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  • Would this jQuery is.(":hidden") work?

    - by AtiKuSDesign
    Hi guys, I'm playing around with the 'is' filter in jQuery and I am currently without the opportunity to use a testing server. What I want to know is...would this work to display both hello and goodbye? $(document).ready(function(){ if ($("p").is(':visible')) { $(this).css('display','block'); } }); <p>hello</p> <p style="display:none">goodbye</p> Basically what I want to do is run an action on something when it is visible but not run it when it isn't. Thanks guys

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  • How do I get the response time from a jQuery ajax call?

    - by Dumpen
    So I am working on tool that can show long a request to a page is taking. I am doing this by using jQuery Ajax (http://api.jquery.com/jQuery.ajax/) and I want to figure out the best way to get the response time. I found a thread (http://forum.jquery.com/topic/jquery-get-time-of-ajax-post) which describes using the "Date" in JavaScript, but is this method really reliable? An example of my code could be this below $.ajax({ type: "POST", url: "some.php", }).done(function () { // Here I want to get the how long it took to load some.php and use it further });

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  • jQuery - now: Creating an object and storing values in it to pass to an AJAX call

    - by Josh K
    I have an array: myarr = []; I'm filling it with some values: myarray['name'] = "Me!"; Now I want to transform that array into a set of Key = Value pairs. I though jQuery would do it automatically, but it doesn't seem to. $.ajax ({ type: "POST", dataType: "text", url: "myurl", data: myarr }); Is there a way to do this or something I'm doing wrong? I get no javascript errors, and no serverside errors other then no POST information at all. I need the request to be sent as a true POST request. I need to keep the php code simple because sometimes the login won't be an AJAX call. I'm now trying the following with an error unexepected token ':' myarr: { 'name':'me' } The question has now become: How do I initialize a new javascript object as "blank", how do I set up mappings, and how do I pass it in an AJAX call?

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  • Patterns for avoiding jQuery silent fails

    - by Matias
    Is there any good practice to avoid your jQuery code silently fail? For example: $('.this #is:my(complexSelector)').doSomething(); I know that every time this line get executed, the selector is intended to match at least one element, or certain amount of elements. Is there any standard or good way to validate that? I thought about something like this: var $matchedElements = $('.this #is:my(complexSelector)'); if ($matchedElements.length < 0) throw 'No matched elements'; $matchedElements.doSomething(); Also I think unit testing would be a valid option instead of messing the code. My question may be silly, but I wonder whether there is a better option than the things that I'm currently doing or not. Also, maybe I'm in the wrong way checking if any element match my selector. However, as the page continues growing, the selectors could stop matching some elements and pieces of functionality could stop working inadvertently.

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  • auto reload: how it works?

    - by Syom
    i need to change something in my site, if some fields changed in database, but without reloading the page! but i have no idea how i can do it. could you give me an idea? thanks

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  • Expanding videoplayer like CNN-website, prerably jQuery-based

    - by Nils
    I'm wondering if anyone knows of a script/plugin, jquery-based or otherwise, which could be used to achive the effect that can be found on CNN.com. I'm talking about the videos that are representet by a small thumbnail, that when clicked expands in to the text and plays. I'm by no means a JS-guru, and me and flash isn't the bestest of friends, but I'm not completly cluess. Essentially, what im looking for is a way to click a thumbnail, expand a swf, and stop it if i contract it again. something like that. ANY ideas, tips or insights are welcome!

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  • JQuery - remove the chars not matching regEx

    - by JQueryBeginner
    Hi All, I am trying to use jquery for validating forms. This is the pattern that is allowed in a text box for a user. var pattern = /^[a-zA-Z0-9!#$&%*+,-./: ;=?@_]/g; If the user types anything else other than this then that has to be replaced with a "". $(document).ready(function() { $('#iBox').blur(function() { var jVal = $('#iBox').val(); if(jVal.match(pattern)) { alert("Valid"); } else { alert("New "+jVal.replace(!(pattern),"")); } }); }); }); But the replace function does not work this way.

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  • jquery dynamic stracture with Eq

    - by mapet
    i want to make a single submission with dynamic jquery script but it doesn't worked what wrong with my code? $(document).ready(function(){ $("#foo").each( function( i ) { $("button#foo").eq(i).click(function() { var a = this.value(); alert(a); }); }); }); <div id="tabs-1"><input type="type" value="one"><button id="foo"></button></div> <div id="tabs-2"><input type="type" value="two"><button id="foo"></button></div> <div id="tabs-3"><input type="type" value="tree"><button id="foo"></button></div> thanks mapet

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  • Accessing a variable passed by jquery using php

    - by celenius
    How does php access a variable passed by JQuery? I have the following code: $.post("getLatLong.php", { latitude: 500000}, function(data){ alert("Data Loaded: " + data); }); but I don't understand how to access this value using php. I've tried $userLat=$_GET["latitude"]; and $userLat=$_GET[latitude]; and then I try to print out the value (to check that it worked) using: echo $userLat; but it does not return anything. I can't figure out how to access what is being passed to it.

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  • jQuery Supersized Plugin callback when slideshow finishd

    - by Nic Hubbard
    I am using the Supersized jQuery plugin which makes images fullscreen and also implements a slideshow. Currently, this plugin does not have a callback for when the slideshow is finished, rather, it just continually repeats. Is there a way that I could trigger a function after the last slide is shown? Currently, I have it working to trigger a function when the last slide STARTS to be shown, as I have a setInterval which checks for the "last" class on the slideshow images. But, this runs the function when that last slide starts, not when it is finished. Does anyone have ideas on how I could accomplish this?

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  • Using Jquery to check if a URL is valid

    - by user102533
    A long running background process creates a text file to indicate the completion of the process. From the frontend, I'd need to check every few seconds if the text file has been created or not. I am doing this check from However the file is created in http://DomainB.com/Mytext.txt Can someone help me write a jquery script that checks for a file across domain? PS: Currently, I am doing a ajax postback that executes a WebMethod in ASP.NET that creates HttpWebRequest. This works functionally, but I have major performance problems. So, I need a light weight way of finding if a URL is valid or not.

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  • jQuery fadeTo not working in IE8

    - by Lynda
    I have a div fading in using fadeTo. It works great in Firefox and IE9. It does not work in IE8. Here is my code: JS: var $j = jQuery.noConflict(); window.onload = function(){ $j('#fadein').fadeTo(6000, 1, function() { }); }; HTML <div class="img-center" id="fadein" style="opacity:0;"> <img src="src.jpg" alt="Text" class="feature-image" /> </div> How do I get this to work in IE8? I do not mind changing from fadeTo to fadeIn or some other method of fading in a div as long as it works in IE8.

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  • jQuery .each() with Array

    - by John Crain
    Basically, I am trying to gather the IDs of every element with a specific class and place those IDs into an array. I'm using jQuery 1.4.1 and have tried using .each(), but don't really understand it or how to pass the array out of the function. $('a#submitarray').click(function(){ var datearray = new Array(); $('.selected').each(function(){ datearray.push($(this).attr('id')); }); // AJAX code to send datearray to process.php file }); I'm sure I'm way off, as I'm pretty new at this, so any advice help would be awesome. Thanks!

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  • Pass Success variable to code

    - by João Dias
    How can I pass a variable that has been calculated in the success callback of an ajax function, to the document.ready ? I have this code function loadActions() { var countDiv; $.ajax({ type: "POST", cache: false, url:"modules/actions/actions.php", success : function (data) { $("#actions-container").html(data); $('.action-details').hide(); countDiv = $('.action-tab-odd').length + $('.action-tab-even').length ; } }); return countDiv; } $(document).ready(function(){ var count = loadActions(); }); But count is allways undefined. How can I get this to work? Thank you

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  • Mysql Query is not working in edited jTable code, why?

    - by Furkan Kadioglu
    I'm using this example: www.jtable.org I've downloaded the jTable PHP version. I then edited the script. The jTable simple version is working, but my edited version isn't. I can create a list, but I can't add a row; this code is causing problems. However, PHP doesn't display any error messages. else if($_GET["action"] == "create") { //Insert record into database $result = mysql_query("INSERT INTO veriler(bolge, sehir, firma, adres, tel, web) VALUES('" . $_POST["bolge"] . "', '" . $_POST["sehir"] . "', '" . $_POST["firma"] . "', '" . $_POST["adres"] . "', '" . $_POST["tel"] . "', '" . $_POST["web"] . "'"); //Get last inserted record (to return to jTable) $result = mysql_query("SELECT * FROM veriler WHERE id = LAST_INSERT_ID();"); $row = mysql_fetch_array($result); //Return result to jTable $jTableResult = array(); $jTableResult['Result'] = "OK"; $jTableResult['Record'] = $row; print json_encode($jTableResult); } What is the problem?

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  • jquery beginner: change background on click

    - by user1873217
    I'm trying to change the background of an element on click based on the current color. Here's the relevant html: <div id="rect" style="height: 100px; width:300px; background: red"> </div> and my jquery attempt: $("#rect").click(function() { if ($(this).css('background') == 'red') { $(this).css('background','blue');} else {$(this).css('background','yellow');} }); I'm always getting a yellow box; the 'true' condition never fires. What am I doing wrong?

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  • jQuery ajax Data Sent to Controller are Empty only in IE

    - by saman gholami
    This is my jQuery code : $.ajax({ url: "/Ajax/GetConcertTime", type: "POST", cache: false, data: { concertID: concertID.replace("ct", ""), date: selectedDateValue }, success: function (dataFromServer) { //some codes ... }, error: function (a, b, c) { alert(c); } }); And this is my controller code for catching parameters : [HttpPost] public ActionResult GetConcertTime(string concertId, string date) { int cid = Convert.ToInt32(concertId); try { MelliConcertEntities db = new MelliConcertEntities(); var lst = (from x in db.Showtimes where x.Concert.ID == cid && x.ShowtimeDate.Equals(date) && x.IsActive == true select x.ShowtimeTime).Distinct().ToList(); JavaScriptSerializer js = new JavaScriptSerializer(); return Content(js.Serialize(lst)); } catch (Exception ex) { return Content(ex.Message); } } After debugging i know the parameters in Controller (concertId and date) are empty when i useing IE browser.but in other browser it's work properly. What should i do for this issue?

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  • Jquery – Append selected items in spans

    - by criley
    Hi. I'm trying to select all elements that have a class, get their ID's (if they have one), and append individual spans to the end of my document based on that information. This is as far as I've managed to get: var element = $(".foo"), element_id = element.attr("id"), span_id = "for-" + element + "-id-" + element_id, ; I am hoping to append a span for each element gathered. Here are some examples of the span format I wish to achieve: <span id="for-img-id-profile"></span> <span id="for-div-id-content"></span> If possible, I would also like to allow for elements without an ID to be formatted like so: <span id="for-h1"></span> I really appreciate the help as I'm very new to jQuery and am trying to learn.

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  • JQuery: Remove duplicate elements?

    - by Keith Donegan
    Say I have a list of links with duplicate values as below: <a href="#">Book</a> <a href="#">Magazine</a> <a href="#">Book</a> <a href="#">Book</a> <a href="#">DVD</a> <a href="#">DVD</a> <a href="#">DVD</a> <a href="#">Book</a> How would I, using JQuery, remove the dups and be left with the following for example: <a href="#">Book</a> <a href="#">Magazine</a> <a href="#">DVD</a> Basically I am looking for a way to remove any duplicate values found and show 1 of each link.

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  • Can jQuery's fadeIn work without AJAX?

    - by Thierry Lam
    I'm submitting a form, sometimes I have some messages that I want to show to the user. I want those messages to jQuery fadeIn after they click on the submit button. Is it possible to achieve that if the submission doesn't involve any AJAX? Here's a sample Django/Python code: # View code message = 'feedback to user' # Template <div id="messages">{{ message }}</div> The equivalent PHP code of the above might be: <?php $message = 'feedback to user'; ?> <div id="messages"><?= $message ?></div> I want #messages above to fade in after a POST. How can I achieve that?

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  • Stopping jQuery Jumping to Newly Loaded Content.

    - by Damien
    I have a div with is replaced upon certain user actions. These actions are performed under the div that is being replaced and in the case that the div is too large to fit completely into the view window, along with the buttons used to change it underneath, the browser will jump to the top of the newly loaded div. Which is annoying. Does anyone know of a way to stop these? Cheers. Here is the jQuery code. ChartContent is a small blob of html function UpdateChartImage(ChartContent) { //do updates on div here var existingChart = $("#" + $(ChartContent).attr("id")); existingChart.fadeOut("fast", function() { existingChart.replaceWith(ChartContent); }).fadeIn("fast"); } Incidentally I have prevented the button from doing it's default behaviour so I don't think it's related to that.

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  • simple jquery image change onclick failing

    - by ian
    I have a simple jQuery image switch that is failing. $('.heart_img').click(function() { var heart_type = $(this).attr('src'); //alert( heart_type ); if ( heart_type == 'images/unheart.png') { //alert('uheart'); $(this).attr('src','images/heart.png'); } else if ( heart_type == 'images/heart.png'); { $(this).attr('src','images/unheart.png'); } }); The alerts fire correctly when not commented out so and the images are in the correct place so I am not sure what the problem is.

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  • can you use jquery lazyload on all images (not just ones out of view)

    - by ooo
    i have a webpage with a lot of images (photo album). I am using lazyloading jquery plugin which is great to only load the images out of browser view when i scroll down. The one issue i have is that i want the loading icon to show up first on images loading IN the current view as well as some of them are big images and they show up with that bad browser "image not loaded yet" icon until they download. I don't see any property on this plugin to support this for both in view and for scrolling. does anyone know if this is possible?

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  • jquery, simplemodal with a tooltip?

    - by matthewsteiner
    I'm using http://dev.mariusilie.net/content/simple-tooltip-jquery-plugin for my tooltip and simple modal for a modal window. I've got a link in the modal window and when I put my mouse over it, the tooltip is there, but it's beneath the modal window. I think it has to do with "z-index". I looked and I think the modal window is at 1000. I've set the #simpleTooltip property in the css with various z-index values, with no luck. It always appears beneath the modal window. Any Ideas?

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  • Toggled() text input field not working in IE6 in Jquery 1.3.2

    - by Michal
    In IE6 after showing() or toggling() an initially hidden text input field it is impossible to enter any text in the box. It is also impossible to focus() on the element. I am using jquery 1.3.2 Here is the code... Any ideas? $(document).ready(function(){ $(".hide").click(function(){ $(".form").toggle(); }) }) and HTML <form> <div class="hide"> Show </div> <div class="form" style="display:none"> <input type="text" name="crap"> </div> </form>

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