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  • How to obtain a random sub-datatable from another data table

    - by developerit
    Introduction In this article, I’ll show how to get a random subset of data from a DataTable. This is useful when you already have queries that are filtered correctly but returns all the rows. Analysis I came across this situation when I wanted to display a random tag cloud. I already had the query to get the keywords ordered by number of clicks and I wanted to created a tag cloud. Tags that are the most popular should have more chance to get picked and should be displayed larger than less popular ones. Implementation In this code snippet, there is everything you need. ' Min size, in pixel for the tag Private Const MIN_FONT_SIZE As Integer = 9 ' Max size, in pixel for the tag Private Const MAX_FONT_SIZE As Integer = 14 ' Basic function that retreives Tags from a DataBase Public Shared Function GetTags() As MediasTagsDataTable ' Simple call to the TableAdapter, to get the Tags ordered by number of clicks Dim dt As MediasTagsDataTable = taMediasTags.GetDataValide ' If the query returned no result, return an empty DataTable If dt Is Nothing OrElse dt.Rows.Count < 1 Then Return New MediasTagsDataTable End If ' Set the font-size of the group of data ' We are dividing our results into sub set, according to their number of clicks ' Example: 10 results -> [0,2] will get font size 9, [3,5] will get font size 10, [6,8] wil get 11, ... ' This is the number of elements in one group Dim groupLenth As Integer = CType(Math.Floor(dt.Rows.Count / (MAX_FONT_SIZE - MIN_FONT_SIZE)), Integer) ' Counter of elements in the same group Dim counter As Integer = 0 ' Counter of groups Dim groupCounter As Integer = 0 ' Loop througt the list For Each row As MediasTagsRow In dt ' Set the font-size in a custom column row.c_FontSize = MIN_FONT_SIZE + groupCounter ' Increment the counter counter += 1 ' If the group counter is less than the counter If groupLenth <= counter Then ' Start a new group counter = 0 groupCounter += 1 End If Next ' Return the new DataTable with font-size Return dt End Function ' Function that generate the random sub set Public Shared Function GetRandomSampleTags(ByVal KeyCount As Integer) As MediasTagsDataTable ' Get the data Dim dt As MediasTagsDataTable = GetTags() ' Create a new DataTable that will contains the random set Dim rep As MediasTagsDataTable = New MediasTagsDataTable ' Count the number of row in the new DataTable Dim count As Integer = 0 ' Random number generator Dim rand As New Random() While count < KeyCount Randomize() ' Pick a random row Dim r As Integer = rand.Next(0, dt.Rows.Count - 1) Dim tmpRow As MediasTagsRow = dt(r) ' Import it into the new DataTable rep.ImportRow(tmpRow) ' Remove it from the old one, to be sure not to pick it again dt.Rows.RemoveAt(r) ' Increment the counter count += 1 End While ' Return the new sub set Return rep End Function Pro’s This method is good because it doesn’t require much work to get it work fast. It is a good concept when you are working with small tables, let says less than 100 records. Con’s If you have more than 100 records, out of memory exception may occur since we are coping and duplicating rows. I would consider using a stored procedure instead.

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  • Array sorting efficiency... Beginner need advice

    - by SoleSoft
    I'll start by saying I am very much a beginner programmer, this is essentially my first real project outside of using learning material. I've been making a 'Simon Says' style game (the game where you repeat the pattern generated by the computer) using C# and XNA, the actual game is complete and working fine but while creating it, I wanted to also create a 'top 10' scoreboard. The scoreboard would record player name, level (how many 'rounds' they've completed) and combo (how many buttons presses they got correct), the scoreboard would then be sorted by combo score. This led me to XML, the first time using it, and I eventually got to the point of having an XML file that recorded the top 10 scores. The XML file is managed within a scoreboard class, which is also responsible for adding new scores and sorting scores. Which gets me to the point... I'd like some feedback on the way I've gone about sorting the score list and how I could have done it better, I have no other way to gain feedback =(. I know .NET features Array.Sort() but I wasn't too sure of how to use it as it's not just a single array that needs to be sorted. When a new score needs to be entered into the scoreboard, the player name and level also have to be added. These are stored within an 'array of arrays' (10 = for 'top 10' scores) scoreboardComboData = new int[10]; // Combo scoreboardTextData = new string[2][]; scoreboardTextData[0] = new string[10]; // Name scoreboardTextData[1] = new string[10]; // Level as string The scoreboard class works as follows: - Checks to see if 'scoreboard.xml' exists, if not it creates it - Initialises above arrays and adds any player data from scoreboard.xml, from previous run - when AddScore(name, level, combo) is called the sort begins - Another method can also be called that populates the XML file with above array data The sort checks to see if the new score (combo) is less than or equal to any recorded scores within the scoreboardComboData array (if it's greater than a score, it moves onto the next element). If so, it moves all scores below the score it is less than or equal to down one element, essentially removing the last score and then places the new score within the element below the score it is less than or equal to. If the score is greater than all recorded scores, it moves all scores down one and inserts the new score within the first element. If it's the only score, it simply adds it to the first element. When a new score is added, the Name and Level data is also added to their relevant arrays, in the same way. What a tongue twister. Below is the AddScore method, I've added comments in the hope that it makes things clearer O_o. You can get the actual source file HERE. Below the method is an example of the quickest way to add a score to follow through with a debugger. public static void AddScore(string name, string level, int combo) { // If the scoreboard has not yet been filled, this adds another 'active' // array element each time a new score is added. The actual array size is // defined within PopulateScoreBoard() (set to 10 - for 'top 10' if (totalScores < scoreboardComboData.Length) totalScores++; // Does the scoreboard even need sorting? if (totalScores > 1) { for (int i = totalScores - 1; i > - 1; i--) { // Check to see if score (combo) is greater than score stored in // array if (combo > scoreboardComboData[i] && i != 0) { // If so continue to next element continue; } // Check to see if score (combo) is less or equal to element 'i' // score && that the element is not the last in the // array, if so the score does not need to be added to the scoreboard else if (combo <= scoreboardComboData[i] && i != scoreboardComboData.Length - 1) { // If the score is lower than element 'i' and greater than the last // element within the array, it needs to be added to the scoreboard. This is achieved // by moving each element under element 'i' down an element. The new score is then inserted // into the array under element 'i' for (int j = totalScores - 1; j > i; j--) { // Name and level data are moved down in their relevant arrays scoreboardTextData[0][j] = scoreboardTextData[0][j - 1]; scoreboardTextData[1][j] = scoreboardTextData[1][j - 1]; // Score (combo) data is moved down in relevant array scoreboardComboData[j] = scoreboardComboData[j - 1]; } // The new Name, level and score (combo) data is inserted into the relevant array under element 'i' scoreboardTextData[0][i + 1] = name; scoreboardTextData[1][i + 1] = level; scoreboardComboData[i + 1] = combo; break; } // If the method gets the this point, it means that the score is greater than all scores within // the array and therefore cannot be added in the above way. As it is not less than any score within // the array. else if (i == 0) { // All Names, levels and scores are moved down within their relevant arrays for (int j = totalScores - 1; j != 0; j--) { scoreboardTextData[0][j] = scoreboardTextData[0][j - 1]; scoreboardTextData[1][j] = scoreboardTextData[1][j - 1]; scoreboardComboData[j] = scoreboardComboData[j - 1]; } // The new number 1 top name, level and score, are added into the first element // within each of their relevant arrays. scoreboardTextData[0][0] = name; scoreboardTextData[1][0] = level; scoreboardComboData[0] = combo; break; } // If the methods get to this point, the combo score is not high enough // to be on the top10 score list and therefore needs to break break; } } // As totalScores < 1, the current score is the first to be added. Therefore no checks need to be made // and the Name, Level and combo data can be entered directly into the first element of their relevant // array. else { scoreboardTextData[0][0] = name; scoreboardTextData[1][0] = level; scoreboardComboData[0] = combo; } } } Example for adding score: private static void Initialize() { scoreboardDoc = new XmlDocument(); if (!File.Exists("Scoreboard.xml")) GenerateXML("Scoreboard.xml"); PopulateScoreBoard("Scoreboard.xml"); // ADD TEST SCORES HERE! AddScore("EXAMPLE", "10", 100); AddScore("EXAMPLE2", "24", 999); PopulateXML("Scoreboard.xml"); } In it's current state the source file is just used for testing, initialize is called within main and PopulateScoreBoard handles the majority of other initialising, so nothing else is needed, except to add a test score. I thank you for your time!

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  • Oracle Virtualization at Oracle OpenWorld 2012

    - by Chris Kawalek
    Mini-Series Entry 1 of 3: Hands-On Virtualization This is the first entry of a 3 part mini-series aimed at highlighting server and desktop virtualization at this year’s Oracle OpenWorld.  Oracle OpenWorld 2012 is fast approaching! If you are as excited as we are about the fascinating new Oracle virtualization content featured at Oracle OpenWorld 2012, you won’t want to miss this blog mini-series. We will be highlighting sessions that cover advances and innovations in our products, our product strategy and roadmap, and hands on labs for step-by-step instructions from our field and product experts. In the blog mini-series you will learn about: The Oracle Virtualization general keynote session Hands-on labs  Key Oracle server and desktop virtualization sessions In this entry, we will cover the Oracle Virtualization keynote session and the hands-on labs you won't want to miss. General Session: Oracle Virtualization Strategy and Roadmap Session ID: GEN8725 Oracle offers the industry’s most complete and integrated virtualization portfolio enabling organizations to realize benefits beyond simple consolidation as they transform their data centers into flexible cloud-based infrastructures. Join Oracle executives and experts to learn about Oracle’s desktop-to-data-center virtualization solutions, such as the OS, with built-in management integration at all layers that can help you virtualize and manage the complete computing environment, from physical servers to virtual servers and applications. This “don’t-miss” session offers details of the latest product updates and strategy; product roadmaps; integration with enterprise applications; and real-world examples of how Oracle server, desktop, and storage virtualization is benefiting customers. Here are our top picks for Hands-On Labs for Oracle OpenWorld 2012: Oracle Virtual Desktop Infrastructure Performance and Tablet Mobility Session ID: HOL9907 This hands-on lab demonstrates the performance (using an industry-standard load tester) and roaming capabilities of Oracle Virtual Desktop Infrastructure with Oracle’s Sun Ray Clients, Apple iPad and other clients. Deploying an IaaS Environment with Oracle VM: Hands-On Lab  Session ID: HOL9558 This hands-on lab takes you through the planning and deployment of an infrastructure as a service (IaaS) environment with Oracle VM as the foundation. It covers a range of topics, from planning storage capacity, LUN creation, network bandwidth planning, and best practices to designing and streamlining the environment for ease of management. Learn from deeply experienced field engineers and product experts. Virtualize and Deploy Oracle Applications in Minutes with Oracle VM: Hands-On Lab Session ID: HOL9559 This hands-on lab is for application architects or system administrators who will need to deploy and manage Oracle Applications. You’ll learn how Oracle VM Templates can turn you into a power user who can virtualize and deploy complex Oracle Applications in minutes. Longtime field-experienced engineers and product experts will show you, step by step, how to download and import templates and deploy the applications. x86 Enterprise Cloud Infrastructure with Oracle VM 3.x and Sun ZFS Storage Appliance Session ID: HOL9870 The purpose of this hands-on lab is to demonstrate the functionality and usage of Oracle’s enterprise cloud infrastructure for x86 with Oracle VM 3.x. It covers:  Creation of VMs Migration of VMs  Quick and easy deployment of Oracle applications with Oracle VM Templates  Usage of the Storage Connect plug-in for the Sun ZFS Storage Appliance You can find these and other great sessions on the Oracle OpenWorld 2012 Content Catalogue. Start checking now to better plan and organize your week at the conference. Then you’ll be ready to sign up for all of your sessions in mid-July when the scheduling tool goes live. While the hands-on labs allow you to directly interact with Oracle virtualization products, the conference sessions allow you to hear from a wide variety of industry experts on how they're using they technology in real world deployments, solving specific challenges, and more. In tomorrow's entry, we'll start talking about the many conference sessions related to Oracle server and desktop virtualization you can attend during the show. See you then! - The Oracle Virtualization marketing team

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  • How John Got 15x Improvement Without Really Trying

    - by rchrd
    The following article was published on a Sun Microsystems website a number of years ago by John Feo. It is still useful and worth preserving. So I'm republishing it here.  How I Got 15x Improvement Without Really Trying John Feo, Sun Microsystems Taking ten "personal" program codes used in scientific and engineering research, the author was able to get from 2 to 15 times performance improvement easily by applying some simple general optimization techniques. Introduction Scientific research based on computer simulation depends on the simulation for advancement. The research can advance only as fast as the computational codes can execute. The codes' efficiency determines both the rate and quality of results. In the same amount of time, a faster program can generate more results and can carry out a more detailed simulation of physical phenomena than a slower program. Highly optimized programs help science advance quickly and insure that monies supporting scientific research are used as effectively as possible. Scientific computer codes divide into three broad categories: ISV, community, and personal. ISV codes are large, mature production codes developed and sold commercially. The codes improve slowly over time both in methods and capabilities, and they are well tuned for most vendor platforms. Since the codes are mature and complex, there are few opportunities to improve their performance solely through code optimization. Improvements of 10% to 15% are typical. Examples of ISV codes are DYNA3D, Gaussian, and Nastran. Community codes are non-commercial production codes used by a particular research field. Generally, they are developed and distributed by a single academic or research institution with assistance from the community. Most users just run the codes, but some develop new methods and extensions that feed back into the general release. The codes are available on most vendor platforms. Since these codes are younger than ISV codes, there are more opportunities to optimize the source code. Improvements of 50% are not unusual. Examples of community codes are AMBER, CHARM, BLAST, and FASTA. Personal codes are those written by single users or small research groups for their own use. These codes are not distributed, but may be passed from professor-to-student or student-to-student over several years. They form the primordial ocean of applications from which community and ISV codes emerge. Government research grants pay for the development of most personal codes. This paper reports on the nature and performance of this class of codes. Over the last year, I have looked at over two dozen personal codes from more than a dozen research institutions. The codes cover a variety of scientific fields, including astronomy, atmospheric sciences, bioinformatics, biology, chemistry, geology, and physics. The sources range from a few hundred lines to more than ten thousand lines, and are written in Fortran, Fortran 90, C, and C++. For the most part, the codes are modular, documented, and written in a clear, straightforward manner. They do not use complex language features, advanced data structures, programming tricks, or libraries. I had little trouble understanding what the codes did or how data structures were used. Most came with a makefile. Surprisingly, only one of the applications is parallel. All developers have access to parallel machines, so availability is not an issue. Several tried to parallelize their applications, but stopped after encountering difficulties. Lack of education and a perception that parallelism is difficult prevented most from trying. I parallelized several of the codes using OpenMP, and did not judge any of the codes as difficult to parallelize. Even more surprising than the lack of parallelism is the inefficiency of the codes. I was able to get large improvements in performance in a matter of a few days applying simple optimization techniques. Table 1 lists ten representative codes [names and affiliation are omitted to preserve anonymity]. Improvements on one processor range from 2x to 15.5x with a simple average of 4.75x. I did not use sophisticated performance tools or drill deep into the program's execution character as one would do when tuning ISV or community codes. Using only a profiler and source line timers, I identified inefficient sections of code and improved their performance by inspection. The changes were at a high level. I am sure there is another factor of 2 or 3 in each code, and more if the codes are parallelized. The study’s results show that personal scientific codes are running many times slower than they should and that the problem is pervasive. Computational scientists are not sloppy programmers; however, few are trained in the art of computer programming or code optimization. I found that most have a working knowledge of some programming language and standard software engineering practices; but they do not know, or think about, how to make their programs run faster. They simply do not know the standard techniques used to make codes run faster. In fact, they do not even perceive that such techniques exist. The case studies described in this paper show that applying simple, well known techniques can significantly increase the performance of personal codes. It is important that the scientific community and the Government agencies that support scientific research find ways to better educate academic scientific programmers. The inefficiency of their codes is so bad that it is retarding both the quality and progress of scientific research. # cacheperformance redundantoperations loopstructures performanceimprovement 1 x x 15.5 2 x 2.8 3 x x 2.5 4 x 2.1 5 x x 2.0 6 x 5.0 7 x 5.8 8 x 6.3 9 2.2 10 x x 3.3 Table 1 — Area of improvement and performance gains of 10 codes The remainder of the paper is organized as follows: sections 2, 3, and 4 discuss the three most common sources of inefficiencies in the codes studied. These are cache performance, redundant operations, and loop structures. Each section includes several examples. The last section summaries the work and suggests a possible solution to the issues raised. Optimizing cache performance Commodity microprocessor systems use caches to increase memory bandwidth and reduce memory latencies. Typical latencies from processor to L1, L2, local, and remote memory are 3, 10, 50, and 200 cycles, respectively. Moreover, bandwidth falls off dramatically as memory distances increase. Programs that do not use cache effectively run many times slower than programs that do. When optimizing for cache, the biggest performance gains are achieved by accessing data in cache order and reusing data to amortize the overhead of cache misses. Secondary considerations are prefetching, associativity, and replacement; however, the understanding and analysis required to optimize for the latter are probably beyond the capabilities of the non-expert. Much can be gained simply by accessing data in the correct order and maximizing data reuse. 6 out of the 10 codes studied here benefited from such high level optimizations. Array Accesses The most important cache optimization is the most basic: accessing Fortran array elements in column order and C array elements in row order. Four of the ten codes—1, 2, 4, and 10—got it wrong. Compilers will restructure nested loops to optimize cache performance, but may not do so if the loop structure is too complex, or the loop body includes conditionals, complex addressing, or function calls. In code 1, the compiler failed to invert a key loop because of complex addressing do I = 0, 1010, delta_x IM = I - delta_x IP = I + delta_x do J = 5, 995, delta_x JM = J - delta_x JP = J + delta_x T1 = CA1(IP, J) + CA1(I, JP) T2 = CA1(IM, J) + CA1(I, JM) S1 = T1 + T2 - 4 * CA1(I, J) CA(I, J) = CA1(I, J) + D * S1 end do end do In code 2, the culprit is conditionals do I = 1, N do J = 1, N If (IFLAG(I,J) .EQ. 0) then T1 = Value(I, J-1) T2 = Value(I-1, J) T3 = Value(I, J) T4 = Value(I+1, J) T5 = Value(I, J+1) Value(I,J) = 0.25 * (T1 + T2 + T5 + T4) Delta = ABS(T3 - Value(I,J)) If (Delta .GT. MaxDelta) MaxDelta = Delta endif enddo enddo I fixed both programs by inverting the loops by hand. Code 10 has three-dimensional arrays and triply nested loops. The structure of the most computationally intensive loops is too complex to invert automatically or by hand. The only practical solution is to transpose the arrays so that the dimension accessed by the innermost loop is in cache order. The arrays can be transposed at construction or prior to entering a computationally intensive section of code. The former requires all array references to be modified, while the latter is cost effective only if the cost of the transpose is amortized over many accesses. I used the second approach to optimize code 10. Code 5 has four-dimensional arrays and loops are nested four deep. For all of the reasons cited above the compiler is not able to restructure three key loops. Assume C arrays and let the four dimensions of the arrays be i, j, k, and l. In the original code, the index structure of the three loops is L1: for i L2: for i L3: for i for l for l for j for k for j for k for j for k for l So only L3 accesses array elements in cache order. L1 is a very complex loop—much too complex to invert. I brought the loop into cache alignment by transposing the second and fourth dimensions of the arrays. Since the code uses a macro to compute all array indexes, I effected the transpose at construction and changed the macro appropriately. The dimensions of the new arrays are now: i, l, k, and j. L3 is a simple loop and easily inverted. L2 has a loop-carried scalar dependence in k. By promoting the scalar name that carries the dependence to an array, I was able to invert the third and fourth subloops aligning the loop with cache. Code 5 is by far the most difficult of the four codes to optimize for array accesses; but the knowledge required to fix the problems is no more than that required for the other codes. I would judge this code at the limits of, but not beyond, the capabilities of appropriately trained computational scientists. Array Strides When a cache miss occurs, a line (64 bytes) rather than just one word is loaded into the cache. If data is accessed stride 1, than the cost of the miss is amortized over 8 words. Any stride other than one reduces the cost savings. Two of the ten codes studied suffered from non-unit strides. The codes represent two important classes of "strided" codes. Code 1 employs a multi-grid algorithm to reduce time to convergence. The grids are every tenth, fifth, second, and unit element. Since time to convergence is inversely proportional to the distance between elements, coarse grids converge quickly providing good starting values for finer grids. The better starting values further reduce the time to convergence. The downside is that grids of every nth element, n > 1, introduce non-unit strides into the computation. In the original code, much of the savings of the multi-grid algorithm were lost due to this problem. I eliminated the problem by compressing (copying) coarse grids into continuous memory, and rewriting the computation as a function of the compressed grid. On convergence, I copied the final values of the compressed grid back to the original grid. The savings gained from unit stride access of the compressed grid more than paid for the cost of copying. Using compressed grids, the loop from code 1 included in the previous section becomes do j = 1, GZ do i = 1, GZ T1 = CA(i+0, j-1) + CA(i-1, j+0) T4 = CA1(i+1, j+0) + CA1(i+0, j+1) S1 = T1 + T4 - 4 * CA1(i+0, j+0) CA(i+0, j+0) = CA1(i+0, j+0) + DD * S1 enddo enddo where CA and CA1 are compressed arrays of size GZ. Code 7 traverses a list of objects selecting objects for later processing. The labels of the selected objects are stored in an array. The selection step has unit stride, but the processing steps have irregular stride. A fix is to save the parameters of the selected objects in temporary arrays as they are selected, and pass the temporary arrays to the processing functions. The fix is practical if the same parameters are used in selection as in processing, or if processing comprises a series of distinct steps which use overlapping subsets of the parameters. Both conditions are true for code 7, so I achieved significant improvement by copying parameters to temporary arrays during selection. Data reuse In the previous sections, we optimized for spatial locality. It is also important to optimize for temporal locality. Once read, a datum should be used as much as possible before it is forced from cache. Loop fusion and loop unrolling are two techniques that increase temporal locality. Unfortunately, both techniques increase register pressure—as loop bodies become larger, the number of registers required to hold temporary values grows. Once register spilling occurs, any gains evaporate quickly. For multiprocessors with small register sets or small caches, the sweet spot can be very small. In the ten codes presented here, I found no opportunities for loop fusion and only two opportunities for loop unrolling (codes 1 and 3). In code 1, unrolling the outer and inner loop one iteration increases the number of result values computed by the loop body from 1 to 4, do J = 1, GZ-2, 2 do I = 1, GZ-2, 2 T1 = CA1(i+0, j-1) + CA1(i-1, j+0) T2 = CA1(i+1, j-1) + CA1(i+0, j+0) T3 = CA1(i+0, j+0) + CA1(i-1, j+1) T4 = CA1(i+1, j+0) + CA1(i+0, j+1) T5 = CA1(i+2, j+0) + CA1(i+1, j+1) T6 = CA1(i+1, j+1) + CA1(i+0, j+2) T7 = CA1(i+2, j+1) + CA1(i+1, j+2) S1 = T1 + T4 - 4 * CA1(i+0, j+0) S2 = T2 + T5 - 4 * CA1(i+1, j+0) S3 = T3 + T6 - 4 * CA1(i+0, j+1) S4 = T4 + T7 - 4 * CA1(i+1, j+1) CA(i+0, j+0) = CA1(i+0, j+0) + DD * S1 CA(i+1, j+0) = CA1(i+1, j+0) + DD * S2 CA(i+0, j+1) = CA1(i+0, j+1) + DD * S3 CA(i+1, j+1) = CA1(i+1, j+1) + DD * S4 enddo enddo The loop body executes 12 reads, whereas as the rolled loop shown in the previous section executes 20 reads to compute the same four values. In code 3, two loops are unrolled 8 times and one loop is unrolled 4 times. Here is the before for (k = 0; k < NK[u]; k++) { sum = 0.0; for (y = 0; y < NY; y++) { sum += W[y][u][k] * delta[y]; } backprop[i++]=sum; } and after code for (k = 0; k < KK - 8; k+=8) { sum0 = 0.0; sum1 = 0.0; sum2 = 0.0; sum3 = 0.0; sum4 = 0.0; sum5 = 0.0; sum6 = 0.0; sum7 = 0.0; for (y = 0; y < NY; y++) { sum0 += W[y][0][k+0] * delta[y]; sum1 += W[y][0][k+1] * delta[y]; sum2 += W[y][0][k+2] * delta[y]; sum3 += W[y][0][k+3] * delta[y]; sum4 += W[y][0][k+4] * delta[y]; sum5 += W[y][0][k+5] * delta[y]; sum6 += W[y][0][k+6] * delta[y]; sum7 += W[y][0][k+7] * delta[y]; } backprop[k+0] = sum0; backprop[k+1] = sum1; backprop[k+2] = sum2; backprop[k+3] = sum3; backprop[k+4] = sum4; backprop[k+5] = sum5; backprop[k+6] = sum6; backprop[k+7] = sum7; } for one of the loops unrolled 8 times. Optimizing for temporal locality is the most difficult optimization considered in this paper. The concepts are not difficult, but the sweet spot is small. Identifying where the program can benefit from loop unrolling or loop fusion is not trivial. Moreover, it takes some effort to get it right. Still, educating scientific programmers about temporal locality and teaching them how to optimize for it will pay dividends. Reducing instruction count Execution time is a function of instruction count. Reduce the count and you usually reduce the time. The best solution is to use a more efficient algorithm; that is, an algorithm whose order of complexity is smaller, that converges quicker, or is more accurate. Optimizing source code without changing the algorithm yields smaller, but still significant, gains. This paper considers only the latter because the intent is to study how much better codes can run if written by programmers schooled in basic code optimization techniques. The ten codes studied benefited from three types of "instruction reducing" optimizations. The two most prevalent were hoisting invariant memory and data operations out of inner loops. The third was eliminating unnecessary data copying. The nature of these inefficiencies is language dependent. Memory operations The semantics of C make it difficult for the compiler to determine all the invariant memory operations in a loop. The problem is particularly acute for loops in functions since the compiler may not know the values of the function's parameters at every call site when compiling the function. Most compilers support pragmas to help resolve ambiguities; however, these pragmas are not comprehensive and there is no standard syntax. To guarantee that invariant memory operations are not executed repetitively, the user has little choice but to hoist the operations by hand. The problem is not as severe in Fortran programs because in the absence of equivalence statements, it is a violation of the language's semantics for two names to share memory. Codes 3 and 5 are C programs. In both cases, the compiler did not hoist all invariant memory operations from inner loops. Consider the following loop from code 3 for (y = 0; y < NY; y++) { i = 0; for (u = 0; u < NU; u++) { for (k = 0; k < NK[u]; k++) { dW[y][u][k] += delta[y] * I1[i++]; } } } Since dW[y][u] can point to the same memory space as delta for one or more values of y and u, assignment to dW[y][u][k] may change the value of delta[y]. In reality, dW and delta do not overlap in memory, so I rewrote the loop as for (y = 0; y < NY; y++) { i = 0; Dy = delta[y]; for (u = 0; u < NU; u++) { for (k = 0; k < NK[u]; k++) { dW[y][u][k] += Dy * I1[i++]; } } } Failure to hoist invariant memory operations may be due to complex address calculations. If the compiler can not determine that the address calculation is invariant, then it can hoist neither the calculation nor the associated memory operations. As noted above, code 5 uses a macro to address four-dimensional arrays #define MAT4D(a,q,i,j,k) (double *)((a)->data + (q)*(a)->strides[0] + (i)*(a)->strides[3] + (j)*(a)->strides[2] + (k)*(a)->strides[1]) The macro is too complex for the compiler to understand and so, it does not identify any subexpressions as loop invariant. The simplest way to eliminate the address calculation from the innermost loop (over i) is to define a0 = MAT4D(a,q,0,j,k) before the loop and then replace all instances of *MAT4D(a,q,i,j,k) in the loop with a0[i] A similar problem appears in code 6, a Fortran program. The key loop in this program is do n1 = 1, nh nx1 = (n1 - 1) / nz + 1 nz1 = n1 - nz * (nx1 - 1) do n2 = 1, nh nx2 = (n2 - 1) / nz + 1 nz2 = n2 - nz * (nx2 - 1) ndx = nx2 - nx1 ndy = nz2 - nz1 gxx = grn(1,ndx,ndy) gyy = grn(2,ndx,ndy) gxy = grn(3,ndx,ndy) balance(n1,1) = balance(n1,1) + (force(n2,1) * gxx + force(n2,2) * gxy) * h1 balance(n1,2) = balance(n1,2) + (force(n2,1) * gxy + force(n2,2) * gyy)*h1 end do end do The programmer has written this loop well—there are no loop invariant operations with respect to n1 and n2. However, the loop resides within an iterative loop over time and the index calculations are independent with respect to time. Trading space for time, I precomputed the index values prior to the entering the time loop and stored the values in two arrays. I then replaced the index calculations with reads of the arrays. Data operations Ways to reduce data operations can appear in many forms. Implementing a more efficient algorithm produces the biggest gains. The closest I came to an algorithm change was in code 4. This code computes the inner product of K-vectors A(i) and B(j), 0 = i < N, 0 = j < M, for most values of i and j. Since the program computes most of the NM possible inner products, it is more efficient to compute all the inner products in one triply-nested loop rather than one at a time when needed. The savings accrue from reading A(i) once for all B(j) vectors and from loop unrolling. for (i = 0; i < N; i+=8) { for (j = 0; j < M; j++) { sum0 = 0.0; sum1 = 0.0; sum2 = 0.0; sum3 = 0.0; sum4 = 0.0; sum5 = 0.0; sum6 = 0.0; sum7 = 0.0; for (k = 0; k < K; k++) { sum0 += A[i+0][k] * B[j][k]; sum1 += A[i+1][k] * B[j][k]; sum2 += A[i+2][k] * B[j][k]; sum3 += A[i+3][k] * B[j][k]; sum4 += A[i+4][k] * B[j][k]; sum5 += A[i+5][k] * B[j][k]; sum6 += A[i+6][k] * B[j][k]; sum7 += A[i+7][k] * B[j][k]; } C[i+0][j] = sum0; C[i+1][j] = sum1; C[i+2][j] = sum2; C[i+3][j] = sum3; C[i+4][j] = sum4; C[i+5][j] = sum5; C[i+6][j] = sum6; C[i+7][j] = sum7; }} This change requires knowledge of a typical run; i.e., that most inner products are computed. The reasons for the change, however, derive from basic optimization concepts. It is the type of change easily made at development time by a knowledgeable programmer. In code 5, we have the data version of the index optimization in code 6. Here a very expensive computation is a function of the loop indices and so cannot be hoisted out of the loop; however, the computation is invariant with respect to an outer iterative loop over time. We can compute its value for each iteration of the computation loop prior to entering the time loop and save the values in an array. The increase in memory required to store the values is small in comparison to the large savings in time. The main loop in Code 8 is doubly nested. The inner loop includes a series of guarded computations; some are a function of the inner loop index but not the outer loop index while others are a function of the outer loop index but not the inner loop index for (j = 0; j < N; j++) { for (i = 0; i < M; i++) { r = i * hrmax; R = A[j]; temp = (PRM[3] == 0.0) ? 1.0 : pow(r, PRM[3]); high = temp * kcoeff * B[j] * PRM[2] * PRM[4]; low = high * PRM[6] * PRM[6] / (1.0 + pow(PRM[4] * PRM[6], 2.0)); kap = (R > PRM[6]) ? high * R * R / (1.0 + pow(PRM[4]*r, 2.0) : low * pow(R/PRM[6], PRM[5]); < rest of loop omitted > }} Note that the value of temp is invariant to j. Thus, we can hoist the computation for temp out of the loop and save its values in an array. for (i = 0; i < M; i++) { r = i * hrmax; TEMP[i] = pow(r, PRM[3]); } [N.B. – the case for PRM[3] = 0 is omitted and will be reintroduced later.] We now hoist out of the inner loop the computations invariant to i. Since the conditional guarding the value of kap is invariant to i, it behooves us to hoist the computation out of the inner loop, thereby executing the guard once rather than M times. The final version of the code is for (j = 0; j < N; j++) { R = rig[j] / 1000.; tmp1 = kcoeff * par[2] * beta[j] * par[4]; tmp2 = 1.0 + (par[4] * par[4] * par[6] * par[6]); tmp3 = 1.0 + (par[4] * par[4] * R * R); tmp4 = par[6] * par[6] / tmp2; tmp5 = R * R / tmp3; tmp6 = pow(R / par[6], par[5]); if ((par[3] == 0.0) && (R > par[6])) { for (i = 1; i <= imax1; i++) KAP[i] = tmp1 * tmp5; } else if ((par[3] == 0.0) && (R <= par[6])) { for (i = 1; i <= imax1; i++) KAP[i] = tmp1 * tmp4 * tmp6; } else if ((par[3] != 0.0) && (R > par[6])) { for (i = 1; i <= imax1; i++) KAP[i] = tmp1 * TEMP[i] * tmp5; } else if ((par[3] != 0.0) && (R <= par[6])) { for (i = 1; i <= imax1; i++) KAP[i] = tmp1 * TEMP[i] * tmp4 * tmp6; } for (i = 0; i < M; i++) { kap = KAP[i]; r = i * hrmax; < rest of loop omitted > } } Maybe not the prettiest piece of code, but certainly much more efficient than the original loop, Copy operations Several programs unnecessarily copy data from one data structure to another. This problem occurs in both Fortran and C programs, although it manifests itself differently in the two languages. Code 1 declares two arrays—one for old values and one for new values. At the end of each iteration, the array of new values is copied to the array of old values to reset the data structures for the next iteration. This problem occurs in Fortran programs not included in this study and in both Fortran 77 and Fortran 90 code. Introducing pointers to the arrays and swapping pointer values is an obvious way to eliminate the copying; but pointers is not a feature that many Fortran programmers know well or are comfortable using. An easy solution not involving pointers is to extend the dimension of the value array by 1 and use the last dimension to differentiate between arrays at different times. For example, if the data space is N x N, declare the array (N, N, 2). Then store the problem’s initial values in (_, _, 2) and define the scalar names new = 2 and old = 1. At the start of each iteration, swap old and new to reset the arrays. The old–new copy problem did not appear in any C program. In programs that had new and old values, the code swapped pointers to reset data structures. Where unnecessary coping did occur is in structure assignment and parameter passing. Structures in C are handled much like scalars. Assignment causes the data space of the right-hand name to be copied to the data space of the left-hand name. Similarly, when a structure is passed to a function, the data space of the actual parameter is copied to the data space of the formal parameter. If the structure is large and the assignment or function call is in an inner loop, then copying costs can grow quite large. While none of the ten programs considered here manifested this problem, it did occur in programs not included in the study. A simple fix is always to refer to structures via pointers. Optimizing loop structures Since scientific programs spend almost all their time in loops, efficient loops are the key to good performance. Conditionals, function calls, little instruction level parallelism, and large numbers of temporary values make it difficult for the compiler to generate tightly packed, highly efficient code. Conditionals and function calls introduce jumps that disrupt code flow. Users should eliminate or isolate conditionls to their own loops as much as possible. Often logical expressions can be substituted for if-then-else statements. For example, code 2 includes the following snippet MaxDelta = 0.0 do J = 1, N do I = 1, M < code omitted > Delta = abs(OldValue ? NewValue) if (Delta > MaxDelta) MaxDelta = Delta enddo enddo if (MaxDelta .gt. 0.001) goto 200 Since the only use of MaxDelta is to control the jump to 200 and all that matters is whether or not it is greater than 0.001, I made MaxDelta a boolean and rewrote the snippet as MaxDelta = .false. do J = 1, N do I = 1, M < code omitted > Delta = abs(OldValue ? NewValue) MaxDelta = MaxDelta .or. (Delta .gt. 0.001) enddo enddo if (MaxDelta) goto 200 thereby, eliminating the conditional expression from the inner loop. A microprocessor can execute many instructions per instruction cycle. Typically, it can execute one or more memory, floating point, integer, and jump operations. To be executed simultaneously, the operations must be independent. Thick loops tend to have more instruction level parallelism than thin loops. Moreover, they reduce memory traffice by maximizing data reuse. Loop unrolling and loop fusion are two techniques to increase the size of loop bodies. Several of the codes studied benefitted from loop unrolling, but none benefitted from loop fusion. This observation is not too surpising since it is the general tendency of programmers to write thick loops. As loops become thicker, the number of temporary values grows, increasing register pressure. If registers spill, then memory traffic increases and code flow is disrupted. A thick loop with many temporary values may execute slower than an equivalent series of thin loops. The biggest gain will be achieved if the thick loop can be split into a series of independent loops eliminating the need to write and read temporary arrays. I found such an occasion in code 10 where I split the loop do i = 1, n do j = 1, m A24(j,i)= S24(j,i) * T24(j,i) + S25(j,i) * U25(j,i) B24(j,i)= S24(j,i) * T25(j,i) + S25(j,i) * U24(j,i) A25(j,i)= S24(j,i) * C24(j,i) + S25(j,i) * V24(j,i) B25(j,i)= S24(j,i) * U25(j,i) + S25(j,i) * V25(j,i) C24(j,i)= S26(j,i) * T26(j,i) + S27(j,i) * U26(j,i) D24(j,i)= S26(j,i) * T27(j,i) + S27(j,i) * V26(j,i) C25(j,i)= S27(j,i) * S28(j,i) + S26(j,i) * U28(j,i) D25(j,i)= S27(j,i) * T28(j,i) + S26(j,i) * V28(j,i) end do end do into two disjoint loops do i = 1, n do j = 1, m A24(j,i)= S24(j,i) * T24(j,i) + S25(j,i) * U25(j,i) B24(j,i)= S24(j,i) * T25(j,i) + S25(j,i) * U24(j,i) A25(j,i)= S24(j,i) * C24(j,i) + S25(j,i) * V24(j,i) B25(j,i)= S24(j,i) * U25(j,i) + S25(j,i) * V25(j,i) end do end do do i = 1, n do j = 1, m C24(j,i)= S26(j,i) * T26(j,i) + S27(j,i) * U26(j,i) D24(j,i)= S26(j,i) * T27(j,i) + S27(j,i) * V26(j,i) C25(j,i)= S27(j,i) * S28(j,i) + S26(j,i) * U28(j,i) D25(j,i)= S27(j,i) * T28(j,i) + S26(j,i) * V28(j,i) end do end do Conclusions Over the course of the last year, I have had the opportunity to work with over two dozen academic scientific programmers at leading research universities. Their research interests span a broad range of scientific fields. Except for two programs that relied almost exclusively on library routines (matrix multiply and fast Fourier transform), I was able to improve significantly the single processor performance of all codes. Improvements range from 2x to 15.5x with a simple average of 4.75x. Changes to the source code were at a very high level. I did not use sophisticated techniques or programming tools to discover inefficiencies or effect the changes. Only one code was parallel despite the availability of parallel systems to all developers. Clearly, we have a problem—personal scientific research codes are highly inefficient and not running parallel. The developers are unaware of simple optimization techniques to make programs run faster. They lack education in the art of code optimization and parallel programming. I do not believe we can fix the problem by publishing additional books or training manuals. To date, the developers in questions have not studied the books or manual available, and are unlikely to do so in the future. Short courses are a possible solution, but I believe they are too concentrated to be much use. The general concepts can be taught in a three or four day course, but that is not enough time for students to practice what they learn and acquire the experience to apply and extend the concepts to their codes. Practice is the key to becoming proficient at optimization. I recommend that graduate students be required to take a semester length course in optimization and parallel programming. We would never give someone access to state-of-the-art scientific equipment costing hundreds of thousands of dollars without first requiring them to demonstrate that they know how to use the equipment. Yet the criterion for time on state-of-the-art supercomputers is at most an interesting project. Requestors are never asked to demonstrate that they know how to use the system, or can use the system effectively. A semester course would teach them the required skills. Government agencies that fund academic scientific research pay for most of the computer systems supporting scientific research as well as the development of most personal scientific codes. These agencies should require graduate schools to offer a course in optimization and parallel programming as a requirement for funding. About the Author John Feo received his Ph.D. in Computer Science from The University of Texas at Austin in 1986. After graduate school, Dr. Feo worked at Lawrence Livermore National Laboratory where he was the Group Leader of the Computer Research Group and principal investigator of the Sisal Language Project. In 1997, Dr. Feo joined Tera Computer Company where he was project manager for the MTA, and oversaw the programming and evaluation of the MTA at the San Diego Supercomputer Center. In 2000, Dr. Feo joined Sun Microsystems as an HPC application specialist. He works with university research groups to optimize and parallelize scientific codes. Dr. Feo has published over two dozen research articles in the areas of parallel parallel programming, parallel programming languages, and application performance.

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  • Calculix Data Visualiser using QT

    - by Ann
    I am doing a project on CalculiX data visualizor,using Qt.I 've to draw the structure and after giving force the displacement should be shawn as variation in color.I chose HSV coloring,but while executing I got an error message:"QColor::from Hsv:HSV parameters out of range".The code is: DataViz1::DataViz1(QWidget *parent) : QWidget(parent), ui(new Ui::DataViz1) { DArea = new QGLScreen(this); DArea-setGeometry(QRect(10,10,700,600)); //TODO This values are feeded by user dfile="/home/41407/color.txt";//input file with displacement mfile="/home/41407/mesh21.txt";//input file nodeId="*NODE"; elId="*ELEMENT"; DataId="displ"; parseMfile(); parseDfile(); DArea->Nodes=Nodes; DArea->Elements=Elements; DArea->Data=Data; DArea->fillColorArray(); //printf("Colr is %d",DArea->pickColor(-11.02,0));fflush(stdout); ui->setupUi(this); } DataViz1::~DataViz1() { delete ui; } void DataViz1::parseMfile() { QFile file(mfile); if (!file.open(QIODevice::ReadOnly | QIODevice::Text)) return; int node_end=0; QTextStream in(&file); in.skipWhiteSpace(); while (!in.atEnd()) { QString line = in.readLine(); if(line.startsWith(nodeId))//Node block in Mfile { while(1) { line = in.readLine(); if(line.startsWith(elId)) { break; } Nodes< while(1) { line = in.readLine(); Elements<<line; //printf("Element is %s\n",line.toLocal8Bit().constData());fflush(stdout); if(in.atEnd()) break; } } } } void DataViz1::parseDfile() { QFile file(dfile); if (!file.open(QIODevice::ReadOnly | QIODevice::Text)) return; int node_end=0; QTextStream in(&file); in.skipWhiteSpace(); while (!in.atEnd()) { QString line = in.readLine(); if(line.startsWith(DataId)) { continue; } line = in.readLine(); Data< } /......................................................................../ include "qglscreen.h" include GLfloat LightAmbient[]= { 0.5f, 0.5f, 0.5f, 1.0f }; GLfloat LightDiffuse[]= { 1.0f, 1.0f, 1.0f, 1.0f }; GLfloat LightPosition[]= { 0.0f, 0.0f, 2.0f, 1.0f }; QGLScreen::QGLScreen(QWidget *parent):QGLWidget(QGLFormat(QGL::SampleBuffers), parent) { clearColor = Qt::black; xRot = 0; yRot = 0; zRot = 0; ifdef QT_OPENGL_ES_2 program = 0; endif //TODO user input ElType="HE8"; DType="SolidFrame"; axis="X"; } QGLScreen::~QGLScreen() { } QSize QGLScreen::minimumSizeHint() const { return QSize(50, 50); } QSize QGLScreen::sizeHint() const { return QSize(200, 200); } void QGLScreen::setClearColor(const QColor &color) { clearColor = color; updateGL(); } void QGLScreen::initializeGL() { xRot=0; yRot=0; zRot=0; scaling = 1.0; /* select clearing (background) color */ glClearColor (0.0, 0.0, 0.0, 0.0); glMatrixMode(GL_PROJECTION); glLoadIdentity(); // glViewport(0,0,10,10); glOrtho(-10.0, +10.0, -10.0, +10.0, -10.0,+10.0); glEnable (GL_LINE_SMOOTH); glHint (GL_LINE_SMOOTH_HINT, GL_DONT_CARE); } void QGLScreen::wheel1() { scaling1 += .0025; count2++; update(); } void QGLScreen::wheel2() { if(count2-14) { scaling1 -= .0025; count2--; update(); } } void QGLScreen::drawModel(int x1,int y1,int x2,int y2) { makeCurrent(); QStringList Cnode,Celement; for (int i = 0; i < Elements.size(); ++i) { Celement=Elements.at(i).split(","); // printf("Element is %s",Celement.at(0).toLocal8Bit().constData());fflush(stdout); //printf("Node at el is %s\n",(findNode(Celement.at(1).toInt())).at(1).toLocal8Bit().constData()); fflush(stdout); if(ElType=="HE8") { //First four nodes float ENX1=(findNode(Celement.at(1).toInt())).at(1).toDouble(); float ENX2=(findNode(Celement.at(2).toInt())).at(1).toDouble(); float ENX3=(findNode(Celement.at(3).toInt())).at(1).toDouble(); float ENX4=(findNode(Celement.at(4).toInt())).at(1).toDouble(); float ENY1=(findNode(Celement.at(1).toInt())).at(2).toDouble(); float ENY2=(findNode(Celement.at(2).toInt())).at(2).toDouble(); float ENY3=(findNode(Celement.at(3).toInt())).at(2).toDouble(); float ENY4=(findNode(Celement.at(4).toInt())).at(2).toDouble(); float ENZ1=(findNode(Celement.at(1).toInt())).at(3).toDouble(); float ENZ2=(findNode(Celement.at(2).toInt())).at(3).toDouble(); float ENZ3=(findNode(Celement.at(3).toInt())).at(3).toDouble(); float ENZ4=(findNode(Celement.at(4).toInt())).at(3).toDouble(); //Second four Nodes float ENX5=(findNode(Celement.at(5).toInt())).at(1).toDouble(); float ENX6=(findNode(Celement.at(6).toInt())).at(1).toDouble(); float ENX7=(findNode(Celement.at(7).toInt())).at(1).toDouble(); float ENX8=(findNode(Celement.at(8).toInt())).at(1).toDouble(); float ENY5=(findNode(Celement.at(5).toInt())).at(2).toDouble(); float ENY6=(findNode(Celement.at(6).toInt())).at(2).toDouble(); float ENY7=(findNode(Celement.at(7).toInt())).at(2).toDouble(); float ENY8=(findNode(Celement.at(8).toInt())).at(2).toDouble(); float ENZ5=(findNode(Celement.at(5).toInt())).at(3).toDouble(); float ENZ6=(findNode(Celement.at(6).toInt())).at(3).toDouble(); float ENZ7=(findNode(Celement.at(7).toInt())).at(3).toDouble(); float ENZ8=(findNode(Celement.at(8).toInt())).at(3).toDouble(); //Identify Colors GLfloat ENC[8][3]; for(int k=1;k<8;k++) { int hsv=pickColor(findData(Celement.at(k).toInt()).toDouble(),0); //printf("hsv is %d=",hsv);fflush(stdout); getRGB(hsv); //printf("%d*%d*%d\n",red,green,blue); //ENC[k]={red,green,blue}; ENC[k][0]=red; ENC[k][1]=green; ENC[k][2]=blue; } //Plot the first four direct loop if(DType=="WireFrame"){ glBegin(GL_LINE_LOOP); glColor3f(255,0,0); glVertex3f(ENX1,ENY1,ENZ1); glColor3f(255,0,0); glVertex3f(ENX2,ENY2,ENZ2); glColor3f(255,0,0); glVertex3f(ENX3,ENY3,ENZ3); glColor3f(255,0,0); glVertex3f(ENX4,ENY4,ENZ4); glEnd(); //Plot the second four direct loop glBegin(GL_LINE_LOOP); glColor3f(0,0,255); glVertex3f(ENX5,ENY5,ENZ5); glColor3f(0,0,255); glVertex3f(ENX6,ENY6,ENZ6); glColor3f(0,0,255); glVertex3f(ENX7,ENY7,ENZ7); glColor3f(0,0,255); glVertex3f(ENX8,ENY8,ENZ8); glEnd(); //Plot the interconnections glBegin(GL_LINE); glColor3f(150,150,150); glVertex3f(ENX1,ENY1,ENZ1); glVertex3f(ENX5,ENY5,ENZ5); glEnd(); glBegin(GL_LINE); glColor3f(150,150,150); glVertex3f(ENX2,ENY2,ENZ2); glVertex3f(ENX6,ENY6,ENZ6); glEnd(); glBegin(GL_LINE); glColor3f(150,150,150); glVertex3f(ENX3,ENY3,ENZ3); glVertex3f(ENX7,ENY7,ENZ7); glEnd(); glBegin(GL_LINE); glColor3f(150,150,150); glVertex3f(ENX4,ENY4,ENZ4); glVertex3f(ENX8,ENY8,ENZ8); glEnd(); } if(DType=="SolidFrame") { glBegin(GL_QUADS); glColor3fv(ENC[1]); glVertex3f(ENX1,ENY1,ENZ1); glColor3fv(ENC[2]); glVertex3f(ENX2,ENY2,ENZ2); glColor3fv(ENC[3]); glVertex3f(ENX3,ENY3,ENZ3); glColor3fv(ENC[4]); glVertex3f(ENX4,ENY4,ENZ4); glEnd(); //break; glBegin(GL_QUADS); glColor3fv(ENC[5]); glVertex3f(ENX5,ENY5,ENZ5); glColor3fv(ENC[6]); glVertex3f(ENX6,ENY6,ENZ6); glColor3fv(ENC[7]); glVertex3f(ENX7,ENY7,ENZ7); glColor3fv(ENC[8]); glVertex3f(ENX8,ENY8,ENZ8); glEnd(); glBegin(GL_QUAD_STRIP); glColor3fv(ENC[1]); glVertex3f(ENX1,ENY1,ENZ1); glColor3fv(ENC[5]); glVertex3f(ENX5,ENY5,ENZ5); glColor3fv(ENC[2]); glVertex3f(ENX2,ENY2,ENZ2); glColor3fv(ENC[6]); glVertex3f(ENX6,ENY6,ENZ6); glEnd(); glBegin(GL_QUAD_STRIP); glColor3fv(ENC[3]); glVertex3f(ENX3,ENY3,ENZ3); glColor3fv(ENC[7]); glVertex3f(ENX7,ENY7,ENZ7); glColor3fv(ENC[4]); glVertex3f(ENX4,ENY4,ENZ4); glColor3fv(ENC[8]); glVertex3f(ENX8,ENY8,ENZ8); glEnd(); glBegin(GL_QUAD_STRIP); glColor3fv(ENC[2]); glVertex3f(ENX2,ENY2,ENZ2); glColor3fv(ENC[6]); glVertex3f(ENX6,ENY6,ENZ6); glColor3fv(ENC[3]); glVertex3f(ENX3,ENY3,ENZ3); glColor3fv(ENC[7]); glVertex3f(ENX7,ENY7,ENZ7); glEnd(); glBegin(GL_QUAD_STRIP); glColor3fv(ENC[1]); glVertex3f(ENX1,ENY1,ENZ1); glColor3fv(ENC[5]); glVertex3f(ENX5,ENY5,ENZ5); glColor3fv(ENC[4]); glVertex3f(ENX4,ENY4,ENZ4); glColor3fv(ENC[8]); glVertex3f(ENX8,ENY8,ENZ8); glEnd(); } } } } QStringList QGLScreen::findNode(int element) { QStringList Temp; for (int i = 0; i < Nodes.size(); ++i) { Temp=Nodes.at(i).split(","); if(Temp.at(0).toInt()==element) { break; } } return Temp; } QString QGLScreen::findData(int Node) { QString Temp; QRegExp sep("\s+"); for (int i = 0; i < Data.size(); ++i) { if((Data.at(i).split("\t")).at(0).section(sep,1,1).toInt()==Node) { if(axis=="X") { Temp=Data.at(i).split("\t").at(0).section(sep,2,2); } if(axis=="Y") { Temp=Data.at(i).split("\t").at(0).section(sep,3,3); } if(axis=="Z") { Temp=Data.at(i).split("\t").at(0).section(sep,4,4); } break; } } return Temp; } void QGLScreen::fillColorArray() { QString Temp1,Temp2,Temp3; double d1s=0,d2s=0,d3s=0,d1l=0,d2l=0,d3l=0,diff=0; QRegExp sep("\\s+"); for (int i = 0; i < Data.size(); ++i) { Temp1=(Data.at(i).split("\t")).at(0).section(sep,2,2); if(d1s>Temp1.toDouble()) { d1s=Temp1.toDouble(); } if(d1l<Temp1.toDouble()) { d1l=Temp1.toDouble(); } Temp2=(Data.at(i).split("\t")).at(0).section(sep,3,3); if(d2s>Temp2.toDouble()) { d2s=Temp2.toDouble(); } if(d2l<Temp2.toDouble()) { d2l=Temp2.toDouble(); } Temp3=(Data.at(i).split("\t")).at(0).section(sep,4,4); if(d3s>Temp3.toDouble()) { d3s=Temp3.toDouble(); } if(d3l<Temp3.toDouble()) { d3l=Temp3.toDouble(); } // printf("data is %s",Temp.toLocal8Bit().constData());fflush(stdout); } color[0][0]=d1l; for(int i=1;i<360;i++) { //printf("Large is%f small is %f",d1l,d1s); diff=d1l-d1s; if(d1l==0&&d1s<0) color[0][i]=color[0][i-1]-diff/360; else if(d1l>0&&d1s==0) color[0][i]=color[0][i-1]+diff/360; else if(d1l>0&&d1s<0) color[0][i]=color[0][i-1]-diff/360; diff=d2l-d2s; if(d2l==0&&d2s<0) color[1][i]=color[1][i-1]-diff/360; else if(d2l>0&&d2s==0) color[1][i]=color[1][i-1]+diff/360; else if(d2l>0&&d2s<0) color[1][i]=color[1][i-1]-diff/360; diff=d3l-d3s; if(d3l==0&&d3s<0) color[2][i]=color[2][i-1]-diff/360; else if(d3l>0&&d3s==0) color[2][i]=color[2][i-1]+diff/360; else if(d3l>0&&d3s<0) color[2][i]=color[2][i-1]-diff/360; } //for(int i=0;i<360;i++) printf("%d %f %f %f\n",i,color[0][i],color[1][i],color[2][i]); } int QGLScreen::pickColor(double data,int Did) { int i,pos; if(axis=="X")Did=0; if(axis=="Y")Did=1; if(axis=="Z")Did=2; //printf("%f data is",data);fflush(stdout); for(int i=0;i<360;i++) { if(color[Did][i]<data && data>color[Did][i+1]) { //printf("Orginal dat is %f Data found is %f and pos %d\n",data,color[Did][i],i);fflush(stdout); pos=i; break; } } return pos; } void QGLScreen::getRGB(int hsv) { QColor c; c.setHsv(hsv,255,255,255); QColor r=QColor::fromHsv(hsv,255,255); red=r.red(); green=r.green(); blue=r.blue(); } void QGLScreen::paintGL() { glClear(GL_COLOR_BUFFER_BIT | GL_DEPTH_BUFFER_BIT); glPushAttrib(GL_ALL_ATTRIB_BITS); glMatrixMode(GL_PROJECTION); glPushMatrix(); glLoadIdentity(); GLfloat x = 3.0 * GLfloat(width()) / height(); glOrtho(-x, +x, -3.0, +3.0, 4.0, 15.0); glMatrixMode(GL_MODELVIEW); glPushMatrix(); glLoadIdentity(); glTranslatef(0.0, 0.0, -10.0); glScalef(scaling, scaling, scaling); glRotatef(xRot, 1.0, 0.0, 0.0); glRotatef(yRot, 0.0, 1.0, 0.0); glRotatef(zRot, 0.0, 0.0, 1.0); drawModel(0,0,1,1); /* don't wait! * start processing buffered OpenGL routines */ glFlush (); } /void QGLScreen::zoom1() { scaling+=.05; update(); }/ void QGLScreen::resizeGL(int width, int height) { int side = qMin(width, height); glViewport((width - side) / 2, (height - side) / 2, side, side); #if !defined(QT_OPENGL_ES_2) glMatrixMode(GL_PROJECTION); glLoadIdentity(); #ifndef QT_OPENGL_ES glOrtho(-0.5, +0.5, +0.5, -0.5, 4.0, 15.0); #else glOrthof(-0.5, +0.5, +0.5, -0.5, 4.0, 15.0); #endif glMatrixMode(GL_MODELVIEW); #endif } void QGLScreen::mousePressEvent(QMouseEvent *event) { lastPos = event-pos(); } void QGLScreen::mouseMoveEvent(QMouseEvent *event) { GLfloat dx = GLfloat(event->x() - lastPos.x()) / width(); GLfloat dy = GLfloat(event->y() - lastPos.y()) / height(); if (event->buttons() & Qt::LeftButton) { xRot+= 180 * dy; yRot += 180 * dx; update(); } else if (event->buttons() & Qt::RightButton) { xRot += 180 * dy; yRot += 180 * dx; update(); } lastPos = event->pos(); } void QGLScreen::mouseReleaseEvent(QMouseEvent * /* event */) { emit clicked(); }

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  • ignoring informational payload, type INVALID_COOKIE msgid=00000000

    - by user197279
    I'm configuring a site-to-site vpn between openswan ipsec and cisco asa 5540. After the step, i started ipesc service but the error i'm seeing is: ignoring informational payload, type INVALID_COOKIE msgid=00000000 Nov 5 09:42:30 pluto[11712]: "myVPN" #1: received and ignored informational message Nov 5 09:42:51 pluto[11712]: "myVPN" #1: ignoring informational payload, type INVALID_COOKIE msgid=00000000 Nov 5 09:42:51 pluto[11712]: "myVPN" #1: received and ignored informational message Nov 5 09:43:30 pluto[11712]: "myVPN" #1: max number of retransmissions (2) reached STATE_MAIN_I2 Nov 5 09:43:30 pluto[11712]: "myVPN" #1: starting keying attempt 2 of at most 3 Any advise why I'm getting this error on openswan? Also sudo ipsec whack --status gives: "myVPN": 10.0.xx.0/24===10.0.7x.x[54.209.y.yyy,+S=C]---10.0.xx.x...10.0.70.x---41.22x.4.xx<41.22x.4.xx[+S=C]===41.22y.4.yyy/32; unrouted; eroute owner: #0 000 "myVPN": myip=54.209.zz.zz; hisip=unset; 000 "myVPN": ike_life: 86400s; ipsec_life: 28800s; rekey_margin: 540s; rekey_fuzz: 100%; keyingtries: 3 000 "myVPN": policy: PSK+ENCRYPT+TUNNEL+DONTREKEY+UP+IKEv2ALLOW+SAREFTRACK+lKOD+rKOD; prio: 24,32; interface: eth0; 000 "myVPN": newest ISAKMP SA: #0; newest IPsec SA: #0; 000 "myVPN": IKE algorithms wanted: AES_CBC(7)_256-SHA1(2)_000-MODP1024(2); flags=-strict 000 "myVPN": IKE algorithms found: AES_CBC(7)_256-SHA1(2)_160-MODP1024(2) 000 "myVPN": ESP algorithms wanted: AES(12)_256-SHA1(2)_000; flags=-strict 000 "myVPN": ESP algorithms loaded: AES(12)_256-SHA1(2)_160 000 000 #5: "myVPN":500 STATE_MAIN_I2 (sent MI2, expecting MR2); EVENT_RETRANSMIT in 8s; nodpd; idle; import:admin initiate 000 #5: pending Phase 2 for "myVPN" replacing #0 Thanks.

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  • OpenSolaris / Nexenta problems with NetXen 4-port NIC card (ntxn driver)

    - by ewwhite
    Hello, I'm running NexentaStor Enterprise on an HP ProLiant DL180 G6 server. The onboard NIC interfaces surface as igb0 and igb1 and work well. However, I've added an HP NC375T 4-port network card using the NetXen 3031 chipset. This card should be handled by the ntxn driver in the SUNWntxn package, but that results in "ntxn0: failed to map doorbell" messages upon boot. The network interfaces don't show up. After some research, I found HP's driver package for the card. The release notes for the driver package state: This version of the Driver is supported only on Oracle Solaris 10 5/09 & 10/09. Oracle Solaris 10 5/09 & 10/09 contain an older version of NetXen P3 driver package called SUNWntxn. So, adding another version of NetXen P3 driver package using pkgadd command might result in conflicts with the NetXen driver binary & related files. Users are advised to uninstall native SUNWntxn driver package before installing the new package. The install completes, but I end up with a different set of errors in initializing the card. ifconfig ntxn0 plumb ifconfig: cannot open link "ntxn0": DLPI link does not exist dmesg output: Jan 29 07:20:17 ch-san2 ntxn: [ID 977263 kern.warning] WARNING: Memory not available Jan 29 07:20:17 ch-san2 ntxn: [ID 404858 kern.notice] NOTICE: ntxn0: Mac registration error Trying to manually create the device files: root@ch-san2:/volumes# add_drv -i "4040,100" ntxn ("ntxn") already in use as a driver or alias. Update the driver: root@ch-san2:/volumes# update_drv -f ntxn devfsadm: driver failed to attach: ntxn Warning: Driver (ntxn) successfully added to system but failed to attach Any ideas on how to get this driver working, or should I ditch the card and go with an Intel or something else?

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  • Header set Access-Control-Allow-Origin not working with mod_rewrite + mod_jk

    - by tharant
    My first question on here on SF so please forgive me if I manage to bork the post. :) Anyways, I'm using mod_rewrite on one of my machines with a simple rule that redirects to a webapp on another machine. I'm also setting the header 'Access-Control-Allow-Origin' on both machines. The problem is that when I hit the rewrite rule, I loose the 'Access-Control-Allow-Origin' header setting. Here's an example of the Apache config for the first machine: NameVirtualHost 10.0.0.2:80 <VirtualHost 10.0.0.2:80> DocumentRoot /var/www/host.example.com ServerName host.example.com JkMount /webapp/* jkworker Header set Access-Control-Allow-Origin "*" RewriteEngine on RewriteRule ^/otherhost http://otherhost.example.com/webapp [R,L] </VirtualHost> And here's an example of the Apache config for the second: NameVirtualHost 10.0.1.2:80 <VirtualHost 10.0.1.2:80> DocumentRoot /var/www/otherhost.example.com ServerName otherhost.example.com JkMount /webapp/* jkworker Header set Access-Control-Allow-Origin "*" </VirtualHost> When I hit host.example.com we see that the header is set: $ curl -i http://host.example.com/ HTTP/1.1 302 Moved Temporarily Server: Apache/2.2.11 (FreeBSD) mod_ssl/2.2.11 OpenSSL/0.9.7e-p1 DAV/2 mod_jk/1.2.26 Content-Length: 0 Access-Control-Allow-Origin: * Content-Type: text/html;charset=ISO-8859-1 And when I hit otherhost.example.com we see that it too is setting the header: $ curl -i http://otherhost.example.com HTTP/1.1 200 OK Server: Apache/2.0.46 (Red Hat) Location: http://otherhost.example.com/index.htm Content-Length: 0 Access-Control-Allow-Origin: * Content-Type: text/html;charset=UTF-8 But when I try to hit the rewrite rule at host.example.com/otherhost we get no love: $ curl -i http://host.example.com/otherhost/ HTTP/1.1 302 Found Server: Apache/2.2.11 (FreeBSD) mod_ssl/2.2.11 OpenSSL/0.9.7e-p1 DAV/2 mod_jk/1.2.26 Location: http://otherhost.example.com/ Content-Length: 0 Content-Type: text/html; charset=iso-8859-1 Can anybody point out what I'm doing wrong here? Could mod_jk be part of the problem?

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  • Yum Update Failing mod_ssl and glibc_devel

    - by Kerry
    Any ideas on how to get this to not fail? # yum update Freeing read locks for locker 0x82: 4189/140342084876032 Freeing read locks for locker 0x84: 4189/140342084876032 Freeing read locks for locker 0x85: 4189/140342084876032 Freeing read locks for locker 0x86: 4189/140342084876032 Freeing read locks for locker 0x87: 4189/140342084876032 Freeing read locks for locker 0x9a: 4189/140342084876032 Freeing read locks for locker 0x9c: 4189/140342084876032 Freeing read locks for locker 0x9d: 4189/140342084876032 Freeing read locks for locker 0x9e: 4189/140342084876032 Freeing read locks for locker 0x9f: 4189/140342084876032 Freeing read locks for locker 0xa0: 4189/140342084876032 Freeing read locks for locker 0xa1: 4189/140342084876032 Freeing read locks for locker 0xa2: 4189/140342084876032 Freeing read locks for locker 0xa3: 4189/140342084876032 Freeing read locks for locker 0xa4: 4189/140342084876032 Freeing read locks for locker 0xa5: 4189/140342084876032 Freeing read locks for locker 0xa6: 4189/140342084876032 Freeing read locks for locker 0xa7: 4189/140342084876032 Freeing read locks for locker 0xa8: 4189/140342084876032 Freeing read locks for locker 0xa9: 4189/140342084876032 Freeing read locks for locker 0xaa: 4189/140342084876032 Loaded plugins: fastestmirror Loading mirror speeds from cached hostfile * base: mirror.hmc.edu * epel: mirrors.kernel.org * extras: centos.mirror.freedomvoice.com * updates: mirrors.sonic.net Setting up Update Process Resolving Dependencies There are unfinished transactions remaining. You might consider running yum-complete-transaction first to finish them. The program yum-complete-transaction is found in the yum-utils package. --> Running transaction check ---> Package device-mapper-persistent-data.x86_64 0:0.2.8-2.el6 will be updated ---> Package device-mapper-persistent-data.x86_64 0:0.2.8-4.el6_5 will be an update ---> Package glibc-headers.x86_64 0:2.12-1.132.el6 will be updated --> Processing Dependency: glibc-headers = 2.12-1.132.el6 for package: glibc-devel-2.12-1.132.el6.x86_64 ---> Package glibc-headers.x86_64 0:2.12-1.132.el6_5.2 will be an update ---> Package httpd.x86_64 0:2.2.15-29.el6.centos will be updated --> Processing Dependency: httpd = 2.2.15-29.el6.centos for package: 1:mod_ssl-2.2.15-29.el6.centos.x86_64 ---> Package httpd.x86_64 0:2.2.15-30.el6.centos will be an update ---> Package kernel.x86_64 0:2.6.32-431.17.1.el6 will be installed ---> Package kernel-devel.x86_64 0:2.6.32-431.17.1.el6 will be installed ---> Package selinux-policy-targeted.noarch 0:3.7.19-231.el6_5.1 will be updated ---> Package selinux-policy-targeted.noarch 0:3.7.19-231.el6_5.3 will be an update --> Finished Dependency Resolution Error: Package: 1:mod_ssl-2.2.15-29.el6.centos.x86_64 (@base) Requires: httpd = 2.2.15-29.el6.centos Removing: httpd-2.2.15-29.el6.centos.x86_64 (@base) httpd = 2.2.15-29.el6.centos Updated By: httpd-2.2.15-30.el6.centos.x86_64 (updates) httpd = 2.2.15-30.el6.centos Error: Package: glibc-devel-2.12-1.132.el6.x86_64 (@base) Requires: glibc-headers = 2.12-1.132.el6 Removing: glibc-headers-2.12-1.132.el6.x86_64 (@base) glibc-headers = 2.12-1.132.el6 Updated By: glibc-headers-2.12-1.132.el6_5.2.x86_64 (updates) glibc-headers = 2.12-1.132.el6_5.2 Available: glibc-headers-2.12-1.132.el6_5.1.x86_64 (updates) glibc-headers = 2.12-1.132.el6_5.1 You could try using --skip-broken to work around the problem ** Found 34 pre-existing rpmdb problem(s), 'yum check' output follows: audit-2.2-4.el6_5.x86_64 is a duplicate with audit-2.2-2.el6.x86_64 audit-libs-2.2-4.el6_5.x86_64 is a duplicate with audit-libs-2.2-2.el6.x86_64 curl-7.19.7-37.el6_5.3.x86_64 is a duplicate with curl-7.19.7-37.el6_4.x86_64 device-mapper-multipath-0.4.9-72.el6_5.2.x86_64 is a duplicate with device-mapper-multipath-0.4.9-72.el6_5.1.x86_64 device-mapper-multipath-libs-0.4.9-72.el6_5.2.x86_64 is a duplicate with device-mapper-multipath-libs-0.4.9-72.el6_5.1.x86_64 2:ethtool-3.5-1.4.el6_5.x86_64 is a duplicate with 2:ethtool-3.5-1.2.el6_5.x86_64 glibc-2.12-1.132.el6_5.2.x86_64 is a duplicate with glibc-2.12-1.132.el6.x86_64 glibc-common-2.12-1.132.el6_5.2.x86_64 is a duplicate with glibc-common-2.12-1.132.el6.x86_64 glibc-devel-2.12-1.132.el6_5.2.x86_64 is a duplicate with glibc-devel-2.12-1.132.el6.x86_64 glibc-devel-2.12-1.132.el6_5.2.x86_64 has missing requires of glibc-headers = ('0', '2.12', '1.132.el6_5.2') gnutls-2.8.5-14.el6_5.x86_64 is a duplicate with gnutls-2.8.5-13.el6_5.x86_64 httpd-2.2.15-29.el6.centos.x86_64 has missing requires of httpd-tools = ('0', '2.2.15', '29.el6.centos') httpd-manual-2.2.15-30.el6.centos.noarch has missing requires of httpd = ('0', '2.2.15', '30.el6.centos') iproute-2.6.32-32.el6_5.x86_64 is a duplicate with iproute-2.6.32-31.el6.x86_64 kernel-firmware-2.6.32-431.17.1.el6.noarch is a duplicate with kernel-firmware-2.6.32-431.11.2.el6.noarch kernel-headers-2.6.32-431.17.1.el6.x86_64 is a duplicate with kernel-headers-2.6.32-431.11.2.el6.x86_64 kpartx-0.4.9-72.el6_5.2.x86_64 is a duplicate with kpartx-0.4.9-72.el6_5.1.x86_64 krb5-libs-1.10.3-15.el6_5.1.x86_64 is a duplicate with krb5-libs-1.10.3-10.el6_4.6.x86_64 libblkid-2.17.2-12.14.el6_5.x86_64 is a duplicate with libblkid-2.17.2-12.14.el6.x86_64 libcurl-7.19.7-37.el6_5.3.x86_64 is a duplicate with libcurl-7.19.7-37.el6_4.x86_64 libcurl-devel-7.19.7-37.el6_5.3.x86_64 is a duplicate with libcurl-devel-7.19.7-37.el6_4.x86_64 libtasn1-2.3-6.el6_5.x86_64 is a duplicate with libtasn1-2.3-3.el6_2.1.x86_64 libuuid-2.17.2-12.14.el6_5.x86_64 is a duplicate with libuuid-2.17.2-12.14.el6.x86_64 libxml2-2.7.6-14.el6_5.1.x86_64 is a duplicate with libxml2-2.7.6-14.el6.x86_64 mdadm-3.2.6-7.el6_5.2.x86_64 is a duplicate with mdadm-3.2.6-7.el6.x86_64 1:mod_ssl-2.2.15-30.el6.centos.x86_64 is a duplicate with 1:mod_ssl-2.2.15-29.el6.centos.x86_64 1:mod_ssl-2.2.15-30.el6.centos.x86_64 has missing requires of httpd = ('0', '2.2.15', '30.el6.centos') nss-softokn-3.14.3-10.el6_5.x86_64 is a duplicate with nss-softokn-3.14.3-9.el6.x86_64 openssl-1.0.1e-16.el6_5.7.x86_64 is a duplicate with openssl-1.0.1e-16.el6_5.4.x86_64 openssl-1.0.1e-16.el6_5.14.x86_64 is a duplicate with openssl-1.0.1e-16.el6_5.7.x86_64 openssl-devel-1.0.1e-16.el6_5.14.x86_64 is a duplicate with openssl-devel-1.0.1e-16.el6_5.7.x86_64 selinux-policy-3.7.19-231.el6_5.3.noarch is a duplicate with selinux-policy-3.7.19-231.el6_5.1.noarch tzdata-2014d-1.el6.noarch is a duplicate with tzdata-2014b-1.el6.noarch util-linux-ng-2.17.2-12.14.el6_5.x86_64 is a duplicate with util-linux-ng-2.17.2-12.14.el6.x86_64 UPDATE I installed and ran yum-complete-transaction as requested, it finished some things and suggested I run package-cleanup --problems, which yielded this: package-cleanup --problems Loaded plugins: fastestmirror Package httpd-manual-2.2.15-30.el6.centos.noarch requires httpd = ('0', '2.2.15', '30.el6.centos') Package httpd-2.2.15-29.el6.centos.x86_64 requires httpd-tools = ('0', '2.2.15', '29.el6.centos') Package mod_ssl-2.2.15-30.el6.centos.x86_64 requires httpd = ('0', '2.2.15', '30.el6.centos') Package glibc-devel-2.12-1.132.el6_5.2.x86_64 requires glibc-headers = ('0', '2.12', '1.132.el6_5.2') I'm definitely not a sys-admin, what would be the next step? UPDATE 2 I ran yum distro-sync: # yum distro-sync Loaded plugins: fastestmirror Loading mirror speeds from cached hostfile * base: mirror.hmc.edu * epel: mirrors.kernel.org * extras: centos.mirror.freedomvoice.com * updates: mirrors.sonic.net Setting up Distribution Synchronization Process Resolving Dependencies --> Running transaction check ---> Package glibc-headers.x86_64 0:2.12-1.132.el6 will be updated --> Processing Dependency: glibc-headers = 2.12-1.132.el6 for package: glibc-devel-2.12-1.132.el6.x86_64 ---> Package glibc-headers.x86_64 0:2.12-1.132.el6_5.2 will be an update ---> Package httpd.x86_64 0:2.2.15-29.el6.centos will be updated --> Processing Dependency: httpd = 2.2.15-29.el6.centos for package: 1:mod_ssl-2.2.15-29.el6.centos.x86_64 ---> Package httpd.x86_64 0:2.2.15-30.el6.centos will be an update --> Finished Dependency Resolution Error: Package: 1:mod_ssl-2.2.15-29.el6.centos.x86_64 (@base) Requires: httpd = 2.2.15-29.el6.centos Removing: httpd-2.2.15-29.el6.centos.x86_64 (@base) httpd = 2.2.15-29.el6.centos Updated By: httpd-2.2.15-30.el6.centos.x86_64 (updates) httpd = 2.2.15-30.el6.centos Error: Package: glibc-devel-2.12-1.132.el6.x86_64 (@base) Requires: glibc-headers = 2.12-1.132.el6 Removing: glibc-headers-2.12-1.132.el6.x86_64 (@base) glibc-headers = 2.12-1.132.el6 Updated By: glibc-headers-2.12-1.132.el6_5.2.x86_64 (updates) glibc-headers = 2.12-1.132.el6_5.2 Available: glibc-headers-2.12-1.132.el6_5.1.x86_64 (updates) glibc-headers = 2.12-1.132.el6_5.1 You could try using --skip-broken to work around the problem ** Found 34 pre-existing rpmdb problem(s), 'yum check' output follows: audit-2.2-4.el6_5.x86_64 is a duplicate with audit-2.2-2.el6.x86_64 audit-libs-2.2-4.el6_5.x86_64 is a duplicate with audit-libs-2.2-2.el6.x86_64 curl-7.19.7-37.el6_5.3.x86_64 is a duplicate with curl-7.19.7-37.el6_4.x86_64 device-mapper-multipath-0.4.9-72.el6_5.2.x86_64 is a duplicate with device-mapper-multipath-0.4.9-72.el6_5.1.x86_64 device-mapper-multipath-libs-0.4.9-72.el6_5.2.x86_64 is a duplicate with device-mapper-multipath-libs-0.4.9-72.el6_5.1.x86_64 2:ethtool-3.5-1.4.el6_5.x86_64 is a duplicate with 2:ethtool-3.5-1.2.el6_5.x86_64 glibc-2.12-1.132.el6_5.2.x86_64 is a duplicate with glibc-2.12-1.132.el6.x86_64 glibc-common-2.12-1.132.el6_5.2.x86_64 is a duplicate with glibc-common-2.12-1.132.el6.x86_64 glibc-devel-2.12-1.132.el6_5.2.x86_64 is a duplicate with glibc-devel-2.12-1.132.el6.x86_64 glibc-devel-2.12-1.132.el6_5.2.x86_64 has missing requires of glibc-headers = ('0', '2.12', '1.132.el6_5.2') gnutls-2.8.5-14.el6_5.x86_64 is a duplicate with gnutls-2.8.5-13.el6_5.x86_64 httpd-2.2.15-29.el6.centos.x86_64 has missing requires of httpd-tools = ('0', '2.2.15', '29.el6.centos') httpd-manual-2.2.15-30.el6.centos.noarch has missing requires of httpd = ('0', '2.2.15', '30.el6.centos') iproute-2.6.32-32.el6_5.x86_64 is a duplicate with iproute-2.6.32-31.el6.x86_64 kernel-firmware-2.6.32-431.17.1.el6.noarch is a duplicate with kernel-firmware-2.6.32-431.11.2.el6.noarch kernel-headers-2.6.32-431.17.1.el6.x86_64 is a duplicate with kernel-headers-2.6.32-431.11.2.el6.x86_64 kpartx-0.4.9-72.el6_5.2.x86_64 is a duplicate with kpartx-0.4.9-72.el6_5.1.x86_64 krb5-libs-1.10.3-15.el6_5.1.x86_64 is a duplicate with krb5-libs-1.10.3-10.el6_4.6.x86_64 libblkid-2.17.2-12.14.el6_5.x86_64 is a duplicate with libblkid-2.17.2-12.14.el6.x86_64 libcurl-7.19.7-37.el6_5.3.x86_64 is a duplicate with libcurl-7.19.7-37.el6_4.x86_64 libcurl-devel-7.19.7-37.el6_5.3.x86_64 is a duplicate with libcurl-devel-7.19.7-37.el6_4.x86_64 libtasn1-2.3-6.el6_5.x86_64 is a duplicate with libtasn1-2.3-3.el6_2.1.x86_64 libuuid-2.17.2-12.14.el6_5.x86_64 is a duplicate with libuuid-2.17.2-12.14.el6.x86_64 libxml2-2.7.6-14.el6_5.1.x86_64 is a duplicate with libxml2-2.7.6-14.el6.x86_64 mdadm-3.2.6-7.el6_5.2.x86_64 is a duplicate with mdadm-3.2.6-7.el6.x86_64 1:mod_ssl-2.2.15-30.el6.centos.x86_64 is a duplicate with 1:mod_ssl-2.2.15-29.el6.centos.x86_64 1:mod_ssl-2.2.15-30.el6.centos.x86_64 has missing requires of httpd = ('0', '2.2.15', '30.el6.centos') nss-softokn-3.14.3-10.el6_5.x86_64 is a duplicate with nss-softokn-3.14.3-9.el6.x86_64 openssl-1.0.1e-16.el6_5.7.x86_64 is a duplicate with openssl-1.0.1e-16.el6_5.4.x86_64 openssl-1.0.1e-16.el6_5.14.x86_64 is a duplicate with openssl-1.0.1e-16.el6_5.7.x86_64 openssl-devel-1.0.1e-16.el6_5.14.x86_64 is a duplicate with openssl-devel-1.0.1e-16.el6_5.7.x86_64 selinux-policy-3.7.19-231.el6_5.3.noarch is a duplicate with selinux-policy-3.7.19-231.el6_5.1.noarch tzdata-2014d-1.el6.noarch is a duplicate with tzdata-2014b-1.el6.noarch util-linux-ng-2.17.2-12.14.el6_5.x86_64 is a duplicate with util-linux-ng-2.17.2-12.14.el6.x86_64

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  • Address (url) forwarding with Vyatta

    - by Trikks
    Hi Got this kind of noob question i suppose. I got this very basic network setup and need help to set up some address forwarding. As seen in my illustration below all traffic enters via the eth0 interface (85.123.32.23). The external dns is setup to direct all hosts to this ip as well. Now, how on earth do I filter the incoming requests to each box? The Ip's are static! Se the network layout here: http://vyatta.org/files/u11160/setup.png I do not wish to solve this by assigning tons of ports etc. In my wishful thinking something like this would be nice :) set service nat rule 10 type destination set service nat rule 10 inbound-interface eth0 set service nat rule 10 destination address ftp.myhost.com set service nat rule 10 inside-address address 192.168.100.20 This way ALL traffic to the address ftp.myhost.com (at eth0) should be routed to the internal ip, 192.168.100.20. Right, is there anyone who could point in some direction? Maybe it's wrong to use nat? Please help me! :)

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  • Address (url) forwarding with Vyatta

    - by Trikks
    Got this kind of noob question i suppose. I got this very basic network setup and need help to set up some address forwarding. As seen in my illustration below all traffic enters via the eth0 interface (85.123.32.23). The external dns is setup to direct all hosts to this ip as well. Now, how on earth do I filter the incoming requests to each box? The Ip's are static! My network layout: I do not wish to solve this by assigning tons of ports etc. In my wishful thinking something like this would be nice :) set service nat rule 10 type destination set service nat rule 10 inbound-interface eth0 set service nat rule 10 destination address ftp.myhost.com set service nat rule 10 inside-address address 192.168.100.20 This way ALL traffic to the address ftp.myhost.com (at eth0) should be routed to the internal ip, 192.168.100.20. Right, is there anyone who could point in some direction? Maybe it's wrong to use nat? Please help me! :)

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  • Web server with static IP from cable provider

    - by Dmitri
    I have a subscription to 5 static IP addresses. I want to run a web server from behind a router. My network config is as follows: Server's local address is 10.1.10.2, has IIS running on it, port 80 and 443 (IIS is not my fault, had to be done) the server's ip address is static, the subnet mask is 255.255.255.0, gateway is 10.1.10.1, which is the local address of the cable modem / router / gateway thingy. All looks to be in textbook order as far as the LAN goes. I can get to anything on my LAN from any computer on my LAN, whether they have static IP or get it through DHCP from the cable modem/router thingy. however, I have no internet access form any of my LAN computers. I called Comcast tech support and they say they can connect to my modem/router just fine and can actually use it to ping any computer on the internet or any computer on my LAN from the router/modem (i checked, myself, this is in fact the case). However, nothing on my LAN has internet connectivity. I tried pinging the DNS servers, nothing. I tried directly typing in web sites' IP addresses, nothing, so doesn't seem to be a DNS issue. Any Ideas? What malfunction of a router could be causing such weird behavior? nay ideas or educated guesses are very much appreciated.

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  • Why apache doesn't restart after configuring SSL?

    - by poz2k4444
    I've installed apache2 and then configure it to work with SSL following this and this tutorials, the problem becomes when I try to restart the service, the following error throws: (98)Address already in use: make_sock: could not bind to address 0.0.0.0:443 no listening sockets available, shutting down Unable to open logs the output of netstat -anp | grep 443 just display firefox listening and anything else, how could I solve this and get the service running?? The ouput of ps -Af|grep <firefox PID> is: root 1949 1 11 18:42 tty1 00:20:55 /opt/firefox/firefox-bin root 2025 1949 4 18:43 tty1 00:08:39 /opt/firefox/plugin-container /root/.mozilla/plugins/libflashplayer.so -greomni /opt/firefox/omni.ja 1949 true plugin after closing firefox and then cheking again for port 443 the output is: tcp 0 0 10.32.208.179:38923 74.125.139.155:443 TIME_WAIT - tcp 0 0 10.32.208.179:45706 74.125.139.113:443 TIME_WAIT - tcp 0 0 10.32.208.179:40456 74.125.139.156:443 TIME_WAIT - tcp 0 0 10.32.208.179:56823 69.171.227.62:443 FIN_WAIT2 - unix 3 [ ] STREAM CONNECTED 12443 1721/dbus-daemon @/tmp/dbus-8ee35rmOOS Seeing the error logs, which are not at the time when I'm doing this, the last errors are: [Tue Oct 02 18:41:54 2012] [error] Init: Unable to read server certificate from file /etc/apache2/ssl/sever.crt [Tue Oct 02 18:41:54 2012] [error] SSL Library Error: 218529960 error:0D0680A8:asn1 encoding routines:ASN1_CHECK_TLEN:wrong tag [Tue Oct 02 18:41:54 2012] [error] SSL Library Error: 218595386 error:0D07803A:asn1 encoding routines:ASN1_ITEM_EX_D2I:nested asn1 error

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  • PPTP Client setup, Fedora 17

    - by Suarez Romina
    I am trying to connect to hidemyass.com VPN services via PPTP, but I am having issues understanding why it isn't working, since I don't get a warning or fatal error and my IP remains the same. This is how i create the connection: [root@lasvegas-nv-datacenter ~]# pptpsetup --create TUNNELNAME --server 199.58.165.20 --username MYUSERNAME --password MYPASSWORD --encrypt --start And this is the output: Using interface ppp0 Connect: ppp0 <-- /dev/pts/1 CHAP authentication succeeded MPPE 128-bit stateless compression enabled local IP address 10.200.21.14 remote IP address 10.200.20.1 After that, I check the log and this is what i get: [root@lasvegas-nv-datacenter ~]# tail -f /var/log/messages Aug 24 11:25:33 lasvegas-nv-datacenter pptp[3892]: anon log[ctrlp_rep:pptp_ctrl.c:254]: Sent control packet type is 1 'Start-Control-Connection-Request' Aug 24 11:25:33 lasvegas-nv-datacenter pptp[3892]: anon log[ctrlp_disp:pptp_ctrl.c:754]: Received Start Control Connection Reply Aug 24 11:25:33 lasvegas-nv-datacenter pptp[3892]: anon log[ctrlp_disp:pptp_ctrl.c:788]: Client connection established. Aug 24 11:25:34 lasvegas-nv-datacenter pptp[3892]: anon log[ctrlp_rep:pptp_ctrl.c:254]: Sent control packet type is 7 'Outgoing-Call-Request' Aug 24 11:25:34 lasvegas-nv-datacenter pptp[3892]: anon log[ctrlp_disp:pptp_ctrl.c:873]: Received Outgoing Call Reply. Aug 24 11:25:34 lasvegas-nv-datacenter pptp[3892]: anon log[ctrlp_disp:pptp_ctrl.c:912]: Outgoing call established (call ID 0, peer's call ID 20096). Aug 24 11:25:38 lasvegas-nv-datacenter pppd[3884]: CHAP authentication succeeded Aug 24 11:25:38 lasvegas-nv-datacenter pppd[3884]: MPPE 128-bit stateless compression enabled Aug 24 11:25:38 lasvegas-nv-datacenter pppd[3884]: local IP address 10.200.21.14 Aug 24 11:25:38 lasvegas-nv-datacenter pppd[3884]: remote IP address 10.200.20.1 Can someone help me? Basically, i Ieed to connect to the VPN and have my IP changed after the connection. I read a lot of guides but still cannot understand why I don't get a connection.

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  • Windows 7 - Wireless Signal Good - Internet Often Says Limited or No Activity

    - by Anthony Trilussa Pizzo
    Hi - I have a New Dell Studio XPS latop that I hooked up in early January of 2010. The Dell Studio XPS laptop is connected to my wireless router (Belkin Wireless N). The router was purchased in Februaru of 2010 because I thought my router was bad (A D-Link router). Comcast is my ISP. Everyday, at random times, the internet will have a good signal (according to the little Win 7 icon on the taskbar) but I will receive a message saying limited or no internet access and I cannot access the internet. I have the internet setup to automatically get an IP and I did the IPCONFIG release / renew but with no success. I even had a WiFi enabled Blackberry right next to my computer and whenever the computer loses an WiFi connection, so does the Blackberry. The router isnt't bad, because the old router did the same thing - giving me limited or no internet access while working sometimes. I also tried using two other laptops in same physical position as my Dell Studio XPS laptop and they have the same problem. I am going crazy trying to figure this out as I have called the Router Company (Belkin), my ISP (Comcast), and my computer maker (Dell). Can anyone offer some suggestions and I can try them as we work through this and maybe one of the suggestion will be right one. Thanks in advance for even reading my problem. I searched for a problem similar to mine on the internet, but I have not been able to keep a steady internet connection. (Side note - I used to have an IBM thinkpad laptop and D - Link router and for years that wireless connection worked FLAWLESSLY, with the same physical set up - the laptop in my bedroom, and the router in the basement.)

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  • Cassandra Remote Connection

    - by Lyuben Todorov
    I'm not managing to connect to cassandra from outside machines. The database is hosted on a windows machine and im trying to connect through a mac (but this shouldn't cause problems) Local connection works: C:\cassandra\bin>cassandra-cli Starting Cassandra Client Connected to: "Test Cluster" on 127.0.0.1/9160 Welcome to Cassandra CLI version 1.1.6 But fails from other machines on the same network bin/cassandra-cli --host 192.168.0.10 --port 9160 org.apache.thrift.transport.TTransportException: java.net.ConnectException: Operation timed out at org.apache.thrift.transport.TSocket.open(TSocket.java:183) at org.apache.thrift.transport.TFramedTransport.open(TFramedTransport.java:81) at org.apache.cassandra.cli.CliMain.connect(CliMain.java:70) at org.apache.cassandra.cli.CliMain.main(CliMain.java:246) Exception connecting to 192.168.0.10/9160. Reason: Operation timed out. Welcome to Cassandra CLI version 1.2.0-beta3 Type 'help;' or '?' for help. Type 'quit;' or 'exit;' to quit. There is a router on the network but these ports have been triggred Ports: 1024, 7000, 7001, 7199, 9160 And the same ports were forwarded to 192.168.0.10 (where Cassandra is hosted) Cassandra version is 1.0.7 And the settings I think i need to change in cassandra.yaml listen_address: 192.168.0.10 rpc_address: I'm not really sure if I've missed any steps. Any help would be appreciated.

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  • How do I access the web server on my desktop from my laptop?

    - by Steven
    I'm running Apache on my stationary and I would like to access a website through my laptop. This is some of the Apache config: NameVirtualHost 127.0.0.1:80 <VirtualHost 127.0.0.1:80> ServerName mysite.com DocumentRoot I:/wamp/www/mysite/ </VirtualHost> ServerName localhost:80 <Directory /> Options FollowSymLinks AllowOverride all Order deny,allow Deny from all </Directory> On my laptop I've added the following to the HOSTS file: 10.0.0.3 mysite.com But accessing the page through mysite.com is not very successfull. If I enter the IP address directly, I only get a Forbidden message. What do I need to do in order to get this to work? Update I'm runing WAMPSERVER 2.1 (Apache 2.2.17) Apache is up and running I can ping 10.0.0.3 from laptop I'm not able to ping http://mysite.com from laptop IE gives me a 403 Forbidden - The website declined to show this webpage The only log that get's entries when trying to access the website from my laptop, is access.log. access.log 10.0.0.4 - - [13/Jun/2011:10:14:04 +0200] "GET / HTTP/1.1" 403 202 apache_error.log [Mon Jun 13 10:08:16 2011] [error] VirtualHost localhost:0 -- mixing * ports and non-* ports with a NameVirtualHost address is not supported, proceeding with undefined results UPDATE 2 My apache config has the following entry: AllowOverride all Order Deny,Allow Deny from all Allow from 127.0.0.1 Could it be that this Allow from is stopping other computers accessing the page?

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  • Windows Server 2008 R2 SP1 Drivers Missing Would Not Install?

    - by bleepzter
    I am building my dev machine with WS2008R2SP1. I consider Windows Server as the best development environment for C# since I tend to focus on server-centric (integration) applications. The desktop flavor of Windows (7) doesn't play nicely with things like Commerce Server or BizTalk... so I to like stick to the environment I develop for. Previously I used to develop inside of VM's but I've found that it is super inefficient and tends to take a toll on the laptops. (I've gone through two of them in 6 months). Problem is that I multiple devices that do not want to be recognized by Windows: My machine is Dell Precision M4500: Intel Core i7-Q740, 1TB HDD, 8GB RAM, Dell re-branded Broadcom DW1501 802x11n Half-Mini Card, Dell re-branded Broadcom DW375 Bluetooh Module, Intel 82577LM Gigabit Network connection NVidia Quadro FX1800 Graphics The devices in question are the Dell rebranded broadcom network and bluetooth adapters: Broadcom USH: USB\VID_0A5C&PID_5800&REV_0101&MI_00 USB\VID_0A5C&PID_5800&MI_00 DW375 Bluetooth Module USB\VID_413C&PID_8187&REV_0517 USB\VID_413C&PID_8187 When I ran the broadcom installers I get "Operating System not supported" which I think is a big oversight on Broadcom's part. Why check for system version string? UGHGHGH Moreover if I try to manually force the driver in windows... I get an error: Driver Management concluded the process to install driver FileRepository\btwampsecfl.inf_amd64_neutral_d8fc2b85d035ed47\btwampsecfl.inf for Device Instance ID USB\VID_0A5C&PID_5800&MI_00\7&66DE6C9&0&0000 with the following status: 0xe0000217. '- or - Driver Management concluded the process to install driver FileRepository\btwampfl.inf_amd64_neutral_d4c4acf036c61299\btwampfl.inf for Device Instance ID USB\VID_413C&PID_8187\90004EEEF5A6 with the following status: 0xe0000217. I googled the 0xe0000217 error code and it says Bad service install section in the driver inf file... Any ideas on how to fix this? I also tried the post by BetaIQ on MSDN Forum, unfortunately the links to the driver package included in the post were dead :( PS. On a side note I also do mobile development for Android, iOS, and Windows Phone, and BB. Having the bluetooth is quite useful with mobile devices.

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  • Removing Little Snitch completely (Mac OS X Snow Leopard)

    - by Mathias Bynens
    I uninstalled Little Snitch months ago. Or so, I thought. When opening Console.app, I see something like this: Here’s a textual log: 21/11/09 22:05:31 com.apple.launchd[1] (at.obdev.littlesnitchd[10045]) Exited with exit code: 1 21/11/09 22:05:31 com.apple.launchd[1] (at.obdev.littlesnitchd) Throttling respawn: Will start in 10 seconds 21/11/09 22:05:33 Little Snitch UIAgent[10046] 2.0.4.385: m65968c1c 21/11/09 22:05:33 Little Snitch UIAgent[10046] 2.0.4.385: m579328b9 21/11/09 22:05:33 Little Snitch UIAgent[10046] 2.0.4.385: m41531ded 21/11/09 22:05:33 com.apple.launchd.peruser.501[170] (at.obdev.LittleSnitchUIAgent) Throttling respawn: Will start in 10 seconds 21/11/09 22:05:41 com.apple.launchd[1] (at.obdev.littlesnitchd[10049]) Exited with exit code: 1 21/11/09 22:05:41 com.apple.launchd[1] (at.obdev.littlesnitchd) Throttling respawn: Will start in 10 seconds 21/11/09 22:05:43 Little Snitch UIAgent[10050] 2.0.4.385: m65968c1c 21/11/09 22:05:43 Little Snitch UIAgent[10050] 2.0.4.385: m579328b9 21/11/09 22:05:43 Little Snitch UIAgent[10050] 2.0.4.385: m41531ded 21/11/09 22:05:43 com.apple.launchd.peruser.501[170] (at.obdev.LittleSnitchUIAgent) Throttling respawn: Will start in 10 seconds Spotlight searches for ‘little snitch’ or ‘littlesnitch’ yield no results. Yet, it seems like I didn’t get rid of Little Snitch entirely, since it’s still using up my CPU. Any ideas?

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  • How to kill unkillable Python-processes running as root

    - by Andrei
    I am experiencing an annoying problem with sshuttle running it on 10.7.3, MBA with the latest firmware update -- after I stop it (ctrl+c twice), or loose connection, or close the lid, I cannot restore it until I restart the system. The restarting takes notably more time, than it would normally take. I have tried to flush ipfw rules - not helping. Could you advice me how to restore sshuttle connection (without restarting os)? The following processes remain running as root, which I do not know how to kill (tried sudo kill -9 <pid> with no luck): root 14464 python ./main.py python -v -v --firewall 12296 12296 root 14396 python ./main.py python -v -v --firewall 12297 12297 root 14306 python ./main.py python -v -v --firewall 12298 12298 root 3678 python ./main.py python -v -v --firewall 12299 12299 root 2263 python ./main.py python -v -v --firewall 12300 12300 The command I use to run proxy: ./sshuttle --dns -r [email protected] 10.0.0.0/8 -vv The last message I get trying to restore the connection: ... firewall manager: starting transproxy. s: Ready: 1 r=[4] w=[] x=[] s: < channel=0 cmd=PING len=7 s: > channel=0 cmd=PONG len=7 (fullness=554) s: mux wrote: 15/15 s: Waiting: 1 r=[4] w=[] x=[] (fullness=561/0) >> ipfw -q add 12300 check-state ip from any to any >> ipfw -q add 12300 skipto 12301 tcp from any to 127.0.0.0/8 >> ipfw -q add 12300 fwd 127.0.0.1,12300 tcp from any to 10.0.0.0/8 not ipttl 42 keep-state setup >> ipfw -q add 12300 divert 12300 udp from any to 10.0.1.1/32 53 not ipttl 42 >> ipfw -q add 12300 divert 12300 udp from any 12300 to any not ipttl 42 Update: $ ps -ax|grep python 1611 ?? 0:06.49 python ./main.py python -v -v --firewall 12300 12300 48844 ?? 0:00.05 python ./main.py python -v -v --firewall 12299 12299 49538 ttys000 0:00.00 grep python

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  • Active Directory Domain Services - Network Name Cannot be Found

    - by Arief
    I have really weird problem that I could not explain. I am trying to redirect all users home folder to the new server. I have copied all the files including the permissions to the new server. All I need to do is to update the user profile for home folder by changing the server name. However, I got this message when I enter the new server name: My server that serving as AD can resolve the name by ping and nslookup of the server name. The only thing that I don't understand why the MMC cannot resolve the name. I did change with the IP Address and I still get the same error message. Thank you so much for your help. UPDATE: I know what seems to be a problem, but I don't know how to fix it. The new server that will serve all Home folder is actually sitting in the cloud with different IP Address as the Domain Controller. The Domain Controller is sitting locally in the office with 10.0.0.0/24 IP Addresses. The new server that is sitting in on Data Centre is on 172.10.10.10/24 IP Addresses. The static route has been set up on both end, and the DNS as well. I believe this is the issue. Does anyone how to overcome this situation? Thank you.

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  • What's the best way to telnet from a remote Windows PC without using RDP?

    - by Rob D.
    Three Networks: 10.1.1.0 - Mine 172.1.1.0 - My Branch Office 172.2.2.0 - My Branch Office's VOIP VLAN. My PC is on 10.1.1.0. I need to telnet into a Cisco router on 172.2.2.0. The 10.1.1.0 network has no routes to 172.2.2.0, but a VPN connects 10.1.1.0 to 172.1.1.0. Traffic on 172.1.1.0 can route to 172.2.2.0. All PCs on 172.1.1.0 are running Windows XP. Without disrupting anyone using those PCs, I want to open a telnet session from one of those PCs to the router on 172.2.2.0. I've tried the following: psexec.exe \\branchpc telnet 172.2.2.1 psexec.exe \\branchpc cmd.exe telnet 172.2.2.1 psexec.exe \\branchpc -c plink -telnet 172.2.2.1 Methods 1 and 2 both failed because telnet.exe is not usable over psexec. Method 3 actually succeeded in creating the connection, but I cannot login because the session registers my carriage return twice. My password is always blank because at the "Username:" prompt I'm effectively typing: Routeruser[ENTER][ENTER] It's probably time to deploy WinRM... Does anyone know of any other alternatives? Does anyone know how I can fix plink.exe so it only receives one carriage return when I use it over psexec?

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  • Wifi network undetectable on a Lenovo G470

    - by Rex
    I have a WPA2 secured network with a visible SSID at home that works perfectly fine with a Dell laptop,a HP netbook and sundry mobile phones. When I try connecting my sister's Lenovo G470, it refuses to detect the wifi network no matter what, but shows up the neighbors' networks. The Lenovo also works correctly at her office. Both laptops run Windows 7. Already tried/checked the following: Manually configure wifi network settings (copied over from the Dell) Ensure there is no MAC address filtering on the router. Ensure router DHCP server is not running out of addresses to assign (I have set it to allocate upto 10). Reboot laptop, router etc. Is this a known problem, and is there anything else one could try? Update - The problematic Lenovo uses Windows 7 Home Basic while the Dell that works uses Home Premium and the HP netbook uses Starter edition - if that makes any difference. Further update - It is able to connect if I reboot into safe mode with networking. However in 'normal' mode it shows up the network sporadically, and then says there was an error connecting to it. All the network parameters, password, encryption, etc etc are EXACTLY the same as they are on the Dell.

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  • Forward all tracif from one IP to another Ip on OS X

    - by Josh
    This is related to this question I just asked... I have two IP address on my iMac I want to "bridge". I'm not sure what the proper terminology is... here's the situation. My iMac has a firewire connection to my laptop and an ethernet connection to the rest of my office. My laptop has an ip of 192.168.100.2 (on the firewire interface). My iMac has an IP of 192.168.100.1 on the firewire interface, and two IPs, 10.1.0.6 and 10.1.0.7, on it's ethernet interface. If I wanted to forward all traffic coming in from 192.168.100.2 on my OS X machine to go out on IP 10.1.0.7, and vice-versa, can this be done? I assume I would use the ipfw command. Essentially I want to "bridge" the firewire network to the ethernet network so my laptop can see all the machines on the 10.1 network, and all those machines can see my laptop at 10.1.0.7. Is this possible?

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  • Unable to connect remotely to Vsftpd server set up on CentOS VirtualBox

    - by ryekayo
    I have set up a Vsftp server using the following instructions provided Here and even went as far as following the commentary at the bottom. But I am unable to connect remotely. When I attempt to use FileZilla or my Ubuntu terminal, I always get: ryan@ryan-Galago-UltraPro:~$ ftp 10.0.x.xx ftp: connect: Connection timed out ftp> I have checked and re-checked iptables conf file and made sure that Port 21 is being Accepted and it is. I have looked this up on the web and decided to try nmap to port scan it and this is what I get for a result: ryan@ryan-Galago-UltraPro:~$ nmap -PN 10.0.xx.xx Starting Nmap 6.40 ( http://nmap.org ) at 2014-08-19 15:01 EDT Nmap scan report for 10.0.xx.xx Host is up. All 1000 scanned ports on 10.0.xx.xx are filtered Nmap done: 1 IP address (1 host up) scanned in 201.38 seconds Is there anything else that I should do or check for? UPDATE: I have tried to ping from the virtual machine to my IP address on Ubuntu and have been successfully able to. I cannot ping to my virtual machine from Ubuntu. I have narrowed this down to possibly being a firewall related issue on Ubuntu's side, but why would I be unable to connect from FileZilla?

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