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  • Different routing rules for a particular user using firewall mark and ip rule

    - by Paul Crowley
    Running Ubuntu 12.10 on amd64. I'm trying to set up different routing rules for a particular user. I understand that the right way to do this is to create a firewall rule that marks the packets for that user, and add a routing rule for that mark. Just to get testing going, I've added a rule that discards all packets as unreachable: # ip rule 0: from all lookup local 32765: from all fwmark 0x1 unreachable 32766: from all lookup main 32767: from all lookup default With this rule in place and all firewall chains in all tables empty and policy ACCEPT, I can still ping remote hosts just fine as any user. If I then add a rule to mark all packets and try to ping Google, it fails as expected # iptables -t mangle -F OUTPUT # iptables -t mangle -A OUTPUT -j MARK --set-mark 0x01 # ping www.google.com ping: unknown host www.google.com If I restrict this rule to the VPN user, it seems to have no effect. # iptables -t mangle -F OUTPUT # iptables -t mangle -A OUTPUT -j MARK --set-mark 0x01 -m owner --uid-owner vpn # sudo -u vpn ping www.google.com PING www.google.com (173.194.78.103) 56(84) bytes of data. 64 bytes from wg-in-f103.1e100.net (173.194.78.103): icmp_req=1 ttl=50 time=36.6 ms But it appears that the mark is being set, because if I add a rule to drop these packets in the firewall, it works: # iptables -t mangle -A OUTPUT -j DROP -m mark --mark 0x01 # sudo -u vpn ping www.google.com ping: unknown host www.google.com What am I missing? Thanks!

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  • Different nginx rules based on referrer

    - by juana
    I'm using WordPress with WP Super Cache. I want visitors who come from Google (That inlcudes all country specific referrers like google.co.in, google.co.uk and etc.) to see uncached contents. There are my nginx rules which are not working the way I want: server { server_name website.com; location / { root /var/www/html/website.com; index index.php; if ($http_referer ~* (www.google.com|www.google.co) ) { rewrite . /index.php break; } if (-f $request_filename) { break; } set $supercache_file ''; set $supercache_uri $request_uri; if ($request_method = POST) { set $supercache_uri ''; } if ($query_string) { set $supercache_uri ''; } if ($http_cookie ~* "comment_author_|wordpress|wp-postpass_" ) { set $supercache_uri ''; } if ($supercache_uri ~ ^(.+)$) { set $supercache_file /wp-content/cache/supercache/$http_host/$1index.html; } if (-f $document_root$supercache_file) { rewrite ^(.*)$ $supercache_file break; } if (!-e $request_filename) { rewrite . /index.php last; } } location ~ \.php$ { fastcgi_pass 127.0.0.1:9000; fastcgi_index index.php; fastcgi_param SCRIPT_FILENAME /var/www/html/website.com$fastcgi_script_name; include fastcgi_params; } } What should I do to achieve my goal?

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  • htaccess rewrite rules in Nginx: setting the rewrite path

    - by ct2k7
    I have a htaccess file I'm trying to convert into an nignx config file. Here's my htaccess file. RewriteEngine on RewriteCond %{SCRIPT_FILENAME} !-f RewriteCond %{SCRIPT_FILENAME} !-d RewriteRule !\.(jpg|css|js|gif|png)$ public/ [L] RewriteRule !\.(jpg|css|js|gif|png)$ public/index.php?url=$1 And the rules I have in my nginx config file: location / { if ($request_uri !~ "-f"){ rewrite !\.(jpg|css|js|gif|png)$ public/ break; } rewrite !\.(jpg|css|js|gif|png)$ public/index.php?url=$1; } # pass the PHP scripts to FastCGI server listening on 127.0.0.1:9000 location ~ \.php$ { # Move to the @missing part when the file doesn't exist try_files $uri @missing; # Fix for server variables that behave differently under nginx/$ fastcgi_split_path_info ^(.+\.php)(/.+)$; # Include the standard fastcgi_params file included with ngingx include fastcgi_params; fastcgi_param PATH_INFO $fastcgi_path_info; fastcgi_index index.php; # Pass to upstream PHP-FPM; This must match whater you name you$ #fastcgi_pass phpfpm; fastcgi_pass 127.0.0.1:9000; } location @missing { rewrite ^(.*)$ public/index.php?url=$1 break; } However, when I hit /, I get a 403 Forbidden, but I can get to /public/index.php, thus the rewrite isn't working. Any ideas on what I'm doing wrong?

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  • Apache rewrite rules and special characters

    - by Massimo
    I have a server where some files have an actual %20 in their name (they are generated by an automated tool which handles spaces this way, and I can't do anything about this); this is not a space: it's "%" followed by "2" followed by "0". On this server, there is an Apache web server, and there are some web pages which links to those files, using their name in URLs like http://servername/file%20with%20a%20name%20like%20this.html; those pages are also generated by the same tool, so I (again!) can't do anything about that. A full search-and-replace on all files, pages and URLs is out of question here. The problem: when Apache gets called with an URL like the one above, it (correctly) translates the "%20"s into spaces, and then of course it can't find the files, because they don't have actuale spaces in their names. How can I solve this? I discovered than by using an URL like http://servername/file%2520name.html it works nicely, because then Apache translates "%25" into a "%" sign, and thus the correct filename gets built. I tried using an Apache rewrite rule, and I can succesfully replace spaces with hypens with a syntax like this: RewriteRule (.*)\ (.*) $1-$2 The problem: when I try to replace them with a "%2520" sequence, this just doesn't happen. If I use RewriteRule (.*)\ (.*) $1%2520$2 then the resulting URL is http://servername/file520name.html; I've tried "%25" too, but then I only get a "5"; it just looks like the initial "%2" gets somewhat discarded. The questions: How can I build such a regexp to replace spaces with "%2520"? Is this the only way I can deal with this issue (other than a full search-and-replace which, as I said, can't be done), or do you have any better idea?

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  • fail2ban block ports rules iptable

    - by J Spen
    I just installed Ubuntu Server 14.04 and don't have much experience with IPtables. I am trying to get a basic setup going where I only accept SSH connections on port 22 and 2222. I actually have that working with no problem using fail2ban ssh. Then I wanted to block all other ports except 423 and 4242 but either method of DROPing all connections that are not listed seems not to work and it blocks me out of everything. Below is the setup that works: -P INPUT ACCEPT -P FORWARD ACCEPT -P OUTPUT ACCEPT -N fail2ban-ssh -A INPUT -p tcp -m multiport --dports 22,2222 -j fail2ban-ssh -A fail2ban-ssh -j RETURN I tried to change it either to: -P INPUT DROP -P FORWARD ACCEPT -P OUTPUT ACCEPT -N fail2ban-ssh -A INPUT -p tcp -m multiport --dports 22,2222 -j fail2ban-ssh -A fail2ban-ssh -j RETURN or: -P INPUT ACCEPT -P FORWARD ACCEPT -P OUTPUT ACCEPT -N fail2ban-ssh -A INPUT -p tcp -m multiport --dports 22,2222 -j fail2ban-ssh -A INPUT -j DROP -A fail2ban-ssh -j RETURN I have noticed that the rules for fail2ban-ssh are automatically added to my iptables on boot because if I save them with iptables-persistant they are entered twice. How do I go about blocking everything accept those 2 ports using fail2ban? Is it a bad fail2ban configuration or do I need to add the fail2ban-ssh -j Return somewhere else in my code.

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  • Iptables rules, forward between two interfaces

    - by Marco
    i have a some difficulties in configuring my ubuntu server firewall ... my situation is this: eth0 - internet eth1 - lan1 eth2 - lan2 I want that clients from lan1 can't communicate with clients from lan2, except for some specific services. E.g. i want that clients in lan1 can ssh into client in lan2, but only that. Any other comunication is forbidden. So, i add this rules to iptables: #Block all traffic between lan, but permit traffic to internet iptables -I FORWARD -i eth1 -o ! eth0 -j DROP iptables -I FORWARD -i eth2 -o ! eth0 -j DROP # Accept ssh traffic from lan1 to client 192.168.20.2 in lan2 iptables -A FORWARD -i eth1 -o eth2 -p tcp --dport 22 -d 192.168.20.2 -j ACCEPT This didn't works. Doing iptables -L FORWARD -v i see: Chain FORWARD (policy DROP 0 packets, 0 bytes) pkts bytes target prot opt in out source destination 33 144 DROP all -- eth1 !eth0 anywhere anywhere 0 0 DROP all -- eth2 !eth0 anywhere anywhere 23630 20M ACCEPT all -- any any anywhere anywhere state RELATED,ESTABLISHED 0 0 ACCEPT all -- eth1 any anywhere anywhere 175 9957 ACCEPT all -- eth1 any anywhere anywhere 107 6420 ACCEPT all -- eth2 any anywhere anywhere 0 0 ACCEPT all -- pptp+ any anywhere anywhere 0 0 ACCEPT all -- tun+ any anywhere anywhere 0 0 ACCEPT tcp -- eth1 eth2 anywhere server2.lan tcp dpt:ssh All packets are dropped, and the count of packets for the last rule is 0 ... How i have to modify my configuration? Thank you. Regards Marco

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  • converting apache rewrite rules to nginx for xenforo

    - by nick
    Hi all, I am migrating some forums from vbulletin 3.8.x to xenforo, and trying to keep my old link structure alive. Basically, XF provides some php files that I can redirect the old url style to and it handles the proper 301 redirection. Regardless of that end, I am having difficulty rewriting the rules which I can only find defined in apache's rewrite style: RewriteRule [\d]+-[^/]+/.+-([\d]+)/([\d]+)/ showthread.php?t=$1&page=$2 [NC,L] RewriteRule [\d]+-[^/]+/.+-([\d]+)/ showthread.php?t=$1 [NC,L] RewriteRule ([\d]+)-[^/]+/([\d]+)/ forumdisplay.php?f=$1&page=$2 [NC,L] RewriteRule ([\d]+)-[^/]+/ forumdisplay.php?f=$1 [NC,L] I have been experimenting and thought this should work, but obviously not: if (!-e $request_filename) { rewrite [0-9a-zA-Z\-]/[0-9a-zA-Z\-]-([0-9])/([0-9])/ /showthread.php?t=$1&page=$2 last; rewrite [0-9a-zA-Z\-]/[0-9a-zA-Z\-]-([0-9])/ /showthread.php?t=$1 last; rewrite ([0-9])-[0-9a-zA-Z\-]/([0-9])/ /forumdisplay.php?f=$1&page=$2 last; rewrite ([0-9])-[0-9a-zA-Z\-]/ /forumdisplay.php?f=$1 last; rewrite ^(.*)$ /index.php last; } old vB showthread format: website.tld/233-website-issues-requests/wiki-down-73789/ new XF showthread format: website.tld/threads/the-wiki-is-down.65509/ old vB forumdisplay format: website.tld/233-website-issues-requests/ new XF forumdisplay format: website.tld/forums/website-issues-and-requests.253/

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  • Proper Rules For SSL Redirect For Subdomains

    - by Zac Cleaves
    RewriteCond %{HTTP_HOST} ^(.*\.)*subexample.example.com$ [NC] RewriteCond %{SERVER_PORT} !^443$ RewriteRule ^(.*)$ https://subexample.example.com/$1 [R] Is what I have been using. It works as long as I go to a specific page, like subexample.example.com/orders.php. But if you try to go to the root of the subdomain, it adds the extra "/example" at the end. Any suggestion on a set of rules that will work? Thank you so much for your responces! Actually, this is what I am trying to do: http://support.mydomain.net >> https://support.mydomain.net AND(!) http://support.mydomain.net/anypage* >> https://support.mydomain.net/anypage* > RewriteCond %{HTTPS} off RewriteRule (.*) > https://%{HTTP_HOST}%{REQUEST_URI} Works, except I need it to only do it for the support.mydomain.net With the above set up, you get a certificate warning if you try to go just mydomain.net, which I do not have or need an SSL certificate installed on. UPDATE! The other issue with the rule I have written above, is that if you try to go to the root of the subdomain (i.e. support.mydomain.net) it goes to https://support.mydomain.net/support This is driving me crazy, help! =) Any help would be greatly appreciated!

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  • Find all CSS rules that apply to an element

    - by Carl Byström
    Many tools/APIs provide ways of selecting elements of specific classes or IDs. There's also possible to inspect the raw stylesheets loaded by the browser. However, for browsers to render an element, they'll compile all CSS rules (possibly from different stylesheet files) and apply it to the element. This is what you see with Firebug or the WebKit Inspector - the full CSS inheritance tree for an element. How can I reproduce this feature in pure JavaScript without requiring additional browser plugins? Perhaps an example can provide some clarification for what I'm looking for: <style type="text/css"> p { color :red; } #description { font-size: 20px; } </style> <p id="description">Lorem ipsum</p> Here the p#description element have two CSS rules applied: a red color and a font size of 20 px. I would like to find the source from where these computed CSS rules originate from (color comes the p rule and so on).

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  • Handling Complex Rules in in GUI applciations (C++ or C#)

    - by Canacourse
    Im working on a dialog box in which several rules must be satisfied before the OK button is enabled. Currently any action on the page such as entering data or selecting an item from a drop down list (amongst other things) calls a single function called ProcessEvent() - this function handles all logic and either enables or disables the OK button. My problem is I finding it difficult making the rules concise and understandable. Some of the rules can be negated by another action on the dialog and I have now ended up with if else statements all over the place or which are difficult to read and follow & extend. The code below is a simplification of the problem but demonstrates it well. How do I handle this problem better (If its Possible) bool CWorkstation::ProcessEvent(void) { UpdateData(); CharCount = GetDlgItemInt(IDC_CharCount, NULL, FALSE); //get latest if ( IsDlgButtonChecked(IDC_USEDBNAME)) { if (!IsDlgButtonChecked(IDC_MAXDBNAME)) { EnableNext(TRUE); } } if (IsDlgButtonChecked(IDC_MAXDBNAME) && CharCount) { if (IsDlgButtonChecked(IDC_USEXMLNAME)) { if ( PrefixName.IsEmpty() ) { EnableNext(FALSE); } else { EnableNext(TRUE); } } } if (IsDlgButtonChecked(IDC_USEXMLNAME) && PrefixName.GetLength() > 1) { EnableNext(TRUE); } if ( IsDlgButtonChecked(IDC_WSAUTONAME) || IsDlgButtonChecked(IDC_RENAMEIFDUP)) { // TRACE("IDC_WSAUTONAME is Checked\n"); if ( IsDlgButtonChecked(IDC_USEXMLNAME) && PrefixName.GetLength() > 1 ) { if ( IsDlgButtonChecked(IDC_IDC_USESHORTNAME) ) { EnableNext(TRUE); } else if ( IsDlgButtonChecked(IDC_USELONGNAME) ) { EnableNext(TRUE); } else { EnableNext(FALSE); } } if ( !IsDlgButtonChecked(IDC_USEPREFIX) ) { if ( IsDlgButtonChecked(IDC_IDC_USESHORTNAME) || IsDlgButtonChecked(IDC_USELONGNAME) ) { EnableNext(TRUE); } } return false; } }

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  • CakePHP in a subdirectory using nginx (Rewrite rules?)

    - by lhnz
    I managed to get this to work a while back, but on returning to the cakephp project I had started it seems that whatever changes I've made to nginx recently (or perhaps a recent update) have broken my rewrite rules. Currently I have: worker_processes 1; events { worker_connections 1024; } http { include mime.types; default_type application/octet-stream; sendfile on; keepalive_timeout 65; server { listen 80; server_name localhost; location / { root html; index index.php index.html index.htm; } location /basic_cake/ { index index.php; if (-f $request_filename) { break; } if (!-f $request_filename) { rewrite ^/basic_cake/(.+)$ /basic_cake/index.php?url=$1 last; break; } } location /cake_test/ { index index.php; if (-f $request_filename) { break; } if (!-f $request_filename) { rewrite ^/cake_test/(.+)$ /cake_test/index.php?url=$1 last; break; } } # redirect server error pages to the static page /50x.html # error_page 500 502 503 504 /50x.html; location = /50x.html { root html; } # pass the PHP scripts to FastCGI server listening on 127.0.0.1:9000 # location ~ \.php$ { root html; fastcgi_pass 127.0.0.1:9000; fastcgi_index index.php; fastcgi_param SCRIPT_FILENAME $document_root$fastcgi_script_name; include fastcgi_params; } } server { listen 8081; server_name localhost; root /srv/http/html/xsp; location / { index index.html index.htm index.aspx default.aspx; } location ~ \.(aspx|asmx|ashx|asax|ascx|soap|rem|axd|cs|config|dll)$ { fastcgi_pass 127.0.0.1:9001; fastcgi_param SCRIPT_FILENAME $document_root$fastcgi_script_name; include fastcgi_params; } } } The problem that I have is that the css and images will not load from the webroot. Instead if I visit http://localhost/basic_cake/css/cake.generic.css, I get a page which tells me: CakePHP: the rapid development php framework Missing Controller Error: CssController could not be found. Error: Create the class CssController below in file: app/controllers/css_controller.php var $name = 'Css'; } ? Notice: If you want to customize this error message, create app/views/errors/missing_controller.ctp CakePHP: the rapid development php framework Does anybody have any ideas on how to fix this?

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  • Apache (Solaris 10): 2 symlinks to the same file, one works the other doesn't

    - by justcatchingrye
    I'm seeing a strange issue with Apache I have a system that pulls a configuration file from a web server. I want to use a symlink with the name 'ocds-dpsarch01a.rules'. This doesn't work. However, if I change one character in that name and link it to the same file, it works - See below I can't think of any reason why one symlink would work when another doesn't? I would have thought either the Apache configuration is right and all symlinks work, or it isn't and no syslinks work(?) Any thoughts welcome ls -l /REMOVED/apache2/htdocs/rules/syslog/*cds-dpsarch01a.rules lrwxrwxrwx 1 root root 62 May 13 13:55 ocds-dpsarch01a.rules - /REMOVED/apache2/htdocs/templates/syslog/DCM_SST_DPST_01.rules lrwxrwxrwx 1 root root 62 May 13 13:52 xcds-dpsarch01a.rules - /REMOVED/apache2/htdocs/templates/syslog/DCM_SST_DPST_01.rules 1) Application starting and successfully reading configuration from the web server 13/05/2010 13:56:37: Information: Connecting ... 13/05/2010 13:56:37: Debug: Reading REMOVED:// REMOVED /rules/syslog/xcds-dpsarch01a.rules 13/05/2010 13:56:37: Debug: HTTP response: HTTP/1.1 200 OK Date: Thu, 13 May 2010 13:56:34 GMT Server: Apache Last-Modified: Fri, 09 Apr 2010 12:28:26 GMT ETag: "5073-a744-ee92ae80" Accept-Ranges: bytes Content-Length: 42820 Cache-Control: max-age=5 Expires: Thu, 13 May 2010 13:56:39 GMT NL7C-Filtered: Content-Type: text/plain Connection: close 13/05/2010 13:56:37: Debug: Plain text rules file detected. 2) Application starting and failing to read configuration from the web server 13/05/2010 13:56:55: Information: Connecting ... 13/05/2010 13:56:55: Debug: Reading REMOVED :// REMOVED /rules/syslog/ocds-dpsarch01a.rules 13/05/2010 13:56:55: Debug: HTTP response: HTTP/1.1 403 Forbidden Date: Wed, 12 May 2010 15:25:11 GMT Server: Apache Vary: accept-language,accept-charset Accept-Ranges: bytes Connection: close Content-Type: text/html; charset=iso-8859-1 Content-Language: en Expires: Wed, 12 May 2010 15:25:11 GMT 13/05/2010 13:56:55: Error: HTTP: HTTP/1.1 403 Forbidden Date: Wed, 12 May 2010 15:25:11 GMT Server: Apache Vary: accept-language,accept-charset Accept-Ranges: bytes Connection: close Content-Type: text/html; charset=iso-8859-1 Content-Language: en Expires: Wed, 12 May 2010 15:25:11 GMT 13/05/2010 13:56:55: Error: HTTP GET failed 13/05/2010 13:56:55: Error: Failed to open Rules file: REMOVED :// REMOVED /rules/syslog/ocds-dpsarch01a.rules

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  • windows 7 64 bit visual studio 2008 libtiff build nmake error

    - by user1244539
    I am trying to build tiff 4.0.2 on my Windows 7 x64 system with Visual Studio 2008, but it was showing errors: C:\Program Files\Microsoft SDKs\Windows\v6.0A\include\mmsystem.h(2347) : error C2061: syntax error : identifier 'QINT' C:\Program Files\Microsoft SDKs\Windows\v6.0A\include\mmsystem.h(2362) : error C2059: syntax error : '}' C:\Program Files\Microsoft SDKs\Windows\v6.0A\include\mmsystem.h(2397) : error C2061: syntax error : identifier 'JOYCAPS' C:\Program Files\Microsoft SDKs\Windows\v6.0A\include\mmsystem.h(2397) : error C2059: syntax error : ';' C:\Program Files\Microsoft SDKs\Windows\v6.0A\include\mmsystem.h(2398) : error C2061: syntax error : identifier 'PJOYCAPS' C:\Program Files\Microsoft SDKs\Windows\v6.0A\include\mmsystem.h(2398) : error C2059: syntax error : ';' C:\Program Files\Microsoft SDKs\Windows\v6.0A\include\mmsystem.h(2399) : error C2061: syntax error : identifier 'NPJOYCAPS' C:\Program Files\Microsoft SDKs\Windows\v6.0A\include\mmsystem.h(2399) : error C2059: syntax error : ';' C:\Program Files\Microsoft SDKs\Windows\v6.0A\include\mmsystem.h(2400) : error C2061: syntax error : identifier 'LPJOYCAPS' C:\Program Files\Microsoft SDKs\Windows\v6.0A\include\mmsystem.h(2400) : error C2059: syntax error : ';' C:\Program Files\Microsoft SDKs\Windows\v6.0A\include\mmsystem.h(2534) : error C2146: syntax error : missing ')' before identifier 'pjc' C:\Program Files\Microsoft SDKs\Windows\v6.0A\include\mmsystem.h(2534) : error C2081: 'LPJOYCAPSA' : name in formal parameter list illegal C:\Program Files\Microsoft SDKs\Windows\v6.0A\include\mmsystem.h(2534) : error C2061: syntax error : identifier 'pjc' C:\Program Files\Microsoft SDKs\Windows\v6.0A\include\mmsystem.h(2534) : error C2059: syntax error : ';' C:\Program Files\Microsoft SDKs\Windows\v6.0A\include\mmsystem.h(2534) : error C2059: syntax error : ',' C:\Program Files\Microsoft SDKs\Windows\v6.0A\include\mmsystem.h(2534) : error C2059: syntax error : ')' NMAKE: fatal error u1077: "c:\program files(x86)\microsoft visual studio 9.0\vc\bin\cl.exe": return code '0x2' This is what I was doing: Extracted tiff 4.0.2 In VS 2008 x64 Win 7 command prompt setting the environment for x86 by running vcvars32.bat Changing the path to tiff 4.0.2/libtiff folder Running nmake /f makefile.vc to create a static library of libtiff Following these steps in Windows XP generates the .lib file but in Windows 7 it fails. This is the first time I'm making any .lib files.

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  • Installing Catalyst 11.6 for an ATI HD 6970

    - by David Oliver
    Ubuntu Maverick 10.10 is displaying the desktop okay (though limited to 1600x1200) after my having installed my new HD 6970 card, so I'm now trying to install the proprietary driver (I understand the open source one requires a more recent kernel than that in Maverick). The proprietary driver under 'Additional Drivers' resulted in a black screen on boot, so I deactivated and am trying to follow the manual install instructions at the cchtml Ubuntu Maverick Installation Guide. When I try to create the .deb packages with: sh ati-driver-installer-11-6-x86.x86_64.run --buildpkg Ubuntu/maverick I get: david@skipper:~/catalyst11.6$ sh ati-driver-installer-11-6-x86.x86_64.run --buildpkg Ubuntu/maverick Created directory fglrx-install.oLN3ux Verifying archive integrity... All good. Uncompressing ATI Catalyst(TM) Proprietary Driver-8.861......................... ===================================================================== ATI Technologies Catalyst(TM) Proprietary Driver Installer/Packager ===================================================================== Generating package: Ubuntu/maverick Package build failed! Package build utility output: ./packages/Ubuntu/ati-packager.sh: 396: debclean: not found dpkg-buildpackage: export CFLAGS from dpkg-buildflags (origin: vendor): -g -O2 dpkg-buildpackage: export CPPFLAGS from dpkg-buildflags (origin: vendor): dpkg-buildpackage: export CXXFLAGS from dpkg-buildflags (origin: vendor): -g -O2 dpkg-buildpackage: export FFLAGS from dpkg-buildflags (origin: vendor): -g -O2 dpkg-buildpackage: export LDFLAGS from dpkg-buildflags (origin: vendor): -Wl,-Bsymbolic-functions dpkg-buildpackage: source package fglrx-installer dpkg-buildpackage: source version 2:8.861-0ubuntu1 dpkg-buildpackage: source changed by ATI Technologies Inc. <http://ati.amd.com/support/driver.html> dpkg-source --before-build fglrx.64Vzxk dpkg-buildpackage: host architecture amd64 debian/rules build Can't exec "debian/rules": Permission denied at /usr/bin/dpkg-buildpackage line 507. dpkg-buildpackage: error: debian/rules build failed with unknown exit code -1 Cleaning in directory . /usr/bin/fakeroot: line 176: debian/rules: Permission denied debuild: fatal error at line 1319: couldn't exec fakeroot debian/rules: dpkg-buildpackage: export CFLAGS from dpkg-buildflags (origin: vendor): -g -O2 dpkg-buildpackage: export CPPFLAGS from dpkg-buildflags (origin: vendor): dpkg-buildpackage: export CXXFLAGS from dpkg-buildflags (origin: vendor): -g -O2 dpkg-buildpackage: export FFLAGS from dpkg-buildflags (origin: vendor): -g -O2 dpkg-buildpackage: export LDFLAGS from dpkg-buildflags (origin: vendor): -Wl,-Bsymbolic-functions dpkg-buildpackage: source package fglrx-installer dpkg-buildpackage: source version 2:8.861-0ubuntu1 dpkg-buildpackage: source changed by ATI Technologies Inc. <http://ati.amd.com/support/driver.html> dpkg-source --before-build fglrx.QEmIld dpkg-buildpackage: host architecture amd64 debian/rules build Can't exec "debian/rules": Permission denied at /usr/bin/dpkg-buildpackage line 507. dpkg-buildpackage: error: debian/rules build failed with unknown exit code -1 Cleaning in directory . Can't exec "debian/rules": Permission denied at /usr/bin/debuild line 1314. debuild: fatal error at line 1313: couldn't exec debian/rules: Permission denied dpkg-buildpackage: export CFLAGS from dpkg-buildflags (origin: vendor): -g -O2 dpkg-buildpackage: export CPPFLAGS from dpkg-buildflags (origin: vendor): dpkg-buildpackage: export CXXFLAGS from dpkg-buildflags (origin: vendor): -g -O2 dpkg-buildpackage: export FFLAGS from dpkg-buildflags (origin: vendor): -g -O2 dpkg-buildpackage: export LDFLAGS from dpkg-buildflags (origin: vendor): -Wl,-Bsymbolic-functions dpkg-buildpackage: source package fglrx-installer dpkg-buildpackage: source version 2:8.861-0ubuntu1 dpkg-buildpackage: source changed by ATI Technologies Inc. <http://ati.amd.com/support/driver.html> dpkg-source --before-build fglrx.xtY6vC dpkg-buildpackage: host architecture amd64 debian/rules build Can't exec "debian/rules": Permission denied at /usr/bin/dpkg-buildpackage line 507. dpkg-buildpackage: error: debian/rules build failed with unknown exit code -1 Cleaning in directory . /usr/bin/fakeroot: line 176: debian/rules: Permission denied debuild: fatal error at line 1319: couldn't exec fakeroot debian/rules: dpkg-buildpackage: export CFLAGS from dpkg-buildflags (origin: vendor): -g -O2 dpkg-buildpackage: export CPPFLAGS from dpkg-buildflags (origin: vendor): dpkg-buildpackage: export CXXFLAGS from dpkg-buildflags (origin: vendor): -g -O2 dpkg-buildpackage: export FFLAGS from dpkg-buildflags (origin: vendor): -g -O2 dpkg-buildpackage: export LDFLAGS from dpkg-buildflags (origin: vendor): -Wl,-Bsymbolic-functions dpkg-buildpackage: source package fglrx-installer dpkg-buildpackage: source version 2:8.861-0ubuntu1 dpkg-buildpackage: source changed by ATI Technologies Inc. <http://ati.amd.com/support/driver.html> dpkg-source --before-build fglrx.oYWICI dpkg-buildpackage: host architecture amd64 debian/rules build Can't exec "debian/rules": Permission denied at /usr/bin/dpkg-buildpackage line 507. dpkg-buildpackage: error: debian/rules build failed with unknown exit code -1 Removing temporary directory: fglrx-install.oLN3ux I've installed devscripts which has debclean in it. I've tried running the command with and without sudo. I'm not experienced with installing from downloads/source, but it seems like the file debian/source isn't being set to be executable when it needs to be. If I extract only, without using the package builder command, debian/rules is 744. As to what to do next, I'm stumped. Many thanks.

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  • MySQL 5 multiple JOIN syntax not working in MySQL 4

    - by draco
    Hello all, the current SQL query works fine locally on MAMP 1.8.4 running MySQL 5.1.37. SELECT EL.log_actions, EL.log_date, EL.log_value, EL.log_type, EA.admins_name, EU.users_name, EU.users_matric FROM events_log EL JOIN events_users EU USING (users_id) JOIN events_admins EA USING (admins_id) ORDER BY EL.log_id DESC LIMIT 0, 10 However, when I bring this query live to production server which is running MySQL 4.1.22-standard, the following error occurred (whether or not there are data in the entry). A Database Error Occurred Error Number: 1054 Unknown column 'sceclub_exclaim2007.EU.admins_id' in 'on clause' SELECT EL.log_actions, EL.log_date, EL.log_value, EL.log_type, EA.admins_name, EU.users_name, EU.users_matric FROM events_log EL JOIN events_users EU USING (users_id) JOIN events_admins EA USING (admins_id) ORDER BY EL.log_id DESC LIMIT 0, 20 This is based on CodeIgniter 1.7.2 and both production and development are running the same set of database. Database tables events_users: users_id users_name users_credits users_matric users_redeem events_admins: admins_id admins_email admins_name admins_pass admins_date admins_modified admins_last_login events_attendance: attendance_id users_id events_id events_events: events_id events_name events_venue events_time events_desc events_pass events_log:log_id admins_id log_actions log_date log_value users_id log_type I'm new to MySQL so I'm not aware of any difference in versions or what could be a possible cause, thank you in advance! Tried googling for MySQL4 difference to no avail too. Also tried using SELECT EL.log_actions, EL.log_date, EL.log_value, EL.log_type, EA.admins_name, EU.users_name, EU.users_matric FROM events_log EL JOIN events_users EU where EL.users_id = EU.users_id JOIN events_admins EA USING EL.admins_id = EA.admins_id ORDER BY EL.log_id DESC LIMIT 0, 10 But then I got the error in both production and development. A Database Error Occurred Error Number: 1064 You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'JOIN events_admins EA USING EL.admins_id = EA.admins_id ORDER BY' at line 8 SELECT EL.log_actions, EL.log_date, EL.log_value, EL.log_type, EA.admins_name, EU.users_name, EU.users_matric FROM events_log EL JOIN events_users EU where EL.users_id = EU.users_id JOIN events_admins EA USING EL.admins_id = EA.admins_id ORDER BY EL.log_id DESC LIMIT 0, 20 If you can point me to some resources where I can read up more on MySQL 4 syntax to achieve the same thing effect like I did with MySQL 5 syntax, please let me know. Thanks again!

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  • Komodo Edit 5.2 Django Template Syntax Error - Info: <head> previously mentioned

    - by Lance McNearney
    I am using Komodo Edit 5.2 for editing html and Django template files. It always shows a single syntax error inside the first {% block %} area on the first tag of my template. For example: {% extends "base.html" %} {% load i18n %} {% block title %}Hello{% endblock %} {% block content %} <p>Hello</p> <-- Syntax error on this single line <p>Other lines have no errors</p> {% endblock %} {% block footer %} <p>No errors here</p> {% endblock %} The syntax error given is: Info: <head> previously mentioned I know for a fact that the error has nothing to do with my <head> tag since it occurs in the base template and in child templates (and the IDE isn't smart enough to process the base templates when in a child, etc.) All of my html tags are closed properly and everything validates for XHTML strict. This forum post mentions a similar problem but offers no solution (and may be specific to Smarty syntax highlighting). Any ideas on how to resolve this error (or disable it from being shown)?

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  • Looking for Antlr Grammar syntaxt highlight in VS2010

    - by David Mårtensson
    I am looking for some way to edit antlr grammar files directly within VS2010 with syntax highlight. I have used antlrworks a lot but it has the drawback that I have to start antlrworks separately and then browse to the file I want to edit, do the changed and save. For minor fixes I do not need all the tools in Antlrworks but I still would like the syntax highlight. But I have not been able to get VS2010 to open antlrworks with the right file and I have found no other way to get syntax highlight directly within VS2010 editor, it just opens as plain text. I can get visual studio to open antlrworks but it will open with only the last set of files it had open, not the one I clicked on. So my question(s) are: Is there a way to get antlrworks to open with the right file when I double click in it in visual studio project explorer? Is there any other way to get correct syntax highlight for antlr grammar files within visual studio (or with another editor, preferably not one that costs money, but if there are no free ones a commercial one might be an option).

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  • ETL , Esper or Drools?

    - by geoaxis
    Hello, The question environment relates to JavaEE, Spring I am developing a system which can start and stop arbitrary TCP (or other) listeners for incoming messages. There could be a need to authenticate these messages. These messages need to be parsed and stored in some other entities. These entities model which fields they store. So for example if I have property1 that can have two text fields FillLevel1 and FillLevel2, I could receive messages on TCP which have both fill levels specified in text as F1=100;F2=90 Later I could add another filed say FillLevel3 when I start receiving messages F1=xx;F2=xx;F3=xx. But this is a conscious decision on the part of system modeler. My question is what do you think is better to use for parsing and storing the message. ETL (using Pantaho, which is used in other system) where you store the raw message and use task executor to consume them one by one and store the transformed messages as per your rules. One could use Espr or Drools to do the same thing , storing rules and executing them with timer, but I am not sure how dynamic you could get with making rules (they have to be made by end user in a running system and preferably in most user friendly way, ie no scripts or code, only GUI) The end user should be capable of changing the parse rules. It is also possible that end user might want to change the archived data as well (for example in the above example if a new value of FillLevel is added, one would like to put a FillLevel=-99 in the previous values to make the data consistent). Please ask for explanations, I have the feeling that I need to revise this question a bit. Thanks

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  • In Ruby, why is a method invocation not be able to be treated as a unit when "do" and "end" is used?

    - by Jian Lin
    The following question is related to the question "Ruby Print Inject Do Syntax". My question is, can we insist on using do and end and make it work with puts or p? This works: a = [1,2,3,4] b = a.inject do |sum, x| sum + x end puts b # prints out 10 so, is it correct to say, inject is a class method of the Array class, which takes a block of code, and then returns a number. If so, then it should be no different from calling a function and getting back a return value: b = foo(3) puts b or b = circle.getRadius() puts b In the above two cases, we can directly say puts foo(3) puts circle.getRadius() so, there is no way to make it work directly by using the following 2 ways: a = [1,2,3,4] puts a.inject do |sum, x| sum + x end but it gives ch01q2.rb:7:in `inject': no block given (LocalJumpError) from ch01q2.rb:4:in `each' from ch01q2.rb:4:in `inject' from ch01q2.rb:4 grouping the method call using ( ) doesn't work either: a = [1,2,3,4] puts (a.inject do |sum, x| sum + x end) and this gives: ch01q3.rb:4: syntax error, unexpected kDO_BLOCK, expecting ')' puts (a.inject do |sum, x| ^ ch01q3.rb:4: syntax error, unexpected '|', expecting '=' puts (a.inject do |sum, x| ^ ch01q3.rb:6: syntax error, unexpected kEND, expecting $end end) ^ finally, the following version works: a = [1,2,3,4] puts a.inject { |sum, x| sum + x } but why doesn't the grouping of the method invocation using ( ) work in the earlier example? What if a programmer insist that he uses do and end, can it be made to work?

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  • In Ruby, why does a method invocation not be able to be treated as a unit when "do" and "end" is use

    - by Jian Lin
    The following question is related to http://stackoverflow.com/questions/2127836/ruby-print-inject-do-syntax The question is, can we insist on using DO and END and make it work with puts or p? This works: a = [1,2,3,4] b = a.inject do |sum, x| sum + x end puts b # prints out 10 so, is it correct to say, inject is a class method of the Array class, which takes a block of code, and then returns a number. If so, then it should be no different from calling a function and getting back a return value: b = foo(3) puts b or b = circle.getRadius() puts b In the above two cases, we can directly say puts foo(3) puts circle.getRadius() so, there is no way to make it work directly by using the following 2 ways: a = [1,2,3,4] puts a.inject do |sum, x| sum + x end but it gives ch01q2.rb:7:in `inject': no block given (LocalJumpError) from ch01q2.rb:4:in `each' from ch01q2.rb:4:in `inject' from ch01q2.rb:4 grouping the method call using ( ) doesn't work either: a = [1,2,3,4] puts (a.inject do |sum, x| sum + x end) and this gives: ch01q3.rb:4: syntax error, unexpected kDO_BLOCK, expecting ')' puts (a.inject do |sum, x| ^ ch01q3.rb:4: syntax error, unexpected '|', expecting '=' puts (a.inject do |sum, x| ^ ch01q3.rb:6: syntax error, unexpected kEND, expecting $end end) ^ finally, the following version works: a = [1,2,3,4] puts a.inject { |sum, x| sum + x } but why doesn't the grouping of the method invocation using ( ) work? What if a programmer insists that he uses do and end, can it be made to work directly with p or puts, without an extra temporary variable?

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  • xcode project-/target-settings-syntax for linker flag force_load on iPhone

    - by Kaiserludi
    Hi all. I am confronted with the double bind, that on the one hand for one of the 3rd party static libraries, my iPhone application uses, the linker flag -all_load has to be set in the application project- or target settings, otherwise the app crashes at runtime not finding some symbols, called internally from the lib, on the other hand for another 3rd party static lib -all_load must not be set on application level, or the app won't build thanks to a "duplicate symbols"-linker error. To solve this issue I now want to use force_load instant of load_all, as it due to documentation it does the same like all_load, but only for the passed path or lib-file, instead of all libs. The problem with force_load is, I do not have a clue, how to pass a path or file as parameter with it, when passing it via xcode project- or target-settings. All syntax-possibilities coming to my mind either lead into xcode thinking its another linker flag instead of a parameter to the previous one, or the linker is throwing syntax related errors or the flag simply does nothing at all in comparison to not being set. I also opened the .pbxproj-file in a text-editor to edit it to the correct command line syntax manually, but when reloading the project with xcode, it auto changes the syntax into interpreting the parameter to force_load as a separate flag. Anyone having an idea on this issue? Thx, Kaiserludi.

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  • In Ruby, why is a method invocation not able to be treated as a unit when "do" and "end" is used?

    - by Jian Lin
    The following question is related to the question "Ruby Print Inject Do Syntax". My question is, can we insist on using do and end and make it work with puts or p? This works: a = [1,2,3,4] b = a.inject do |sum, x| sum + x end puts b # prints out 10 so, is it correct to say, inject is an instance method of the Array object, and this instance method takes a block of code, and then returns a number. If so, then it should be no different from calling a function or method and getting back a return value: b = foo(3) puts b or b = circle.getRadius() puts b In the above two cases, we can directly say puts foo(3) puts circle.getRadius() so, there is no way to make it work directly by using the following 2 ways: a = [1,2,3,4] puts a.inject do |sum, x| sum + x end but it gives ch01q2.rb:7:in `inject': no block given (LocalJumpError) from ch01q2.rb:4:in `each' from ch01q2.rb:4:in `inject' from ch01q2.rb:4 grouping the method call using ( ) doesn't work either: a = [1,2,3,4] puts (a.inject do |sum, x| sum + x end) and this gives: ch01q3.rb:4: syntax error, unexpected kDO_BLOCK, expecting ')' puts (a.inject do |sum, x| ^ ch01q3.rb:4: syntax error, unexpected '|', expecting '=' puts (a.inject do |sum, x| ^ ch01q3.rb:6: syntax error, unexpected kEND, expecting $end end) ^ finally, the following version works: a = [1,2,3,4] puts a.inject { |sum, x| sum + x } but why doesn't the grouping of the method invocation using ( ) work in the earlier example? What if a programmer insist that he uses do and end, can it be made to work?

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  • Inheritance security rules violated while overriding member - SecurityRuleSet.Level2

    - by Page Brooks
    I have a class that inherits from Exception. In .NET 4, I started receiving a runtime error: Inheritance security rules violated while overriding member: MyBusinessException.GetObjectData(System.Runtime.Serialization.SerializationInfo, System.Runtime.Serialization.StreamingContext)'. Security accessibility of the overriding method must match the security accessibility of the method being overriden. I think the issue is caused by the fact that I am overriding GetObjectData. I know one answer for resolving the issue is to set the SecurityRuleSet: [assembly: SecurityRules(SecurityRuleSet.Level1)] This is not an acceptable answer, I'd like to know how to fix the issue without having to relax the default security rules in .NET 4.

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  • Problem in apache2 with mod rewrite when setting rules in .conf files instead of .htaccess

    - by gonzlikes
    Hi, Because of weird security policies of my hosting provider I have to define my rewrite rules in /etc/apache2/conf.d/examplesite.conf instead of writing them on an .htaccess on the www folder of that site. What I'm trying to do is setup a Wordpress Mu server (http://mu.wordpress.org/forums/topic/17349 ) and so far its working on a 50%. The main blog loads perfectly but other sub blogs (located for example at www.example.com/blog2 ) don't. I'm guessing the problem is that the rewrite rules behave differently when declared at .conf files for each virtual host instead of using .htaccess files. Has anybody else had this problem? How can you fix it?

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  • Configuring Team System Code Analysis via a FxCop rules file

    - by Ian G
    Is there anyway to configure the code analysis rules in Visual Studio Team System to match those in an FxCop configuration file and keep them in sync automatically? Not all the developers on the team have TS so keeping the rules we are currently running in an FxCop file is required so everyone can run the same set, but it would nice for those with to be able to run them in the IDE. We're introducing static analysis to an existing project so turning on everything now isn't a useful option. (We are not using Foundation Server for source control, if that makes any difference.)

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