Search Results

Search found 22900 results on 916 pages for 'image upload'.

Page 24/916 | < Previous Page | 20 21 22 23 24 25 26 27 28 29 30 31  | Next Page >

  • Nginx: check content-length before file upload takes place

    - by robw
    I'm trying to prevent users from uploading (accidentally or maliciously) very large files to my website. I have nginx max_client_body_size set to 4M, but if a file larger than this is uploaded, then it uploads the entire file before returning 413 (entity too large). I want to make nginx check the Content-Length header, so that it rejects the request before it's uploaded. Alternatively, a Rails solution would also be acceptable. Any help appreciated.

    Read the article

  • Multiple file upload with preview

    - by sean717
    Hi, Is there any good control or plug-in for uploading multiple photos with preview? As far as I understand it is impossible to preview photo on local computer using just JavaScript. So it has to use Flash or Java. Thanks, also, I use ASP.NET.

    Read the article

  • Detecting file upload size on the client side?

    - by DisgruntledGoat
    I'm using PHP for file uploads. In the PHP manual it shows an example using a MAX_FILE_SIZE hidden field, saying that it will detect on the client side (i.e. the browser) whether the file is too large or not. I've just tried the example in Firefox, Chrome and IE and it doesn't work. The file is always uploaded, even if it is way larger than the specified hidden field. Incidentally, if the file is larger than MAX_FILE_SIZE then calling move_uploaded_file doesn't work, so it seems the variable is having an effect server-side, but not client-side.

    Read the article

  • posting form with file upload

    - by Jan
    I am having trouble with uploading a file when using jquery. I have the following HTML in a form. <fieldset> <ul> <li> <div class="field"><input size="35" type="file" name="formFile" id="formFile"/></div> </li> <li> <div class="field"><input size="35" type="text" name="formFileName" id="formFileName" /></div> </li> </ul> </fieldset> To post the data I am using $('#myForm').ajaxForm( When I post the data and the recieved data contains some javascript, the javascript is not recognised. I expected the javscriptcode to run when the data is recieved, but it happens to early. The results indicates that $ or jquery could not be found. If I remove the name attribute from the input type=file element, there are no errors, but that is not the correct solution. How could this happen?

    Read the article

  • Upload files from website

    - by Andrew
    All I want to do is allow the user to browse through their folders to look for a file, select it and then press submit which saves the file to my server as well as the path to the saved file. How would someone do this? (Some sort of tutorial website would help a lot)

    Read the article

  • jQuery ajax form and Zend_Form file upload

    - by Sinisa Valentic
    If i submit my ajax form from jQuery, and do print_r($_FILES); i get a list of files uploaded, but if i do something like this $add_form->sound_file->isUploaded(); or $params = $this->_getAllParams(); print_r($params); i don't get my file in zend parametars, and i don't get it uploaded!? Mayb the problem is with he context beng ajax?!

    Read the article

  • Java - Display % of upload done

    - by tr-raziel
    I have a java applet for uploading files to server. I want to display the % of data sent but when I use ObjectOutputStream.write() it just writes to the buffer, does not wait until the data has actually been sent. How can I achieve this. Perhaps I need to use thread synchronization or something. Any clues would be most helpful. This is the code I'm using right now: try{ for(File file : ficheiros){ FileInputStream stream = new FileInputStream (file); int bytesRead1 = 0;; int off1 = 0; int len1 = 100000; if(file.length() < 100000) len1 = new Long(file.length()).intValue(); byte[] bytes1 = new byte[len1]; while (off1 < file.length()) { bytes1 = new byte[len1]; if((file.length() - off1) < len1){ len1 = (new Long(file.length()).intValue() - off1); bytes1 = new byte[len1]; } if((bytesRead1 = stream.read(bytes1)) != -1){ //I want this to block until all data has been sent outputToServlet.write(bytes1, 0, bytesRead1 ); System.out.println("off1: " + off1); off1 = off1 + len1; outputToServlet.flush(); } sent += len1; if(sent>totalLength) sent = (int)totalLength; updateFeedback(sent,totalLength,false);//calls method to display % } updateFeedback(-1,-1,true); } }catch(Exception e){ e.printStackTrace(); } Thanks

    Read the article

  • Detecting when error image in PictureBox is used

    - by DMan
    I found this on Google, click here, which someone asked a similar question, receiving a response that they should check if their file exists. However, I'm loading images from web links, in which it displays an error image if A)The picture is not found or B)If, like in image hosting services like Photobucket, displays the 'Bandwidth exceeded' image. Is there a way to detect if either an error image is showing or if a image is invalid?

    Read the article

  • Image rotation algorithm

    - by Stefano Driussi
    I'm looking for an algorithm that rotates an image by some degrees (input). public Image rotateImage(Image image, int degrees) (Image instances could be replaced with int[] containing each pixel RGB values, My problem is that i need to implement it for a JavaME MIDP 2.0 project so i must use code runnable on JVM prior to version 1.5 Can anyone help me out with this ? EDIT: I forgot to mention that i don't have SVG APIs available and that i need a method to rotate by arbitrary degree other than 90 - 180- 270 Also, no java.awt.* packages are available on MIDP 2.0

    Read the article

  • Emulating Windows Photo Viewer image dragging in c#

    - by murasaki5
    Hi, i'm trying to emulate how image is being dragged inside the windows photo viewer when it is large. The problem is, i don't how to drag the image while keeping it intact in the form's edges. If you're observing windows photo viewer, when you drag the image downward for instance the image moves and stops when the top end of the image is visible, but in my app, it continues to move since i don't know how to check when to stop it. Any idea please?

    Read the article

  • Loading .png image from array of uint8_t into OpenGL ES texture

    - by unknownthreat
    Normally, when we want to load a texture for OpenGL ES with .png, we simply add the .png images into XCode. The .png files will be altered for optimization by XCode and these altered png files can loaded into OpenGL ES texture during the runtime. However, what I am trying to do is quite different. I am trying to load a .png file that is not from the prebuilt/compile. The png file will be transmitted externally from UDP, and it will be in the form of array of bytes. I am very sure that the png is transferred correctly, but when it comes to displaying the png image in the form of the OpenGL ES texture, the image somehow shows incorrectly. The colors that are being sent are presented but the positions are somehow very incorrect. However, the position of the colors still retain some aspects of the original position. Here: The left image shows the original .png, while the right shows the png being displayed on iPhone using OpenGL ES Texture. It looks more like the png data is not being decoded or incorrectly processed. Below is OpenGL ES code for turning the image into texture: - (void) setTextureFromImageByte: (uint8_t*)imageByte{ if (self = [super init]){ NSData* imageData = [[NSData alloc] initWithBytes: imageByte length: imageLength]; UIImage* img = [[UIImage alloc] initWithData: imageData]; CGImageRef image = img.CGImage; int width = 512; int height = 512; if (image){ int tempWidth = (int)width, tempHeight = (int)height; if ((tempWidth & (tempWidth - 1)) != 0 ){ NSLog(@"CAUTION! width is not power of 2. width == %d", tempWidth); }else if ((tempHeight & (tempHeight - 1)) != 0 ){ NSLog(@"CAUTION! height is not power of 2. height == %d", tempHeight); }else{ void *spriteData = calloc(width * 4, height * 4); CGContextRef spriteContext = CGBitmapContextCreate(spriteData, width, height, 8, width*4, CGImageGetColorSpace(image), kCGImageAlphaPremultipliedLast); CGContextDrawImage(spriteContext, CGRectMake(0.0, 0.0, width, height), image); CGContextRelease(spriteContext); glBindTexture(GL_TEXTURE_2D, 1); glTexSubImage2D(GL_TEXTURE_2D, 0, 0, 0, 320, 435, GL_RGBA, GL_UNSIGNED_BYTE, spriteData); free(spriteData); } }else NSLog(@"ERROR: Image not loaded..."); [img release]; [imageData release]; } } So does anyone knows how to deal with this? Is it because of iPhone only accepts altered png from XCode? What can we do in this case in order to make the png image be able to display correctly?

    Read the article

  • jQuery Actual image diamension

    - by Mithun
    I have a 1024x768 image <span class="frame"> <img alt="Image" title="Image" src="http://localhost/zapav/site/assets/questions/D41120CA-7164-11DF-A79E-F4CE462E9D80_Green_Sea_Turtle.jpg"> </span> and the below CSS sets the image width to .frame img{ width:425px; } And the jQuery code $('.uploaded_image img').attr("width"); returns 425 How can i retrieve the actual width of the image 1024 in JavaScipt?

    Read the article

  • Image panning in sencha touch 2

    - by MattD
    I'm trying to have show a large image that the user can pan around (so scroll vertically & horizontally). But I can't get the image to scroll. This is what I have: Ext.define('myapp.view.image.Floorplan', { extend: 'Ext.Container', requires: 'Ext.Img', xtype: 'floorplan', config: { title: 'Floorplan', iconCls: 'locate', items: [ { xtype: 'image', scrollable: true, src: './resources/images/floorplan.png', height: 1570, width: 1047 } ] } }); How can I make the image scrollable? Thanks Matt

    Read the article

  • How to specify the image scaling algorithm used by a WPF Image?

    - by mackenir
    Is there a way to specify how an image is scaled up in an Image element with LayoutTransform set to a ScaleTransform with integer values for ScaleX and ScaleY? I want to display the scaled image crisply (ie using 'nearest neighbour' scaling), with no blurring. (Imagine how you would want a bitmap editing program to behave when zooming in). I noticed the protected property VisualBitmapScalingMode on Image, so created a subclass of Image that sets this property to BitmapScalingMode.NearestNeighbor. However, this had no effect.

    Read the article

  • Image depending on the text in Python/Django

    - by PyOut
    Hello, How can I find an image, depending on the text? I have image model with keywords: class Post(models.Model): image = ImageField(_('Image'), blank=True, upload_to='folder') keywords = models.CharField(_('Keywords'), max_length=80) And model which will serve as the search for a suitable image class TextSearch(models.Model): body = models.TextField(_('Text'))

    Read the article

  • MODx changing my image path

    - by Austin
    In the MODx WYSIWYG whenever I click the Image icon to insert an image, followed by browse image it generates the wrong path: /data/12/1/111/99/1111262/user/1169144/htdocs/images/image.jpg instead of assets/images/image.jpg I have checked my Resource URL and Resource Path and they both look correct. Has anyone ever experienced MODx rewriting your paths to the server vs what it should be? Thanks in advance.

    Read the article

  • swf to image on the website??

    - by eblek
    hi, i want to convert a swf to image on my website. a user makes some changes on the stage and if he press a button "get image link", the swf stage will be converted to an image and its image link will appear within a box. like imageshack.. so user can use it in forums as image. how can i do this? i even dont know it is about flash or html...

    Read the article

  • i get error when i try to upload a file?

    - by getaway
    I keep getting an error:Notice: Undefined index: on line 35 line 35: $handle = new Upload($_FILES['my_field']); this is my input field <input type="file" size="32" name="my_field" value="" /> I do not understand this error, thanks!!! EDIT: <form name="upload" id="upload" enctype="multipart/form-data" method="post" action="actions/upload.php" /> <p><input type="file" size="32" name="my_field" value="" /></p> <p class="button"><input type="hidden" name="action" value="image" /> <br> <input style="margin-left:224px;" type="submit" name="submit" value="upload" />

    Read the article

  • Creando un File Upload

    - by jaullo
    Para iniciar hablaremos un poco sobre el control File Upload, de esta forma daremos una idea general de que es y como trabaja. El File Upload es un control de asp.net que permite que los usuarios seleccionen un archivo de cualquier ubicación en el equipo y lo suban a un directorio predeterminado a traves de una página asp.net. En principio este control esta limitado para no permitir subir archivos de mas de 4 MB. Sin embargo, desde el webconfig de nuestra aplicacón podremos cambiar ese valor, ya sea para aumentarlo o bien para disminuirlo. Nuestro ejemplo, se enfocará en crear un webcontrol que permita seleccionar un archivo y guardarlo, asi que empecemos. Lo primero será agregar a nuestra página un webcontrol que llamaremos Upload.ascx Posteriormente en nuestro webcontrol, agregamos el siguiente código: <table style="width: 100%">         <tr>             <td colspan="3">             <div align="center">                  <asp:Label ID="Label1" runat="server" Text="File Upload"></asp:Label>              </div>             </td>                    </tr>         <tr>             <td style="width: 456px" rowspan="2">                                                             &nbsp;</td>             <td style="width: 386px">                                <div align="center">                         <asp:FileUpload ID="FileUpload1" runat="server" Height="24px" Width="243px" />                         <span id="Span1" runat="server" />                            </div>                      </td>             <td rowspan="2">                                                             </td>         </tr>         <tr>             <td style="width: 386px">                 <div align="center">                      <asp:ImageButton Id="btnupload" runat="server" OnClick="btnupload_Click"                     ImageUrl="~/Styles/img/upload.png" style="text-align: center" />           </div>                  </td>         </tr>         <tr>             <td colspan="3">                 &nbsp;</td>         </tr>     </table>  De esta forma nuestro control deberá verse algo así   Por último en el code behin de nuestro control agregamos el código a nuestro boton, el cual será el encargado de leer el archivo que se encuentra en el File Upload y guardarlo en la ruta especificada.  Protected Sub btnupload_Click(ByVal sender As Object, ByVal e As System.Web.UI.ImageClickEventArgs) Handles btnupload.Click         If FileUpload1.HasFile Then             Dim fileExt As String             fileExt = System.IO.Path.GetExtension(FileUpload1.FileName)             If (fileExt = ".exe") Then                 Label1.Text = "You can´t upload .exe file!"             Else                 Try                     FileUpload1.SaveAs(decrpath & _                        FileUpload1.FileName)                     Label1.Text = "File name: " & _                       FileUpload1.PostedFile.FileName & "<br>" & _                       "File Size: " & _                       FileUpload1.PostedFile.ContentLength & " kb<br>" & _                       "Content type: " & _                       FileUpload1.PostedFile.ContentType                 Catch ex As Exception                     Label1.Text = "ERROR: " & ex.Message.ToString()                 End Try             End If         Else             Label1.Text = "You have not specified a file!"         End If            End Sub   Como vemos en el código anterior tambien hemos agregado otros elementos los cuales nos dirán el nombre del archivo, el tipo de contenido y el tamaño en kb una vez que el archivo ha sido súbido al servidor. Por último deben tomar en cuenta que decrpath es la ruta en donde será subido el archivo, la cual deben variar a su gusto.

    Read the article

  • How to Implement Complex Form Data?

    - by SoulBeaver
    I'm supposed to implement a relatively complex form that looks like follows, but has at least four more pages requiring the user to fill in all necessary information for the tracks: This data will need to be sent to the server, which is implemented using Dropwizard. I'm looking for best practices on how to upload and send such a complex form with potentially dozens of songs to the server. The simplest available solution I have seen is a simple multipart/form-data request with the following form schema (Source): Client <html> <body> <h1>File Upload with Jersey</h1> <form action="rest/file/upload" method="post" enctype="multipart/form-data"> <p> Select a file : <input type="file" name="file" size="45" /> </p> <input type="submit" value="Upload It" /> </form> </body> </html> Server @POST @Path("/upload") @Consumes(MediaType.MULTIPART_FORM_DATA) public Response uploadTrack(final FormDataMultiPart multiPart) { List<FormDataBodyPart> artists = multiPart.getFields("artist"); StringBuffer output = new StringBuffer(); for (FormDataBodyPart artist : artists) output.append(artist.getValueAs(String.class)); List<FormDataBodyPart> tracks = multiPart.getFields("track"); for (FormDataBodyPart track : tracks) writeToFile(track.getValueAs(InputStream.class), "Foo"); return Response.status(200).entity(output.toString()).build(); } Then I have also read about file uploads via Ajax or Formdata (Mozilla HttpRequest) which allows for Posts in the formats application/x-www-form-urlencoded, multipart/form-data, or text/plain. I don't know which approach, if any, is best. An ideal solution would be to utilize Jackson to convert a json string into my data objects, but I don't get the impression that this is possible with binary data.

    Read the article

  • Google Image Search Quick Fix

    - by Asian Angel
    Are you tired of unneeded webpage loading and extra link clicking just to access an image found using Google Image Search? Now you can jump directly to the image itself with the clickGOOGLEview extension for Google Chrome. The Problem When you find an image that you like using Google Image Search you always have to go through extra hassle just to get to the image itself. First you have an entire webpage loading in your browser and then you have to click through that irritating “See full size image” link. All that you need is the image, right? Problem Fixed Once you have installed the clickGOOGLEview extension you will absolutely love the result. Find an image that you like, click the link, and there is your new image without any of the hassle or extra link clicking. Big or small having direct access to the image is how it should have been from the beginning. Conclusion The clickGOOGLEview extension does one thing and does it extremely well…it gets you to those images without the extra hassle or additional link clicking. Links Download the clickGOOGLEview extension (Google Chrome Extensions) Similar Articles Productive Geek Tips Make Firefox Quick Search Use Google’s Beta Search KeysChange Internet Explorer in Windows Vista to Search Google by DefaultMake Firefox Built-In Search Box Use Google’s Experimental Search KeysQuick Tip: Show PageRank in Firefox while Google Toolbar is HiddenQuick Tip: Use Google Talk Sidebar in Firefox TouchFreeze Alternative in AutoHotkey The Icy Undertow Desktop Windows Home Server – Backup to LAN The Clear & Clean Desktop Use This Bookmarklet to Easily Get Albums Use AutoHotkey to Assign a Hotkey to a Specific Window Latest Software Reviews Tinyhacker Random Tips Revo Uninstaller Pro Registry Mechanic 9 for Windows PC Tools Internet Security Suite 2010 PCmover Professional Kill Processes Quickly with Process Assassin Need to Come Up with a Good Name? Try Wordoid StockFox puts a Lightweight Stock Ticker in your Statusbar Explore Google Public Data Visually The Ultimate Excel Cheatsheet Convert the Quick Launch Bar into a Super Application Launcher

    Read the article

  • how to upload & preview multiple images at single input and store in to php mysql [closed]

    - by Nilesh Sonawane
    This is nilesh , i am newcomer in this field , i need the script for when i click the upload button then uploaded images it should preview and store into db like wise i want to upload 10 images at same page using php mysql . #div { border:3px dashed #CCC; width:500px; min-height:100px; height:auto; text-align:center: } Multi-Images Uploader '.$f.''; } } } ? </div> <br> <font color='#3d3d3d' size='small'>By: Ahmed Hussein</font> this script select multiple images and then uplod , but i need to upload at a time only one image which preview and store into database like wise min 10 image user can upload .......

    Read the article

< Previous Page | 20 21 22 23 24 25 26 27 28 29 30 31  | Next Page >