins" than specs.

    Read the article

  • Rails : can't write unknown attribute `url'

    - by user2954789
    I am new to ruby on rails,and I am learning by creating a blog. I am not able to save to my blogs table and I get this error "can't write unknown attribute url" Blogs migration :db/migrate/ class CreateBlogs < ActiveRecord::Migration --def change --- create_table :blogs do |t| ---- t.string :title ---- t.text :description ---- t.string :slug ---- t.timestamps --- end --end end Blogs Model :/app/models/blogs.rb class Blogs < ActiveRecord::Base --acts_as_url :title --def to_param ---url --end --validates :title, presence:true end Blogs Controller : /app/controllers/blogs_controller.rb class BlogsController < ApplicationController before_action :require_login --def new --- @blogs = Blogs.new --end --def show ---@blogs = Blogs.find(params[:id]) --end --def create ---@blogs = Blogs.new(blogs_params) --if @blogs.save ---flash[:success] = "Your Blog has been created." ---redirect_to home_path --else ---render 'new' --end -end --def blogs_params ---params.require(:blogs).permit(:title,:description) --end private --def require_login ---unless signed_in? ----flash[:error] = "You must be logged in to create a new Blog" ----redirect_to signin_path ---end --end end Blogs Form:/app/views/blogs/new.html.erb Blockquote <%= form_for @blogs, url: blogs_path do |f| %><br/> <%= render 'shared/error_messages_blogs' %><br/> <%= f.label :title %><br/> <%= f.text_field :title %><br/> <%= f.label :description %><br/> <%= f.text_area :description %><br/> <%= f.submit "Submit Blog", class: "btn btn-large btn-primary" %><br/> <% end %><br/> and I have also added "resources :blogs" to my routes.rb file. I get this error in controller at if @blogs.save

    Read the article

  • Should frontend and backend be handled by different controllers?

    - by DR
    In my previous learning projects I always used a single controller, but now I wonder if that is good practice or even always possible. In all RESTful Rails tutorials the controllers have a show, an edit and an index view. If an authorized user is logged on, the edit view becomes available and the index view shows additional data manipulation controls, like a delete button or a link to the edit view. Now I have a Rails application which falls exactly into this pattern, but the index view is not reusable: The normal user sees a flashy index page with lots of pictures, complex layout, no Javascript requirement, ... The Admin user index has a completly different minimalistic design, jQuery table and lots of additional data, ... Now I'm not sure how to handle this case. I can think of the following: Single controller, single view: The view is split into two large blocks/partials using an if statement. Single controller, two views: index and index_admin. Two different controllers: BookController and BookAdminController None of these solutions seems perfect, but for now I'm inclined to use the 3rd option. What's the preferred way to do this?

    Read the article

  • Using DisplayFor inside a display template

    - by Oenotria
    I've created a htmlhelper extension to reduce the amount of repetitive markup when creating forms: public static MvcHtmlString RenderField<TModel, TValue>(this HtmlHelper<TModel> htmlHelper, Expression<Func<TModel, TValue>> expression) { return htmlHelper.DisplayFor(expression, "formfield"); } The idea being that inside my views I can just write @Html.RenderField(x=>x.MyFieldName) and it will print the label and the field's content with the appropriate div tags in place already. Inside the displaytemplates folder I have created formfield.cshtml containing the following: <div class="display-group"> <div class="display-label"> @Html.LabelFor(x => x) </div> <div class="display-field"> @Html.DisplayFor(x => x) </div> </div> Unfortunately it doesn't appear that it is possible to nest DisplayFor inside a display template (it doesn't render anything). I don't want to just using @Model because then I won't get checkboxes for boolean values, calendar controls for dates etc. Is there a good way around this?

    Read the article

  • How to accommodate for the different screen resolution of iPhone 4?

    - by mystify
    This is a programming question! Read on before you vote to close! According to Apple, iPhone 4 has a new screen resolution: 3.5-inch (diagonal) widescreen Multi-Touch display 960-by-640-pixel resolution at 326 ppi This little detail affects our apps in a heavy way. Most of the demo apps on the net have one thing in common: They position views in the believe that the screen has a fixed size of 320 x 480 pixels. So what most -if not all- developers do is: They designed everything in such a way, that a touchable area is -for example- 50 x 50 pixels big. Just enough to tap it. Things have been positioned relative to the upper left, to reach a specific position on screen - let's say the center, or somewhere at the bottom. Edit: It seems Apple has integrated an switch that allows to tell if an app is highRes or not. Nice. When we develop high-resolution apps, probably they won't work on older devices. And if they did, they would suffer a lot from 4-times the size of any image, having to scale them down in memory. This is community wiki. Just add anything that you think is relevant to this huge problem (constant screen res was one of the main reasons why I didn't go for Android!!).

    Read the article

  • Determining Best Table Structure for MySQL Performance

    - by Joe Majewski
    I'm working on a browser-based RPG for one of my websites, and right now I'm trying to determine the best way to organize my SQL tables for performance and maintenance. Here's my question: Does the number of columns in an SQL table affect the speed in which it can be queried? I am not a newbie when it comes to PHP or MySQL. I used to develop things with the common goal of getting them to work, but I've recently advanced to the stage where a functional program is not good enough unless it's fast and reliable. Anyways, right now I have a members table that has around 15 columns. It contains information such as the player's username, password, email, logins, page views, etcetera. It doesn't contain any information on the player's progress in the game, however. If I added columns for things such as army size, gold, turns, and whatnot, then it could easily rise to around 40 or 50 total columns. Oh, and my database structure IS normalized. Will a table with 50 columns that gets constantly queried be a bad idea? Should I split it into two tables; one for the user's general information and one for the user's game statistics? I know I could check the query time myself, but I haven't actually created the tables yet and I think I'd be better off with some professional advice on this important decision for my game. Thank you for your time! :)

    Read the article

  • Unable to dismiss MFMailComposeViewController, delegate not called

    - by Rod
    HI, I am calling MFMailComposeViewController from UITableViewController. Problem is, delegate method mailComposeController:(MFMailComposeViewController)controllerdidFinishWithResult* is never called when I select Cancel or Send button in Mail compose window. Here is the table view class: @implementation DetailsTableViewController - (void)tableView:(UITableView *)tableView didSelectRowAtIndexPath:(NSIndexPath *)indexPath { if (indexPath.section==0 && indexPath.row==4){ //SEND MAIL MFMailComposeViewController *controller = [[MFMailComposeViewController alloc] init]; controller.mailComposeDelegate = self; if ([MFMailComposeViewController canSendMail]) { [controller setSubject:[NSString stringWithFormat:@"Ref %@",[item objectForKey:@"reference"]]]; [controller setMessageBody:@" " isHTML:NO]; [controller setToRecipients:[NSArray arrayWithObject:[item objectForKey:@"email"]]]; [self presentModalViewController:controller animated:YES]; } [controller release]; } } - (void)mailComposeController:(MFMailComposeViewController*)controllerdidFinishWithResult:(MFMailComposeResult)result error:(NSError*)error { // NEVER REACHES THIS PLACE [self dismissModalViewControllerAnimated:YES]; NSLog (@"mail finished"); } The application don't crash. After Cancel or Send button is presses Compose Window stays on the screen with buttons disabled. I can exit application pressing Home key. I am able to open other Modal Views form TableView but not MailCompose.

    Read the article

< Previous Page | 227 228 229 230 231 232 233 234 235 236 237 238  | Next Page >