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  • iTunes Connect rejects my binary because I used a pre-release version of the SDK, what should I do?

    - by Prairiedogg
    NOTE - I'm posting this question to answer myself as a service to the community. Stay tuned for the answer. I downloaded a pre-release version of the iPhone SDK and tried to update one of my existing apps using a binary I built with it. Obviously you are not supposed to do this but I had forgotten about the warning when I installed the pre-release SDK. Anyway - I have two questions: Can I simply set the base SDK to an earlier version in the build settings and get around this problem? If not, then what should I do?

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  • Stackoverflow Flair Facebook app error

    - by emre
    Just to lewt you know, what happened when I allowed the app in FB Fatal error: Uncaught exception 'FacebookRestClientException' with message 'Param assoc_time must be a number' in /home/content/r/e/j/rejun2000/html/fb_so/php/facebookapi_php5_restlib.php:2878 Stack trace: #0 /home/content/r/e/j/rejun2000/html/fb_so/php/facebookapi_php5_restlib.php(2544): FacebookRestClient-call_method('facebook.data.s...', Array) #1 /home/content/r/e/j/rejun2000/html/fb_so/utils.php(188): FacebookRestClient-data_setAssociation('uid_so_uid2', '616867493', '5004213880486') #2 /home/content/r/e/j/rejun2000/html/fb_so/utils.php(208): setSoUID('616867493', -1, Object(Facebook)) #3 /home/content/r/e/j/rejun2000/html/fb_so/index.php(26): updateProfileBox('616867493', -1, Object(Facebook)) #4 {main} thrown in /home/content/r/e/j/rejun2000/html/fb_so/php/facebookapi_php5_restlib.php on line 2878

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  • Why would a FaceBook application "work" on a profile, but not a page?

    - by ed.talmadge
    I made a FaceBook application that works fine on profiles, but I can't figure out how to get it to show on a FaceBook page. For example, after I visit the application canvas URL, allow the application, then edit application settings and "add" to box and tab view... I cannot click the "plus" symbol to the left of the tabs in order to add a tab for the application. It does not appear in the list of available applications. Meanwhile, the application is working/showing up on profiles with no issues. I DID check the "Installable to Pages" checkbox on the application (authentication tab) settings. What could cause this? Here is the application canvas URL: http://apps.facebook.com/russian_girls/

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  • How do I get Facebook Connect to alert me when people comment on my blog?

    - by andygeers
    I'm using Facebook Connect's "Comments Box" (http://wiki.developers.facebook.com/index.php/Comments_Box) to handle comments on my blog. However, there doesn't appear to be an easy way to find out when people comment - ideally I'd like to receive an email whenever it happens, but I'd settle for an RSS feed or similar. Is there an easy way to set this up? Officially as an admin you can enable "notifications" but these are just the passive things that show up when you log on to Facebook itself - I rarely do this, and anyway it doesn't seem to work for anonymous comments.

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  • Facebook Api - Local development, Testserver, Liveserver ... How?

    - by Thijs Kaspers
    I'm working on a new website that uses the Facebook API for users to login and several implementations of the graph Api. My workflow usually is: Development on localhost Development using MAMP/XAMPP or similar software Push to server - testing domain A team of people can test the changes for a few days to see if everything works as planned. Push to server - live domain Changes are live for public Facebook uses the site URL in the appsettings and for security reasons, they will only redirect to that url... Problem is.. I have localhost and 2 different domains. How can I make this work? Ofcourse I could edit the hostsfile, but that only fixes it for localhost.. Still no solution for the testdomain. Please tell me this is somehow possible! I'm getting more and more depressed with the Facebook API.

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  • How do I post dynamic information to Facebook from Flash?

    - by daidai
    I am building a Flash site and I want to be able to allow the user to post dynamically produced information to their Facebook wall, but I can't find out any information within the Facebook developers documentation. Its simple enough in Javascript/HTML: <script type="text/javascript"> function callPublish(msg, attachment, action_link) { FB.ensureInit(function () { FB.Connect.streamPublish('', attachment, action_link); }); } </script> <input type="button" onclick="callPublish('',{'name':'Post this to Facebook','href':'http://dev2.com','description':'this is some body test'},null);return false;" value="Preview Dialog" /> As you can see I don't want to create sessions or login or anything complicated, just post to info to their wall.

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  • How can I update my business' Facebook page via my Ruby on Rails app?

    - by Eric S.
    I'm creating a new rails app for my business, and I just finished a new feature where I can put an announcement on the website (for specials, sales, etc.). I want this announcement to automatically be set to my business' Facebook page. How can I easily do this? Is the only way to create a Facebook application, and then if so, can a Facebook application have permissions to edit a business' page (I know apps can edit user profiles, but I don't know about business pages)? Thanks for any help!

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  • Set up lnux box for hosting a-z [apache mysql php ssl]

    - by microchasm
    I am in the process of reinstalling the OS on a machine that will be used to host a couple of apps for our business. The apps will be local only; access from external clients will be via vpn only. The prior setup used a hosting control panel (Plesk) for most of the admin, and I was looking at using another similar piece of software for the reinstall - but I figured I should finally learn how it all works. I can do most of the things the software would do for me, but am unclear on the symbiosis of it all. This is all an attempt to further distance myself from the land of Configuration Programmer/Programmer, if at all possible. I can't find a full walkthrough anywhere for what I'm looking for, so I thought I'd put up this question, and if people can help me on the way I will edit this with the answers, and document my progress/pitfalls. Hopefully someday this will help someone down the line. The details: CentOS 5.5 x86_64 httpd: Apache/2.2.3 mysql: 5.0.77 (to be upgraded) php: 5.1 (to be upgraded) The requirements: SECURITY!! Secure file transfer Secure client access (SSL Certs and CA) Secure data storage Virtualhosts/multiple subdomains Local email would be nice, but not critical The Steps: Download latest CentOS DVD-iso (torrent worked great for me). Install CentOS: While going through the install, I checked the Server Components option thinking I was going to be using another Plesk-like admin. In hindsight, considering I've decided to try to go my own way, this probably wasn't the best idea. Basic config: Setup users, networking/ip address etc. Yum update/upgrade. Upgrade PHP: To upgrade PHP to the latest version, I had to look to another repo outside CentOS. IUS looks great and I'm happy I found it! cd /tmp #wget http://dl.iuscommunity.org/pub/ius/stable/Redhat/5/x86_64/epel-release-1-1.ius.el5.noarch.rpm #rpm -Uvh epel-release-1-1.ius.el5.noarch.rpm #wget http://dl.iuscommunity.org/pub/ius/stable/Redhat/5/x86_64/ius-release-1-4.ius.el5.noarch.rpm #rpm -Uvh ius-release-1-4.ius.el5.noarch.rpm yum list | grep -w \.ius\. [will list all packages available in the IUS repo] rpm -qa | grep php [will list installed packages needed to be removed. the installed packages need to be removed before you can install the IUS packages otherwise there will be conflicts] #yum shell >remove php-gd php-cli php-odbc php-mbstring php-pdo php php-xml php-common php-ldap php-mysql php-imap Setting up Remove Process >install php53 php53-mcrypt php53-mysql php53-cli php53-common php53-ldap php53-imap php53-devel >transaction solve >transaction run Leaving Shell #php -v PHP 5.3.2 (cli) (built: Apr 6 2010 18:13:45) This process removes the old version of PHP and installs the latest. To upgrade mysql: Pretty much the same process as above with PHP #/etc/init.d/mysqld stop [OK] rpm -qa | grep mysql [installed mysql packages] #yum shell >remove mysql mysql-server Setting up Remove Process >install mysql51 mysql51-server mysql51-devel >transaction solve >transaction run Leaving Shell #service mysqld start [OK] #mysql -v Server version: 5.1.42-ius Distributed by The IUS Community Project And this is where I'm at. I will keep editing this as I make progress. Any tips on how to Configure Virtualhosts for SSL, setting up a CA, setting up SFTP with openSSH, or anything else would be appreciated.

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  • PHP/MySQL Swap places in database + JavaScript (jQuery)

    - by James Brooks
    I'm currently developing a website which stores bookmarks in a MySQL database using PHP and jQuery. The MySQL for bookmarks looks like this (CSV format): id,userid,link_count,url,title,description,tags,shareid,fav,date "1";"1";"0";"img/test/google.png";"Google";"Best. Search Engine. Ever.";"google, search, engine";"7nbsp";"0";"1267578934" "2";"1";"1";"img/test/james-brooks.png";"jTutorials";"Best. jQuery Tutorials. Ever.";"jquery, jtutorials, tutorials";"8nbsp";"0";"1267578934" "3";"1";"2";"img/test/benokshosting.png";"Benoks Hosting";"Cheap website hosting";"Benoks, Hosting, server, linux, cpanel";"9nbsp;";"0";"1267578934" "4";"1";"3";"img/test/jbrooks.png";"James Brooks";"Personal website FTW!";"james, brooks, jbrooksuk, blog, personal, portfolio";"1nbsp";"0";"1267578934" "6";"1";"4";"img/test/linkbase.png";"LinkBase";"Store and organise your bookmarks and access them from anywhere!";"linkbase, bookmarks, organisation";"3nbsp";"0";"1267578934" "5";"1";"5";"img/test/jtutorials.png";"jTutorials";"jQuery tutorials, videos and examples!";"jquery, jtutorials, tutorials";"2nbsp";"0";"1267578934" I'm using jQuery Sortable to move the bookmarks around (similar to how Google Chrome does). Here is the JavaScript code I use to format the bookmarks and post the data to the PHP page: $(".bookmarks").sortable({scroll: false, update: function(event, ui){ // Update bookmark position in the database when the bookmark is dropped var newItems = $("ul.bookmarks").sortable('toArray'); console.log(newItems); var oldItems = ""; for(var imgI=0;imgI < newItems.length;imgI++) { oldItems += $("ul.bookmarks li#" + imgI + " img").attr("id") + ","; } oldItems = oldItems.slice(0, oldItems.length-1); console.log("New position: " + newItems); console.log("Old position: " + oldItems); // Post the data $.post('inc/updateBookmarks.php', 'update=true&olditems=' + oldItems + "&newitems=" + newItems, function(r) { console.log(r); }); } }); The PHP page then goes about splitting the posted arrays using explode, like so: if(isset($pstUpdate)) { // Get the current and new positions $arrOldItems = $_POST['olditems']; $arrOldItems = explode(",", $arrOldItems); $arrNewItems = $_POST['newitems']; $arrNewItems = explode(",", $arrNewItems); // Get the user id $usrID = $U->user_field('id'); // Update the old place to the new one for($anID=0;$anID<count($arrOldItems);$anID++) { //echo "UPDATE linkz SET link_count='" . $arrNewItems[$anID] . "' WHERE userid='" . $usrID . "' AND link_count='" . $arrOldItems[$anID] . "'\n"; //echo "SELECT id FROM linkz WHERE link_id='".$arrOldItems[$anID]."' AND userid='".$usrID."'"; $curLinkID = mysql_fetch_array(mysql_query("SELECT id FROM linkz WHERE link_count='".$arrOldItems[$anID]."' AND userid='".$usrID."'")) or die(mysql_error()); echo $arrOldItems[$anID] . " => " . $arrNewItems[$anID] . " => " . $curLinkID['id'] . "\n"; //mysql_query("UPDATE linkz SET link_count='" . $arrNewItems[$anID] . "' WHERE userid='" . $usrID . "' AND link_count='" . $curLinkID['id'] . "'") or die(mysql_error()); // Join a string with the new positions $outPos .= $arrNewItems[$anID] . "|"; } echo substr($outPos, 0, strlen($outPost) - 1); } So, each bookmark is given it's own link_count id (which starts from 0 for each user). Every time a bookmark is changed, I need the link_count to be changed as needed. If we take this array output as the starting places: Array ( [0] => 0 [1] => 1 [2] => 2 [3] => 3 [4] => 4 [5] => 5 ) Each index equalling the link_count position, the resulting update would become: Array ( [0] => 1 [1] => 0 [2] => 3 [3] => 4 [4] => 5 [5] => 2 ) I have tried many ways but none are successful. Thanks in advance.

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  • Not sure how to link json 100% in php

    - by ronhdoge
    Im trying to create an rss feed that my droid app reads but i have some holes that i can figure how to fix the rss link page is http://www.mandarich.com/mandarichServer/mlb/indexbaseball.php when reading the rss i can see where the icon is missing on some and cant figure out why and cant figure saint louis at all. and the code i have for the php is as follows: <?php $teams["boston"] = "bostonredsox.gif"; $teams["nyyankees"] = "newyorkyankes.gif"; $teams["baltimore"] = "baltimoreorioles.gif"; $teams["tampa"] = "tampabayrays.gif"; $teams["toronto"] = "torontobluejays.gif"; $teams["atlanta"] = "atlantabraves.gif"; $teams["florida"] = "floridamarlins.gif"; $teams["nymets"] = "newyorkmets.gif"; $teams["philadelphia"] = "philadelphiaphillies.gif"; $teams["washington"] = "washingtonnationals.gif"; $teams["chicagosox"] = "chicagowhitesox.gif"; $teams["cleveland"] = "clevelandindians.gif"; $teams["detroit"] = "detroittigers.gif"; $teams["kansas"] = "kansascityroyals.gif"; $teams["minnesota"] = "minnesotatwins.gif"; $teams["chicagocubs"] = "chicagocubs.gif"; $teams["cincinnati"] = "cinncinatireds.gif"; $teams["houston"] = "houstonastros.gif"; $teams["milwaukee"] = "milwaukeebrewers.gif"; $teams["pittsburgh"] = "pitsburghpirates.gif"; $teams["st.louis"] = "stlouiscardinals.gif"; $teams["laangels"] = "losangelesangels.gif"; $teams["oakland"] = "oaklandathletics.gif"; $teams["seattle"] = "seattlemariners.gif"; $teams["texas"] = "texasrangers.gif"; $teams["arizona"] = "arizonadiamondbacks.gif"; $teams["colorado"] = "coloradorockies.gif"; $teams["ladodgers"] = "losangelesdodgers.gif"; $teams["sandiego"] = "sandiegopadres.gif"; $teams["sanfrancisco"] = "sanfranciscogiants.gif"; $abbr["arizona"] = "ARI"; $abbr["oakland"] = "OAK"; $abbr["baltimore"] = "BAL"; $abbr["tampa"] = "TAM"; $abbr["boston"] = "BOS"; $abbr["nyyankees"] = "NYY"; $abbr["texas"] = "TEX"; $abbr["toronto"] = "TOR"; $abbr["laangels"] = "LAA"; $abbr["atlanta"] = "ALT"; $abbr["colorado"] = "COL"; $abbr["philadelphia"] = "PHI"; $abbr["florida"] = "FLA"; $abbr["milwaukee"] = "MIL"; $abbr["washington"] = "WAS"; $abbr["chicagosox"] = "CHW"; $abbr["cleveland"] = "CLE"; $abbr["detroit"] = "DET"; $abbr["seattle"] = "SEA"; $abbr["sanfrancisco"] = "SFO"; $abbr["st.louis"] = "STL"; $abbr["chicagocubs"] = "CHC"; $abbr["houston"] = "HOU"; $abbr["nymets"] = "NYM"; $abbr["cincinnati"] = "CIN"; $abbr["sandiego"] = "SDG"; $abbr["ladodgers"] = "LAD"; $abbr["pittsburgh"] = "PIT"; $abbr["minnesota"] = "MIN"; $abbr["kansas"] = "KAN"; ?

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  • PHP GD Text Transparency..

    - by Deagle
    Hello, I can't slove this. I'm trying to make a text transparency but doesn't work.. Here how it looks: qshort.com/userbar/gd.php Here how if possible to show with transparency: qshort.com/userbar/transparent.png Is that possible? Here my PHP Code: <?php header('Content-type: image/png'); $im = imagecreatefrompng("signature.png"); $white = imagecolorallocate($im, 255, 255, 255); $grey = imagecolorallocate($im, 114, 114, 114); $black = imagecolorallocate($im, 0, 0, 0); $tr = imagecolorallocatealpha($im, 255, 255, 255, 20); $trg = imagecolorallocatealpha($im, 114, 114, 114, 50); $font = 'TCCB.TTF'; $mtext="Money: $0"; $mx="261"; $my="80"; $ms="16"; imagettftext($im, $ms, 0, $mx+1, $my, $grey, $font, $mtext); imagettftext($im, $ms, 0, $mx-1, $my, $grey, $font, $mtext); imagettftext($im, $ms, 0, $mx, $my+1, $grey, $font, $mtext); imagettftext($im, $ms, 0, $mx, $my-1, $grey, $font, $mtext); imagettftext($im, $ms, 0, $mx, $my, $white, $font, $mtext); $atext="Score: 0"; $ax="261"; $ay="100"; $as="16"; imagettftext($im, $as, 0, $ax+1, $ay, $grey, $font, $atext); imagettftext($im, $as, 0, $ax-1, $ay, $grey, $font, $atext); imagettftext($im, $as, 0, $ax, $ay+1, $grey, $font, $atext); imagettftext($im, $as, 0, $ax, $ay-1, $grey, $font, $atext); imagettftext($im, $as, 0, $ax, $ay, $white, $font, $atext); $ctext="Properties: 0"; $cx="261"; $cy="120"; $cs="16"; imagettftext($im, $cs, 0, $cx+1, $cy, $grey, $font, $ctext); imagettftext($im, $cs, 0, $cx-1, $cy, $grey, $font, $ctext); imagettftext($im, $cs, 0, $cx, $cy+1, $grey, $font, $ctext); imagettftext($im, $cs, 0, $cx, $cy-1, $grey, $font, $ctext); imagettftext($im, $cs, 0, $cx, $cy, $white, $font, $ctext); $ntext="Nickname"; $nx="20"; $ny="45"; $ns="35"; imagettftext($im, $ns, 0, $nx+1, $ny, $trg, $font, $ntext); imagettftext($im, $ns, 0, $nx-1, $ny, $trg, $font, $ntext); imagettftext($im, $ns, 0, $nx, $ny+1, $trg, $font, $ntext); imagettftext($im, $ns, 0, $nx, $ny-1, $trg, $font, $ntext); imagettftext($im, $ns, 0, $nx, $ny, $tr, $font, $ntext); imagepng($im); imagedestroy($im); ?> Thanks, Waiting for answer.

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  • HTML / PHP form

    - by user317128
    I am trying to code an all in one HTML/PHP contact from with error checking. When I load this file in my browser there is not HTML. I am a newb php programmer so most likely forgot something pretty obvious. <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> <title>All In One Feedback Form</title> </head> <body> <? $form_block = " <input type=\"hidden\" name=\"op\" value=\"ds\"> <form method=\"post\" action=\"$server[PHP_SELF]\"> <p>Your name<br /> <input name=\"sender_name\" type=\"text\" size=30 value=\"$_POST[sender_name]\" /></p> <p>Email<br /> <input name=\"sender_email\" type=\"text\" size=30 value=\"$_POST[sender_email]\"/></p> <p>Message<br /> <textarea name=\"message\" cols=30 rows=5 value=\"$_POST[message]\"></textarea></p> <input name=\"submit\" type=\"submit\" value=\"Send This Form\" /> </form>"; if ($_POST[op] != "ds") { //they see this form echo "$form_block"; } else if ($_POST[op] == "ds") { if ($_POST[sender_name] == "") { $name_err = "Please enter your name<br>"; $send = "no"; } if ($_POST[sender_email] == "ds") { $email_err = "Please enter your email<br>"; $send = "no"; } if ($_POST[message] == "ds") { $message_err = "please enter message<br>"; $send = "no"; } if ($send != "no") { //its ok to send $to = "[email protected]"; $subject = "All in one web site feed back"; $mailheaders = "From: website <some email [email protected]> \n"; $mailheaders .= "Reply-To: $_POST[sender_email]\n"; $msg = "Email sent from this site www.ccccc.com\n"; $msg .= "Senders name: $_POST[senders_name]\n"; $msg .= "Sender's E-Mail: $_POST[sender_email]\n"; $msg .= "Message: $_POST[message]\n\n"; mail($to, $subject, $msg, $mailheaders); echo "<p>Mail has been sent</p>"; } else if ($send == "no") { echo "$name_err"; echo "$email_err"; echo "$message_err"; echo "$form_block"; } } ?> </body> </html> FYI I am trying the example from a book named PHP 6 Fast and Easy Wed Development

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  • HTML / PHP from

    - by user317128
    I am trying to code an all in one HTML/PHP contact from with error checking. When I load this file in my browser there is not HTML. I am a newb php programmer so most likely forgot something pretty obvious. <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> <title>All In One Feedback Form</title> </head> <body> <? $form_block = " <input type=\"hidden\" name=\"op\" value=\"ds\"> <form method=\"post\" action=\"$server[PHP_SELF]\"> <p>Your name<br /> <input name=\"sender_name\" type=\"text\" size=30 value=\"$_POST[sender_name]\" /></p> <p>Email<br /> <input name=\"sender_email\" type=\"text\" size=30 value=\"$_POST[sender_email]\"/></p> <p>Message<br /> <textarea name=\"message\" cols=30 rows=5 value=\"$_POST[message]\"></textarea></p> <input name=\"submit\" type=\"submit\" value=\"Send This Form\" /> </form>"; if ($_POST[op] != "ds") { //they see this form echo "$form_block"; } else if ($_POST[op] == "ds") { if ($_POST[sender_name] == "") { $name_err = "Please enter your name<br>"; $send = "no"; } if ($_POST[sender_email] == "ds") { $email_err = "Please enter your email<br>"; $send = "no"; } if ($_POST[message] == "ds") { $message_err = "please enter message<br>"; $send = "no"; } if ($send != "no") { //its ok to send $to = "[email protected]"; $subject = "All in one web site feed back"; $mailheaders = "From: website <some email [email protected]> \n"; $mailheaders .= "Reply-To: $_POST[sender_email]\n"; $msg = "Email sent from this site www.ccccc.com\n"; $msg .= "Senders name: $_POST[senders_name]\n"; $msg .= "Sender's E-Mail: $_POST[sender_email]\n"; $msg .= "Message: $_POST[message]\n\n"; mail($to, $subject, $msg, $mailheaders); echo "<p>Mail has been sent</p>"; } else if ($send == "no") { echo "$name_err"; echo "$email_err"; echo "$message_err"; echo "$form_block"; } } ?> </body> </html> FYI I am trying the example from a book named PHP 6 Fast and Easy Wed Development

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  • dynamically drawing polylines on googlemaps using php/mysql

    - by arc
    Hi. I am new to the googlemaps API. I have written a small app for my mobile phone that periodically updates its location to an SQL databse. I would like to display this information on a googlemap in my browser. Ideally i'd like to then poll the database periodically and if any new co-ords have arrived, add them to the line. Best way of describing it is this; http://tiny.cc/HEIa0 In a quest to get to there, i've started on the documents on google and been modifying them to try and acheive what I want. It doesn't work - and i don't know enough to know why. I would love some advice as to why, and any pointers towards my ultimate goal would be very much welcomed. Google Maps AJAX + MySQL/PHP Example <script type="text/javascript"> //<![CDATA[ function load() { if (GBrowserIsCompatible()) { var map = new GMap2(document.getElementById("map")); map.addControl(new GSmallMapControl()); map.addControl(new GMapTypeControl()); map.setCenter(new GLatLng(47.614495, -122.341861), 13); GDownloadUrl("phpsqlajax_genxml.php", function(data) { var xml = GXml.parse(data); var line = []; var markers = xml.documentElement.getElementsByTagName("points"); for (var i = 0; i < points.length; i++) { var point = points.item(i); var lat = point.getAttribute("lat"); var lng = point.getAttribute("lng"); var latlng = new GLatLng(lat, lng); line.push(latlng); if (point.firstChild) { var station = point.firstChild.nodeValue; var marker = createMarker(latlng, station); map.addOverlay(marker); } } var polyline = new GPolyline(line, "#ff0000", 3, 1); map.addOverlay(polyline); }); } //]]> My php file is generating the following XML; <?xml version="1.0" encoding="UTF-8" ?> <points> <point lng="-122.340141" lat="47.608940"/> <point lng="-122.344391" lat="47.613590"/> <point lng="-122.356445" lat="47.624561"/> <point lng="-122.337654" lat="47.606365"/> <point lng="-122.345673" lat="47.612823"/> <point lng="-122.340363" lat="47.605961"/> <point lng="-122.345467" lat="47.613976"/> <point lng="-122.326584" lat="47.617214"/> <point lng="-122.342834" lat="47.610126"/> </points> I have successfully worked through this; http://code.google.com/apis/maps/articles/phpsqlajax.html before attempting to customise the code. Any pointers? Where am I go wrong?

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  • Send smtp mail in php with HTML page attach as a text

    - by Nirmal
    Hello All.... I have a requirement of sending mail using smtp server in php. Now I am able to send the mail using smtp for a plain text. but I have a requirement where I need to attach an HTML page, which includes set of images. Now for that I am trying the following code : <?php require_once "Mail.php"; $to = '[email protected]'; $from = '[email protected]'; $subject = $_POST['subject']; $body = $_POST['message']; $fileatt = $_FILES['fileatt']['tmp_name']; $fileatt_type = $_FILES['fileatt']['type']; $fileatt_name = $_FILES['fileatt']['name']; $headers = array ('From' => $from, 'To' => $to, 'Subject' => $subject); if (is_uploaded_file($fileatt)) { echo("<p>Inside 1</p>"); $file = fopen($fileatt,'rb'); $data = fread($file,filesize($fileatt)); fclose($file); // Generate a boundary string $semi_rand = md5(time()); $mime_boundary = "==Multipart_Boundary_x{$semi_rand}x"; array_push(&$headers, 'MIME-Version: 1.0'); array_push(&$headers, 'Content-Type: multipart/mixed;'); array_push(&$headers, " boundary=\"{$mime_boundary}\""); echo("<p>Inside 2</p>"); $body = "This is a multi-part message in MIME format.\n\n" . "--{$mime_boundary}\n" . "Content-Type: text/plain; charset=\"iso-8859-1\"\n" . "Content-Transfer-Encoding: 7bit\n\n" . $body . "\n\n"; echo("<p>Inside 3</p>"); $data = chunk_split(base64_encode($data)); echo("<p>Inside 4</p>"); $body .= "--{$mime_boundary}\n" . "Content-Type: {$fileatt_type};\n" . " name=\"{$fileatt_name}\"\n" . "Content-Transfer-Encoding: base64\n\n" . $data . "\n\n" . "--{$mime_boundary}--\n"; echo("<p>Inside 5</p>"); } $host = "[email protected]"; $username = "[email protected]"; $password = "user"; $smtp = Mail::factory('smtp', array ('host' => $host, 'auth' => true, 'username' => $username, 'password' => $password)); $mail = $smtp->send($to, $headers, $body); if (PEAR::isError($mail)) { echo("<p>" . $mail->getMessage() . "</p>"); } else { echo("<p>Message successfully sent!</p>"); } ?> Now this code works fine for me, and it's sending the mail to the target email address. But when I open this email in the inbox, it's showing me the following text in the mailbox: This is a multi-part message in MIME format. --==Multipart_Boundary_x368d72fe1ff44518e90537abdb4bf029x Content-Type: text/plain; charset="iso-8859-1" Content-Transfer-Encoding: 7bit test 1011 --==Multipart_Boundary_x368d72fe1ff44518e90537abdb4bf029x Content-Type: text/html; name="mailing.html" Content-Transfer-Encoding: base64 PCFET0NUWVBFIGh0bWwgUFVCTElDICItLy9XM0MvL0RURCBYSFRNTCAxLjAgVHJhbnNpdGlvbmFs Ly9FTiIgImh0dHA6Ly93d3cudzMub3JnL1RSL3hodG1sMS9EVEQveGh0bWwxLXRyYW5zaXRpb25h ................ So, it's clearly showing me the encoded data. So, what should modify to send the proper html page that should be visible in targeted email's inbox? Thanks in advance...

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  • PHP - DOM class - numbered entities and encodings problem

    - by user343607
    Hi guys, I'm having some difficult with PHP DOM class. I am making a sitemap script, and I need the output of $doc-saveXML() to be like <?xml version="1.0" encoding="UTF-8"?> <root> <url> <loc>http://www.somesite.com/servi&#xE7;os/redesign</loc> </url> </root> or <?xml version="1.0" encoding="UTF-8"?> <root> <url> <loc>http://www.somesite.com/servi&#231;os/redesign</loc> </url> </root> but I am getting: <?xml version="1.0" encoding="UTF-8"?> <root> <url> <loc>http://www.somesite.com/servi&amp;#xE7;os/redesign</loc> </url> </root> This is the closet I could get, using a replace named to numbered entities function. I was also able to reproduce <?xml version="1.0" ?> <root> <url> <loc>http://www.somesite.com/servi&amp;#xE7;os/redesign</loc> </url> </root> But without the encoding specified. The best solution (the way I think the code should be written) would be: <?php $myArray = array(); // do some stuff to populate the with URL strings $doc = new DOMDocument('1.0', 'UTF-8'); // here we modify some property. Maybe is the answer I am looking for... $urlset = doc->createElement("urlset"); $urlset = $doc->appendChild($urlset); foreach($myArray as $address) { $url = $doc->createElement("url"); $url = $urlset->appendChild($url); $loc = $doc->createElement("loc"); $loc = $url->appendChild($loc); $valueContent = $doc->createTextNode($value); $valueContent = $loc->appendChild($address); } echo $doc->saveXML(); ?> Notes: Server response header contains charset as UTF-8; PHP script is saved in UTF-8; URLs read are UTF-8 strings; Above script contains encoding declaration on DOMDocument constructor, and does not use any convert functions, like htmlentities, urlencode, utf8_encode... I've tried changing the DOMDocument properties DOMDocument::$resolveExternals and DOMDocument::$substituteEntities values. None combinations worked. And yes, I know I can made all process without specifying the character set on DOMDocument constructor, dump string content into a variable and make a very simple string substitution with string replace functions. This works. But I would like to know where I am slipping, how can this be made using native API's and settings, or even if this is possible. Thanks in advance.

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  • php form doesnt submit one of the fields

    - by steve
    i have bought a template that have built in contact form problem is that it submits every thing except "company" name i have spent few hours messing around with it but cant get to work it. if you can point me to some solution i would be greatful thanks in advance this is contact form <form action="php/contact.php" method="post" id="contactform"> <ol> <li> <label for="name">your name <span class="red">*</span></label> <input id="name" name="name" class="text" /> </li> <li> <label for="email">Your email <span class="red">*</span></label> <input id="email" name="email" class="text" /> </li> <li> <label for="company">Company Name</label> <input id="company" name="company" class="text" /> </li> <li> <label for="subject">Subject</label> <input id="subject" name="subject" class="text" /> </li> <li> <label for="message">Message <span class="red">*</span></label> <textarea id="message" name="message" rows="6" cols="50"></textarea> </li> <li class="buttons"> <input type="image" name="imageField" id="imageField" src="images/button.jpg" /> </li> </ol> </form> this is java script <script type="text/javascript"> // <![CDATA[ jQuery(document).ready(function(){ $('#contactform').submit(function(){ var action = $(this).attr('action'); $.post(action, { name: $('#name').val(), email: $('#email').val(), company: $('#company').val(), subject: $('#subject').val(), message: $('#message').val() }, function(data){ $('#contactform #submit').attr('disabled',''); $('.response').remove(); $('#contactform').before('<p class="response">'+data+'</p>'); $('.response').slideDown(); if(data=='Thanks for your message, will contact you soon.') $('#contactform').slideUp(); } ); return false; }); }); // ]]> </script> this is php script if(!$_POST) exit; $email = $_POST['email']; //$error[] = preg_match('/\b[A-Z0-9._%-]+@[A-Z0-9.-]+.[A-Z]{2,4}\b/i', $POST['email']) ? '' : 'INVALID EMAIL ADDRESS'; if(!eregi("^[a-z0-9]+([\.-][a-z0-9]+)" ."@"."([a-z0-9]+([.-][a-z0-9]+))+"."\.[a-z]{2,}"."$",$email )){ $error.="Invalid email address entered"; $errors=1; } if($errors==1) echo $error; else{ $values = array ('name','email','message'); $required = array('name','email','message'); $your_email = "[email protected]"; $email_subject = "New Message: ".$_POST['subject']; $email_content = "new message:\n"; foreach($values as $key => $value){ if(in_array($value,$required)){ if ($key != 'subject' && $key != 'company') { if( empty($_POST[$value]) ) { echo 'Please fill in all required fields, marked with *'; exit; } } $email_content .= $value.': '.$_POST[$value]."\n"; } } if(@mail($your_email,$email_subject,$email_content)) { echo 'Thanks for your message, will contact you soon.'; } else { echo 'ERROR!'; } }

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  • Why doesn't PHP's oci_connect return false?

    - by absolethe
    I have a situation in which we have two production databases that synchronize with one other. Server One is considered the primary. Sometimes due to maintenance or a disaster Server Two will become primary. In some of our code that means we have to manually go in and edit the server name for database connections. I find this annoying, so the last thing I wrote I put the server information for both and set up a loop. If oci_connect failed on the Server One 3 times it would move on to Server Two. If Server Two failed 3 times it would notify the user a connection couldn't be made. This has worked fine most times we've had the situation of switching the servers. Yesterday, for example, it worked fine. Today it didn't. It just sat and spun endlessly. No error in the PHP error log. No failure to move on from. No error output to the screen. Nothing for 5 minutes. So then I had to manually edit the stupid config file. I asked what could possibly be different and I was told "yesterday the database was down, but not the server. today the server is down." Okay...? But I don't see a distinction. I would expect oci_connect to return false if it can't establish any sort of communication with the server. I'd expect it to timeout and error. Not just pass it on when it receives an error code from the server. What if there's a network problem, for example? Is this a bug in oci_connect or is there a possibility that something in our PHP configuration gives oci_connect a crazily long timeout? If it is a sort of "bug" is there some way I can check to see if the server is up first? Like a ping? (Of course when I did a ping through the command prompt I got a response from Server One and then was told, "it's back now" although I am skeptical about the timing on that.) Anyway, if anyone could shed some light on why oci_connect might run endlessly without failing and how to keep it from doing so I'd be grateful. -- Edit: My code looks like the examples on PHP.net only in some loops. $count = count($servers); for($i = 0; $i < $count; $i++){ if((!isset($connection)) || ($connection == false)){ // Attempt to connect to the oracle database $connection = @oci_connect($servers[$i]["user"], $servers[$i]["pass"], $servers[$i]["conid"]) or ($conn_error = oracle_error()); // Try again if there was a failure if(($connection == false) || (isset($con_error))){ // Three (two more) tries per alternative for($j = $st; $j < $fn; $j++){ // Try again to connect $connection = @oci_connect($servers[$i]["user"], $servers[$i]["pass"], $servers[$i]["conid"]) or ($conn_error = oracle_error()); } // for($j = 2; $j < 4; $j++) } // if($connection == false) } // if(!isset($connection) || ($connection == false)) } // for($i = 0; $i < $count; $i++)

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  • PHP - Accessing a value selected in Combobox

    - by Pavitar
    I want to write a code that should let me select from a drop down list and onClick of a button load the data from a mysql database.However I cannot access the value selected in the drop down menu.I have tried to access them by $_POST['var_name'] but still can't do it. I'm new to PHP. Following is my code: <?php function load(){ $department = $_POST['dept']; $employee = $_POST['emp']; //echo "$department"; //echo "$employee"; $con = mysqli_connect("localhost", "root", "pwd", "payroll"); $rs = $con->query("select * from dept where deptno='$department'"); $row = $rs->fetch_row(); $n = $row[0]; $rs->free(); $con->close(); } ?> <html> <head> <title>Payroll</title> </head> <body> <h1 align="center">IIT Department</h1> <form method="post"> <table align="center"> <tr> <td> Dept Number: <select name="dept"> <option value="10" selected="selected">10</option> <option value="20">20</option> <option value="30">30</option> <option value="40">40</option> </select> </td> <td> <input type="button" value="ShowDeptEmp" name="btn1"> </td> <td> Job: <select name="job"> <option value="President" selected="selected">President</option> <option value="Manager">Manager</option> <option value="Clerk">Clerk</option> <option value="Salesman">Salesman</option> <option value="Analyst">Analyst</option> </select> </td> <td> <input type="button" value="ShowJobEmp" name="btn1"> </td> </tr> </table> </form> <?php if(isset($_POST['dept']) && $_POST['dept'] != "") load(); ?> </body> </html>

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  • PHP Form - Empty input enter this text - Validation

    - by James Skelton
    No doubt very simple question for someone with php knowledge. I have a form with a datepicker, all is fine when a user has selected a date the email is send with: Date: 2012 04 10 But i would like if the user has skipped this and left blank (as i have not made this required) to send as: Date: Not Entered (<-- Or something) Instead at the minute of course it reads: Date: Form input <input type="text" class="form-control" id="datepicker" name="datepicker" size="50" value="Date Of Wedding" /> This is the validator $(document).ready(function(){ //validation contact form $('#submit').click(function(event){ event.preventDefault(); var fname = $('#name').val(); var validInput = new RegExp(/^[a-zA-Z0-9\s]+$/); var email = $('#email').val(); var validEmail = new RegExp(/^([a-zA-Z0-9_\.\-])+\@(([a-zA-Z0-9\-])+\.)+([a-zA-Z0-9]{2,4})+$/); var message = $('#message').val(); if(fname==''){ showError('<div class="alert alert-danger">Please enter your name.</div>', $('#name')); $('#name').addClass('required'); return;} if(!validInput.test(fname)){ showError('<div class="alert alert-danger">Please enter a valid name.</div>', $('#name')); $('#name').addClass('required'); return;} if(email==''){ showError('<div class="alert alert-danger">Please enter an email address.</div>', $('#email')); $('#email').addClass('required'); return;} if(!validEmail.test(email)){ showError('<div class="alert alert-danger">Please enter a valid email.</div>', $('#email')); $('#email').addClass('required'); return;} if(message==''){ showError('<div class="alert alert-danger">Please enter a message.</div>', $('#message')); $('#message').addClass('required'); return;} // setup some local variables var request; var form = $(this).closest('form'); // serialize the data in the form var serializedData = form.serialize(); // fire off the request to /contact.php request = $.ajax({ url: "contact.php", type: "post", data: serializedData }); // callback handler that will be called on success request.done(function (response, textStatus, jqXHR){ $('.contactWrap').show( 'slow' ).fadeIn("slow").html(' <div class="alert alert-success centered"><h3>Thank you! Your message has been sent.</h3></div> '); }); // callback handler that will be called on failure request.fail(function (jqXHR, textStatus, errorThrown){ // log the error to the console console.error( "The following error occured: "+ textStatus, errorThrown ); }); }); //remove 'required' class and hide error $('input, textarea').keyup( function(event){ if($(this).hasClass('required')){ $(this).removeClass('required'); $('.error').hide("slow").fadeOut("slow"); } }); // show error showError = function (error, target){ $('.error').removeClass('hidden').show("slow").fadeIn("slow").html(error); $('.error').data('target', target); $(target).focus(); console.log(target); console.log(error); return; } });

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  • Trying to use json to populate areas of my website using mysql, php, and jquery.

    - by RyanPitts
    Ok, so this is my first attempt at doing anything with JSON. I have done a lot with PHP and MySql as well as jQuery and JavaScript...but nothing with JSON. I have some data in a MySql database. In the codes below i am using a PHP file to retrieve the data from the MySql database and using json_encode to format it to JSON. This file is being called by the JavaScript that runs when the page loads (well, it runs on document.ready actually). I then use jQuery to access the JSON keys and values to fill in areas of the page "dynamically". Here is the code snippets i am using (excuse my "noobness" on writing these snippets, still learning all this). This is my script that is on my HTML page test.php: <script type="text/javascript"> $(document).ready(function(){ $.getJSON("json_events.php",function(data){ $.each(data.events, function(i,events){ var tblRow = "<tr>" +"<td>" + events.id + "</td>" +"<td>" + events.customerId + "</td>" +"<td>" + events.filingName + "</td>" +"<td>" + events.title + "</td>" +"<td>" + events.details + "</td>" +"<td>" + events.dateEvent + "</td>" +"<td><a href='assets/customers/testchurch/events/" + events.image + "'>" + events.image + "</a></td>" +"<td>" + events.dateStart + "</td>" +"<td>" + events.dateEnd + "</td>" +"</tr>" $(tblRow).appendTo("#eventsdata tbody"); }); }); $.getJSON("json_events.php",function(data){ $.each(data.events, function(i,events){ $("#title").html("First event title: " + events.title + " ..."); }); }); }); </script> This is the code for the php file being called by the above JS: json_events.php <?php require_once('includes/configread.php'); $arrayEvents = array(); $resultsEvents = mysql_query("SELECT * FROM events"); while($objectEvents = mysql_fetch_object($resultsEvents)) { $arrayEvents[] = $objectEvents; } $json_object_events = json_encode($arrayEvents); $json_events = "{\"events\": " . $json_object_events . " }"; echo $json_events; require_once('includes/closeconnread.php'); ?> This is my JSON that is held in the variable $json_events from my php file json_events.php: { "events": [ { "id": "2", "customerId": "1004", "filingName": "testchurch", "title": "Kenya 2011 Training Meeting", "details": "This meeting will be taking place on Sunday, February 10th @ 6pm. Get ready for our annual Kenya trip in 2011. We have been blessed to be able to take this trip for the past 3 years. Now, it's your turn to bless others! Come to this training meeting to learn how to minister to the people in Kenya and also learn what we'll be doing there.", "dateEvent": "2011-02-10", "image": "kenya2011.jpg", "dateStart": "2010-09-04", "dateEnd": "2011-02-10" }, { "id": "6", "customerId": "1004", "filingName": "testchurch", "title": "New Series: The Journey", "details": "We will be starting our new series titled "The Journey". Come worship with us as we walk with Paul on his 2nd missionary journey.", "dateEvent": "2011-01-02", "image": "", "dateStart": "2010-09-06", "dateEnd": "2011-01-02" } ] } This is my HTML on test.php: <table id="eventsdata" border="1"> <thead> <tr> <th>id</th> <th>customerId</th> <th>filingName</th> <th>title</th> <th>details</th> <th>dateEvent</th> <th>image</th> <th>dateStart</th> <th>dateEnd</th> </tr> </thead> <tbody></tbody> </table> <div id="title"></div> I have two questions really... Question 1: Does this code look like it is written correctly at first glance? Question 2: I want to be able to select only the title from the first event in the JSON array. The code i am using now is selecting the second events' title by default it seems. How can i accomplish this?

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  • How do I simplify this php script

    - by user225269
    Any suggestions on how I can simplify the php script below?This was my previous question: http://stackoverflow.com/questions/2712237/how-to-check-if-a-checkbox-radio-button-is-checked-in-php that is linked to this one, What I'm trying to do here is to output the data depending on the checkbox that is checked. But my code isn't really good, it shows 2 tables if the condition is met by the 2 results. As you can see in the code below, any suggestions on how I can simplify this? <?php $con = mysql_connect("localhost","root","nitoryolai123$%^"); if (!$con) { die('Could not connect: ' . mysql_error()); } mysql_select_db("school", $con); $id = mysql_real_escape_string($_POST['idnum']); if ( $_POST['yr'] == 'year' and $_POST['sec'] == 'section' ){ $result2 = mysql_query("SELECT * FROM student WHERE IDNO='$id'"); echo "<table border='1'> <tr> <th>IDNO</th> <th>YEAR</th> <th>SECTION</th> </tr>"; while($row = mysql_fetch_array($result2)) { echo "<tr>"; echo "<td>" . $row['IDNO'] . "</td>"; echo "<td>" . $row['YEAR'] . "</td>"; echo "<td>" . $row['SECTION'] . "</td>"; echo "</tr>"; } echo "</table>"; } if ( $_POST['yr'] == 'year' and $_POST['sec'] == 'section' and $_POST['lname'] == 'lastname'){ $result3 = mysql_query("SELECT * FROM student WHERE IDNO='$id'"); echo "<table border='1'> <tr> <th>IDNO</th> <th>YEAR</th> <th>SECTION</th> <th>LASTNAME</th> </tr>"; while($row = mysql_fetch_array($result3)) { echo "<tr>"; echo "<td>" . $row['IDNO'] . "</td>"; echo "<td>" . $row['YEAR'] . "</td>"; echo "<td>" . $row['SECTION'] . "</td>"; echo "<td>" . $row['LASTNAME'] . "</td>"; echo "</tr>"; } echo "</table>"; } mysql_close($con); ?>

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  • Android SDK PATH Error: doesn´t find home directory

    - by THeo Oliveira
    I use Ubuntu 12.10 and I tried to follow this guide Install android sdk and eclipse in Ubuntu 12.04 but I keep getting this error: Error: The AVD manager normally uses the user's profile directory to store AVD files. However it failed to find the default profile directory. To fix this, please set the environment variable ANDROID_SDK_HOME to a valid path such as ¨~¨. Any ideas how can I fix this?

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