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  • Why doesn't this external JavaScript load?

    - by Ben Herila
    I've been futzing with this for hours trying to figure out why codemirror.js won't load in any browser other than Firefox. Any ideas? index.html <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Strict//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-strict.dtd"> <html xmlns="http://www.w3.org/1999/xhtml" xml:lang="en"> <head> <title></title> <script src="CodeMirror/js/codemirror.js"></script> <link href="Styles/Style.css" rel="stylesheet" type="text/css" /> <link href="http://ajax.googleapis.com/ajax/libs/jqueryui/1.8/themes/base/jquery-ui.css" rel="stylesheet" type="text/css" /> <script src="http://ajax.googleapis.com/ajax/libs/jquery/1.4/jquery.min.js"></script> <script src="http://ajax.googleapis.com/ajax/libs/jqueryui/1.8/jquery-ui.min.js"></script> <script type="text/javascript"> $(document).ready(function () { $('#container-1').tabs(); }); </script> <style type="text/css"> /* (some css) */ </style> </head><body> <!-- (some stuff) --> </body></html> CodeMirror/js/codemirror.js alert("LOL");

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  • Googlebot substitutes the links of Rails app with subdomain.

    - by Victor
    I have this Rails app, with domain name abc.com. I am also having a separate subdomain for Piwik stats, in this subdomain stats.abc.com. Googlebot somehow listed some of the links with my subdomain too. http://abc.com/login http://stats.abc.com/login http://abc.com/signup http://stats.abc.com/signup The ones with stats will reference to the same page in the app, but are treated entirely different website. I have put in robots.txt in stats after this matter, but wondering if there is any appropriate way to block this because I may have new subdomains in future. Here's my content in robots.txt User-agent: * Disallow: / Thanks.

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  • GitLab on a fresh Ubuntu 13 EC2 instance

    - by Polly
    I've spun up a fresh Amazon EC2 instance for a micro Ubuntu 13 server to be used as a GitLab server. I know the specs are a little low, but it should serve well for my purposes. It has an elastic (static) IP address that I have created an A record for git.mydomain.com. The first thing I did to the instance was add 1GB of swap to keep it happy from a memory perspective. I then set the hostname of the box to be git.mydomain.com and followed https://github.com/gitlabhq/gitlabhq/blob/6-2-stable/doc/install/installation.md to the letter. Everything seems to have worked, except for the web server side of things. Doing a gitlab:check shows the following: Checking Environment ... Git configured for git user? ... yes Has python2? ... yes python2 is supported version? ... yes Checking Environment ... Finished Checking GitLab Shell ... GitLab Shell version >= 1.7.4 ? ... OK (1.7.4) Repo base directory exists? ... yes Repo base directory is a symlink? ... no Repo base owned by git:git? ... yes Repo base access is drwxrws---? ... yes update hook up-to-date? ... yes update hooks in repos are links: ... can't check, you have no projects Running /home/git/gitlab-shell/bin/check Check GitLab API access: /usr/local/lib/ruby/2.0.0/net/http.rb:878:in `initialize': Connection refused - connect(2) (Errno::ECONNREFUSED) from /usr/local/lib/ruby/2.0.0/net/http.rb:878:in `open' from /usr/local/lib/ruby/2.0.0/net/http.rb:878:in `block in connect' from /usr/local/lib/ruby/2.0.0/timeout.rb:52:in `timeout' from /usr/local/lib/ruby/2.0.0/net/http.rb:877:in `connect' from /usr/local/lib/ruby/2.0.0/net/http.rb:862:in `do_start' from /usr/local/lib/ruby/2.0.0/net/http.rb:851:in `start' from /home/git/gitlab-shell/lib/gitlab_net.rb:62:in `get' from /home/git/gitlab-shell/lib/gitlab_net.rb:29:in `check' from /home/git/gitlab-shell/bin/check:11:in `<main>' gitlab-shell self-check failed Try fixing it: Make sure GitLab is running; Check the gitlab-shell configuration file: sudo -u git -H editor /home/git/gitlab-shell/config.yml Please fix the error above and rerun the checks. Checking GitLab Shell ... Finished Checking Sidekiq ... Running? ... yes Number of Sidekiq processes ... 1 Checking Sidekiq ... Finished Checking GitLab ... Database config exists? ... yes Database is SQLite ... no All migrations up? ... yes GitLab config exists? ... yes GitLab config outdated? ... no Log directory writable? ... yes Tmp directory writable? ... yes Init script exists? ... yes Init script up-to-date? ... yes projects have namespace: ... can't check, you have no projects Projects have satellites? ... can't check, you have no projects Redis version >= 2.0.0? ... yes Your git bin path is "/usr/bin/git" Git version >= 1.7.10 ? ... yes (1.8.3) Checking GitLab ... Finished It seems like I'm very nearly there. Searching on this error I have only found advice that unfortunately hasn't helped. I'm not using any kind of SSL setup, which a lot of the posts I found were about. I have tried appending 127.0.0.1 git.mydomain.com to /etc/hosts and giving the instance a reboot but there was no change. My config/gitlab.yml file has host: git.mydomain.com in it, and my gitlab-shell/config.yml has gitlab_url: "http://git.mydomain.com/" in it. I'm sure I'm missing something simple, but I've been through every relevant link I can find and have had no positive results; thank you in advance for any help!

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  • Having a Link Only Appear If a Logged-In User Appears on a Dynamic List

    - by John
    Hello, For the function below, I would like the link <div class="footervote"><a href="http://www...com/.../footervote.php">Vote</a></div> to only appear if the logged in user currently appears on editorlist.php. (I. e. if the loginid in the function corresponds to any of the usernames that currently appear in editorlist.php.) Appearing on editorlist.php is something that is dynamic. How can I do this? Thanks in advance, John function show_userbox() { // retrieve the session information $u = $_SESSION['username']; $uid = $_SESSION['loginid']; // display the user box echo '<div id="userbox"> <div class="username">'.$u.'</div> <div class="submit"><a href="http://www...com/.../submit.php">Submit an item.</a></div> <div class="changepassword"><a href="http://www...com/.../changepassword.php">Change Password</a></div> <div class="logout"><a href="http://www...com/.../logout.php">Logout</a></div> <div class="footervote"><a href="http://www...com/.../footervote.php">Vote</a></div> </div>'; } On editorlist.php: $sqlStr = "SELECT l.loginid, l.username, l.created, DATEDIFF(NOW(), l.created) AS days, COALESCE(s.total, 0) AS countSubmissions, COALESCE(c.total, 0) AS countComments, COALESCE(s.total, 0) * 10 + COALESCE(c.total, 0) AS totalScore, DATEDIFF(NOW(), l.created) + COALESCE(s.total, 0) * 10 + COALESCE(c.total, 0) AS totalScore2 FROM login l LEFT JOIN ( SELECT loginid, COUNT(1) AS total FROM submission GROUP BY loginid ) s ON l.loginid = s.loginid LEFT JOIN ( SELECT loginid, COUNT(1) AS total FROM comment GROUP BY loginid ) c ON l.loginid = c.loginid GROUP BY l.loginid ORDER BY totalScore2 DESC LIMIT 10"; $result = mysql_query($sqlStr); $arr = array(); echo "<table class=\"samplesrec1edit\">"; while ($row = mysql_fetch_array($result)) { echo '<tr>'; echo '<td class="sitename1edit1"><a href="http://www...com/.../members/index.php?profile='.$row["username"].'">'.stripslashes($row["username"]).'</a></td>'; echo '<td class="sitename1edit2">'.($row["countSubmissions"]).'</td>'; echo '<td class="sitename1edit2">'.($row["countComments"]).'</td>'; echo '<td class="sitename1edit2">'.($row["days"]).'</td>'; echo '<td class="sitename1edit2">'.($row["totalScore2"]).'</td>'; echo '</tr>'; } echo "</table>";

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  • 302 vs 301 redirect in this specific case

    - by Binder
    We have a website that displays information in a location based manner, i.e. it detects the IP of the visiting user and redirects him/her to an appropriate landing page; for e.g. a user coming from 'Egypt' will be redirected to http://www.mysite.com/egypt/cairo and a user visting from dubai will be redirected to http://www.mysite.com/uae/dubai, so on and so forth and we cater to multiple locations in the middle-east. Now, we have been advised by our SEO consultant that we should put a 301 (permanent redirect) on http://www.mysite.com to point to http://www.mysite.com/ksa/riyadh I would like to know the negative implications that this would have on Google indexing or otherwise, as I fundamentally disagree with this suggestion and believe that in a siutation like this a 302 redirect would be more appropriate.

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  • What is your favourite programming-related lolcat picture?

    - by DR
    In the spirit of these questions... http://stackoverflow.com/questions/234075/what-is-your-best-programmer-joke http://stackoverflow.com/questions/354686/programming-related-songs http://stackoverflow.com/questions/517897/anyone-know-any-programming-related-poetry ... I wonder: What is your favourite programming-related lolcat picture? Please add one answer per picture.

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  • Compact web server with Lua support?

    - by OverTheRainbow
    Hello, I need to find a very compact, cross-platform web server that can run Lua scripts, ie. either a regular web server like Mongoose that will forward queries to a Lua program in eg. FastCGI, or a web server itself written in Lua which will save the need to provide a separate web server. I recently started learning about Lua so am still in the dark about what is available out there, save for the three I came accross: Barracuda Embedded Web Server http://barracudaserver.com/ba/doc/ Xavante - Lua HTTP 1.1 Web server http://keplerproject.github.com/xavante/ Haserl http://haserl.sourceforge.net/ If someone's already done this recently, what solution would you recommend along with any tutorial/article that would get me started? Thank you.

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  • Href link with php value

    - by Aruna
    hi i am having a link like below <a href="#" onclick="window.open('http://www.twitter.com/home?status=Reading+Facebook share, Yahoo Buzz and Tweet this buttons for Blogger blogs+http://www.didiknow.com');">Tweet this</a> i want to insert a php variable value inside for the status thing like <a href="#" onclick="window.open('http://www.twitter.com/home?status=$markme_ddesc">Tweet this</a> how to do so?? please help me..

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  • How to catch non exist requested URL in Java servlet ?

    - by Frank
    My objects are stored online in two different places : <1 On my nmjava.com site, where I can put them in a directory called "Dir_My_App/Dir_ABC/" <2 On Google App Engine datastore When my Java app runs it checks both places for the objects, I designed the app so that it tries to get an object from a Url, it doesn't care whether it's an object in a directory or an object returned by a servlet. My_Object Get_Object(String Site_Url,String Object_Path) { ... get object by the name of Object_Path from the Site_Url ... } Now the request Url for my web site nmjava.com might look like this : http://nmjava.com/Dir_My_App/Dir_ABC/My_Obj_123 [ In a directory ] Or in the case of Google App Engine servlet : http://nm-java.appspot.com/Check_License/Dir_My_App/Dir_ABC/My_Obj_123 [ Non exist ] The "Object_Path" was generated by my app automatically. It can now get the object from my site by the above method like this : My_Object Get_Object("http://nmjava.com","/Dir_My_App/Dir_ABC/My_Obj_123"); In the Google App Engine, my servlet is running and ready to serve the object, if the request comes in correctly, but since I don't want to design my app to know whether the object is in one site's directory or in other site's datastore, I need to design the servlet to catch the non exist Url, such as the one above, and be able to make a call : My_Object Get_Object("http://nm-java.appspot.com/Check_License","/Dir_My_App/Dir_ABC/My_Obj_123"); So my question is : When a request comes into the servlet with a non exist Url, how should it catch it and analyze the url in order to respond properly, in my case it should know that : http://nm-java.appspot.com/Check_License/Dir_My_App/Dir_ABC/My_Obj_123 is asking for the object "My_Obj_123" [ ignore the dirs ] and return the object from the datastore. Now I'm getting this : Error: Not Found The requested URL /Check_License/Dir_My_App/Dir_ABC/My_Obj_123 was not found on this server. Where in my servlet and how do I detect the request for this non exist Url ?

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  • Python: find <title>

    - by Peter
    I have this: response = urllib2.urlopen(url) html = response.read() begin = html.find('<title>') end = html.find('</title>',begin) title = html[begin+len('<title>'):end].strip() if the url = http://www.google.com then the title have no problem as "Google", but if the url = "http://www.britishcouncil.org/learning-english-gateway" then the title become "<!doctype html public "-//W3C//DTD HTML 4.0 Transitional//EN"> <HTML> <HEAD> <base href="http://www.britishcouncil.org/" /> <META http-equiv="Content-Type" Content="text/html;charset=utf-8"> <meta name="WT.sp" content="Learning;Home Page Smart View" /> <meta name="WT.cg_n" content="Learn English Gateway" /> <META NAME="DCS.dcsuri" CONTENT="/learning-english-gateway.htm">..." What is actually happening, why I couldn't return the "title"?

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  • HTML5 audio with PHP script does not work on iPad/Iphone

    - by saulob
    Ok, I'm trying to play an HTML audio code on iPad but does not work. I created one PHP script to send to the MP3 request to the HTML5 audio code mp3_file_player.php?n=mp3file.mp3 The player is here: http://www.avault.com/news/podcast-news/john-romero-podcast-episode-80/ You will see that works on every HTML5 supported browser even on my iPod Touch. But does not work on iPad/iPhone, even on Safari on Mac OSX (I tried on Safari/Windows, worked fine) This is my PHP code: header("X-Powered-By: "); header("Accept-Ranges: bytes"); header("Content-Length: ". (string)(filesize($episode_filename)) .""); header("Content-type: audio/mpeg"); readfile($episode_filename); exit(); Everything works fine, the MP3 has the same headers like reading the mp3 directly. HTTP Headers from direct file access: (Status-Line) HTTP/1.1 200 OK Date Mon, 31 May 2010 20:27:31 GMT Server Apache/2.2.9 Last-Modified Wed, 26 May 2010 13:39:19 GMT Etag "dac0039-41d91f8-4877f669cefc0" Accept-Ranges bytes Content-Length 50656162 Content-Range bytes 18390614-69046775/69046776 Keep-Alive timeout=15, max=100 Connection Keep-Alive Content-Type audio/mpeg HTTP Header from my PHP script: (Status-Line) HTTP/1.1 200 OK Date Mon, 31 May 2010 20:27:08 GMT Server Apache/2.2.9 Accept-Ranges bytes Content-Length 69046776 Keep-Alive timeout=15, max=100 Connection Keep-Alive Content-Type audio/mpeg The only thing different it's the Content-Range, I even tried to add it, but if I use it the player will not work on my Ipod Touch. So I removed. Thank you very much.

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  • Regular Expression problem

    - by Yatendra Goel
    I want a regex to find the following types of strings: http://anything.abc.tld http://anything.abc.tld/ where abc - abc always remains abc anything - it could be any string tld - it could be any tld (top-level-domain) like .com .net .co.in .co.uk etc. Note: The url must not contain any other thing at the end, means http://anything.abc.tld/xyz is not acceptable.

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  • How to login with python and save cookie, then use that info to view page for member only

    - by patcsong
    I am quite new in python and trying to write a script to login to the page at http://ryushare.com/login.python. I have try many attempt, but it fails to login and i have no idea why. After login to the page, I wish to get the return of http://ryushare.com/file-manager.python Here's the code I try to attempt by reading the example from others. import urllib, urllib2, cookielib username = 'myusername' password = 'mypassword' cj = cookielib.CookieJar() opener = urllib2.build_opener(urllib2.HTTPCookieProcessor(cj)) login_data = urllib.urlencode({'login' : username, 'password' : password}) opener.open('http://www.ryushare.com/login.python', login_data) resp = opener.open('http://ryushare.com/file-manager.python') print resp.read() I check the source code of the login page, it said the username and password value is "login and password" so i change it. I have try some other example which can be found here like google news feed, It also can not able to login : (

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  • SpringBatch Jaxb2Marshaller: different name of class and xml attribute

    - by user588961
    I try to read an xml file as input for spring batch: Java Class: package de.example.schema.processes.standardprocess; @XmlAccessorType(XmlAccessType.FIELD) @XmlType(name = "Process", namespace = "http://schema.example.de/processes/process", propOrder = { "input" }) public class Process implements Serializable { @XmlElement(namespace = "http://schema.example.de/processes/process") protected ProcessInput input; public ProcessInput getInput() { return input; } public void setInput(ProcessInput value) { this.input = value; } } SpringBatch dev-job.xml: <bean id="exampleReader" class="org.springframework.batch.item.xml.StaxEventItemReader" scope="step"> <property name="fragmentRootElementName" value="input" /> <property name="resource" value="file:#{jobParameters['dateiname']}" /> <property name="unmarshaller" ref="jaxb2Marshaller" /> </bean> <bean id="jaxb2Marshaller" class="org.springframework.oxm.jaxb.Jaxb2Marshaller"> <property name="classesToBeBound"> <list> <value>de.example.schema.processes.standardprocess.Process</value> <value>de.example.schema.processes.standardprocess.ProcessInput</value> ... </list> </property> </bean> Input file: <?xml version="1.0" encoding="UTF-8"?> <process:process xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:process="http://schema.example.de/processes/process"> <process:input> ... </process:input> </process:process> It fires the following exception: [javax.xml.bind.UnmarshalException: unexpected element (uri:"http://schema.example.de/processes/process", local:"input"). Expected elements are <<{http://schema.example.de/processes/process}processInput] at org.springframework.oxm.jaxb.JaxbUtils.convertJaxbException(JaxbUtils.java:92) at org.springframework.oxm.jaxb.AbstractJaxbMarshaller.convertJaxbException(AbstractJaxbMarshaller.java:143) at org.springframework.oxm.jaxb.Jaxb2Marshaller.unmarshal(Jaxb2Marshaller.java:428) If I change to in xml it work's fine. Unfortunately I can change neither the xml nor the java class. Is there a possibility to make Jaxb2Marshaller map the element 'input' to the class 'ProcessInput'?

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  • How can i fetch the large image from url

    - by Kutbi
    i used below code to fetch the image from url.but its not working for large image.. i missing something to add for that type of image to fetch. imgView = (ImageView)findViewById(R.id.ImageView01); imgView.setImageBitmap(loadBitmap("http://www.360technosoft.com/mx4.jpg")); //imgView.setImageBitmap(loadBitmap("http://sugardaddydiaries.com/wp-content/uploads/2010/12/how_do_i_get_sugar_daddy.jpg")); //setImageDrawable("http://sugardaddydiaries.com/wp-content/uploads/2010/12/holding-money-copy.jpg"); //Drawable drawable = LoadImageFromWebOperations("http://www.androidpeople.com/wp-content/uploads/2010/03/android.png"); //imgView.setImageDrawable(drawable); /* try { ImageView i = (ImageView)findViewById(R.id.ImageView01); Bitmap bitmap = BitmapFactory.decodeStream((InputStream)new URL("http://sugardaddydiaries.com/wp-content/uploads/2010/12/holding-money-copy.jpg").getContent()); i.setImageBitmap(bitmap); } catch (MalformedURLException e) { System.out.println("hello"); } catch (IOException e) { System.out.println("hello"); }*/ } protected Drawable ImageOperations(Context context, String string, String string2) { // TODO Auto-generated method stub try { InputStream is = (InputStream) this.fetch(string); Drawable d = Drawable.createFromStream(is, "src"); return d; } catch (MalformedURLException e) { e.printStackTrace(); return null; } catch (IOException e) { e.printStackTrace(); return null; } }

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  • making hyperlink

    - by Nikhil K
    I have an arraylist (eg: h1) contain some urls. eg: http://www.google.com,http://www.yahoo.com,http://www.xyz.com,..... How can i put hyperlinks to each elements in that arraylist in c# ? Means by clicking on that url it should navigate to corresponding website.Can you give an example?? Also, how can i use 'Hyperlink' keyword in c# ?

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  • ListView is Widget(View) or Layout(Viewgroup)?

    - by Manoj Maurya
    Hi All, I need your help to explore few topics in Android. My understanding is Widget is View and Layout is ViewGroups in Android. I described the problems as below- Please go through the below links- developer.android.com/guide/topics/ui/custom-components.html- (add http:// in the beginning) developer.android.com/resources/tutorials/views/index.html - (add http:// in the beginning) In the first link ListView is included as Widget and in the Second link ListView has been shown as Layout. So, is ListView is Widget(View) or Layout(Viewgroup)? Same is the case for Spinner in Andriod developer.android.com/resources/tutorials/views/hello-spinner.html- (add http:// in the beginning) (Link- says Spinner is Widget(View)) developer.android.com/guide/topics/ui/layout-objects.html- (add http:// in the beginning) says Spinner is Layout(ViewGroup) So, Spinner is View or ViewGroup? Please update me with your views?

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  • How does 37signals job preview functionality work?

    - by slythic
    Hi all, I'm interested in getting a preview functionality working similar to how the 37signals job site does: http://jobs.37signals.com. Below are some screen shots of how it works. Step 1. Create your ad http://cl.ly/dfc4761b015c7f43c8ab (URL /jobs/new) Step 2. Preview your ad http://cl.ly/9c4b4041cfea83d8569e (URL /jobs/new/preview) Step 3. Publish your ad http://cl.ly/a58284d90fd380d2c26b (URL /listings/new/purchase?token=5198) So assuming you have Post model where Step 1 usually takes place in the new/create view/actions, how should one continue to Step 2 Preview and then after previewing, proceeding to the Step 3 publishing the post/ad? Do they actually save the ad/post in the database before continuing to Step 2 (Preview) but set a flag (like a boolean field called preview set to true)? It looks like they set a token paramater but I'm not sure what it's used for) I'm interested in this because it seems to go against the CRUD/REST and I thought it would be good to know how it worked. Thanks!

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  • method is not called from xhtml

    - by Amlan Karmakar
    Whenever I am clicking the h:commandButton,the method associated with the action is not called.action="${statusBean.update}" is not working, the update is not being called. 1) Here is my xhtml page <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml" xmlns:ui="http://java.sun.com/jsf/facelets" xmlns:h="http://java.sun.com/jsf/html" xmlns:f="http://java.sun.com/jsf/core" xmlns:p="http://primefaces.org/ui"> <h:head></h:head> <h:body> <h:form > <p:dataList value="#{statusBean.statusList}" var="p"> <h:outputText value="#{p.statusId}-#{p.statusmsg}"/><br/> <p:inputText value="#{statusBean.comment.comment}"/> <h:commandButton value="comment" action="${statusBean.update}"></h:commandButton> </p:dataList> </h:form> </h:body> </html> 2)Here is my statusBean package com.bean; import java.util.List; import javax.faces.context.FacesContext; import javax.persistence.EntityManager; import javax.persistence.EntityManagerFactory; import javax.persistence.Persistence; import javax.persistence.Query; import javax.servlet.http.HttpSession; import com.entity.Album; import com.entity.Comment; import com.entity.Status; import com.entity.User; public class StatusBean { Comment comment; Status status; private EntityManager em; public Comment getComment() { return comment; } public void setComment(Comment comment) { this.comment = comment; } public Status getStatus() { return status; } public void setStatus(Status status) { this.status = status; } public StatusBean(){ comment = new Comment(); status=new Status(); EntityManagerFactory emf=Persistence.createEntityManagerFactory("FreeBird"); em =emf.createEntityManager(); } public String save(){ FacesContext context = FacesContext.getCurrentInstance(); HttpSession session = (HttpSession) context.getExternalContext().getSession(true); User user = (User) session.getAttribute("userdet"); status.setEmail(user.getEmail()); System.out.println("status save called"); em.getTransaction().begin(); em.persist(status); em.getTransaction().commit(); return "success"; } public List<Status> getStatusList(){ FacesContext context = FacesContext.getCurrentInstance(); HttpSession session = (HttpSession) context.getExternalContext().getSession(true); User user=(User) session.getAttribute("userdet"); Query query = em.createQuery("SELECT s FROM Status s WHERE s.email='"+user.getEmail()+"'", Status.class); List<Status> results =query.getResultList(); return results; } public String update(){ System.out.println("Update Called..."); //comment.setStatusId(Integer.parseInt(statusId)); em.getTransaction().begin(); em.persist(comment); em.getTransaction().commit(); return "success"; } }

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  • How to read remote video on Amazon S3 using ffmpeg

    - by virtualize
    I need to create poster frames from videos hosted on Amazon S3 via ffmpeg. So is there a way to use the remote video file directly in ffmpeg command line like this: ffmpeg -i "http://bucket.s3.amazonaws.com/video.mp4" -ss 00:00:10 -vframes 1 -f image2 "image%03d.jpg" ffmpeg just returns: http://bucket.s3.amazonaws.com/video.mp4: I/O error occurred Usually that means that input file is truncated and/or corrupted. I also tried forcing ffmpeg to use the videos mp4 container for reading: ffmpeg -f mp4 -i "http://bucket.s3.amazonaws.com/video.mp4" ... But no luck. Wget this video from S3 and processing it locally works fine of course, as well as reading the file remotely from other 'standard' http servers. So I know that ffmpeg supports remote file reading, but why not on S3?

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  • xsl:for-each not supported in this context

    - by alexbf
    Hi! I have this XSLT document : <xsl:stylesheet version="1.0" xmlns:mstns="http://www.w3.org/2001/XMLSchema" xmlns="http://www.w3.org/2001/XMLSchema" xmlns:xs="http://www.w3.org/2001/XMLSchema" xmlns:msdata="urn:schemas-microsoft-com:xml-msdata" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"> <xsl:output method="xml" version="1.0" encoding="UTF-8" indent="yes"/> <xsl:template match="/MyDocRootElement"> <xs:schema id="DataSet" targetNamespace="http://www.w3.org/2001/XMLSchema" attributeFormDefault="qualified" elementFormDefault="qualified" > <xs:element name="DataSet" msdata:IsDataSet="true"> <xs:complexType> <xs:choice maxOccurs="unbounded"> <xs:element name="Somename"> </xs:element> <xs:element name="OtherName"> </xs:element> <!-- FOR EACH NOT SUPPORTED? --> <xsl:for-each select="OtherElements/SubElement"> <xs:element name="OtherName"> </xs:element> </xsl:for-each> </xs:choice> </xs:complexType> </xs:element> </xs:schema> </xsl:template> </xsl:stylesheet> I have a validation error saying that the "for-each element is not supported in this context" I am guessing it has something to do with the xs namespace validation. Any ideas on how can I make this work? (Exclude validation?) Thanks Alex

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  • Is the google docs embeddable previewer out of beta and will it have an have an API?

    - by Jonathan Hendler
    https://docs.google.com/viewer is awesome, but there are some customizations I need to make, and documentation would be helpful. Discovered here http://googlesystem.blogspot.com... . Haven't seen any public documentation that would help. http://code.google.com/apis/documents/overview.html covers the Google docs - where the above is more a clone of the Google Books previewer http://books.google.com/books .

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  • WCF SERVICE gives us faulted response

    - by malik
    My service is hosted on IIS7, windows 2008 server with sql server2008 express. I am getting following error when the process takes more than 2 minutes i got this response, i m unable to find out either it is due to sql server time out or wcf time out. my sql server process is also took long. An error occurred while receiving the HTTP response to http://REMOTE/SynchronizationService_test/SyncService.svc. This could be due to the service endpoint binding not using the HTTP protocol. This could also be due to an HTTP request context being aborted by the server (possibly due to the service shutting down). See server logs for more details.

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  • Can no longer debug ActiveX controls in Visual Studio 2008

    - by Phenglei Kai
    For a long time I would throw up a DebugBreak() or ASSERT(false) in the startup code of my ActiveX control, load up IE, go to a localhost page hosting my control, wait for the dialog to show up, then debug my application. I could also launch it under the debugger by setting IE as the container. I tried again for the first time in 2 months and now this no longer works. If I use the ASSERT(false) method, when I get the Visual C++ Debug dialog and click "retry", IE simply closes without any debugger activity. When I try launching from VS2008 and hoping the DebugBreak() will kick in after I load the page, VS2008 does break, but it says either the "RPC Server is Unavailable" or the "RPC Client Call failed." I am never allowed to have my application in the debugger and it doesn't show up in the modules list of VS. The stack trace in VS2008 only contains Microsoft DLLs and modules and not a hint of my code. I assume it's something I've picked up through Windows Update that broke this. Has anyone else ever seen this issue and know how to make it go away? As it stands, I'm now completely unable to debug my ActiveX control.

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