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  • What is a more "ruby way" to write this code?

    - by steadfastbuck
    This was a homework assignment for my students (I am a teaching assistant) in c and I am trying to learn Ruby, so I thought I would code it up. The goal is to read integers from a redirected file and print some simple information. The first line in the file is the number of elements, and then each integer resides on its own line. This code works (although perhaps inefficiently), but how can I make the code more Ruby-like? #!/usr/bin/ruby -w # first line is number of inputs (Don't need it) num_inputs = STDIN.gets.to_i # read inputs as ints h = Hash.new STDIN.each do |n| n = n.to_i h[n] = 1 unless h[n] and h[n] += 1 end # find smallest mode h.sort.each do |k,v| break puts "Mode is: #{k}", "\n" if v == h.values.max end # mode unique? v = h.values.sort print "Mode is unique: " puts v.pop == v.pop, "\n" # print number of singleton odds, # odd elems repeated odd number times in desc order # even singletons in desc order odd_once = 0 odd = Array.new even = Array.new h.each_pair do |k, v| odd_once += 1 if v == 1 and k.odd? odd << k if v.odd? even << k if v == 1 and k.even? end puts "Number of elements with an odd value that appear only once: #{odd_once}", "\n" puts "Elements repeated an odd number of times:" puts odd.sort.reverse, "\n" puts "Elements with an even value that appear exactly once:" puts even.sort.reverse, "\n" # print fib numbers in the hash class Fixnum def is_fib? l, h = 0, 1 while h <= self return true if h == self l, h = h, l+h end end end puts "Fibonacci numbers:" h.keys.sort.each do |n| puts n if n.is_fib? end

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  • Why Is Java Missing Access Specifiers?

    - by Tom Tresansky
    Does anyone understand why Java is missing: An access specifier which allows access by the class and all subclasses, but NOT by other classes in the same package? (Protected-minus) An access specifier which allows access by the class, all classes in the same package, AND all classes in any sub-package? (Default-plus) An access specifier which adds classes in sub-packages to the entities currently allowed access by protected? (Protected-plus) I wish I had more choices than protected and default. In particular, I'm interested in the Protected-plus option. Say I want to use a Builder/Factory patterned class to produce an object with many links to other objects. The constructors on the objects are all default, because I want to force you to use the factory class to produce instances, in order to make sure the linking is done correctly. I want to group the factories in a sub-package to keep them all together and distinct from the objects they are instantiating---this just seems like a cleaner package structure to me. No can do, currently. I have to put the builders in the same package as the objects they are constructing, in order to gain the access to defaults. But separating project.area.objects from project.area.objects.builders would be so nice. So why is Java lacking these options? And, is there anyway to fake it?

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  • Mysql query, need suggestion or solution

    - by Xi Kam
    Can anyone help me, i have two tables and i need records from both the table //////////////////////////////++ Query 1 ++//////////////////////////////////// SELECT SUM(rec_issued) AS issed, regen_id, YEAR(issue_date) AS iYear, MONTH(issue_date) AS iMonth FROM `view_rec_issued` WHERE `regen_id` = 2 GROUP BY YEAR(issue_date) DESC, MONTH(issue_date) DESC ORDER BY issue_date ASC issed regen_id iYear iMonth 424 2 2011 3 4340 2 2011 4 4235 2 2011 5 10570 2 2012 2 4761 2 2012 3 5000 2 2012 4 3700 2 2012 5 3414 2 2012 6 3700 2 2012 7 2992 2 2012 8 995 2 2012 10 ![Result from Query 1][1] //////////////////////////////++ Query 2 ++//////////////////////////////////// SELECT SUM(total_redem) AS redemed, regen_id, YEAR(redemption_date) AS rYear, MONTH(redemption_date) AS rMonth FROM `recredem_month_wise` WHERE `regen_id` = 2 GROUP BY YEAR(redemption_date) DESC, MONTH(redemption_date) DESC order by redemption_date ASC redemed regen_id rYear rMonth 424 2 2011 3 260 2 2011 4 6523 2 2011 5 1070 2 2011 6 200 2 2011 10 500 2 2011 11 9750 2 2012 2 5000 2 2012 3 5500 2 2012 4 3803 2 2012 5 3700 2 2012 7 3000 2 2012 8 ![Result from Query 2][2] But i want it as - issed regen_id iYear iMonth redemed regen_id rYear rMonth 424 2 2011 3 424 2 2011 3 4340 2 2011 4 260 2 2011 4 4235 2 2011 5 6523 2 2011 5 NULL NULL NULL NULL 1070 2 2011 6 NULL NULL NULL NULL 200 2 2011 10 NULL NULL NULL NULL 500 2 2011 11 10570 2 2012 2 9750 2 2012 2 4761 2 2012 3 5000 2 2012 3 5000 2 2012 4 5500 2 2012 4 3700 2 2012 5 3803 2 2012 5 3414 2 2012 6 NULL NULL NULL NULL 3700 2 2012 7 3700 2 2012 7 2992 2 2012 8 3000 2 2012 8 995 2 2012 10 NULL NULL NULL NULL ![I want this output][3] In these table regen_id is unique and i need data as YEAR and MONTH, if in any table not have the records in perticular month and year it should retrieve zero or null. But in every record year and month should equal like this - iYear = rYear and iMonth = rMonth So we can merge both the fields - No need to show year and month twice iYear and rYear = year iMonth and rMonth = month Thank You Please look at this problem.

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  • Aggregation, Association and Composition (examples of code given)

    - by Bukocen
    I have such a simple example: public class Order { private ArrayList<Product> orders = new ArrayList<Product>(); public void add(Product p) { orders.add(p); } } Is it aggregation or composition? I guess it's composition, because orders will be delated after delete of Order, right? Unfortunately it was a task and answer was different;/ Do you know why? second problem: public class Client extends Person { String adress = ""; Orders orders = new Orders(); public Client(String n, String sn) { name = n; surName = sn; } public String getAddress() { return adress; } public Orders getOrders() { return this.orders; } } Is it Association between Client and Orders? My teacher told me that this is association, but I was wondering why it's not a aggregation/composition - he told me that aggregation or composition occur only when one class contains few instances of different class - is that right? I guess not, because e.g. car contains ONE wheel and it's aggregation I guess? What type of relation is that and why? Greetings

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  • How (and if) to write a single-consumer queue using the task parallel library?

    - by Eric
    I've heard a bunch of podcasts recently about the TPL in .NET 4.0. Most of them describe background activities like downloading images or doing a computation, using tasks so that the work doesn't interfere with a GUI thread. Most of the code I work on has more of a multiple-producer / single-consumer flavor, where work items from multiple sources must be queued and then processed in order. One example would be logging, where log lines from multiple threads are sequentialized into a single queue for eventual writing to a file or database. All the records from any single source must remain in order, and records from the same moment in time should be "close" to each other in the eventual output. So multiple threads or tasks or whatever are all invoking a queuer: lock( _queue ) // or use a lock-free queue! { _queue.enqueue( some_work ); _queueSemaphore.Release(); } And a dedicated worker thread processes the queue: while( _queueSemaphore.WaitOne() ) { lock( _queue ) { some_work = _queue.dequeue(); } deal_with( some_work ); } It's always seemed reasonable to dedicate a worker thread for the consumer side of these tasks. Should I write future programs using some construct from the TPL instead? Which one? Why?

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  • filtering search results with php

    - by fl3x7
    Hello, Cant really find any useful information on this through Google so hope someone here with some knowledge can help. I have a set of results which are pulled from a multi dimensional array. Currently the array key is the price of a product whilst the item contains another array which contains all the product details. key=>Item(name=>test, foo=>bar) So currently when I list the items I just order by the key, smallest first and it lists the products smallest price first. However I want to build on this so that when a user sees the results they can choose other ordering options like list all products by a name, certain manufacturer, colour, x ,y ,z etc etc from a drop down box(or something similar) This is where I need some guidance. Im just not sure how to go about it or best practise or anything. The only way I can think of is to order all the items by the nested array eg by the name, manufacturer etc. but how do I do that in PHP? Hope you understand what im trying to achieve(if not just ask). Any help on this with ideas, approaches or examples would be great. Thanks for reading p.s Im using PHP5

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  • Python: Sorting array with custom pattern

    - by Binka
    In my little project here I have sorted a list in decending order, however, my goal is to sort it in this custom pattern. (largest - smallest - next largest - next smallest -)etc. In java I was able to do this like this... My goal is to do the same thing but in python, except backwards. Any ideas on how to convert that last for loop that does the wackysort into python and make it go backwards? public static void wackySort(int[] nums){ //first, this simply sorts the array by ascending order. int sign = 0; int temp = 0; int temp2 = 0; for (int i = 0; i < nums.length; i++){ for (int j = 0; j < nums.length -1; j++){ if (nums[j] > nums[j+1]){ temp = nums[j]; nums[j] = nums[j+1]; nums[j+1] = temp; } } } //prepare for new array to actually do the wacky sort. System.out.println(); int firstPointer = 0; int secondPointer = nums.length -1; int[] newarray = new int[nums.length]; int size = nums.length; //for loop that increments by two taking second slot replacing the last (n-1) term for (int i = 0; i < nums.length -1; i+=2){ newarray[i] = nums[firstPointer++]; newarray[i+1] = nums[secondPointer--]; } //storing those values back in the nums array for (int i = 0; i < nums.length; i++){ nums[i] = newarray[i]; } }

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  • SELECT Statement without duplicate rows on the multiple join tables

    - by theBo
    I have 4 tables built with JOINS and I would like to SELECT DISTINCT rows on the setsTbl.s_id so they always show regardless if there's relational data against them or not!. This is what I have at present which displays the data but doesn't display all of but not the entire distinct row! SELECT setsTbl.s_id, setsTbl.setName, userProfilesTbl.no + ' ' + userProfilesTbl.surname AS Name, trainingTbl.t_date, userAssessmentTbl.o_id FROM userProfilesTbl LEFT OUTER JOIN userAssessmentTbl ON userProfilesTbl.UserId = userAssessmentTbl.UserId FULL OUTER JOIN trainingTbl ON userAssessmentTbl.tt_id = trainingTbl.tt_id RIGHT OUTER JOIN setsTbl ON trainingTbl.s_id = setsTbl.s_id WHERE (userProfilesTbl.st_id=@st_id AND userProfilesTbl.sh_id=@sh_id) AND (DATEPART(yyyy,t_date) = @y_date ) OR (userAssessmentTbl.o_id IS NULL) ORDER BY setName ASC, t_date ASC With this statement I get some of the rows (the ones with data against them) but as stated the s_id field does not return distinct. This following inner select statement works in part when used in SQL Query analyzer and returns pretty much the data i require s_id setName Name o_id ----- ----- ----- ------ 1 100 Barnes 2 2 100 Beardsley 3 3 101 Aldridge 1 4 102 Molby 2 5 102 Whelan 3 but not when used outside of that environment. select * from ( SELECT userProfilesTbl.serviceNo + ' ' + userProfilesTbl.surname AS Name, userProfilesTbl.st_id, userProfilesTbl.sh_id, userAssessmentTbl.o_id, setsTbl.s_id, setsTbl.setName, row_number() over ( partition by setsTbl.s_id order by setsTbl.s_id ) r FROM userProfilesTbl LEFT OUTER JOIN userAssessmentTbl ON userProfilesTbl.UserId = userAssessmentTbl.UserId FULL OUTER JOIN trainingTbl ON userAssessmentTbl.tt_id = trainingTbl.tt_id RIGHT OUTER JOIN setsTbl ON trainingTbl.s_id = setsTbl.s_id ) x where x.r = 1 Not receiving any errors just not displaying the data?

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  • Smarty/PHP loop not being passed to IE(Pc) or Chrome/FF(Mac)

    - by Kyle Sevenoaks
    Hi, I've been working on a site that has a lot of PHP/Smarty involved, I've been asked to re-skin a webstore checkout process, but during this we've discovered this issue. This particular quirk is one part of a tax calculation that doesn't get sent to the browser in IE for PC and Chrome/FF for the Mac. It's NOT in the output source in the browsers, but is in FF, Chrome and Opera on the PC. Here is the code that doesn't "work:" {foreach $cart.taxes.$currency as $tax} <div id="subTotalCaption2"><p style="width:100px;">{$tax.name_lang}:</p></div> <div id="taxAmount2"><p>{$tax.formattedAmount}</p></div> {/foreach} It's not a CSS issue as if you go all the way through the checkout process and then back to the order page (Not using the back button, using the on-site links) it works. There is another calculation on the last page of the process that does the same thing: {foreach from=$order.taxes.$currency item="tax"} <tr> <td colspan="{$colspan}" class="tax">{$tax.name_lang}:</td> <td>{$tax.formattedAmount}</td> </tr> {/foreach} I guess my question is what could cause this to not be read (Parsed?) in IE and the mac but other browsers do it fine on the PC. Thanks.

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  • Strategies for testing reactive, asynchronous code

    - by Arne
    I am developing a data-flow oriented domain-specific language. To simplify, let's just look at Operations. Operations have a number of named parameters and can be asked to compute their result using their current state. To decide when an Operation should produce a result, it gets a Decision that is sensitive to which parameter got a value from who. When this Decision decides that it is fulfilled, it emits a Signal using an Observer. An Accessor listens for this Signal and in turn calls the Result method of the Operation in order to multiplex it to the parameters of other Operations. So far, so good, nicely decoupled design, composable and reusable and, depending on the specific Observer used, as asynchronous as you want it to be. Now here's my problem: I would love to start coding actual Tests against this design. But with an asynchronous Observer... how should I know that the whole signal-and-parameters-plumbing worked? Do I need to use time outs while waiting for a Signal in order to say that it was emitted successfully or not? How can I be, formally, sure that the Signal will not be emitted if I just wait a little longer (halting problem? ;-)) And, how can I be sure that the Signal was emitted because it was me who set a parameter, and not another Operation? It might well be that my test comes to early and sees a Signal that was emitted way before my setting a parameter caused a Decision to emit it. Currently, I guess the trivial cases are easy to test, but as soon as I want to test complex many-to-many - situations between operations I must resort to hoping that the design Just Works (tm)...

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  • $_POST Variable Detected in Chrome but not in Firefox

    - by user1707973
    I am using 2 images in a form to sort out query results from the database. The form is submitted using the POST method. When i click on the first image, the query results have to be sorted in ascending order, and when i click on the second, the results have to be sorted in the descending order. This is the code for the form: <form name="" action="" method="post"> <input type="hidden" name="typep" value="price" /> <input type="image" name="sort" value="asc" src="images/asc-ar.png" /> <input type="image" name="sort" value="desc" src="images/dsc-ar.png" /> </form> Now this is the code for checking if the $_REQUEST['sort'] variable is set and therefore whether sorting is required or not. if ($_REQUEST['sort'] != "") { $sort = $_REQUEST['sort']; $typep = $_REQUEST['typep']; //query to be executed depending on values of $sort and $typep } Firefox does detect the $_REQUEST['typep'] variable but not the $_REQUEST['sort'] one. This works perfectly in Chrome though. When i test the site in Firefox, it doesn't detect the $_REQUEST['sort'] variable and therefore the if condition evaluates to false and the search results don't get sorted.

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  • What are the potential problems with exposing the Facebook API secret?

    - by genehack
    I'm writing a little web utility that posts status updates to Twitter and/or Facebook. That involved creating 'applications' with both those services in order to get API keys and 'secrets'. My question is how protected I really need to keep those secrets -- in order for this to work at all, you seem to need the secret to interact with the authentication part of the service to grant the app access to your account and/or grant it permission to post updates on your behalf. Facebook's documentation says to protect the secret, but at least one other Facebook utility distributes the API key and secret in the source. It's important to note: this isn't your standard Facebook 'application' that runs within the context of Facebook, nor is it a standard "desktop"-style compiled app -- it's a web-based application intended to be run on your own web server. The audience for this is probably small and somewhat more sophisticated than average -- so, one technical alternative would be to require people to obtain their own API key and secret to use the app. That seems like a lot of work, however, and a fairly large barrier to entry to anybody using this. Anybody know or have any insight on what sort of trouble I'm letting myself in for if I put both the secrets and the API keys in the config for my app and check it into Github for all the world to see?

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  • Java: "cannot find symbol" error of a String[] defined within a while-loop

    - by David
    Here's the relevant code: public static String[] runTeams (String CPUcolor) { boolean z = false ; //String[] a = new String[6] ; boolean CPU = false ; while (z == false) { while (CPU==false) { String[] a = assignTeams () ; printOrder (a) ; for (int i = 1; i<a.length; i++) { if (a[i].equals(CPUcolor)) CPU = true ; } if (CPU==false) { System.out.println ("ERROR YOU NEED TO INCLUDE THE COLOR OF THE CPU IN THE TURN ORDER") ; } } System.out.println ("is this turn order correct? (Y/N)") ; String s = getIns () ; while (!((s.equals ("y")) || (s.equals ("Y")) || (s.equals ("n")) || (s.equals ("N")))) { System.out.println ("try again") ; s = getIns () ; } if (s.equals ("y") || s.equals ("Y") ) z = true ; } return a ; } the error i get is: Risk.java:416: cannot find symbol symbol : variable a location: class Risk return a ; ^ Why did i get this error? It seems that a is clearly defined in the line String[] a = assignTeams () ; and if anything is used by the lineprintOrder (a) ;` it seems to me that if the symbol a really couldn't be found then the compiler should blow up there and not at the return statment. (also the method assignTeams returns an array of Strings.)

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  • How can I create an array of random numbers in C++

    - by Nick
    Instead of The ELEMENTS being 25 is there a way to randomly generate a large array of elements....10000, 100000, or even 1000000 elements and then use my insertion sort algorithms. I am trying to have a large array of elements and use insertion sort to put them in order and then also in reverse order. Next I used clock() in the time.h file to figure out the run time of each algorithm. I am trying to test with a large amount of numbers. #define ELEMENTS 25 void insertion_sort(int x[],int length); void insertion_sort_reverse(int x[],int length); int main() { clock_t tStart = clock(); int B[ELEMENTS]={4,2,5,6,1,3,17,14,67,45,32,66,88, 78,69,92,93,21,25,23,71,61,59,60,30}; int x; cout<<"Not Sorted: "<<endl; for(x=0;x<ELEMENTS;x++) cout<<B[x]<<endl; insertion_sort(B,ELEMENTS); cout <<"Sorted Normal: "<<endl; for(x=0;x<ELEMENTS;x++) cout<< B[x] <<endl; insertion_sort_reverse(B,ELEMENTS); cout <<"Sorted Reverse: "<<endl; for(x=0;x<ELEMENTS;x++) cout<< B[x] <<endl; double seconds = clock() / double(CLK_TCK); cout << "This program has been running for " << seconds << " seconds." << endl; system("pause"); return 0; }

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  • Mysterious combination

    - by pstone
    I decided to learn concurrency and wanted to find out in how many ways instructions from two different processes could overlap. The code for both processes is just a 10 iteration loop with 3 instructions performed in each iteration. I figured out the problem consisted of leaving X instructions fixed at a point and then fit the other X instructions from the other process between the spaces taking into account that they must be ordered (instruction 4 of process B must always come before instruction 20). I wrote a program to count this number, looking at the results I found out that the solution is n Combination k, where k is the number of instructions executed throughout the whole loop of one process, so for 10 iterations it would be 30, and n is k*2 (2 processes). In other words, n number of objects with n/2 fixed and having to fit n/2 among the spaces without the latter n/2 losing their order. Ok problem solved. No, not really. I have no idea why this is, I understand that the definition of a combination is, in how many ways can you take k elements from a group of n such that all the groups are different but the order in which you take the elements doesn't matter. In this case we have n elements and we are actually taking them all, because all the instructions are executed ( n C n). If one explains it by saying that there are 2k blue (A) and red (B) objects in a bag and you take k objects from the bag, you are still only taking k instructions when 2k instructions are actually executed. Can you please shed some light into this? Thanks in advance.

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  • NHibernate Native SQL multiple joins

    - by Chris
    Hi all, I"m having some problems with Nhibernate and native sql. I've got an entity with alot of collections and I am doing an SQL Fulltext search on it. So when returning 100 or so entities, I dont want all collections be lazy loaded. For this I changed my SQL query: SELECT Query.* FROM (SELECT {spr.*}, {adr.*}, {adrt.*}, {cty.*}, {com.*}, {comt.*}, spft.[Rank] AS [Rak], Row_number() OVER(ORDER BY spft.[Rank] DESC) AS rownum FROM customer spr INNER JOIN CONTAINSTABLE ( customerfulltext , computedfulltextindex , '" + parsedSearchTerm + @"' ) AS spft ON spr.customerid = spft.[Key] LEFT JOIN [Address] adr ON adr.customerid = spr.customerid INNER JOIN [AddressType] adrt ON adrt.addresstypeid = adr.addresstypeid INNER JOIN [City] cty ON cty.cityid = adr.cityid LEFT JOIN [Communication] com ON com.customerid = spr.customerid INNER JOIN [CommunicationType] comt ON comt.communicationtypeid = com.communicationtypeid) as Query ORDER BY Query.[Rank] DESC This is how I setup the query: var items = GetCurrentSession() .CreateSQLQuery(query) .AddEntity("spr", typeof(Customer)) .AddJoin("adr", "spr.addresses") .AddJoin("adrt", "adr.Type") .AddJoin("cty", "adr.City") .AddJoin("com", "spr.communicationItems") .AddJoin("comt", "com.Type") .List<Customer>(); What happens now is, that the query returns customers twice (or more), I assume this is because of the joins since for each customer address, communicationItem (e.g. phone, email), a new sql row is returned. In this case I thought I could use the DistinctRootEntityResultTransformer. var items = GetCurrentSession() .CreateSQLQuery(query) .AddEntity("spr", typeof(Customer)) .AddJoin("adr", "spr.addresses") .AddJoin("adrt", "adr.Type") .AddJoin("cty", "adr.City") .AddJoin("com", "spr.communicationItems") .AddJoin("comt", "com.Type") .SetResultTransformer(new DistinctRootEntityResultTransformer()) .List<Customer>(); Doing so an exception is thrown. This is because I try to list customers .List<Customer>() but the transformer returns only entities of the last join added. E.g. in the case above, the entity with alias "comt" is returned when doing .List() instead of .List(). If I would switch last join with the join alias "cty", then the transformer returns a list of cities only... Anyone knows how I can return a clean list of customers in this case?

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  • Memory interleaving

    - by Tim Green
    Hello, I have this question that has me rather confused. Suppose that a 1G x 32-bit main memory is built using 256M x 4-bit RAM chips and that this memory is byte-addressable. I have deduced that one would require 4*1G = 2^2*2*30 = 2^32 - so 32 bits to address the full memory. My problem now comes with, say, if you had memory (byte) address "14", determine which memory module this would go into. (There would have to be 8 chips per module to make the 32-bit wide memory, and 4 modules overall giving 32 chips in total. Modules are numbered from 0). In high-order interleave, it appears trivial that it's the first (0) memory module given a lot of the first few bits are 0. However, low-order interleave has me stumped. I can't figure out (for sure) how many bits are used to determine a memory module (possibly 2, given there are 4 in total?). The given solution is Module 3. This is not homework in the same sense so I will not be tagging it as such.

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  • What is the point of connecting two routers directly together

    - by rubixibuc
    The way subnets work, wouldn't connecting two router interfaces together require their own subnet between them. Unless that subnet mask has 31 bits, wouldn't that was adress space. I'm asking because I often seen that done in networking books. How can this be done without wasting IP Addresses? They usually draw this when explaining subnetting. They have a central router connected to several other each one supposed to be creating their own subnet. Is this really how subnettimg is done? Example <-------[Router 1]-----Wasteful Subnet-------[Router 2]------> | | | \/

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  • Update MySQl table onDrop?

    - by dougvt
    Hi all. I am writing a PHP/MySQL application (using CodeIgniter) that uses some jQuery functionality for dragging table rows. I have a table in which the user can drag rows to the desired order (kind of a queue for which I need to preserve the rank of each row). I've been trying to figure out how to (and whether I should) update the database each time the user drops a row, in order to simplify the UI and avoid a "Save" button. I have the jQuery working and can send a serialized list back to the server onDrop, but is it good design practice to run an update query this often? The table will usually have 30-40 rows max, but if the user drags row 1 far down the list, then potentially all the rows would need to be updated to update the rank field. I've been wondering whether to send a giant query to the server, to loop through the rows in PHP and update each row with its own Update query, to send a small serialized list to a stored procedure to let the server do all the work, or perhaps a better method I haven't considered. I've read that stored procedures in MySQL are not very efficient and use a separate process for each call. Any advice as to the right solution here? Thanks very much for your help!

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  • Given a vector of maximum 10 000 natural and distinct numbers, find 4 numbers(a, b, c, d) such that

    - by king_kong
    Hi, I solved this problem by following a straightforward but not optimal algorithm. I sorted the vector in descending order and after that substracted numbers from max to min to see if I get a + b + c = d. Notice that I haven't used anywhere the fact that elements are natural, distinct and 10 000 at most. I suppose these details are the key. Does anyone here have a hint over an optimal way of solving this? Thank you in advance! Later Edit: My idea goes like this: '<<quicksort in descending order>>' for i:=0 to count { // after sorting, loop through the array int d := v[i]; for j:=i+1 to count { int dif1 := d - v[j]; int a := v[j]; for k:=j+1 to count { if (v[k] > dif1) continue; int dif2 := dif1 - v[k]; b := v[k]; for l:=k+1 to count { if (dif2 = v[l]) { c := dif2; return {a, b, c, d} } } } } } What do you think?(sorry for the bad indentation)

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  • A "quick" vector editor (SVG) for Linux (for annotating images?)

    - by sdaau
    I often need to take a bitmap (.png) image, and draw some lines or text on top of it, and possibly export a new, thusly "annotated" image. I know I can basically do all this in inkscape - but inkscape is a complex program, and it needs almost a minute to start up properly on my PCs. So I was thinking - is there something like a "mini" vector editor for Linux, which would start up fast, and allow me to: Right-click, open an image in this editor program The program scales the active "document"/"window size" to the size of the image I can zoom in/zoom out (and possibly crop) the image I can add at least lines, boxes and text in different colors? A bonus for me would be to have the overlay graphics saved as SVG format, say with the same filename as the image - as in, "image.png.svg" being saved in the same directory where the original "image.png" is located (thus allowing opening and editing these "annotations" further, either in this editor, or possibly in inkscape). And another bonus would be the export of the annotated image to a bitmap. Anyone know about anything like this?

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  • cakephp find('list') - problem using

    - by MOFlint
    I'm trying to get an array to poplulate a Counties select. If I use find('all') I can get the data but this array needs flattening to use in the view with $form-input($counties). If I use find('list') I can't seem to get the right array - which is simple array of county names. What I have tried is this: $ops=array( 'conditions' => array( 'display' => '!=0', 'TO_DAYS(event_finish) >= TO_DAYS(NOW())' ), 'fields' => 'DISTINCT venue_county', 'order' => 'venue_county DESC' ); $this->set('counties', $this->Event->find('list',$ops)); but the SQL this generates is: SELECT Event.id, DISTINCT Event.venue_county FROM events AS Event WHERE display = 1 AND TO_DAYS(event_finish) = TO_DAYS(NOW()) ORDER BY venue_county DESC which generates an error because it first inserts the Event.id field in the query - which is not wanted and causes the error. In my database I have a single table for Events which includes the venue address and I don't really want to create another table for address. What options should I be using efor the find('list') call?

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  • Log4j Logging to the Wrong Directory

    - by John
    I have a relatively complex log4j.xml configuration file with many appenders. Some machines the application runs on need a separate log directory, which is actually a mapped network drive. To get around this, we embed a system property as part of the filename in order to specify the directory. Here is an example: The "${user.dir}" part is set as a system property on each system, and is normally set to the root directory of the application. On some systems, this location is not the root of the application. The problem is that there is always one appender where this is not set, and the file appears not to write to the mapped drive. The rest of the appenders do write to the correct location per the system property. As a unit test, I set up our QA lab to hard-code the values for the appender above, and it worked: however, a different appender will then append to the wrong file. The mis-logged file is always the same for a given configuration: it is not a random file each time. My best educated guess is that there is a HashMap somewhere containing these appenders, and for some reason, the first one retrieved from the map does not have the property set. Our application does have custom system properties loading: the main() method loads a properties file and calls into System.setProperties(). My first instinct was to check the static initialization order, and to ensure the controller class with the main method does not call into log4j (directly or indirectly) before setting the properties just in case this was interfering with log4j's own initialization. Even removing all vestiges of log4j from the initialization logic, this error condition still occurs.

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  • Query to bring count from comma seperated Value

    - by Mugil
    I have Two Tables One for Storing Products and Other for Storing Orders List. CREATE TABLE ProductsList(ProductId INT NOT NULL PRIMARY KEY, ProductName VARCHAR(50)) INSERT INTO ProductsList(ProductId, ProductName) VALUES(1,'Product A'), (2,'Product B'), (3,'Product C'), (4,'Product D'), (5,'Product E'), (6,'Product F'), (7,'Product G'), (8,'Product H'), (9,'Product I'), (10,'Product J'); CREATE TABLE OrderList(OrderId INT NOT NULL PRIMARY KEY AUTO_INCREMENT, EmailId VARCHAR(50), CSVProductIds VARCHAR(50)) SELECT * FROM OrderList INSERT INTO OrderList(EmailId, CSVProductIds) VALUES('[email protected]', '2,4,1,5,7'), ('[email protected]', '5,7,4'), ('[email protected]', '2'), ('[email protected]', '8,9'), ('[email protected]', '4,5,9'), ('[email protected]', '1,2,3'), ('[email protected]', '9,10'), ('[email protected]', '1,5'); Output ItemName NoOfOrders Product A 4 Product B 3 Product C 1 Product D 3 Product E 4 Product F 0 Product G 2 Product H 1 Product I 2 Product J 1 The Order List Stores the ItemsId as Comma separated value for every customer who places order.Like this i am having more than 40k Records in my dB table Now I am assigned with a task of creating report in which I should display Items and No of People ordered Items as Shown Below I Used Query as below in my PHP to bring the Orders One By One and storing in array. SELECT COUNT(PL.EmailId) FROM OrderList PL WHERE CSVProductIds LIKE '2' OR CSVProductIds LIKE '%,2,%' OR CSVProductIds LIKE '%,2' OR CSVProductIds LIKE '2,%'; 1.Is it possible to get the same out put by using Single Query 2.Does using a like in mysql query slows down the dB when the table has more no of records i.e 40k rows

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  • Find existence of number in a sorted list in constant time? (Interview question)

    - by Rich
    I'm studying for upcoming interviews and have encountered this question several times (written verbatim) Find or determine non existence of a number in a sorted list of N numbers where the numbers range over M, M N and N large enough to span multiple disks. Algorithm to beat O(log n); bonus points for constant time algorithm. First of all, I'm not sure if this is a question with a real solution. My colleagues and I have mused over this problem for weeks and it seems ill formed (of course, just because we can't think of a solution doesn't mean there isn't one). A few questions I would have asked the interviewer are: Are there repeats in the sorted list? What's the relationship to the number of disks and N? One approach I considered was to binary search the min/max of each disk to determine the disk that should hold that number, if it exists, then binary search on the disk itself. Of course this is only an order of magnitude speedup if the number of disks is large and you also have a sorted list of disks. I think this would yield some sort of O(log log n) time. As for the M N hint, perhaps if you know how many numbers are on a disk and what the range is, you could use the pigeonhole principle to rule out some cases some of the time, but I can't figure out an order of magnitude improvement. Also, "bonus points for constant time algorithm" makes me a bit suspicious. Any thoughts, solutions, or relevant history of this problem?

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