Adding up fractions in PHP
- by Gamemorize
I would like to create a loop that keeps adding a set fraction, here in my example 1/3, and which later I can check against for matches with integer values.
Obviously when php adds 1/3 + 1/3 + 1/3 the result is 0.9999999, so i thought I could use the occasional round to help me, but this isn't working either.
The idea that I had would be that .333 + .333 becomes .666 and that if rounded that would become .667, then + .333 and the result is 1. However round only seems to work, for me, if the number of digits actually decreases. so round (0.666, 3) remains 0.666
<?php
$denom = 3;
$frac = 1/$denom;
$frac = round($frac,3);
$value = 0;
$max =24;
for($f = 1; $f <= $max; $f++){
echo "old value is now at ".$value.".<br/>";
$value = $value+$frac;
echo "value is now at ".$value.".<br/>";
$value = round($value,3);
echo "rounded value is now at ".$value.".<br/>";
$valueArray[$f] = $value;
//and here for ease of testing....
if (($value==1)OR ($value==2)OR ($value==3)OR ($value==4)OR ($value==5)OR ($value==6)OR ($value==7)OR ($value==8)){
echo "match!<br/>";
}else{
echo "no match!<br/>";
}
}
?>
Am I going about this in a totally stupid way?
Accuracy when the value is not an integer is not needed, just that it can == with integers.
