Search Results

Search found 45836 results on 1834 pages for 'right to left layout'.

Page 241/1834 | < Previous Page | 237 238 239 240 241 242 243 244 245 246 247 248  | Next Page >

  • Algorithm: Determine shape of two sectors delineated by an arbitrary path, and then fill one.

    - by Arseniy Banayev
    NOTE: This is a challenging problem for anybody who likes logic problems, etc. Consider a rectangular two-dimensional grid of height H and width W. Every space on the grid has a value, either 0 1 or 2. Initially, every space on the grid is a 0, except for the spaces along each of the four edges, which are initially a 2. Then consider an arbitrary path of adjacent (horizontally or vertically) grid spaces. The path begins on a 2 and ends on a different 2. Every space along the path is a 1. The path divides the grid into two "sectors" of 0 spaces. There is an object that rests on an unspecified 0 space. The "sector" that does NOT contain the object must be filled completely with 2. Define an algorithm that determines the spaces that must become 2 from 0, given an array (list) of values (0, 1, or 2) that correspond to the values in the grid, going from top to bottom and then from left to right. In other words, the element at index 0 in the array contains the value of the top-left space in the grid (initially a 2). The element at index 1 contains the value of the space in the grid that is in the left column, second from the top, and so forth. The element at index H contains the value of the space in the grid that is in the top row but second from the left, and so forth. Once the algorithm finishes and the empty "sector" is filled completely with 2s, the SAME algorithm must be sufficient to do the same process again. The second (and on) time, the path is still drawn from a 2 to a different 2, across spaces of 0, but the "grid" is smaller because the 2s that are surrounded by other 2s cannot be touched by the path (since the path is along spaces of 0). I thank whomever is able to figure this out for me, very very much. This does not have to be in a particular programming language; in fact, pseudo-code or just English is sufficient. Thanks again! If you have any questions, just leave a comment and I'll specify what needs to be specified.

    Read the article

  • Jquery slider going the wrong way

    - by Rob
    Im using a jquery slider and having an issue with what direction it scrolls on click. It seems to screw up after clicking the right arrow then left, but will scroll left if clicked first, weird. Is this a bug or am I missing something here? PS- Im using Chrome (Mac) but seems to behave the same with Firefox and Safari See example http://www.warface.co.uk/clients/warface.co.uk/blog/ Please click the red central arrow to reveal the slider. Many thanks Rob

    Read the article

  • How can I set opacity of the reflection when using -webkit-box-reflect?

    - by Mike Palmer
    I've been playing with the -webkit-box-reflect property in Chrome and can achieve a reflection that fades with the following code (it's example code from the Webkit blog): -webkit-box-reflect: below 5px -webkit-gradient( linear, left top, left bottom, from(transparent), color-stop(0.5, transparent), to(white) ); Problem is, I want to set the opacity for the mask to a more subtle setting, but it seems to be choking on rgba(). Has anybody been able to successfully get different levels of opacity? Any help is appreciated, thanks!

    Read the article

  • angular-ui-router : breadcrumps ok but view ko

    - by anakin59490
    this is my app.router.js : agentRouter.config([ '$stateProvider', '$urlRouterProvider', function($stateProvider, $urlRouterProvider) { var root = { name: 'root', abstract: true, url: '', title: 'home', views: { 'header': { templateUrl: 'views/headers/header.app.html', controller: 'HeaderCtrl' }, 'body': { templateUrl: "views/root.html" }, 'footer': { templateUrl: 'views/footers/footer.app.html' } } }; var agent = { name: 'root.agent', url: '/agent', title: 'agent', views: { 'root.sidebar': { templateUrl: "views/main.sidebar.html" }, 'root.container': { templateUrl: "views/partials/agent/list.container.html" } } }; var detail = { name: 'root.agent.detail', url: '/detail/:id', title: 'agentDetail', // use for breadcrumb views: { 'root.sidebar': { templateUrl: "views/main.sidebar.html" }, 'root.container': { templateUrl: "views/partials/agent/list.chantier.html" } } }; /.../ $stateProvider.state(root); $stateProvider.state(agent); $stateProvider.state(detail); } ]); and this is my root.html : <!--Breadcrumb content--> <ul class="row breadcrumb"> <i class="glyphicon glyphicon-home" style=""></i> <li ng-repeat="state in $state.$current.path"> <a ng-href="#{{state.url.format($stateParams)}}"><span ng-bind="state.title"></span></a> <span ng-hide="$last" class=""></span> </li> </ul> <!--Sidebar content--> <div ui-view="root.sidebar">default root.sidebar</div> <!--Container content--> <div style="background-color: #f9f9f9" ui-view="root.container">default root.container</div> I can access to my "agent" page (a list of person) and my breadcrumb is right : home / agent but when i click on an item of the list i got always the same page but my breadcrumb is right : home / agent / agentDetail but in app.router.js if change detail like this : var detail = { name: 'root.detail', // référence initiale + detail (fils) url: '/agent/detail/:id', // réference utilisée dans les fichiers HTML, attention c'est la suite de l'url précédente!!! title: 'agentDetail', // référence utilisée pour le breadcump views: { 'root.sidebar': { templateUrl: "views/main.sidebar.html" }, 'root.container': { templateUrl: "views/partials/agent/list.chantier.html" } } }; i got the right page (list.chantier.xml) but the breadcrumb is false : home / agentDetail instead of home / agent / agentDetail I would like to got the right breadcrumb (home / agent / agentDetail) with the right page (list.chantier.html) when i click on an item of the agent list page (list.container.html) Thank you in advance for your help

    Read the article

  • infix operation to postfix using stacks

    - by Chris De La O
    We are writing a program that needs to convert an infix operation (4 5/3) to postfix (4 5 3 / ) using stacks. however my convert to postfix does not work as it doesnt not output the postFix array that is supposed to store the conversion from infix notation to postfix notation. here is the code for the convertToPostix fuction. //converts infix expression to postfix expression void ArithmeticExpression::convertToPostfix(char *const inFix, char *const postFix) { //create a stack2 object named cow Stack2<char> cow; cout<<postFix; char thing = '('; //push a left parenthesis onto the stack cow.push(thing); //append a right parenthesis to the end of inFix array strcat(inFix, ")"); int i = 0;//declare an int that will control posFix position //if the stack is not empty if (!cow.isEmpty()) { //loop to run until the last character in inFix array for (int x = 0; inFix[x]!= '\0'; x++ ) { //if the inFix element is a digit if (isdigit(inFix[x])) { postFix[i]=inFix[x];//it is assigned to the next element in postFix array i++;//move on to next element in postFix } //if the inFix element is a left parenthesis else if (inFix[x]=='(') { cow.push(inFix[x]);//push it unto the stack } //if the inFix element is an operator else if (isOperator(inFix[x])) { char oper2 = inFix[x];//char variable holds inFix operator if (isOperator(cow.stackTop()))//if the top node in the stack is an operator { while (isOperator(cow.stackTop()))//and while the top node in the stack is an operator { char oper1 = cow.stackTop();//char variable holds node operator if(precedence( oper1, oper2))//if the node operator has higher presedence than node operator { postFix[i] = cow.pop();//we pop such operator and insert it in postFix array's next element cow.push(inFix[x]);//and push inFix operator unto the stack i++;//move to the next element in posFix } } } //if the top node is not an operator //we push the current inFix operator unto the top of the stack else cow.push(inFix[x]); } //if the inFix element is a right parenthesis else if (inFix[x]==')') { //we pop everything in the stack and insert it in postFix //until we arrive at a left paranthesis while (cow.stackTop()!='(') { postFix[i] = cow.pop(); i++; } //we then pop and discard left parenthesis cow.pop(); } } postFix[i]='\0'; //print !!postFix array!! (not stack) print();//code for this is just cout<<postFix; }

    Read the article

  • Operator overloading in C++

    - by user265260
    If you overload - like operator-(), it is to be used to the left of the object, however overloading () like operator()() it is used to the right of the object. How do we know which operator is to be used on the left and which ones to be used on the right?

    Read the article

  • need help to float a header in a wordpress theme

    - by aadil ennia
    i need help with a wordpress theme, i want to localize a theme but i have some problemes my new blog is in arabic (rtl) and i want to replace the theme logo in the right (float to right) and the banner ad to the left side in the header, also i tried to float the search bar to the left but i did not succeed in that, can you please help me to localize this great theme? ah i forget to tell you the theme name is "Vanillia" http://newwpthemes.com/wordpress-theme/vanillia/ here is a screenshot of what i need to do (http://) i47.tinypic.com/28cg0ax.png

    Read the article

  • Is there a way to get all valid keywords for CSS property?

    - by NV
    Round two. First was "How do I get all supported CSS properties in WebKit?". I'm looking for magic CSSkeywords function: CSSkeywords('float') --> ['left', 'right', 'none'] CSSkeywords('width') --> ['auto'] CSSkeywords('background') --> [ ["repeat", "repeat-x", "repeat-y", "no-repeat"], ["scroll", "fixed"], ["top", "center", "bottom", "left"], /*regexp for color*/, /*regexp for url*/, "none" ]

    Read the article

  • How can i learn Table Name in database an column name?

    - by Phsika
    How can i learn table Name in database an how can i learn any Table's Column name? SELECT Col.COLUMN_NAME, Col.DATA_TYPE FROM INFORMATION_SCHEMA.COLUMNS AS Col LEFT OUTER JOIN INFORMATION_SCHEMA.CONSTRAINT_COLUMN_USAGE AS Usg ON Col.TABLE_NAME = Usg.TABLE_NAME AND Col.COLUMN_NAME = Usg.COLUMN_NAME LEFT OUTER JOIN INFORMATION_SCHEMA.TABLE_CONSTRAINTS AS Con ON Usg.CONSTRAINT_NAME = Con.CONSTRAINT_NAME WHERE Col.TABLE_NAME = 'Addresses_Temp' AND Con.Constraint_TYPE = 'PRIMARY KEY' But it returns to me empty data:(

    Read the article

  • Two List Boxes side by side and stretchable

    - by Ilya Biryukov
    I have two list boxes like show below, side by side. They both have anchors on top, bottom, left and right. When I stretch the window the left listbox grows over the right one. While I want the margin between them to stay and for both listboxes to expand evenly. Is there anyway to achieve this? Thanks!

    Read the article

  • vertical divider css

    - by 422
    I am creating a vertical divider, that works fine. But the css is cumbersome. The css is: .headerDivider1 { border-left:1px solid #38546d;height:80px;position:absolute;right:250px;top:10px; } .headerDivider2 { border-left:1px solid #16222c;height:80px;position:absolute;right:249px;top:10px; } The html is: <div class="headerDivider1"></div><div class="headerDivider2"></div> The result is: How could I tidy the html and css up please ?

    Read the article

  • How to append() an element and set its style with css() at the same time with jQuery

    - by Acorn
    I tried: $('#canvas').append('<div class="tile"></div>').css({left: leftPos, top: topPos});, but that sets the style of #canvas rather than the appended element. I then tried: $('#canvas').append(('<div class="tile"></div>').css({left: leftPos, top: topPos}));, but that gives the error "Object <div class="tile"></div> has no method 'css'". How can I add the element and set its style at the same time?

    Read the article

  • SubSonic 3 LeftOuterJoin

    - by michaelpearce
    I have read in this forum that left outer join syntax is not supported by subsonic in an answer to a question on the topic by "Apocatastasis". I have the same issue in that when I create a query using the .LeftOuterJoin the resulting sql has an inner join rather than a left outer join. Can someone please confirm that LeftOuterJoin is indeed not supported and, if that is the case, why is it included in the active record syntax? Thanks Michael

    Read the article

  • Does Oracle re-hash the driving table for each join on the same table columns?

    - by thecoop
    Say you've got the following query on 9i: SELECT /*+ USE_HASH(t2 t3) */ * FROM table1 t1 -- this has lots of rows LEFT JOIN table2 t2 ON t1.col1 = t2.col1 AND t1.col2 = t2.col2 LEFT JOIN table3 t3 ON t1.col1 = t3.col1 AND t1.col2 = t3.col2 Due to 9i not having RIGHT OUTER HASH JOIN, it needs to hash table1 for both joins. Does it re-hash table1 between joining t2 and t3 (even though it's using the same join columns), or does it keep the same hash information for both joins?

    Read the article

  • How do i get the mouse position?

    - by acidzombie24
    Basically in relation to this question It seems like e.X,y and e.Location.X,Y is relative to mousedown? I seen negative values when i havent moved it left/above the parent picbox. So it seems like the values are relative to my mousedown, but i need values relative to the parent because i update the left/top every event and other datat and relative to mousedown is breaking my code.

    Read the article

  • submenu items in WPF Menu

    - by Vishal
    how to make SUBMENU ites visible vertical as a left navigation in CODEGURU.COM In windows we use layoutstyle property to make all main and child items to be viewed vertical and DOCK the menustrip to left. How to acheive this in WPF

    Read the article

  • trouble in using flalign (LaTeX)

    - by Jorge
    I am trying to put 3 equations with "=" signs aligned but also left aligned. I tried the following: \documentclass{article} \usepackage{amsmath} \begin{document} \begin{flalign*} RPC &= A+B\tilde{f} +C x &\ A &= a+\eta &\ E &= cte & \end{flalign*} \end{document} With this I get the stuff in the left and the "=" signs aligned. However, I also need A (in the second equation) and E (in the third equation) to be aligned to the R (in the first one) Does anyone know how to get it? thanks

    Read the article

  • KnockoutJS showing a sorted list by item category

    - by Darksbane
    I just started learning knockout this week and everything has gone well except for this one issue. I have a list of items that I sort multiple ways but one of the ways I want to sort needs to have a different display than the standard list. As an example lets say I have this code var BetterListModel = function () { var self = this; food = [ { "name":"Apple", "quantity":"3", "category":"Fruit", "cost":"$1", },{ "name":"Ice Cream", "quantity":"1", "category":"Dairy", "cost":"$6", },{ "name":"Pear", "quantity":"2", "category":"Fruit", "cost":"$2", },{ "name":"Beef", "quantity":"1", "category":"Meat", "cost":"$3", },{ "name":"Milk", "quantity":"5", "category":"Dairy", "cost":"$4", }]; self.allItems = ko.observableArray(food); // Initial items // Initial sort self.sortMe = ko.observable("name"); ko.utils.compareItems = function (l, r) { if (self.sortMe() =="cost"){ return l.cost > r.cost ? 1 : -1 } else if (self.sortMe() =="category"){ return l.category > r.category ? 1 : -1 } else if (self.sortMe() =="quantity"){ return l.quantity > r.quantity ? 1 : -1 }else { return l.name > r.name ? 1 : -1 } }; }; ko.applyBindings(new BetterListModel()); and the HTML <p>Your values:</p> <ul class="deckContents" data-bind="foreach:allItems().sort(ko.utils.compareItems)"> <li><div style="width:100%"><div class="left" style="width:30px" data-bind="text:quantity"></div><div class="left fixedWidth" data-bind="text:name"></div> <div class="left fixedWidth" data-bind="text:cost"></div> <div class="left fixedWidth" data-bind="text:category"></div><div style="clear:both"></div></div></li> </ul> <select data-bind="value:sortMe"> <option selected="selected" value="name">Name</option> <option value="cost">Cost</option> <option value="category">Category</option> <option value="quantity">Quantity</option> </select> </div> So I can sort these just fine by any field I might sort them by name and it will display something like this 3 Apple $1 Fruit 1 Beef $3 Meat 1 Ice Cream $6 Dairy 5 Milk $4 Dairy 2 Pear $2 Fruit Here is a fiddle of what I have so far http://jsfiddle.net/Darksbane/X7KvB/ This display is fine for all the sorts except the category sort. What I want is when I sort them by category to display it like this Fruit 3 Apple $1 Fruit 2 Pear $2 Fruit Meat 1 Beef $3 Meat Dairy 1 Ice Cream $6 Dairy 5 Milk $4 Dairy Does anyone have any idea how I might be able to display this so differently for that one sort?

    Read the article

  • Cakephp beforeFind() - How do I add a JOIN condition AFTER the belongsTo association is added?

    - by michael
    I'm in Model-beforeFind($queryData), trying to add a JOIN condition to the queryData on a model which has belongsTo associations. Unfortunately, the new JOIN references a table in the belongsTo association, so it must appear AFTER the belongsTo in the query. Here is my Tagged-belongsTo association: app\plugins\tags\models\tagged.php (line 192) Array ( [Tag] => Array ( [className] => Tag [foreignKey] => tag_id [conditions] => [fields] => [order] => [counterCache] => ) [Group] => Array ( [className] => Group [foreignKey] => foreign_key [conditions] => Array ( [Tagged.model] => Group ) [fields] => [order] => [counterCache] => ) ) Here is the JOIN added in Tagged-beforeFind(), notice that the belongsTo joins have not yet been added: app\plugins\tags\models\tagged.php (line 194) Array ( [conditions] => Array ( [Tag.keyname] => europe ) [fields] => Array ( [0] => DISTINCT Group.* [1] => GroupPermission.* ) [joins] => Array ( [0] => Array ( [table] => permissions [alias] => GroupPermission [foreignKey] => [type] => INNER [conditions] => Array ( [GroupPermission.model] => Group [0] => GroupPermission.foreignId = Group.id [or] => Array ( ... ) ) ) ) [limit] => [offset] => [order] => Array ( [0] => ) [page] => 1 [group] => [callbacks] => 1 [by] => europe [model] => Group ) When I check the output, it fails with "1054: Unknown column 'Group.id' in 'on clause'" because the Permissions join appeared BEFORE the Groups join. SELECT DISTINCT `Group`.*, `GroupPermission`.* FROM `tagged` AS `Tagged` INNER JOIN permissions AS `GroupPermission` ON (`GroupPermission`.`model` = 'Group' AND `GroupPermission`.`foreignId` = `Group`.`id` AND (...)) LEFT JOIN `tags` AS `Tag` ON (`Tagged`.`tag_id` = `Tag`.`id`) LEFT JOIN `groups` AS `Group` ON (`Tagged`.`foreign_key` = `Group`.`id` AND `Tagged`.`model` = 'Group') WHERE `Tag`.`keyname` = 'europe' But this SQL (with Permissions joined moved to the end) works fine: SELECT DISTINCT `Group`.*, `GroupPermission`.* FROM `tagged` AS `Tagged` LEFT JOIN `tags` AS `Tag` ON (`Tagged`.`tag_id` = `Tag`.`id`) LEFT JOIN `groups` AS `Group` ON (`Tagged`.`foreign_key` = `Group`.`id` AND `Tagged`.`model` = 'Group') INNER JOIN permissions AS `GroupPermission` ON (`GroupPermission`.`model` = 'Group' AND `GroupPermission`.`foreignId` = `Group`.`id` AND (...)) WHERE `Tag`.`keyname` = 'europe' How do I add my join in beforeFind() after the belongsTo join?

    Read the article

  • Passing ActionListeners in Java, pack()

    - by Crystal
    Two questions. First question is I'm trying to create a simple form that when you press a button, it adds a Person object to the ArrayList. However, since I am not used to GUIs, I tried creating one and am first just trying to get the user input from the JTextField, create an ActionListener object of the appropriate type, so once that works, then I can pass in all the JTextField inputs to create my Person object. Unfortunately, I am not getting any data when I type in something to the firstName JTextField and was wondering if someone could look at my code below. import java.awt.*; import java.awt.event.*; import javax.swing.*; import java.util.List; import java.util.ArrayList; public class AddressBook { public static void main(String[] args) { EventQueue.invokeLater(new Runnable() { public void run() { AddressBookFrame frame = new AddressBookFrame(); frame.setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE); JMenuBar menuBar = new JMenuBar(); frame.setJMenuBar(menuBar); JMenu fileMenu = new JMenu("File"); JMenuItem openItem = new JMenuItem("Open"); JMenuItem saveItem = new JMenuItem("Save"); JMenuItem saveAsItem = new JMenuItem("Save As"); JMenuItem printItem = new JMenuItem("Print"); JMenuItem exitItem = new JMenuItem("Exit"); fileMenu.add(openItem); fileMenu.add(saveItem); fileMenu.add(saveAsItem); fileMenu.add(printItem); fileMenu.add(exitItem); menuBar.add(fileMenu); JMenu editMenu = new JMenu("Edit"); JMenuItem newItem = new JMenuItem("New"); JMenuItem editItem = new JMenuItem("Edit"); JMenuItem deleteItem = new JMenuItem("Delete"); JMenuItem findItem = new JMenuItem("Find"); JMenuItem firstItem = new JMenuItem("First"); JMenuItem previousItem = new JMenuItem("Previous"); JMenuItem nextItem = new JMenuItem("Next"); JMenuItem lastItem = new JMenuItem("Last"); editMenu.add(newItem); editMenu.add(editItem); editMenu.add(deleteItem); editMenu.add(findItem); editMenu.add(firstItem); editMenu.add(previousItem); editMenu.add(nextItem); editMenu.add(lastItem); menuBar.add(editMenu); JMenu helpMenu = new JMenu("Help"); JMenuItem documentationItem = new JMenuItem("Documentation"); JMenuItem aboutItem = new JMenuItem("About"); helpMenu.add(documentationItem); helpMenu.add(aboutItem); menuBar.add(helpMenu); frame.setVisible(true); } }); } } class AddressBookFrame extends JFrame { public AddressBookFrame() { setLayout(new BorderLayout()); setTitle("Address Book"); setSize(DEFAULT_WIDTH, DEFAULT_HEIGHT); AddressBookToolBar toolBar = new AddressBookToolBar(); add(toolBar, BorderLayout.NORTH); AddressBookStatusBar aStatusBar = new AddressBookStatusBar("5"); add(aStatusBar, BorderLayout.SOUTH); AddressBookForm form = new AddressBookForm(); add(form, BorderLayout.CENTER); } public static final int DEFAULT_WIDTH = 500; public static final int DEFAULT_HEIGHT = 500; } /* Create toolbar buttons and add buttons to toolbar */ class AddressBookToolBar extends JPanel { public AddressBookToolBar() { setLayout(new FlowLayout(FlowLayout.LEFT)); JToolBar bar = new JToolBar(); JButton newButton = new JButton("New"); JButton editButton = new JButton("Edit"); JButton deleteButton = new JButton("Delete"); JButton findButton = new JButton("Find"); JButton firstButton = new JButton("First"); JButton previousButton = new JButton("Previous"); JButton nextButton = new JButton("Next"); JButton lastButton = new JButton("Last"); bar.add(newButton); bar.add(editButton); bar.add(deleteButton); bar.add(findButton); bar.add(firstButton); bar.add(previousButton); bar.add(nextButton); bar.add(lastButton); add(bar); } } /* Creates the status bar string */ class AddressBookStatusBar extends JPanel { public AddressBookStatusBar(String statusBarString) { setLayout(new FlowLayout(FlowLayout.LEFT)); this.statusBarString = new JLabel("Total number of people: " + statusBarString); add(this.statusBarString); } private JLabel statusBarString; private int totalContacts; } class AddressBookForm extends JPanel { public AddressBookForm() { this.setLayout(new GridLayout(2, 1)); JPanel formPanel = new JPanel(); formPanel.setLayout(new GridLayout(4, 2)); JTextField firstName = new JTextField(20); JTextField lastName = new JTextField(20); JTextField telephone = new JTextField(20); JTextField email = new JTextField(20); JLabel firstNameLabel = new JLabel("First Name: ", JLabel.LEFT); formPanel.add(firstNameLabel); formPanel.add(firstName); JLabel lastNameLabel = new JLabel("Last Name: ", JLabel.LEFT); formPanel.add(lastNameLabel); formPanel.add(lastName); JLabel telephoneLabel = new JLabel("Telephone: ", JLabel.LEFT); formPanel.add(telephoneLabel); formPanel.add(telephone); JLabel emailLabel = new JLabel("Email: ", JLabel.LEFT); formPanel.add(emailLabel); formPanel.add(email); add(formPanel); JPanel buttonPanel = new JPanel(); JButton insertButton = new JButton("Insert"); JButton displayButton = new JButton("Display"); // create button actions AddressBookManager insertAction = new AddressBookManager(firstName.getText()); insertButton.addActionListener(insertAction); buttonPanel.add(insertButton); buttonPanel.add(displayButton); add(buttonPanel); } private List<Person> addressList = new ArrayList<Person>(); private class AddressBookManager implements ActionListener { public AddressBookManager(String text) { // addressList.add( setName(text); System.out.println("Test" + text); } public void actionPerformed(ActionEvent e) { System.out.println("Hello" + name); } public void setName(String name) { this.name = name; } private String name; } } Second question is, how do I make my form not take up the whole center space. I don't like the stretch look and was hoping the JTextFields could be just one line long, not a big box. Same thing with the buttons. Any thoughts? Thanks.

    Read the article

  • MySQL join problem

    - by snaken
    Whats wrong with this SQL? It should return results but returns nothing SELECT `pid` FROM `products` LEFT JOIN `prods_to_features` ON (`ptf_pid` = `pid`) WHERE (`ptf_id` = '66' OR `ptf_id` = '67') AND (`ptf_id` = '76') Is it not possible to have the 2nd where clause for the table that has been used in the left join?

    Read the article

< Previous Page | 237 238 239 240 241 242 243 244 245 246 247 248  | Next Page >