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  • Pain Comes Instantly

    - by user701213
    When I look back at recent blog entries – many of which are not all that current (more on where my available writing time is going later) – I am struck by how many of them focus on public policy or legislative issues instead of, say, the latest nefarious cyberattack or exploit (or everyone’s favorite new pastime: coining terms for the Coming Cyberpocalypse: “digital Pearl Harbor” is so 1941). Speaking of which, I personally hope evil hackers from Malefactoria will someday hack into my bathroom scale – which in a future time will be connected to the Internet because, gosh, wouldn’t it be great to have absolutely everything in your life Internet-enabled? – and recalibrate it so I’m 10 pounds thinner. The horror. In part, my focus on public policy is due to an admitted limitation of my skill set. I enjoy reading technical articles about exploits and cybersecurity trends, but writing a blog entry on those topics would take more research than I have time for and, quite honestly, doesn’t play to my strengths. The first rule of writing is “write what you know.” The bigger contributing factor to my recent paucity of blog entries is that more and more of my waking hours are spent engaging in “thrust and parry” activity involving emerging regulations of some sort or other. I’ve opined in earlier blogs about what constitutes good and reasonable public policy so nobody can accuse me of being reflexively anti-regulation. That said, you have so many cycles in the day, and most of us would rather spend it slaying actual dragons than participating in focus groups on whether dragons are really a problem, whether lassoing them (with organic, sustainable and recyclable lassos) is preferable to slaying them – after all, dragons are people, too - and whether we need lasso compliance auditors to make sure lassos are being used correctly and humanely. (A point that seems to evade many rule makers: slaying dragons actually accomplishes something, whereas talking about “approved dragon slaying procedures and requirements” wastes the time of those who are competent to dispatch actual dragons and who were doing so very well without the input of “dragon-slaying theorists.”) Unfortunately for so many of us who would just get on with doing our day jobs, cybersecurity is rapidly devolving into the “focus groups on dragon dispatching” realm, which actual dragons slayers have little choice but to participate in. The general trend in cybersecurity is that powers-that-be – which encompasses groups other than just legislators – are often increasingly concerned and therefore feel they need to Do Something About Cybersecurity. Many seem to believe that if only we had the right amount of regulation and oversight, there would be no data breaches: a breach simply must mean Someone Is At Fault and Needs Supervision. (Leaving aside the fact that we have lots of home invasions despite a) guard dogs b) liberal carry permits c) alarm systems d) etc.) Also note that many well-managed and security-aware organizations, like the US Department of Defense, still get hacked. More specifically, many powers-that-be feel they must direct industry in a multiplicity of ways, up to and including how we actually build and deploy information technology systems. The more prescriptive the requirement, the more regulators or overseers a) can be seen to be doing something b) feel as if they are doing something regardless of whether they are actually doing something useful or cost effective. Note: an unfortunate concomitant of Doing Something is that often the cure is worse than the ailment. That is, doing what overseers want creates unfortunate byproducts that they either didn’t foresee or worse, don’t care about. After all, the logic goes, we Did Something. Prescriptive practice in the IT industry is problematic for a number of reasons. For a start, prescriptive guidance is really only appropriate if: • It is cost effective• It is “current” (meaning, the guidance doesn’t require the use of the technical equivalent of buggy whips long after horse-drawn transportation has become passé)*• It is practical (that is, pragmatic, proven and effective in the real world, not theoretical and unproven)• It solves the right problem With the above in mind, heading up the list of “you must be joking” regulations are recent disturbing developments in the Payment Card Industry (PCI) world. I’d like to give PCI kahunas the benefit of the doubt about their intentions, except that efforts by Oracle among others to make them aware of “unfortunate side effects of your requirements” – which is as tactful I can be for reasons that I believe will become obvious below - have gone, to-date, unanswered and more importantly, unchanged. A little background on PCI before I get too wound up. In 2008, the Payment Card Industry (PCI) Security Standards Council (SSC) introduced the Payment Application Data Security Standard (PA-DSS). That standard requires vendors of payment applications to ensure that their products implement specific requirements and undergo security assessment procedures. In order to have an application listed as a Validated Payment Application (VPA) and available for use by merchants, software vendors are required to execute the PCI Payment Application Vendor Release Agreement (VRA). (Are you still with me through all the acronyms?) Beginning in August 2010, the VRA imposed new obligations on vendors that are extraordinary and extraordinarily bad, short-sighted and unworkable. Specifically, PCI requires vendors to disclose (dare we say “tell all?”) to PCI any known security vulnerabilities and associated security breaches involving VPAs. ASAP. Think about the impact of that. PCI is asking a vendor to disclose to them: • Specific details of security vulnerabilities • Including exploit information or technical details of the vulnerability • Whether or not there is any mitigation available (as in a patch) PCI, in turn, has the right to blab about any and all of the above – specifically, to distribute all the gory details of what is disclosed - to the PCI SSC, qualified security assessors (QSAs), and any affiliate or agent or adviser of those entities, who are in turn permitted to share it with their respective affiliates, agents, employees, contractors, merchants, processors, service providers and other business partners. This assorted crew can’t be more than, oh, hundreds of thousands of entities. Does anybody believe that several hundred thousand people can keep a secret? Or that several hundred thousand people are all equally trustworthy? Or that not one of the people getting all that information would blab vulnerability details to a bad guy, even by accident? Or be a bad guy who uses the information to break into systems? (Wait, was that the Easter Bunny that just hopped by? Bringing world peace, no doubt.) Sarcasm aside, common sense tells us that telling lots of people a secret is guaranteed to “unsecret” the secret. Notably, being provided details of a vulnerability (without a patch) is of little or no use to companies running the affected application. Few users have the technological sophistication to create a workaround, and even if they do, most workarounds break some other functionality in the application or surrounding environment. Also, given the differences among corporate implementations of any application, it is highly unlikely that a single workaround is going to work for all corporate users. So until a patch is developed by the vendor, users remain at risk of exploit: even more so if the details of vulnerability have been widely shared. Sharing that information widely before a patch is available therefore does not help users, and instead helps only those wanting to exploit known security bugs. There’s a shocker for you. Furthermore, we already know that insider information about security vulnerabilities inevitably leaks, which is why most vendors closely hold such information and limit dissemination until a patch is available (and frequently limit dissemination of technical details even with the release of a patch). That’s the industry norm, not that PCI seems to realize or acknowledge that. Why would anybody release a bunch of highly technical exploit information to a cast of thousands, whose only “vetting” is that they are members of a PCI consortium? Oracle has had personal experience with this problem, which is one reason why information on security vulnerabilities at Oracle is “need to know” (we use our own row level access control to limit access to security bugs in our bug database, and thus less than 1% of development has access to this information), and we don’t provide some customers with more information than others or with vulnerability information and/or patches earlier than others. Failure to remember “insider information always leaks” creates problems in the general case, and has created problems for us specifically. A number of years ago, one of the UK intelligence agencies had information about a non-public security vulnerability in an Oracle product that they circulated among other UK and Commonwealth defense and intelligence entities. Nobody, it should be pointed out, bothered to report the problem to Oracle, even though only Oracle could produce a patch. The vulnerability was finally reported to Oracle by (drum roll) a US-based commercial company, to whom the information had leaked. (Note: every time I tell this story, the MI-whatever agency that created the problem gets a bit shirty with us. I know they meant well and have improved their vulnerability handling/sharing processes but, dudes, next time you find an Oracle vulnerability, try reporting it to us first before blabbing to lots of people who can’t actually fix the problem. Thank you!) Getting back to PCI: clearly, these new disclosure obligations increase the risk of exploitation of a vulnerability in a VPA and thus, of misappropriation of payment card data and customer information that a VPA processes, stores or transmits. It stands to reason that VRA’s current requirement for the widespread distribution of security vulnerability exploit details -- at any time, but particularly before a vendor can issue a patch or a workaround -- is very poor public policy. It effectively publicizes information of great value to potential attackers while not providing compensating benefits - actually, any benefits - to payment card merchants or consumers. In fact, it magnifies the risk to payment card merchants and consumers. The risk is most prominent in the time before a patch has been released, since customers often have little option but to continue using an application or system despite the risks. However, the risk is not limited to the time before a patch is issued: customers often need days, or weeks, to apply patches to systems, based upon the complexity of the issue and dependence on surrounding programs. Rather than decreasing the available window of exploit, this requirement increases the available window of exploit, both as to time available to exploit a vulnerability and the ease with which it can be exploited. Also, why would hackers focus on finding new vulnerabilities to exploit if they can get “EZHack” handed to them in such a manner: a) a vulnerability b) in a payment application c) with exploit code: the “Hacking Trifecta!“ It’s fair to say that this is probably the exact opposite of what PCI – or any of us – would want. Established industry practice concerning vulnerability handling avoids the risks created by the VRA’s vulnerability disclosure requirements. Specifically, the norm is not to release information about a security bug until the associated patch (or a pretty darn good workaround) has been issued. Once a patch is available, the notice to the user community is a high-level communication discussing the product at issue, the level of risk associated with the vulnerability, and how to apply the patch. The notices do not include either the specific customers affected by the vulnerability or forensic reports with maps of the exploit (both of which are required by the current VRA). In this way, customers have the tools they need to prioritize patching and to help prevent an attack, and the information released does not increase the risk of exploit. Furthermore, many vendors already use industry standards for vulnerability description: Common Vulnerability Enumeration (CVE) and Common Vulnerability Scoring System (CVSS). CVE helps ensure that customers know which particular issues a patch addresses and CVSS helps customers determine how severe a vulnerability is on a relative scale. Industry already provides the tools customers need to know what the patch contains and how bad the problem is that the patch remediates. So, what’s a poor vendor to do? Oracle is reaching out to other vendors subject to PCI and attempting to enlist then in a broad effort to engage PCI in rethinking (that is, eradicating) these requirements. I would therefore urge all who care about this issue, but especially those in the vendor community whose applications are subject to PCI and who may not have know they were being asked to tell-all to PCI and put their customers at risk, to do one of the following: • Contact PCI with your concerns• Contact Oracle (we are looking for vendors to sign our statement of concern)• And make sure you tell your customers that you have to rat them out to PCI if there is a breach involving the payment application I like to be charitable and say “PCI meant well” but in as important a public policy issue as what you disclose about vulnerabilities, to whom and when, meaning well isn’t enough. We need to do well. PCI, as regards this particular issue, has not done well, and has compounded the error by thus far being nonresponsive to those of us who have labored mightily to try to explain why they might want to rethink telling the entire planet about security problems with no solutions. By Way of Explanation… Non-related to PCI whatsoever, and the explanation for why I have not been blogging a lot recently, I have been working on Other Writing Venues with my sister Diane (who has also worked in the tech sector, inflicting upgrades on unsuspecting and largely ungrateful end users). I am pleased to note that we have recently (self-)published the first in the Miss Information Technology Murder Mystery series, Outsourcing Murder. The genre might best be described as “chick lit meets geek scene.” Our sisterly nom de plume is Maddi Davidson and (shameless plug follows): you can order the paper version of the book on Amazon, or the Kindle or Nook versions on www.amazon.com or www.bn.com, respectively. From our book jacket: Emma Jones, a 20-something IT consultant, is working on an outsourcing project at Tahiti Tacos, a restaurant chain offering Polynexican cuisine: refried poi, anyone? Emma despises her boss Padmanabh, a brilliant but arrogant partner in GD Consulting. When Emma discovers His-Royal-Padness’s body (verdict: death by cricket bat), she becomes a suspect.With her overprotective family and her best friend Stacey providing endless support and advice, Emma stumbles her way through an investigation of Padmanabh’s murder, bolstered by fusion food feeding frenzies, endless cups of frou-frou coffee and serious surfing sessions. While Stacey knows a PI who owes her a favor, landlady Magda urges Emma to tart up her underwear drawer before the next cute cop with a search warrant arrives. Emma’s mother offers to fix her up with a PhD student at Berkeley and showers her with self-defense gizmos while her old lover Keoni beckons from Hawai’i. And everyone, even Shaun the barista, knows a good lawyer. Book 2, Denial of Service, is coming out this summer. * Given the rate of change in technology, today’s “thou shalts” are easily next year’s “buggy whip guidance.”

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  • Command line mode only -- successful login only brings me back to login screen

    - by seth
    whenever I log in the screen goes black, I see a glimpse of terminal-esque text, and then it brings me back to the log in screen (Ubuntu 12.04). I can enter and log in via the command line. The guest account works find. I think this happened because I edited some Xorg related file trying to make an external monitor work with my laptop. I copy pasted from a forum post so I dont recall the file or what i put in the file. Can't find the forum post again and my bash history wasn't recorded from that session. I tried reinstalling Xorg and ubuntu-desktop, nvidia, resetting any configs I could find... I'm really at a loss of what to do. Here's my /.xsession-errors: /usr/sbin/lightdm-session: 11: /home/seth/.profile: -s: not found Backend : gconf Integration : true Profile : unity Adding plugins Initializing core options...done Initializing composite options...done Initializing opengl options...done Initializing decor options...done Initializing vpswitch options...done Initializing snap options...done Initializing mousepoll options...done Initializing resize options...done Initializing place options...done Initializing move options...done Initializing wall options...done Initializing grid options...done I/O warning : failed to load external entity "/home/seth/.compiz/session/108fa6ea48f8a973b9133850948930576700000017740033" Initializing session options...done Initializing gnomecompat options...done ** Message: applet now removed from the notification area Initializing animation options...done Initializing fade options...done Initializing unitymtgrabhandles options...done Initializing workarounds options...done Initializing scale options...done compiz (expo) - Warn: failed to bind image to texture Initializing expo options...done Initializing ezoom options...done ** Message: using fallback from indicator to GtkStatusIcon (compiz:1846): GConf-CRITICAL **: gconf_client_add_dir: assertion `gconf_valid_key (dirname, NULL)' failed Initializing unityshell options...done Nautilus-Share-Message: Called "net usershare info" but it failed: 'net usershare' returned error 255: net usershare: cannot open usershare directory /var/lib/samba/usershares. Error No such file or directory Please ask your system administrator to enable user sharing. Setting Update "main_menu_key" Setting Update "run_key" Setting Update "launcher_hide_mode" Setting Update "edge_responsiveness" Setting Update "launcher_capture_mouse" ** Message: moving back from GtkStatusIcon to indicator compiz (decor) - Warn: failed to bind pixmap to texture ** (zeitgeist-datahub:2128): WARNING **: zeitgeist-datahub.vala:227: Unable to get name "org.gnome.zeitgeist.datahub" on the bus! failed to create drawable compiz (core) - Warn: glXCreatePixmap failed compiz (core) - Warn: Couldn't bind background pixmap 0x1e00001 to texture compiz (decor) - Warn: failed to bind pixmap to texture ** Message: No keyring secrets found for Sonic.net_356/802-11-wireless-security; asking user. compiz (decor) - Warn: failed to bind pixmap to texture compiz (decor) - Warn: failed to bind pixmap to texture ** Message: No keyring secrets found for Sonic.net_356/802-11-wireless-security; asking user. ** Message: No keyring secrets found for Sonic.net_356/802-11-wireless-security; asking user. ** Message: No keyring secrets found for Sonic.net_356/802-11-wireless-security; asking user. ** Message: No keyring secrets found for Sonic.net_356/802-11-wireless-security; asking user. ** Message: No keyring secrets found for Sonic.net_356/802-11-wireless-security; asking user. ** Message: No keyring secrets found for Sonic.net_356/802-11-wireless-security; asking user. ** Message: No keyring secrets found for Sonic.net_356/802-11-wireless-security; asking user. ** Message: No keyring secrets found for Sonic.net_356/802-11-wireless-security; asking user. ** Message: No keyring secrets found for Sonic.net_356/802-11-wireless-security; asking user. ** Message: No keyring secrets found for Sonic.net_356/802-11-wireless-security; asking user. ** Message: No keyring secrets found for Sonic.net_356/802-11-wireless-security; asking user. ** Message: No keyring secrets found for Sonic.net_356/802-11-wireless-security; asking user. [2348:2352:12678840568:ERROR:gpu_watchdog_thread.cc(231)] The GPU process hung. Terminating after 10000 ms. [2256:2283:14450711755:ERROR:ssl_client_socket_nss.cc(1542)] handshake with server mail.google.com:443 failed; NSS error code -5938, net_error -107 [2256:2283:14450726175:ERROR:ssl_client_socket_nss.cc(1542)] handshake with server mail.google.com:443 failed; NSS error code -5938, net_error -107 [2256:2283:14450746028:ERROR:ssl_client_socket_nss.cc(1542)] handshake with server mail.google.com:443 failed; NSS error code -5938, net_error -107 [2256:2283:14464521342:ERROR:ssl_client_socket_nss.cc(1542)] handshake with server mail.google.com:443 failed; NSS error code -5938, net_error -107 [2256:2283:14464541249:ERROR:ssl_client_socket_nss.cc(1542)] handshake with server mail.google.com:443 failed; NSS error code -5938, net_error -107 [2256:2283:14690775186:ERROR:ssl_client_socket_nss.cc(1542)] handshake with server mail.google.com:443 failed; NSS error code -5938, net_error -107 [2256:2283:14690795231:ERROR:ssl_client_socket_nss.cc(1542)] handshake with server mail.google.com:443 failed; NSS error code -5938, net_error -107 [2256:2283:14704543843:ERROR:ssl_client_socket_nss.cc(1542)] handshake with server mail.google.com:443 failed; NSS error code -5938, net_error -107 [2256:2283:14704566717:ERROR:ssl_client_socket_nss.cc(1542)] handshake with server mail.google.com:443 failed; NSS error code -5938, net_error -107 [2256:2283:14766138587:ERROR:ssl_client_socket_nss.cc(1542)] handshake with server mail.google.com:443 failed; NSS error code -5938, net_error -107 [2256:2283:14857232694:ERROR:ssl_client_socket_nss.cc(1542)] handshake with server mail.google.com:443 failed; NSS error code -5938, net_error -107 [2256:2283:14930901403:ERROR:ssl_client_socket_nss.cc(1542)] handshake with server mail.google.com:443 failed; NSS error code -5938, net_error -107 [2256:2283:14930965542:ERROR:ssl_client_socket_nss.cc(1542)] handshake with server mail.google.com:443 failed; NSS error code -5938, net_error -107 [2256:2283:14944566814:ERROR:ssl_client_socket_nss.cc(1542)] handshake with server mail.google.com:443 failed; NSS error code -5938, net_error -107 [2256:2283:14944592215:ERROR:ssl_client_socket_nss.cc(1542)] handshake with server mail.google.com:443 failed; NSS error code -5938, net_error -107 [2256:2283:15170929788:ERROR:ssl_client_socket_nss.cc(1542)] handshake with server mail.google.com:443 failed; NSS error code -5938, net_error -107 [2256:2283:15170947382:ERROR:ssl_client_socket_nss.cc(1542)] handshake with server mail.google.com:443 failed; NSS error code -5938, net_error -107 [2256:2283:15184585015:ERROR:ssl_client_socket_nss.cc(1542)] handshake with server mail.google.com:443 failed; NSS error code -5938, net_error -107 [2256:2283:15184605475:ERROR:ssl_client_socket_nss.cc(1542)] handshake with server mail.google.com:443 failed; NSS error code -5938, net_error -107 [2256:2283:15366189036:ERROR:ssl_client_socket_nss.cc(1542)] handshake with server mail.google.com:443 failed; NSS error code -5938, net_error -107 [2256:2283:15410983381:ERROR:ssl_client_socket_nss.cc(1542)] handshake with server mail.google.com:443 failed; NSS error code -5938, net_error -107 [2256:2283:15411569689:ERROR:ssl_client_socket_nss.cc(1542)] handshake with server mail.google.com:443 failed; NSS error code -5938, net_error -107 [2256:2283:15431632431:ERROR:ssl_client_socket_nss.cc(1542)] handshake with server mail.google.com:443 failed; NSS error code -5938, net_error -107 [2256:2283:15431674438:ERROR:ssl_client_socket_nss.cc(1542)] handshake with server mail.google.com:443 failed; NSS error code -5938, net_error -107 [2256:2283:15457304356:ERROR:ssl_client_socket_nss.cc(1542)] handshake with server mail.google.com:443 failed; NSS error code -5938, net_error -107 [2256:2283:15656020938:ERROR:ssl_client_socket_nss.cc(1542)] handshake with server mail.google.com:443 failed; NSS error code -5938, net_error -107 [2256:2283:15656042383:ERROR:ssl_client_socket_nss.cc(1542)] handshake with server mail.google.com:443 failed; NSS error code -5938, net_error -107 [2256:2283:15674651268:ERROR:ssl_client_socket_nss.cc(1542)] handshake with server mail.google.com:443 failed; NSS error code -5938, net_error -107 [2256:2283:15674671786:ERROR:ssl_client_socket_nss.cc(1542)] handshake with server mail.google.com:443 failed; NSS error code -5938, net_error -107 [2256:2283:16052544301:ERROR:ssl_client_socket_nss.cc(1542)] handshake with server mail.google.com:443 failed; NSS error code -5938, net_error -107 [2256:2283:16057387653:ERROR:ssl_client_socket_nss.cc(1542)] handshake with server mail.google.com:443 failed; NSS error code -5938, net_error -107 [2256:2283:16157122849:ERROR:ssl_client_socket_nss.cc(1542)] handshake with server mail.google.com:443 failed; NSS error code -5938, net_error -107 [2256:2283:16157123851:ERROR:ssl_client_socket_nss.cc(1542)] handshake with server mail.google.com:443 failed; NSS error code -5938, net_error -107 [2256:2283:16157125473:ERROR:ssl_client_socket_nss.cc(1542)] handshake with server mail.google.com:443 failed; NSS error code -5938, net_error -107 [2256:2283:16157126544:ERROR:ssl_client_socket_nss.cc(1542)] handshake with server mail.google.com:443 failed; NSS error code -5938, net_error -107 [2256:2283:16157129682:ERROR:ssl_client_socket_nss.cc(1542)] handshake with server mail.google.com:443 failed; NSS error code -5938, net_error -107 If anyone can help me out, I'd be forever grateful

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  • A New Threat To Web Applications: Connection String Parameter Pollution (CSPP)

    - by eric.maurice
    Hi, this is Shaomin Wang. I am a security analyst in Oracle's Security Alerts Group. My primary responsibility is to evaluate the security vulnerabilities reported externally by security researchers on Oracle Fusion Middleware and to ensure timely resolution through the Critical Patch Update. Today, I am going to talk about a serious type of attack: Connection String Parameter Pollution (CSPP). Earlier this year, at the Black Hat DC 2010 Conference, two Spanish security researchers, Jose Palazon and Chema Alonso, unveiled a new class of security vulnerabilities, which target insecure dynamic connections between web applications and databases. The attack called Connection String Parameter Pollution (CSPP) exploits specifically the semicolon delimited database connection strings that are constructed dynamically based on the user inputs from web applications. CSPP, if carried out successfully, can be used to steal user identities and hijack web credentials. CSPP is a high risk attack because of the relative ease with which it can be carried out (low access complexity) and the potential results it can have (high impact). In today's blog, we are going to first look at what connection strings are and then review the different ways connection string injections can be leveraged by malicious hackers. We will then discuss how CSPP differs from traditional connection string injection, and the measures organizations can take to prevent this kind of attacks. In web applications, a connection string is a set of values that specifies information to connect to backend data repositories, in most cases, databases. The connection string is passed to a provider or driver to initiate a connection. Vendors or manufacturers write their own providers for different databases. Since there are many different providers and each provider has multiple ways to make a connection, there are many different ways to write a connection string. Here are some examples of connection strings from Oracle Data Provider for .Net/ODP.Net: Oracle Data Provider for .Net / ODP.Net; Manufacturer: Oracle; Type: .NET Framework Class Library: - Using TNS Data Source = orcl; User ID = myUsername; Password = myPassword; - Using integrated security Data Source = orcl; Integrated Security = SSPI; - Using the Easy Connect Naming Method Data Source = username/password@//myserver:1521/my.server.com - Specifying Pooling parameters Data Source=myOracleDB; User Id=myUsername; Password=myPassword; Min Pool Size=10; Connection Lifetime=120; Connection Timeout=60; Incr Pool Size=5; Decr Pool Size=2; There are many variations of the connection strings, but the majority of connection strings are key value pairs delimited by semicolons. Attacks on connection strings are not new (see for example, this SANS White Paper on Securing SQL Connection String). Connection strings are vulnerable to injection attacks when dynamic string concatenation is used to build connection strings based on user input. When the user input is not validated or filtered, and malicious text or characters are not properly escaped, an attacker can potentially access sensitive data or resources. For a number of years now, vendors, including Oracle, have created connection string builder class tools to help developers generate valid connection strings and potentially prevent this kind of vulnerability. Unfortunately, not all application developers use these utilities because they are not aware of the danger posed by this kind of attacks. So how are Connection String parameter Pollution (CSPP) attacks different from traditional Connection String Injection attacks? First, let's look at what parameter pollution attacks are. Parameter pollution is a technique, which typically involves appending repeating parameters to the request strings to attack the receiving end. Much of the public attention around parameter pollution was initiated as a result of a presentation on HTTP Parameter Pollution attacks by Stefano Di Paola and Luca Carettoni delivered at the 2009 Appsec OWASP Conference in Poland. In HTTP Parameter Pollution attacks, an attacker submits additional parameters in HTTP GET/POST to a web application, and if these parameters have the same name as an existing parameter, the web application may react in different ways depends on how the web application and web server deal with multiple parameters with the same name. When applied to connections strings, the rule for the majority of database providers is the "last one wins" algorithm. If a KEYWORD=VALUE pair occurs more than once in the connection string, the value associated with the LAST occurrence is used. This opens the door to some serious attacks. By way of example, in a web application, a user enters username and password; a subsequent connection string is generated to connect to the back end database. Data Source = myDataSource; Initial Catalog = db; Integrated Security = no; User ID = myUsername; Password = XXX; In the password field, if the attacker enters "xxx; Integrated Security = true", the connection string becomes, Data Source = myDataSource; Initial Catalog = db; Integrated Security = no; User ID = myUsername; Password = XXX; Intergrated Security = true; Under the "last one wins" principle, the web application will then try to connect to the database using the operating system account under which the application is running to bypass normal authentication. CSPP poses serious risks for unprepared organizations. It can be particularly dangerous if an Enterprise Systems Management web front-end is compromised, because attackers can then gain access to control panels to configure databases, systems accounts, etc. Fortunately, organizations can take steps to prevent this kind of attacks. CSPP falls into the Injection category of attacks like Cross Site Scripting or SQL Injection, which are made possible when inputs from users are not properly escaped or sanitized. Escaping is a technique used to ensure that characters (mostly from user inputs) are treated as data, not as characters, that is relevant to the interpreter's parser. Software developers need to become aware of the danger of these attacks and learn about the defenses mechanism they need to introduce in their code. As well, software vendors need to provide templates or classes to facilitate coding and eliminate developers' guesswork for protecting against such vulnerabilities. Oracle has introduced the OracleConnectionStringBuilder class in Oracle Data Provider for .NET. Using this class, developers can employ a configuration file to provide the connection string and/or dynamically set the values through key/value pairs. It makes creating connection strings less error-prone and easier to manager, and ultimately using the OracleConnectionStringBuilder class provides better security against injection into connection strings. For More Information: - The OracleConnectionStringBuilder is located at http://download.oracle.com/docs/cd/B28359_01/win.111/b28375/OracleConnectionStringBuilderClass.htm - Oracle has developed a publicly available course on preventing SQL Injections. The Server Technologies Curriculum course "Defending Against SQL Injection Attacks!" is located at http://st-curriculum.oracle.com/tutorial/SQLInjection/index.htm - The OWASP web site also provides a number of useful resources. It is located at http://www.owasp.org/index.php/Main_Page

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  • How do I configure freeSSHd on Windows Server 2008 so I can log in using ssh?

    - by Daryl Spitzer
    I've installed freeSSHd on a Windows Server 2008 box (following the instructions in How to install an SSH Server in Windows Server 2008), including: created a user named "dspitzer" with NTLM authorization opened an exception for port 22 in the Windows Firewall But when I try to connect (from a Mac OS X 10.5.8 command-line), I get permission denied after entering the password: $ ssh 12.34.56.78 [email protected]'s password: Permission denied, please try again. [email protected]'s password: Permission denied, please try again. [email protected]'s password: Received disconnect from 12.34.56.78: 2: Too many attempts. I've also tried: $ ssh [email protected] [email protected]'s password: Permission denied, please try again. [email protected]'s password: Permission denied, please try again. [email protected]'s password: Received disconnect from 12.34.56.78: 2: Too many attempts. I've also tried changing the authorization to "Password stored as SHA1 hash" and entering a simple password, but I get the same problem. And I've tried a different user name ("Administrator") with no luck. I've confirmed that I am connecting to the server I'm configuring—if I stop freeSSHd and try to connect I get: $ ssh 12.34.56.78 ssh: connect to host 12.34.56.78 port 22: Operation timed out I get the exact same results from a Linux command-line. Any advice or troubleshooting tips? Update: I tried disabling the firewall (in response to geeklin's comment) and it made no difference. Update #2: I no longer have this machine (I've changed employers), so I have no way of verifying the answers. I guess all I can do is make this question "community wiki".

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  • How do I configure freeSSHd on Windows Server 2008 so I can log in using ssh?

    - by Daryl Spitzer
    I've installed freeSSHd on a Windows Server 2008 box (following the instructions in How to install an SSH Server in Windows Server 2008), including: created a user named "dspitzer" with NTLM authorization opened an exception for port 22 in the Windows Firewall But when I try to connect (from a Mac OS X 10.5.8 command-line), I get permission denied after entering the password: $ ssh 12.34.56.78 [email protected]'s password: Permission denied, please try again. [email protected]'s password: Permission denied, please try again. [email protected]'s password: Received disconnect from 12.34.56.78: 2: Too many attempts. I've also tried: $ ssh [email protected] [email protected]'s password: Permission denied, please try again. [email protected]'s password: Permission denied, please try again. [email protected]'s password: Received disconnect from 12.34.56.78: 2: Too many attempts. I've also tried changing the authorization to "Password stored as SHA1 hash" and entering a simple password, but I get the same problem. And I've tried a different user name ("Administrator") with no luck. I've confirmed that I am connecting to the server I'm configuring—if I stop freeSSHd and try to connect I get: $ ssh 12.34.56.78 ssh: connect to host 12.34.56.78 port 22: Operation timed out I get the exact same results from a Linux command-line. Any advice or troubleshooting tips? Update: I tried disabling the firewall (in response to geeklin's comment) and it made no difference. Update #2: I no longer have this machine (I've changed employers), so I have no way of verifying the answers. I guess all I can do is make this question "community wiki".

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  • LDAP change user pass on client

    - by Sean
    I am trying to allow ldap users to change their password on client machines. I have tried pam every which way I can think of /etc/ldap.conf & /etc/pam_ldap.conf, as well. At this point I'm stuck. Client: Ubuntu 11.04 Server: Debian 6.0 The current output is this: sobrien4@T-E700F-1:~$ passwd passwd: Authentication service cannot retrieve authentication info passwd: password unchanged /var/log/auth.log gives this during the command: May 9 10:49:06 T-E700F-1 passwd[18515]: pam_unix(passwd:chauthtok): user "sobrien4" does not exist in /etc/passwd May 9 10:49:06 T-E700F-1 passwd[18515]: pam_ldap: ldap_simple_bind Can't contact LDAP server May 9 10:49:06 T-E700F-1 passwd[18515]: pam_ldap: reconnecting to LDAP server... May 9 10:49:06 T-E700F-1 passwd[18515]: pam_ldap: ldap_simple_bind Can't contact LDAP server getent passwd |grep sobrien4 (note keeping short since testing with that account, however it outputs all ldap users): sobrien4:Ffm1oHzwnLz0U:10000:12001:Sean O'Brien:/home/sobrien4:/bin/bash getent group shows all ldap groups. /etc/pam.d/common-password (Note this is just the most current, I have tried a lot of different options): password required pam_cracklib.so retry=3 minlen=8 difok=3 password [success=1 default=ignore] pam_unix.so use_authtok md5 password required pam_ldap.so use_authtok password required pam_permit.so Popped open wireshark as well, the server & client are talking. I have the password changing working on the server. I.E. the server that runs slapd, I can log in with the ldap user and change the passwords. I tried copying the working configs from the server initially and no dice. I also tried cloning it, and just changing ip & host, and no go. My guess is that the client is not authorized by ip or hostname to change a pass. Pertaining to the slapd conf, I saw this in a guide and tried it: access to attrs=loginShell,gecos by dn="cn=admin,dc=cengineering,dc=etb" write by self write by * read access to * by dn="cn=admin,dc=cengineering,dc=etb" write by self write by * read So ldap seems to be working okay, just can't change the password.

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  • FTP Upload ftpWebRequest Proxy

    - by Rodney Vinyard
    Searchable:   FTP Upload ftpWebRequest Proxy FTP command is not supported when using HTTP proxy     In the article below I will cover 2 topics   1.       C# & Windows Command-Line FTP Upload with No Proxy Server   2.       C# & Windows Command-Line FTP Upload with Proxy Server   Not covered here: Secure FTP / SFTP   Sample Attributes: ·         UploadFilePath = “\\servername\folder\file.name” ·         Proxy Server = “ftp://proxy.server/” ·         FTP Target Server = ftp.target.com ·         FTP User = “User” ·         FTP Password = “Password” with No Proxy Server ·         Windows Command-Line > ftp ftp.target.com > ftp User: User > ftp Password: Password > ftp put \\servername\folder\file.name > ftp dir           (result: file.name listed) > ftp del file.name > ftp dir           (result: file.name deleted) > ftp quit   ·         C#   //----------------- //Start FTP via _TargetFtpProxy //----------------- string relPath = Path.GetFileName(\\servername\folder\file.name);   //result: relPath = “file.name”   FtpWebRequest ftpWebRequest = (FtpWebRequest)WebRequest.Create("ftp.target.com/file.name); ftpWebRequest.Method = WebRequestMethods.Ftp.UploadFile;   //----------------- //user - password //----------------- ftpWebRequest.Credentials = new NetworkCredential("user, "password");   //----------------- // set proxy = null! //----------------- ftpWebRequest.Proxy = null;   //----------------- // Copy the contents of the file to the request stream. //----------------- StreamReader sourceStream = new StreamReader(“\\servername\folder\file.name”);   byte[] fileContents = Encoding.UTF8.GetBytes(sourceStream.ReadToEnd()); sourceStream.Close(); ftpWebRequest.ContentLength = fileContents.Length;     //----------------- // transer the stream stream. //----------------- Stream requestStream = ftpWebRequest.GetRequestStream(); requestStream.Write(fileContents, 0, fileContents.Length); requestStream.Close();   //----------------- // Look at the response results //----------------- FtpWebResponse response = (FtpWebResponse)ftpWebRequest.GetResponse();   Console.WriteLine("Upload File Complete, status {0}", response.StatusDescription);   with Proxy Server ·         Windows Command-Line > ftp proxy.server > ftp User: [email protected] > ftp Password: Password > ftp put \\servername\folder\file.name > ftp dir           (result: file.name listed) > ftp del file.name > ftp dir           (result: file.name deleted) > ftp quit   ·         C#   //----------------- //Start FTP via _TargetFtpProxy //----------------- string relPath = Path.GetFileName(\\servername\folder\file.name);   //result: relPath = “file.name”   FtpWebRequest ftpWebRequest = (FtpWebRequest)WebRequest.Create("ftp://proxy.server/" + relPath); ftpWebRequest.Method = WebRequestMethods.Ftp.UploadFile;   //----------------- //user - password //----------------- ftpWebRequest.Credentials = new NetworkCredential("[email protected], "password");   //----------------- // set proxy = null! //----------------- ftpWebRequest.Proxy = null;   //----------------- // Copy the contents of the file to the request stream. //----------------- StreamReader sourceStream = new StreamReader(“\\servername\folder\file.name”);   byte[] fileContents = Encoding.UTF8.GetBytes(sourceStream.ReadToEnd()); sourceStream.Close(); ftpWebRequest.ContentLength = fileContents.Length;     //----------------- // transer the stream stream. //----------------- Stream requestStream = ftpWebRequest.GetRequestStream(); requestStream.Write(fileContents, 0, fileContents.Length); requestStream.Close();   //----------------- // Look at the response results //----------------- FtpWebResponse response = (FtpWebResponse)ftpWebRequest.GetResponse();   Console.WriteLine("Upload File Complete, status {0}", response.StatusDescription);

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  • How can I get access to password hashing in postgresql? Tried installing postgresql-contrib in ubun

    - by Tchalvak
    So I'm trying to just hash some passwords in postgresql, and the only hashing solution that I've found for postgresql is part of the pgcrytpo package ( http://www.postgresql.org/docs/8.3/static/pgcrypto.html ) that is supposed to be in postgresql-contrib ( http://www.postgresql.org/docs/8.3/static/contrib.html ). So I installed postgresql-contrib, (sudo apt-get install postgresql-contrib), restarted my server (as a simple way to restart postgresql). However, I still don't have access to any of the functions for hashing that are supposed to be in postgresql-contrib, e.g.: ninjawars=# select crypt('global salt' || 'new password' || 'user created date', gen_salt('sha256')); ERROR: function gen_salt(unknown) does not exist ninjawars=# select digest('test', 'sha256') from players limit 1; ERROR: function digest(unknown, unknown) does not exist ninjawars=# select hmac('test', 'sha256') from players limit 1; ERROR: function hmac(unknown, unknown) does not exist So how can I hash passwords in postgresql, on ubuntu?

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  • How to reduce timeout for bad password on disconnected laptop?

    - by Elroy Flynn
    I use a Windows 7 laptop computer. When not attached to my AD domain, if I enter an incorrect password, I have to wait approximately a full minute before the failure response comes back. When attached to the domain, the response is instant. I think that what's happening is that is that when my entry fails against the cached pw, Windows tries to reach the domain controller and the timeout for that operation is about 60s. Is there a registry entry that controls the timeout? I'd love to reduce it.

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  • How to deal with arrays of data in cookies

    - by peter
    Hi all, I want to store data in a cookie and I am not exactly sure how I will go about it. The data is the UserName, and Password values for the users that are logging into a website, e.g. sometime like this UserName = bob, Password=Passw0rd1 UserName = harry, Password=BLANK UserName = george, Password=R0jjd6s What this means is that bob and george logged into the site and chose to have their password remembered, but harry chose for his password not to be remembered. So on the login dialog a dropdown will be present with all the usernames in it 'bob', 'harry', 'george'. If they select the username bob the password will automatically be filled in, etc. So how does that information need to be stored in the cookie? Like it is above, or does it have to be, UserName1 = bob, Password1=Passw0rd1 UserName2 = harry, Password2=BLANK UserName3 = george, Password3=R0jjd6s Are the username and password values actually stored in the same cookie, or is each piece of data separate? Any information would be good.

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  • How do I set a postgresql password in pgpass.conf for the Administrator account on Windows Server 2008?

    - by brad
    I have a pgpass.conf file that works well for my default user. It is in C:/Users/myuser/AppData/Roaming/postgresql/pgpass.conf. It reads like so; localhost:5432:*:postgres:password1 I have a process that runs under the Administrator account. When I run whoami under this process I get nt authority/system. I want to be able to access the database from this process but it gets stuck because it needs a password. I have tried putting the above pgpass.conf into C:/Users/Administrator/AppData/postgresql/pgpass.conf and C:/Users/Administrator/AppData/Roaming/postgresql/pgpass.conf but it does not work. Is this the correct place for this file? Am I even able to do this as the Administrator. Unfortunately I cannot change the user that this process runs under.

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  • Worksheet.Unprotect - Office Interop - Difference between 2003 and 2007

    - by sdmcnitt
    I have a .NET winforms app that automates Excel and checks for a worksheet password. The requirements are to be able to detect 1) that the protection is turned off 2) that the password is removed (protected but there is no password) 3) that the password matches the correct password from a database To meet the second requirement the program calls the Worksheet.Unprotect command with a null string, capturing the error. If error as expected, the 3rd check is made. If no error, then the Unprotect worked without a password == password was removed. The code sample below has these checks. The application can do this fine with Office 2003. I have since had my dev machine updated to Office 2007 and it no longer works as it did. When I call the Worksheet.Unprotect, Excel prompts for the password! I need to know how this should be accomplished in the new version of Excel or if there is a way to reference the old PIA. No matter what if I set a reference to Excel 11 it is replaced with the PIA for 12 in the GAC. 'return true if unprotect of worksheet does not generate an error 'all other errors will bubble up 'return false if specific error is "Password is invalid..." Try 'detect unprotected or no password If oWorksheet.ProtectContents Then 'try with no passsword and expect an error 'if no error then raise exception Dim blnRaiseException As Boolean = True Try 'oWorksheet.Unprotect(vbNullString) oWorksheet.Unprotect() Catch ex As Exception blnRaiseException = False End Try If blnRaiseException Then Throw New ExcelSheetNoPasswordException End If oWorksheet.Unprotect(strPwd) 'no error so if we get here -- success fnCheckWorksheetPwd = True 'leave as it was -- this may still cause workbook to think it is changed oWorksheet.Protect(strPwd) Else Throw New ExcelSheetNotProtectedException End If Catch COMex As System.Runtime.InteropServices.COMException 'handle error code -2146827284 If COMex.ErrorCode = -2146827284 Then 'this is the error we're looking for Else Throw End If Catch ex As Exception Throw End Try

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  • Enabling publickey authentication for server's sshd

    - by aaron
    I have two servers running RHEL 5. Both have nearly identical configurations. I have set up RSA Publickey authetication on both, and one works but the other does not: [my_user@client] $ ssh my_user@server1 --- server1 MOTD Banner --- [my_user@server1] $ and on the other server: [my_user@client] $ ssh my_user@server2 my_user@server2's password: --- server2 MOTD Banner --- [my_user@server2] $ server2's /etc/ssh/sshd_config file snippet: RSAAuthentication yes PubkeyAuthentication yes AuthorizedKeysFile .ssh/authorized_keys When I run ssh -vvv I get the following snippet: debug3: authmethod_lookup publickey debug3: remaining preferred: keyboard-interactive,password debug3: authmethod_is_enabled publickey debug3: Next authentication method: publickey debug1: Offering public key: /home/my_user/.ssh/id_rsa debug3: send_pubkey_test debug2: we sent a publickey packet, wait for reply debug1: Authentication that can continue: publickey,gssapi-with-mic,passowrd debug1: Offering public key: /home/my_user/.ssh/id_dsa debug3: send_pubkey_test debug2: we sent a publickey packet, wait for reply debug1: Authentication that can continue: publickey,gssapi-with-mic,passowrd debug3: authmethod_lookup password debug3: remaining preferred: ,password debug3: authmethod_is_enabled password debug1: Next authentication method: password my_user@server2's password:

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  • Trying to send email in Java using gmail always results in username and password not accepted.

    - by Thaeos
    When I call the send method (after setting studentAddress), I get this: javax.mail.AuthenticationFailedException: 535-5.7.1 Username and Password not accepted. Learn more at 535 5.7.1 http://mail.google.com/support/bin/answer.py?answer=14257 y15sm906936wfd.10 I'm pretty sure the code is correct, and 100% positive that the username and password details I'm entering are correct. So is this something wrong with gmail or what? This is my code: import java.util.*; import javax.mail.*; import javax.mail.internet.*; public class SendEmail { private String host = "smtp.gmail.com"; private String emailLogin = "[email protected]"; private String pass = "xxx"; private String studentAddress; private String to; private Properties props = System.getProperties(); public SendEmail() { props.put("mail.smtps.auth", "true"); props.put("mail.smtps.starttls.enable", "true"); props.put("mail.smtp.host", host); props.put("mail.smtp.user", emailLogin); props.put("mail.smtp.password", pass); props.put("mail.smtp.port", "587"); to = "[email protected]"; } public void setStudentAddress(String newAddress) { studentAddress = newAddress; } public void send() { Session session = Session.getDefaultInstance(props, null); MimeMessage message = new MimeMessage(session); try { message.setFrom(new InternetAddress(emailLogin)); InternetAddress[] studentAddressList = {new InternetAddress(studentAddress)}; message.setReplyTo(studentAddressList); message.setRecipient(Message.RecipientType.TO, new InternetAddress(to)); message.setSubject("Test Email"); message.setText("This is a test email!"); Transport transport = session.getTransport("smtps"); transport.connect(host, emailLogin, pass); transport.sendMessage(message, message.getAllRecipients()); transport.close(); } catch (MessagingException me) { System.out.println("There has been an email error!"); me.printStackTrace(); } } } Any ideas...

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  • What's the simplest configuration of SVN on a Windows Server to avoid plain text password storage?

    - by detly
    I have an SVN 1.6 server running on a Windows Server 2003 machine, served via CollabNet's svnserve running as a service (using the svn protocol). I would like to avoid storing passwords in plain text on the server. Unfortunately, the default configuration and SASL with DIGEST-MD5 both require plain text password storage. What is the simplest possible way to avoid storing passwords in plain text? My constraints are: Path-based access control to the SVN repository needs to be possible (currently I can use an authz file). As far as I know, this is more-or-less independent of the authentication method. Active directory is available, but it's not just domain-connected windows machines that need to authenticate: workgroup PCs, Linux PCs and software that uses PySVN to perform SVN operations all need to be able to access the repositories. Upgrading the SVN server is feasible, as is installing additional software.

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  • Why does my Mac always crash when I enable `ask for password after screensaver ended`?

    - by Koning Baard XIV
    I have enabled these two things: Placing the mouse-pointer in the bottom-left corner of any display makes the screensaver appear After the screensaver or stand-by has ended, ask for password However, this combination always leads to this (Black Screen of Death) after entering the screensaver with the bottom-left corner: Here are my system specs: Hardware Overview: Model Name: iMac Model Identifier: iMac9,1 Processor Name: Intel Core 2 Duo Processor Speed: 2,66 GHz Number Of Processors: 1 Total Number Of Cores: 2 L2 Cache: 6 MB Memory: 2 GB Bus Speed: 1,07 GHz Boot ROM Version: IM91.008D.B08 SMC Version (system): 1.44f0 Serial Number (system): W89171JF0TF Hardware UUID: 323A90F0-8A2F-5057-B501-2087489E0DFF System Software Overview: System Version: Mac OS X 10.6.3 (10D573) Kernel Version: Darwin 10.3.0 Boot Volume: Macintosh HD Boot Mode: Normal Computer Name: YOU SHOULD NOT KNOW THIS User Name: YOU SHOULD NOT KNOW THIS Secure Virtual Memory: Not Enabled 64-bit Kernel and Extensions: No Time since boot: 11:46 Can anyone help me? Thanks

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  • On iPhone, how do I show a login screen to get username and password before giving access to iPhone

    - by MikeN
    On iPhone, how do I show a login screen to get username and password before giving access to iPhone app? Also, does the iPhone store a cookie to the secure website like a web browser? I was thinking of giving users to my website a long API key to store in the settings of their iPhone instead of asking them to login with a username/password (seems to be the Slicehost iPhone app approach.) Which is the best way to get a user to login securely? I have full control over the design of the iPhone app and website so have a lot of flexibility.

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  • Remote desktop logs in with saved credentials when connecting from one computer but asks for username and password from another.

    - by AndrejaKo
    I have two computers on which I recently installed windows 7 64 bit. Using VPN, they connect to remote network on which there is a Windows Server 2000 SP4 computer. User is supposed to connect to server using remote desktop. I set same VPN and remote desktop settings on both computers with Windows 7. I set Remote desktop to save connection credentials on both computers, but when I connect to server form one computer, it uses saved credentials and I don't get log-in prompt on server side. On the other computer with same settings using same username and password, I get log-in prompt once the remote desktop connects to server. I even tried copying the .rdp file from the computer on which everything is working fine to the other computer, but that didn't help. Note that I'm not trying to have both computers connected at the same time. What is causing this and how do I make the other computer skip windows server 2000 log-in prompt.

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  • Accessing Oracle 6i and 9i/10g Databases using C#

    - by Mike M
    Hi all, I am making two build files using NAnt. The first aims to automatically compile Oracle 6i forms and reports and the second aims to compile Oracle 9i/10g forms and reports. Within the NAnt task is a C# script which prompts the developer for database credentials (username, password, database) in order to compile the forms and reports. I want to then run these credentials against the relevant database to ensure the credentials entered are correct and, if they are not, prompt the user to re-enter their credentials. My script currently looks as follows: class GetInput { public static void ScriptMain(Project project) { Console.Clear(); Console.WriteLine("==================================================================="); Console.WriteLine("Welcome to the Compile and Deploy Oracle Forms and Reports Facility"); Console.WriteLine("==================================================================="); Console.WriteLine(); Console.WriteLine("Please enter the acronym of the project to work on from the following list:"); Console.WriteLine(); Console.WriteLine("--------"); Console.WriteLine("- BCS"); Console.WriteLine("- COPEN"); Console.WriteLine("- FCDD"); Console.WriteLine("--------"); Console.WriteLine(); Console.Write("Selection: "); project.Properties["project.type"] = Console.ReadLine(); Console.WriteLine(); Console.Write("Please enter username: "); string username = Console.ReadLine(); project.Properties["username"] = username; string password = ReturnPassword(); project.Properties["password"] = password Console.WriteLine(); Console.Write("Please enter database: "); string database = Console.ReadLine(); project.Properties["database"] = database Console.WriteLine(); //Call method to verify user credentials Console.WriteLine(); Console.WriteLine("Compiling files..."; } public static string ReturnPassword() { Console.Write("Please enter password: "); string password = ""; ConsoleKeyInfo nextKey = Console.ReadKey(true); while (nextKey.Key != ConsoleKey.Enter) { if (nextKey.Key == ConsoleKey.Backspace) { if (password.Length > 0) { password = password.Substring(0, password.Length - 1); Console.Write(nextKey.KeyChar); Console.Write(" "); Console.Write(nextKey.KeyChar); } } else { password += nextKey.KeyChar; Console.Write("*"); } nextKey = Console.ReadKey(true); } return password; } } Having done a bit of research, I find that you can connect to Oracle databases using the System.Data.OracleClient namespace clicky. However, as mentioned in the link, Microsoft is discontinuing support for this so it is not a desireable solution. I have also fonud that Oracle provides its own classes for connecting to Oracle databases clicky. However, this only seems to support connecting to Oracle 9 or newer databases (clicky) so it is not feasible solution as I also need to connect to Oracle 6i databases. I could achieve this by calling a bat script from within the C# script, but I would much prefer to have a single build file for simplicity. Ideally, I would like to run a series of commands such as is contained in the following .bat script: rem -- Set Database SID -- set ORACLE_SID=%DBSID% sqlplus -s %nameofuser%/%password%@%dbsid% set cmdsep on set cmdsep '"'; --" set term on set echo off set heading off select '========================================' || CHR(10) || 'Have checked and found both Password and ' || chr(10) || 'Database Identifier are valid, continuing ...' || CHR(10) || '========================================' from dual; exit; This requires me to set the environment variable of ORACLE_SID and then run sqlplus in silent mode (-s) followed by a series of sql set commands (set x), the actual select statement and an exit command. Can I achieve this within a c# script without calling a bat script, or am I forced to call a bat script? Thanks in advance!

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  • Updated MVC 4 to 5.2.0 via Nuget Site compiles but wont run

    - by hjavaher
    I had the bright idea of updating my perfectly working ASP.Net MVC 4 application to the MVC 5 via nuget, Everything compiles just fine but when I try to run the application I get the following yellow screen of death. Has anyone gotten this or know how to solve it? I've searched for it and couldn't find any solutions. Please let me know if there is any farther information that would help you that I can give you. Attempt by security transparent method 'WebMatrix.WebData.PreApplicationStartCode.Start()' to access security critical method 'System.Web.WebPages.Razor.WebPageRazorHost.AddGlobalImport(System.String)' failed. Description: An unhandled exception occurred during the execution of the current web request. Please review the stack trace for more information about the error and where it originated in the code. Exception Details: System.MethodAccessException: Attempt by security transparent method 'WebMatrix.WebData.PreApplicationStartCode.Start()' to access security critical method 'System.Web.WebPages.Razor.WebPageRazorHost.AddGlobalImport(System.String)' failed. Source Error: An unhandled exception was generated during the execution of the current web request. Information regarding the origin and location of the exception can be identified using the exception stack trace below. Stack Trace: [MethodAccessException: Attempt by security transparent method 'WebMatrix.WebData.PreApplicationStartCode.Start()' to access security critical method 'System.Web.WebPages.Razor.WebPageRazorHost.AddGlobalImport(System.String)' failed.] WebMatrix.WebData.PreApplicationStartCode.Start() +112 [InvalidOperationException: The pre-application start initialization method Start on type WebMatrix.WebData.PreApplicationStartCode threw an exception with the following error message: Attempt by security transparent method 'WebMatrix.WebData.PreApplicationStartCode.Start()' to access security critical method 'System.Web.WebPages.Razor.WebPageRazorHost.AddGlobalImport(System.String)' failed..] System.Web.Compilation.BuildManager.InvokePreStartInitMethodsCore(ICollection`1 methods, Func`1 setHostingEnvironmentCultures) +556 System.Web.Compilation.BuildManager.InvokePreStartInitMethods(ICollection`1 methods) +132 System.Web.Compilation.BuildManager.CallPreStartInitMethods(String preStartInitListPath, Boolean& isRefAssemblyLoaded) +102 System.Web.Compilation.BuildManager.ExecutePreAppStart() +153 System.Web.Hosting.HostingEnvironment.Initialize(ApplicationManager appManager, IApplicationHost appHost, IConfigMapPathFactory configMapPathFactory, HostingEnvironmentParameters hostingParameters, PolicyLevel policyLevel, Exception appDomainCreationException) +516 [HttpException (0x80004005): The pre-application start initialization method Start on type WebMatrix.WebData.PreApplicationStartCode threw an exception with the following error message: Attempt by security transparent method 'WebMatrix.WebData.PreApplicationStartCode.Start()' to access security critical method 'System.Web.WebPages.Razor.WebPageRazorHost.AddGlobalImport(System.String)' failed..] System.Web.HttpRuntime.FirstRequestInit(HttpContext context) +9885060 System.Web.HttpRuntime.EnsureFirstRequestInit(HttpContext context) +101 System.Web.HttpRuntime.ProcessRequestNotificationPrivate(IIS7WorkerRequest wr, HttpContext context) +254

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  • Hudson fails to use unix user/group to do authentication

    - by Kane
    I'm trying to use unix user/group database as security realm of hudson. The linux server is using NIS for user management. My account could login the hudson server via ssh. And the hudson server is running by user 'hudson' that is also a member of group 'shadow', so hudson could read /etc/shadow. And I tested the configuration using 'test' button, hudson tells me it works well. But I can't use my unix account and password to login the hudson sever. And I found below java exception in the log of hudson, Jan 12, 2011 8:23:42 AM hudson.security.AuthenticationProcessingFilter2 onUnsuccessfulAuthentication INFO: Login attempt failed org.acegisecurity.BadCredentialsException: pam_authenticate failed : Authentication failure; nested exception is org.jvnet.libpam.PAMException: pam_authenticate failed : Authentication failure at hudson.security.PAMSecurityRealm$PAMAuthenticationProvider.authenticate(PAMSecurityRealm.java:100) at org.acegisecurity.providers.ProviderManager.doAuthentication(ProviderManager.java:195) at org.acegisecurity.AbstractAuthenticationManager.authenticate(AbstractAuthenticationManager.java:45) at org.acegisecurity.ui.webapp.AuthenticationProcessingFilter.attemptAuthentication(AuthenticationProcessingFilter.java:71) at org.acegisecurity.ui.AbstractProcessingFilter.doFilter(AbstractProcessingFilter.java:252) at hudson.security.ChainedServletFilter$1.doFilter(ChainedServletFilter.java:87) at org.acegisecurity.ui.basicauth.BasicProcessingFilter.doFilter(BasicProcessingFilter.java:173) at hudson.security.ChainedServletFilter$1.doFilter(ChainedServletFilter.java:87) at org.acegisecurity.context.HttpSessionContextIntegrationFilter.doFilter(HttpSessionContextIntegrationFilter.java:249) at hudson.security.HttpSessionContextIntegrationFilter2.doFilter(HttpSessionContextIntegrationFilter2.java:66) at hudson.security.ChainedServletFilter$1.doFilter(ChainedServletFilter.java:87) at hudson.security.ChainedServletFilter.doFilter(ChainedServletFilter.java:76) at hudson.security.HudsonFilter.doFilter(HudsonFilter.java:164) at winstone.FilterConfiguration.execute(FilterConfiguration.java:195) at winstone.RequestDispatcher.doFilter(RequestDispatcher.java:368) at winstone.RequestDispatcher.forward(RequestDispatcher.java:333) at winstone.RequestHandlerThread.processRequest(RequestHandlerThread.java:244) at winstone.RequestHandlerThread.run(RequestHandlerThread.java:150) at java.lang.Thread.run(Thread.java:595) Caused by: org.jvnet.libpam.PAMException: pam_authenticate failed : Authentication failure at org.jvnet.libpam.PAM.check(PAM.java:105) at org.jvnet.libpam.PAM.authenticate(PAM.java:123) at hudson.security.PAMSecurityRealm$PAMAuthenticationProvider.authenticate(PAMSecurityRealm.java:90) ... 18 more

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  • Drupal Customizing User Registration Form

    - by Asif Mulla
    Hi All, I am newbie in Drupal 6. I am looking for customizing User registration form. Apparently found that while adding user using Admin login allows registration form to have fields like email address, username, password,confirm password, etc with validations. But when anonymous use wants to register, then only fields like email address and username are displayed. I tried with Profile module available. But now how could I add some fields (password, confirm password, terms & condition check and receive news letter check box)and behavior (password, confirm password validation etc.)? If I am adding such fields they are also get visible in AdminAdd user form resulting duplicate fields like Password,Confirm password. Could you please suggest me how can I do this? I tried googling but confused me a lot as I am beginner to Drupal.

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  • Is my form password being passed in clear text?

    - by liinkas
    This is what my browser sent, when logging into some site: POST http://www.some.site/login.php HTTP/1.0 User-Agent: Opera/8.26 (X2000; Linux i686; Z; en) Host: www.some.site Accept: text/html, application/xml;q=0.9, application/xhtml+xml, image/png, image/jpeg, image/gif, image/x-xbitmap, */*;q=0.1 Accept-Language: en-US,en;q=0.9 Accept-Charset: iso-8859-1, utf-8, utf-16, *;q=0.1 Accept-Encoding: deflate, gzip, x-gzip, identity, *;q=0 Referer: http://www.some.site/ Proxy-Connection: close Content-Length: 123 Content-Type: application/x-www-form-urlencoded lots_of_stuff=here&e2ad811=my_login_name&e327696=my_password&lots_of_stuff=here Can I state that anyone can sniff my login name and password for that site? Maybe just on my LAN? If so (even only on LAN ) then I'm shocked. I thought using <input type="password"> did something more than make all characters look like ' * ' p.s. If it matters I played with netcat (on linux) and made connection browser <= netcat (loged here) <= proxy <= remote_site

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