Search Results

Search found 57986 results on 2320 pages for 'breadth first search'.

Page 285/2320 | < Previous Page | 281 282 283 284 285 286 287 288 289 290 291 292  | Next Page >

  • HttpwebRequest Simulate Click

    - by Afnan
    I was working on httpwebrequest and was trying to search google get result and simulate click to desired link. Is that possible? string raw ="http://www.google.com/search?hl=en&q={0}&aq=f&oq=&aqi=n1g10"; string search = string.Format(raw, HttpUtility.UrlEncode(searchTerm)); HttpWebRequest request = (HttpWebRequest)WebRequest.Create(search); request.Proxy = prox; using (HttpWebResponse response = (HttpWebResponse)request.GetResponse()) { using (StreamReader reader = new StreamReader(response.GetResponseStream(), Encoding.ASCII)) { HtmlElementCollection html = reader.ReadToEnd(); browserA=reader.ReadToEnd(); this.Invoke(new EventHandler(IE1)); } }

    Read the article

  • Retrieving models from form with ModelMultipleChoiceField

    - by colinjameswebb
    I am having difficulties with forms, specifically ModelMultipleChoiceField. I've pieced together this code from various examples, but it sadly doesn't work. I would like to be able to: Search for some Works on work_search.html Display the results of the search, with checkboxes next to each result Select the Works I want, via the checkboxes After pressing Add, display which works were selected. I believe everything is okay except the last part. The page simply displays "works" :( Here is the code - sorry about the length. Models.py class Work(models.Model): title = models.CharField(max_length=200) artist = models.CharField(max_length=200) writers = models.CharField(max_length=200) def __unicode__(self): return self.title + ' - ' + self.artist forms.py class WorkSelectForm(forms.Form): def __init__(self, queryset, *args, **kwargs): super(WorkSelectForm, self).__init__(*args, **kwargs) self.fields['works'] = forms.ModelMultipleChoiceField(queryset=queryset, widget=forms.CheckboxSelectMultiple()) views.py def work_search(request): query = request.GET.get('q', '') if query: qset = ( Q(title__icontains=query) | Q(artist__icontains=query) | Q(writers__icontains=query) ) results = Work.objects.filter(qset).distinct() form = WorkSelectForm(results) return render_to_response("work_search.html", {"form": form, "query": query }) else: results = [] return render_to_response("work_search.html", {"query": query }) def add_works(request): #if request.method == POST: form = WorkSelectForm(request.POST) #if form.isvalid(): items = form.fields['works'].queryset return render_to_response("add_works.html", {"items":items}) work_search.html {% extends "base.html" %} {% block content %} <h1>Search</h1> <form action="." method="GET"> <label for="q">Search: </label> <input type="text" name="q" value="{{ query|escape }}"> <input type="submit" value="Search"> </form> {% if query %} <h2>Results for "{{ query|escape }}":</h2> <form action="add_works" method="post"> <ul> {% if form %} {{ form.as_ul }} {% endif %} </ul> <input type="submit" value="Add"> </form> {% endif %} {% endblock %} add_works.html {% extends "base.html" %} {% block content %} {% if items %} {% for item in items %} {{ item }} {% endfor %} {% else %} <p>Nothing selected</p> {% endif %} {% endblock %}

    Read the article

  • Combine two views into one view

    - by Kevin
    I have two views that I would like to combine into one. The first view shows all items of X where company ID = Y. This is to give preferential sort to the client first, and then everyone else. So I created a second view, all items of X, where company ID != Y. I created it as an Attachment to attach to the first view, but I don't think I got the intended result. How can I combine these views so the first view results are listed first, and then the second view is too, using the same pager, filters, and arguments? Is there any way of achieving this without programming it?

    Read the article

  • Was delegates static by default?

    - by Sri Kumar
    Hello All, I was just trying to understand delegates using the following code. public class delegatesEx { public delegate int Mydelegate(int first, int second); public int add(int first, int second) { return first + second; } public int sub(int first, int second) { return first - second; } } Here is my main method Console.WriteLine("******** Delegates ************"); delegatesEx.Mydelegate myAddDelegates = new delegatesEx.Mydelegate(new delegatesEx().add); int addRes = myAddDelegates(3, 2); Console.WriteLine("Add :" + addRes); delegatesEx.Mydelegate mySubDelegates = new delegatesEx.Mydelegate(new delegatesEx().sub); int subRes = mySubDelegates(3, 2); Console.WriteLine("Sub :" + subRes); I didn't declare delegate to be static but i was able to access it using the Class name. How is it possible?

    Read the article

  • jQuery e.stopPropagation() - how to use without breaking dropbox functionality altogether?

    - by Knut Ole
    Short story: stopPropagation() prevents a dropdown menu from closing - which is good. But it also prevents the dropbox from opening next time around - which is bad. Long story: I'm using Twitter-Bootstrap and I've put a search box inside the dropdown menu like so: <div id="search_word_menu" style="position:absolute;right:157px;top:60px;"> <ul class="nav nav-pills"> <li class="dropdown" id="menu200"> <a class="dropdown-toggle btn-inverse" data-toggle="dropdown" style="width:117px;position:relative;left:2px" href="#menu200"> <i class="icon-th-list icon-white"></i> Testing <b class="caret"></b> </a> <ul class="dropdown-menu"> <li><a href="#">Retweets</a></li> <li><a href="#">Favourites</a></li> <li class="divider"></li> <li><a href="#">A list</a></li> <li class="divider"></li> <li><a href="#">A saved search</a></li> <li><a href="#">A saved #hashtag</a></li> <li class="divider"></li> <li> <!-- HERE --> <input id="drop_search" type="text" class="search_box_in_menu" value="Search..."> </li> </ul> </li> </ul> When I click inside the searchbox, the default behaviour is obviously to close the dropdown - but that makes it rather hard to write in a search term. So I've tried with the e.stopPropagation(), which does indeed prevent the dropdown from closing. Then, when I press enter in the searchbox, I'm closing the dropdown with a .toggle() - also seems to work fine. The PROBLEM arises when I want to to it all again, because the e.stopPropagation() has now disabled the dropdown alltogether - ie. when I press the dropdown menu, it doesn't open anymore! This is because of stopPropagation(), no doubt - but how can I resolve this, so that I get the aforementioned functionality, but without breaking the rest altogether? jQuery below: $(document).ready(function() { console.log("document.ready - "); //clearing search box on click $(".search_box_in_menu").click(function(e) { e.stopPropagation(); // works for the specific task console.log(".search_box_in_menu - click."); if($(this).val() == 'Search...') { $(this).val(''); console.log(".search_box_in_menu - value removed."); }; //return false; //this is e.preventDefault() and e.stopPropagation() }); // when pressing enter key in search box $('.search_box_in_menu').keypress(function(e) { var keycode = (e.keyCode ? e.keyCode : e.which); if(keycode == '13') { console.log(".search_box_in_menu - enter-key pressed."); console.log($(this).val()); $(this).closest('.dropdown-menu').toggle(); //works } }); $('.dropdown').click(function() { console.log(".dropdown - click."); $(this).closest('.dropdown-toggle').toggle(); //does nothing }); Would greatly appreciate some help! I'm starting to suspect this might be a bootstrapped-only problem, or at least caused by their implementation - but it's beyond me atm.

    Read the article

  • UIView animation

    - by iphonedevnoob
    I have a UIView(first view) on top of which I would like to display another UIView(second view). I display the second view using animation which causes the second view to be displayed for about 3/4 of the iPhone screen. The first view is visible underneath the animated second view. I would like to make changes to the first view as the second view is displayed. Any ideas on how I can achieve this. Right now, the animation completes, the second view is displayed and then I can change the first view. I would like to change the layout of the first screen as the second screen is being displayed. Any help is much appreciated.

    Read the article

  • Eclipse: find resource on classpath

    - by seanizer
    Is there a way in eclipse to search the classpath for arbitrary resource file names (or patterns)? I know I can use either Navigate > Open Type (which will scan the classpath for classes) or Navigate > Open Resource, which will search for any resource type, but only in my project folders. Is there any way to achieve a combination ob both, to do a resource search (something like *.xsd) that searches all jars on the classpath?

    Read the article

  • ScrollView scrolling speed

    - by Psudheer_iph
    hi all, thanx in advance. In my app, i am having 2 scrollviews in view.first scroll is placed bottom and then second Scroll placed. if i scroll either first or second both will scroll depends on finger movements. this is working. But my question is, i want the scrolling speed is different for first scroll and second scroll eg. if first scroll moves 2px speed then second scroll has to move double the speed of first scroll i.e 4px. How can i solve this.

    Read the article

  • How to Keep the selected value of the select box after Form POST or GET

    - by Rajasekar
    Im trying to implement the search feature in my website. when the search keyword is entered in the textbox, and the category combo is selected, the form will be Posted and the result will be shown on the same page. what i want is to keep the selected category of the combo by default in the form after posted For eg., If i select the category 'Automobiles' in the combo and click search, after form submit, the combo should show the automobiles as default selected option. Please help me. Any help will be appreciated

    Read the article

  • Hiding div tag when the user clicks outside the div tag.

    - by Madhu
    Hi friends, I have a div tag and I am populating the search results on a custom grid, which is placed inside this divtag. When a user click on the search button, i am displaying the results in the above mentioned div tag. I have a requirement to close the above div tag when the user clicks outside the div tag. It is similar to google search auto comlete. Thanks in advance.

    Read the article

  • create dynamic link buttons in ListView

    - by Sunny
    Hi, I am creating a search using listview. when user enter a word in search, I am generating a listview with the results. Now, there will be tags in each listview row. When, user clicks the tag, again a search happens using the value in the tag. There may be any number of tags for each listview row. I have to generate linkbuttons for these tags. Could anyone please guide me on how to create dynamic linkbuttons and access those values for further search. You can have a look at delicious.com. I need a similar functionality. Thanks in advance.

    Read the article

  • UIWebview handle popup view

    - by Tuan Nguyen
    I've a webpage with one text-box and one button. Click on button will show a popup for searching. On popup page,has 2 buttons, "Search" and "Close". Input the text and click Search, the result will display on a list on this popup, click on a row will close the popup and fill the value to text-box on main-page. On Destop browser, it works fine On Safari on iPad, it will open new tab instead of a popup but work fine. UIWebview in my app, on main-page, click the button, I will go to Search page, but when click Search button and close button, nothing happened, I know because 2 buttons will close the popup or the tab, but I don't know how to handle on my Webview, and also I can fill data to main-page or not? Could anyone point me away? Thanks,

    Read the article

  • Session sharing

    - by GeoXYZ
    Hello, i have a problem with Session sharing... I have a single web application hosted on a server. I created in IIS 2 different domains for the same application (thus each pointing to same physical path). The first domain is used as main interface, and the second domain is used to change settings (kind of like an admin). If the user logs in (login information is stored in session) the first domain, and then goes to the second one, he is also logged in there, which is OK. but when i try to change something in the session (like email address) from the second domain, the data is changed OK but only in the first domain; in the second one i still have the old data... also what i've noticed is that when redirecting from first domain to second domain, every postback control posts back to the first domain even though i am on the second one - this causes encryption errors with the viewstate... If anyone has any ideas, i would appreciate it... Thank you.

    Read the article

  • How to adjust asp.net URL routing based on domain/host?

    - by DrewF
    What's the best way to adjust the path destination for a routing table created in the global.asax Application_Start event based on the domain/sub domain/host? The following worked in IIS6, but with IIS7 the request object is decoupled from the Application_Start event and therefore does not work anymore: Dim strHost As String = Context.Request.Url.Host Dim strDir As String = "" If strHost.Contains("domain1.com") Then strDir = "area1/" Else strDir = "area2/" End If routes.MapPageRoute("Search", "Search", "~/" & strDir & "search.aspx")

    Read the article

  • my jComboBox does not react to my keyListener and actionPerform perfroms weired stuff

    - by aladdin
    hi I am trying to search for UserName and return values onto jComboBox, here is the code public void actionPerformed(java.awt.event.ActionEvent e) { sr = new Search(((String) jComboBoxReceiver.getSelectedItem())); usrList = sr.searchUser(); String[] userList = new String[usrList.size()] ; for(int i=0;i<usrList.size();i++){ userList[i]= usrList.get(i).getUserName(); } model = new DefaultComboBoxModel(userList); jComboBoxReceiver.setModel(model); } However, if i do that, it does perform correctly, however, it will go search for the first item again, which is very confusing... then i tried using key Pressed if(e.getKeyCode()==13){ sr = new Search(((String) jComboBoxReceiver.getSelectedItem())); usrList = sr.searchUser(); String[] userList = new String[usrList.size()] ; for(int i=0;i<usrList.size();i++){ userList[i]= usrList.get(i).getUserName(); } model = new DefaultComboBoxModel(userList); jComboBoxReceiver.setModel(model); } And this one does not react at all ...

    Read the article

  • dynamic searchable fields, best practice?

    - by boblu
    I have a Lexicon model, and I want user to be able to create dynamic feature to every lexicon. And I have a complicate search interface that let user search on every single feature (including the dynamic ones) belonged to Lexicon model. I could have used a serialized text field to save all the dynamic information if they are not for searching. In case I want to let user search on all fields, I have created a DynamicField Model to hold all dynamically created features. But imagine I have 1,000,000,000 lexicon, and if one create a dynamic feature for every lexicon, this will result creating 1,000,000,000 rows in DynamicField model. So the sql search function will become quite inefficient while a lot of dynamic features created. Is there a better solution for this situation? Which way should I take? searching for a better db design for dynamic fields try to tuning mysql(add cache fields, add index ...) with current db design

    Read the article

  • trying to load css/images in django

    - by tipu
    I looked http://docs.djangoproject.com/en/dev/howto/static-files/ already, but am still confused on how to get css/image files loaded. On my server, the images folder and css file are located at /srv/twingle/search my urls.py 1 from django.conf.urls.defaults import * 2 3 # Uncomment the next two lines to enable the admin: 4 # from django.contrib import admin 5 # admin.autodiscover() 6 7 urlpatterns = patterns('twingle.search.views', 8 url(r'^$', 'index'), 9 url(r'^search/(?P<param>\w+)$', 'index'), 10 ) 11 (r'^site_media/(?P<path>.*)$', 'django.views.static.serve', 12 {'document_root': '/srv/twingle/search'}), 13 I try to access my css as follows, <link rel="stylesheet" type="text/css" href="/site_media/style.css" /> That's exactly how the tutorial says to do it, but it doesn't work. Any suggestions?

    Read the article

  • Jquery current menu

    - by Isis
    Hello I have: var href = window.location.href; if(href.search('/welcome\\/') > 0) { $('.menuwelcome').css('display', 'block'); $('#welcome2').append('<b>?????????? ??????????</b>').find('a').remove(); $('#welcome2').find('img').attr('src', '/static/images/arrow_black.gif'); } if(href.search('/contacts\\/') > 0) { $('.menuwelcome').css('display', 'block'); $('#mcontacts').append('<b>????????</b>').find('a').remove(); $('#mcontacts').find('img').attr('src', '/static/images/arrow_black_down.gif'); } if(href.search('/sindbad_history\\/') > 0) { $('.menuwelcome').css('display', 'block'); $('.menuwelcome:first').append('<b>???????</b>').find('a').remove(); $('.menuwelcome:first').find('img').attr('src', '/static/images/arrow_black.gif'); } if(href.search('/insurance\\/') > 0) { $('.menusafe').css('display', 'block'); $('#msafe').append('<b>???????????</b>').find('a').remove(); $('#msafe').find('img').attr('src', '/static/images/arrow_black_down.gif'); } if(href.search('/insurance_advices\\/') > 0) { $('.menusafe').css('display', 'block'); $('.menusafe:first').append('<b>???????? ??????????</b>').find('a').remove(); $('.menusafe:first').find('img').attr('src', '/static/images/arrow_black.gif'); } How can I minimize this code? Sorry for bad english

    Read the article

  • Receiving the post response using curl

    - by Larry Battle
    Hello, I'm trying to make a script that will download search results from a HTTPS website using POST. So far, I'm able to download the web page before the submission but not the response page containing the search results. The problem seems to be that curl isn't waiting long enough for the response page to appear. The website behaviors likes this. Website appears- input form data - click submit - progressing icon appears - returns new web page with search results( new data but the url doesn't change ) My code: curl -d "postData" -k url

    Read the article

  • how do Google and Yahoo replace the URL in the browser status bar?

    - by Mike W
    On the Google and Yahoo search pages, the URLs of the 10 search result links actually point to google.com or yahoo.com. The URLs have extra arguments that allow google.com or yahoo.com to redirect to the actual search result when the link is clicked. When the user mouses over the link, the search result URL (and not the google.com or yahoo.com URL) is displayed in the browser's status bar. I'm wondering how they do that. Many years ago, this would have been accomplished by having some javascript that sets window.status, but that doesn't seem to work anymore, as is explained by http://stackoverflow.com/questions/876390/reliable-cross-browser-way-of-setting-status-bar-text I have a link that looks like this: <a href="http://somedomain.com/ReallyLongURLThatShouldNotBeSeenInTheStatusBar" onmouseover="window.status='http://niceShourtUrl.com/'" onmouseout="window.status=''">Click Me</a> This link tried to use the window.status strategy, but it doesn't work. How do I fix this link so that it acts like the links on Google's and Yahoo's search result pages? In this example, I want "http://niceShourtUrl.com/" to be displayed in the status bar when the user mouses over the link.

    Read the article

  • Complex orderby question (entity framework)

    - by PFranchise
    Ok, so I will start by saying that I am new to all this stuff, and doing my best to work on this project. I have an employee object, that contains a supervisor field. When someone enters a search on my page, a datagrid displays employees whose name match the search. But, I need it to display all employees that report to them and a third tier of employees that report to the original employee's underlings. I only need three tiers. To make this easier, employees only come in 3 ranks, so if rank==3, that employee is not in charge of others. I imagine the best method of retrieving all these employees from my employee table would be something like from employee in context.employees where employee.name == search || employee.boss.name == search || employee.boss.boss.name == search But I am not sure how to make the orderby appear the way I want to. I need it to display in tiers. So, it will look like: Big Boss Boss underling underling Boss underling Boss Boss Big Boss Like I said, there might be an easier way to approach this whole issue, and if there is, I am all ears. Any advice you can give would be HIGHLY appreciated.

    Read the article

  • Can I do full text searches with jquery Autocomplete ?

    - by Jordie
    Hi, I want to be able to search a list of full names. The autocomplete demos I have seen have all searched from the beginning. Thats no good as I want matches on surname too. I can live without full text search if it at least follows word boundaries. Sorta like the tag search here. Hows that done? Cheers

    Read the article

< Previous Page | 281 282 283 284 285 286 287 288 289 290 291 292  | Next Page >