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  • Calling next value of a sequence in jpa

    - by Javi
    Hello, I have a class mapped as an Entity to persist it in a database. I have an id field as the primary key so every time the object is persisted the value of the id is retrieved from the sequence "myClass_pk_seq", a code like the following one. @Entity @Table(name="myObjects") public class MyClass { @Id @GeneratedValue(strategy=GenerationType.SEQUENCE, generator="sequence") @SequenceGenerator(name="sequence", sequenceName="myClass_pk_seq", allocationSize=1) @Column(name="myClassId") private Integer id; ... } I need to get the next value of the sequence myClass_pk_seq to reserve that value (get the next value of the sequence and the current value is incremented), but without saving the object. How can I call the next value of a sequence when it's defined like this? Thanks.

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  • Hibernate ResultTransformer with JPA API

    - by Timo Westkämper
    Has anyone figured out a smart way to do query result transformation through a similar mechanism like specifying a ResultTransformer in Hibernate? All I can think of is transforming each result row after it has been returned by the Query. Is there any other way? For constructor projections (e.g. new DTO(arg1, arg2)) it can be defined in the JPQL query, at least for Hibernate, but how about other cases?

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  • Interface between two related JPA entities

    - by OpenSource
    The scenario is as below (tables shown) Delivery table ------ id channelId type 10 100 fax 20 200 email Fax table ---- id number 100 1234567 101 1234598 Email table ----- id email 200 [email protected] 201 [email protected] basically a one to one relationship between the delivery and the channel entity but since each concrete channel(fax, email) has different members I want to create a generic interface (channel) between the two entities and use it for the @OneToOne relationship. Seems to me a simple scenario where lot of you might have already gone through but I'm unable to succeed. I tried putting that targetEntity thing but no use. Still says "delivery references an unknown entity" Any ideas? thanks in advance

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  • JPA Lookup Hierarchy Mapping

    - by Andy Trujillo
    Given a lookup table: | ID | TYPE | CODE | DESCRIPTION | | 1 | ORDER_STATUS | PENDING | PENDING DISPOSITION | | 2 | ORDER_STATUS | OPEN | AWAITING DISPOSITION | | 3 | OTHER_STATUS | OPEN | USED BY OTHER ENTITY | If I have an entity: @MappedSuperclass @Table(name="LOOKUP") @Inheritance(strategy=InheritanceType.SINGLE_TABLE) @DiscriminatorColumn(name="TYPE", discriminatorType=DiscriminatorType.STRING) public abstract class Lookup { @Id @Column(name="ID") int id; @Column(name="TYPE") String type; @Column(name="CODE") String code; @Column(name="DESC") String description; ... } Then a subclass: @Entity @DiscriminatorValue("ORDER_STATUS") public class OrderStatus extends Lookup { } The expectation is to map it: @Entity @Table(name="ORDERS") public class OrderVO { ... @ManyToOne @JoinColumn(name="STATUS", referencedColumnName="CODE") OrderStatus status; ... } So that the CODE is stored in the database. I expected that if I wrote: OrderVO o = entityManager.find(OrderVO.class, 123); the SQL generated using OpenJPA would look something like: SELECT t0.id, ..., t1.CODE, t1.TYPE, t1.DESC FROM ORDERS t0 LEFT OUTER JOIN LOOKUP t1 ON t0.STATUS = t1.CODE AND t1.TYPE = 'ORDER_STATUS' WHERE t0.ID = ? But the actual SQL that gets generated is missing the AND t1.TYPE = 'ORDER_STATUS' This causes a problem when the CODE is not unique. Is there a way to have the discriminator included on joins or am I doing something wrong here?

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  • JPA ManyToMany problem...

    - by Parhs
    Hello i have an Entity Exam @Id @GeneratedValue(strategy=GenerationType.TABLE) private Long id; ..... ...... @ManyToMany private List<Exam> exams; @ManyToMany(mappedBy="id") private List<Exam> parentExams; The problem is that @ManyToMany private List<Exam> exams; is ok works great... but this doesnt validate?! @ManyToMany(mappedBy="id") private List<Exam> parentExams; Any idea what to do ? I just want to get the exams that are parents of the current exam. ??e???? ??µ?sµat??? ?aµe??

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  • Spring Security: how to implement Brute Force Detection (BFD)?

    - by Kdeveloper
    My web applications security is handled by Spring Security 3.02 but I can't find any out of the box support for Brute Force Detection. I would like to implement some application level BFD protection. For example by storing failed login attempt per user in the database (JPA). The attacked user accounts could then get a lockout period or a forced account re-activation by e-mail. What's the best way to implement this with Spring Security? Does any body have example code or best practices on this?

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  • JPA 2.0 EclipseLink Check for unique

    - by Parhs
    Hello... I have a collumn as unique=true.. in Exam class.... I found that because transactions are commited automaticaly so to force the commit i use em.commit() However i would like to know how to check if it is unique.Running a query isnt a solution because it may be an instert after checking because of the concurency.... Which is the best way to check for uniqness? List<Exam_Normal> exam_normals = exam.getExam_Normal(); exam.setExam_Normal(null); try { em.persist(exam); em.flush(); Long i = 0L; if (exam_normals != null) { for (Exam_Normal e_n : exam_normals) { i++; e_n.setItem(i); e_n.setId(exam); em.persist(e_n); } } } catch (Exception e) { System.out.print("sfalma--"); } } d

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  • Deleting JPA entity containing @CollectionOfElements throws ConstraintViolationException

    - by Lyle
    I'm trying to delete entities which contain lists of Integer, and I'm getting ConstraintViolationExceptions because of the foreign key on the table generated to hold the integers. It appears that the delete isn't cascading to the mapped collection. I've done quite a bit of searching, but all of the examples I've seen on how to accomplish this are in reference to a mapped collection of other entities which can be annotated; here I'm just storing a list of Integer. Here is the relevant excerpt from the class I'm storing: @Entity @Table(name="CHANGE_IDS") @GenericGenerator( name = "CHANGE_ID_GEN", strategy = "org.hibernate.id.enhanced.SequenceStyleGenerator", parameters = { @Parameter(name="sequence_name", value="course_changes_seq"), @Parameter(name="increment_size", value="5000"), @Parameter(name=" optimizer", value="pooled") } ) @NamedQueries ({ @NamedQuery( name="Changes.getByStatus", query= "SELECT c " + "FROM DChanges c " + "WHERE c.status = :status "), @NamedQuery( name="Changes.deleteByStatus", query= "DELETE " + "FROM Changes c " + "WHERE c.status = :status ") }) public class Changes { @Id @GeneratedValue(generator="CHANGE_ID_GEN") @Column(name = "ID") private final long id; @Enumerated(EnumType.STRING) @Column(name = "STATUS", length = 20, nullable = false) private final Status status; @Column(name="DOC_ID") @org.hibernate.annotations.CollectionOfElements @org.hibernate.annotations.IndexColumn(name="DOC_ID_ORDER") private List<Integer> docIds; } I'm deleting the Changes objects using a @NamedQuery: final Query deleteQuery = this.entityManager.createNamedQuery("Changes.deleteByStatus"); deleteQuery.setParameter("status", Status.POST_FLIP); final int deleted = deleteQuery.executeUpdate(); this.logger.info("Deleted " + deleted + " POST_FLIP Changes");

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  • JPA entities -- org.hibernate.TypeMismatchException

    - by shane lee
    Environment: JDK 1.6, JEE5 Hibernate Core 3.3.1.GA, Hibernate Annotations 3.4.0.GA DB:Informix Used reverse engineering to create my persistence entities from db schema [NB:This is a schema in work i cannot change] Getting exception when selecting list of basic_auth_accounts org.hibernate.TypeMismatchException: Provided id of the wrong type for class ebusiness.weblogic.model.UserAccounts. Expected: class ebusiness.weblogic.model.UserAccountsId, got class ebusiness.weblogic.model.BasicAuthAccountsId Both basic_auth_accounts and user_accounts have composite primary keys and one-to-one relationships. Any clues what to do here? This is pretty important that i get this to work. Cannot find any substantial solution on the net, some say to create an ID class which hibernate has done, and some say not to have a one-to-one relationship. Please help me!! /** * BasicAuthAccounts generated by hbm2java */ @Entity @Table(name = "basic_auth_accounts", schema = "ebusdevt", catalog = "ebusiness_dev", uniqueConstraints = @UniqueConstraint(columnNames = { "realm_type_id", "realm_qualifier", "account_name" })) public class BasicAuthAccounts implements java.io.Serializable { private BasicAuthAccountsId id; private UserAccounts userAccounts; private String accountName; private String hashedPassword; private boolean passwdChangeReqd; private String hashMethodId; private int failedAttemptNo; private Date failedAttemptDate; private Date lastAccess; public BasicAuthAccounts() { } public BasicAuthAccounts(UserAccounts userAccounts, String accountName, String hashedPassword, boolean passwdChangeReqd, String hashMethodId, int failedAttemptNo) { this.userAccounts = userAccounts; this.accountName = accountName; this.hashedPassword = hashedPassword; this.passwdChangeReqd = passwdChangeReqd; this.hashMethodId = hashMethodId; this.failedAttemptNo = failedAttemptNo; } public BasicAuthAccounts(UserAccounts userAccounts, String accountName, String hashedPassword, boolean passwdChangeReqd, String hashMethodId, int failedAttemptNo, Date failedAttemptDate, Date lastAccess) { this.userAccounts = userAccounts; this.accountName = accountName; this.hashedPassword = hashedPassword; this.passwdChangeReqd = passwdChangeReqd; this.hashMethodId = hashMethodId; this.failedAttemptNo = failedAttemptNo; this.failedAttemptDate = failedAttemptDate; this.lastAccess = lastAccess; } @EmbeddedId @AttributeOverrides( { @AttributeOverride(name = "realmTypeId", column = @Column(name = "realm_type_id", nullable = false, length = 32)), @AttributeOverride(name = "realmQualifier", column = @Column(name = "realm_qualifier", nullable = false, length = 32)), @AttributeOverride(name = "accountId", column = @Column(name = "account_id", nullable = false)) }) public BasicAuthAccountsId getId() { return this.id; } public void setId(BasicAuthAccountsId id) { this.id = id; } @OneToOne(fetch = FetchType.LAZY) @PrimaryKeyJoinColumn @NotNull public UserAccounts getUserAccounts() { return this.userAccounts; } public void setUserAccounts(UserAccounts userAccounts) { this.userAccounts = userAccounts; } /** * BasicAuthAccountsId generated by hbm2java */ @Embeddable public class BasicAuthAccountsId implements java.io.Serializable { private String realmTypeId; private String realmQualifier; private long accountId; public BasicAuthAccountsId() { } public BasicAuthAccountsId(String realmTypeId, String realmQualifier, long accountId) { this.realmTypeId = realmTypeId; this.realmQualifier = realmQualifier; this.accountId = accountId; } /** * UserAccounts generated by hbm2java */ @Entity @Table(name = "user_accounts", schema = "ebusdevt", catalog = "ebusiness_dev") public class UserAccounts implements java.io.Serializable { private UserAccountsId id; private Realms realms; private UserDetails userDetails; private Integer accessLevel; private String status; private boolean isEdge; private String role; private boolean chargesAccess; private Date createdTimestamp; private Date lastStatusChangeTimestamp; private BasicAuthAccounts basicAuthAccounts; private Set<Sessions> sessionses = new HashSet<Sessions>(0); private Set<AccountGroups> accountGroupses = new HashSet<AccountGroups>(0); private Set<UserPrivileges> userPrivilegeses = new HashSet<UserPrivileges>(0); public UserAccounts() { } public UserAccounts(UserAccountsId id, Realms realms, UserDetails userDetails, String status, boolean isEdge, boolean chargesAccess) { this.id = id; this.realms = realms; this.userDetails = userDetails; this.status = status; this.isEdge = isEdge; this.chargesAccess = chargesAccess; } @EmbeddedId @AttributeOverrides( { @AttributeOverride(name = "realmTypeId", column = @Column(name = "realm_type_id", nullable = false, length = 32)), @AttributeOverride(name = "realmQualifier", column = @Column(name = "realm_qualifier", nullable = false, length = 32)), @AttributeOverride(name = "accountId", column = @Column(name = "account_id", nullable = false)) }) @NotNull public UserAccountsId getId() { return this.id; } public void setId(UserAccountsId id) { this.id = id; } @OneToOne(fetch = FetchType.LAZY, mappedBy = "userAccounts") public BasicAuthAccounts getBasicAuthAccounts() { return this.basicAuthAccounts; } public void setBasicAuthAccounts(BasicAuthAccounts basicAuthAccounts) { this.basicAuthAccounts = basicAuthAccounts; } /** * UserAccountsId generated by hbm2java */ @Embeddable public class UserAccountsId implements java.io.Serializable { private String realmTypeId; private String realmQualifier; private long accountId; public UserAccountsId() { } public UserAccountsId(String realmTypeId, String realmQualifier, long accountId) { this.realmTypeId = realmTypeId; this.realmQualifier = realmQualifier; this.accountId = accountId; } @Column(name = "realm_type_id", nullable = false, length = 32) @NotNull @Length(max = 32) public String getRealmTypeId() { return this.realmTypeId; } public void setRealmTypeId(String realmTypeId) { this.realmTypeId = realmTypeId; } @Column(name = "realm_qualifier", nullable = false, length = 32) @NotNull @Length(max = 32) public String getRealmQualifier() { return this.realmQualifier; } public void setRealmQualifier(String realmQualifier) { this.realmQualifier = realmQualifier; } @Column(name = "account_id", nullable = false) public long getAccountId() { return this.accountId; } public void setAccountId(long accountId) { this.accountId = accountId; } Main Code for classes are:

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  • Compare two dates with JPA

    - by Kiva
    Hello everybody, I need to compare two dates in a JPQL query but it doesn't work. Here is my query: Query query = em.createQuery("SELECT h FROM PositionHistoric h, SeoDate d WHERE h.primaryKey.siteDb = :site AND h.primaryKey.engineDb = :engine AND h.primaryKey.keywordDb = :keyword AND h.date = d AND d.date <= :date ORDER BY h.date DESC"); My parameter date is a java.util.Date My query return a objects list but the dates are upper and lower to my parameter. Someone kown how to do this ? Thanks.

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  • Storing Objects in columns using Hibernate JPA

    - by user210791
    Is it possible to store something like the following using only one table? Right now, what hibernate will do is create two tables, one for Families and one for people. I would like for the familymembers object to be serialized into the column in the database. @Entity(name = "family") class Family{ private final List<Person> familyMembers; } class Person{ String firstName, lastName; int age; }

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  • jpa IllegalArgumentException exception

    - by Bunny Rabbit
    i've three entity classes in my project public class Blobx { @ManyToOne private Userx user; @Id @GeneratedValue(strategy = GenerationType.IDENTITY) private Key id; } public class Index { @Id private String keyword; @OneToMany(cascade = CascadeType.PERSIST) private List<Blobx> blobs; } public class Userx { @Id private String name; @OneToMany(mappedBy = "user") private List<Blobx>blobs; } while running the following lines app engine throws an exception em.getTransaction().begin(); em.persist(index); em.getTransaction().commit();//exception is thrown em.close(); as Caused by: java.lang.IllegalArgumentException: can't operate on multiple entity groups in a single transaction. found both Element { type: "Index" name: "function" } and Element { type: "Userx" name: "18580476422013912411" } i can't understand what's wrong?

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  • Tips for resolving Hibernate/JPA EntityNotFoundException

    - by Damo
    I'm running into a problem with Hibernate where when trying to delete a group of Entities I encounter the following error: javax.persistence.EntityNotFoundException: deleted entity passed to persist: [com.locuslive.odyssey.entity.FreightInvoiceLine#<null>] These are not normally so difficult to track down as they are usually caused by an entity being deleted but not being removed from a Collection that it is a member of. In this case I have removed the entity from every list that I can think of (it's a complex datamodel). I've put JBoss logging into Trace and I can see the collections that are being cascaded. However I can't seem to find the Collection containing the entity that I'm deleting. Does anyone have any tips for resolving this particular Exception? Thanks.

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  • JPA + Hibernate + Named Query + how to JOIN a subquery result

    - by Srihari
    Can anybody help me in converting the following native query into a Named Query? Native Query: SELECT usr1.user_id, urr1.role_id, usr2.user_id, urr2.role_id, usr1.school_id, term.term_name, count(material.material_id) as "Total Book Count", fpc.FOLLETT_PENDING_COUNT as "Follett Pending Count", rrc.RESOLUTION_REQUIRED_COUNT as "Resolution Required Count" FROM va_school sch JOIN va_user_school_rel usr1 on sch.school_id=usr1.school_id JOIN va_user_role_rel urr1 on usr1.user_id=urr1.user_id and urr1.role_id=1001 JOIN va_user_school_rel usr2 on sch.school_id=usr2.school_id JOIN va_user_role_rel urr2 on usr2.user_id=urr2.user_id and urr2.role_id=1002 JOIN va_term term on term.school_id = usr1.school_id JOIN va_class course on course.term_id = term.term_id JOIN va_material material on material.class_id = course.class_id LEFT JOIN (SELECT VA_CLASS.TERM_ID as "TERM_ID", COUNT(*) as "FOLLETT_PENDING_COUNT" FROM VA_CLASS JOIN VA_MATERIAL ON VA_MATERIAL.CLASS_ID = VA_CLASS.CLASS_ID WHERE VA_CLASS.reference_flag = 'A' AND trunc(VA_MATERIAL.FOLLETT_STATUS) = 0 GROUP BY VA_CLASS.TERM_ID) fpc on term.term_id = fpc.term_id LEFT JOIN (SELECT VA_CLASS.TERM_ID as "TERM_ID", COUNT(*) as "RESOLUTION_REQUIRED_COUNT" FROM VA_CLASS JOIN VA_MATERIAL ON VA_MATERIAL.CLASS_ID = VA_CLASS.CLASS_ID WHERE VA_CLASS.reference_flag = 'A' AND trunc(VA_MATERIAL.FOLLETT_STATUS) = 1 GROUP BY VA_CLASS.TERM_ID) rrc on term.term_id = rrc.term_id WHERE course.reference_flag = 'A' GROUP BY usr1.user_id, urr1.role_id, usr2.user_id, urr2.role_id, usr1.school_id, term.term_name, fpc.FOLLETT_PENDING_COUNT, rrc.RESOLUTION_REQUIRED_COUNT ORDER BY usr1.school_id, term.term_name; Thanks in advance. Srihari

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  • JPA ManyToMany referencing issue

    - by dharga
    I have three tables. AvailableOptions and PlanTypeRef with a ManyToMany association table called AvailOptionPlanTypeAssoc. The trimmed down schemas look like this CREATE TABLE [dbo].[AvailableOptions]( [SourceApplication] [char](8) NOT NULL, [OptionId] [int] IDENTITY(1,1) NOT NULL, ... ) CREATE TABLE [dbo].[AvailOptionPlanTypeAssoc]( [SourceApplication] [char](8) NOT NULL, [OptionId] [int] NOT NULL, [PlanTypeCd] [char](2) NOT NULL, ) CREATE TABLE [dbo].[PlanTypeRef]( [PlanTypeCd] [char](2) NOT NULL, [PlanTypeDesc] [varchar](32) NOT NULL, ) And the Java code looks like this. //AvailableOption.java @ManyToMany(cascade={CascadeType.ALL}, fetch=FetchType.EAGER) @JoinTable( name = "AvailOptionPlanTypeAssoc", joinColumns = { @JoinColumn(name = "OptionId"), @JoinColumn(name="SourceApplication")}, inverseJoinColumns=@JoinColumn(name="PlanTypeCd")) List<PlanType> planTypes = new ArrayList<PlanType>(); //PlanType.java @ManyToMany @JoinTable( name = "AvailOptionPlanTypeAssoc", joinColumns = { @JoinColumn(name = "PlanTypeCd")}, inverseJoinColumns={@JoinColumn(name="OptionId"), @JoinColumn(name="SourceApplication")}) List<AvailableOption> options = new ArrayList<AvailableOption>(); The problem arises when making a select on AvailableOptions it joins back onto itself. Note the following SQL code from the backtrace. The second inner join should be on PlanTypeRef. SELECT t0.OptionId, t0.SourceApplication, t2.PlanTypeCd, t2.EffectiveDate, t2.PlanTypeDesc, t2.SysLstTrxDtm, t2.SysLstUpdtUserId, t2.TermDate FROM dbo.AvailableOptions t0 INNER JOIN dbo.AvailOptionPlanTypeAssoc t1 ON t0.OptionId = t1.OptionId AND t0.SourceApplication = t1.SourceApplication INNER JOIN dbo.AvailableOptions t2 ON t1.PlanTypeCd = t2.PlanTypeCd WHERE (t0.SourceApplication = ? AND t0.OptionType = ?) ORDER BY t0.OptionId ASC, t0.SourceApplication ASC [params=(String) testApp, (String) junit0]}

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  • A cycle in object graph detected in JPA.

    - by Nitesh Panchal
    Hello, I am trying to figure out this error since 5 hours without any success. SO i finally thought of posting in here. Please help i am really in big trouble. I am stuck on this and see no way of solving this error. This is my database structure tblBlogRegion BlogRegionId (primary key) BlogRegionName tblGadget GadgetId(primary key) GadgetName tblBlogs BlogId(primary key) Blogname BlogTypeId (reference key from tblSiteTerm tblSiteTerms SiteTermsId(primary key) SiteTermsName tblBlogGadgets BlogGadgetsId(primary key) BlogRegionId(foreign key from tblBlogRegion) BlogId(foreign key from tblBlog) GadgetId(foreign key from tblGadget) Is it not normal database structure? Do you see anything that is cyclic? WHen i try to fetch list from tblGadgets i get this error :- [com.sun.istack.SAXException2: A cycle is detected in the object graph. This will cause infinitely deep XML: entity.BlogGadgets[blogGadgetsId=1] -> entity.Blogs[blogId=2] -> entity.BlogGadgets[blogGadgetsId=1]] I am trying to get list from web service using JAS-WS.

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  • JPA + Hibernate + Named Query + how to JOIN a subquery result

    - by Srihari
    Hi, Can anybody help me in converting the following native query into a Named Query? Native Query: SELECT usr1.user_id, urr1.role_id, usr2.user_id, urr2.role_id, usr1.school_id, term.term_name, count(material.material_id) as "Total Book Count", fpc.FOLLETT_PENDING_COUNT as "Follett Pending Count", rrc.RESOLUTION_REQUIRED_COUNT as "Resolution Required Count" FROM va_school sch JOIN va_user_school_rel usr1 on sch.school_id=usr1.school_id JOIN va_user_role_rel urr1 on usr1.user_id=urr1.user_id and urr1.role_id=1001 JOIN va_user_school_rel usr2 on sch.school_id=usr2.school_id JOIN va_user_role_rel urr2 on usr2.user_id=urr2.user_id and urr2.role_id=1002 JOIN va_term term on term.school_id = usr1.school_id JOIN va_class course on course.term_id = term.term_id JOIN va_material material on material.class_id = course.class_id LEFT JOIN (SELECT VA_CLASS.TERM_ID as "TERM_ID", COUNT(*) as "FOLLETT_PENDING_COUNT" FROM VA_CLASS JOIN VA_MATERIAL ON VA_MATERIAL.CLASS_ID = VA_CLASS.CLASS_ID WHERE VA_CLASS.reference_flag = 'A' AND trunc(VA_MATERIAL.FOLLETT_STATUS) = 0 GROUP BY VA_CLASS.TERM_ID) fpc on term.term_id = fpc.term_id LEFT JOIN (SELECT VA_CLASS.TERM_ID as "TERM_ID", COUNT(*) as "RESOLUTION_REQUIRED_COUNT" FROM VA_CLASS JOIN VA_MATERIAL ON VA_MATERIAL.CLASS_ID = VA_CLASS.CLASS_ID WHERE VA_CLASS.reference_flag = 'A' AND trunc(VA_MATERIAL.FOLLETT_STATUS) = 1 GROUP BY VA_CLASS.TERM_ID) rrc on term.term_id = rrc.term_id WHERE course.reference_flag = 'A' GROUP BY usr1.user_id, urr1.role_id, usr2.user_id, urr2.role_id, usr1.school_id, term.term_name, fpc.FOLLETT_PENDING_COUNT, rrc.RESOLUTION_REQUIRED_COUNT ORDER BY usr1.school_id, term.term_name; Thanks in advance. Srihari

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  • Client timeout when using WCF through Spring.net

    - by Khash
    I'm using WCF through Spring.net WCF integration link text This works relatively fine, however it seems that WCF and Spring get in each other's way when instantiating client channels. This means that only a single client channel is created for a service and therefore the clients get a timeout after the configured timeout is expired since the same client channel has been open since it was instantiated by Spring. To make the matters worst, once a channel goes to a fault state, it affect all users of that service since spring doesn't create a new channel for each user. Has anyone managed to use WCF and Spring.net work together without these issues?

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  • JPA @TableGenerator shared between multiple entities

    - by Mauricio
    Hi Guys, I have a 'dog' Entitiy with an @Id and a @TableGenerator ... @TableGenerator(table = "seq", name = "dog_gen", pkColumnName = "seq_name", valueColumnName="seq_val") @Id @GeneratedValue(strategy = GenerationType.TABLE, generator = "dog_gen") private Long id; ... Is there a way to reuse the same table generator (dog_gen) in other entity? I want to keep the same id sequence in two independent Entities, say dog=1, dog=2, dog=3, cat=4, cat=5, dog=6 and so on... Both entities don't share a common superclass to implement some kind of inheritance with the id property. If I add the @GeneratedValue( generator="dog_gen") on my cat entity, omitting the @TableGenerator declaration throws an Exception saying it can't find the generator when starting the context. Caused by: org.hibernate.AnnotationException: Unknown Id.generator: dog_gen at org.hibernate.cfg.BinderHelper.makeIdGenerator(BinderHelper.java:413) at org.hibernate.cfg.AnnotationBinder.bindId(AnnotationBinder.java:1795) at org.hibernate.cfg.AnnotationBinder.processElementAnnotations(AnnotationBinder.java:1229) at org.hibernate.cfg.AnnotationBinder.bindClass(AnnotationBinder.java:733) at org.hibernate.cfg.AnnotationConfiguration.processArtifactsOfType(AnnotationConfiguration.java:498) at org.hibernate.cfg.AnnotationConfiguration.secondPassCompile(AnnotationConfiguration.java:277)

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  • Duplicate column name by JPA with @ElementCollection and @Inheritance

    - by gerry
    I've created the following scenario: @javax.persistence.Entity @Inheritance(strategy = InheritanceType.TABLE_PER_CLASS) public class MyEntity implements Serializable{ @Id @GeneratedValue protected Long id; ... @ElementCollection @CollectionTable(name="ENTITY_PARAMS") @MapKeyColumn (name = "ENTITY_KEY") @Column(name = "ENTITY_VALUE") protected Map<String, String> parameters; ... } As well as: @javax.persistence.Entity public class Sensor extends MyEntity{ @Id @GeneratedValue protected Long id; ... // so here "protected Map<String, String> parameters;" is inherited !!!! ... } So running this example, no tables are created and i get the following message: WARNUNG: Got SQLException executing statement "CREATE TABLE ENTITY_PARAMS (Entity_ID BIGINT NOT NULL, ENTITY_VALUE VARCHAR(255), ENTITY_KEY VARCHAR(255), Sensor_ID BIGINT NOT NULL, ENTITY_VALUE VARCHAR(255))": com.mysql.jdbc.exceptions.jdbc4.MySQLSyntaxErrorException: Duplicate column name 'ENTITY_VALUE' I also tried overriding the attributes on the Sensor class... @AttributeOverrides({ @AttributeOverride(name = "ENTITY_KEY", column = @Column(name = "SENSOR_KEY")), @AttributeOverride(name = "ENTITY_VALUE", column = @Column(name = "SENSOR_VALUE")) }) ... but the same error. Can anybody help me?

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  • How to backup database to disk using JPA?

    - by Nitesh Panchal
    Hello, Which query to write in JPQL for backing up database on disk? If in JPQL it's not available even native sql query will do. Also, i would like to bring one issue in front of stackoverflow developers :- This site doesn't properly work in Opera (Opera 9.63). Whenever i write question and click "Post Your question" The button click event doesn't fire at all, may be, the server side event doesn't fire or something. However, no such problem comes in IE and firefox.

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  • JPA persistence.xml share same jar file

    - by user213855
    Hi! I'm wondering if I can share the same jar file for several persistence units.. I mean: I have two persistence units described in my persistence.xml file and the entities are not in the same JAR. Entities are in a separated JAR file but, in that one, there are entites for both persistence units. I think I red somewhere that I coould use tag something like this: externalEntities.jar#com.mycompany.EntityA so I could separate them. I tried this solution and it doesn't work. Now I guess that it couldn't be done to package all entities (for two different persistence units) in the same JAR file. What do yo think?

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  • Why is an oracle sequence named hibernate_sequence being created with JPA using Hibernate with the O

    - by JavaRocky
    All my entities use this type of @Id @Id @GeneratedValue(strategy = GenerationType.SEQUENCE, generator = "MYENTITY_SEQ") @SequenceGenerator(name = "MYENTITY_SEQ", sequenceName = "MYENTITY_SEQ") @Column(name = "MYENTITY", nullable = false) private Long id; Or @Id @Column(name = "MYENTITY") I find that an oracle sequence named hibernate_sequence is always created. Why is this so? And how can i avoid this? I am using JPA1 with Hibernate 3 and the Oracle 10g dialect.

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  • JPA - Performance with using multiple entity manager

    - by Nguyen Tuan Linh
    My situation is: The code is not mine I have two kinds of database: one is Dad, one is Son. In Dad, I have a table to store JNDI name. I will look up Dad using JNDI, create entity manager, and retrieve this table. From these retrieved JNDI names, I will create multiple entity managers using multiple Son databases. The problem is: Son have thousands of entities. It takes each Son database around 10 minutes to load all entities. If there is 4 Son databases, it will be 40 minutes. My question: Is there any way to load all entities and use them for all entity manager? Please look at the code below For each Son JNDI: Map<String, String> puSonProperties = new HashMap<String, String>(); puSonProperties.put("javax.persistence.jtaDataSource", sonJndi); EntityManagerFactory emf = Persistence.createEntityManagerFactory("PUSon", puSonProperties); PUSon - All of them use the same persistence unit log.info("Verify entity manager for son: {0} - {1}", sonCode, emSon.find(Son_configuration.class, 0) != null ? "ok" : "failed!"); This is the actual code where the loading of all entities begins. 10 mins.

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  • Provisioning api jpa

    - by user268515
    Hi i tried the following code Appsprovisioning.java public void calluser() throws AppsForYourDomainExceptiion IOException, { for(UserEntry userEntry : retrieveAllUsers().getEntries()) { m[x]= userEntry.getTitle().getPlainText(); x++; } try { for(int i=0;i<x;i++) { String sd=m[i]; stud greeting1 = new stud(sd); em.persist(greeting1); System.out.println("jk"); } } finally { em.close(); } public UserFeed retrieveAllUsers()throws ,ServiceException, IOException{ userService = new UserService("Myapplication"); userService.setUserCredentials("[email protected]","xxxxxxxx"); URL retrieveUrl = new URL("https://www.google.com/a/feeds/montfortperungudi.edu.in/user/2.0/"); UserFeed allUsers = new UserFeed(); UserFeed currentPage; Link nextLink; do { currentPage = userService.getFeed(retrieveUrl, UserFeed.class); allUsers.getEntries().addAll(currentPage.getEntries()); nextLink = currentPage.getLink(Link.Rel.NEXT, Link.Type.ATOM); if (nextLink != null) { retrieveUrl = new URL(nextLink.getHref()); } } while (nextLink != null); return allUsers; } } Servlet.java public class servlet extends HttpServlet { private static final long serialVersionUID = 1L; private static final Logger log = Logger.getLogger(servlet.class.getName()); // EntityManager em=null; AppsProvisioning aa=new AppsProvisioning(); public void doGet(HttpServletRequest req, HttpServletResponse resp)throws IOException { //em = EMFService.get().createEntityManager(); try { aa.calluser(); }catch(Exception e){ System.out.println("SEF "+e);} finally { // em.clear(); // em.close(); } } } Table Creation import javax.persistence.Entity; import javax.persistence.Id; @Entity(name="stud") public class stud { @Id private String fathername; public stud(String fathername) {// TODO Auto-generated constructor stub this.fathername=fathername; } public void setFathername(String fathername) { this.fathername = fathername; } public String getFathername() { return fathername; } } I cant able to store all the users in the table.. Its returning Session out error.

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