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  • Is there any way to set or code breakpoints conditionally?

    - by froadie
    I've been wondering this for a while - is there a way to code/program breakpoints...? Conditionally? For example, can I specify something like - "when this variable becomes this value, break and open the debugger"? (Would be quite useful, especially in long loops when you want to debug loop execution of a late loop value.) I suppose this may be IDE-specific since debugging is implemented differently in different IDEs... I'd be interested to know how to do this in any IDE, but specifically in Eclipse and Visual Studio.

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  • Recieving server broadcast on mobile in real time

    - by Manjoor
    I have to write a simple mobile application that is able to recieve broadcast from a server, connected using GPRS, over a secure SSL connection. The amount of data mobile need to recieve is very small (about 100 character string for a single broadcast and maximum 10 broadcast per minute) I need to display it on screen and generate a alert sound (and vibrate the device). Client need not to send anything back to server. (ofcourse at the time of intialization the client app need to send some data for authorization) The target mobile plateform is symbion S60 and Blackberry. How can i do this? What tools, SDK and Third party framework (if needed) i should use? I am familier with java and network programming but not for mobile device.

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  • How can I interrupt a ServerSocket accept() method?

    - by lukeo05
    Hi, In my main thread I have a while(listening) loop which calls accept() on my ServerSocket object, then starts a new client thread and adds it to a Collection when a new client is accepted. I also have an Admin thread which I want to use to issue commands, like 'exit', which will cause all the client threads to be shut down, shut itself down, and shut down the main thread, by turning listening to false. However, the accept() call in the while(listening) loop blocks, and there doesn't seem to be any way to interrupt it, so the while condition cannot be checked again and the program cannot exit! Is there a better way to do this? Or some way to interrupt the blocking method? Thanks!

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  • Scala actors: receive vs react

    - by jqno
    Let me first say that I have quite a lot of Java experience, but have only recently become interested in functional languages. Recently I've started looking at Scala, which seems like a very nice language. However, I've been reading about Scala's Actor framework in Programming in Scala, and there's one thing I don't understand. In chapter 30.4 it says that using react instead of receive makes it possible to re-use threads, which is good for performance, since threads are expensive in the JVM. Does this mean that, as long as I remember to call react instead of receive, I can start as many Actors as I like? Before discovering Scala, I've been playing with Erlang, and the author of Programming Erlang boasts about spawning over 200,000 processes without breaking a sweat. I'd hate to do that with Java threads. What kind of limits am I looking at in Scala as compared to Erlang (and Java)? Also, how does this thread re-use work in Scala? Let's assume, for simplicity, that I have only one thread. Will all the actors that I start run sequentially in this thread, or will some sort of task-switching take place? For example, if I start two actors that ping-pong messages to each other, will I risk deadlock if they're started in the same thread? According to Programming in Scala, writing actors to use react is more difficult than with receive. This sounds plausible, since react doesn't return. However, the book goes on to show how you can put a react inside a loop using Actor.loop. As a result, you get loop { react { ... } } which, to me, seems pretty similar to while (true) { receive { ... } } which is used earlier in the book. Still, the book says that "in practice, programs will need at least a few receive's". So what am I missing here? What can receive do that react cannot, besides return? And why do I care? Finally, coming to the core of what I don't understand: the book keeps mentioning how using react makes it possible to discard the call stack to re-use the thread. How does that work? Why is it necessary to discard the call stack? And why can the call stack be discarded when a function terminates by throwing an exception (react), but not when it terminates by returning (receive)? I have the impression that Programming in Scala has been glossing over some of the key issues here, which is a shame, because otherwise it's a truly excellent book.

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  • Alright, I'm still stuck on this homework problem. C++

    - by Josh
    Okay, the past few days I have been trying to get some input on my programs. Well I decided to scrap them for the most part and try again. So once again, I'm in need of help. For the first program I'm trying to fix, it needs to show the sum of SEVEN numbers. Well, I'm trying to change is so that I don't need the mem[##] = ####. I just want the user to be able to input the numbers and the program run from there and go through my switch loop. And have some kind of display..saying like the sum is?.. Here's my code so far. #include <iostream> #include <iomanip> #include <ios> using namespace std; int main() { const int READ = 10; const int WRITE = 11; const int LOAD = 20; const int STORE = 21; const int ADD = 30; const int SUBTRACT = 31; const int DIVIDE = 32; const int MULTIPLY = 33; const int BRANCH = 40; const int BRANCHNEG = 41; const int BRANCHZERO = 42; const int HALT = 43; int mem[100] = {0}; //Making it 100, since simpletron contains a 100 word mem. int operation; //taking the rest of these variables straight out of the book seeing as how they were italisized. int operand; int accum = 0; // the special register is starting at 0 int counter; for ( counter=0; counter < 100; counter++) mem[counter] = 0; // This is for part a, it will take in positive variables in //a sent-controlled loop and compute + print their sum. Variables from example in text. mem[0] = 1009; mem[1] = 1109; mem[2] = 2010; mem[3] = 2111; mem[4] = 2011; mem[5] = 3100; mem[6] = 2113; mem[7] = 1113; mem[8] = 4300; counter = 0; //Makes the variable counter start at 0. while(true) { operand = mem[ counter ]%100; // Finds the op codes from the limit on the mem (100) operation = mem[ counter ]/100; //using a switch loop to set up the loops for the cases switch ( operation ){ case READ: //reads a variable into a word from loc. Enter in -1 to exit cout <<"\n Input a positive variable: "; cin >> mem[ operand ]; counter++; break; case WRITE: // takes a word from location cout << "\n\nThe content at location " << operand << " is " << mem[operand]; counter++; break; case LOAD:// loads accum = mem[ operand ];counter++; break; case STORE: //stores mem[ operand ] = accum;counter++; break; case ADD: //adds accum += mem[operand];counter++; break; case SUBTRACT: // subtracts accum-= mem[ operand ];counter++; break; case DIVIDE: //divides accum /=(mem[ operand ]);counter++; break; case MULTIPLY: // multiplies accum*= mem [ operand ];counter++; break; case BRANCH: // Branches to location counter = operand; break; case BRANCHNEG: //branches if acc. is < 0 if (accum < 0) counter = operand; else counter++; break; case BRANCHZERO: //branches if acc = 0 if (accum == 0) counter = operand; else counter++; break; case HALT: // Program ends break; } } return 0; } part B int main() { const int READ = 10; const int WRITE = 11; const int LOAD = 20; const int STORE = 21; const int ADD = 30; const int SUBTRACT = 31; const int DIVIDE = 32; const int MULTIPLY = 33; const int BRANCH = 40; const int BRANCHNEG = 41; const int BRANCHZERO = 41; const int HALT = 43; int mem[100] = {0}; int operation; int operand; int accum = 0; int pos = 0; int j; mem[22] = 7; // loop 7 times mem[25] = 1; // increment by 1 mem[00] = 4306; mem[01] = 2303; mem[02] = 3402; mem[03] = 6410; mem[04] = 3412; mem[05] = 2111; mem[06] = 2002; mem[07] = 2312; mem[08] = 4210; mem[09] = 2109; mem[10] = 4001; mem[11] = 2015; mem[12] = 3212; mem[13] = 2116; mem[14] = 1101; mem[15] = 1116; mem[16] = 4300; j = 0; while ( true ) { operand = memory[ j ]%100; // Finds the op codes from the limit on the memory (100) operation = memory[ j ]/100; //using a switch loop to set up the loops for the cases switch ( operation ){ case 1: //reads a variable into a word from loc. Enter in -1 to exit cout <<"\n enter #: "; cin >> memory[ operand ]; break; case 2: // takes a word from location cout << "\n\nThe content at location " << operand << "is " << memory[operand]; break; case 3:// loads accum = memory[ operand ]; break; case 4: //stores memory[ operand ] = accum; break; case 5: //adds accum += mem[operand];; break; case 6: // subtracts accum-= memory[ operand ]; break; case 7: //divides accum /=(memory[ operand ]); break; case 8: // multiplies accum*= memory [ operand ]; break; case 9: // Branches to location j = operand; break; case 10: //branches if acc. is < 0 break; case 11: //branches if acc = 0 if (accum == 0) j = operand; break; case 12: // Program ends exit(0); break; } j++; } return 0; }

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  • Convert the ada code to its C .

    - by maddy
    HI All, I have a piece of ada code shown below which is a simple switch case statements.Is there any better way to convert this into C. for I in 1..100 loop case I is when 100 => Dollars := Dollars + 1; when 25|50|75 => Quarters := Quarters + 1; when 10|20|30|40|60|70|80|90 => Dimes := Dimes + 1; when 5|15|35|45|55|65|85|95 => Nickles := Nickles + 1; when others => Pennies := Pennies + 1; end case; end loop; Now by adding the switch and the case for each values in the case,i can do that conversion,But it seems tyo make the code too big.Is there anywa other simple and compact way.Please get back to me if the question is not clear? Regards maddy

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  • How can I make a steady automata in JavaScript?

    - by RobertWHurst
    I'm working on a JavaScript game and I've got an automata system controlling game time and sprite animation as well as giving a hand to the path finding system for timing and such. My problem is on slow browsers the JavaScript loop I'm using for counting the time is not very accurate. It tends to jump around a lot. I there a way to force the loop to run consistently at 30 fps? The automata can drop frames if it needs to catch up so if the solution requires dropping frames that's ok.

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  • Insert rownumber repeatedly in records in t-sql.

    - by jeff
    Hi, I want to insert a row number in a records like counting rows in a specific number of range. example output: RowNumber ID Name 1 20 a 2 21 b 3 22 c 1 23 d 2 24 e 3 25 f 1 26 g 2 27 h 3 28 i 1 29 j 2 30 k I rather to try using the rownumber() over (partition by order by column name) but my real records are not containing columns that will count into 1-3 rownumber. I already try to loop each of record to insert a row count 1-3 but this loop affects the performance of the query. The query will use for the RDL report, that is why as much as possible the performance of the query must be good. any suggestions are welcome. Thanks

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  • Concatenation with Zero is not occuring properly in code?

    - by Vineet
    I was trying to reverse a number in pl/sql ,its working fine but when my number contain any 0,output come unexpected .for eg 1234 output 4321 1000 output 1 1203 ouput 3021 10001 output 1 DECLARE r number(9); num number(9):=&p_num; BEGIN WHILE num>=1 LOOP IF mod(num,10)=0 THEN -- extracting last digit of a number . r:=r||0; --if end digit is 0 then concat r with 0 ELSE r:=r||mod(num,10);--if mod is not 0 then it would be last digit. END IF; num:=trunc(num/10);--Removing last digit from number END LOOP; dbms_output.put_line(r); END;

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  • Windbg pseudoregister expansion

    - by Giuseppe Guerrini
    Hi, I am trying to automate a device driver's debug session in Windows XP with Windbg. My device has an "index" register and a "data" register, both memory mapped. The index register must be filled with the internal register's index, and the value can be read from the data register. So, the followind Windbg command prints correctly the value of the internel register 0x4C: !ed [uc] 0xfa000000 0x4c; !dd [uc] 0xfa000004 L1 Now I would like to dump a range of internal registers, but it seems that the alias expansion doesn't work as expected in the !ed command. I am trying this cycle: .for (r $t0=0; @$t0<0x100; r $t0=@$t0+1) { !ed [uc] 0xfa000000 @$t0; !dd [uc] 0xfa000004 L1 } but it seems that the !ed command is ignored, as if @$t0 was expanded in an empty string. Tried "$t0", "@$t0", "${t0}" and "@${t0}", but without success. What am I doing wrong? Thank you in advance

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  • SQL bottleneck, how to fix

    - by masfenix
    This is related to my previous thread: http://stackoverflow.com/questions/3069806/sql-query-takes-about-10-20-minutes However, I kinda figured out the problem. The problem (as described in the previous thread) is not the insert (while its still slow), the problem is looping through the data itself Consider the following code: Dim rs As DAO.Recordset Dim sngStart As Single, sngEnd As Single Dim sngElapsed As Single Set rs = CurrentDb().QueryDefs("select-all").OpenRecordset MsgBox "All records retreived" sngStart = Timer Do While Not rs.EOF rs.MoveNext Loop sngEnd = Timer sngElapsed = Format(sngEnd - sngStart, "Fixed") ' Elapsed time. MsgBox ("The query took " & sngElapsed _ & " seconds to run.") As you can see, this loop does NOTHING. You'd expect it to finish in seconds, however it takes about 857 seconds to run (or 15 minutes). I dont know why it is so slow. Maybe the lotusnotes sql driver? any other ideas? (java based solution, any other solution) What my goal is: To get all the data from remote server and insert into local access table

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  • ruby-gstreamer doesn't send EOS message

    - by Cheba
    I've managed to make it play sound but it never gets EOS message. And thus script never exits. require 'gst' main_loop = GLib::MainLoop.new pipeline = Gst::Pipeline.new "audio-player" source = Gst::ElementFactory.make "filesrc", "file-source" source.location = "/usr/share/sounds/gnome/default/alerts/bark.ogg" decoder = Gst::ElementFactory.make "decodebin", "decoder" conv = Gst::ElementFactory.make "audioconvert", "converter" sink = Gst::ElementFactory.make "alsasink", "output" pipeline.add source, decoder, conv, sink source >> decoder conv >> sink decoder.signal_connect "pad-added" do |element, pad, data| pad >> conv['sink'] end pipeline.bus.add_watch do |bus, message| puts "Message: #{message.inspect}" case message.type when Gst::Message::Type::ERROR puts message.structure["debug"] main_loop.quit when Gst::Message::Type::EOS puts 'End of stream' main_loop.quit end end pipeline.play begin puts 'Running main loop' main_loop.run ensure puts 'Shutting down main loop' pipeline.stop end

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  • Help with complex sql query

    - by eugeneK
    To make story short, i'm building self-learning banner management system. Users will be able to insert these banners to their site when banners will be shown based on sales/impressions ratio. I have 4 tables Banners bannerID int bannerImage varchar.... SmartBanners smartBannerID int smartBannerArrayID int bannerID int impressionsCount int visibility tinyint (percents) SmartBannerArrays smartBannerArrayID int userID int Statistics bannerID int saleAmountPerDay decimal... Each night i need to generate new "visibility" for each SmartBanner based on whole SmartBannerArray that same user has. So i need to get sum of impressions and sales for each bannerID in SmartBannerArray. All comes to my mind is to use double cursor, one will loop thought SmartBannerArrays get needed values for sum of impressions and sales and then inner loop which will access each SmartBanner and change it's "visibility" percentage based on (sales/impressions)/(sumOfSales/sumOfImpressions)*100 Hope you get the picture... Is there any other way to design better tables or not to use double cursor to avoid server overload ?

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  • iPhone SDK: Bonjour & NSNetService name != published name?

    - by Harkonian
    In my iPhone app, I'm publishing a bonjour service and using the following delegate method: - (void)netServiceDidPublish:(NSNetService *)ns { NSLog(@"Bonjour Service Published: http://%@.%@", [ns name], [ns domain]); } The "name" property is returning the device name, "How's Testing", which is correct. However, when I use Safari to discover available services the name is "hows-testing" -- the service is http://hows-testing.local.:. Why is the published name different than what is being reported by the NSNetService? How do I display for the actual name of the published service? Assuming that, for some reason, there is no way to get the published name from the object, how do I determine it myself? I understand that it's based on device name, but what are the substitution rules? Remove apostrophes, replace spaces with dash...anything else? What about special characters?

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  • best practice to obtain time zone for iPhone vs iPod Touch

    - by johnbdh
    I am creating an app that requires the users current time zone. If the device being used is an iPhone and the user has their Time Zone set to automatically change, I think I can be fairly confident that localTimeZone or systemTimezone will give me the correct time zone for the user's location. If on the other hand the device is an iPod Touch, the time zone returned by localTimeZone and systemTimeZone appears to always be whatever time zone is set in the Date & Time settings, regardless of the user's actual location. I tried using location services but, while the lat/long is being provided properly, the time zone offset in the timesStamp I am getting is always the same as whatever the user has set for their time zone setting. Any suggestions? John

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  • Oracle 10g - Best way to escape single quotes

    - by satynos
    I have to generate some update statements based off a table in our database. I created the following script which is generating the update statements I need. But when I try to run those scripts I am getting errors pertaining to unescaped single quotes in the content and &B, &T characters which have special meaning in oracle. I took care of the &B and &T problem by setting SET DEFINE OFF. Whats the best way to escape single quotes within the content? DECLARE CURSOR C1 IS SELECT * FROM EMPLOYEES; BEGIN FOR I IN C1 LOOP DBMS_OUTPUT.PUT_LINE('UPDATE EMPLOYEES SET FIRST_NAME= ''' || I.FIRST_NAME|| ''', LAST_NAME = ''' || I.LAST_NAME ''', DOB = ''' || I.DOB|| ''' WHERE EMPLOYEE_ID = ''' || I.EMPLOYEE_ID || ''';'); END LOOP; END; Here if the first_name or last_name contains single quotes then the generated update statements break. Whats the best way to escape those single quotes within the first_name and last_name?

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  • How to always run a service in the background

    - by Thomas H
    Hi I am in the process of creating an app that is similar to the build-in SMS app. What I need: - a service that is always running in the background - every 5 min. the service checks the current location of the device and calls a web service - if certain criteria are meet, the service should generate a notification (just like the SMS app) - when the notification is clicked, the user is taken to the app (just like the SMS app) - when the app is installed the service should be started - when the device is rebooted, the service should be started What I have tried: - running a regular service which worked just fine until android kills the service - using the AlarmManager the make the 5 min. interval call to a service. But I was not able to make this work. Any help would be greatly appreciated... -Thomas

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  • Performance Optimization for Matrix Rotation

    - by Summer_More_More_Tea
    Hello everyone: I'm now trapped by a performance optimization lab in the book "Computer System from a Programmer's Perspective" described as following: In a N*N matrix M, where N is multiple of 32, the rotate operation can be represented as: Transpose: interchange elements M(i,j) and M(j,i) Exchange rows: Row i is exchanged with row N-1-i A example for matrix rotation(N is 3 instead of 32 for simplicity): ------- ------- |1|2|3| |3|6|9| ------- ------- |4|5|6| after rotate is |2|5|8| ------- ------- |7|8|9| |1|4|7| ------- ------- A naive implementation is: #define RIDX(i,j,n) ((i)*(n)+(j)) void naive_rotate(int dim, pixel *src, pixel *dst) { int i, j; for (i = 0; i < dim; i++) for (j = 0; j < dim; j++) dst[RIDX(dim-1-j, i, dim)] = src[RIDX(i, j, dim)]; } I come up with an idea by inner-loop-unroll. The result is: Code Version Speed Up original 1x unrolled by 2 1.33x unrolled by 4 1.33x unrolled by 8 1.55x unrolled by 16 1.67x unrolled by 32 1.61x I also get a code snippet from pastebin.com that seems can solve this problem: void rotate(int dim, pixel *src, pixel *dst) { int stride = 32; int count = dim >> 5; src += dim - 1; int a1 = count; do { int a2 = dim; do { int a3 = stride; do { *dst++ = *src; src += dim; } while(--a3); src -= dim * stride + 1; dst += dim - stride; } while(--a2); src += dim * (stride + 1); dst -= dim * dim - stride; } while(--a1); } After carefully read the code, I think main idea of this solution is treat 32 rows as a data zone, and perform the rotating operation respectively. Speed up of this version is 1.85x, overwhelming all the loop-unroll version. Here are the questions: In the inner-loop-unroll version, why does increment slow down if the unrolling factor increase, especially change the unrolling factor from 8 to 16, which does not effect the same when switch from 4 to 8? Does the result have some relationship with depth of the CPU pipeline? If the answer is yes, could the degrade of increment reflect pipeline length? What is the probable reason for the optimization of data-zone version? It seems that there is no too much essential difference from the original naive version. EDIT: My test environment is Intel Centrino Duo processor and the verion of gcc is 4.4 Any advice will be highly appreciated! Kind regards!

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  • Abort a slow flush to disk after write?

    - by Therealstubot
    Is there a way to abort a python write operation in such a way that the OS doesn't feel it's necessary to flush the unwritten data to the disc? I'm writing data to a USB device, typically many megabytes. I'm using 4096 bytes as my block size on the write, but it appears that Linux caches up a bunch of data early on, and write it out to the USB device slowly. If at some point during the write, my user decides to cancel, I want the app to just stop writing immediately. I can see that there's a delay between when the data stops flowing from the application, and the USB activity light stops blinking. Several seconds, up to about 10 seconds typically. I find that the app is holding in the close() method, I'm assuming, waiting for the OS to finish writing the buffered data. I call flush() after every write, but that doesn't appear to have any impact on the delay. I've scoured the python docs for an answer but have found nothing.

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  • Adding an Object to Vector loses Reference using Java?

    - by thechiman
    I have a Vector that holds a number of objects. My code uses a loop to add objects to the Vector depending on certain conditions. My question is, when I add the object to the Vector, is the original object reference added to the vector or does the Vector make a new instance of the object and adds that? For example, in the following code: private Vector numbersToCalculate; StringBuffer temp = new StringBuffer(); while(currentBuffer.length() > i) { //Some other code numbersToCalculate.add(temp); temp.setLength(0); //resets the temp StringBuffer } What I'm doing is adding the "temp" StringBuffer to the numbersToCalculate Vector. Should I be creating a new StringBuffer within the loop and adding that or will this code work? Thanks for the help! Eric

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  • Packet Crafting on a Mac

    - by JayCrossler
    I think (based on searching the forums), that NetCat is the best option, but wanted to hear if others are preferable. Anyone have good success with a packet-crafting tool (specifically on Mac)? I've tried HPing, but had some issues. I'm looking into NetCat ('nc' on mac) now, but it's not working as I had thought. Basically, I captured some packets that a remote control sends over a wifi network to turn lights on and off (using X10 controllers), and am looking for a way to replay them by crafting a TCP packet from the command line. I used Wireshark to sniff the traffic, so I know the package is: DEVICE -sendplc-"C4 DIM 10" I'm trying: echo 'DEVICE -sendplc-"C4 DIM 10"' nc 192.168.2.196 6003 but there's no response from the receiving system. The exact bytestream is (if anyone wants to check that I got the right dataframe): 08004642f1b400260897ad6308004500004b08e240004006aaf5c0a802c1c0a802c4d8d7177399aab39 e57ff4753801880ae37ea00000101080a323353ce01b406424445564943457e73656e64706c637e2243 34204f4e220a Next step I'm going to check is to make sure the packet arrives exactly by sniffing and compare it to the original. [EDIT: Also at ServerFault now: Packet Crafting on a Mac, so this one becomes a duplicate across the two sites]

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  • stop and split generated sequence at repeats - clojure

    - by fitzsnaggle
    I am trying to make a sequence that will only generate values until it finds the following conditions and return the listed results: case head = 0 - return {:origin [all generated except 0] :pattern 0} 1 - return {:origin nil :pattern [all-generated-values] } repeated-value - {:origin [values-before-repeat] :pattern [values-after-repeat] { ; n = int ; x = int ; hist - all generated values ; Keeps the head below x (defn trim-head [head x] (loop [head head] (if (> head x) (recur (- head x)) head))) ; Generates the next head (defn next-head [head x n] (trim-head (* head n) x)) (defn row [x n] (iterate #(next-head % x n) n)) ; Generates a whole row - ; Rows are a max of x - 1. (take (- x 1) (row 11 3)) Examples of cases to stop before reaching end of row: [9 8 4 5 6 7 4] - '4' is repeated so STOP. Return preceding as origin and rest as pattern. {:origin [9 8] :pattern [4 5 6 7]} [4 5 6 1] - found a '1' so STOP, so return everything as pattern {:origin nil :pattern [4 5 6 1]} [3 0] - found a '0' so STOP {:origin [3] :pattern [0]} :else if the sequences reaches a length of x - 1: {:origin [all values generated] :pattern nil} The Problem I have used partition-by with some success to split the groups at the point where a repeated value is found, but would like to do this lazily. Is there some way I can use take-while, or condp, or the :while clause of the for loop to make a condition that partitions when it finds repeats? Some Attempts (take 2 (partition-by #(= 1 %) (row 11 4))) (for [p (partition-by #(stop-match? %) head) (iterate #(next-head % x n) n) :while (or (not= (last p) (or 1 0 n) (nil? (rest p))] {:origin (first p) :pattern (concat (second p) (last p))})) # Updates What I really want to be able to do is find out if a value has repeated and partition the seq without using the index. Is that possible? Something like this - { (defn row [x n] (loop [hist [n] head (gen-next-head (first hist) x n) steps 1] (if (>= (- x 1) steps) (case head 0 {:origin [hist] :pattern [0]} 1 {:origin nil :pattern (conj hist head)} ; Speculative from here on out (let [p (partition-by #(apply distinct? %) (conj hist head))] (if-not (nil? (next p)) ; One partition if no repeats. {:origin (first p) :pattern (concat (second p) (nth 3 p))} (recur (conj hist head) (gen-next-head head x n) (inc steps))))) {:origin hist :pattern nil}))) }

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  • Compressing three individual jpeg pics containing temporal redundancy?

    - by michael
    I am interfacing and embedded device with a camera module that returns a single jpeg compressed frame each time I trigger it. I would like to take three successive shots (approx 1 frame per 1/4 second) and further compress the images into a single file. The assumption here is that there is a lot of temporal redundancy, therefore lots of room for more compression across the three frames (compared to sending three separate jpeg images). I will be implementing the solution on an embedded device in C without any libraries and no OS. The camera will be taking pics in an area with very little movement (no visitors or screens in the background, maybe a tree with swaying branches), so I think my assumption about redundancy is pretty solid. When the file is finally viewed on a pc/mac, I don't mind having to write something to extract the three frames (so it can be a nonstandard cluge) So I guess the actual question is: What is the best way to compress these three images together given the fact that they are already in JPEG format (it is a possibly to convert back to a raw image, but if i dont have too...)

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  • GKSession sendDataToAllPeers including sender?

    - by Typeoneerror
    I've got a number of devices connected over wifi using GameKit. I have a simple UIAlertView popping up when peers receive data. All but the sendee show this alert view when data is sent, so I'm wondering if that's a bug in my app or if that's expected behavior. If the device doing the sending is also a GKSessionModePeer, I would expect it to "fire" its receiveData: message as well since I'm sending to all peers. Should I call a method manually at the same on the sendee device? For example, if I wanted to send a "GameStart" packet to the 4 phones, the peers would call startGame: in the receiveData:fromPeer:inSession:context: method when it receives that packet and the sendee would be calling sendDataToAllPeers: and call startGame: on itself. Does that sound right or is there a way to include the sendee in the sendDataToAllPeers: list so that it responds exactly the same as all connected peers?

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