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  • PHP login, getting wrong count value from query / fetch array

    - by Chris
    Hello, *EDIT*Thanks to the comments below it has been figured out that the problem lies with the md5, without everything works as it should. But how do i implent the md5 then? I am having some troubles with the following code below to login. The database and register system are already working. The problem lies that it does not find any result at all in the query. IF the count is 0 it should redirect the user to a secured page. But this only works if i write count = 0, but this should be 0 , only if the user name and password is found he should be directed to the secure (startpage) of the site after login. For example root (username) root (password) already exists but i cannot seem to properly login with it. <?php session_start(); if (!empty($_POST["send"])) { $username = ($_POST["username"]); $password = (md5($_POST["password"])); $count = 0; $con = mysql_connect("localhost" , "root", ""); mysql_select_db("testdb", $con); $result = mysql_query("SELECT name, password FROM user WHERE name = '".$username."' AND password = '".$password."' ") or die("Error select statement"); $count = mysql_num_rows($result); if($count > 0) // always goes the to else, only works with >=0 but then the data is not found in the database, hence incorrect { $row = mysql_fetch_array($result); $_SESSION["username"] = $row["name"]; header("Location: StartPage.php"); } else { echo "Wrong login data, please try again"; } mysql_close($con); } ?>

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  • Whenever I hold alt/option and move my mouse, Mac OS X resizes my window... how do I stop that?

    - by Justin Searls
    I've been using Mac OS X for maybe 6 years now, and I have no idea what's causing this. Maybe someone else has this experience and can help me out. Symptom: while holding the alt/option key, if I move my mouse the current window starts resizing, anchored at the top left (it behaves exactly as if I had clicked-and-dragged the lower-right icon on the window). Anyone have an idea of what I may have installed that caused this? Or how to make it stop?

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  • Is there a Hyper-V virtual machine client for XP? Linux? Mac?

    - by mattlandis
    Is there a Hyper-V virtual machine client for XP? Linux? Mac? I'm aware that we could VNC or RDP into the virtual machine but the problem is if the VM is not running or is suspend the end user can't start it and IT needs to get involved. I guess what I'm looking for is something like VMconnect.exe that runs on xp or linux. Or, If I am totally barking up the wrong tree let me know. ;-)

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  • Returning Json object from controller action to jQuery

    - by PsychoCoder
    I'm attempting to get this working properly (2 days now). I'm working on a log in where I'm calling the controller action from jQuery, passing it a JSON object (utilizing json2.js) and returning a Json object from the controller. I'm able to call the action fine, but instead of being able to put the response where I want it it just opens a new window with this printed on the screen: {"Message":"Invalid username/password combination"} And the URL looks like http://localhost:13719/Account/LogOn so instead of calling the action and not reloading the page it's taking the user to the controller, which isn't good. So now for some code, first the controller code [HttpPost] public ActionResult LogOn(LogOnModel model, string returnUrl = "") { if (ModelState.IsValid) { var login = ObjectFactory.GetInstance<IRepository<PhotographerLogin>>(); var user = login.FindOne(x => x.Login == model.Username && x.Pwd == model.Password); if (user == null) return Json(new FailedLoginViewModel { Message = "Invalid username/password combination" }); else { if (!string.IsNullOrEmpty(returnUrl)) return Redirect(returnUrl); else return RedirectToAction("Index", "Home"); } } return RedirectToAction("Index", "Home"); } And the jQuery code $("#signin_submit").click(function () { var login = getLogin(); $.ajax({ type: "POST", url: "../Account/LogOn", data: JSON.stringify(login), dataType: 'json', contentType: 'application/json; charset=utf-8', error: function (xhr) { $("#message").text(xhr.statusText); }, success: function (result) { } }); }); function getLogin() { var un = $("#username").val(); var pwd = $("#password").val(); var rememberMe = $("#rememberme").val(); return (un == "") ? null : { Username: un, Password: pwd, RememberMe: rememberMe }; } In case you need to see the actual login form here that is as well <fieldset id="signin_menu"> <div> <span id="message"></span> </div> <% Html.EnableClientValidation(); %> <% using (Html.BeginForm("LogOn", "Account", FormMethod.Post, new { @id = "signin" })) {%> <% ViewContext.FormContext.ValidationSummaryId = "valLogOnContainer"; %> <%= Html.LabelFor(m => m.Username) %> <%= Html.TextBoxFor(m => m.Username, new { @class = "inputbox", @tabindex = "4", @id = "username" })%><%= Html.ValidationMessageFor(m => m.Username, "*")%> <p> <%= Html.LabelFor(m=>m.Password) %> <%= Html.PasswordFor(m => m.Password, new { @class = "inputbox", @tabindex = "5", @id = "password" })%><%= Html.ValidationMessageFor(m => m.Password, "*")%> </p> <p class="remember"> <input id="signin_submit" value="Sign in" tabindex="6" type="submit"/> <%= Html.CheckBoxFor(m => m.RememberMe, new { @class = "inputbox", @tabindex = "7", @id = "rememberme" })%> <%= Html.LabelFor(m => m.RememberMe) %> <p class="forgot"> <a href="#" id="forgot_password_link" title="Click here to reset your password.">Forgot your password?</a> </p> <p class="forgot-username"> <a href="#" id="forgot_username_link" title="Fogot your login name? We can help with that">Forgot your username?</a> </p> </p> <%= Html.ValidationSummaryJQuery("Please fix the following errors.", new Dictionary<string, object> { { "id", "valLogOnContainer" } })%> <% } %> </fieldset> The login form is loaded on the main page with <% Html.RenderPartial("LogonControl");%> Not sure if that has any bearing on this or not but thought I'd mention it. EDIT: The login form is loaded similar to the Twitter login, click a link and the form loads with the help of jQuery & CSS

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  • Solaris ldap Authentication

    - by Tman
    Iv been having a trouble trying to get my Solaris 10 server to authenticate against an eDir server.im managed to Set up my linux(RHeL,SLES) servers to authenticate against the ldap Server.which works fine. Here is my configuration Files. ldapclient list: NS_LDAP_FILE_VERSION= 2.0 NS_LDAP_BINDDN= cn=proxyuser,o=AEDev NS_LDAP_BINDPASSWD= {NS1}ecfa88f3a945c22222233 NS_LDAP_SERVERS= 192.168.0.19 NS_LDAP_SEARCH_BASEDN= ou=auth,o=AEDev NS_LDAP_AUTH= simple NS_LDAP_SEARCH_SCOPE= sub NS_LDAP_CACHETTL= 0 NS_LDAP_CREDENTIAL_LEVEL= anonymous NS_LDAP_SERVICE_SEARCH_DESC= group:ou=Groups,ou=auth,o=AEDev NS_LDAP_SERVICE_SEARCH_DESC= shadow:ou=users,ou=auth,o=AEDev?sub?objectClass=shadowAccount NS_LDAP_SERVICE_SEARCH_DESC= passwd:ou=auth,o=AEDev?sub?objectClass=posixAccount NS_LDAP_BIND_TIME= 10 NS_LDAP_SERVICE_AUTH_METHOD= pam_ldap:simple getent passwd works fine: root:x:0:0:Super-User:/:/sbin/sh daemon:x:1:1::/: bin:x:2:2::/usr/bin: sys:x:3:3::/: adm:x:4:4:Admin:/var/adm: lp:x:71:8:Line Printer Admin:/usr/spool/lp: uucp:x:5:5:uucp Admin:/usr/lib/uucp: nuucp:x:9:9:uucp Admin:/var/spool/uucppublic:/usr/lib/uucp/uucico smmsp:x:25:25:SendMail Message Submission Program:/: listen:x:37:4:Network Admin:/usr/net/nls: gdm:x:50:50:GDM Reserved UID:/: webservd:x:80:80:WebServer Reserved UID:/: postgres:x:90:90:PostgreSQL Reserved UID:/:/usr/bin/pfksh svctag:x:95:12:Service Tag UID:/: nobody:x:60001:60001:NFS Anonymous Access User:/: noaccess:x:60002:60002:No Access User:/: nobody4:x:65534:65534:SunOS 4.x NFS Anonymous Access User:/: tlla:x:2012:100::/home/tlla: test:x:2011:100::/home/test: thato:x:2010:100::/home/thato: pam.conf login auth sufficient pam_unix_auth.so.1 #server_policy login auth sufficient /usr/lib/security/pam_ldap.so.1 try_first_pass login auth required pam_dial_auth.so.1 rlogin auth sufficient pam_rhosts_auth.so.1 rlogin auth requisite pam_authtok_get.so.1 rlogin auth required pam_dhkeys.so.1 rlogin auth required pam_unix_cred.so.1 rlogin auth sufficient pam_unix_auth.so.1 rlogin auth sufficient /usr/lib/security/pam_ldap.so.1 try_first_pass rsh auth sufficient pam_rhosts_auth.so.1 rsh auth required pam_unix_cred.so.1 rsh auth sufficient pam_unix_auth.so.1 #server_policy rsh auth sufficient /usr/lib/security/pam_ldap.so.1 try_first_pass other auth requisite pam_authtok_get.so.1 other auth required pam_dhkeys.so.1 other auth required pam_unix_cred.so.1 other auth sufficient pam_unix_auth.so.1 other auth sufficient /usr/lib/security/pam_ldap.so.1 try_first_pass passwd auth required pam_passwd_auth.so.1 passwd auth sufficient pam_unix_auth.so.1 ssh account sufficient pam_unix.so.1 ssh account sufficient /usr/lib/security/pam_ldap.so.1 try_first_pass other account requisite pam_roles.so.1 other account sufficient pam_unix_account.so.1 other account sufficient /usr/lib/security/pam_ldap.so.1 try_first_pass other password required pam_dhkeys.so.1 other password requisite pam_authtok_get.so.1 other password requisite pam_authtok_check.so.1 other password required pam_authtok_store.so.1 other password sufficient pam_unix.so.1 other password sufficient /usr/lib/security/pam_ldap.so.1 try_first_pass Local Authentication Works But LDAP Authentication Doesn't Work.

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  • Linux udev persistent net rule

    - by Anonymous
    I have a Linux system (Slackware Linux 13.0) with two network interfaces. Let's call them NIC0 and NIC1 My goal is to make NIC0 to appear as eth0 in the system. I know this can be achieved via udev rules that map network aliases to MAC addresses of network interfaces. In Slackware Linux the file /etc/udev/rules.d/70-persistent-net.rules contains such rules. The trickiest part of my problem is that I need to fake the MAC address of NIC0. I know I can dynamically change the MAC addres of a network interface with the command: ifconfig eth0 hw ether <new MAC address> Do you see the problem? This supposes that the network interfaces are already set up. So my question is: If I would have an udev rule for NIC1(the one that shall go up as eth1, with its original MAC address), would it be enough for the system to bring the other network interface (NIC0) as eth0 by default? This way I could change its MAC address later, after the udev machinery completes and the network aliases are brought up.

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  • Bugzilla email issue

    - by xian
    My bugzilla system keep hit the following error: There was an error sending mail from '[email protected]' to '[email protected]':Can't send data I think that is some problem with my setting and configuration. First is the urlbase I have tried setting it to bugzilla.example.com, and http://127.0.0.1:81/, and http://10.0.0.236/ (My laptop IP address, I use this laptop to set up bugzilla) but the error still persists. Actually what should I put in the urlbase field? Parameter = Email Under mail_delivery_method, i choose SMTP. Under mailfrom, I put bugzilla-daemon. smtpserver, I tried leaving it blank, or setting it to 220.181.12.12 before, but could not solve my problem For my sql, the following is the data and command I used: C:\mysql\bin>mysql --user=root -p mysql Enter password: 1234 (When I install mysql into my laptop, it ask me to key an username and password, i have key in username as 'cvuser' and password as '1234', but here never ask me to key in any username) Welcome to the MySQL monitor. Commands end with ; or \g. Your MySQL connection id is 1 Server version: 5.5.15 MySQL Community Server (GPL) mysql> GRANT ALL PRIVILEGES ON bugs.* TO 'bugs'@'localhost' IDENTIFIED BY '123456'; Query OK, 0 rows affected (0.03 sec) In C:\Bugzilla\localconfig, I put the following info: # # How to access the SQL database: # $db_host = "localhost"; # where is the database? $db_port = 3306; # which port to use $db_name = "bugs"; # name of the MySQL database $db_user = "bugs"; # user to attach to the MySQL database # # Enter your database password here. It's normally advisable to specify # a password for your bugzilla database user. # If you use apostrophe (') or a backslash (\) in your password, you'll # need to escape it by preceding it with a \ character. (\') or (\\) # $db_pass = '123456'; Can someone tell me where my mistake is? I have googled for this issue for few days but still cannot find the solution.

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  • Can't login via ssh after upgrading to Ubuntu 12.10

    - by user42899
    I have an Ubuntu 12.04LTS instance on AWS EC2 and I upgraded it to 12.10 following the instructions at https://help.ubuntu.com/community/QuantalUpgrades. After upgrading I can no longer ssh into my VM. It isn't accepting my ssh key and my password is also rejected. The VM is running, reachable, and SSH is started. The problem seems to be about the authentication part. SSH has been the only way for me to access that VM. What are my options? ubuntu@alice:~$ ssh -v -i .ssh/sos.pem [email protected] OpenSSH_5.9p1 Debian-5ubuntu1, OpenSSL 1.0.1 14 Mar 2012 debug1: Reading configuration data /home/ubuntu/.ssh/config debug1: Reading configuration data /etc/ssh/ssh_config debug1: /etc/ssh/ssh_config line 19: Applying options for * debug1: Connecting to www.hostname.com [37.37.37.37] port 22. debug1: Connection established. debug1: identity file .ssh/sos.pem type -1 debug1: identity file .ssh/sos.pem-cert type -1 debug1: Remote protocol version 2.0, remote software version OpenSSH_5.9p1 Debian-5ubuntu1 debug1: match: OpenSSH_5.9p1 Debian-5ubuntu1 pat OpenSSH* debug1: Enabling compatibility mode for protocol 2.0 debug1: Local version string SSH-2.0-OpenSSH_5.9p1 Debian-5ubuntu1 debug1: SSH2_MSG_KEXINIT sent debug1: SSH2_MSG_KEXINIT received debug1: kex: server->client aes128-ctr hmac-md5 none debug1: kex: client->server aes128-ctr hmac-md5 none debug1: sending SSH2_MSG_KEX_ECDH_INIT debug1: expecting SSH2_MSG_KEX_ECDH_REPLY debug1: Server host key: RSA 33:33:33:33:33:33:33:33:33:33:33:33:33:33 debug1: Host '[www.hostname.com]:22' is known and matches the RSA host key. debug1: Found key in /home/ubuntu/.ssh/known_hosts:12 debug1: ssh_rsa_verify: signature correct debug1: SSH2_MSG_NEWKEYS sent debug1: expecting SSH2_MSG_NEWKEYS debug1: SSH2_MSG_NEWKEYS received debug1: Roaming not allowed by server debug1: SSH2_MSG_SERVICE_REQUEST sent debug1: SSH2_MSG_SERVICE_ACCEPT received debug1: Authentications that can continue: publickey,password debug1: Next authentication method: publickey debug1: Trying private key: .ssh/sos.pem debug1: read PEM private key done: type RSA debug1: Authentications that can continue: publickey,password debug1: Next authentication method: password [email protected]'s password: debug1: Authentications that can continue: publickey,password Permission denied, please try again.

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  • Duplicity on a ReadyNAS

    - by Jason Swett
    Has anyone here run Duplicity on a ReadyNAS? I'm trying but here's what I get: duplicity full --encrypt-key="ABC123" /home/jason/ scp://[email protected]//gob Invalid SSH password Running 'sftp -oServerAliveInterval=15 -oServerAliveCountMax=2 [email protected]' failed (attempt #1) I've also found this post that says the "Invalid SSH password" message doesn't actually mean invalid SSH password. This would make sense because I'm not using an SSH password; I'm using a public key. I can ssh, ftp, sftp and rsync into my ReadyNAS just fine. (Actually, to be more accurate, I can get past authentication with ssh, ftp and sftp but I can't actually do anything past that. Regardless, that's enough to tell me that "Invalid SSH password" is bogus. Rsync works with no problems.) The post I found says the command will work as soon as the directory at the end of your scp command exists, but I don't know how to check for that. I know the share gob exists on my ReadyNAS and I know it's writable because I'm writing to it with rsync. Also, here is the verbose output: Using archive dir: /home/jason/.cache/duplicity/3bdd353b29468311ffa8485160da6873 Using backup name: 3bdd353b29468311ffa8485160da6873 Import of duplicity.backends.rsyncbackend Succeeded Import of duplicity.backends.sshbackend Succeeded Import of duplicity.backends.localbackend Succeeded Import of duplicity.backends.botobackend Succeeded Import of duplicity.backends.cloudfilesbackend Succeeded Import of duplicity.backends.giobackend Succeeded Import of duplicity.backends.hsibackend Succeeded Import of duplicity.backends.imapbackend Succeeded Import of duplicity.backends.ftpbackend Succeeded Import of duplicity.backends.webdavbackend Succeeded Import of duplicity.backends.tahoebackend Succeeded Main action: full ================================================================================ duplicity 0.6.10 (September 19, 2010) Args: /usr/bin/duplicity full --encrypt-key=ABC123 -v9 /home/jason/ scp://[email protected]//gob Linux gob 2.6.35-22-generic #33-Ubuntu SMP Sun Sep 19 20:34:50 UTC 2010 i686 /usr/bin/python 2.6.6 (r266:84292, Sep 15 2010, 15:52:39) [GCC 4.4.5] ================================================================================ Using temporary directory /tmp/duplicity-cridGi-tempdir Registering (mkstemp) temporary file /tmp/duplicity-cridGi-tempdir/mkstemp-ztuF5P-1 Temp has 86334349312 available, backup will use approx 34078720. Running 'sftp -oServerAliveInterval=15 -oServerAliveCountMax=2 [email protected]' (attempt #1) State = sftp, Before = '[email protected]'s' State = sftp, Before = '' Invalid SSH password Running 'sftp -oServerAliveInterval=15 -oServerAliveCountMax=2 [email protected]' failed (attempt #1) Any ideas as to what's going wrong?

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  • How to link to a subfolder of a share?

    - by Nicolas Raoul
    On my Windows XP server, a folder called Share2 is shared. It contains a subfolder called folder3. The guest account is protected by a password, which means network users have to type the guest password to access it. When a user types \\server\Share2 in his file explorer, he is prompted for a password. When a user types \\server\Share2\folder3 in his file explorer, an error appears. He is not even prompted for a password. This is problematic because I want to link to this particular folder. How can I link to folder3? Notes: - Both Desktop shortcuts and HTML links in IE7/8 give an error if I link to folder3, but work if I just link to Share2. - Using the file:// syntax instead of the \\ syntax leads to the same results. - Password setting per http://www.lancelhoff.com/how-to-password-protect-a-shared-folder - Not using "Simple File Sharing" - The error message is ???????????????????????? which means "could not find it. check the path and try again". No English Windows around to try, sorry! It is easy to reproduce the problem though, so can anyone post the English error message for the sake of searchability? Thanks!

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  • Failure to obtain IP with ARP over Wi-Fi with personal Wi-Fi router in client mode

    - by axk
    I'm trying to connect a Samsung TV to the Internet using a TL-MR3020 personal wireless router in client mode. The TV fails to connect to the network. It sees the ethernet cable connected though. Here's my network topology: Here's what I've captured with Wireshark filtering for ARP (eth.type == 0x0806): It appears the TV fails to get the IP of the gateway (DSL modem/router) for some reason. One thing I've noticed is that the source MAC for the ARP requests coming from the TV is the MAC of the Portable wireless router (that is cd:89:00), not the TV itself and the modem sends the responses to that MAC (I'm not an expert and don't know if its okay or it may make the TV fail to get the requested IP). Also I'm able to ping the TV from the DSL router (through the telnet interface) and the router has an entry in its MAC table for the TV's IP with the Portable wireless router's MAC (that is cd:89:00). If I'm able to ping the TV I suppose it should know the router's MAC to respond to the ping, but then why these continuous ARP requests... I've also tried to connect my desktop trough this Portable wireless router the same way I'm trying to connect the TV and it works fine, I can set the DSL Modem's IP as the default gateway on the desktop's NIC and connect to the Internet. The TV can connect to the Internet when connected to the DSL Router with a wired connection. Any suggestions on what may be the cause of the problem / how to further debug it are welcome. Thanks!

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  • Home Sharing and Remote on iTunes causing firewall nags

    - by BoltClock
    It seems that enabling Home Sharing and/or hooking up my iPhone's Remote to iTunes causes Mac OS X Snow Leopard's firewall to freak out and keep nagging every time I launch iTunes to ask if I'd like it to accept incoming connections. If I turn off Home Sharing and forget all Remotes, the nag dialog no longer comes up. I could also disable the firewall, but I think that's a silly thing to do. iTunes is already in the firewall whitelist, so the only thing I know that could cause Mac OS X to nag is a bad application bundle code signature. I checked with this Terminal command: $ codesign -vvv /Applications/iTunes.app/ And sure enough, this is what it outputs: /Applications/iTunes.app/: a sealed resource is missing or invalid /Applications/iTunes.app/Contents/Resources/English.lproj/AutofillSettings.nib/objects.xib: resource added /Applications/iTunes.app/Contents/Resources/English.lproj/iTunesDJSettings.nib/objects.xib: resource added /Applications/iTunes.app/Contents/Resources/English.lproj/MobilePhonePrefs.nib/objects.xib: resource added /Applications/iTunes.app/Contents/Resources/English.lproj/MobilePhoneSetup.nib/objects.xib: resource added /Applications/iTunes.app/Contents/Resources/English.lproj/UniversalAccess.nib/objects.xib: resource added I've tried reinstalling iTunes as suggested by this answer, but Mac OS X still nags about incoming connections and the exact same output is generated when I run the above command again. On my PC, Windows Firewall has never nagged whenever I turn on Home Sharing and hook up Remote on my iPhone. Both computers use iTunes 9.2.1. My Mac runs Mac OS X 10.6.4. Is there anything special I need to do that I might have missed? Or how do I resolve the issue? EDIT: I've updated to iTunes 10, but the nags on my Mac are still there and only go away if I turn off Home Sharing and Remote. EDIT 2: I've updated to Remote 2.0 on my iPhone, but the firewall nags are persisting. Has anyone else had this firewall issue at all?

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  • How do I remove encryption from a VMware Workstation 7 image?

    - by Chad
    I successfully encrypted a VM image and confirmed it still runs. I then closed the VM and reopened it and confirmed the encryption password was valid and worked. However, now I want to un-encrypt the VM. When I choose that option, it asks for "your password". I assume this means the password I created when I encrypted it. It doesn't work. I can still open the VM with the password and run it. But, it refuses to remove the encryption using that password. Am I missing something? Is there a password that I don't know about? Some details: I created this image (using standalone converter; physical machine source) I converted it to ACE Converted back to a normal VM (un-ACE'd it) Encrypted it Cannot remove the encryption but can open it and run it As you can see... I am exploring the VMware features. Thanks for any guidance you can give.

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  • Apache Server not working in MAMP

    - by jasonaburton
    Here's what I did before the problem started: I was creating a database for a site that I am working on in phpMyAdmin. I wrote some code to try to connect to the database I just created and I couldn't connect. I assumed it might be because I needed a password to connect to the database, so I created a password for it. Immediately after I created the password phpMyAdmin kicked me out saying: "#1045 - Access denied for user 'root'@'localhost' (using password: YES)" "phpMyAdmin tried to connect to the MySQL server, and the server rejected the connection. You should check the host, username and password in your configuration and make sure that they correspond to the information given by the administrator of the MySQL server." I found the php.ini file and searched for where I could change the password to match the one I just made, but couldn't find where I needed to change it. So I decided to scrap the database and uninstall MAMP from my computer and reinstall it hoping it would just reset all the defaults and I could go on my merry way. But now after reinstalling MAMP and trying to run the servers Apache won't start up and I have no idea why. One problem after another... Any advice or helpful ideas?

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  • How do I remove encryption from a VMware Workstation 7 image?

    - by Chad
    I successfully encrypted a VM image and confirmed it still runs. I then closed the VM and reopened it and confirmed the encryption password was valid and worked. However, now I want to un-encrypt the VM. When I choose that option, it asks for "your password". I assume this means the password I created when I encrypted it. It doesn't work. I can still open the VM with the password and run it. But, it refuses to remove the encryption using that password. Am I missing something? Is there a password that I don't know about? Some details: I created this image (using standalone converter; physical machine source) I converted it to ACE Converted back to a normal VM (un-ACE'd it) Encrypted it Cannot remove the encryption but can open it and run it As you can see... I am exploring the VMware features. Thanks for any guidance you can give.

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  • All application passwords lost on Windows 7

    - by Rynardt
    A couple of days ago I changed my Windows 7 login password. My laptop is on my company's domain, so password changes are done over the internal network. Since changing the password I noticed that all my saved Chrome passwords are missing. Also Skype, Windows Live, Internet Explorer and Outlook lost their saved passwords. I guess there could be more applications with lost passwords, but I have not opened them yet. This makes me think that most applications saves their passwords to a general password vault on the Windows system and this vault got somehow corrupted when I changed my domain login password for windows. Do anyone have any idea of how to fix this and prevent it from happening again? EDIT : More Info I do development work at the office, so most of the time I bypass the firewall and connect directly to the internet gateway. Now and then I would connect to the company wifi network to do printing and access files on a NAS. So by default my laptop does not connect to the wifi hotspot. On this occasion to update the password, I had to connect to the wifi. So referring to the comment by OmnipotentEntity below, could this have happened when the system rebooted without a connection to the network as the laptop does not auto connect to the wifi hotspot?

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  • Router vs switch in a LAN [closed]

    - by servernewbie
    If I have a LAN and and connect it with a switch, I understand it uses a CAM table to route packets in layer 2 (by saving mac to port relations). So far all good. However, when using a router for a LAN (ONLY for a LAN, not to connect it to "the outside" WAN/internet/etc) I get a bit confused as to how it internally processes packets. I would first split this into two router scenarios: Router with buit-in switch In this scenario, I would expect that it will act exactly as a switch with a CAM table internally. This would probably benefit a bit in speed (guessing here?) compared to the next option. Router without built-in switch Here is where I get confused. If hostA wants to send a packet to hostB, it will ARP to find hostB's MAC address and send it there. Now, if we had a switch (above scenario) this would be easy. But how does it work now in a router WITHOUT a switch? If I would guess, hostA would send an Ethernet frame with hostB's MAC address to the line. The router would fetch the packet (even though the router has another MAC address, it would still fetch this packet even if it only contains hostB's MAC address). It would strip the Ethernet frame header and check the IP, and then check its own internal ARP table again for the MAC address. Now, this would seem like a waste of resources compared to a router with a built-in switch. But maybe it does not work like that at all. Does it also contain a CAM table? If that would be true, what would then the difference between these two routers really be?

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  • Protect all XML-RPC calls with HTTP basic auth but one

    - by bodom_lx
    I set up a Django project for smartphone serving XML-RPC methods over HTTPS and using basic auth. All XML-RPC methods require username and password. I would like to implement a XML-RPC method to provide registration to the system. Obviously, this method should not require username and password. The following is the Apache conf section responsible for basic auth: <Location /RPC2> AuthType Basic AuthName "Login Required" Require valid-user AuthBasicProvider wsgi WSGIAuthUserScript /path/to/auth.wsgi </Location> This is my auth.wsgi: import os import sys sys.stdout = sys.stderr sys.path.append('/path/to/project') os.environ['DJANGO_SETTINGS_MODULE'] = 'project.settings' from django.contrib.auth.models import User from django import db def check_password(environ, user, password): """ Authenticates apache/mod_wsgi against Django's auth database. """ db.reset_queries() kwargs = {'username': user, 'is_active': True} try: # checks that the username is valid try: user = User.objects.get(**kwargs) except User.DoesNotExist: return None # verifies that the password is valid for the user if user.check_password(password): return True else: return False finally: db.connection.close() There are two dirty ways to achieve my aim with current situation: Have a dummy username/password to be used when trying to register to the system Have a separate Django/XML-RPC application on another URL (ie: /register) that is not protected by basic auth Both of them are very ugly, as I would also like to define a standard protocol to be used for services like mine (it's an open Dynamic Ridesharing Architecture) Is there a way to unprotect a single XML-RPC call (ie. a defined POST request) even if all XML-RPC calls over /RPC2 are protected?

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  • Protect all XML-RPC calls with HTTP basic auth but one

    - by bodom_lx
    I set up a Django project for smartphone serving XML-RPC methods over HTTPS and using basic auth. All XML-RPC methods require username and password. I would like to implement a XML-RPC method to provide registration to the system. Obviously, this method should not require username and password. The following is the Apache conf section responsible for basic auth: <Location /RPC2> AuthType Basic AuthName "Login Required" Require valid-user AuthBasicProvider wsgi WSGIAuthUserScript /path/to/auth.wsgi </Location> This is my auth.wsgi: import os import sys sys.stdout = sys.stderr sys.path.append('/path/to/project') os.environ['DJANGO_SETTINGS_MODULE'] = 'project.settings' from django.contrib.auth.models import User from django import db def check_password(environ, user, password): """ Authenticates apache/mod_wsgi against Django's auth database. """ db.reset_queries() kwargs = {'username': user, 'is_active': True} try: # checks that the username is valid try: user = User.objects.get(**kwargs) except User.DoesNotExist: return None # verifies that the password is valid for the user if user.check_password(password): return True else: return False finally: db.connection.close() There are two dirty ways to achieve my aim with current situation: Have a dummy username/password to be used when trying to register to the system Have a separate Django/XML-RPC application on another URL (ie: /register) that is not protected by basic auth Both of them are very ugly, as I would also like to define a standard protocol to be used for services like mine (it's an open Dynamic Ridesharing Architecture) Is there a way to unprotect a single XML-RPC call (ie. a defined POST request) even if all XML-RPC calls over /RPC2 are protected?

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  • Why is ssh agent forwarding not working?

    - by J. Pablo Fernández
    In my own computer, running MacOSX, I have this in ~/.ssh/config Host * ForwardAgent yes Host b1 ForwardAgent yes b1 is a virtual machine running Ubuntu 12.04. I ssh to it like this: ssh pupeno@b1 and I get logged in without being asked for a password because I already copied my public key. Due to forwarding, I should be able to ssh to pupeno@b1 from b1 and it should work, without asking me for a password, but it doesn't. It asks me for a password. What am I missing? This is the verbose output of the second ssh: pupeno@b1:~$ ssh -v pupeno@b1 OpenSSH_5.9p1 Debian-5ubuntu1, OpenSSL 1.0.1 14 Mar 2012 debug1: Reading configuration data /etc/ssh/ssh_config debug1: /etc/ssh/ssh_config line 19: Applying options for * debug1: Connecting to b1 [127.0.1.1] port 22. debug1: Connection established. debug1: identity file /home/pupeno/.ssh/id_rsa type -1 debug1: identity file /home/pupeno/.ssh/id_rsa-cert type -1 debug1: identity file /home/pupeno/.ssh/id_dsa type -1 debug1: identity file /home/pupeno/.ssh/id_dsa-cert type -1 debug1: identity file /home/pupeno/.ssh/id_ecdsa type -1 debug1: identity file /home/pupeno/.ssh/id_ecdsa-cert type -1 debug1: Remote protocol version 2.0, remote software version OpenSSH_5.9p1 Debian-5ubuntu1 debug1: match: OpenSSH_5.9p1 Debian-5ubuntu1 pat OpenSSH* debug1: Enabling compatibility mode for protocol 2.0 debug1: Local version string SSH-2.0-OpenSSH_5.9p1 Debian-5ubuntu1 debug1: SSH2_MSG_KEXINIT sent debug1: SSH2_MSG_KEXINIT received debug1: kex: server->client aes128-ctr hmac-md5 none debug1: kex: client->server aes128-ctr hmac-md5 none debug1: sending SSH2_MSG_KEX_ECDH_INIT debug1: expecting SSH2_MSG_KEX_ECDH_REPLY debug1: Server host key: ECDSA 35:c0:7f:24:43:06:df:a0:bc:a7:34:4b:da:ff:66:eb debug1: Host 'b1' is known and matches the ECDSA host key. debug1: Found key in /home/pupeno/.ssh/known_hosts:1 debug1: ssh_ecdsa_verify: signature correct debug1: SSH2_MSG_NEWKEYS sent debug1: expecting SSH2_MSG_NEWKEYS debug1: SSH2_MSG_NEWKEYS received debug1: Roaming not allowed by server debug1: SSH2_MSG_SERVICE_REQUEST sent debug1: SSH2_MSG_SERVICE_ACCEPT received debug1: Authentications that can continue: publickey,password debug1: Next authentication method: publickey debug1: Trying private key: /home/pupeno/.ssh/id_rsa debug1: Trying private key: /home/pupeno/.ssh/id_dsa debug1: Trying private key: /home/pupeno/.ssh/id_ecdsa debug1: Next authentication method: password pupeno@b1's password:

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  • How to connect via SSH to a linux mint system that is connected via OpenVPN

    - by Hilyin
    Is there a way to make SSH port not get sent through VPN so when my computer is connected to a VPN, it can still be remoted in via SSH from its non-VPN IP? I am using Mint Linux 13. Thank you for your help! This is the instructions I followed to setup the VPN: Open Terminal Type: sudo apt-get install network-manager-openvpn Press Y to continue. Type: sudo restart network-manager Download BTGuard certificate (CA) by typing: sudo wget -O /etc/openvpn/btguard.ca.crt http://btguard.com/btguard.ca.crt Click on the Network Manager icon, expand VPN Connections, and choose Configure VPN A Network Connections window will appear with the VPN tab open. Click Add. 8. A Choose A VPN Connection Type window will open. Select OpenVPN in the drop-down menu and click Create.. . In the Editing VPN connection window, enter the following: Connection name: BTGuard VPN Gateway: vpn.btguard.com Optional: Manually select your server location by using ca.vpn.btguard.com for Canada or eu.vpn.btguard.com for Germany. Type: select Password User name: username Password: password CA Certificate: browse and select this file: /etc/openvpn/btguard.ca.crt Click Advanced... near the bottom of the window. Under the General tab, check the box next to Use a TCP connection Click OK, then click Apply. Setup complete! How To Connect Click on the Network Manager icon in the panel bar. Click on VPN Connections Select BTGuard VPN The Network Manager icon will begin spinning. You may be prompted to enter a password. If so, this is your system account keychain password, NOT your BTGuard password. Once connected, the Network Manager icon will have a lock next to it indicating you are browsing securely with BTGuard.

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  • ASP.NET MVC Html.ValidationSummary(true) does not display model errors

    - by msi
    I have some problem with Html.ValidationSummary. I don't want to display property errors in ValidationSummary. And when I set Html.ValidationSummary(true) it does not display error messages from ModelState. When there is some Exception in controller action on string MembersManager.RegisterMember(member); catch section adds an error to the ModelState: ModelState.AddModelError("error", ex.Message); But ValidationSummary does not display this error message. When I set Html.ValidationSummary(false) all messages are displaying, but I don't want to display property errors. How can I fix this problem? Here is the code I'm using: Model: public class Member { [Required(ErrorMessage = "*")] [DisplayName("Login:")] public string Login { get; set; } [Required(ErrorMessage = "*")] [DataType(DataType.Password)] [DisplayName("Password:")] public string Password { get; set; } [Required(ErrorMessage = "*")] [DataType(DataType.Password)] [DisplayName("Confirm Password:")] public string ConfirmPassword { get; set; } } Controller: [HttpPost] public ActionResult Register(Member member) { try { if (!ModelState.IsValid) return View(); MembersManager.RegisterMember(member); } catch (Exception ex) { ModelState.AddModelError("error", ex.Message); return View(member); } } View: <% using (Html.BeginForm("Register", "Members", FormMethod.Post, new { enctype = "multipart/form-data" })) {%> <p> <%= Html.LabelFor(model => model.Login)%> <%= Html.TextBoxFor(model => model.Login)%> <%= Html.ValidationMessageFor(model => model.Login)%> </p> <p> <%= Html.LabelFor(model => model.Password)%> <%= Html.PasswordFor(model => model.Password)%> <%= Html.ValidationMessageFor(model => model.Password)%> </p> <p> <%= Html.LabelFor(model => model.ConfirmPassword)%> <%= Html.PasswordFor(model => model.ConfirmPassword)%> <%= Html.ValidationMessageFor(model => model.ConfirmPassword)%> </p> <div> <input type="submit" value="Create" /> </div> <%= Html.ValidationSummary(true)%> <% } %>

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  • Mercurial fails while commiting/updating/etc. using Mercuriual+TrueCrypt+MAC

    - by lukewar
    While trying to work with Mercurial on project located on TrueCrypt partition I always get en error as follows: ** unknown exception encountered, details follow ** report bug details to http://mercurial.selenic.com/bts/ ** or [email protected] ** Mercurial Distributed SCM (version 1.5.2+20100502) ** Extensions loaded: Traceback (most recent call last): File "/usr/local/bin/hg", line 27, in mercurial.dispatch.run() File "/Library/Python/2.6/site-packages/mercurial/dispatch.py", line 16, in run sys.exit(dispatch(sys.argv[1:])) File "/Library/Python/2.6/site-packages/mercurial/dispatch.py", line 30, in dispatch return _runcatch(u, args) File "/Library/Python/2.6/site-packages/mercurial/dispatch.py", line 50, in _runcatch return _dispatch(ui, args) File "/Library/Python/2.6/site-packages/mercurial/dispatch.py", line 470, in _dispatch return runcommand(lui, repo, cmd, fullargs, ui, options, d) File "/Library/Python/2.6/site-packages/mercurial/dispatch.py", line 340, in runcommand ret = _runcommand(ui, options, cmd, d) File "/Library/Python/2.6/site-packages/mercurial/dispatch.py", line 521, in _runcommand return checkargs() File "/Library/Python/2.6/site-packages/mercurial/dispatch.py", line 475, in checkargs return cmdfunc() File "/Library/Python/2.6/site-packages/mercurial/dispatch.py", line 469, in d = lambda: util.checksignature(func)(ui, *args, **cmdoptions) File "/Library/Python/2.6/site-packages/mercurial/util.py", line 401, in check return func(*args, **kwargs) File "/Library/Python/2.6/site-packages/mercurial/commands.py", line 3332, in update return hg.update(repo, rev) File "/Library/Python/2.6/site-packages/mercurial/hg.py", line 362, in update stats = _merge.update(repo, node, False, False, None) File "/Library/Python/2.6/site-packages/mercurial/merge.py", line 495, in update _checkunknown(wc, p2) File "/Library/Python/2.6/site-packages/mercurial/merge.py", line 77, in _checkunknown for f in wctx.unknown(): File "/Library/Python/2.6/site-packages/mercurial/context.py", line 660, in unknown return self._status[4] File "/Library/Python/2.6/site-packages/mercurial/util.py", line 156, in get result = self.func(obj) File "/Library/Python/2.6/site-packages/mercurial/context.py", line 622, in _status return self._repo.status(unknown=True) File "/Library/Python/2.6/site-packages/mercurial/localrepo.py", line 1023, in status if (f not in ctx1 or ctx2.flags(f) != ctx1.flags(f) File "/Library/Python/2.6/site-packages/mercurial/context.py", line 694, in flags flag = findflag(self._parents[0]) File "/Library/Python/2.6/site-packages/mercurial/context.py", line 690, in findflag return ff(path) File "/Library/Python/2.6/site-packages/mercurial/dirstate.py", line 145, in f if 'x' in fallback(x): TypeError: argument of type 'NoneType' is not iterable It is worth mention that Mercurial works perfectly if project is not located on TrueCrypt partition. Configuration: MacOS X 10.6.3 Mercurial Distributed SCM (version 1.5.2+20100502) Python 2.6.5 Have anyone of you generous people able to help me? :)

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  • ASP.NET MVC 2 InputExtensions different on server than local machine

    - by Mike
    Hi everyone, So this is kind of a crazy problem to me, but I've had no luck Googling it. I have an ASP.NET MVC 2 application (under .NET 4.0) running locally just fine. When I upload it to my production server (under shared hosting) I get Compiler Error Message: CS1061: 'System.Web.Mvc.HtmlHelper' does not contain a definition for 'TextBoxFor' and no extension method 'TextBoxFor' accepting a first argument of type 'System.Web.Mvc.HtmlHelper' could be found (are you missing a using directive or an assembly reference?) for this code: <%= this.Html.TextBoxFor(person => person.LastName) %> This is one of the new standard extension methods in MVC 2. So I wrote some diagnostic code: System.Reflection.Assembly ass = System.Reflection.Assembly.GetAssembly(typeof(InputExtensions)); Response.Write("From GAC: " + ass.GlobalAssemblyCache.ToString() + "<br/>"); Response.Write("ImageRuntimeVersion: " + ass.ImageRuntimeVersion.ToString() + "<br/>"); Response.Write("Version: " + System.Diagnostics.FileVersionInfo.GetVersionInfo(ass.Location).ToString() + "<br/>"); foreach (var method in typeof(InputExtensions).GetMethods()) { Response.Write(method.Name + "<br/>"); } running locally (where it works fine), I get this as output: From GAC: True ImageRuntimeVersion: v2.0.50727 Version: File: C:\Windows\assembly\GAC_MSIL\System.Web.Mvc\2.0.0.0__31bf3856ad364e35\System.Web.Mvc.dll InternalName: System.Web.Mvc.dll OriginalFilename: System.Web.Mvc.dll FileVersion: 2.0.50217.0 FileDescription: System.Web.Mvc.dll Product: Microsoft® .NET Framework ProductVersion: 2.0.50217.0 Debug: False Patched: False PreRelease: False PrivateBuild: False SpecialBuild: False Language: Language Neutral CheckBox CheckBox CheckBox CheckBox CheckBox CheckBox CheckBoxFor CheckBoxFor CheckBoxFor Hidden Hidden Hidden Hidden HiddenFor HiddenFor HiddenFor Password Password Password Password PasswordFor PasswordFor PasswordFor RadioButton RadioButton RadioButton RadioButton RadioButton RadioButton RadioButtonFor RadioButtonFor RadioButtonFor TextBox TextBox TextBox TextBox TextBoxFor TextBoxFor TextBoxFor ToString Equals GetHashCode GetType and when running on the production server (where it fails), I see: From GAC: True ImageRuntimeVersion: v2.0.50727 Version: File: C:\Windows\assembly\GAC_MSIL\System.Web.Mvc\2.0.0.0__31bf3856ad364e35\System.Web.Mvc.dll InternalName: System.Web.Mvc.dll OriginalFilename: System.Web.Mvc.dll FileVersion: 2.0.41001.0 FileDescription: System.Web.Mvc.dll Product: Microsoft® .NET Framework ProductVersion: 2.0.41001.0 Debug: False Patched: False PreRelease: False PrivateBuild: False SpecialBuild: False Language: Language Neutral CheckBox CheckBox CheckBox CheckBox CheckBox CheckBox Hidden Hidden Hidden Hidden Hidden Hidden Password Password Password Password RadioButton RadioButton RadioButton RadioButton RadioButton RadioButton TextBox TextBox TextBox TextBox ToString Equals GetHashCode GetType note that "TextBoxFor" is not present (hence the error). I have MVC referenced in the csproj: <Reference Include="System.Web.Mvc, Version=2.0.0.0, Culture=neutral, PublicKeyToken=31bf3856ad364e35, processorArchitecture=MSIL"> <SpecificVersion>True</SpecificVersion> <HintPath>References\System.Web.Mvc.dll</HintPath> <Private>True</Private> </Reference> I just can't figure it what to do next. Thoughts? Thanks! -Mike

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  • Can't clone gitosis-admin.git local from my snow leopard server running gitosis

    - by joggink
    I've installed gitosis as described here: http://gist.github.com/264304 One of the things that I had to adjust was to give my git user permissions to use ssh (which I did trough server admin - access - ssh and added the 'git' user). When I ssh from my local machine (mac osx) as the git user, I get this response: PTY allocation request failed on channel 0 bash: gitosis-serve: command not found Connection to 10.0.0.108 closed. Which I think is normal, because in Pro GIT the author says you should get something like this if you try ssh'ing to the server using your git user: PTY allocation request failed on channel 0 fatal: unrecognized command 'gitosis-serve schacon@quaternion' Connection to gitserver closed. So far so good, I think? Now when I try to clone my gitosis-admin.git repository using this command: $git clone [email protected]:gitosis-admin.git I get this: Initialized empty Git repository in /Users/joggink/gitosis-admin/.git/ bash: gitosis-serve: command not found fatal: The remote end hung up unexpectedly So after doing some searching, I found an answer here on serverfault claiming I should use ssh:// as protocol for my git clone (which I thought is the default git protocol?) However, when I try: $git clone ssh://[email protected]:gitosis-admin.git This is the response: The authenticity of host ' (::1)' can't be established. RSA key fingerprint is 80:4d:77:c7:78:cb:c9:42:e3:82:06:7c:fe:c0:08:ce. Are you sure you want to continue connecting (yes/no)? yes Warning: Permanently added '' (RSA) to the list of known hosts. Password: Password: Password: Permission denied (publickey,keyboard-interactive). fatal: The remote end hung up unexpectedly When I type in my own password (because my git user has no password), I get following error: The authenticity of host ' (::1)' can't be established. RSA key fingerprint is 80:4d:77:c7:78:cb:c9:42:e3:82:06:7c:fe:c0:08:ce. Are you sure you want to continue connecting (yes/no)? yes Warning: Permanently added '' (RSA) to the list of known hosts. Password: bash: git-upload-pack: command not found fatal: The remote end hung up unexpectedly I added my upload-pack location as followed: $git clone -u /usr/local/git/bin/git-upload-pack ssh://[email protected]:gitosis-admin.git I get the error that gitosis-admin.git isn't a git repo... Initialized empty Git repository in /Users/joggink/gitosis-admin/.git/ The authenticity of host ' (::1)' can't be established. RSA key fingerprint is 80:4d:77:c7:78:cb:c9:42:e3:82:06:7c:fe:c0:08:ce. Are you sure you want to continue connecting (yes/no)? yes Warning: Permanently added '' (RSA) to the list of known hosts. Password: fatal: '[email protected]:gitosis-admin.git' does not appear to be a git repository fatal: The remote end hung up unexpectedly I've been searching for a solution for almost a week now, and every topic I've found on the internet gives no result...

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