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  • Browser Not Reading Entire XML File

    - by Chris
    I have an XML file that is written by a PHP script. The data for the XML file is gathered from several different RSS feeds. The PHP script is invoked every 5 minutes by a Cron Job. The PHP Script takes maybe 5-10 seconds to write the XML File. Here's the problem: After the XML file is written, I can open it through DreamWeaver and read everything just fine - but when I enter the XML File's URL into my Web Browser (IE or Firefox), I get a "XML Parsing Error: not well-formed" Error in the Browser. When I do View Source in the Browser, the XML file appears incomplete - but when I open the file directly off the server, it is complete. Anyone know what's going on here?

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  • XML and .NET: How to replace specific node with many other ones loaded from raw xml data

    - by Entrase
    Let's suppose we have an element like this one in the main xml file: <group name="gr1" filename="groups/gr1.xml"/>. The second file gr1.xml contains something like this: <item name="i1">Item one</item> <item name="i2">Item two</item> <item name="i3">Item three</item> Note that there is no XML declaration in gr1.xml, just plain items without single parent node. So… Which is the best way to replace <group/> with its <item/>s? I have already tried some things like manual enclosing of gr1.xml content into a single node with XML declaration and loading it into XmlDocument, but it doesn't look like a good solution.

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  • XSLT: How to get XML

    - by Jyotsna Sonawane
    I have a XSL that transforms one format of XML into another. In input XML I have a node with following value - which is actually a XML string if we replace &lt; with < (less than) for e.g. &lt;Paragraph&gt;&lt;Title&gt;&lt;!CDATA[Pour les nuits du 2012-10-01 - 2012-10-30]]&gt;&lt;/Title&gt;&lt;Text&gt;&lt;![CDATA[TAXES INCLUSES.]]&gt;&lt;/Text&gt;&lt;/Paragraph&gt; I want to have the content of otherInfo as a XML node in output XML. if I do , I do not get it as a XML node - it is output just as text. How can I make XSL output the content of otherInfo as XML node ?

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  • bash script to find/grep particular string in xml files in particular folders

    - by user3702188
    i have a problem at work, where i need to simplify the process how i searrh for logs. I would like to ask for help from experts here. We have different services for every channel. The structure is following: - root/channel_1/service_1/2014-05-21/file_54544654541.xml - root/channel_1/server2_2/2014-05-20/file_74272172.xml - root/channel_1/service_3/2014-05-22/file_45456546.xml - root/channel_2/service_4/2014-05-23/file_78754456.xml - root/channel_2/service_5/2014-05-24/file_546546546.xml my main problem is to find particular string in these xml files. Lets say, i know the channel name but i dont know the service name under which my particular string should be present. Also i know the date. So in search i want to enter the channel name the date and string. The search would be going via all service folders and looking for string only in all xml files under particular date folder and particular channel. any ideas for quickest and easiest solution to achieve this? Either by bash or perl? Any help would be appreciated thanks

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  • nginx: How can I set proxy_* directives only for matching URIs?

    - by Artem Russakovskii
    I've been at this for hours and I can't figure out a clean solution. Basically, I have an nginx proxy setup, which works really well, but I'd like to handle a few urls more manually. Specifically, there are 2-3 locations for which I'd like to set proxy_ignore_headers to Set-Cookie to force nginx to cache them (nginx doesn't cache responses with Set-Cookie as per http://wiki.nginx.org/HttpProxyModule#proxy_ignore_headers). So for these locations, all I'd like to do is set proxy_ignore_headers Set-Cookie; I've tried everything I could think of outside of setting up and duplicating every config value, but nothing works. I tried: Nesting location directives, hoping the inner location which matches on my files would just set this value and inherit the rest, but that wasn't the case - it seemed to ignore anything set in the outer location, most notably proxy_pass and I end up with a 404). Specifying the proxy_cache_valid directive in an if block that matches on $request_uri, but nginx complains that it's not allowed ("proxy_cache_valid" directive is not allowed here). Specifying a variable equal to "Set-Cookie" in an if block, and then trying to set proxy_cache_valid to that variable later, but nginx isn't allowing variables for this case and throws up. It should be so simple - modifying/appending a single directive for some requests, and yet I haven't been able to make nginx do that. What am I missing here? Is there at least a way to wrap common directives in a reusable block and have multiple location blocks refer to it, after adding their own unique bits? Thank you. Just for reference, the main location / block is included below, together with my failed proxy_ignore_headers directive for a specific URI. location / { # Setup var defaults set $no_cache ""; # If non GET/HEAD, don't cache & mark user as uncacheable for 1 second via cookie if ($request_method !~ ^(GET|HEAD)$) { set $no_cache "1"; } if ($http_user_agent ~* '(iphone|ipod|ipad|aspen|incognito|webmate|android|dream|cupcake|froyo|blackberry|webos|s8000|bada)') { set $mobile_request '1'; set $no_cache "1"; } # feed crawlers, don't want these to get stuck with a cached version, especially if it caches a 302 back to themselves (infinite loop) if ($http_user_agent ~* '(FeedBurner|FeedValidator|MediafedMetrics)') { set $no_cache "1"; } # Drop no cache cookie if need be # (for some reason, add_header fails if included in prior if-block) if ($no_cache = "1") { add_header Set-Cookie "_mcnc=1; Max-Age=17; Path=/"; add_header X-Microcachable "0"; } # Bypass cache if no-cache cookie is set, these are absolutely critical for Wordpress installations that don't use JS comments if ($http_cookie ~* "(_mcnc|comment_author_|wordpress_(?!test_cookie)|wp-postpass_)") { set $no_cache "1"; } if ($request_uri ~* wpsf-(img|js)\.php) { proxy_ignore_headers Set-Cookie; } # Bypass cache if flag is set proxy_no_cache $no_cache; proxy_cache_bypass $no_cache; # under no circumstances should there ever be a retry of a POST request, or any other request for that matter proxy_next_upstream off; proxy_read_timeout 86400s; # Point nginx to the real app/web server proxy_pass http://localhost; # Set cache zone proxy_cache microcache; # Set cache key to include identifying components proxy_cache_key $scheme$host$request_method$request_uri$mobile_request; # Only cache valid HTTP 200 responses for this long proxy_cache_valid 200 15s; #proxy_cache_min_uses 3; # Serve from cache if currently refreshing proxy_cache_use_stale updating timeout; # Send appropriate headers through proxy_set_header Host $host; # no need for this proxy_set_header X-Real-IP $remote_addr; # no need for this proxy_set_header X-Forwarded-For $proxy_add_x_forwarded_for; # Set files larger than 1M to stream rather than cache proxy_max_temp_file_size 1M; access_log /var/log/nginx/androidpolice-microcache.log custom; }

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  • Nginx config rewriting subdomain name to 1st URI segment

    - by tim peterson
    I'm unable to do the following nginx.conf rewrite: test.mysite.info to: mysite.info/test here's what i've tried: server { server_name test.mysite.info; rewrite ^ https://mysite.info/test/$request_uri; } I know my DNS (Route53 AWS) is correct b/c: test.mysite.info redirects to mysite.info (just not mysite.info/test) I have an Apache server handling mysite.com which using .htaccess I can rewrite test.mysite.com to mysite.com/test. I haven't changed anything else from the default nginx.conf installation so I'm totally confused as to why such a simple thing isn't working. Here is my full nginx.conf file if that is helpful.

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  • What is the best way to configure Apache or AWS to support a Rails multi tenancy application that allows each customer to have their own domain name?

    - by Ryan Arneson
    I'm building a Rails 3 SaaS site that allows for multi-tenancy. When a customer signs up they put in their own domain name, e.g. example.com. I need example.com to point to my SaaS application and serve them their content. My questions are as follows: Do I need to create an Apache vhost for each customer using their own domain? Is there an easier way with CNAME's to just have the customer point to the IP address of my server(s) that then forwards the request onto my application through some catch all vhost? Would I be able to create the CNAME record for the customer so they don't have to do any setup? Would this be a case better suited to Amazon Web Services? Any help or explanation or corrections on my understanding of dns would be appreciated. I'm a developer so the server ops portion of this is a bit cloudy.

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  • How do I configure Ruby On Rails on windows XP with APACHE and MYSQL

    - by Gaurav Sharma
    Hello Everyone, It has been quite some time I am struggling to get Ruby On Rails working on my System which is having Windows XP operating system. I am trying to configure ROR to use apache and mysql so that I do not have to install additional servers to run ruby on rails. I also tried InstantRails but faced same problems. I went through the tutorial mentioned in getting rails to wrok on a windows machine running xampp and did all the steps which were necessary. All went fine (installing rails, running the ruby, gem and rails command from command prompt) but when I tried to run my application by typing localhost:3000/say/hello nothing happened and I was redirected to the google page for searching to this keyword. Please help me Thanks

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  • How to retrieve all MySQL settings?

    - by Max Kielland
    I have a configured MySQL server (MySQL 5.1.47-community) that works perfect. I installed a second server (MySQL 5.5.15-community) to see if the new version of MySQL would work with my application before upgrading. When I run the application against the new server it behaves different. When I run it against the old server (MySQL 5.1.47-community) everything works perfect. I remember that I set some parameters through the MySQL prompt to accept larger result set and some other stuff, now I can't remember what I did. So my question is: Is there a way to transfer all the MySQL settings from one server to another? Thanks.

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  • There is an error in XML document... When calling to web service

    - by Sigurjón Guðbergsson
    I have created a web service and a function in it that should return a list of 11thousand records retreived from a pervasive database Here is my function in the web service. [WebService(Namespace = "http://tempuri.org/")] [WebServiceBinding(ConformsTo = WsiProfiles.BasicProfile1_1)] [System.ComponentModel.ToolboxItem(false)] public class BBI : System.Web.Services.WebService { [WebMethod] public List<myObject> getAll() { List<myObject> result = new List<myObject>(); PsqlConnection conn = new PsqlConnection("Host=soemthing;Port=something;Database=something;Encoding=IBM861"); conn.Open(); string strSql = "select 0, 1, 2, 3, 4, 5 from something"; PsqlCommand DBCmd = new PsqlCommand(strSql, conn); PsqlDataReader myDataReader; myDataReader = DBCmd.ExecuteReader(); while (myDataReader.Read()) { myObject b = new myObject(); b.0 = Convert.ToInt32(myDataReader[0].ToString()); b.1 = myDataReader[1].ToString(); b.2 = myDataReader[2].ToString(); b.3 = myDataReader[3].ToString(); b.4 = myDataReader[4].ToString(); b.5 = myDataReader[5].ToString(); result.Add(b); } conn.Close(); myDataReader.Close(); return result; } } Then i add web reference to this web service in my client program and call the reference BBI. Then i call to the getAll function and get the error : There is an error in XML document (1, 63432). public List<BBI.myObject> getAll() { BBI.BBI bbi = new BBI.BBI(); List<BBI.myObject> allBooks = bbi.getAll().OfType<BBI.myObject>().ToList(); return allBooks; } Here is the total exception detail System.InvalidOperationException was unhandled by user code Message=There is an error in XML document (1, 71897). Source=System.Xml StackTrace: at System.Xml.Serialization.XmlSerializer.Deserialize(XmlReader xmlReader, String encodingStyle, XmlDeserializationEvents events) at System.Xml.Serialization.XmlSerializer.Deserialize(XmlReader xmlReader, String encodingStyle) at System.Web.Services.Protocols.SoapHttpClientProtocol.ReadResponse(SoapClientMessage message, WebResponse response, Stream responseStream, Boolean asyncCall) at System.Web.Services.Protocols.SoapHttpClientProtocol.Invoke(String methodName, Object[] parameters) at BBI.BBI.getAllBooks() in c:\WINDOWS\Microsoft.NET\Framework\v4.0.30319\Temporary ASP.NET Files\vefur\73db60db\a4ee31dd\App_WebReferences.jl1r8jv6.0.cs:line 252 at webServiceFuncions.getAllBooks() in c:\Documents and Settings\forritari\Desktop\Vefur - Nýr\BBI\trunk\Vefur\App_Code\webServiceFuncions.cs:line 59 InnerException: System.Xml.XmlException Message='', hexadecimal value 0x01, is an invalid character. Line 1, position 71897. Source=System.Xml LineNumber=1 LinePosition=71897 SourceUri="" StackTrace: at System.Xml.XmlTextReaderImpl.Throw(Exception e) at System.Xml.XmlTextReaderImpl.Throw(String res, String[] args) at System.Xml.XmlTextReaderImpl.Throw(Int32 pos, String res, String[] args) at System.Xml.XmlTextReaderImpl.ParseNumericCharRefInline(Int32 startPos, Boolean expand, StringBuilder internalSubsetBuilder, Int32& charCount, EntityType& entityType) at System.Xml.XmlTextReaderImpl.ParseCharRefInline(Int32 startPos, Int32& charCount, EntityType& entityType) at System.Xml.XmlTextReaderImpl.ParseText(Int32& startPos, Int32& endPos, Int32& outOrChars) at System.Xml.XmlTextReaderImpl.ParseText() at System.Xml.XmlTextReaderImpl.ParseElementContent() at System.Xml.XmlTextReaderImpl.Read() at System.Xml.XmlTextReader.Read() at System.Xml.XmlReader.ReadElementString() at Microsoft.Xml.Serialization.GeneratedAssembly.XmlSerializationReaderBBI.Read2_Book(Boolean isNullable, Boolean checkType) at Microsoft.Xml.Serialization.GeneratedAssembly.XmlSerializationReaderBBI.Read20_getAllBooksResponse() at Microsoft.Xml.Serialization.GeneratedAssembly.ArrayOfObjectSerializer35.Deserialize(XmlSerializationReader reader) at System.Xml.Serialization.XmlSerializer.Deserialize(XmlReader xmlReader, String encodingStyle, XmlDeserializationEvents events) InnerException: The database records are containing all kind of strange symbols, for example ¤rmann Kr. Einarsson and Tv” ‘fint˜ri Can someone see what im doing wrong here?

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  • Correct way to read configuration file and using configuration values

    - by Harza
    I'm reading applications .config file using .NET ConfigurationManager like it should be done, but .... Which one is most preferred option: Read config and store instance of (build in or custom) ConfigurationElement for later use Read config and store only needed values (but not instances of ConfigrationElement classes) for later use Read ConfigurationElement from config always when configuration values are needed These two things are in my mind: Performance impact in case 3 when reading config all the time Problems occuring in case 1 when using cached instances of ConfigurationElements

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  • C# Windows Service XML

    - by Goober
    Scenario I have a windows service written in C# that performs some processing based on parsing an XML file and use that data to carry out various tasks. The service also does various bits of logging - which uses settings from an APP.Config file. The Problem When the service is compiled, installed and run, the XML file seems to disappear. I'm getting the impression that it is just ignored or something like that. So far I've tried using TWO App.Config files, one named App.Config that contains settings for the service, and the other called MyService.exe.config that contains all of the data that was used in the XML file (the idea being that I can parse the XML from a config file that actually gets compiled and appears in my installation directory. However When I do this, all that happens is that ONE config file appears (with the name MyService.exe.config), but it contains the contents of the App.Config file and not the XML data that I want to parse. What I need All I want is to have a config file for my settings, and an XML file for my data. Question Is this possible? I know the application works as it was originally built as a console application that ran fine. Other The application has to be designed this way (as in, I need my data stored as XML, and my settings stored in a config file). Thoughts If I could somehow combine the contents of the two files into ONE config file, that would be one way of solving the problem. However, I have tried this and of course I get a "Type Initialisation Exception", as the config file cannot interprate the XML data (probably because the tags are custom and do not form any part of the config schema - or something like that). Ideas Please could someone explain to me if it is possible for me to have an XML file AND a config file that will actually be compiled and stored in my installation directory for the service when it is run? CODE Custom XML/Data Config File <?xml version="1.0" encoding="utf-8" ?> <configuration> <servers> <SV066930> <add name="Name" value = "SV066930" /> <processes> <SimonTest1> <add name="ProcessName" value="notepad.exe" /> <add name="CommandLine" value="C:\\WINDOWS\\system32\\notepad.exe C:\\WINDOWS\\Profiles\\TA2TOF1\\Desktop\\SimonTest1.txt" /> </SimonTest1> </processes> </SV066930> </servers> </configuration> APP.Config Settings File <?xml version="1.0" encoding="utf-8" ?> <configuration> <configSections> <section name="dataConfiguration" type="Microsoft.Practices.EnterpriseLibrary.Data.Configuration.DatabaseSettings, Microsoft.Practices.EnterpriseLibrary.Data, Version=4.0.0.0, Culture=neutral, PublicKeyToken=xxxxxxxxxxx" /> </configSections> <connectionStrings> <add name="DB" connectionString="Data Source=etc......" /> </connectionStrings> </configuration> Help greatly appreciated.

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  • Converting XML to RSS

    - by hkw
    I've got an xml feed that will be published in one location of our website, and would like to repurpose that for an RSS feed. A few different pages on the website will also be referencing the same xml - all of those transformations are set up and working. The base xml file (XMLTEST.xml) is using this structure: <POST> <item> <POST_ID>80000852</POST_ID> <POST_TITLE>title</POST_TITLE> <POST_CHANNEL>I</POST_CHANNEL> <POST_DESC>description</POST_DESC> <LINK>http://www...</LINK> <STOC>N</STOC> </item> </POST> I'm trying to transform the xml into an RSS feed using the following setup (feed.xml + rss.xsl) feed.xml: <?xml-stylesheet href="rss.xsl" type="text/xsl"?> <RSSChannels> <RSSChannel src="XMLTEST.xml"/> </RSSChannels> rss.xsl: <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"> <xsl:output method="xml" omit-xml-declaration="yes" /> <xsl:template match="RSSChannels"> <rss version="2.0"> <channel> <title>site title</title> <link></link> <description>Site description...</description> <xsl:apply-templates /> </channel> </rss> </xsl:template> <xsl:template match="RSSChannel"> <xsl:apply-templates select="document(@src)" /> </xsl:template> <xsl:template match="item"> <xsl:choose> <xsl:when test="STOC = 'Y'"></xsl:when> <xsl:when test="POST_CHANNEL = 'I'"></xsl:when> <xsl:otherwise> <item> <title> <xsl:value-of select="*[local-name()='POST_TITLE']" /> </title> <link> <xsl:value-of select="*[local-name()='LINK']" /> </link> <description> <xsl:value-of select="*[local-name()='POST_DESC']" /> </description> </item> </xsl:otherwise> </xsl:choose> </xsl:template> </xsl:stylesheet> When I try to view the output of feed.xml in Firefox, all of the filtering is applied correctly (sorting out items that shouldn't be published in that channel), but the page outputs as plain text, rather than the usual feed-detection that takes place in Firefox. Any ideas on what I'm missing? Thanks for any suggestions you can provide.

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  • Replacing innertext of XML node using PHP DOMDocument

    - by Rohan Kumar
    I want to replace innertext of a XML node my XML file named test.xml is <?xml version="1.0" encoding="utf-8"?> <ads> <loop>no</loop> <item> <description>Description 1</description> </item> <item> <description>Text in item2</description> </item> <item> <description>Let play with this XML</description> </item> </ads> I want to change the value of loop and description tag both, and it should be saved in test.xml like: <?xml version="1.0" encoding="utf-8"?> <ads> <loop>yes</loop> <item> <description>Description Changing Here</description> </item> <item> <description>Changing text in item2</description> </item> <item> <description>We will play later</description> </item> </ads> I tried code in PHP: <? $file = "test.xml"; $fp = fopen($file, "rb") or die("cannot open file"); $str = fread($fp, filesize($file)); $dom=new DOMDocument(); $dom->formatOutput = true; $dom->preserveWhiteSpace = false; $dom->loadXML($str) or die("Error"); //$dom->load("items.xml"); $root=$dom->documentElement; // This can differ (I am not sure, it can be only documentElement or documentElement->firstChild or only firstChild) $loop=$root->getElementsByTagName('loop')->item(0);//->textContent; //echo $loop; if(trim($loop->textContent)=='no') { echo 'ok'; $root->getElementsByTagName('loop')->item(0)->nodeValue ='yes'; } echo "<xmp>NEW:\n". $dom->saveXML() ."</xmp>"; ?> I tried only for loop tag.I don't know how to replace nodevalue in description tag. When I run this page it shows output like: ok NEW: <?xml version="1.0" encoding="utf-8"?> <ads> <loop>yes</loop> <item> <description>Description 1</description> </item> <item> <description>Changing text in item2</description> </item> <item> <description>Let play with this XML</description> </item> </ads> It gives the value yes in browser but don't save it in test.xml any reason?

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  • Problem with Spring @Configuration class

    - by easyrider
    Hi, i use class with @Configuration annotation to configure my spring application: @Configuration public class SpringConfiguration { @Value("${driver}") String driver; @Value("${url}") String url; @Value("${minIdle}") private int minIdle; // snipp .. @Bean(destroyMethod = "close") public DataSource dataSource() { DataSource dataSource = new DataSource(); dataSource.setDriverClassName(driver); dataSource.setUrl(url); dataSource.setUsername(user); dataSource.setPassword(password); dataSource.setMinIdle(minIdle); return dataSource; } and properties file in CLASSPATH driver=org.postgresql.Driver url=jdbc:postgresql:servicerepodb minIdle=1 I would like to get my DataSource configured object in my DAO class: ApplicationContext ctx = new AnnotationConfigApplicationContext(SpringConfiguration.class); DataSource dataSource = ctx.getBean(DataSource.class); But i get the error: org.springframework.beans.factory.BeanCreationException: Error creating bean with name 'springConfiguration': Injection of autowired dependencies failed; nested exception is org.springframework.beans.factory.BeanCreationException: Could not autowire field: private int de.hska.repo.configuration.SpringConfiguration.minIdle; nested exception is org.springframework.beans.TypeMismatchException: Failed to convert value of type 'java.lang.String' to required type 'int'; nested exception is **java.lang.NumberFormatException: For input string: "${minIdle}"** Caused by: java.lang.NumberFormatException: For input string: **"${minIdle}"** at java.lang.NumberFormatException.forInputString(**Unknown Source**) at java.lang.Integer.parseInt(Unknown Source) at java.lang.Integer.valueOf(Unknown Source) It worked with String properties (driver, url), but ${minIdle} (of type int) can't be resolved! Please help. Thanx in advance!

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  • WCF Multiple Service Configuration Issue

    - by Goober
    Scenario Ignoring that fact that some of the settings might be wrong and inconsistent. Why does the program fail to compile when I try and put these 2 separate configurations for WCF Services into the same APP.CONFIG file? One was writen by myself and another by a friend, yet I cannot get the application to compile. What have I missed? ERROR Type Initialization Exception CODE <configuration> <system.serviceModel> <!--START Service 1 CONFIGURATION--> <bindings> <netTcpBinding> <binding name="tcpServiceEndPoint" closeTimeout="00:01:00" openTimeout="00:01:00" receiveTimeout="00:10:00" sendTimeout="00:01:00" transactionFlow="false" transferMode="Buffered" transactionProtocol="OleTransactions" hostNameComparisonMode="StrongWildcard" listenBacklog="10" maxBufferPoolSize="524288" maxBufferSize="65536" maxConnections="10" maxReceivedMessageSize="65536"> <readerQuotas maxDepth="32" maxStringContentLength="8192" maxArrayLength="16384" maxBytesPerRead="4096" maxNameTableCharCount="16384" /> <reliableSession ordered="true" inactivityTimeout="00:05:00" enabled="true" /> <security mode="None"> <transport clientCredentialType="Windows" protectionLevel="EncryptAndSign" /> <message clientCredentialType="Windows" /> </security> </binding> </netTcpBinding> </bindings> <client> <endpoint address="" binding="netTcpBinding" bindingConfiguration="tcpServiceEndPoint" contract="ListenerService.IListenerService" name="tcpServiceEndPoint" /> </client> <!--END Service 1 CONFIGURATION-->

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  • Why is the XML DTD not found by the browser

    - by hyperuser
    When I load my XML file in a browser, it complains there is 'no style information': "This XML file does not appear to have any style information associated with it. The document tree is shown below." So I wrote an external DTD, then an internal DTD, but keep getting the same 'no style information' error. It doesn't even show the DTD! What am I doing wrong? <?xml version="1.0"?> <!DOCTYPE fotos [ <!ELEMENT fotos (titel,auteur)> <!ELEMENT titel (#PCDATA)> <!ELEMENT auteur (#PCDATA)> ]> <fotos> <titel>titel1</titel> <auteur>jan</auteur> </fotos>

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  • wmic output well formed xml on remote queries

    - by Mervin
    I want to use the WMI command line tool (wmic) to get information about windows computers on the network and output it as valid xml. However, I can't seem to find the right way to do this as the outputted xml currently contains invalid tokens for which I think I should use the /TRANSLATE:basicxml switch. The command: wmic /NODE:"tech-demo" /IMPLEVEL:Impersonate /USER:MyUser /PASSWORD:MyPassword /PRIVILEGES:DISABLE /AUTHLEVEL:Pkt /AUTHORITY:"ntlmdomain:companydomain.local" PATH Win32_LogicalDisk GET * /FORMAT:rawxml This command runs but returns invalid xml tokens ('<' and '' I think? edit: it appears to fail parsing at ‹) When I add the translate switch I get the message: Can not use credentials for local connections a bit strange that it tries to query the local pc when I add the switch.. Help would be greatly appreciated.

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  • Consume an XML Feed with PowerPoint 2010

    - by Matt Schweers
    Hi there. I'm looking for a way to consume an XML feed from a web-service directly into PowerPoint 2010. I found the LiveWeb plugin (http://skp.mvps.org/liveweb.htm) for PowerPoint that, while pretty cool, really only pulls in actual web content in a way that feels more like an iframe. Ideally, I would like to consume raw XML web service/feed with PowerPoint, parse it, and stylize the results. Is this possible? Even reading from a static XML file would be a good start.

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  • How to Read XML and Generate SQL Insert

    - by hackerkatt
    I am trying to write a VB Script to read a XML file (downloaded daily) and insert the information into a MSSQL DB. The content of the XML is a list if CDRs (Call Data Records). I need to parse the file and insert the cdr's into a table. I'm a Ruby,Perl,PHP,Javascript,SQL,... programer. But I've really never written any VB Script. I've done some googling and find a number of examples on how to generate XML from a SQL Query, but not the reverse. Any help/suggestions would be greatly appreciated. Thank you!

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  • Android app crashes when I change the default xml layout file to another

    - by mib1413456
    I am currently just starting to learn android development and have created a basic "Hello world" app that uses "activity_main.xml" for the default layout. I tried to create a new layout xml file called "new_layout.xml" with a text view, a text field and a button and did the following changes in the MainActivity.java file: setContentView(R.layout.new_layout); I did nothing else expect for adding a new_layout.xml in the res/layout folder, I have tried restarting and cleaning the project but nothing. Below is my activity_main.xml file, new_layout.xml file and MainActivity.java activity_main.xml: <FrameLayout xmlns:android="http://schemas.android.com/apk/res/android" xmlns:tools="http://schemas.android.com/tools" android:id="@+id/container" android:layout_width="match_parent" android:layout_height="match_parent" tools:context="org.example.androidsdk.demo.MainActivity" tools:ignore="MergeRootFrame" /> new_layout.xml: <?xml version="1.0" encoding="utf-8"?> <LinearLayout xmlns:android="http://schemas.android.com/apk/res/android" android:layout_width="match_parent" android:layout_height="match_parent" android:orientation="horizontal" > <TextView android:id="@+id/textView1" android:layout_width="wrap_content" android:layout_height="wrap_content" android:text="TextView" /> <EditText android:id="@+id/editText1" android:layout_width="wrap_content" android:layout_height="wrap_content" android:layout_weight="1" android:ems="10" > <requestFocus /> </EditText> <Button android:id="@+id/button1" android:layout_width="wrap_content" android:layout_height="wrap_content" android:text="Button" /> MainActivity.java file package org.example.androidsdk.demo; import android.app.Activity; import android.app.ActionBar; import android.app.Fragment; import android.os.Bundle; import android.view.LayoutInflater; import android.view.Menu; import android.view.MenuItem; import android.view.View; import android.view.ViewGroup; import android.os.Build; public class MainActivity extends Activity { @Override protected void onCreate(Bundle savedInstanceState) { super.onCreate(savedInstanceState); setContentView(R.layout.new_layout); if (savedInstanceState == null) { getFragmentManager().beginTransaction() .add(R.id.container, new PlaceholderFragment()) .commit(); } } @Override public boolean onCreateOptionsMenu(Menu menu) { // Inflate the menu; this adds items to the action bar if it is present. getMenuInflater().inflate(R.menu.main, menu); return true; } @Override public boolean onOptionsItemSelected(MenuItem item) { // Handle action bar item clicks here. The action bar will // automatically handle clicks on the Home/Up button, so long // as you specify a parent activity in AndroidManifest.xml. int id = item.getItemId(); if (id == R.id.action_settings) { return true; } return super.onOptionsItemSelected(item); } /** * A placeholder fragment containing a simple view. */ public static class PlaceholderFragment extends Fragment { public PlaceholderFragment() { } @Override public View onCreateView(LayoutInflater inflater, ViewGroup container, Bundle savedInstanceState) { View rootView = inflater.inflate(R.layout.fragment_main, container, false); return rootView; } } }

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  • Is it possible to use .properties files in web.xml in conjunction with contextConfigLocation paramet

    - by Vladimir
    Here is part of my web.xml: <context-param> <param-name>contextConfigLocation</param-name> <param-value> classpath:application-config.xml </param-value> </context-param> application-config.xml uses property placeholder: <context:property-placeholder location="classpath:properties/db.properties"/> Is it possible somehow to define which properties file to use in web.xml rather than in application-config.xml?

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  • How to select visibility of specific worksheet at the opening of Excel using Spreadsheet XML

    - by user211607
    Hi, I am getting spreadsheet xml from a code logic (Flex Grids to spreadsheet xml). I have 3 worksheets (A, B, C) in that spreadsheet xml. I am opening this spreadsheet xml in Excel. I want to view worksheet B when I am opening the spreadhseet xml in Excel. Is there any tag/code, I need to add so that worksheet B will be visible at initial? I can add that code in code logic Thanks ... Atul

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  • Print XML file and download it

    - by Pankaj
    I am create xml using serialization and trying to print them using this code string xmlDate = xml.GetXML(); string name = string.Format("{0}_HighEST", ProjectName); Response.AddHeader("Content-disposition", "attachment; filename=\"" + name + "_HighEST.xml\""); Response.ContentType = string.Format("application/.xml", name); how can assign my xmldata to Response so that data will write on downloaded xml?

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  • Parsing secure entries XML file with jquery

    - by user573131
    Apologies if this is elementary. I'm primarily a front end designer/dev. I have webform through a form service called wufoo. Wufoo generates a lovely XML (or json) file that can be grabed and parsed. I'm trying to grab the entries xml feed that is associated with the form and parse it via jquery to show who has entered. Im using the following code (which works with a local xml file). http://bostonwebsitemakeover.com/2/test <script type="text/javascript" src="http://ajax.googleapis.com/ajax/libs/jquery/1.3.2/jquery.js"></script> <script> $(document).ready(function () { $.ajax({ type: "GET", url: "people.xml", dataType: "xml", success: xmlParser }); }); function xmlParser(xml) { $('#load').fadeOut(); $(xml).find("Entry").each(function () { $(".main").append('<div class="entry">' + $(this).find("Field1").text() + ' ' + $(this).find("Field2").text() + ' http://twitter.com/' + $(this).find("Field17").text() + '</div>'); $(".entry").fadeIn(1000); }); } </script> My XML file contains the following: <?xml version="1.0"?> <Entries> <Entry> <EntryId>1</EntryId> <Field1>Meaghan</Field1> <Field2>Severson</Field2> <Field17/> </Entry> <Entry> <EntryId>2</EntryId> <Field1>Michael</Field1> <Field2>Flint</Field2> <Field17>michaelflint</Field17> </Entry> <Entry> <EntryId>3</EntryId> <Field1>Niki</Field1> <Field2>Brown</Field2> <Field17>nikibrown</Field17> </Entry> <Entry> <EntryId>4</EntryId> <Field1>Niki</Field1> <Field2>Brown</Field2> <Field17>nikibrown</Field17> </Entry> </Entries> I'm wondering how I would do this with the xml file hosted on the wufoo (which is https) So I guess Im asking how do I authenticate the feed via jquery? Or do i need to do this via json? Could someone explain how?

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