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  • visusal studio embedded crystal report keeps prompting database login?

    - by phill
    I'm using visual studio 2005 to develop a form with a combobox passing a value into the parameter of an embedded crystal report. I'm trying to figure out why it keeps prompting me for a database login every single time you try to run the report with a different combobox selection. Here is my code: private Sub Form1_load... Dim ConnName As String Dim ServerName As String Dim DBName As String Dim user As String Dim pass As String Dim gDBA As ADODB.Connection Dim records As ADODB.Recordset Dim datver As ADODB.Recordset Dim query As String '---OPEN THE DATABASE CONNECTIONS gDBA = New ADODB.Connection ': gDBA.CursorLocation = adUseServer 'Added to prevent time out error gDBA.CommandTimeout = 1000 : gDBA.ConnectionTimeout = 1000 gDBA.ConnectionString = "Server=svr13;Database=subscribers;User ID=KViews;Password=Solution;Trusted_Connection=True;" gDBA.Open("Data Source=Kaseya;Initial Catalog=subscribers;User Id=KViews;Password=Solution;", "KViews", "Solution") records = New ADODB.Recordset query = "select distinct groupname from _v_k order by groupname desc" 'records.ActiveConnection = gDBA.ConnectionString records.CursorType = CursorTypeEnum.adOpenForwardOnly records.LockType = LockTypeEnum.adLockReadOnly records.Open(query, gDBA) Do While Not records.EOF ComboBox1.Items.Add(records.Fields("groupname").Value) records.MoveNext() Loop end Sub Private Sub Button1_Click(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles Button1.Click Dim selected As String selected = ComboBox1.Text Dim cryRpt As New ReportDocument cryRpt.Load("C:\Visual Studio 2005\Projects\WindowsApplication1\WindowsApplication1\CrystalReport1.rpt") cryRpt.SetDatabaseLogon("KViews", "Solutions", "svr13", "subscribers") cryRpt.SetParameterValue("companyname", selected) CrystalReportViewer1.ReportSource = cryRpt CrystalReportViewer1.Refresh() End Sub I looked at this previous posting http://stackoverflow.com/questions/1132314/database-login-prompt-with-crystal-reports but this wasn't very helpful. I couldn't find where a CMC was to disable the prompt. Any ideas? thanks in advance

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  • Running RSpec Files From ruby code

    - by Brian D.
    I'm trying to run RSpec tests straight from ruby code. More specifically, I'm running some mysql scripts, loading the rails test environment and then I want to run my rspec tests (which is what I'm having trouble with)... I'm trying to do this with a rake task. Here is my code so far: require"spec" require "spec/rake/spectask" RAILS_ENV = 'test' namespace :run_all_tests do desc "Run all of your tests" puts "Reseting test database..." system "mysql --user=root --password=dev < C:\\Brian\\Work\\Personal\\BrianSite\\database\\BrianSite_test_CreateScript.sql" puts "Filling database tables with test data..." system "mysql --user=root --password=dev < C:\\Brian\\Work\\Personal\\BrianSite\\database\\Fill_Test_Tables.sql" puts "Starting rails test environment..." task :run => :environment do puts "RAILS_ENV is #{RAILS_ENV}" # Run rspec test files here... require "spec/models/blog_spec.rb" end end I thought the require "spec/models/blog_spec.rb" would do it, but the tests aren't running. Anyone know where I'm going wrong? Thanks for any help.

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  • Update database settings in properties file in Spring

    - by mvg
    Hi all, I am trying to create a Database Manager page which shows the database details on page load and updates the database settings when the user press submit I followed this tutorial and set the database settings in properties file. I managed to update the database settings in properties file programmatically. When I retrieved the database settings using the following code DriverManagerDataSource databaseSource = (DriverManagerDataSource)context.getBean("dataSource"); databaseSource.getUsername(); I managed to get the old value and unable to get the new value This is the mapping in applicationContext.xml file <bean class="org.springframework.beans.factory.config.PropertyPlaceholderConfigurer"> <property name="location"> <value>classpath:/bundle/database.properties</value> </property> </bean> <bean id="dataSource" class="org.springframework.jdbc.datasource.DriverManagerDataSource"> <property name="driverClassName" value="${jdbc.driverClassName}" /> <property name="url" value="${jdbc.url}" /> <property name="username" value="${jdbc.username}" /> <property name="password" value="${jdbc.password}" /> </bean> I checked the properties file and found it to be updated with the latest input. What am I missing? Thanks in advance P.S I am using JSF1.2 with Spring 3 Update Just making my requirement simple. I am creating a setparate dbsettings page, so that when user wishes to connect to different database he/she can just enter the details in dbsettings page and connect

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  • Maven build fails on an Ant FTP task failure

    - by fraido
    I'm using the FTP Ant task with maven-antrun-plugin <plugin> <groupId>org.apache.maven.plugins</groupId> <artifactId>maven-antrun-plugin</artifactId> <executions> <execution> <id>ftp</id> <phase>generate-resources</phase> <configuration> <tasks> <ftp action="get" server="${ftp.server.ip}" userid="${ftp.server.userid}" password="${ftp.server.password}" remotedir="${ftp.server.remotedir}" depends="yes" verbose="yes" skipFailedTransfers="true" ignoreNoncriticalErrors="true"> <fileset dir="target/test-classes/testdata"> <include name="**/*.html" /> </fileset> </ftp> </tasks> </configuration> <goals> <goal>run</goal> </goals> </execution> </executions> ... the problem is that my build fails when the folder ${ftp.server.remotedir} doesn't exist. I tried to specify skipFailedTransfers="true" ignoreNoncriticalErrors="true but these don't fix the problem and the build keeps failing. An Ant BuildException has occured: could not change remote directory: 550 /myBadDir: The system cannot find the file specified. Do you know how to instruct my maven build to don't care about this Ant task error

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  • Voting on Hacker News stories programmatically?

    - by igorgue
    I decided to write an app like: http://michaelgrinich.com/hackernews/ but for Android devices, my idea will use a web application backend (because I rather code in Python and for the web than completely in Java for Android devices). What I have right now implemented is something like this: $ curl -i http://localhost:8080/stories.json?page=1\&stories=1 HTTP/1.0 200 OK Date: Sun, 25 Apr 2010 07:59:37 GMT Server: WSGIServer/0.1 Python/2.6.5 Content-Length: 296 Content-Type: application/json [{"title": "Don\u2019t talk to aliens, warns Stephen Hawking", "url": "http://www.timesonline.co.uk/tol/news/science/space/article7107207.ece?", "unix_time": 1272175177, "comments": 15, "score": 38, "user": "chaostheory", "position": 1, "human_time": "Sun Apr 25 01:59:37 2010", "id": "1292241"}] The next step (and final I think) is voting, my design is doing something like this: $ curl -i http://localhost:8080/stories/1?vote=up -u username:password Will vote up and: $ curl -i http://localhost:8080/stories/1?vote=down -u username:password Down. I have no idea how to do it though... I was planning to use Twill but the login link is always different, e.g.: http://news.ycombinator.com/x?fnid=7u89ccHKln Later the Android app will consume this API. Any experience with programmatically browsing Hacker News?

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  • How to process AJAX requests more securely in PHP?

    - by animuson
    Ok, so I want to send AJAX requests to my website from my Flash games to process data, but I don't want people downloading them, decompiling them, then sending fake requests to be processed, so I'm trying to figure out the most secure way to process in the PHP files. My first idea was to use Apache's built in Authorization module to require a username and password to access the pages on a separate subdomain of my website, but then you'd have to include that username and password in the AJAX request anyway so that seems kind of pointless to even try. My current option looks pretty promising but I want to make sure it will work. Basically it just checks the IP address being sent using REMOTE_ADDR to make sure it's the IP address that my server runs on. <? $allowed = new Array("64.120.211.89", "64.120.211.90"); if (!in_array($_SERVER['REMOTE_ADDR'], $allowed)) header("HTTP/1.1 403 Forbidden"); ?> Both of those IP addresses point to my server. Things I'm worried about: 1) If I send a request from Flash/ActionScript, will that affect the IP address in any way? 2) Is it possible for malicious users to change the IP address that is being sent with REMOTE_ADDR to one of my IP addresses? Any other ways you would suggest that might be more secure?

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  • Requirements for connecting to Oracle with JDBC?

    - by Lord Torgamus
    I'm a newbie to Java-related web development, and I can't seem to get a simple program with JDBC working. I'm using off-the-shelf Oracle 10g XE and the Eclipse EE IDE. From the books and web pages I've checked so far, I've narrowed the problem down to either an incorrectly written database URL or a missing JAR file. I'm getting the following error: java.sql.SQLException: No suitable driver found for jdbc:oracle://127.0.0.1:8080 with the following code: import java.sql.*; public class DatabaseTestOne { public static void main(String[] args) { String url = "jdbc:oracle://127.0.0.1:8080"; String username = "HR"; String password = "samplepass"; String sql = "SELECT EMPLOYEE_ID FROM EMPLOYEES WHERE LAST_NAME='King'"; Connection connection; try { connection = DriverManager.getConnection(url, username, password); Statement statement = connection.createStatement(); System.out.println(statement.execute(sql)); connection.close(); } catch (SQLException e) { System.err.println(e); } } } What is the proper format for a database URL, anyways? They're mentioned a lot but I haven't been able to find a description. Thanks! EDIT (the answer): Based on duffymo's answer, I got ojdbc14.jar from http://www.oracle.com/technology/software/tech/java/sqlj_jdbc/htdocs/jdbc_10201.html and dropped it in the Eclipse project's Referenced Libraries. Then I changed the start of the code to ... try { Class.forName("oracle.jdbc.driver.OracleDriver"); } catch (ClassNotFoundException e) { System.err.println(e); } // jdbc:oracle:thin:@<hostname>:<port>:<sid> String url = "jdbc:oracle:thin:@GalacticAC:1521:xe"; ... and it worked.

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  • Connect to a remote Oracle 11g server using OracleClient of .NET 2.0

    - by Raghu M
    I have to connect to a Oracle server on the network using a .NET / C# (Winform) application. I am trying to use System.Data.OracleClient but in vain. Here are the details I can possibly think of (that might help someone reading this question): Platform: Visual Studio 2005 / .NET 2.0 with C# on Windows Vista Home Premium Library: System.Data.OracleClient Server: Oracle 11g (located on the same LAN) Please note that I don't have Oracle installed locally and I have hunted every discussion forum possible for help - but most of them assume local Oracle installation! Here is my connection string: "User Id=TSUSER;Password=ts12TS;Data Source=(DESCRIPTION=(ADDRESS=(PROTOCOL=TCP)(HOST=MyServerIP)(PORT=1521))(CONNECT_DATA=(SERVICE_NAME=ORCL)));" And I get this error: OCIEnvCreate failed with return code -1 but error message text was not available. Stack trace: at System.Data.OracleClient.OciHandle..ctor(OciHandle parentHandle, HTYPE handleType, MODE ocimode, HANDLEFLAG handleflags) at System.Data.OracleClient.OracleInternalConnection.OpenOnLocalTransaction(String userName, String password, String serverName, Boolean integratedSecurity, Boolean unicode, Boolean omitOracleConnectionName) at System.Data.OracleClient.OracleInternalConnection..ctor(OracleConnectionString connectionOptions) at System.Data.OracleClient.OracleConnectionFactory.CreateConnection(DbConnectionOptions options, Object poolGroupProviderInfo, DbConnectionPool pool, DbConnection owningObject) at System.Data.ProviderBase.DbConnectionFactory.CreatePooledConnection(DbConnection owningConnection, DbConnectionPool pool, DbConnectionOptions options) at System.Data.ProviderBase.DbConnectionPool.CreateObject(DbConnection owningObject) at System.Data.ProviderBase.DbConnectionPool.UserCreateRequest(DbConnection owningObject) at System.Data.ProviderBase.DbConnectionPool.GetConnection(DbConnection owningObject) at System.Data.ProviderBase.DbConnectionFactory.GetConnection(DbConnection owningConnection) at System.Data.ProviderBase.DbConnectionClosed.OpenConnection(DbConnection outerConnection, DbConnectionFactory connectionFactory) at System.Data.OracleClient.OracleConnection.Open() at DGKit.Util.DataUtil.Generate() in D:\SVNRoot\sandbox\DGDev\Util\DataUtil.cs:line 68

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  • Configurating JOOMLA's e-mail notification for new account

    - by Dion
    I'm using Joomla 1.5 to create a local site for my office. The site will be accessed locally via intranet, and my PC will be the localhost for the site. I'm using a Login pluggin, so that anyone who wanted to enter the site should create an account. In JOOMLA, all user who created their account for the first time will receive a notification e-mail like : "Hello pras, You have been added as a User to Information Center by an Administrator. This e-mail contains your username and password to log in to http://localhost/yaddayadda/ Username: hadisuryo.prasetio Password: xxxx Please do not respond to this message as it is automatically generated and is for information purposes only." but if the user click the URL in the mail, which is, "localhost/yaddayadda/" they will not be directed to my site, but to their own PC's localhost.... My question is : How can I Modified the e-mail or the site configuration so that the URL will not be "localhost/yaddayadda/" anymore, but will be "(My-IP adress)/yaddayadda" I'm not going to host my site to a web hosting service, just using my PC as a host. I've been trying to trace on each config and .ini files...it seems that i have to do something with the "JURI" function or the "$mosConfig_live_site" on the backlink.php file $mosConfig_absolute_path = JPATH_SITE; $mosConfig_live_site = JURI :: base(); $url_array = explode('/', $_SERVER['REQUEST_URI']); Can anyone give me assistance ? Thank You

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  • Requested operation requires an OLE DB Session object... - Connecting Excel to SQL server via ADO

    - by Frank V
    I'm attempting to take Excel 2003 and connect it to SQL Server 2000 to run a few dynamicly generated SQL Queries which ultimately filling certain cells. I'm attempting to do this via VBA via ADO (I've tried 2.8 to 2.0) but I'm getting an error while setting the ActiveConnection variable which is inside the ADODB.Connection object. I need to resolve this pretty quick... Requested operation requires an OLE DB Session object, which is not supported by the current provider. I'm honestly not sure what this error means and right now I don't care. How can get this connection to succeed so that I can run my queries? Here is my VB code: Dim SQL As String, RetValue As String SQL = " select top 1 DateTimeValue from SrcTable where x='value' " 'Not the real SQL RetValue = "" Dim RS As ADODB.Recordset Dim Con As New ADODB.Connection Dim Cmd As New ADODB.Command Con.ConnectionString = "Provider=sqloledb;DRIVER=SQL Server;Data Source=Server\Instance;Initial Catalog=MyDB_DC;User Id=<UserName>;Password=<Password>;" Con.CommandTimeout = (60 * 30) Set Cmd.ActiveConnection = Con ''Error occurs here. ' I'm not sure if the rest is right. I've just coded it. Can't get past the line above. Cmd.CommandText = SQL Cmd.CommandType = adCmdText Con.Open Set RS = Cmd.Execute() If Not RS.EOF Then RetValue = RS(0).Value Debug.Print "RetValue is: " & RetValue End If Con.Close I imagine something is wrong with the connection string but I've tried over a dozen variations. Now I'm just shooting in the dark.... Note/Update: To make matters more confusing, if I Google for the error quote above, I get a lot of hits back but nothing seems relevant or I'm not sure what information is relevant.... I've got the VBA code in "Sheet1" under "Microsoft Excel Objects." I've done this before but usually put things in a module. Could this make a difference?

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  • setting default value of superglobal

    - by Prasoon Saurav
    I have been working on a Timesheet Management website. I have my home page as index.php //index.php <?php session_start(); if($_SESSION['logged']=='set') { $x=$_SESSION['username']; echo '<div align="right">'; echo 'Welcome ' .$x.'<br/>'; echo'<a href="logout.php" class="links">&nbsp;<b><u>Logout</u></b></a>' ; } else if($_SESSION['logged']='unset') { echo'<form id="searchform" method="post" action="processing.php"> <div> <div align="right"> Username&nbsp;<input type="text" name="username" id="s" size="15" value="" /> &nbsp;Password&nbsp;<input type="password" name="pass" id="s" size="15" value="" /> <input type="submit" name="submit" value="submit" /> </div> <br /> </div> </form> '; } ?> The problem I am facing is that during the first run of this script I get an error Notice: Undefined index: logged in C:\wamp\www\ps\index.php but after refreshing the page the error vanishes. How can I correct this problem? logged is a variable which helps determine whether the user is logged in or not. When the user is logged in $_SESSION['logged'] is set, otherwise unset. I want the default value of $_SESSION['logged'] to be unset prior to the execution of the script. How can I solve this problem?

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  • Connecting to database on web host in Visual Studio

    - by Anders Svensson
    I have a web site developed locally with a local Sql Server database. I also have a web host that provides one Sql Server database for my site. Now I want to deploy the application, and I would like to be able to manage the remote database from the Server Explorer in Visual Studio. I have the connection string used in the application, which works fine for adding, say, a datasource to a control etc. But I don't know if there's any way to use it to connect the database inside the Server Explorer so that I can add tables etc. I have read that you're supposed to be able to this instead of using the Sql Server Management Studio, but I have'nt read anything about how to connect to the remote database in it. What I have tried so far is this: I have selected Add database in Server Explorer. This brings up first a dialog where I choose Sql Server. And then I get a dialog where I can set Server name (which I tried using the ip address in the connection string below), and Authentication (where I chose Sql Server Authentication, with the user id and password from below). But when I test the connection it fails. Here's the connection string, which works fine when used for datasources in the application (obviously with different user name and password): Any help appreciated!

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  • Displaying emails in a JTable (Java Swing)

    - by Paul
    Hi I'm new to all this. I have been trying to display fetched emails in a JTable using the JavaMail add-on. However when I ask the program to set the value it never does. I have been working in NetBeans if that is any help? the fetchMail class finds all may on a server. The gui class is used to display all emails in a table as well as creating mail. You will probably think that I have tried it like a bull in a china shop, I am new to Java and trying to give myself a challenge. Any help/advice would be greatly appreciated fetchMail: package mail; import java.util.; import java.io.; import java.text.DateFormat; import java.text.SimpleDateFormat; import javax.mail.; import javax.mail.internet.; import javax.mail.search.; import javax.activation.; public class fetchMail { public void fetch(String username, String pass, String search){ MessagesTableModel tableModel = new MessagesTableModel(); String complete; DateFormat df = new SimpleDateFormat("dd/MM/yyyy"); gui gui = new gui(); // SUBSTITUTE YOUR ISP's POP3 SERVER HERE!!! String host = "imap.gmail.com"; // SUBSTITUTE YOUR USERNAME AND PASSWORD TO ACCESS E-MAIL HERE!!! String user = username; String password = pass; // SUBSTITUTE YOUR SUBJECT SUBSTRING TO SEARCH HERE!!! String subjectSubstringToSearch = search; // Get a session. Use a blank Properties object. Session session = Session.getInstance(new Properties()); Properties props = System.getProperties(); props.setProperty("mail.store.protocol", "imaps"); props.setProperty("mail.imap.socketFactory.class", "javax.net.ssl.SSLSocketFactory"); props.setProperty("mail.imap.socketFactory.fallback", "false"); try { // Get a Store object Store store = session.getStore("imaps"); store.connect(host, user, password); // Get "INBOX" Folder fldr = store.getFolder("INBOX"); fldr.open(Folder.READ_WRITE); int count = fldr.getMessageCount(); System.out.println(count + " total messages"); // Message numebers start at 1 for(int i = 1; i <= count; i++) { // Get a message by its sequence number Message m = fldr.getMessage(i); // Get some headers Date date = m.getSentDate(); int pos = i - 1; String d = df.format(date); Address [] from = m.getFrom(); String subj = m.getSubject(); String mimeType = m.getContentType(); complete = date + "\t" + from[0] + "\t" + subj + "\t" + mimeType; //tableModel.setMessages(m); gui.setDate(d, pos); // System.out.println(d + " " + i); } // Search for e-mails by some subject substring String pattern = subjectSubstringToSearch; SubjectTerm st = new SubjectTerm(pattern); // Get some message references Message [] found = fldr.search(st); System.out.println(found.length + " messages matched Subject pattern \"" + pattern + "\""); for (int i = 0; i < found.length; i++) { Message m = found[i]; // Get some headers Date date = m.getSentDate(); Address [] from = m.getFrom(); String subj = m.getSubject(); String mimeType = m.getContentType(); //System.out.println(date + "\t" + from[0] + "\t" + // subj + "\t" + mimeType); Object o = m.getContent(); if (o instanceof String) { // System.out.println("**This is a String Message**"); // System.out.println((String)o); } else if (o instanceof Multipart) { // System.out.print("**This is a Multipart Message. "); Multipart mp = (Multipart)o; int count3 = mp.getCount(); // System.out.println("It has " + count3 + // " BodyParts in it**"); for (int j = 0; j < count3; j++) { // Part are numbered starting at 0 BodyPart b = mp.getBodyPart(j); String mimeType2 = b.getContentType(); // System.out.println( "BodyPart " + (j + 1) + // " is of MimeType " + mimeType); Object o2 = b.getContent(); if (o2 instanceof String) { // System.out.println("**This is a String BodyPart**"); // System.out.println((String)o2); } else if (o2 instanceof Multipart) { // System.out.print( // "**This BodyPart is a nested Multipart. "); Multipart mp2 = (Multipart)o2; int count2 = mp2.getCount(); // System.out.println("It has " + count2 + // "further BodyParts in it**"); } else if (o2 instanceof InputStream) { // System.out.println( // "**This is an InputStream BodyPart**"); } } //End of for } else if (o instanceof InputStream) { // System.out.println("**This is an InputStream message**"); InputStream is = (InputStream)o; // Assumes character content (not binary images) int c; while ((c = is.read()) != -1) { // System.out.write(c); } } // Uncomment to set "delete" flag on the message //m.setFlag(Flags.Flag.DELETED,true); } //End of for // "true" actually deletes flagged messages from folder fldr.close(true); store.close(); } catch (MessagingException mex) { // Prints all nested (chained) exceptions as well mex.printStackTrace(); } catch (IOException ioex) { ioex.printStackTrace(); } } } gui: /* * gui.java * * Created on 13-May-2010, 18:29:30 */ package mail; import java.text.DateFormat; import java.text.FieldPosition; import java.text.ParsePosition; import java.text.SimpleDateFormat; import java.util.Date; import java.util.Vector; import javax.mail.Address; import javax.swing.JScrollPane; import javax.swing.JTable; import javax.swing.ListSelectionModel; import javax.swing.event.ListSelectionEvent; import javax.swing.event.ListSelectionListener; import javax.swing.event.TableModelListener; import javax.swing.table.DefaultTableModel; import javax.swing.table.TableModel; public class gui extends javax.swing.JFrame { private MessagesTableModel tableModel; // Table listing messages. private JTable table; String date; /** Creates new form gui */ public gui() { initComponents(); } @SuppressWarnings("unchecked") private void initComponents() { recieve = new javax.swing.JButton(); jButton1 = new javax.swing.JButton(); jScrollPane1 = new javax.swing.JScrollPane(); inboxTable = new javax.swing.JTable(); setDefaultCloseOperation(javax.swing.WindowConstants.EXIT_ON_CLOSE); recieve.setText("Receve"); recieve.addActionListener(new java.awt.event.ActionListener() { public void actionPerformed(java.awt.event.ActionEvent evt) { recieveActionPerformed(evt); } }); jButton1.setText("new"); jButton1.addActionListener(new java.awt.event.ActionListener() { public void actionPerformed(java.awt.event.ActionEvent evt) { jButton1ActionPerformed(evt); } }); inboxTable.setModel(new javax.swing.table.DefaultTableModel( new Object [][] { {null, null, null}, {null, null, null}, {null, null, null}, {null, null, null} }, new String [] { "Date", "subject", "sender" } ) { Class[] types = new Class [] { java.lang.String.class, java.lang.String.class, java.lang.String.class }; public Class getColumnClass(int columnIndex) { return types [columnIndex]; } }); jScrollPane1.setViewportView(inboxTable); inboxTable.getColumnModel().getColumn(0).setResizable(false); inboxTable.getColumnModel().getColumn(1).setResizable(false); inboxTable.getColumnModel().getColumn(2).setResizable(false); javax.swing.GroupLayout layout = new javax.swing.GroupLayout(getContentPane()); getContentPane().setLayout(layout); layout.setHorizontalGroup( layout.createParallelGroup(javax.swing.GroupLayout.Alignment.LEADING) .addGroup(layout.createSequentialGroup() .addGap(39, 39, 39) .addGroup(layout.createParallelGroup(javax.swing.GroupLayout.Alignment.LEADING) .addComponent(jScrollPane1, javax.swing.GroupLayout.PREFERRED_SIZE, 558, javax.swing.GroupLayout.PREFERRED_SIZE) .addGroup(layout.createSequentialGroup() .addComponent(recieve) .addGap(18, 18, 18) .addComponent(jButton1, javax.swing.GroupLayout.PREFERRED_SIZE, 75, javax.swing.GroupLayout.PREFERRED_SIZE))) .addGap(73, 73, 73)) ); layout.setVerticalGroup( layout.createParallelGroup(javax.swing.GroupLayout.Alignment.LEADING) .addGroup(layout.createSequentialGroup() .addGap(31, 31, 31) .addGroup(layout.createParallelGroup(javax.swing.GroupLayout.Alignment.BASELINE) .addComponent(recieve) .addComponent(jButton1)) .addGap(18, 18, 18) .addComponent(jScrollPane1, javax.swing.GroupLayout.PREFERRED_SIZE, 258, javax.swing.GroupLayout.PREFERRED_SIZE) .addContainerGap(179, Short.MAX_VALUE)) ); pack(); }// </editor-fold> private void recieveActionPerformed(java.awt.event.ActionEvent evt) { fetchMail fetch = new fetchMail(); fetch.fetch(email goes here, password goes here, search goes here); } private void jButton1ActionPerformed(java.awt.event.ActionEvent evt) { createMail create = new createMail(); centerW center = new centerW(); //create.attVis(); center.center(create); create.setVisible(true); } public void setDate(String Date, int pos){ //pos = pos + 1; String [] s = new String [5]; s[pos] = Date; inboxTable.setValueAt(Date, pos, 0); } public String getDate(){ return date; } /** * @param args the command line arguments */ public static void main(String args[]) { java.awt.EventQueue.invokeLater(new Runnable() { public void run() { new gui().setVisible(true); } }); } // Variables declaration - do not modify private javax.swing.JTable inboxTable; private javax.swing.JButton jButton1; private javax.swing.JScrollPane jScrollPane1; private javax.swing.JButton recieve; // End of variables declaration }

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  • Discussion - Allowing / blocking user access to pages (Client Side Only!) - Javascript / Jquery

    - by Ozaki
    TLDR Using plain HTML / Javascript (Client Side) I want to prevent viewing of certain pages. The user will have to type a username and password and depending on that they get access to different pages. Answers can NOT include server side whatsoever It does not matter if they can break it easily. There is no sensitive information etc. Also the target audience will not have access to internet OR probably know what a cookie is... At some point the user will have to type username / password.(I can define the cookie here) Currently I thought of using cookies to set a cookie for each page to say "true" / "false" but that would get messy with so many cookies. Or setting an array within a cookie for each page? I have div field "#Content" which as it looks encompasses all of my content on the page so blocking out content will be as simple as replacing it with ("sorry you don't have access") etc. For Example: $.cookie("Access","page1, page2, page3"{ expires: 1 }); I am looking for anyway to do this does not have to be with cookies. Would be nice to get a discussion of different ways this can be done. So the question is: What do YOU think would be a good way to go about doing this with client side validation?

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  • how avoids deadlock condition

    - by rima
    Hi I try to write a program like a compiler.In this case I must simulate these codes of SQLPL(This one can be just for example).for example in command prompt i wana do these: c:\> sqlplus .... Enter User-Name:(here we must enter username) xxxx Enter password:(same up)yyyyy ... sql>(now i want to send my sql command to shell)prompt "rima"; "rima" [<-output] sql> prompt "xxxx" sql> exit very simple. I try to use this code: ProcessStartInfo psi = new ProcessStartInfo( @"sqlplus"); psi.UseShellExecute = false; psi.CreateNoWindow = true; psi.RedirectStandardInput = true; psi.RedirectStandardOutput = true; //psi.RedirectStandardError = true; Process process = new Process(); process.StartInfo = psi; bool started = process.Start(); if (started) { process.StandardInput.WriteLine("user/password"); process.StandardInput.Flush(); string ret = process.StandardOutput.ReadLine(); // <-- stalls here System.Console.WriteLine("sqlplus says :" + ret + "\"."); } i find out it form here but as if u read this code has problem!DEADLOCK Condition problem! this is my second time i ask my question,every time my knowledge growing,but i cant get how I can solve my problem at last!!! So I kindly kiss your hand,please help me,these process is not clear for me.any one can give me a code that handle my problem?Already i look at all codes,also I try to use ProcessRunner that in my last post some one offer me,but I cant use it also,i receive an error. I hope by first example u find out what i want,and solve the second code problem... thanks I use C# for implemantation

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  • What is wrong with accessing DBI directly?

    - by canavanin
    Hi everyone! I'm currently reading Effective Perl Programming (2nd edition). I have come across a piece of code which was described as being poorly written, but I don't yet understand what's so bad about it, or how it should be improved. It would be great if someone could explain the matter to me. Here's the code in question: sub sum_values_per_key { my ( $class, $dsn, $user, $password, $parameters ) = @_; my %results; my $dbh = DBI->connect( $dsn, $user, $password, $parameters ); my $sth = $dbh->prepare( 'select key, calculate(value) from my_table'); $sth->execute(); # ... fill %results ... $sth->finish(); $dbh->disconnect(); return \%results; } The example comes from the chapter on testing your code (p. 324/325). The sentence that has left me wondering about how to improve the code is the following: Since the code was poorly written and accesses DBI directly, you'll have to create a fake DBI object to stand in for the real thing. I have probably not understood a lot of what the book has so far been trying to teach me, or I have skipped the section relevant for understanding what's bad practice about the above code... Well, thanks in advance for your help!

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  • Java to C# code converter

    - by acadia
    Hello, Are there any converters available that converts Java code to C#? I need to convert the below code into C# String token = new String(""); URL url1 =new URL( "http", domain, Integer.valueOf(portnum), "/Workplace/setCredentials?op=getUserToken&userId="+username+"&password="+password +"&verify=true"); URLConnection conn1=url1.openConnection(); ((HttpURLConnection)conn1).setRequestMethod("POST"); InputStream contentFileUrlStream = conn1.getInputStream(); BufferedReader br = new BufferedReader(new InputStreamReader(contentFileUrlStream)); token=br.readLine(); String encodedAPIToken = URLEncoder.encode(token); String doubleEncodedAPIToken ="ut=" + encodedAPIToken;//.substring(0, encodedAPIToken.length()-1); //String doubleEncodedAPIToken ="ut=" + URLEncoder.encode(encodedAPIToken); //String userToken = "ut=" + URLEncoder.encode(token, "UTF-8"); //URLEncoder.encode(token); String vsId = "vsId=" + URLEncoder.encode(docId.substring(5, docId.length()), "UTF-8"); url="http://" + domain + ":" + portnum + "/Workplace/getContent?objectStoreName=RMROS&objectType=document&" + vsId + "&" +doubleEncodedAPIToken; String vsId = "vsId=" + URLEncoder.encode(docId.substring(5, docId.length()), "UTF-8"); url="http://" + domain + ":" + portnum + "/Workplace/getContent?objectStoreName=RMROS&objectType=document&" + vsId + "&" +doubleEncodedAPIToken; Thanks in advance

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  • Google Spreadsheet API problem: memory exceeded

    - by Robbert
    Hi guys, Don't know if anyone has experience with the Google Spreadsheets API or the Zend_GData classes but it's worth a go: When I try to insert a value in a 750 row spreadsheet, it takes ages and then throws an error that my memory limit (which is 128 MB!) was exceeded. I also got this when querying all records of this spreadsheet but this I can imaging because it's quite a lot of data. But why does this happen when inserting a row? That's not too complex, is it? Here's the code I used: public function insertIntoSpreadsheet($username, $password, $spreadSheetId, $data = array()) { $service = Zend_Gdata_Spreadsheets::AUTH_SERVICE_NAME; $client = Zend_Gdata_ClientLogin::getHttpClient($username, $password, $service); $client->setConfig(array( 'timeout' => 240 )); $service = new Zend_Gdata_Spreadsheets($client); if (count($data) == 0) { die("No valid data"); } try { $newEntry = $service->insertRow($data, $spreadSheetId); return true; } catch (Exception $e) { return false; } }

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  • How to get database table header information into an CSV File.

    - by Rachel
    I am trying to connect to the database and get current state of a table and update that information into csv file, with below mentioned piece of code, am able to get data information into csv file but am not able to get header information from database table into csv file. So my questions is How can I get Database Table Header information into an CSV File ? $config['database'] = 'sakila'; $config['host'] = 'localhost'; $config['username'] = 'root'; $config['password'] = ''; $d = new PDO('mysql:dbname='.$config['database'].';host='.$config['host'], $config['username'], $config['password']); $query = "SELECT * FROM actor"; $stmt = $d->prepare($query); // Execute the statement $stmt->execute(); var_dump($stmt->fetch(PDO::FETCH_ASSOC)); $data = fopen('file.csv', 'w'); while ($row = $stmt->fetch(PDO::FETCH_ASSOC)) { echo "Hi"; // Export every row to a file fputcsv($data, $row); } Header information meaning: Vehicle Build Model car 2009 Toyota jeep 2007 Mahindra So header information for this would be Vehicle Build Model Any guidance would be highly appreciated.

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  • How do I use Perl's LWP to log in to a web application?

    - by maxjackie
    I would like to write a script to login to a web application and then move to other parts of the application: use HTTP::Request::Common qw(POST); use LWP::UserAgent; use Data::Dumper; $ua = LWP::UserAgent->new(keep_alive=>1); my $req = POST "http://example.com:5002/index.php", [ user_name => 'username', user_password => "password", module => 'Users', action => 'Authenticate', return_module => 'Users', return_action => 'Login', ]; my $res = $ua->request($req); print Dumper(\$res); if ( $res->is_success ) { print $res->as_string; } When I try this code I am not able to login to the application. The HTTP status code returned is 302 that is found, but with no data. If I post username/password with all required things then it should return the home page of the application and keep the connection live to move other parts of the application.

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  • Handling responses in libcurl

    - by sfactor
    i have a code to send a Form Post with login credentials to a webpage. it looks like this CURL *curl; CURLcode res; struct curl_httppost *formpost=NULL; struct curl_httppost *lastptr=NULL; struct curl_slist *headerlist=NULL; static const char buf[] = "Expect:"; curl_global_init(CURL_GLOBAL_ALL); /* Fill in the username */ curl_formadd(&formpost, &lastptr, CURLFORM_COPYNAME, "user", CURLFORM_COPYCONTENTS, "username", CURLFORM_END); /* Fill in the password */ curl_formadd(&formpost, &lastptr, CURLFORM_COPYNAME, "pass", CURLFORM_COPYCONTENTS, "password", CURLFORM_END); /* Fill in the submit field too, even if this is rarely needed */ curl_formadd(&formpost, &lastptr, CURLFORM_COPYNAME, "submit", CURLFORM_COPYCONTENTS, "send", CURLFORM_END); curl = curl_easy_init(); /* initalize custom header list (stating that Expect: 100-continue is not wanted */ headerlist = curl_slist_append(headerlist, buf); if(curl) { /* what URL that receives this POST */ curl_easy_setopt(curl, CURLOPT_URL, "http://127.0.0.1:8000/index.html"); /* only disable 100-continue header if explicitly requested */ curl_easy_setopt(curl, CURLOPT_HTTPHEADER, headerlist); curl_easy_setopt(curl, CURLOPT_HTTPPOST, formpost); res = curl_easy_perform(curl); /* always cleanup */ curl_easy_cleanup(curl); /* then cleanup the formpost chain */ curl_formfree(formpost); /* free slist */ curl_slist_free_all (headerlist); } now i need to know is how do i handle the responses i get back from the server? i need to store the response into a string and then work on it.

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  • iPad keyboard will not dismiss if navigation controller presentation style is "form sheet".

    - by Kalle
    UPDATE: This is apparently "works as intended" classed by Apple. See accepted answer below for details. Update: this question is about a behavior discovered in the iPad keyboard, where it refuses to be dismissed if shown in a modal dialog with a navigation controller. Basically, if I present the navigation controller with the following line: navigationController.modalPresentationStyle = UIModalPresentationFormSheet; The keyboard refuses to be dismissed. If I comment out this line, the keyboard goes away fine. ... I've got two textFields, username and password; username has a Next button and password has a Done button. The keyboard won't go away if I present this in a modal navigation controller. WORKS broken *b = [[broken alloc] initWithNibName:@"broken" bundle:nil]; [self.view addSubview:b.view]; DOES NOT WORK broken *b = [[broken alloc] initWithNibName:@"broken" bundle:nil]; UINavigationController *navigationController = [[UINavigationController alloc] initWithRootViewController:b]; navigationController.modalPresentationStyle = UIModalPresentationFormSheet; navigationController.modalTransitionStyle = UIModalTransitionStyleFlipHorizontal; [self presentModalViewController:navigationController animated:YES]; [navigationController release]; [b release]; If I remove the navigation controller part and present 'b' as a modal view controller by itself, it works. Is the navigation controller the problem? WORKS broken *b = [[broken alloc] initWithNibName:@"broken" bundle:nil]; b.modalTransitionStyle = UIModalTransitionStyleFlipHorizontal; [self presentModalViewController:b animated:YES]; [b release]; WORKS broken *b = [[broken alloc] initWithNibName:@"broken" bundle:nil]; UINavigationController *navigationController = [[UINavigationController alloc] initWithRootViewController:b]; [self presentModalViewController:navigationController animated:YES]; [navigationController release]; [b release];

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  • C# WebBrowser Invoke issue

    - by James Jeffrey
    I am logging into facebook using a web browser. Everything works, but the problem is when I invoke the button click I need to check if the password is correct but, the check seems to happen before the button is invoked which makes no sense at all because the checking code is after the invoke. private void Facebook_Login(String username, String password) { webBrowser1.Url = new Uri("http://m.facebook.com"); while (webBrowser1.ReadyState != WebBrowserReadyState.Complete) Application.DoEvents(); HtmlElementCollection inputs = webBrowser1.Document.GetElementsByTagName("input"); foreach(HtmlElement input in inputs) { if (input.GetAttribute("name") == "email") { input.SetAttribute("value", "[email protected]"); } if (input.GetAttribute("name") == "pass") { input.SetAttribute("value", "kelaroostj"); // dont worry that pass wont work lol. } if (input.GetAttribute("name") == "login") { input.InvokeMember("click"); } } while (webBrowser1.ReadyState != WebBrowserReadyState.Complete) Application.DoEvents(); HtmlElementCollection bs = webBrowser1.Document.GetElementsByTagName("b"); foreach(HtmlElement b in bs) { MessageBox.Show(b.InnerHtml); } Log_Message("Logged into Facebook with: [email protected]"); }

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  • ASP.NET Login Control rejects users who exist

    - by rsteckly
    Hi, I'm having some trouble with the ASP.NET 2.0 Login Control. I've setup a database with the aspI.net regsql tool. I've checked the application name. It is set to "/". The application can access the SQL Server. In fact, when I go to retrieve the password, it will even send me the password. Despite this, the login control continues to reject logins. I added this to the web.config: <membership defaultProvider="AspNetSqlProvider"> <providers> <clear/> <add name="AspNetSqlProvider" connectionStringName="LocalSqlServer" applicationName="/" type="System.Web.Security.SqlMembershipProvider, System.Web, Version=2.0.0.0, Culture=neutral, PublicKeyToken=b03f5f7f11d50a3a"/> </providers> And I added the following to my connection strings: <remove name="LocalSqlServer" /> <add name="LocalSqlServer" connectionString="Data Source=IDC-4\EXCALIBUR;Initial Catalog=allied_nr;Integrated Security=True;Asynchronous Processing=True"/> (Note the "remove name" is to get rid of the default connection string in the App_Data directory.) Why won't the login control authenticate users?

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  • Android - Loop Through strings.xml file

    - by Alexis Cartier
    I was wondering if there is anyway to loop through the strings.xml file. Let's say that I have the following format: <!-- FIRST SECTION --> <string name="change_password">Change Password</string> <string name="change_server">Change URL</string> <string name="default_password">password</string> <string name="default_server">http://xxx:8080</string> <string name="default_username">testPhoneAccount</string> <!-- SECOND SECTION --> <string name="debug_settings_category">Debug Settings</string> <string name="reload_data_every_startup_pref">reload_data_every_startup</string> <string name="reload_data_on_first_startup_pref">reload_data_on_first_startup</string> Now let's say I have this: private HashMap<String,Integer> hashmapStringValues = new HashMap<String, Integer>(); Is there a way to iterate only in the second section of my xml file? Maybe wrap the section with a tag like <section2> and then iterate through it? public void initHashMap(){ for (int i=0;i< ???? ;i++) //Here I need to loop only in the second section of my xml file { String nameOfTag = ? // Here I get the name of the tag int value = R.string.nameOfTag // Here I get the associated value of the tag this.hashmapStringValues.put(nameOfTag,value); } }

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