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• Deleting first and last element of a linked list in C

  - by LuckySlevin

  struct person { int age; char name[100]; struct person *next; }; void delfirst(struct person **p)// For deleting the beginning { struct person *tmp,*m; m = (*p); tmp = (*p)->next; free(m); return; } void delend(struct person **p)// For deleting the end { struct person *tmp,*m; tmp=*p; while(tmp->next!=NULL) { tmp=tmp->next; } m->next=tmp; free(tmp); m->next = NULL; return; } I'm looking for two seperate functions to delete the first and last elements of a linked list. Here is what i tried. What do you suggest? Especially deleting first is so problematic for me.

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• Cleaner method for list comprehension clean-up

  - by Dan McGrath

  This relates to my previous question: Converting from nested lists to a delimited string I have an external service that sends data to us in a delimited string format. It is lists of items, up to 3 levels deep. Level 1 is delimited by '|'. Level 2 is delimited by ';' and level 3 is delimited by ','. Each level or element can have 0 or more items. An simplified example is: a,b;c,d|e||f,g|h;; We have a function that converts this to nested lists which is how it is manipulated in Python. def dyn_to_lists(dyn): return [[[c for c in b.split(',')] for b in a.split(';')] for a in dyn.split('|')] For the example above, this function results in the following: >>> dyn = "a,b;c,d|e||f,g|h;;" >>> print (dyn_to_lists(dyn)) [[['a', 'b'], ['c', 'd']], [['e']], [['']], [['f', 'g']], [['h'], [''], ['']]] For lists, at any level, with only one item, we want it as a scalar rather than a 1 item list. For lists that are empty, we want them as just an empty string. I've came up with this function, which does work: def dyn_to_min_lists(dyn): def compress(x): return "" if len(x) == 0 else x if len(x) != 1 else x[0] return compress([compress([compress([item for item in mv.split(',')]) for mv in attr.split(';')]) for attr in dyn.split('|')]) Using this function and using the example above, it returns: [[['a', 'b'], ['c', 'd']], 'e', '', ['f', 'g'], ['h', '', '']] Being new to Python, I'm not confident this is the best way to do it. Are there any cleaner ways to handle this? This will potentially have large amounts of data passing through it, are there any more efficient/scalable ways to achieve this?

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• Python - creating a list with 2 characteristics bug

  - by user2733911

  The goal is to create a list of 99 elements. All elements must be 1s or 0s. The first element must be a 1. There must be 7 1s in total. import random import math import time # constants determined through testing generation_constant = 0.96 def generate_candidate(): coin_vector = [] coin_vector.append(1) for i in range(0, 99): random_value = random.random() if (random_value > generation_constant): coin_vector.append(1) else: coin_vector.append(0) return coin_vector def validate_candidate(vector): vector_sum = sum(vector) sum_test = False if (vector_sum == 7): sum_test = True first_slot = vector[0] first_test = False if (first_slot == 1): first_test = True return (sum_test and first_test) vector1 = generate_candidate() while (validate_candidate(vector1) == False): vector1 = generate_candidate() print vector1, sum(vector1), validate_candidate(vector1) Most of the time, the output is correct, saying something like [1, 0, 0, 0, 0, 0, 0, 0, 1, 0, 0, 0, 0, 0, 1, 0, 0, 1, 0, 1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 0, 0, 0] 7 True but sometimes, the output is: [0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0] 2 False What exactly am I doing wrong?

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• Eclipse making background video skip with almost every click of the mouse

  - by RustyH

  The problem is i like to listen to videos online (mostly or all flash video) while programming and never had any problems until i started using eclipse, now every time i do just about anything other than type, it makes the video skip/freeze really bad and is really annoying. I have never had this happen using visual studio, netbeans, or adobe flash for that matter, unless i was compiling or doing something that hogs the processor. Are there any settings that might could fix this its getting really annoying. it happens almost every time i even click "find" on the find pop-up window and it is not like it is having to search a big file or anything it is only 700 lines, with honestly only about 1/2 that have content on them. Any ideas?

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• How to skip words in OS X terminal?

  - by Yuval

  Say I wrote a long command in the Mac OSX terminal, i.e say "Hello, how are you? I am good thank you. How is it going with you? Fine, thanks" and now I decided I want to change the word Hello to Hi. To do that, right now I have to keep pressing (or hold down) the left keyboard key until the "cursor" gets to the end of the word Hello, and then delete it. The usual 'holding down option' technique doesn't work as it does in most other OS X applications. Is there a way to skip a word at a time instead (or any other shorter way of getting the cursor there)? Thanks!

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• Is it possible to skip .rvmrc confirmation?

  - by Viacheslav Molokov

  We are using RVM for managing Ruby installations and environments. Usually we are using this .rvmrc script: #!/bin/bash if [ ! -e '.version' ]; then VERSION=`pwd | sed 's/[a-z/-]//g'` echo $VERSION > .version rvm gemset create $VERSION fi VERSION=`cat .version` rvm use 1.9.2@$VERSION This script forces RVM to create new gem environment for each our project/version. But each time we was deploying new version RVM asks us to confirm new .rvmrc file. When we cd to this directory first time, we are getting something like: =============================================================== = NOTICE: = =============================================================== = RVM has encountered a not yet trusted .rvmrc file in the = = current working directory which may contain nasty code. = = = = Examine the contents of this file to be sure the contents = = are good before trusting it! = = = = Press 'q' to exit the reader when finished reading the file = =============================================================== (press enter to continue when ready) This is not as bad for development environments, but with auto deploy it require to manually confirm each new version on each server. Is it possible to skip this confirmation?

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• Can Robocopy be made to skip open files?

  - by domspurling

  We are using Robocopy to redistribute files which arrive via FTP in a drop folder. Ideally we want Robocopy to leave files alone if they are still being FTPd. Having tried various switches, Robocopy still copies the open files. It doesn't delete them, so the FTP continues unaffected. However, we end up with truncated files being distributed to their destination. Can Robocopy be made to skip open files? Perhaps there is something more suitable than Robocopy for this task?

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• print a linear linked list into a table

  - by user1796970

  I am attempting to print some values i have stored into a LLL into a readable table. The data i have stored is the following : DEBBIE STARR F 3 W 1000.00 JOAN JACOBUS F 9 W 925.00 DAVID RENN M 3 H 4.75 ALBERT CAHANA M 3 H 18.75 DOUGLAS SHEER M 5 W 250.00 SHARI BUCHMAN F 9 W 325.00 SARA JONES F 1 H 7.50 RICKY MOFSEN M 6 H 12.50 JEAN BRENNAN F 6 H 5.40 JAMIE MICHAELS F 8 W 150.00 i have stored each firstname, lastname, gender, tenure, payrate, and salary into their own List. And would like to be able to print them out in the same format that they are viewed on the text file i read them in from. i have messed around with a few methods that allow me to traverse and print the Lists, but i end up with ugly output. . . here is my code for the storage of the text file and the format i would like to print out: public class Payroll { private LineWriter lw; private ObjectList output; ListNode input; private ObjectList firstname, lastname, gender, tenure, rate, salary; public Payroll(LineWriter lw) { this.lw = lw; this.firstname = new ObjectList(); this.lastname = new ObjectList(); this.gender = new ObjectList(); this.tenure = new ObjectList(); this.rate = new ObjectList(); this.salary = new ObjectList(); this.output = new ObjectList(); this.input = new ListNode(); } public void readfile() { File file = new File("payfile.txt"); try{ Scanner scanner = new Scanner(file); while(scanner.hasNextLine()) { String line = scanner.nextLine(); Scanner lineScanner = new Scanner(line); lineScanner.useDelimiter("\\s+"); while(lineScanner.hasNext()) { firstname.insert1(lineScanner.next()); lastname.insert1(lineScanner.next()); gender.insert1(lineScanner.next()); tenure.insert1(lineScanner.next()); rate.insert1(lineScanner.next()); salary.insert1(lineScanner.next()); } } }catch(FileNotFoundException e) {e.printStackTrace();} } public void printer(LineWriter lw) { String msg = " FirstName " + " LastName " + " Gender " + " Tenure " + " Pay Rate " + " Salary "; output.insert1(msg); System.out.println(output.getFirst()); System.out.println(" " + firstname.getFirst() + " " + lastname.getFirst() + "\t" + gender.getFirst() + "\t" + tenure.getFirst() + "\t" + rate.getFirst() + "\t" + salary.getFirst()); } }

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• WPF, C# - Making Intellisense/Autocomplete list, fastest way to filter list of strings

  - by user559548

  Hello everyone, I'm writing an Intellisense/Autocomplete like the one you find in Visual Studio. It's all fine up until when the list contains probably 2000+ items. I'm using a simple LINQ statement for doing the filtering: var filterCollection = from s in listCollection where s.FilterValue.IndexOf(currentWord, StringComparison.OrdinalIgnoreCase) >= 0 orderby s.FilterValue select s; I then assign this collection to a WPF Listbox's ItemSource, and that's the end of it, works fine. Noting that, the Listbox is also virtualised as well, so there will only be at most 7-8 visual elements in memory and in the visual tree. However the caveat right now is that, when the user types extremely fast in the richtextbox, and on every key up I execute the filtering + binding, there's this semi-race condition, or out of sync filtering, like the first key stroke's filtering could still be doing it's filtering or binding work, while the fourth key stroke is also doing the same. I know I could put in a delay before applying the filter, but I'm trying to achieve a seamless filtering much like the one in Visual Studio. I'm not sure where my problem exactly lies, so I'm also attributing it to IndexOf's string operation, or perhaps my list of string's could be optimised in some kind of index, that could speed up searching. Any suggestions of code samples are much welcomed. Thanks.

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• Double Linked List Insertion Sorting Bug

  - by house

  Hello, I have implemented an insertion sort in a double link list (highest to lowest) from a file of 10,000 ints, and output to file in reverse order. To my knowledge I have implemented such a program, however I noticed in the ouput file, a single number is out of place. Every other number is in correct order. The number out of place is a repeated number, but the other repeats of this number are in correct order. Its just strange how this number is incorrectly placed. Also the unsorted number is only 6 places out of sync. I have looked through my program for days now with no idea where the problem lies, so I turn to you for help. Below is the code in question, (side note: can my question be deleted by myself? rather my colleges dont thieve my code, if not how can it be deleted?) void DLLIntStorage::insertBefore(int inValue, node *nodeB) { node *newNode; newNode = new node(); newNode->prev = nodeB->prev; newNode->next = nodeB; newNode->value = inValue; if(nodeB->prev==NULL) { this->front = newNode; } else { nodeB->prev->next = newNode; } nodeB->prev = newNode; } void DLLIntStorage::insertAfter(int inValue, node *nodeB) { node *newNode; newNode = new node(); newNode->next = nodeB->next; newNode->prev = nodeB; newNode->value = inValue; if(nodeB->next == NULL) { this->back = newNode; } else { nodeB->next->prev = newNode; } nodeB->next = newNode; } void DLLIntStorage::insertFront(int inValue) { node *newNode; if(this->front == NULL) { newNode = new node(); this->front = newNode; this->back = newNode; newNode->prev = NULL; newNode->next = NULL; newNode->value = inValue; } else { insertBefore(inValue, this->front); } } void DLLIntStorage::insertBack(int inValue) { if(this->back == NULL) { insertFront(inValue); } else { insertAfter(inValue, this->back); } } ifstream& operator>> (ifstream &in, DLLIntStorage &obj) { int readInt, counter = 0; while(!in.eof()) { if(counter==dataLength) //stops at 10,000 { break; } in >> readInt; if(obj.front != NULL ) { obj.insertion(readInt); } else { obj.insertBack(readInt); } counter++; } return in; } void DLLIntStorage::insertion(int inValue) { node* temp; temp = this->front; if(temp->value >= inValue) { insertFront(inValue); return; } else { while(temp->next!=NULL && temp!=this->back) { if(temp->value >= inValue) { insertBefore(inValue, temp); return; } temp = temp->next; } } if(temp == this->back) { insertBack(inValue); } } Thankyou for your time.

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• Linked list in C

  - by ScReYm0

  I am still new at lists in C and i got a big problem... First i wanna show you my code for inserting item to the list: void input_books_info(int number_of_books, BOOK *current) { int i; for(i = 0; i < number_of_books; i++) { while(current->next != NULL) current = current->next; current->next = (BOOK *)malloc(sizeof(BOOK)); printf_s("%d book catalog number: ", i + 1); scanf_s("%s", &current->next->catalog_number , 20); printf_s("%d book title: ", i + 1); scanf_s("%s", current->next->title ,80); printf_s("%d book author: ", i + 1); scanf_s("%s", current->next->author ,40); printf_s("%d book publisher: ", i+1); scanf_s("%s", current->next->publisher,80); printf_s("%d book price: ", i + 1); scanf_s("%f", &current->next->price, 5); printf_s("%d book year published: ", i + 1); scanf_s("%d", &current->next->year_published, 5); current->next->next = NULL; printf_s("\n\n"); } } And this is my main function: void main (void) { int number_of_books, t = 1; char book_catalog_number[STRMAX]; char book_title[STRMAX]; char book_author[STRMAX]; char reading_file[STRMAX]; char saving_file[STRMAX]; first = malloc(sizeof(BOOK)); first->next = NULL; /* printf_s("Enter file name: "); gets(saving_file); first->next = book_open(first, saving_file); */ while(t) { char m; printf_s("1. Input \n0. Exit \n\n"); printf_s("Choose operation: "); m = getch(); switch(m) { case '1': printf_s("\ninput number of books: "); scanf_s("%d", &number_of_books); input_books_info(number_of_books, first); printf_s("\n"); break; default: printf_s("\nNo entry found!\n\n\n\n\n"); break; } } } and last maybe here is the problem the printing function: void print_books_info(BOOK *current) { while(current->next != NULL && current != NULL) { printf_s("%s, ", current->next->catalog_number); printf_s("%s, ", current->author); printf_s("%s, ", current->next->title); printf_s("%s, ", current->next->author); printf_s("%s, ", current->next->publisher); printf_s("%.2f, ", current->next->price); printf_s("%d", current->next->year_published); printf_s("\n\n"); current = current->next; } } And my problem is that, when i run the app, program is moving good. But when I start the app, the program is storing only first input of data second and third are lost ... Can you help me to figure out it... ???

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• Unable to add separator in list view

  - by Suru

  This is my code @Override protected void onCreate(Bundle savedInstanceState) { super.onCreate(savedInstanceState); setContentView(R.layout.email_list_main); emailResults = new ArrayList<GetEmailFromDatabase>(); //int[] colors = {0,0xFFFF0000,0}; //getListView().setDivider(new GradientDrawable(Orientation.RIGHT_LEFT, colors)); //getListView().setDividerHeight(2); emailListFeedAdapter = new EmailListFeedAdapter(this, R.layout.email_listview_row, emailResults); setListAdapter(this.emailListFeedAdapter); getResults(); if(emailResults != null && emailResults.size() > -1){ emailListFeedAdapter.notifyDataSetChanged(); for(int i=0;i< emailResults.size();i++){ try { Here I getting email Sent date emailListFeedAdapter.add( emailResults.get(i)); datetime_text1 = emailResults.get(i).getDate(); formatter1 = new SimpleDateFormat(); formatter1 = DateFormat.getDateInstance((DateFormat.MEDIUM)); Calendar currentDate1 = Calendar.getInstance(); Item_Date1 = formatter1.parse(datetime_text1); current_Date1 = formatter1.format(currentDate1.getTime()); current_System_Date1 = formatter1.parse(current_Date1); currentDate1.add(Calendar.DATE, -1); yesterdaydate = formatter1.format(currentDate1.getTime()); yeaterday_Date = formatter1.parse(yesterdaydate); currentDate1.add(Calendar.DATE, -2); threeDaysback = formatter1.format(currentDate1.getTime()); Three_Days_Back = formatter1.parse(threeDaysback); Here I am comparing current date with list view item date, and here is my problem, dates are matching but it is not entering in if condition I tried in so many ways but nothing worked the code for separator is bellow. if(Item_Date.compareTo(current_System_Date)==0){ if(index1){ emailListFeedAdapter.addSeparatorItem("SEPARATOR"); //i--; index1=false; } } else if(yeaterday_Date.compareTo(Item_Date1)==0){ if(index2){ emailListFeedAdapter.addSeparatorItem("SEPARATOR"); //i--; index2 = false; } } else if(Item_Date1.compareTo(Three_Days_Back)==0){ if(index3){ emailListFeedAdapter.addSeparatorItem("SEPARATOR"); //i--; index3 = false; } } } catch (ParseException e) { // TODO Auto-generated catch block e.printStackTrace(); } } } } In EmailListFeedAdapter private TreeSet<Integer> mSeparatorsSet = new TreeSet<Integer>(); public void addSeparatorItem(final String item) { //itemss.add(emailResults.get(0)); // save separator position mSeparatorsSet.add(itemss.size() - 1); notifyDataSetChanged(); } @Override public int getItemViewType(int position) { return mSeparatorsSet.contains(position) ? TYPE_SEPARATOR : TYPE_ITEM; } holder = new ViewHolder(); switch (type) { case TYPE_ITEM: emailView= inflater.inflate(R.layout.email_listview_row, null); break; case TYPE_SEPARATOR: emailView= inflater.inflate(R.layout.item2, null); holder.textView = (TextView)emailView.findViewById(R.id.textSeparator); emailView.setTag(holder); holder.textView.setText("SEPARATOR"); break; } Here is ViewHolder class public static class ViewHolder { public TextView textView; } if anybody knows then please tell me where I am doing wrong. Thanx

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• Restart list numbering in word for each new list created

  - by Feena

  Hi, I am exporting content from a jsp page into MS Word using javascript. When the user is in Word there is a table with 10 rows and 2 columns, A & B. The user creates an ordered list in row 1, column A like this: 1 dog 2 cat 3 mouse if the user then creates a second list in row 1 column B is turns out like this: 4 car 5 truck 6 bike instead of: 1 car 2 truck 3 bike Word is set up to continue the numbering in lists from prior lists automatically. I know this can be reset easily but the users dont want to have to do this. They want the numbering of any potential lists created to restarted at 1. when the document is exported into Word and opened in front of them. So this must be set up in the javasctipt code or using a style or something prior to getting into Word. This is what I dont know how to do. Any help is much appreciated. Thanks, Feena.

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• Django: getting the list of related records for a list of objects

  - by Silver Light

  Hello! I have two models related one-to many: class Person(models.Model): name = models.CharField(max_length=255); surname = models.CharField(max_length=255); age = models.IntegerField(); class Dog(models.Model): name = models.CharField(max_length=255); owner = models.ForeignKey('Person'); I want to output a list of persons below each person a list of dogs he has. Here's how I can do it: in view: persons = Person.objects.all()[0:100]; in template: {% for p in persons %} {{ p.name }} has dogs:<br /> {% for d in persons.dog_set.all %} - {{ d.name }}<br /> {% endfor %} {% endfor %} But if I do it like that, Django will execute 101 SQL queries which is very inefficient. I tried to make a custom manager, which will get all the persons, then all the dogs and links them in python, but then I can't use paginator (my another question: http://stackoverflow.com/questions/2532475/django-paginator-raw-sql-query ) and it looks quite ugly. Is there a more graceful way doing this?

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• Trying to get these list items to display inline

  - by Joel

  I have several unordered lists that I want to display like this: <ul> <li><img></li> <li><p></li> //inline </ul> //linebreak <ul> <li><img></li> <li><p></li> //inline </ul> ...etc I'm not able to get the li items to be inline with eachother. They are stacking vertically. I have stripped away most styling but still can't figure out what I'm doing wrong: html: <ul class="instrument"> <li class="imagebox"><img src="/images/matepe.jpg" width="247" height="228" alt="Matepe" /></li> <li class="textbox"><p>The matepe is a 24 key instrument that is played by the Kore-Kore people in North-Eastern Zimbabwe and Mozambique. It utilizes four fingers-each playing an individual melody. These melodies also interwieve to create resultant melodies that can be manipulated thru accenting different fingers. The matepe is used in Rattletree as the bridge from the physical world to the spirit world. The matepe is used in the Kore-Kore culture to summon the Mhondoro spirits which are thought to be able to communicate directly with Mwari (God) without the need of an intermediary.</p></li> </ul> <ul class="instrument"> <li class="imagebox"><img src="/images/soprano_little.jpg" border="0" width="247" height="170" alt="Soprano" /></li> <li class="textbox"><p>The highest voice of the Rattletree Marimba orchestra is the Soprano marimba. The soprano is used to whip up the energy on the dancefloor and help people reach ecstatic state with it's high and clear singing voice. The range of these sopranos goes much lower than 'typical' Zimbabwean style sopranos. The sopranos play the range of the right hand of the matepe and go two notes higher and five notes lower. Rattletree uses two sopranos.</p></li> </ul> <ul class="instrument"> <li class="imagebox"><img src="/images/bari_little.jpg" border="0" width="247" height="170" alt="Baritone" /></li> <li class="textbox"><p>The Baritone is the next lower voice in the orchestra. The bari is where the funk is. Generally bubbling over the Bass line, the baritone creates the syncopations and polyrhythms that messes with the 'minds' of the dancers and helps seperate the listener from the physical realm of thought. The range of the baritone covers the full range of the left hand side of the matepe.</p></li> </ul> <ul class="instrument"> <li class="imagebox"><img src="/images/darren_littlebass.jpg" border="0" width="247" height="195" alt="Bass"/><strong>Bass Marimba</strong></li> <li class="textbox"><p>The towering Bass Marimba is the foundation of the Rattletree Marimba sound. Putting out frequencies as low as 22hZ, the bass creates the drive that gets the dancefloor moving. It is 5.5' tall, 9' long, and 4' deep. It is played by standing on a platform and struck with mallets that have lacross-ball size heads (they are actually made with rubber dog balls). The Bass marimba's range covers the lowest five notes of the matepe and goes another five notes lower.</p></li> </ul> <ul class="instrument"> <li class="imagebox"><img src="/images/wayne_little.jpg" border="0" width="247" height="177" alt="Drums"/><strong>Drumset</strong></li> <li class="textbox"><p>All the intricate polyrhythms are held together tastefully with the drumset. The drums provides the consistancy and grounding that the dancers need to keep going all night. While the steady kick and high-hat provide that grounding function, the toms and snare and allowed to be another voice in the poylrhythmic texture-helping the dancers abandon the concept of a "one" within this cyclical music.</p></li> </ul> css: ul.instrument { text-align:left; display:inline; } ul.instrument li { list-style-type: none; } li.imagebox { } li.textbox { } li.textbox p{ width: 247px; }

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• Link List Implementation Help - Visual C++

  - by Greenhouse Gases

  Hi there I'm trying to implement a link list which stores the city name (though you will see this commented out as I need to resolve the issue of not being able to use string and needing to use a primitive data type instead during the declaration), longitude, latitude and of course a pointer to the next node in the chain. I am new to the Visual C++ environment and my brain is somewhat scrambled after coding for several straight hours today so I wondered if anyone could help resolve the 2 errors I am getting (ignore the #include syntax as I had to change them to avoid the browser interpreting html!): 1U08221.obj : error LNK2028: unresolved token (0A000298) "public: __thiscall Locations::Locations(void)" (??0Locations@@$$FQAE@XZ) referenced in function "int __clrcall main(cli::array^)" (?main@@$$HYMHP$01AP$AAVString@System@@@Z) 1U08221.obj : error LNK2019: unresolved external symbol "public: __thiscall Locations::Locations(void)" (??0Locations@@$$FQAE@XZ) referenced in function "int __clrcall main(cli::array^)" (?main@@$$HYMHP$01AP$AAVString@System@@@Z) The code for my header file is here: include string struct locationNode { //char[10] nodeCityName; double nodeLati; double nodeLongi; locationNode* Next; }; class Locations { private: int size; public: Locations(); // constructor for the class locationNode* Head; int Add(locationNode* Item); }; and here is the code for the file containing the main method: // U08221.cpp : main project file. include "stdafx.h" include "Locations.h" include iostream include string using namespace std; int n = 0; int x; string cityNameInput; bool acceptedInput = false; int Locations::Add(locationNode *NewItem) { locationNode *Sample = new locationNode; Sample = NewItem; Sample-Next = Head; Head = Sample; return size++; } void CorrectCase(string name) // Correct upper and lower case letters of input { x = name.size(); int firstLetVal = name[0], letVal; n = 1; // variable for name index from second letter onwards if((name[0] 90) && (name[0] < 123)) // First letter is lower case { firstLetVal = firstLetVal - 32; // Capitalise first letter name[0] = firstLetVal; } while(n <= x - 1) { if((name[n] = 65) && (name[n] <= 90)) { letVal = name[n] + 32; name[n] = letVal; } n++; } cityNameInput = name; } void nameValidation(string name) { n = 0; // start from first letter x = name.size(); while(!acceptedInput) { if((name[n] = 65) && (name[n] <= 122)) // is in the range of letters { while(n <= x - 1) { while((name[n] =91) && (name[n] <=97)) // ERROR!! { cout << "Please enter a valid city name" << endl; cin name; } n++; } } else { cout << "Please enter a valid city name" << endl; cin name; } if(n <= x - 1) { acceptedInput = true; } } cityNameInput = name; } int main(array ^args) { cout << "Enter a city name" << endl; cin cityNameInput; nameValidation(cityNameInput); // check is made up of valid characters CorrectCase(cityNameInput); // corrects name to standard format of capitalised first letter, and lower case subsequent letters cout << cityNameInput; cin cityNameInput; Locations::Locations(); Locations *Parts = new Locations(); locationNode *Part; Part = new locationNode; //Part-nodeCityName = "London"; Part-nodeLati = 87; Part-nodeLongi = 80; Parts-Add(Part); } I am familiar with the concepts but somewhat inexperienced with OOP so am making some silly errors that you can never find when you've stared at something too long. Any help you can offer will be appreciated! Thanks

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• list images from directory by function

  - by osc2nuke

  i'm using this function: function getmyimages($qid){ $imgdir = 'modules/Projects/uploaded_project_images/'. $qid .''; // the directory, where your images are stored $allowed_types = array('png','jpg','jpeg','gif'); // list of filetypes you want to show $dimg = opendir($imgdir); while($imgfile = readdir($dimg)) { if(in_array(strtolower(substr($imgfile,-3)),$allowed_types)) { $a_img[] = $imgfile; sort($a_img); reset ($a_img); } } $totimg = count($a_img); // total image number for($x=0; $x < $totimg; $x++) { $size = getimagesize($imgdir.'/'.$a_img[$x]); // do whatever $halfwidth = ceil($size[0]/2); $halfheight = ceil($size[1]/2); $mytest = 'name: '.$a_img[$x].' width: '.$size[0].' height: '.$size[1].'<br /><a href="'. $imgdir .'/'.$a_img[$x].'">'. $a_img[$x]. '</a>'; } return $mytest; } And i call this function between a while row as: $sql_select = $db->sql_query('SELECT * from '.$prefix.'_projects WHERE topic=\''.$cid.'\''); OpenTable(); while ($row2 = $db->sql_fetchrow($sql_select)){ $qid = $row2['qid']; $project_query = $db->sql_query('SELECT p.uid, p.uname, p.subject, p.story, p.storyext, p.date, p.topic, p.pdate, p.materials, p.bidoptions, p.projectduration, pd.id_duration, pm.material_id, pbo.bidid, pc.cid FROM ' . $prefix . '_projects p, ' . $prefix . '_projects_duration pd, ' . $prefix . '_project_materials pm, ' . $prefix . '_project_bid_options pbo, ' . $prefix . '_project_categories pc WHERE p.topic=\''.$cid.'\' and p.qid=\''.$qid.'\' and p.bidoptions=pbo.bidid and p.materials=pm.material_id and p.projectduration=pd.id_duration'); while ($project_row = $db->sql_fetchrow($project_query)) { //$qid = $project_row['qid']; $uid = $project_row['uid']; $uname = $project_row['uname']; $subject = $project_row['subject']; $story = $project_row['story']; $storyext = $project_row['storyext']; $date = $project_row['date']; $topic = $project_row['topic']; $pdate = $project_row['pdate']; $materials = $project_row['materials']; $bidoptions = $project_row['bidoptions']; $projectduration = $project_row['projectduration']; //Get the topic name $topic_query = $db->sql_query('SELECT cid,title from '.$prefix.'_project_categories WHERE cid =\''.$cid.'\''); while ($topic_row = $db->sql_fetchrow($topic_query)) { $topic_id = $topic_row['cid']; $topic_title = $topic_row['title']; } //Get the material text $material_query = $db->sql_query('SELECT material_id,material_name from '.$prefix.'_project_materials WHERE material_id =\''.$materials.'\''); while ($material_row = $db->sql_fetchrow($material_query)) { $material_id = $material_row['material_id']; $material_name = $material_row['material_name']; } //Get the bid methode $bid_query = $db->sql_query('SELECT bidid,bidname from '.$prefix.'_project_bid_options WHERE bidid =\''.$bidoptions.'\''); while ($bid_row = $db->sql_fetchrow($bid_query)) { $bidid = $bid_row['bidid']; $bidname = $bid_row['bidname']; } //Get the project duration $duration_query = $db->sql_query('SELECT id_duration,duration_value,duration_alias from '.$prefix.'_projects_duration WHERE id_duration =\''.$projectduration.'\''); while ($duration_row = $db->sql_fetchrow($duration_query)) { $id_duration = $duration_row['id_duration']; $duration_value = $duration_row['duration_value']; $duration_alias = $duration_row['duration_alias']; } } echo '<br/><b>id</b>--->' .$qid. '<br/><b>uid</b>--->' .$uid. '<br/><b>username</b>--->' .$uname. '<br/><b>subject</b>--->'.$subject. '<br/><b>story1</b>--->'.$story. '<br/><b>story2</b>--->'.$storyext. '<br/><b>postdate</b>--->'.$date. '<br/><b>categorie</b>--->'.$topic_title . '<br/><b>project start</b>--->'.$pdate. '<br/><b>materials</b>--->'.$material_name. '<br/><b>bid methode</b>--->'.$bidname. '<br/><b>project duration</b>--->'.$duration_alias.'<br /><br /><br/><b>image url</b>--->'.getmyimages($qid).'<br /><br />'; } CloseTable(); the result outputs only the "last" file from the directories. if i do a echo instead of a return $mytest; it read the whole directory but ruïns the output.

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• SPSiteDataQuery Returns Only One List Type At A Time

  - by Brian Jackett

  The SPSiteDataQuery class in SharePoint 2007 is very powerful, but it has a few limitations.  One of these limitations that I ran into this morning (and caused hours of frustration) is that you can only return results from one list type at a time.  For example, if you are trying to query items from an out of the box custom list (list type = 100) and document library (list type = 101) you will only get items from the custom list (SPSiteDataQuery defaults to list type = 100.)  In my situation I was attempting to query multiple lists (created from custom list templates 10001 and 10002) each with their own content types. Solution     Since I am only able to return results from one list type at a time, I was forced to run my query twice with each time setting the ServerTemplate (translates to ListTemplateId if you are defining custom list templates) before executing the query.  Below is a snippet of the code to accomplish this. SPSiteDataQuery spDataQuery = new SPSiteDataQuery(); spDataQuery.Lists = "<Lists ServerTemplate='10001' />"; // ... set rest of properties for spDataQuery   var results = SPContext.Current.Web.GetSiteData(spDataQuery).AsEnumerable();   // only change to SPSiteDataQuery is Lists property for ServerTemplate attribute spDataQuery.Lists = "<Lists ServerTemplate='10002' />";   // re-execute query and concatenate results to existing entity results = results.Concat(SPContext.Current.Web.GetSiteData(spDataQuery).AsEnumerable());   Conclusion     Overall this isn’t an elegant solution, but it’s a workaround for a limitation with the SPSiteDataQuery.  I am now able to return data from multiple lists spread across various list templates.  I’d like to thank those who commented on this MSDN page that finally pointed out the limitation to me.  Also a thanks out to Mark Rackley for “name dropping” me in his latest article (which I humbly insist I don’t belong in such company)  as well as encouraging me to write up a quick post on this issue above despite my busy schedule.  Hopefully this post saves some of you from the frustrations I experienced this morning using the SPSiteDataQuery.  Until next time, Happy SharePoint’ing all.         -Frog Out   Links MSDN Article for SPSiteDataQuery http://msdn.microsoft.com/en-us/library/microsoft.sharepoint.spsitedataquery.lists.aspx

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• How to skip parentheses on Netbeans with enter?

  - by nunos

  So I have been programming in C++ with Eclipse and have the habit of hitting enter to skip parentheses (anyone who has ever used eclipse probably knows what I am talking about). I have recently started learning Java and decided to use NetBeans, mostly due to the much more simple interface. However, I would like to know if there a way to skip the (), [], < and "" on enter just like what happens in Eclipse in NetBeans. Thanks.

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• jquery skip list item

  - by steve

  Is there a way for a jQuery function to "skip" an li? Such as Having 3 list items, you click on the 1st one, it calls a next() function, and skips the 2nd li and goes to the 3rd. Current code is here: $('ul.gallery li').click(function() { $(window).scrollTo($(this).next('li'), 800, {easing:'easeOutCirc', axis:'x', offset:-50 } ); }); I want it to skip the immediate li and go to the one after that.

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• Convert multi-dimensional list to a 1D list in Python

  - by Sayan

  Hello, A multidimensional list like l=[[1,2],[3,4]] could be converted to a 1D one by doing sum(l,[]). Can anybody please explain how that happens? Thanks, Sayan

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• Why can I not convert from List<IScreen> to List<IRenderable> even when IScreen implements IRenderab

  - by Blub

  Pretty self explanatory question, glad for any answer. For me it doesn't make sense. I don't care about losing information. I just want to concatenate all my lists that inherit IRenderable somehow into a single list and then call IRenderable methods on it. I have a feeling that this is some basic rule of programming I forgot...

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• How to skip a statement in Eclipse during debugging

  - by frankfwl

  Is it possible to skip a statement in Eclipse while debugging? Suppose the process stopped at breakpoint and I want to skip the breakpoint line ( or maybe a few lines below), can I do it? On the debug tab, it only has "Step into", "Step over" and "Step return" buttons. I did google around but couldn't find anything, hopefully I can find an answer here.

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• Skip Corrupt Revisions During SvnAdmin Load

  - by cisellis

  I have a dump file that I am generating from VSS with the use of the VSS2SVN script. I've tested the generated dump file before and some of the revisions are corrupt for one reason or another (binary data or long path strings seem to be the main culprit). This is fine. In the past I have used svndumpfilter to split the dump file, remove the corrupt revisions and continue to load the repository. It worked but took a lot of manual effort to start the load, hit the bad revision, split the dump file, continue loading the repo, etc. This dump file is pretty large (~5GB) and takes several hours to load. I think I know the answer to this but is there any way to simply tell svnadmin load to keep going and skip corrupt revisions? I know how to verify, backup, etc. the dump file and don't need any of that. I don't care about recovering corrupt revisions. I just want to start the load, walk away, and not worry about checking it every few hours to manually remove the corrupt revisions. Is that possible? Thanks.

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• mysqldump skip one table

  - by danneth

  I'm running a cronjob to backup our system using mysqldump. The database contains 90 or so tables. One of these tables is HUGE and every once in a while causes the dump to fail. From the manual I see that you can specify specific tables to dump shell> mysqldump [options] db_name [tbl_name ...] This got me thinking. What if I have two jobs, one for dumping the huge table, and one for all the others. To accomplish this it would be nice if I could to something like shell> mysqldump -u backupuser -p database huge_table > db_huge_table.sql shell> mysqldump -u backupuser -p database --skip huge_table > db_rest.sql Unfortenately I'm not seeing such and option. I could of course explicitly state the 90 tables, but that just seems like a mess. Another option would be a script of some sort, but before checking that route I'll try this resource. MySQL is 5.1.61 on CentOS 6.2

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