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  • Rails dealing with blank params at controller level

    - by stephenmurdoch
    I have a User model: class User < ActiveRecord::Base has_secure_password # validation lets users update accounts without entering password validates :password, presence: { on: :create }, allow_blank: { on: :update } validates :password_confirmation, presence: { if: :password_digest_changed? } end I also have a password_reset_controller: def update # this is emailed to the user by the create action - not shown @user=User.find_by_password_reset_token!(params[:id]) if @user.update_attributes(params[:user]) # user is signed in if password and confirmation pass validations sign_in @user redirect_to root_url, :notice => "Password has been reset." else flash.now[:error] = "Something went wrong, please try again." render :edit end end Can you see the problem here? A user can submit a blank a password/confirmation and rails will sign them in, because the User model allows blank on update. It's not a security concern, since an attacker would still need access to a user's email account before they could get anywhere near this action, but my problem is that a user submitting 6 blank chars would be signed in, and their password would not be changed for them, which could lead to confusion later on. So, I've come up with the following solution, and I'd like to check if there's a better way of doing it, before I push to production: def update @user=User.find_by_password_reset_token!(params[:id]) # if user submits blank password, add an error, and render edit action if params[:user][:password].blank? @user.errors.add(:password_digest, "can't be blank.") render :edit elsif @user.update_attributes(params[:user]) sign_in @user redirect_to root_url, :notice => "Password has been reset." else flash.now[:error] = "Something went wrong, please try again." render :edit end end Should I be checking for nil as well as blank? Are there any rails patterns or idiomatic ruby techniques for solving this? [Fwiw, I've got required: true on the html inputs, but want this handled server side too.]

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  • Mpd as pppoe server with authorisation by freeradius2

    - by Korjavin Ivan
    I install freeradius2, add to raddb/users: test Cleartext-Password := "test1" Service-Type = Framed-User, Framed-Protocol = PPP, Framed-IP-Address = 10.36.0.2, Framed-IP-Netmask = 255.255.255.0, start radiusd, and check auth: radtest test test1 127.0.0.1 1002 testing123 Sending Access-Request of id 199 to 127.0.0.1 port 1812 User-Name = "test" User-Password = "test1" NAS-IP-Address = 127.0.0.1 NAS-Port = 1002 Message-Authenticator = 0x00000000000000000000000000000000 rad_recv: Access-Accept packet from host 127.0.0.1 port 1812, id=199, length=44 Service-Type = Framed-User Framed-Protocol = PPP Framed-IP-Address = 10.36.0.2 Framed-IP-Netmask = 255.255.255.0 Works fine. Next step. Add to mpd.conf: radius: set auth disable internal set auth max-logins 1 CI set auth enable radius-auth set radius timeout 90 set radius retries 2 set radius server 127.0.0.1 testing123 1812 1813 set radius me 127.0.0.1 create link template L pppoe set link action bundle B set link max-children 1000 set link no multilink set link no shortseq set link no pap chap-md5 chap-msv1 chap-msv2 set link enable chap set pppoe acname Internet load radius create link template em1 L set pppoe iface em1 set link enable incoming And trying to connect, auth failed, here is mpd log: mpd: [em1-2] LCP: auth: peer wants nothing, I want CHAP mpd: [em1-2] CHAP: sending CHALLENGE #1 len: 21 mpd: [em1-2] LCP: LayerUp mpd: [em1-2] CHAP: rec'd RESPONSE #1 len: 58 mpd: [em1-2] Name: "test" mpd: [em1-2] AUTH: Trying RADIUS mpd: [em1-2] RADIUS: Authenticating user 'test' mpd: [em1-2] RADIUS: Rec'd RAD_ACCESS_REJECT for user 'test' mpd: [em1-2] AUTH: RADIUS returned: failed mpd: [em1-2] AUTH: ran out of backends mpd: [em1-2] CHAP: Auth return status: failed mpd: [em1-2] CHAP: Reply message: ^AE=691 R=1 mpd: [em1-2] CHAP: sending FAILURE #1 len: 14 mpd: [em1-2] LCP: authorization failed Then i start freeradius as radiusd -fX, and get this log: rad_recv: Access-Request packet from host 127.0.0.1 port 46400, id=223, length=282 NAS-Identifier = "rubin.svyaz-nt.ru" NAS-IP-Address = 127.0.0.1 Message-Authenticator = 0x14d36639bed8074ec2988118125367ea Acct-Session-Id = "815965-em1-2" NAS-Port = 2 NAS-Port-Type = Ethernet Service-Type = Framed-User Framed-Protocol = PPP Calling-Station-Id = "00e05290b3e3 / 00:e0:52:90:b3:e3 / em1" NAS-Port-Id = "em1" Vendor-12341-Attr-12 = 0x656d312d32 Tunnel-Medium-Type:0 = IEEE-802 Tunnel-Client-Endpoint:0 = "00:e0:52:90:b3:e3" User-Name = "test" MS-CHAP-Challenge = 0xbb1e68d5bbc30f228725a133877de83e MS-CHAP2-Response = 0x010088746ae65b68e435e9d045ad6f9569b60000000000000000b56991b4f20704cb6c68e5982eec5e98a7f4b470c109c1b9 # Executing section authorize from file /usr/local/etc/raddb/sites-enabled/default +- entering group authorize {...} ++[preprocess] returns ok ++[chap] returns noop [mschap] Found MS-CHAP attributes. Setting 'Auth-Type = mschap' ++[mschap] returns ok [eap] No EAP-Message, not doing EAP ++[eap] returns noop [files] users: Matched entry DEFAULT at line 172 ++[files] returns ok Found Auth-Type = MSCHAP # Executing group from file /usr/local/etc/raddb/sites-enabled/default +- entering group MS-CHAP {...} [mschap] No Cleartext-Password configured. Cannot create LM-Password. [mschap] No Cleartext-Password configured. Cannot create NT-Password. [mschap] Creating challenge hash with username: test [mschap] Client is using MS-CHAPv2 for test, we need NT-Password [mschap] FAILED: No NT/LM-Password. Cannot perform authentication. [mschap] FAILED: MS-CHAP2-Response is incorrect ++[mschap] returns reject Failed to authenticate the user. Login incorrect: [test] (from client localhost port 2 cli 00e05290b3e3 / 00:e0:52:90:b3:e3 / em1) Using Post-Auth-Type REJECT # Executing group from file /usr/local/etc/raddb/sites-enabled/default +- entering group REJECT {...} [attr_filter.access_reject] expand: %{User-Name} -> test attr_filter: Matched entry DEFAULT at line 11 ++[attr_filter.access_reject] returns updated Delaying reject of request 2 for 1 seconds Going to the next request Waking up in 0.9 seconds. Sending delayed reject for request 2 Sending Access-Reject of id 223 to 127.0.0.1 port 46400 MS-CHAP-Error = "\001E=691 R=1" Why i have error "[mschap] No Cleartext-Password configured. Cannot create LM-Password." ? I define cleartext-password in users. I check raddb/sites-enabled/default authorize { chap mschap eap { ok = return } files } looks ok for me. Whats wrong with mpd/chap/radius ?

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  • SSH error: Permission denied, please try again

    - by Kamal
    I am new to ubuntu. Hence please forgive me if the question is too simple. I have a ubuntu server setup using amazon ec2 instance. I need to connect my desktop (which is also a ubuntu machine) to the ubuntu server using SSH. I have installed open-ssh in ubuntu server. I need all systems of my network to connect the ubuntu server using SSH (no need to connect through pem or pub keys). Hence opened SSH port 22 for my static IP in security groups (AWS). My SSHD-CONFIG file is: # Package generated configuration file # See the sshd_config(5) manpage for details # What ports, IPs and protocols we listen for Port 22 # Use these options to restrict which interfaces/protocols sshd will bind to #ListenAddress :: #ListenAddress 0.0.0.0 Protocol 2 # HostKeys for protocol version 2 HostKey /etc/ssh/ssh_host_rsa_key HostKey /etc/ssh/ssh_host_dsa_key HostKey /etc/ssh/ssh_host_ecdsa_key #Privilege Separation is turned on for security UsePrivilegeSeparation yes # Lifetime and size of ephemeral version 1 server key KeyRegenerationInterval 3600 ServerKeyBits 768 # Logging SyslogFacility AUTH LogLevel INFO # Authentication: LoginGraceTime 120 PermitRootLogin yes StrictModes yes RSAAuthentication yes PubkeyAuthentication yes #AuthorizedKeysFile %h/.ssh/authorized_keys # Don't read the user's ~/.rhosts and ~/.shosts files IgnoreRhosts yes # For this to work you will also need host keys in /etc/ssh_known_hosts RhostsRSAAuthentication no # similar for protocol version 2 HostbasedAuthentication no # Uncomment if you don't trust ~/.ssh/known_hosts for RhostsRSAAuthentication #IgnoreUserKnownHosts yes # To enable empty passwords, change to yes (NOT RECOMMENDED) PermitEmptyPasswords no # Change to yes to enable challenge-response passwords (beware issues with # some PAM modules and threads) ChallengeResponseAuthentication no # Change to no to disable tunnelled clear text passwords #PasswordAuthentication yes # Kerberos options #KerberosAuthentication no #KerberosGetAFSToken no #KerberosOrLocalPasswd yes #KerberosTicketCleanup yes # GSSAPI options #GSSAPIAuthentication no #GSSAPICleanupCredentials yes X11Forwarding yes X11DisplayOffset 10 PrintMotd no PrintLastLog yes TCPKeepAlive yes #UseLogin no #MaxStartups 10:30:60 #Banner /etc/issue.net # Allow client to pass locale environment variables AcceptEnv LANG LC_* Subsystem sftp /usr/lib/openssh/sftp-server # Set this to 'yes' to enable PAM authentication, account processing, # and session processing. If this is enabled, PAM authentication will # be allowed through the ChallengeResponseAuthentication and # PasswordAuthentication. Depending on your PAM configuration, # PAM authentication via ChallengeResponseAuthentication may bypass # the setting of "PermitRootLogin without-password". # If you just want the PAM account and session checks to run without # PAM authentication, then enable this but set PasswordAuthentication # and ChallengeResponseAuthentication to 'no'. UsePAM yes Through webmin (Command shell), I have created a new user named 'senthil' and added this new user to 'sudo' group. sudo adduser -y senthil sudo adduser senthil sudo I tried to login using this new user 'senthil' in 'webmin'. I was able to login successfully. When I tried to connect ubuntu server from my terminal through SSH, ssh senthil@SERVER_IP It asked me to enter password. After the password entry, it displayed: Permission denied, please try again. On some research I realized that, I need to monitor my server's auth log for this. I got the following error in my auth log (/var/log/auth.log) Jul 2 09:38:07 ip-192-xx-xx-xxx sshd[3037]: pam_unix(sshd:auth): authentication failure; logname= uid=0 euid=0 tty=ssh ruser= rhost=MY_CLIENT_IP user=senthil Jul 2 09:38:09 ip-192-xx-xx-xxx sshd[3037]: Failed password for senthil from MY_CLIENT_IP port 39116 ssh2 When I tried to debug using: ssh -v senthil@SERVER_IP OpenSSH_5.9p1 Debian-5ubuntu1, OpenSSL 1.0.1 14 Mar 2012 debug1: Reading configuration data /etc/ssh/ssh_config debug1: /etc/ssh/ssh_config line 19: Applying options for * debug1: Connecting to SERVER_IP [SERVER_IP] port 22. debug1: Connection established. debug1: identity file {MY-WORKSPACE}/.ssh/id_rsa type 1 debug1: Checking blacklist file /usr/share/ssh/blacklist.RSA-2048 debug1: Checking blacklist file /etc/ssh/blacklist.RSA-2048 debug1: identity file {MY-WORKSPACE}/.ssh/id_rsa-cert type -1 debug1: identity file {MY-WORKSPACE}/.ssh/id_dsa type -1 debug1: identity file {MY-WORKSPACE}/.ssh/id_dsa-cert type -1 debug1: identity file {MY-WORKSPACE}/.ssh/id_ecdsa type -1 debug1: identity file {MY-WORKSPACE}/.ssh/id_ecdsa-cert type -1 debug1: Remote protocol version 2.0, remote software version OpenSSH_5.8p1 Debian-7ubuntu1 debug1: match: OpenSSH_5.8p1 Debian-7ubuntu1 pat OpenSSH* debug1: Enabling compatibility mode for protocol 2.0 debug1: Local version string SSH-2.0-OpenSSH_5.9p1 Debian-5ubuntu1 debug1: SSH2_MSG_KEXINIT sent debug1: SSH2_MSG_KEXINIT received debug1: kex: server->client aes128-ctr hmac-md5 none debug1: kex: client->server aes128-ctr hmac-md5 none debug1: sending SSH2_MSG_KEX_ECDH_INIT debug1: expecting SSH2_MSG_KEX_ECDH_REPLY debug1: Server host key: ECDSA {SERVER_HOST_KEY} debug1: Host 'SERVER_IP' is known and matches the ECDSA host key. debug1: Found key in {MY-WORKSPACE}/.ssh/known_hosts:1 debug1: ssh_ecdsa_verify: signature correct debug1: SSH2_MSG_NEWKEYS sent debug1: expecting SSH2_MSG_NEWKEYS debug1: SSH2_MSG_NEWKEYS received debug1: Roaming not allowed by server debug1: SSH2_MSG_SERVICE_REQUEST sent debug1: SSH2_MSG_SERVICE_ACCEPT received debug1: Authentications that can continue: password debug1: Next authentication method: password senthil@SERVER_IP's password: debug1: Authentications that can continue: password Permission denied, please try again. senthil@SERVER_IP's password: For password, I have entered the same value which I normally use for 'ubuntu' user. Can anyone please guide me where the issue is and suggest some solution for this issue?

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  • Creating a secure SQL server login - CHECK_EXPIRATION & CHECK_POLICY

    - by cabhilash
    In SQL Server you can create users using T-SQL or using the options provided by SQL Server Management Studio.   CREATE LOGIN sql_user WITH PASSWORD ='sql_user_password' MUST_CHANGE, DEFAULT_DATABASE = defDB, CHECK_EXPIRATION = ON, CHECK_POLICY = ONAs mentioned in the previous article (http://weblogs.asp.net/cabhilash/archive/2010/04/07/login-failed-for-user-sa-because-the-account-is-currently-locked-out-the-system-administrator-can-unlock-it.aspx) when CHECK_POLICY = ON user account follows the password rules provided in the system on which the SQL server is installed. When MUST_CHANGE keyword is used user is forced to change the password when he/she tries to login for the first time. CHECK_EXPIRATION and CHECK_POLICY are only enforced on Windows Server 2003 and later. If you want to turn off the password expiration enforcement or security policy enforcement, you can do by using the following statements. (But these wont work if you have created your login with MUST_CHANGE and user didn't change the default password) ALTER LOGIN sql_login WITH CHECK_EXPIRATION = OFF go ALTER LOGIN sql_login WITH CHECK_POLICY = OFF

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  • Authentication failure!

    - by veera
    At the time of installation i gave login password and that was the login keyring password and authentication password.. then once in user accounts-login options in dat for password options i set as none and then i locked.. after that the passwd which i gave at the time of installation remained as login keyring passwd but wen i entered that passwd for authentication while installing some packages it's showing authentication failure.pls try again.. so i couldnt download any packages or updates.. is there any possibilities to change/reset the authentication password.. pls help me..

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  • Would you consider using training/mentoring from LearnersParadise.com?

    - by HK1
    My initial question deserves some explanation. I signed up for an account at learnersparadise.com. After signing up I couldn't login so I opted to use their "send password" feature. Upon receiving my password in my email I confirmed two things A) They trimmed off 2 of the last digits of my 10-digit password without informing me and saved it that way in their database B) my password is not saved in their database using a one-way hash since they were able to email me my password. I'm quite certain that both of these are perfectly awful programming practices. I suspect that the mentors/trainers at learnersparadise are not necessarily affiliated with the website and it's design since they are basically people like you and me (hopefully more skill than me) who have signed up to become mentors. However, I'm still uncertain about signing up for training/mentoring at a site that uses such poor programming practices themselves? Would you let learnersparadise poor programming practices affect your opinion of their trainers/mentors?

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  • tomcat6 manager

    - by Bary W Pollack
    I've just installed Ubuntu 10.04 LTS Server with LAMP support. Tomcat6 seems to run ok. But, I am unable to get into the manager-webapp... I've updated the tomcat-users.xml file: <?xml version='1.0' encoding='utf-8'?> <tomcat-users> <role rolename="tomcat"/> <role rolename="role1"/> <role rolename="manager"/> <role rolename="admin"/> <user username="tomcat" password="tomcat" roles="tomcat,manager,admin"/> <user username="both" password="tomcat" roles="tomcat,role1"/> <user username="role1" password="tomcat" roles="role1"/> <user username="admin" password="admin" roles="manager,admin"/> </tomcat-users> But, no matter what I try, it keeps rejecting my username/password combo. What might I be missing?

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  • Excessive denied requests for port 58322 in syslog

    - by Nathan C.
    My iptables is setup to block all unneeded ports as it should but I'm checking my syslog due to these random but all-to-frequent apache2 crashes and I noticed a lot of requests such as this. In all the archived syslogs that I have these are present from different IP addresses. There is a similar question with an accepted here: What service uses UDP port 60059? Jun 4 06:49:27 HOSTNAME kernel: iptables denied: IN=eth0 OUT= MAC=fe:fd:ad:ff:dd:95:c8:4c:75:f5:d6:3f:08:00 SRC=218.7.74.50 DST=MY.SERVER.IP.HERE LEN=129 TOS=0x00 PREC=0x00 TTL=115 ID=27636 PROTO=UDP SPT=9520 DPT=58322 LEN=109 Jun 4 06:49:31 HOSTNAME kernel: iptables denied: IN=eth0 OUT= MAC=fe:fd:ad:ff:dd:95:c8:4c:75:f5:d6:3f:08:00 SRC=95.160.226.177 DST=MY.SERVER.IP.HERE LEN=131 TOS=0x00 PREC=0x00 TTL=116 ID=31468 PROTO=UDP SPT=47642 DPT=58322 LEN=111 Jun 4 06:49:54 HOSTNAME kernel: iptables denied: IN=eth0 OUT= MAC=fe:fd:ad:ff:dd:95:c8:4c:75:f5:d6:3f:08:00 SRC=78.137.36.10 DST=MY.SERVER.IP.HERE LEN=131 TOS=0x00 PREC=0x00 TTL=118 ID=21872 PROTO=UDP SPT=57872 DPT=58322 LEN=111 Jun 4 06:50:14 HOSTNAME kernel: iptables denied: IN=eth0 OUT= MAC=fe:fd:ad:ff:dd:95:c8:4c:75:f5:d6:3f:08:00 SRC=111.253.217.11 DST=MY.SERVER.IP.HERE LEN=131 TOS=0x00 PREC=0x00 TTL=116 ID=28882 PROTO=UDP SPT=51826 DPT=58322 LEN=111 Jun 4 06:51:02 HOSTNAME kernel: iptables denied: IN=eth0 OUT= MAC=fe:fd:ad:ff:dd:95:c8:4c:75:f5:d6:3f:08:00 SRC=189.45.114.173 DST=MY.SERVER.IP.HERE LEN=131 TOS=0x16 PREC=0x00 TTL=113 ID=19985 PROTO=UDP SPT=41087 DPT=58322 LEN=111 Jun 4 06:51:09 HOSTNAME kernel: iptables denied: IN=eth0 OUT= MAC=fe:fd:ad:ff:dd:95:c8:4c:75:f5:d6:3f:08:00 SRC=87.89.202.28 DST=MY.SERVER.IP.HERE LEN=131 TOS=0x00 PREC=0x00 TTL=116 ID=7874 PROTO=UDP SPT=17524 DPT=58322 LEN=111 Jun 4 06:51:20 HOSTNAME kernel: iptables denied: IN=eth0 OUT= MAC=fe:fd:ad:ff:dd:95:c8:4c:75:f5:d6:3f:08:00 SRC=24.44.124.35 DST=MY.SERVER.IP.HERE LEN=131 TOS=0x00 PREC=0x00 TTL=118 ID=12978 PROTO=UDP SPT=45596 DPT=58322 LEN=111 Jun 4 06:51:22 HOSTNAME kernel: iptables denied: IN=eth0 OUT= MAC=fe:fd:ad:ff:dd:95:c8:4c:75:f5:d6:3f:08:00 SRC=81.174.48.236 DST=MY.SERVER.IP.HERE LEN=93 TOS=0x00 PREC=0x00 TTL=48 ID=0 DF PROTO=UDP SPT=21352 DPT=58322 LEN=73 Jun 4 06:51:23 HOSTNAME kernel: iptables denied: IN=eth0 OUT= MAC=fe:fd:ad:ff:dd:95:c8:4c:75:f5:d6:3f:08:00 SRC=124.107.61.84 DST=MY.SERVER.IP.HERE LEN=131 TOS=0x00 PREC=0x00 TTL=114 ID=13038 PROTO=UDP SPT=14357 DPT=58322 LEN=111 Jun 4 06:51:30 HOSTNAME kernel: iptables denied: IN=eth0 OUT= MAC=fe:fd:ad:ff:dd:95:c8:4c:75:f5:d6:3f:08:00 SRC=88.8.23.200 DST=MY.SERVER.IP.HERE LEN=123 TOS=0x00 PREC=0x00 TTL=117 ID=21062 PROTO=UDP SPT=4291 DPT=58322 LEN=103 Jun 4 06:51:54 HOSTNAME kernel: iptables denied: IN=eth0 OUT= MAC=fe:fd:ad:ff:dd:95:c8:4c:75:f5:d6:3f:08:00 SRC=80.202.244.234 DST=MY.SERVER.IP.HERE LEN=129 TOS=0x00 PREC=0x00 TTL=114 ID=339 PROTO=UDP SPT=14020 DPT=58322 LEN=109 I'm not overly experienced with server configuration and debugging, so I only just installed logcheck after reading that previous question. I guess my question is what steps should I take after reading this log info to 1) further protect myself, 2) understand if this could be causing any other problems with my VPS, and 3) use this data to help others?

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  • MS Word Macro in visual Basic

    - by Mac
    I have a Visual Basic system that in places runs word macros. I now need to have a MS Word Macro that I can search for a character and then extend the search to another character and extract the details into a vb variable from the first to the last character. Thereafter I need to search for the next occurrence of the first character and repeat the exercise. When all have been processed the last search must inform me that there are no more. During the searches I need to identify the section numbers where I find the searches and be able to get them in VB variable. Any assistance will be greatly appreciated. Regards Mac

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  • How to execute? [closed]

    - by Viswa
    Possible Duplicate: how to read the password from variable? I did the below code in my python script,but its not work. #! /usr/bin/python import os address = "rsync -avrz [email protected]:/opt/script/python/data/ /opt/script/python/data/" passwd ="my server password" os.system('%(address)s "echo %(passwd)s"' %locals()) it throws below error. If arg is a remote file/dir, prefix it with a colon (:). rsync error: syntax or usage error (code 1) at main.c(1236) [Receiver=3.0.7] If i run os.system('%(address)s' %locals()) means it work without any error but it ask password. I need that password should be read from my passwd variable. How to write python script to read server password from my variable.

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  • Problem while running the j2me application

    - by Paru
    I am not able to view any content in the emulator while running the application. The Build is not failed and i am able run the application successfully. While i am closing the emulator i am getting an error. i can provide both code and log here. import javax.microedition.lcdui.; import javax.microedition.midlet.; import java.io.; import java.lang.; import javax.microedition.io.; import javax.microedition.rms.; public class Login extends MIDlet implements CommandListener { TextField ItemName=null; TextField ItemNo=null; TextField UserName=null; TextField Password=null; Form authForm,mainscreen; TextBox t = null; StringBuffer b = new StringBuffer(); private Display myDisplay = null; private Command okCommand = new Command("Login", Command.OK, 1); private Command exitCommand = new Command("Exit", Command.EXIT, 2); private Command sendCommand = new Command("Send", Command.OK, 1); private Command backCommand = new Command("Back", Command.BACK, 2); private Alert alert = null; public Login() { ItemName=new TextField("Item Name","",10,TextField.ANY); ItemNo=new TextField("Item No","",10,TextField.ANY); myDisplay = Display.getDisplay(this); UserName=new TextField("Your Name","",10,TextField.ANY); Password=new TextField("Password","",10,TextField.PASSWORD); authForm=new Form("Identification"); mainscreen=new Form("Logging IN"); mainscreen.addCommand(sendCommand); mainscreen.addCommand(backCommand); authForm.append(UserName); authForm.append(Password); authForm.addCommand(okCommand); authForm.addCommand(exitCommand); authForm.setCommandListener(this); myDisplay.setCurrent(authForm); } public void startApp() throws MIDletStateChangeException { } public void pauseApp() { } protected void destroyApp(boolean unconditional) throws MIDletStateChangeException { } public void commandAction(Command c, Displayable d) { if ((c == okCommand) && (d == authForm)) { if (UserName.getString().equals("") || Password.getString().equals("")){ alert = new Alert("Error", "You should enter Username and Password", null, AlertType.ERROR); alert.setTimeout(Alert.FOREVER); myDisplay.setCurrent(alert); } else{ //myDisplay.setCurrent(mainscreen); login(UserName.getString(),Password.getString()); } } if ((c == backCommand) && (d == mainscreen)) { myDisplay.setCurrent(authForm); } if ((c == exitCommand) && (d == authForm)) { notifyDestroyed(); } if ((c == sendCommand) && (d == mainscreen)) { if(ItemName.getString().equals("") || ItemNo.getString().equals("")){ } else{ sendItem(ItemName.getString(),ItemNo.getString()); } } } public void login(String UserName,String PassWord) { HttpConnection connection=null; DataInputStream in=null; String url="http://olario.net/submitpost/submitpost/login.php"; OutputStream out=null; try { connection=(HttpConnection)Connector.open(url); connection.setRequestMethod(HttpConnection.POST); connection.setRequestProperty("IF-Modified-Since", "2 Oct 2002 15:10:15 GMT"); connection.setRequestProperty("User-Agent","Profile/MIDP-1.0 Configuration/CLDC-1.0"); connection.setRequestProperty("Content-Language", "en-CA"); connection.setRequestProperty("Content-Length",""+ (UserName.length()+PassWord.length())); connection.setRequestProperty("username",UserName); connection.setRequestProperty("password",PassWord); out = connection.openDataOutputStream(); out.flush(); in = connection.openDataInputStream(); int ch; while((ch = in.read()) != -1) { b.append((char) ch); //System.out.println((char)ch); } //t = new TextBox("Reply",b.toString(),1024,0); //mainscreen.append(b.toString()); String auth=b.toString(); if(in!=null) in.close(); if(out!=null) out.close(); if(connection!=null) connection.close(); if(auth.equals("ok")){ mainscreen.setCommandListener(this); myDisplay.setCurrent(mainscreen); } } catch(IOException x){ } } public void sendItem(String itemname,String itemno){ HttpConnection connection=null; DataInputStream in=null; String url="http://www.olario.net/submitpost/submitpost/submitPost.php"; OutputStream out=null; try { connection=(HttpConnection)Connector.open(url); connection.setRequestMethod(HttpConnection.POST); connection.setRequestProperty("IF-Modified-Since", "2 Oct 2002 15:10:15 GMT"); connection.setRequestProperty("User-Agent","Profile/MIDP-1.0 Configuration/CLDC-1.0"); connection.setRequestProperty("Content-Language", "en-CA"); connection.setRequestProperty("Content-Length",""+ (itemname.length()+itemno.length())); connection.setRequestProperty("itemCode",itemname); connection.setRequestProperty("qty",itemno); out = connection.openDataOutputStream(); out.flush(); in = connection.openDataInputStream(); int ch; while((ch = in.read()) != -1) { b.append((char) ch); //System.out.println((char)ch); } //t = new TextBox("Reply",b.toString(),1024,0); //mainscreen.append(b.toString()); String send=b.toString(); if(in!=null) in.close(); if(out!=null) out.close(); if(connection!=null) connection.close(); if(send.equals("added")){ alert = new Alert("Error", "Send Successfully", null, AlertType.INFO); alert.setTimeout(Alert.FOREVER); myDisplay.setCurrent(alert); } } catch(IOException x){ } } } and the log is pre-init: pre-load-properties: exists.config.active: exists.netbeans.user: exists.user.properties.file: load-properties: exists.platform.active: exists.platform.configuration: exists.platform.profile: basic-init: cldc-pre-init: cldc-init: cdc-init: ricoh-pre-init: ricoh-init: semc-pre-init: semc-init: savaje-pre-init: savaje-init: sjmc-pre-init: sjmc-init: ojec-pre-init: ojec-init: cdc-hi-pre-init: cdc-hi-init: nokiaS80-pre-init: nokiaS80-init: nsicom-pre-init: nsicom-init: post-init: init: conditional-clean-init: conditional-clean: deps-jar: pre-preprocess: do-preprocess: Pre-processing 0 file(s) into /home/sreekumar/NetBeansProjects/Login/build/preprocessed directory. post-preprocess: preprocess: pre-compile: extract-libs: do-compile: post-compile: compile: pre-obfuscate: proguard-init: skip-obfuscation: proguard: post-obfuscate: obfuscate: lwuit-build: pre-preverify: do-preverify: post-preverify: preverify: pre-jar: set-password-init: set-keystore-password: set-alias-password: set-password: create-jad: add-configuration: add-profile: do-extra-libs: nokiaS80-prepare-j9: nokiaS80-prepare-manifest: nokiaS80-prepare-manifest-no-icon: nokiaS80-create-manifest: jad-jsr211-properties.check: jad-jsr211-properties: semc-build-j9: do-jar: nsicom-create-manifest: do-jar-no-manifest: update-jad: Updating application descriptor: /home/sreekumar/NetBeansProjects/Login/dist/Login.jad Generated "/home/sreekumar/NetBeansProjects/Login/dist/Login.jar" is 3501 bytes. sign-jar: ricoh-init-dalp: ricoh-add-app-icon: ricoh-build-dalp-with-icon: ricoh-build-dalp-without-icon: ricoh-build-dalp: savaje-prepare-icon: savaje-build-jnlp: post-jar: jar: pre-run: netmon.check: open-netmon: cldc-run: Copying 1 file to /home/sreekumar/NetBeansProjects/Login/dist/nbrun4244989945642509378 Copying 1 file to /home/sreekumar/NetBeansProjects/Login/dist/nbrun4244989945642509378 Jad URL for OTA execution: http://localhost:8082/servlet/org.netbeans.modules.mobility.project.jam.JAMServlet//home/sreekumar/NetBeansProjects/Login/dist//Login.jad Starting emulator in execution mode Running with storage root /home/sreekumar/j2mewtk/2.5.2/appdb/temp.DefaultColorPhone1 /home/sreekumar/NetBeansProjects/Login/nbproject/build-impl.xml:915: Execution failed with error code 143. BUILD FAILED (total time: 35 seconds)

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  • How to install PyQt on Mac OS X 10.6.

    - by Jebagnanadas
    Hello all, I'm quite new to Mac OS X. when i tried to install PyQt on Mac Os X after installing python 3.1, Qt 4.6.2 and SIP 4.10.1 i encounter the following error when i execute $python3 configure.py command. Determining the layout of your Qt installation... This is the GPL version of PyQt 4.7 (licensed under the GNU General Public License) for Python 3.1 on darwin. Type '2' to view the GPL v2 license. Type '3' to view the GPL v3 license. Type 'yes' to accept the terms of the license. Type 'no' to decline the terms of the license. Do you accept the terms of the license? yes Checking to see if the QtGui module should be built... Checking to see if the QtHelp module should be built... Checking to see if the QtMultimedia module should be built... Checking to see if the QtNetwork module should be built... Checking to see if the QtOpenGL module should be built... Checking to see if the QtScript module should be built... Checking to see if the QtScriptTools module should be built... Checking to see if the QtSql module should be built... Checking to see if the QtSvg module should be built... Checking to see if the QtTest module should be built... Checking to see if the QtWebKit module should be built... Checking to see if the QtXml module should be built... Checking to see if the QtXmlPatterns module should be built... Checking to see if the phonon module should be built... Checking to see if the QtAssistant module should be built... Checking to see if the QtDesigner module should be built... Qt v4.6.2 free edition is being used. Qt is built as a framework. SIP 4.10.1 is being used. The Qt header files are in /usr/include. The shared Qt libraries are in /Library/Frameworks. The Qt binaries are in /Developer/Tools/Qt. The Qt mkspecs directory is in /usr/local/Qt4.6. These PyQt modules will be built: QtCore. The PyQt Python package will be installed in /Library/Frameworks/Python.framework/Versions/3.1/lib/python3.1/site-packages. PyQt is being built with generated docstrings. PyQt is being built with 'protected' redefined as 'public'. The Designer plugin will be installed in /Developer/Applications/Qt/plugins/designer. The PyQt .sip files will be installed in /Library/Frameworks/Python.framework/Versions/3.1/share/sip/PyQt4. pyuic4, pyrcc4 and pylupdate4 will be installed in /Library/Frameworks/Python.framework/Versions/3.1/bin. Generating the C++ source for the QtCore module... sip: Usage: sip [-h] [-V] [-a file] [-b file] [-c dir] [-d file] [-e] [-g] [-I dir] [-j #] [-k] [-m file] [-o] [-p module] [-r] [-s suffix] [-t tag] [-w] [-x feature] [-z file] [file] Error: Unable to create the C++ code. Anybody here installed PyQt on Mac OS X 10.6.2 successfully.. Any help would be much appreciated.. Thanks in advance..

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  • Using AES encryption in .NET - CryptographicException saying the padding is invalid and cannot be removed

    - by Jake Petroules
    I wrote some AES encryption code in C# and I am having trouble getting it to encrypt and decrypt properly. If I enter "test" as the passphrase and "This data must be kept secret from everyone!" I receive the following exception: System.Security.Cryptography.CryptographicException: Padding is invalid and cannot be removed. at System.Security.Cryptography.RijndaelManagedTransform.DecryptData(Byte[] inputBuffer, Int32 inputOffset, Int32 inputCount, Byte[]& outputBuffer, Int32 outputOffset, PaddingMode paddingMode, Boolean fLast) at System.Security.Cryptography.RijndaelManagedTransform.TransformFinalBlock(Byte[] inputBuffer, Int32 inputOffset, Int32 inputCount) at System.Security.Cryptography.CryptoStream.FlushFinalBlock() at System.Security.Cryptography.CryptoStream.Dispose(Boolean disposing) at System.IO.Stream.Close() at System.IO.Stream.Dispose() ... And if I enter something less than 16 characters I get no output. I believe I need some special handling in the encryption since AES is a block cipher, but I'm not sure exactly what that is, and I wasn't able to find any examples on the web showing how. Here is my code: using System; using System.IO; using System.Security.Cryptography; using System.Text; public static class DatabaseCrypto { public static EncryptedData Encrypt(string password, string data) { return DatabaseCrypto.Transform(true, password, data, null, null) as EncryptedData; } public static string Decrypt(string password, EncryptedData data) { return DatabaseCrypto.Transform(false, password, data.DataString, data.SaltString, data.MACString) as string; } private static object Transform(bool encrypt, string password, string data, string saltString, string macString) { using (AesManaged aes = new AesManaged()) { aes.Mode = CipherMode.CBC; aes.Padding = PaddingMode.PKCS7; int key_len = aes.KeySize / 8; int iv_len = aes.BlockSize / 8; const int salt_size = 8; const int iterations = 8192; byte[] salt = encrypt ? new Rfc2898DeriveBytes(string.Empty, salt_size).Salt : Convert.FromBase64String(saltString); byte[] bc_key = new Rfc2898DeriveBytes("BLK" + password, salt, iterations).GetBytes(key_len); byte[] iv = new Rfc2898DeriveBytes("IV" + password, salt, iterations).GetBytes(iv_len); byte[] mac_key = new Rfc2898DeriveBytes("MAC" + password, salt, iterations).GetBytes(16); aes.Key = bc_key; aes.IV = iv; byte[] rawData = encrypt ? Encoding.UTF8.GetBytes(data) : Convert.FromBase64String(data); using (ICryptoTransform transform = encrypt ? aes.CreateEncryptor() : aes.CreateDecryptor()) using (MemoryStream memoryStream = encrypt ? new MemoryStream() : new MemoryStream(rawData)) using (CryptoStream cryptoStream = new CryptoStream(memoryStream, transform, encrypt ? CryptoStreamMode.Write : CryptoStreamMode.Read)) { if (encrypt) { cryptoStream.Write(rawData, 0, rawData.Length); return new EncryptedData(salt, mac_key, memoryStream.ToArray()); } else { byte[] originalData = new byte[rawData.Length]; int count = cryptoStream.Read(originalData, 0, originalData.Length); return Encoding.UTF8.GetString(originalData, 0, count); } } } } } public class EncryptedData { public EncryptedData() { } public EncryptedData(byte[] salt, byte[] mac, byte[] data) { this.Salt = salt; this.MAC = mac; this.Data = data; } public EncryptedData(string salt, string mac, string data) { this.SaltString = salt; this.MACString = mac; this.DataString = data; } public byte[] Salt { get; set; } public string SaltString { get { return Convert.ToBase64String(this.Salt); } set { this.Salt = Convert.FromBase64String(value); } } public byte[] MAC { get; set; } public string MACString { get { return Convert.ToBase64String(this.MAC); } set { this.MAC = Convert.FromBase64String(value); } } public byte[] Data { get; set; } public string DataString { get { return Convert.ToBase64String(this.Data); } set { this.Data = Convert.FromBase64String(value); } } } static void ReadTest() { Console.WriteLine("Enter password: "); string password = Console.ReadLine(); using (StreamReader reader = new StreamReader("aes.cs.txt")) { EncryptedData enc = new EncryptedData(); enc.SaltString = reader.ReadLine(); enc.MACString = reader.ReadLine(); enc.DataString = reader.ReadLine(); Console.WriteLine("The decrypted data was: " + DatabaseCrypto.Decrypt(password, enc)); } } static void WriteTest() { Console.WriteLine("Enter data: "); string data = Console.ReadLine(); Console.WriteLine("Enter password: "); string password = Console.ReadLine(); EncryptedData enc = DatabaseCrypto.Encrypt(password, data); using (StreamWriter stream = new StreamWriter("aes.cs.txt")) { stream.WriteLine(enc.SaltString); stream.WriteLine(enc.MACString); stream.WriteLine(enc.DataString); Console.WriteLine("The encrypted data was: " + enc.DataString); } }

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  • Why am I getting 403 Forbidden after enabling HTTPS for Apache on Mac OS X?

    - by Daryl Spitzer
    I enabled HTTPS on the Apache server built-in to Mac OS X 10.6 (on my MacBook Pro) by uncommenting: Include /private/etc/apache2/extra/httpd-ssl.conf ...in /etc/apache2/httpd.conf and modifying /etc/apache2/extra/httpd-ssl.conf to include: DocumentRoot "/Users/dspitzer/foo/bar" ServerName dot.com:443 ServerAdmin [email protected] ... SSLCertificateFile "/private/etc/apache2/siab_cert.pem" SSLCertificateKeyFile "/private/etc/apache2/siab_key.pem" Then I restart apache (with sudo apachectl restart) and go to https://localhost/ in Safari, where I get: <!DOCTYPE HTML PUBLIC "-//IETF//DTD HTML 2.0//EN"> <html><head> <title>403 Forbidden</title> </head><body> <h1>Forbidden</h1> <p>You don't have permission to access / on this server.</p> </body></html> I've tried changing 443 in /etc/apache2/extra/httpd-ssl.conf to 8443 and going to https://localhost:8443/ and I get the same error. I read http://serverfault.com/questions/88037/why-am-i-getting-this-403-forbidden-error and confirmed that execute permission is given for all parent directories of the vhost dir: /Users/dspitzer/foo/bar. Is there a log file somewhere that might give me a clue?

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  • How to permanently "renice" a process on Mac OS X (or iOS, etc)?

    - by mralexgray
    I use a nice (free) process manager called ATMonitor for Mac OS X that has a lot of cool hidden features... one of which is being able to click on a running process.. and set the "renice" from +20 (less priority) to -20 (highest priority). The best part.... it sticks between restarts... SO you want XYZ to get full attention all the time.. you set it once and it's done... I want to do the same thing (renice a process) on an iPad running a particular daemon.. and I don't know how to set a renice permanently. I can do it once, and it works fine... But the setting is lost on a reboot. I read somewhere.. Now, as for permanently resetting the priority of a process, this can't be done directly. You can fake it, however, with a shell script that starts the app and then immediately renice's it. Give that script a ".command" extension and it will be double-clickable in the GUI. Not very elegant, but it gets the job done. But as it says.. not very elegant, and I dont think this is how ATMonitor does it.... I found this thread.... http://superuser.com and they gave a way to do it as a launch argument, but no apparent way to save it as a persistent value... for instance - if the program wasn't going to be started by launchd... How do I set a permanent renice level, per executable binary, independent of it's PID, when, how or why it was launched?

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  • Rails requires Rubygems, 1.3.2; I have 1.3.6

    - by JZ
    What is going on here? I'm getting this odd message: Rails requires RubyGems >= 1.3.2. Please install RubyGems and try again: http://rubygems.rubyforge.org justin-zollarss-mac-pro:barcoden2 justinz$ whereis gem /usr/bin/gem justin-zollarss-mac-pro:barcoden2 justinz$ whereis ruby /usr/bin/ruby justin-zollarss-mac-pro:barcoden2 justinz$ whereis rails /usr/bin/rails justin-zollarss-mac-pro:barcoden2 justinz$ ruby -v ruby 1.8.7 (2009-06-12 patchlevel 174) [i686-darwin10] justin-zollarss-mac-pro:barcoden2 justinz$ rails -v Rails 3.0.0.beta justin-zollarss-mac-pro:barcoden2 justinz$ gem -v 1.3.6 justin-zollarss-mac-pro:barcoden2 justinz$ ruby script/server Rails requires RubyGems >= 1.3.2. Please install RubyGems and try again: http://rubygems.rubyforge.org

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  • How to use the md5 hash?

    - by Ken
    Okay, so I'm learning php, html, and mysql to learn website development (for fun). One thing I still don't get is how to use md5 of sha1 hashes. I know how to hash the plain text, but say I want to make a login page. Since the password is hashed and can't be reversed, how would mysql know that the user-inserted password matches the hashed password in the database? Here is what I mean: $password = md5($_POST['password']); $query = ("INSERT INTO `users`.`data` (`password`) VALUES ('$password')"); I know that this snippet of script hashes the password, but how would I use this piece of code and make a login page? Any working examples would be great.

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  • i am facing some problem while passing parameter to crystal report? it is asking for the password of

    - by Gaurav Sharma
    protected void Page_Load(object sender, EventArgs e) { ConnectionInfo myConnectionInfo = new ConnectionInfo(); myConnectionInfo.UserID = "sa"; myConnectionInfo.Password = "********"; setDBLOGONforREPORT(myConnectionInfo); //When i don't write this code it does not ask for the passowrd //but doesn't take Parameter as value int recpt_no = Convert.ToInt32(Request.QueryString["recpt_no"]); ReportDocument report1 = new ReportDocument(); //report1.SetDatabaseLogon("sa", "********"); report1.Load(Server.MapPath("purchase.rpt")); report1.FileName = Server.MapPath("purchase.rpt"); report1.SetParameterValue("recpt_no", recpt_no); CrystalReportViewer1.ReportSource = report1; } private void setDBLOGONforREPORT(ConnectionInfo myconnectioninfo) { TableLogOnInfos mytableloginfos = new TableLogOnInfos(); mytableloginfos = CrystalReportViewer1.LogOnInfo; foreach (TableLogOnInfo myTableLogOnInfo in mytableloginfos) { myTableLogOnInfo.ConnectionInfo = myconnectioninfo; } } kindly Help me as soon as possible respt_no is passed as querysting Gaurav Sharma

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  • How can I most efficiently batch resize images on a Mac?

    - by Nick Douglas
    I've been batch-resizing images through Preview (OS X) through the menu bar, but I want a simpler workflow, since I do this a dozen times a day. What I want: 1. Select a group of image files in finder 2. Hit a button or two (menu item or keyboard shortcut) to do the following: a. Scale all the pictures to 600 pixels wide b. Save as JPG files at 75% quality What I also want: - All of the above, plus step a(1): Crop images to 200 pixel height I can do all that manually, to a batch of files, through Preview. I can do it one at a time with some keyboard shortcuts in Photoshop or Pixelmator. Automator (using Preview) can scale to 600 pixels on the longest dimension, but it doesn't let me specify width. (It can scale specifically to width before cropping height.) It can change to JPG, but it can't specify image quality. And I can assign a keyboard shortcut to the whole process. Is that my best option on a Mac? Can I accomplish this more efficiently through another app like Quicksilver?

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  • How do I get a Mac to request a new IP address from another DHCP server running in parallel while Ne

    - by huyqt
    Hello, I have an interesting situation. I'm trying to us a Linux based machine to allow Mac's to Netboot (similiar to PXE boot) by running a DHCP service in parallel with the "global" DHCP server. The local DHCP server hands out IPs in a private subnet, e.g., 10.168.0.10-10.168.254-254, while the "global" DHCP server hands out IPs from the IP range 10.0.0.1 - 10.0.1.254. The local DHCP range is only supposed to be used in Preboot Execution Environment and Netboot. The local DHCP server is something I have control over, but I do not have access to the global DHCP server. I have a filter to only allow members with the vendor strings "AAPLBSDPC/i386" and "PXEClient". PXE works fine, but Netboot has a quirk. The Apple systems that haven't been connected to the network yet can Netboot fine. But once it grabs a "real" IP address from the global DHCP server, it will "save" it and request it the next time we want it to netboot (which the local dhcp server won't give it). This is what I want: Mar 30 10:52:28 dev01 dhcpd: DHCPDISCOVER from 34:15:xx:xx:xx:xx via eth1 Mar 30 10:52:29 dev01 dhcpd: DHCPOFFER on 10.168.222.46 to 34:15:xx:xx:xx:xx via eth1 Mar 30 10:52:31 dev01 dhcpd: DHCPREQUEST for 10.168.222.46 (10.168.0.1) from 34:15:xx:xx:xx:xx via eth1 Mar 30 10:52:31 dev01 dhcpd: DHCPACK on 10.168.222.46 to 34:15:xx:xx:xx:xx via eth1 Mar 30 10:52:32 dev01 in.tftpd[5890]: tftp: client does not accept options Mar 30 10:52:53 dev01 in.tftpd[5891]: tftp: client does not accept options Mar 30 10:52:53 dev01 in.tftpd[5893]: tftp: client does not accept options Mar 30 10:52:54 dev01 in.tftpd[5895]: tftp: client does not accept options This is what I get when it already has a "stored" IP: Mar 30 10:51:29 dev01 dhcpd: DHCPDISCOVER from 00:25:xx:xx:xx:xx via eth1 Mar 30 10:51:30 dev01 dhcpd: DHCPOFFER on 10.168.222.45 to 00:25:xx:xx:xx:xx via eth1 Mar 30 10:51:31 dev01 dhcpd: DHCPREQUEST for 10.0.0.61 (10.0.0.1) from 00:25:xx:xx:xx:xx via eth1: ignored (not authoritative). Do you have any suggestions? It would be much appreciated.

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  • Mac OS X 10.6.3: how does Apache config work?

    - by w-
    Just got a MacBook Pro 15" so I'm unfamiliar with how the filesystem is laid out. I noticed when in my filesystem that I've got a few paths specifying httpd.conf: /etc/apache2/httpd.conf /opt/local/apache2/conf/httpd.conf /private/etc/apache2/httpd.conf The config files are different in lots of ways (user, group, server_root, modules that are loaded, etc.) The apache2 folders themselves also greatly differ. It seems that the one getting used is either /etc/apache2/httpd.conf or /private/etc/apache2/httpd.conf I'm wondering if I might have messed up my system after installing some packages (php5, django, etc) via macports and maybe ended up with 2 apache2 instances. My questions are hence: which httpd.conf is the one being used ? what are the other files for? thanks --update-- To clarify, I didn't explicitly install apache2 via macports. I'm wondering if it was installed because it was a dependency. After more hunting around I'm learning I never should've installed php to begin with because Snow Leopard already includes php 5.3 from the get go. http://serverfault.com/questions/82410/apache-2-and-php-5-3-via-macports I'll need to open another question that asks about how the Mac filesystem works. Thanks all for replies.

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  • python-pam & pam_time module -- possible to check a user without password?

    - by medigeek
    I've looked at the example script of python-pam and linux pam pages, but it's a bit confusing, at least for a beginner in PAM (that I am): http://www.kernel.org/pub/linux/libs/pam/Linux-PAM-html/Linux-PAM_ADG.html http://packages.ubuntu.com/python-pam Is it possible to check if a user has or does not have access to login, without entering password? I would like to create a script that root can use to check if a user is allowed or not to login to the system. If so, can someone post an example that checks if the user is allowed against pam_time? Thanks in advance!

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  • Mac OS X: which folders should ClamXav Sentry watch?

    - by trolle3000
    I'm using ClamXav on my Mac. I've read this, and I am aware of the whole Macs-need-no-AV-but-they-do-anyway discussion. I guess that's why I would feel like a real jerk if I somehow managed to compromise my system! So ClamXav has been downloaded and ClamXav Sentry set up to start on log-in, but it doesn't really do anything before you tell it to. Specifically, you have to tell it which folders to watch for virusses/vira so I'm wondering, where are good places to look? Currently it's been set up to look the following places: In the home folder: ~/Downloads ~/Library/Caches ~/Library/Contextual Menu Items ~/Library/Cookies ~/Library/Internet Plug-Ins ~/Library/LaunchAgents In my system folder: /Library/Application Support /Library/Caches /Library/Contextual Menu Items /Library/Cookies /Library/Internet Plug-Ins /Library/LaunchAgents /Library/LaunchDaemons /Library/Startupitems Basically, this is 100% conjecture. All (most of) the folders have something to do with the Internet and things that start up automatically, so I'm guessing that's where vira go. But still, the qustion: Which folders should ClamXav Sentry watch, if any? FYI, I'm not using any mail applications, but please include that in your answer for anyone who might be interested.

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  • SOCKS5 proxy only, git wants to use ssh to xx.xx.xx.xx - forward? - mac os

    - by AlexAtNet
    I have SOCKS5 proxy configured and want to work with the git repository, originally cloned from ssh:... So when it tries to connect the error "Network is unreachable" appears. There are a few possible solutions: Use GIT URL rewriting and use https:// with proxy option. Probably should work well for github repositories. Use port forwarding and something like iptables/ipfw to rewrite address xx.xx.xx.xx:22 to 127.0.0.1:10yyy I'm trying to do #2. I have limited knowledge in this area, but know that I should use something like iptables. But then I discovered that on a Mac I should use ipfw. And then in the ipfw man page it told me "This utility is DEPRECATED. Please use pfctl(8) instead". So what I want to do is to rewrite xx.xx.xx.xx:22 to 127.0.0.1:10yyy and remove this rewriting. As I read, the pf.conf line should be rdr proto tcp from 127.0.0.1 to xx.xx.xx.xx port 22 -> 127.0.0.1 port 10yyy But how to add (and remove) this rule from command line?

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  • Where can I find a useful multi-language Unicode font for Mac OS X?

    - by Stephen Jennings
    On every browser I've tried (Firefox, Safari, Chrome, and Omniweb), when I go to a web page containing somewhat less-common characters, I can't see the glyphs. For example, on the Wikipedia page for the Bengali Language, the very first line contains a string of squares; on Windows, I can see the Bengali writing. Firefox does display code points on the Coptic Language article, but not Bengali. I'm not sure why. On Windows, as long as I have the Arial Unicode MS font installed, these characters fall back to that font and display properly. Mac OS X doesn't seem to ship with a font containing these Unicode characters (it has Arial Unicode MS, but it must be a subset of the Windows version because Bengali doesn't display in that font). I checked on my Snow Leopard DVD and I installed "Additional Fonts" from the Optional Installs package, but I'm still missing many languages. Is there any good, free font that contains a large collection of languages? I know creating fonts is difficult and time-consuming, but it seems like including at least one font like this with operating systems should be standard by now.

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