Search Results

Search found 9193 results on 368 pages for 'batcher sort'.

Page 26/368 | < Previous Page | 22 23 24 25 26 27 28 29 30 31 32 33  | Next Page >

  • Ruby -- looking for some sort of "Regexp unescape" method

    - by RubyNoobie
    I have a bunch of strings that appear to have been double-escaped -- eg, I have "\\014\"\\000\"\\016smoothing\"\\011mean\"\\022color\"\\011zero@\\016" but I want "\014"\000"\016smoothing"\011mean"\022color"\011zero@\016" Is there a method I can use to unescape them? I imagine that I could make a regex to remove 1 backslash from every consecutive n backslashes, but I don't have a lot of regex experience and it seems there ought to be a "more elegant" way to do it. For example, when I puts MyString it displays the output I'd like, but I don't know how I might capture that into a variable. Thanks! Edited to add context: I have this class that is being used to marshal / restore some stuff, but when I restore some old strings it spits out a type error which I've determined is because they weren't -- for some inexplicable reason -- stored as base64. They instead appear to be 'double-escaped', when I need them to be 'single-escaped' to get restored. require 'base64' class MarshaledStuff < ActiveRecord::Base validates_presence_of :marshaled_obj def contents obj = self.marshaled_obj return Marshal.restore(Base64.decode64(obj)) end def contents=(newcontents) self.marshaled_obj = Base64.encode64(Marshal.dump(newcontents)) end end

    Read the article

  • How to sort HashSet() function data in sequence?

    - by vincent low
    I am new to Java, the function I would like to perform is to load a series of data from a file, into my hashSet() function. the problem is, I able to enter all the data in sequence, but I can't retrieve it out in sequence base on the account name in the file. Can anyone help? below is my code: public Set retrieveHistory(){ Set dataGroup = new HashSet(); try{ File file = new File("C:\\Documents and Settings\\vincent\\My Documents\\NetBeansProjects\\vincenttesting\\src\\vincenttesting\\vincenthistory.txt"); BufferedReader br = new BufferedReader(new FileReader(file)); String data = br.readLine(); while(data != null){ System.out.println("This is all the record:"+data); Customer cust = new Customer(); //break the data based on the , String array[] = data.split(","); cust.setCustomerName(array[0]); cust.setpassword(array[1]); cust.setlocation(array[2]); cust.setday(array[3]); cust.setmonth(array[4]); cust.setyear(array[5]); cust.setAmount(Double.parseDouble(array[6])); cust.settransaction(Double.parseDouble(array[7])); dataGroup.add(cust); //then proced to read next customer. data = br.readLine(); } br.close(); }catch(Exception e){ System.out.println("error" +e); } return dataGroup; } public static void main(String[] args) { FileReadDataModel fr = new FileReadDataModel(); Set customerGroup = fr.retrieveHistory(); System.out.println(e); for(Object obj : customerGroup){ Customer cust = (Customer)obj; System.out.println("Cust name :" +cust.getCustomerName()); System.out.println("Cust amount :" +cust.getAmount()); }

    Read the article

  • wordpress use table sort functionality in own plugin

    - by choise
    Hi, im creating a own plugin for wordpress where i have to view a set of data. now i want to use the wordpress default table view to display my data, and give some functionality to it default table: is there a way to use this table view for my own plugins (some classes or functions) or do i have to create something similar by myself?

    Read the article

  • Sort/Group XML data with PHP?

    - by Volmar
    I'm trying to make a page using data from the discogs.com (XML)-API. i've been parsing it with simpleXML and it's working pretty well but there is some things i'm not sure how to do. Here is part of the XML: <releases> <release id="1468764" status="Accepted" type="Main"> <title>Versions</title> <format>12", EP</format> <label>Not On Label</label> <year>1999</year> </release> <release id="72246" status="Accepted" type="Main"> <title>The M.O.F Blend</title> <format>LP</format> <label>Blenda Records</label> <year>2002</year> </release> <release id="890064" status="Accepted" type="Main"> <title>The M.O.F Blend</title> <format>CD</format> <label>Blenda Records</label> <year>2002</year> </release> <release id="1563561" status="Accepted" type="TrackAppearance"> <title>Ännu En Gång Vol. 3</title> <trackinfo>Backtrack</trackinfo> <format>Cass, Comp, Mix</format> <label>Hemmalaget</label> <year>2001</year> </release> </releases> What i want to achieve is something similair to how discogs presents the releases: http://www.discogs.com/artist/Mics+Of+Fury where diferent versions of the same release are sorted together. (see. The M.O.F Blend in my link) This is done on discogs with having a master release that features the other releases. unfortunately this information isn't present in the API data, so i want to do the same thing by grouping the <release>-nodes with the same <title>-tags, or add a flag to the <releases> that don't have a unique <title>? any good ideas on the best way of doing this? i also like to know if it's possible to count the <release>-nodes (child of releases) that have the same type-attribute? like in this example count the releases with the type "Main"? maybe it's better to do this things with XMLReader or XPath?

    Read the article

  • Sort CMap Key by String Length

    - by Yan Cheng CHEOK
    Previously, I am using STL map to perform the mentioned task. struct ltstr { bool operator()(std::string s1, std::string s2) const { const int l1 = s1.length(); const int l2 = s2.length(); if (l1 == l2) { // In alphabetical order. return s1.compare(s2) < 0; } // From longest length to shortest length. return l1 > l2; } }; std::map<std::string, int, ltstr> m; How can I perform the same task using CMap? // How to make key sorted by string length? CMap<CString, LPCTSTR, int, int> m;

    Read the article

  • Sqlite3 activerecord :order => "time DESC" doesn't sort

    - by Ole Morten Amundsen
    rails 2.3.4, sqlite3 I'm trying this Production.find(:all, :conditions = ["time ?", start_time.utc], :order = "time DESC", :limit = 100) The condition works perfectly, but I'm having problems with the :order = time DESC. By chance, I discovered that it worked at Heroku (testing with heroku console), which runs PostgreSQL. However, locally, using sqlite3, new entries will be sorted after old ones, no matter what I set time to. Like this (output has been manually stripped): second entry is new: Production id: 2053939460, time: "2010-04-24 23:00:04", created_at: "2010-04-24 23:00:05" Production id: 2053939532, time: "2010-04-25 10:00:00", created_at: "2010-04-27 05:58:30" Production id: 2053939461, time: "2010-04-25 00:00:04", created_at: "2010-04-25 00:00:04" Production id: 2053939463, time: "2010-04-25 01:00:04", created_at: "2010-04-25 01:00:04" Seems like it sorts on the primary key, id, not time. Note that the query works fine on heroku, returning a correctly ordered list! I like sqlite, it's so KISS, I hope you can help me... Any suggestions?

    Read the article

  • Trying to work with a multi-value array in LotusScript and sort of stuck

    - by rrumaner
    I have to find a way to store a series of variables - MonthYear (the key) and a counter. The purpose of this is to track the number of documents processed by Month & Year. I was thinking of a list but I am not sure how to save the data so that it is readable and able to be shown in a table at a later date. I thought about using a multi-dimensional array - someArray(1,0 to 1) and ReDim'ing it each time I start a new MonthYear and then save it back to a field on the document but am not sure how that is going to play out. Does anyone have an idea of how I can accomplish this? The first dimension will be the MonthYear (key) and the second will be a counter that is updated every time a new document is processed. The key will be based on a field on the document being processed. How can I make sure I am updating the right key/counter combination? How can I retrieve the existing counter from the field on the document, update the counter and then replace the value? I thought about just adding a new element (ReDim) every time a document is processed and than somehow adding up all the counters for each key and storing that in an array, but that just seems real messy. There has to be a good way to do this. Any and all ideas will be greatly appreciated

    Read the article

  • php - arrange array to display in score order

    - by Phil Jackson
    hi, i have wrote a script to produce an array of data but now want to display in order of score. The array outputs as follows; [display_name] => Array ( [0] => ACT_Web_Designs [1] => user1_design [2] => user2_design ) [proffesion] => Array ( [0] => Web Developer [1] => web developer [2] => Web Developer ) [score] => Array ( [0] => 15 [1] => 6 [2] => 15 ) [img] => Array ( [0] => ./?0000=gif&0001=3fadb8c362ff39f3322909899ff14760&0002=prof_pic [1] => [2] => ) so in a nutshell I am wanting it to be converted as follows; [display_name] => Array ( [0] => ACT_Web_Designs [1] => user2_design [2] => user1_design ) [proffesion] => Array ( [0] => Web Developer [1] => web developer [2] => Web Developer ) [score] => Array ( [0] => 15 [1] => 15 [2] => 6 ) [img] => Array ( [0] => ./?0000=gif&0001=3fadb8c362ff39f3322909899ff14760&0002=prof_pic [1] => [2] => ) I have been looking at asort() but cant get anything to work. any help would be much appreciated.

    Read the article

  • Sorting 2D array of chars C++

    - by user69514
    I have a 2d array of chars where in each row I store a name... such as this: J O H N P E T E R S T E P H E N A R N O L D J A C K How should I go about sorting the array so that I end up with A R N O L D J A C K J O H N P E T E R S T E P H E N These is a 2d array of chars..... no strings or char points.....

    Read the article

  • effective functional sort

    - by sreservoir
    I'm programming a function for a TI-NSpire, so I can't use the builtins from inside a function. What is the most generally efficient algorithm for sorting a list of numbers without modifying the list itself? (recursion and list-splitting are fair game, as is general use of math.)

    Read the article

  • php: sort and count instances of words in a given string

    - by superUntitled
    Hello, I need help sorting and counting instances of the words in a string. Lets say I have a collection on words: happy beautiful happy lines pear gin happy lines rock happy lines pear How could I use php to count each instance of every word in the string and output it in a loop: There are $count instances of $word So that the above loop would output: There are 4 instances of happy. There are 3 instances of lines. There are 2 instances of gin.... Thank you for your genius.

    Read the article

  • Group and sort blog posts by date in Rails

    - by Senthil
    I've searched all over web and have not found the answer. I'm trying to have a very standard archive option for my blog based on date. A request to url blog.com/archive/2009 shows all posts in 2009, blog.com/archive/2009/11 shows all posts in November 2009 etc. I found two different of code but not very helpful to me. def display_by_date year = params[:year] month = params[:month] day = params[:day] day = '0'+day if day && day.size == 1 @day = day if (year && month && day) render(:template => "blog/#{year}/#{month}/#{date}") elsif year render(:template => "blog/#{year}/list") end end def archive year = params[:year] month = params[:month] day = params[:day] day = '0'+day if day && day.size == 1 if (year && month && day) @posts_by_month = Blog.find(:all, :conditions => ["year is?", year]) else @posts_by_month = Blog.find(:all).group_by { |post| post.created_at.strftime("%B") } end end Any help is appreciated.

    Read the article

  • question about LSD radix sort

    - by davit-datuashvili
    hello i have following code public class LSD{ public static int R=1<<8; public static int bytesword=4; public static void radixLSD(int a[],int l,int r){ int aux[]=new int[a.length]; for (int d=bytesword-1;d>=0;d--){ int i, j; int count[]=new int[R+1]; for ( j=0;j<R;j++) count[j]=0; for (i=l;i<=r;i++) count[digit(a[i],d)+1]++; for (j=1;j<R;j++) count[j]+=count[j-1]; for (i=l;i<=r;i++) aux[count[digit(a[i],d)]++]=a[i]; for (i=l;i<=r;i++) a[i]=aux[i-1]; } } public static void main(String[]args){ int a[]=new int[]{3,6,5,7,4,8,9}; radixLSD(a,0,a.length-1); for (int i=0;i<a.length;i++){ System.out.println(a[i]); } } public static int digit(int n,int d){ return (n>>d)&1; } } but it show me mistake java.lang.ArrayIndexOutOfBoundsException: -1 at LSD.radixLSD(LSD.java:19) at LSD.main(LSD.java:29) please help me

    Read the article

  • sort array with special characters in php

    - by Enkay
    I have an array I'm trying to asort using php. The problem is that the array has accented characters in it and needs to be sorted using "french" rules. cote < côte < coté < côté I've tried many things, like using php collators, but I get the following error : PHP Fatal error: Class 'Collator' not found I've also tried to set locale but it didn't do anything so I'm not sure I was doing it right, or if I need to isntall the locale. I'm a little confused. I'm using PHP 5.2.4 if that helps. If I use asort without anything, it puts all the words with accented characters at the end. Thanks.

    Read the article

  • Need some sort of "conditional grouping" in MySQL.

    - by serg555
    I have Article table: id | type | date ----------------------- 1 | A | 2010-01-01 2 | A | 2010-01-01 3 | B | 2010-01-01 Field type can be A, B or C. I need to run a report that would return how many articles of each type there is per every day, like this: date | count(type="A") | count(type="B") | count(type="C") ----------------------------------------------------- 2010-01-01 | 2 | 1 | 0 2010-01-02 | 5 | 6 | 7 Currently I am running 3 queries for every type and then manually merging the results select date, count(id) from article where type="A" group by date Is it possible to do this in one query? (in pure sql, no stored procedures or anything like that). Thanks

    Read the article

  • Java - PriorityQueue vs sorted LinkedList

    - by msr
    Hello, Which implementation is less "heavy": PriorityQueue or a sorted LinkedList (using a Comparator)? I want to have all the items sorted. The insertion will be very frequent and ocasionally I will have to run all the list to make some operations. Thank you!

    Read the article

  • Controlling Solr score/sort

    - by Znarkus
    I want to filter a property within a range, but items that does not have the property should come last in the result. My solution was to set it to -1 if the property was not set. +(property:[10000000001 TO 10000000019] property:"-1"^0.5) This doesn't work, since every document with property:-1 get a very high score, for some reason. Is there a way to reliably control the sorting here? Boosting the range instead would mean I must boost every other term, which I'd rather not do.

    Read the article

  • Split String in C# without delimiter (sort of)

    - by Zach
    Hi, I want to split a string in C#.NET that looks like this: string Letters = "hello"; and put each letter (h, e, l, l, o) into an array or ArrayList. I have no idea what to use as the delimiter in String.Split(delimiter). I can do it if the original string has commas (or anything else): string Letters = "H,e,l,l,o"; string[] AllLettersArray = Letters.Split(",".ToCharArray()); But I have no idea what to use in a case with (supposedly) no delimiter. Is there a special character like Environment.Newline? Thanks.

    Read the article

  • Sort months ( with strings ) algorithm

    - by Oscar Reyes
    I have this months array: ["January", "March", "December" , "October" ] And I want to have it sorted like this: ["January", "March", "October", "December" ] I'm currently thinking in a "if/else" horrible cascade but I wonder if there is some other way to do this. The bad part is that I need to do this only with "string" ( that is, without using Date object or anything like that ) What would be a good approach?

    Read the article

< Previous Page | 22 23 24 25 26 27 28 29 30 31 32 33  | Next Page >