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  • How to create a list/structure? in JAVA

    - by lox
    i have to create a list of ,let's say 50 people, (in JAVA) and display the list, and i don't really know how to do that. so this is what i have tried to do so far . please correct and complete some of my code . public class Person { String name; String stuff; } public class CreatePerson { public static void ang() { ArrayList<Person> thing=new ArrayList<Person>(); Scanner diskScanner = new Scanner(in); for(int i=0; i<50; i++){ Person pers = new Person(); out.print("name: "); pers.name=diskScanner.nextLine(); out.print("stuff: "); pers.stuff=diskScanner.nextLine(); thing.add(pers); break; } // Display people for (int i=0; i<50; i++) { out.println(??);{ } } }}

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  • Linked List push()

    - by JKid314159
    The stack is initialized with a int MaxSize =3. Then I push one int onto the list. " Pushed:" is returned to the console. Program crashes here. I think my logic is flawed but unsure. Maybe an infinite loop or unmet condition? Thanks for your help. I'm trying to traverse the list to the last node in the second part of the full() method. I implemented this stack as array based so must implement this method full() as this method is inside of main class. while(!stacker.full()) { cout << "Enter number = "; cin >> intIn; stacker.push(intIn); cout << "Pushed: " << intIn << endl; }//while Call to LinkListStack.cpp to class LinkList full(). int LinkList::full() { if(head == NULL) { top = 0; } else { LinkNode * tmp1; LinkNode * tmp2; tmp1 = head; while(top != MaxSize) { if(tmp1->next != NULL){ tmp2 = tmp1->next; tmp1 = tmp2; ++top; }//if }//while }//else return (top + 1 == MaxSize); }

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  • Adding items to a generic list (novice)

    - by Crash893
    I'm some what embarrassed to even ask this but I know there is a better way to do this I just don't know how List<int> numbers = new List<int>(22); numbers.Add(3); numbers.Add(4); numbers.Add(9); numbers.Add(14); numbers.Add(15); numbers.Add(19); numbers.Add(28); numbers.Add(37); numbers.Add(47); numbers.Add(50); numbers.Add(54); numbers.Add(56); numbers.Add(59); numbers.Add(61); numbers.Add(70); numbers.Add(73); numbers.Add(78); numbers.Add(81); numbers.Add(92); numbers.Add(95); numbers.Add(97); numbers.Add(99);

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  • linked list sort function only loops once

    - by Tristan Pearce
    i have a singly linked list that i am trying to sort from least to greatest by price. here is what i have so far struct part { char* name; float price; int quantity; struct part *next; }; typedef struct part partType; partType *sort_price(partType **item) { partType *temp1 = *item; partType *temp2 = (*item)->next; if ( *item == NULL || (*item)->next == NULL ) return *item; else { while ( temp2 != NULL && temp2->next != NULL ){ if (temp2->price > temp2->next->price){ temp1->next = temp2->next; temp2->next = temp2->next->next; temp1->next->next = temp2; } temp1 = temp2; temp2 = temp2->next; } } return *item; } the list is already populated but when i call the sort function it only swaps the first two nodes that satisfy the condition in the if statement. I dont understand why it doesnt do the check again after the two temp pointers are incremented.

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  • Adding and sorting a linked list in C

    - by user1202963
    In my assignment, I have to write a function that takes as arguments a pointer to a "LNode" structure and an integer argument. Then, I have to not only add that integer into the linked list, but also put place it so that the list is in proper ascending order. I've tried several various attempts at this, and this is my code as of posting. LNode* AddItem(LNode *headPtr, int newItem) { auto LNode *ptr = headPtr; ptr = malloc(sizeof(LNode)); if (headPtr == NULL) { ptr->value = newItem; ptr->next = headPtr; return ptr; } else { while (headPtr->value > newItem || ptr->next != NULL) { printf("While\n"); // This is simply to let me know how many times the loop runs headPtr = headPtr->next; } ptr->value = newItem; ptr->next = headPtr; return ptr; } } // end of "AddItem" When I run it, and try to insert say a 5 and then a 3, the 5 gets inserted, but then the while loop runs once and I get a segmentation fault. Also I cannot change the arguments as it's part of a skeletal code for this project. Thanks to anyone who can help. If it helps this is what the structure looks like typedef struct LNode { int value; struct LNode *next; } LNode;

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  • What is a better, cleaner way of using List<T>

    - by Tim Meers
    I'm looking to implement a few nicer ways to use List in a couple of apps I'm working on. My current implementation looks like this. MyPage.aspx.cs protected void Page_Load(object sender, EventArgs e) { BLL.PostCollection oPost = new BLL.PostCollection(); oPost.OpenRecent(); rptPosts.DataSource = oArt; rptPosts.DataBind(); } BLL Class(s) public class Post { public int PostId { get; set; } public string PostTitle { get; set; } public string PostContent { get; set; } public string PostCreatedDate { get; set; } public void OpenRecentInitFromRow(DataRow row) { this.PostId = (int) row["id"]; this.PostTitle = (string) row["title"]; this.PostContent = (string) row["content"]; this.PostCreatedDate = (DateTime) row["createddate"]; } } public class PostCollection : List<Post> { public void OpenRecent() { DataSet ds = DbProvider.Instance().Post_ListRecent(); foreach (DataRow row in ds.Tables[0].Rows) { Post oPost = new Post(); oPost.OpenRecentInitFromRow(row); Add(oPost); } } } Now while this is working all well and good, I'm just wondering if there is any way to improve it, and just make it cleaner that having to use the two different classes do to something I think can happen in just one class or using an interface.

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  • C++ Bubble Sorting for Singly Linked List [closed]

    - by user1119900
    I have implemented a simple word frequency program in C++. Everything but the sorting is OK, but the sorting in the following script does not work. Any emergent help will be great.. #include <stdio.h> #include <string.h> #include <stdlib.h> #include <ctype.h> #include <iostream> #include <fstream> #include <cstdio> using namespace std; #include "ProcessLines.h" struct WordCounter { char *word; int word_count; struct WordCounter *pNext; // pointer to the next word counter in the list }; /* pointer to first word counter in the list */ struct WordCounter *pStart = NULL; /* pointer to a word counter */ struct WordCounter *pCounter = NULL; /* Print statistics and words */ void PrintWords() { ... pCounter = pStart; bubbleSort(pCounter); ... } //end-PrintWords void bubbleSort(struct WordCounter *ptr) { WordCounter *temp = ptr; WordCounter *curr; for (bool didSwap = true; didSwap;) { didSwap = false; for (curr = ptr; curr->pNext != NULL; curr = curr->pNext) { if (curr->word > curr->pNext->word) { temp->word = curr->word; curr->word = curr->pNext->word; curr->pNext->word = temp->word; didSwap = true; } } } }

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  • Java How to find a value in a linked list iteratively and recursively

    - by Roxy
    Hi I have a method that has a reference to a linked list and a int value. So, this method would count and return how often the value happens in the linked list. So, I decided to make a class, public class ListNode{ public ListNode (int v, ListNode n) {value = v; next = n;) public int value; public ListNode next; } Then, the method would start with a public static int findValue(ListNode x, int valueToCount){ // so would I do it like this?? I don't know how to find the value, // like do I check it? for (int i =0; i< x.length ;i++){ valueToCount += valueToCount; } So, I CHANGED this part, If I did this recursively, then I would have public static int findValue(ListNode x, int valueToCount) { if (x.next != null && x.value == valueToCount { return 1 + findValue(x, valueToCount);} else return new findvalue(x, valueToCount); SO, is the recursive part correct now?

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  • Rails how to return a list of answers with a specific question_id

    - by mytwocentsisworthtwocents
    Let's say I have two Models, Answers and Questions (there are others, but irrelevant to the question). The models are as follows: Answer.rb class Answer < ActiveRecord::Base attr_accessible :description, :question_id has_one :question, :through => :user, :dependent => :destroy validates :description, :presence => true end Question.rb class Question < ActiveRecord::Base attr_accessible :budget, :description, :headline, :user_id, :updated_at, :created_at belongs_to :user has_many :answers validates :headline, :description, :user_id, :presence => true end I'd like to display on a page a list of all answers associated with a question, and only those questions. I got this far. I believe this variable finds all the questions in the database by the question_id (foreign key): @findanswers = Answer.all(params[:question_id]) And this one grabs the the id of the current question (this code will reside as an ERB on the page where the current question is located): @questionshow = Question.find(params[:id]) And now I'm stuck. How do I put the two together so that I list all the answers with the current question id?

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  • Sorting a Singly Linked List With Pointers

    - by Mark Simson
    I am trying to sort a singly linked list using bubble sort by manipulating ONLY the pointers, no keys. The following gets stuck in the for loop and loops infinitely. I don't understand why this is. Can anybody explain to me why the end of the list is not being found? Node* sort_list(Node* head) { Node * temp; Node * curr; for(bool didSwap = true; didSwap; ) { didSwap = false; for(curr = head; curr->next != NULL; curr = curr->next) { if(curr->key > curr->next->key) { temp = curr; curr = curr->next; curr->next = temp; didSwap = true; } cout << curr->next->key << endl; } } return head; } If I change the code so that the keys (data) are swapped, then the function works properly but for some reason I am not able make it work by manipulating only pointers.

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  • Having trouble deleting a node from a linked list

    - by Requiem
    I've been working on this code for my shell that I'm creating and for some reason it isn't working. I'm implementing a watchuser function that watch's a user when an argument is given (args[1]). However, when a second argument (args[2]) of "off" is given, the user should be deleted from the linked list and should no longer be watched. struct userList * goList; goList = userInventory; do{ if (strcmp(userInventory->username, args[1]) == 0){ printf("%s\n", args[1]); printf("%s\n",userInventory->username); struct userList * temp2; temp2 = userInventory->next; if (userInventory->next != NULL){ userInventory->next = temp2->next; userInventory->next->prev = userInventory; } free(temp2); } goList = goList->next; }while (goList != userInventory); My global struct is also as follows: struct userList{ char * username; struct userList * prev; struct userList * next; } For reason, this code won't delete the user node from my linked list. The adding works, but this remove function won't and I'm not sure why. The print statements are there just to make sure it's executing the condition, which it is. If anyone could help me find the reasoning behind my error, I'd greatly appreciate it. Till then, I'll be trying to debug this. Thanks.

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  • server will not reply (syn -ack)

    - by Brent
    I like to use the following commands to manage 'TIME_WAIT', in the hope to free up resources. echo 20 > /proc/sys/net/ipv4/tcp_fin_timeout sysctl -w net.ipv4.tcp_tw_reuse=1 sysctl -w net.ipv4.tcp_tw_recycle=1 I found something interesting while doing a tcpdump. Sometimes if a client makes a connection (syn), the server will not reply (syn -ack). My question is, could it be because of the top three commands.

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  • Exchange out of office, sending an OoO reply for every email

    - by rodey
    We are running Exchange 2007 with a mix of Outlook 2003 and Outlook 2007. Is it possible to set the Out of Office Assistant so that when OoO is enabled, it sends a reply to every single email the user receives? Also, is there something I can reference that covers the options for OoO such as length of time between replies, etc.? Thanks!

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  • Exchange out of office, sending an OoO reply for every email

    - by rodey
    We are running Exchange 2007 with a mix of Outlook 2003 and Outlook 2007. Is it possible to set the Out of Office Assistant so that when OoO is enabled, it sends a reply to every single email the user receives? Also, is there something I can reference that covers the options for OoO such as length of time between replies, etc.? Thanks!

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  • Thunderbird 3 "Reply to all", also replies to myself

    - by Jj
    I have my job IMAP account set up in TB 3.0.3. It's becoming very annoying that in group emails where I'm in the CC or TO list I hit "Reply To All" and I find myself in the recipients list. So when I send the email I also get a copy of my own email. I haven't found where to disable or modify this. This doesn't happen with my Gmail account (also set up in TB)

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  • Exchange 2010 global auto reply - hub transport rules?

    - by RodH257
    Our office is closing for the holidays, and I want to setup an auto reply if anyone attempts to email. Rather than get everyone to do it individually I want to set a blanket message on the Exchange 2010 server. Looking around here I found hub transport rules can be used, but I don't want to send a rejection message, like in this post I want to keep the message but just say that we won't get back to you fora couple of weeks. Can anyone point me in the right direction?

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  • Always set "reply-to" for certain recipients?

    - by Benjamin Oakes
    Is it possible to always have Thunderbird set "reply-to" for a certain set of recipients? I sometimes email my significant other at work (about upcoming office parties, events, etc. that she would need to know about), but I'd like to handle the rest of the discussion from my personal email account.

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  • Notes: No reply or respond option

    - by Eqbal
    One of my colleagues got an invite that looks like an email but there is no "Reply" button available. If its a meeting invite (which I can't tell), it has no "Respond" option available. Anyone seen this before?

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  • GMail appearing to ignore Reply-To.

    - by Samuurai
    I'm using a gmail account to send emails from my website. I'm using the same account to pick up emails which are generated by the contact facility on my site. I'm using the Reply-To field to attempt to make it easier to hit reply and easily get back to people. The message comes up with the 'from' address and ignores the 'reply-to' address. Here's my header: Return-Path: <[email protected]> Received: from svr1 (ec2-79-125-266-266.eu-west-1.compute.amazonaws.com [79.125.266.266]) by mx.google.com with ESMTPS id u14sm23273123gvf.17.2010.03.10.14.33.24 (version=TLSv1/SSLv3 cipher=RC4-MD5); Wed, 10 Mar 2010 14:33:25 -0800 (PST) Received: from localhost ([127.0.0.1] helo=www.rds.com) by aquacouture with esmtp (Exim 4.69) (envelope-from <[email protected]>) id 1NpUSx-0001dK-JM for [email protected]; Wed, 10 Mar 2010 22:33:23 +0000 User-Agent: CodeIgniter Date: Wed, 10 Mar 2010 22:33:23 +0000 From: "New Inquiry" <[email protected]> Reply-To: "Beren" <[email protected]> To: [email protected] Subject: =?utf-8?Q?Test?= X-Sender: [email protected] X-Mailer: CodeIgniter X-Priority: 3 (Normal) Message-ID: <[email protected]> Mime-Version: 1.0 Content-Type: multipart/alternative; boundary="B_ALT_4b981e3390ccd" This is a multi-part message in MIME format. Your email application may not support this format. --B_ALT_4b981e3390ccd Content-Type: text/plain; charset=utf-8 Content-Transfer-Encoding: 8bit test --B_ALT_4b981e3390ccd Content-Type: text/html; charset=utf-8 Content-Transfer-Encoding: quoted-printable test --B_ALT_4b981e3390ccd--

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  • convert a binary file in a list (python)

    - by beratch
    Hi all, I'd like to be able to open a binary file, and make a list (kind of array) with all the chars in, like : "\x21\x23\x22\x21\x22\x31" to ["\x21","\x23","\x22","\x21","\x22","\x31"] What would be the best solution to convert it ? Thanks !

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  • Handwritten linked list is segfaulting and I don't understand why

    - by Born2Smile
    Hi I was working on a bit of fun, making an interface to run gnuplot from within c++, and for some reason the my linked list implementation fails. The code below fails on the line plots-append(&plot). Stepping through the code I discovered that for some reason the destructor ~John() is called immediately after the constructor John(), and I cannot seem to figure out why. The code included below is a stripped down version operating only on Plot*. Originally I made the linked list as a template class. And it worked fine as ll<int and ll<char* but for some reason it fails as ll<Plot*. Could youp please help me figure out why it fails? and perhaps help me understand how to make it work? In advance: Thanks a heap! //B2S #include <string.h class Plot{ char title[80]; public: Plot(){ } }; class Link{ Plot* element; Link* next; Link* prev; friend class ll; }; class ll{ Link* head; Link* tail; public: ll(){ head = tail = new Link(); head-prev = tail-prev = head-next = tail-next = head; } ~ll(){ while (head!=tail){ tail = tail-prev; delete tail-next; } delete head; } void append(Plot* element){ tail-element = element; tail-next = new Link(); tail-next-prev = tail; tail-next = tail; } }; class John{ ll* plots; public: John(){ plots= new ll(); } ~John(){ delete plots; } John(Plot* plot){ John(); plots-append(plot); } }; int main(){ Plot p; John k(&p); }

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  • Move node in adjacency list

    - by Industrial
    Hi everyone, I am working on an adjacency list with mySQL and can not (atleast by myself) do the thinking needed to make a decent enough query to be able to move a set of nodes (together with eventual children nodes) around. The table has following columns: id name left right Thanks a lot!

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  • Navbar List Items Not Showing in Internet Explorer 6

    - by Theo
    Hi everyone, I have a bit of a problem with a navbar not displaying correctly in IE6. http://classicpartsltd.com/ - this is the page, and if you hover over a nav item such as 'Goggles' in IE6 you will see that some of the list items are showing up, but that they will in IE7 and IE8... Does anyone know why this would be the case? Many thanks, Theo.

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  • Multiple group expressions in list (ssrs 2005)

    - by Kris
    Hi, I have a problem with group expressions in a list. I want to use two expressions: '=Ceiling(RowNumber(Nothing)/3)' and '=Cint(Fields!kpilevel.Value)' They work both individually, but when I insert them together only 1 works. I inserted them like this: http://img718.imageshack.us/img718/736/problemxq.png Does anyone know how to solve this? Thanks in advance, Kris

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