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• Converting a stopwatch time to milliseconds (regex)

  - by Nick

  I'm trying to figure out the best way to convert a string containing a time to an integer number of milliseconds. I'm using a suboptimal way using a bunch of preg_match()'s and some array handling, but I was wondering if there was an elegant way. Here are some example stopwatch times (some wouldn't actually be seen on a stopwatch but need to be converted anyway): 3:34:05.81 34:05 5 (just 5 seconds) 89 (89 seconds) 76:05 (76 minutes, 5 seconds) Millseconds will not extend past 2 decimal places. You can give me an example using either PHP or Javascript regex functions. Thanks!

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• Performing regex on a stream

  - by takoi

  I have some large text files which im going to preform consecutive matching on (just capturing, not replacing). Im thinking its not such a good idea to keep the whole file in memory, but rather use a Reader. What i know about the input is that if there's a match, its not going to span more than 5 lines. So my idea was to have some sort of buffer which just keeps these 5 lines, or so, do the first search, and continue. But it has to "know" where the regex match ended for this to work. e.g if the match ends at line 2 it should start the next search from here. Is it possible to do something like this in an efficient way?

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• Bash script with regex not behaving on Ubuntu

  - by user265330

  I have a Bash script that is working on my OpenSuSE box, but when copied across to my Ubuntu box, is not working. The script reads in from a file. The file has fields separated by white space (tabs and spaces). #!/bin/bash function test1() { while read LINE do if [[ $LINE =~ "^$" || $LINE =~ "^#.*" ]] ; then continue; fi set -- $LINE local field1=$1 local field2=$2 done < test.file } test1 with test.file containing: # Field1Header Field2Header abcdef A-2 ghijkl B-3 There seem to be two problems: (1) $field2, the one with the hyphen, is blank (2) The regex to strip out the blank lines and lines that start with # is not working Anyone know what's wrong? As I said, it works fine on OpenSuSE. Thanks, Paul

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• Test/expand my email regex

  - by Ross

  I'm really not confident with Regex, I know some basic syntax but not enough to keep me happy. I'm trying to build a regular expression to check if an email is valid. So far here's what I've got: [A-Za-z0-9._-]+@[A-Za-z0-9]+.[A-Za-z.]+ It needs to take account of periods in the username/domain and I think it works with multiple TLDs (e.g. co.uk). I'm working with the preg engine in PHP so it needs to work with that. Thanks if you can help!

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• Excluding a specific substring from a regex

  - by Matt S

  I'm attempting to mangle a SQL query via regex. My goal is essentially grab what is between FROM and ORDER BY, if ORDER BY exists. So, for example for the query: SELECT * FROM TableA WHERE ColumnA=42 ORDER BY ColumnB it should capture TableA WHERE ColumnA=42, and it should also capture if the ORDER BY expression isn't there. The closest I've been able to come is SELECT (.*) FROM (.*)(?=(ORDER BY)) which fails without the ORDER BY. Hopefully I'm missing something obvious. I've been hammering in Expresso for the past hour trying to get this.

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• Regex to *not* match any characters

  - by Erick

  I know it is quite some weird goal here but for a quick and dirty fix for one of our system we do need to not filter any input and let the corruption go into the system. My current regex for this is "\^.*" The problem with that is that it does not match characters as planned ... but for one match it does work. The string that make it not work is ^@jj (basically anything that has ^ ... ). What would be the best way to not match any characters now ? I was thinking of removing the \  but only doing this will transform the "not" into a "start with" ...

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• RewriteRule not working do not know how to test it the regex matches

  - by user564559

  Hello I have a Rewrite rule I am trying to implement on my local host but I cannot get it to do the action no matter how I setup the regex the files are in this naming scheme /docroot/css/stylesheet.min.css and I have them printed in the code like /docroot/css/stylesheet.min.123438348.css (the number is example it comes from a get modified function). Note docroot is an example directory how can I have the server ignore the numbers and redirect to the stylesheet.min.css I need to do this for every css and js files (/js and /css) as well as one specific spritemap image my current attempt RewriteRule ^/(docroot)/(js|css)/(.+)\.(min)\.(.+)\.(js|css)$ /$1/$2/$3.$4.$6 RewriteRule ^(/docroot/images/spritemap)\.([0-9]+)\.(png)$ $1.$3 I have this wrapped in a I am on linux..should this be mod_rewrite.so?"

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• Javascript Regex: how to remove string before > and including >

  - by Kim Jong Woo

  I have a string like so item[3]>something>another>more[1]>here hey>this>is>something>new . . . I would like to produce the following for each iteration indicated by each new line item[3]>something>another>more[1]>here something>another>more[1]>here another>more[1]>here more[1]>here here Another example: hey>this>is>something>new this>is>something>new is>something>new something>new new I would like a regex or some way to incrementally remove the furthest left string up to .

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• Regular expression for a string containing one word but not another

  - by Chris Stahl

  I'm setting up some goals in Google Analytics and could use a little regex help. Lets say I have 4 URLs http://www.anydotcom.com/test/search.cfm?metric=blah&selector=size&value=1 http://www.anydotcom.com/test/search.cfm?metric=blah2&selector=style&value=1 http://www.anydotcom.com/test/search.cfm?metric=blah3&selector=size&value=1 http://www.anydotcom.com/test/details.cfm?metric=blah&selector=size&value=1 I want to create an expression that will identify any URL that contains the string selector=size but does NOT contain details.cfm I know that to find a string that does NOT contain another string I can use this expression: (^((?!details.cfm).)*$) But, I'm not sure how to add in the selector=size portion. Any help would be greatly appreciated!

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• Regex to replace a string in HTML but not within a link or heading

  - by Vladimir

  I am looking for a regex to replace a given string in a html page but only if the string is not a part of the tag itself or appearing as text inside a link or a heading. Examples: Looking for 'replace_me' <p>You can replace_me just fine</p> OK <a href='replace_me'>replace_me</a> no match <h3>replace_me</h3> no match <a href='/test/'><span>replace_me</span></a> no match <p style="background:url('replace_me')">replace_me<h1>replace_me</h1></p> first no match, second OK, third no match Thanks in advance!

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• RegEx - character not before match

  - by danneth

  I understand the consepts of RegEx, but this is more or less the first time I've actually been trying to write some myself. As a part of a project, I'm attempting to parse out strings which match to a certain domain (actually an array of domains, but let's keep it simple). At first I started out with this: url.match('www.example.com') But I noticed I was also getting input like this: http://www.someothersite.com/page?ref=http://www.example.com These rows will ofcourse match for www.example.com but I wish to exclude them. So I was thinking along these lines: Only match rows that contain www.example.com, but not after a ? character. This is what I came up with: var reg = new RegExp("[^\\?]*" + url + "(\\.*)", "gi"); This does however not seem to work, any suggestions would be greatly appreciated as I fear I've used what little knowledge I yet possess in the matter.

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• Javascript string.replace with regex

  - by Jimbo

  I want to replace a url querystring parameter with a new value if it already exists or add it on if not. e.g. The current url could be: a. www.mysite.com/whatever.asp?page=5&version=1 OR b. www.mysite.com/whatever.asp?version=1 I need the resulting url to be www.mysite.com/whatever.asp?page=1&version=1 I suspect I can use string.replace with a regex to do this the most intelligent way but am hoping for a little help with it from someone more experienced with regexs :) Thanks!

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• How do I insert format str and don't remove the matched regular expression in input string in boost:

  - by Yadollah

  I want to put space between punctuations and other words in a sentence. But boost::regex_replace() replaces the punctuation with space, and I want to keep a punctuation in the sentence! for example in this code the output should be "Hello . hi , " regex e1("[.,]"); std::basic_string<char> str = "Hello.hi,"; std::basic_string<char> fmt = " "; cout<<regex_replace(str, e1, fmt)<<endl; Can you help me?

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• Get n Number of words using regex in Java

  - by Aymon Fournier

  I have a section of a book, complete with punctuation, line breaks etc. and I want to be able to extract the first n words from the text, and divide that into 5 parts. Regex mystifies me. This is what I am trying. I creates an array of index size 0, with all the input text: public static String getNumberWords2(String s, int nWords){ String[] m = s.split("([a-zA-Z_0-9]+\b.*?)", (nWords / 5)); return "Part One: \n" + m[1] + "\n\n" + "Part Two: \n" + m[2] + "\n\n" + "Part Three: \n" + m[3] + "\n\n" + "Part Four: \n" + m[4] + "\n\n" + "Part Five: \n" + m[5]; } Thanks!

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• How to test a regex password in Python?

  - by jCuga

  Using a regex in Python, how can I verify that a user's password is: At least 8 characters Must be restricted to, though does not specifically require any of: uppercase letters: A-Z lowercase letters: a-z numbers: 0-9 any of the special characters: @#$%^&+= Note, all the letter/number/special chars are optional. I only want to verify that the password is at least 8 chars in length and is restricted to a letter/number/special char. It's up to the user to pick a stronger / weaker password if they so choose. So far what I have is: import re pattern = "^.*(?=.{8,})(?=.*\d)(?=.*[a-z])(?=.*[A-Z])(?=.*[@#$%^&+=]).*$" password = raw_input("Enter string to test: ") result = re.findall(pattern, password) if (result): print "Valid password" else: print "Password not valid"

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• C# Regex: only letters followed by an optional .

  - by TheDude

  Hello, I am looking for a way to get words out of a sentence. I am pretty far with the following expression: \b([a-zA-Z]+?)\b but there are some occurrences that it counts a word when I want it not to. E.g a word followed by more than one period like "text..". So, in my regex I want to have the period to be at the end of a word zero or one time. Inserting .? did not do the trick, and variations on this have not yielded anything fruitful either. Hope someone can help!

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• Text replace with regex in SQL Server

  - by Thiyaneshwaran S

  Currently I have a SQL server column of type nvarchar(max) which has text that starts with <span class="escape_<<digits>>"></span> The only thing that varies in the pattern is the <<digits>> in the class name. The common part is <span class="myclass_ and the closing </span> Some sample values are <span class="myclass_12"></span> <span class="myclass_234"></span> <span class="myclass_4546"></span> These span text are present only at the beginning of the column. Any such matching span in the middle should not be removed or matched. Whats the SQL Server query with regex to remove all these occurances of span?

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• Return result of block passed to #scan during regex

  - by Oli

  I've searched and not been able to find the right way of doing what I'm trying to. I read a file line by line and want to create a new object from a regex on each line. I'm not using an XML parser because the data is not well formed and listed below is all I need to get from each line. I can't seem to get scan to return the result of the block. It just returns the original string. I have temporarily gotten around it by creating this temp variable, but I'm sure there is a better way. enum = File.foreach(filename) enum.map do |line| temp = nil line.scan(/<cab id="(\w+)" updates="(\d+)"/) { |a,b| temp = Cab.new(a,b) } temp end Thanks for any help.

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• Python: Regex outputs 12_34 - I need 1234

  - by Guy F-W

  So I have input coming in like: 12_34 5_6_8_2 4___3 1234 and the output I need from it is: 1234, 5682, 43, 1234 I'm currently working with r'[0-9]+[0-9_]*'.replace('_','') which (as far as I can tell) successfully rejects any input which is not a combination of numeric digits and under-scores, where the underscore cannot be the first character. However, replacing the _ with the empty string causes 12_34 to come out as 12 and 34. Is there a better method than 'replace' for this? Or could I adapt my regex to deal with this problem?

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• Extract and replace named group regex

  - by user557670

  I was able to extract href value of anchors in an html string. Now, what I want to achieve is extract the href value and replace this value with a new GUID. I need to return both the replaced html string and list of extracted href value and it's corresponding GUID. Thanks in advance. My existing code is like: Dim sPattern As String = "<a[^>]*href\s*=\s*((\""(?<URL>[^\""]*)\"")|(\'(?<URL>[^\']*)\')|(?<URL>[^\s]* ))" Dim matches As MatchCollection = Regex.Matches(html, sPattern, RegexOptions.IgnoreCase Or RegexOptions.IgnorePatternWhitespace) If Not IsNothing(matches) AndAlso matches.Count > 0 Then Dim urls As List(Of String) = New List(Of String) For Each m As Match In matches urls.Add(m.Groups("URL").Value) Next End If Sample HTML string: <html><body><a title="http://www.google.com" href="http://www.google.com">http://www.google.com</a><br /><a href="http://www.yahoo.com">http://www.yahoo.com</a><br /><a title="http://www.apple.com" href="http://www.apple.com">Apple</a></body></html>

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• Java splitting string by custom regex match

  - by slikz

  I am completely new to regular expressions so I'm looking for a bit of help here. I am compiling under JDK 1.5 Take this line as an example that I read from standard input: ab:Some string po:bubblegum What I would like to do is split by the two characters and colon. That is, once the line is split and put into a string array, these should be the terms: ab:Some string po:bubblegum I have this regex right now: String[] split = input.split("[..:]"); This splits at the semicolon; what I would like is for it to match two characters and a semicolon, but split at the space before that starts. Is this even possible? Here is the output from the string array: ab Some String po bubblegum I've read about Pattern.compile() as well. Is this something I should be considering?

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• Regex to match a Java method signature

  - by nitesh

  I am having this particular requirement where a method has to be identified by different regular expressions for different components. For example, there need to be a regex for return parameter, one for method name, one for argument type and one for argument name. I was able to come up with an expression till this step as follows - ([^,]+) ([^,]+)\((([^,]+) ([^,]+))\) It works well for a method signature like - ReturnType foo(Arg parameter) The regular expression identifies ReturnType, foo, Arg and parameter separately. Now the problem is that a method can have no/one/multiple arguments separated by commas. I am not able to get a repeating expression for this. Help will be appreciated.

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• My Java regex isn't capturing the group

  - by Geo

  I'm trying to match the username with a regex. Please don't suggest a split. USERNAME=geo Here's my code: String input = "USERNAME=geo"; Pattern pat = Pattern.compile("USERNAME=(\\w+)"); Matcher mat = pat.matcher(input); if(mat.find()) { System.out.println(mat.group()); } why doesn't it find geo in the group? I noticed that if I use the .group(1), it finds the username. However the group method contains USERNAME=geo. Why?

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• Regular Expression to Match All Characters after another Regex Match

  - by Anthony Wood

  I know this may sound a little confusing, so I am open to suggestions on renaming the title. Basically I have string such as C:...\Downloads\Folder\SubFolder\SubSubFolder. and I want to return the SubFolder and SubSubFolder only. So far, my Regex looks like (?=\\Downloads\\.*?\\).* which matches Downloads\Folder\SubFolder\SubSubFolder. Does anybody have any Ideas what I am missing???? All the solutions below seem to work (except if you didn't know "Folder"). Potentially a bug with the tool I was using to test the regular expressions.

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• varnish invalidate url REGEX from backend

  - by ooouuiii

  Say I have some highly-visited front-page, which displays number of some items by categories. When some item is added / deleted I need to invalidate this front-page/url and some 2 others. What is the best practice how to invalidate those urls from backend in Varnish (4.x)? From what I captured, I can: implement my HTTP PURGE handler in VCL configuration file, that "bans" urls matching received regex from backend to Varnish, send 3x HTTP PURGE requests for those 3 urls. But is this approach safe for this automatic usage? Basicly I need to invalidate some views everytime some related entity is inserted/updated/deleted. Can it lead to ban list cumulation and increasing CPU consumption? Is there any other approach? Thanks.

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