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  • Issues with mx:method, mx.rpc.remoting.mxml.RemoteObject, and sub-classing mx.rpc.remoting.mxml.Remo

    - by Ryan Wilson
    I am looking to subclass RemoteObject. Instead of: <mx:RemoteObject ... > <mx:method ... /> <mx:method ... /> </mx:RemoteObject> I want to do something like: <remoting:CustomRemoteObject ...> <mx:method ... /> <mx:method ... /> </remoting:CustomRemoteObject> where CustomRemoteObject extends mx.rpc.remoting.mxml.RemoteObject like so: package remoting { import mx.rpc.remoting.mxml.RemoteObject; public class CustomRemoteObject extends RemoteObject { public function CustomRemoteObject(destination:String=null) { super(destination); } } } However, when doing so and declaring a CustomRemoteObject in MXML as above, the flex compiler shows the error: Could not resolve <mx:method> to a component implementation At first I thought it had something to do with CustomRemoteObject failing to do something, despite that (or since) it had no change except as to the name. So, I copied the source from mx.rpc.remoting.mxml.RemoteObject into CustomRemoteObject and modified it so the only difference was a refactoring of the class and package name. But still, the same error. Unlike many MXML components, I cannot cmd+click <mx:method> in FlashBuilder to open the source. Likewise, I have not found a reference in mx.rpc.remoting.mxml.RemoteObject, mx.rpc.remoting.RemoteObject, or mx.rpc.remoting.AbstractService, and have been unsuccessful in find its source online. Which leads me to the questions in the title: What exactly is <mx:method>? (yes, I know it's a declaration of a RemoteObject method, and I know how to use it, but it's peculiar in regard to other components) Why did my attempt at subclassing RemoteObject fail, despite it effectually being a rename? Perhaps the root, why can mx.rpc.remoting.mxml.RemoteObject as an MXML declaration accept <mx:method> child tags, yet the source of said class cannot when refactored in name only?

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  • Parsing a UTF-16 encoded xml file in ruby

    - by Matthew Toohey
    Hello I've been trying to parse a UTF-16 encoded xml file in Ruby (1.8.7), and I can't seem to find how to do it by searching (google and stack overflow) Here's the xml file url: http://www.abc.net.au/triplej/feeds/playout/triplejsydneyplayout.xml?_5366 Getting the xml string from Net::HTTP and passing it to REXML, then calling logger.info xmlDoc.inspect produces: <UNDEFINED> ... </> Any ideas? Cheers

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  • Create an Xml file from an object (c#)

    - by remi bourgarel
    Hi All, I work as a web developer with a web designer and we usually do like this : - I create the system , I generate some Xml files - the designer display the xml files with xslt Nothing new. My problem is that I use Xml Serialization to create my xml files, but I never use Deserialization. So I'd like to know if there is a way to avoid fix like these : empty setter for my property empty parameter-less constructor implement IXmlSerializable and throw "notimplementedexception" on deserialization do a copy of the class with public fields thanks.

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  • Log4Net & RollingFileAppender to generate Xml files

    - by SaguiItay
    I've managed to configure Log4Net with a RollingFileAppender in order to generate Xml files. However, the generated files are not valid XML files until a "roll" is performed - the XML doesn't have a closing XML tag. Basically, this prevents to files from being read until that are "closed"/"rolled". Anyone else encountered this issue? I my previous (custom) solution I had to write the closing tag after writing each entry, and overwrite it with the next entry... :(

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  • XML security in world wide web

    - by nikky
    Hi, Im a newbie in XML and i have some questions Can XML be used in stead of normal database (store data in a tuple and column) in website? XML is built to share information easier (from my understanding) such as can share cross platform and in different language used so Is it secure to store secure data in XML? thank you so much

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  • Modify an XML file in Python

    - by michele
    Hi, I have two file. I have to modify the file one in a particular node and add in a list of child. The list is in the file2. Can I do it, and how? from xml.dom.minidom import Document from xml.dom import minidom file1=modificare.xml file2=sorgente.xml xmldoc=minidom.parse(file1) for Node in xmldoc.getElementsByTagName("Sampler"): # put in the file2 content Thanks a lot.

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  • Blocking problem, C#, .net, Deserializing XML to object problem

    - by fernando
    Hi I have a blocking problem I have XML file under some url http://myserver/mywebApp/myXML.xml In the below code which I run in Console Application, bookcollection has null Books field :( <books> <book id="5352"> <date>1986-05-05</date> <title> Alice in chains </title> </book> <book id="4334"> <date>1986-05-05</date> <title> 1000 ways to heaven </title> </book> <book id="1111"> <date>1986-05-05</date> <title> Kitchen and me </title> </book> </books> XmlDocument doc = new XmlDocument(); doc.Load("http://myserver/mywebapp/myXML.xml"); BookCollection books = new BookCollection(); XmlNodeReader reader2 = new XmlNodeReader(doc.DocumentElement); XmlSerializer ser2 = new XmlSerializer(books.GetType()); object obj = ser2.Deserialize(reader2); BookCollection books2= (BookCollection)obj; using System; using System.Collections.Generic; using System.Linq; using System.Text; namespace ConsoleApplication1 { [Serializable()] public class Book { [System.Xml.Serialization.XmlAttribute("id")] public string id { get; set; } [System.Xml.Serialization.XmlElement("date")] public string date { get; set; } [System.Xml.Serialization.XmlElement("title")] public string title { get; set; } } } using System; using System.Collections.Generic; using System.Linq; using System.Text; using System.Xml.Serialization; namespace ConsoleApplication1 { [Serializable()] [System.Xml.Serialization.XmlRootAttribute("books", Namespace = "", IsNullable = false)] public class BookCollection { [XmlArray("books")] [XmlArrayItem("book", typeof(Book))] public Book[] Books { get; set; } } }

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  • Validate xml against xsd using c++

    - by manu
    Hi , i am very new to xml and c++. i want to validate xml against xsd using c++ api.can any one gimme any tutorial link? or sample program.i don want to do using msxml as its works in windows and visual studio. i tried to use xerces and libxml but i have failed.now i am trying using tinyxml. please help me to validate xml against xml schema using c++(not vc++,should work in cross platform) regards, manu

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  • XSL transformation and special XML entities escaping

    - by Tomas R
    I have an XML file which is transformed with XSL. Some elements have to be changed, some have to be left as is - specifically, text with entities &quot;, &amp;, &apos;, &lt;, &gt; should be left as is, and in my case &quot; and &apos; are changed to " and ' accordingly. Test XML: <?xml version="1.0" encoding="UTF-8" ?> <root> <element> &quot; &amp; &apos; &lt; &gt; </element> </root> transformation file: <?xml version="1.0" encoding="UTF-8"?> <xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0"> <xsl:output method="xml" encoding="UTF-8" omit-xml-declaration="no" indent="no" /> <xsl:template match="element"> <xsl:copy> <xsl:value-of disable-output-escaping="no" select="." /> </xsl:copy> </xsl:template> </xsl:stylesheet> result: <?xml version="1.0" encoding="UTF-8"?> <element> " &amp; ' &lt; &gt; </element> desired result: <?xml version="1.0" encoding="UTF-8"?> <element> &quot; &amp; &apos; &lt; &gt; </element> I have 2 questions: why does some of those entities are transformed and other not? how can I get a desired result?

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  • Flash caroussel xml parse html link

    - by Marvin
    Hello I am trying to modify a carousel script I have in flash. Its normal function is making some icons rotate and when clicked they zoom in, fade all others and display a little text. On that text I would like to have a link like a "read more". If I use CDATA it wont display a thing, if I use alt char like &#60;a href=&#34;www.google.com&#34;&#62; Read more + &#60;/a&#62; It just displays the text as: <a href="www.google.com"> Read more + </a>. The flash dynamic text box wont render it as html. I dont enough as2 to figure out how to add this. My code: var xml:XML = new XML(); xml.ignoreWhite = true; //definições do xml xml.onLoad = function() { var nodes = this.firstChild.childNodes; numOfItems = nodes.length; for(var i=0;i<numOfItems;i++) { var t = home.attachMovie("item","item"+i,i+1); t.angle = i * ((Math.PI*2)/numOfItems); t.onEnterFrame = mover; t.toolText = nodes[i].attributes.tooltip; t.content = nodes[i].attributes.content; t.icon.inner.loadMovie(nodes[i].attributes.image); t.r.inner.loadMovie(nodes[i].attributes.image); t.icon.onRollOver = over; t.icon.onRollOut = out; t.icon.onRelease = released; } } And the xml: <?xml version="1.0" encoding="UTF-8"?> <icons> <icon image="images/product.swf" tooltip="Product" content="Hello this is some random text &#60;a href=&#34;www.google.com&#34;&#62; Read More + &#60;/a&#62; "/> </icons> Any suggestions? Thanks.

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  • Blocking problem Deserializing XML to object problem

    - by fernando
    I have a blocking problem I have XML file under some url http://myserver/mywebApp/myXML.xml In the below code which I run in Console Application, bookcollection has null Books field :( <books> <book id="5352"> <date>1986-05-05</date> <title> Alice in chains </title> </book> <book id="4334"> <date>1986-05-05</date> <title> 1000 ways to heaven </title> </book> <book id="1111"> <date>1986-05-05</date> <title> Kitchen and me </title> </book> </books> XmlDocument doc = new XmlDocument(); doc.Load("http://myserver/mywebapp/myXML.xml"); BookCollection books = new BookCollection(); XmlNodeReader reader2 = new XmlNodeReader(doc.DocumentElement); XmlSerializer ser2 = new XmlSerializer(books.GetType()); object obj = ser2.Deserialize(reader2); BookCollection books2= (BookCollection)obj; using System; using System.Collections.Generic; using System.Linq; using System.Text; namespace ConsoleApplication1 { [Serializable()] public class Book { [System.Xml.Serialization.XmlAttribute("id")] public string id { get; set; } [System.Xml.Serialization.XmlElement("date")] public string date { get; set; } [System.Xml.Serialization.XmlElement("title")] public string title { get; set; } } } using System; using System.Collections.Generic; using System.Linq; using System.Text; using System.Xml.Serialization; namespace ConsoleApplication1 { [Serializable()] [System.Xml.Serialization.XmlRootAttribute("books", Namespace = "", IsNullable = false)] public class BookCollection { [XmlArray("books")] [XmlArrayItem("book", typeof(Book))] public Book[] Books { get; set; } } }

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  • Writing to a xml file in java

    - by user243680
    import java.io.*; import javax.xml.parsers.*; import javax.xml.transform.*; import javax.xml.transform.dom.*; import javax.xml.transform.stream.*; import org.w3c.dom.*; public class CreatXMLFile { public static void main(String[] args) throws Exception { BufferedReader bf = new BufferedReader(new InputStreamReader(System.in)); // System.out.print("Enter number to add elements in your XML file: "); // String str = bf.readLine(); int no=2; // System.out.print("Enter root: "); String root = "SMS"; DocumentBuilderFactory documentBuilderFactory =DocumentBuilderFactory.newInstance(); DocumentBuilder documentBuilder =documentBuilderFactory.newDocumentBuilder(); Document document = documentBuilder.newDocument(); Element rootElement = document.createElement(root); document.appendChild(rootElement); // for (int i = 1; i <= no; i++) // System.out.print("Enter the element: "); // String element = bf.readLine(); String element ="Number"; System.out.print("Enter the Number: "); String data = bf.readLine(); Element em = document.createElement(element); em.appendChild(document.createTextNode(data)); rootElement.appendChild(em); String element1 ="message"; System.out.print("Enter the SMS: "); String data1 = bf.readLine(); Element em1 = document.createElement(element1); em1.appendChild(document.createTextNode(data1)); rootElement.appendChild(em1); TransformerFactory transformerFactory = TransformerFactory.newInstance(); Transformer transformer = transformerFactory.newTransformer(); DOMSource source = new DOMSource(document); StreamResult result = new StreamResult(System.out); transformer.transform(source, result); } } i am working on the above code and it gives the following output run: Enter the Number: 768678 Enter the SMS: ytu <?xml version="1.0" encoding="UTF-8" standalone="no"?><SMS><Number>768678</Number><message>ytu</message></SMS>BUILD SUCCESSFUL (total time: 8 seconds) Now i want to write the output generated(<?xml version="1.0" encoding="UTF-8" standalone="no"?><SMS><Number>768678</Number><message>ytu</message></SMS>) to a XML file on the hard disk.How do i do it?

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  • XML parse file from HTTP

    - by Travis
    I have an XML file located at a location such as http://example.com/test.xml I'm trying to parse the XML file to use it in my program with xPath like this but it is not working. Document doc = builder.parse(new File(url)); How can I get the XML file?

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  • Optimal xml storage engine

    - by nixau
    I'm considering optimal open source solution for storing xml documents with further querying on them effectively. Amount of data will be small. As far as I understand native xml databases might form a proper solution for my case. They obviously store xml documents in highly efficient way. It would be great to learn your experience. Any suggestions on proper solution? Have you got any experience employing xml storage engines in your apps?

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  • Redirection of xml file for iphone app

    - by gotye
    Hey guys, I have a xml file on my server like the one below : www.myWebSite.com/myXmlFile.xml which is used by my iphone application. In case the address of my xml file changes to www.myOtherWebsite.com/myXmlFile.xml How can I make my app to work anyway ? What kind of PHP server-side code do I need to write ? Is NSURLConnection supporting reirections ? Thanks for any incomings ;) Gotye.

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  • How to send raw XML in Python?

    - by davywahd
    Hi, I am trying to send raw xml to a service in Python. I have a the address of the service and my question is how would I wrap XML in python and send it to the service. The address is in the format below. 192.1100.2.2:54239 And say the XML is: <xml version="1.0" encoding="UTF-8"><header/><body><code><body/> Anyone know what to do?

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  • Qt C++ XML, validating against a DTD?

    - by Airjoe
    Is there a way to validate an XML file against a DTD with Qt's XML handling? I've tried googling around but can't seem to get a straight answer. If Qt doesn't include support for validating an XML file, what might be the process of implementing validation myself? Any good reference to start with in regards to validating XML against a spec? Thanks for the help!

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  • Is there a way to enforce/preserve order of XML elements in an XML Schema?

    - by MarcoS
    Let's consider the following XML Schema: <?xml version="1.0" encoding="UTF-8"?> <schema targetNamespace="http://www.example.org/library" elementFormDefault="qualified" xmlns="http://www.w3.org/2001/XMLSchema" xmlns:lib="http://www.example.org/library"> <element name="library" type="lib:libraryType"></element> <complexType name="libraryType"> <sequence> <element name="books" type="lib:booksType"></element> </sequence> </complexType> <complexType name="booksType"> <sequence> <element name="book" type="lib:bookType" maxOccurs="unbounded" minOccurs="1"></element> </sequence> </complexType> <complexType name="bookType"> <attribute name="title" type="string"></attribute> </complexType> </schema> and a corresponding XML example: <?xml version="1.0" encoding="UTF-8"?> <lib:library xmlns:lib="http://www.example.org/library" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://www.example.org/library src/library.xsd "> <lib:books> <lib:book title="t1"/> <lib:book title="t2"/> <lib:book title="t3"/> </lib:books> </lib:library> Is there a way to guarantee that the order of <lib:book .../> elements is preserved? I want to be sure that any parser reading the XML will return books in the specified oder, that is first the book with title="t1", then the book with title="t2", and finally the book with title="t3". As far as I know XML parsers are not required to preserve order. I wonder whether one can enforce this through XML Schema? One quick solution for me would be adding an index attribute to the <lib:book .../> element, and delegate order preservation to the application reading the XML. Comments? Suggestions?

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  • Unable to Export contents of Data table (with French formatted Numbers ) to XML

    - by Ananth
    I have a data Table with numbers formatted according to the current regional settings. ie ( in French decimal separators are ',' instead of '.' in English). I need to export it to XML. Numbers in XML needs to be formatted according to the current regional settings.But now numbers in XML are formatted in English.Is there any way to make the number formatting in XML according to current regional settings ( or based on the locale of the Data Table) during the exporting process ?

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  • Representing xml through a single class

    - by Charles
    I am trying to abstract away the difficulties of configuring an application that we use. This application takes a xml configuration file and it can be a bit bothersome to manually edit this file, especially when we are trying to setup some automatic testing scenarios. I am finding that reading xml is nice, pretty easy, you get a network of element nodes that you can just go through and build your structures quite nicely. However I am slowly finding that the reverse is not quite so nice. I want to be able to build a xml configuration file through a single easy to use interface and because xml is composed of a system of nodes I am having a lot of struggle trying to maintain the 'easy' part. Does anyone know of any examples or samples that easily and intuitively build xml files without declaring a bunch of element type classes and expect the user to build the network themselves? For example if my desired xml output is like so <cook version="1.1"> <recipe name="chocolate chip cookie"> <ingredients> <ingredient name="flour" amount="2" units="cups"/> <ingredient name="eggs" amount="2" units="" /> <ingredient name="cooking chocolate" amount="5" units="cups" /> </ingredients> <directions> <direction name="step 1">Preheat oven</direction> <direction name="step 2">Mix flour, egg, and chocolate</direction> <direction name="step 2">bake</direction> </directions> </recipe> <recipe name="hot dog"> ... How would I go about designing a class to build that network of elements and make one easy to use interface for creating recipes? Right now I have a recipe object, an ingredient object, and a direction object. The user must make each one, set the attributes in the class and attach them to the root object which assembles the xml elements and outputs the formatted xml. Its not very pretty and I just know there has to be a better way. I am using python so bonus points for pythonic solutions

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  • Flex - How to edit a xml file on the server

    - by BS_C3
    Hi! I was wondering if it was possible to edit an xml on the server side from a web based flex application. When you use XML files in a Flex application and then compile it to upload it in the server, Flex Buidler generates a swf file with the xml data embedded. How should I do to have access to those XML files?? Thanks for your answers. Regards. BS_C3

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