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  • pyscripter Rpyc error

    - by jf328
    pyscripter 2.5.3.0 x64, python 2.7.7 anaconda 2.0.1, windows 7 I was using pyscripter and EPD python happily in 32 bit, no problem. Just changed to 64 bit anaconda version and re-installed everything but now pyscripter cannot import rpyc -- it runs with internal engine (no anaconda), but no such error in pure python. Thanks very much! btw, there is a similar SO post few years ago, but the answer there does not work. *** Python 2.7.3 (default, Apr 10 2012, 23:24:47) [MSC v.1500 64 bit (AMD64)] on win32. *** Internal Python engine is active *** *** Internal Python engine is active *** >>> import rpyc Traceback (most recent call last): File "<interactive input>", line 1, in <module> File "C:\Anaconda\lib\site-packages\rpyc\__init__.py", line 44, in <module> from rpyc.core import (SocketStream, TunneledSocketStream, PipeStream, Channel, File "C:\Anaconda\lib\site-packages\rpyc\core\__init__.py", line 1, in <module> from rpyc.core.stream import SocketStream, TunneledSocketStream, PipeStream File "C:\Anaconda\lib\site-packages\rpyc\core\stream.py", line 7, in <module> import socket File "C:\Anaconda\Lib\socket.py", line 47, in <module> import _socket ImportError: DLL load failed: The specified procedure could not be found. >>> C:\research>python Python 2.7.7 |Anaconda 2.0.1 (64-bit)| (default, Jun 11 2014, 10:40:02) [MSC v.1500 64bit (AMD64)] on win32 Type "help", "copyright", "credits" or "license" for more information. Anaconda is brought to you by Continuum Analytics. Please check out: http://continuum.io/thanks and https://binstar.org >>> import rpyc >>>

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  • Whats wrong with this HQL query?

    - by ManBugra
    did i encounter a hibernate bug or do i have an error i dont see: select enty.number from EntityAliasName enty where enty.myId in ( select cons.myId from Consens cons where cons.number in ( select ord.number from Orders ord where ord.customer = :customer and ord.creationDate < ( select max(ord.creationDate) from Orders ord where ord.customer = :customer ) ) ) what i do get is the following: org.hibernate.util.StringHelper.root(StringHelper.java:257) Caused by: java.lang.NullPointerException at org.hibernate.util.StringHelper.root(StringHelper.java:257) at org.hibernate.persister.entity.AbstractEntityPersister.getSubclassPropertyTableNumber(AbstractEntityPersister.java:1391) at org.hibernate.persister.entity.BasicEntityPropertyMapping.toColumns(BasicEntityPropertyMapping.java:54) at org.hibernate.persister.entity.AbstractEntityPersister.toColumns(AbstractEntityPersister.java:1367) at org.hibernate.hql.ast.tree.FromElement.getIdentityColumn(FromElement.java:320) at org.hibernate.hql.ast.tree.IdentNode.resolveAsAlias(IdentNode.java:154) at org.hibernate.hql.ast.tree.IdentNode.resolve(IdentNode.java:100) at org.hibernate.hql.ast.tree.FromReferenceNode.resolve(FromReferenceNode.java:117) at org.hibernate.hql.ast.tree.FromReferenceNode.resolve(FromReferenceNode.java:113) at org.hibernate.hql.ast.HqlSqlWalker.resolve(HqlSqlWalker.java:854) at org.hibernate.hql.antlr.HqlSqlBaseWalker.propertyRef(HqlSqlBaseWalker.java:1172) at org.hibernate.hql.antlr.HqlSqlBaseWalker.propertyRefLhs(HqlSqlBaseWalker.java:5167) at org.hibernate.hql.antlr.HqlSqlBaseWalker.propertyRef(HqlSqlBaseWalker.java:1133) at org.hibernate.hql.antlr.HqlSqlBaseWalker.selectExpr(HqlSqlBaseWalker.java:1993) at org.hibernate.hql.antlr.HqlSqlBaseWalker.selectExprList(HqlSqlBaseWalker.java:1932) at org.hibernate.hql.antlr.HqlSqlBaseWalker.selectClause(HqlSqlBaseWalker.java:1476) at org.hibernate.hql.antlr.HqlSqlBaseWalker.query(HqlSqlBaseWalker.java:580) at org.hibernate.hql.antlr.HqlSqlBaseWalker.selectStatement(HqlSqlBaseWalker.java:288) at org.hibernate.hql.antlr.HqlSqlBaseWalker.statement(HqlSqlBaseWalker.java:231) at org.hibernate.hql.ast.QueryTranslatorImpl.analyze(QueryTranslatorImpl.java:254) at org.hibernate.hql.ast.QueryTranslatorImpl.doCompile(QueryTranslatorImpl.java:185) at org.hibernate.hql.ast.QueryTranslatorImpl.compile(QueryTranslatorImpl.java:136) at org.hibernate.engine.query.HQLQueryPlan.<init>(HQLQueryPlan.java:101) at org.hibernate.engine.query.HQLQueryPlan.<init>(HQLQueryPlan.java:80) at org.hibernate.engine.query.QueryPlanCache.getHQLQueryPlan(QueryPlanCache.java:94) at org.hibernate.impl.SessionFactoryImpl.checkNamedQueries(SessionFactoryImpl.java:484) at org.hibernate.impl.SessionFactoryImpl.<init>(SessionFactoryImpl.java:394) at org.hibernate.cfg.Configuration.buildSessionFactory(Configuration.java:1341) using: Hibernate 3.3.2.GA / postgresql

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  • Default class for SQLAlchemy single table inheritance

    - by eclaird
    I've set up a single table inheritance, but I need a "default" class to use when an unknown polymorphic identity is encountered. The database is not in my control and so the data can be pretty much anything. A working example setup: import sqlalchemy as sa from sqlalchemy import orm engine = sa.create_engine('sqlite://') metadata = sa.MetaData(bind=engine) table = sa.Table('example_types', metadata, sa.Column('id', sa.Integer, primary_key=True), sa.Column('type', sa.Integer), ) metadata.create_all() class BaseType(object): pass class TypeA(BaseType): pass class TypeB(BaseType): pass base_mapper = orm.mapper(BaseType, table, polymorphic_on=table.c.type, polymorphic_identity=None, ) orm.mapper(TypeA, inherits=base_mapper, polymorphic_identity='A', ) orm.mapper(TypeB, inherits=base_mapper, polymorphic_identity='B', ) Session = orm.sessionmaker(autocommit=False, autoflush=False) session = Session() Now, if I insert a new unmapped identity... engine.execute('INSERT INTO EXAMPLE_TYPES (TYPE) VALUES (\'C\')') session.query(BaseType).first() ...things break. Traceback (most recent call last): File "<stdin>", line 1, in <module> File ".../SQLAlchemy-0.6.5-py2.6.egg/sqlalchemy/orm/query.py", line 1619, in first ret = list(self[0:1]) File ".../SQLAlchemy-0.6.5-py2.6.egg/sqlalchemy/orm/query.py", line 1528, in __getitem__ return list(res) File ".../SQLAlchemy-0.6.5-py2.6.egg/sqlalchemy/orm/query.py", line 1797, in instances rows = [process[0](row, None) for row in fetch] File ".../SQLAlchemy-0.6.5-py2.6.egg/sqlalchemy/orm/mapper.py", line 2179, in _instance _instance = polymorphic_instances[discriminator] File ".../SQLAlchemy-0.6.5-py2.6.egg/sqlalchemy/util.py", line 83, in __missing__ self[key] = val = self.creator(key) File ".../SQLAlchemy-0.6.5-py2.6.egg/sqlalchemy/orm/mapper.py", line 2341, in configure_subclass_mapper discriminator) AssertionError: No such polymorphic_identity u'C' is defined What I expected: >>> result = session.query(BaseType).first() >>> result <BaseType object at 0x1c8db70> >>> result.type u'C' I think this used to work with some older version of SQLAlchemy, but I haven't been keeping up with the development lately. Any pointers on how to accomplish this?

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  • Subdomain on different host

    - by mattsmith321
    Hi everyone! I'm trying to host a subdomain for my site with a different hosting company and I'm running into issues on how to set it up. Here are the specifics: - Domain is registered with GoDaddy. - Nameservers are pointing to DiscountASP.net where ASP.NET app has been happily running for couple of years. - Would like blog.mydomain.com to point to my account with DreamHost.com to take advantage of their LAMP stack. I have added blog.mydomain.com to DreamHost (after adding mydomain.com) via their control panel. I thought I would be able to add a subdomain entry on GoDaddy to point to DreamHost, but all they allow is blog.mydomain.com = new url. In theory I could just take our .biz or .net domain and host it on DreamHost but was hoping I could do it all with a subdomain. So, to summarize I'd like to know if what I want to do is feasible and if so, how do I go about it (given the constraints of GoDaddy, DiscountASP, & DreamHost). Thanks, Matt

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  • Setting Access-Control-Allow-Origin in Dreamhost possible?

    - by Kaushik Gopal
    Just wanted a confirmation for this: Firefox currently doesn't play well for picking custom fonts through a sub-domain via the font-face tag. Other browsers do this without any problems. A little research showed up saying that i am required to set the Access-Control-Allow-Origin as is shown in the link here: http://pastie.org/653265 Essentially i have my blog at kaushikgopal.com/blog and i was trying to access fonts that within this blog that are available at font.kaushikgopal.com. I tried changing the same in my .htaccess file but couldn't resolve the issue.(I placed a .htaccess file within the font sub-domain folder and directly pasted code from the above pastie link). I submitted a ticket to dreamhost asking for assistance and they were helpful in clearly stating "We do not support Access-Control-Allow-Origin on shared hosting servers". So i didn't go the sub-domain route for fonts. But i'm a little curious, has anyone tried this (with a dreamhost hosting account would be helpful)? Just want to confirm what the tech-support guy suggested is accurate and there's no other way. Thanks. Another nice link clearly stating the problem : http://www.stevesouders.com/tests/font-face/xdomain.php

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  • How do i write this jpql query?

    - by Nitesh Panchal
    Hello, Say i have 5 tables, tblBlogs tblBlogPosts tblBlogPostComment tblUser tblBlogMember BlogId BlogPostsId BlogPostCommentId UserId BlogMemberId BlogTitle BlogId CommentText FirstName UserId PostTitle BlogPostsId BlogId BlogMemberId Now i want to retrieve only those blogs and posts for which blogMember has actually commented. So in short, how do i write this plain old sql :- Select b.BlogTitle, bp.PostTitle, bpc.CommentText from tblBlogs b Inner join tblBlogPosts bp on b.BlogId = bp.BlogId Inner Join tblBlogPostComment bpc on bp.BlogPostsId = bpc.BlogPostsId Inner Join tblBlogMember bm On bpc.BlogMemberId = bm.BlogMemberId Where bm.UserId = 1; As you can see, everything is Inner join, so only that row will be retrieved for which the user has commented on some post of some blog. So, suppose he has joined 3 blogs whose ids are 1,2,3 (The blogs which user has joined are in tblBlogMembers) but the user has only commented in blog 2 (of say BlogPostId = 1). So that row will be retrieved and 1,3 won't as it is Inner Join. How do i write this kind of query in jpql? In jpql, we can only write simple queries like say :- Select bm.blogId from tblBlogMember Where bm.UserId = objUser; Where objUser is supplied using :- em.find(User.class,1); Thus once we get all blogs(Here blogId represents a blog object) which user has joined, we can loop through and do all fancy things. But i don't want to fall in this looping business and write all this things in my java code. Instead, i want to leave that for database engine to do. So, how do i write the above plain sql into jpql? and what type of object the jpql query will return? because i am only selecting few fields from all table. In which class should i typecast the result to? I think i posted my requirement correctly, if i am not clear please let me know. Thanks in advance :).

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  • Magento - Integrating Wordpress into Magento for the homepage

    - by Nick
    I currently have a Magento store where I'm using a CMS page as the homepage. I want to integrate my wordpress blog (hosted on the same server) into this CMS page. It would show the latest blog post and preferably have the comment function available on the front page. The first thing I considered was using the Wordpress Loop on the Magento CMS page, but it doesn't seem like it allows PHP. One other thought I had was to create the homepage using modules or blocks. To be honest, I've never created a module or block so I'm not all that familiar with what is involved. The CMS page that I had created is simply an image slider/carousel (nivo-slider) and some photos with links. None of the content actually needs to be done with CMS, it just needs to be presented within my Magento theme/framework. All homepage updates will be handled by myself, so I can bypass the CMS system all together and just update modules if it turns out that the modules solution will allow me to have both the Wordpress blog and nivo-slider on the same page. Any thoughts?

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  • Twitter Typeahead only shows only 5 results

    - by user3685388
    I'm using the Twitter Typeahead version 0.10.2 autocomplete but I'm only receiving 5 results from my JSON result set. I can have 20 or more results but only 5 are shown. What am I doing wrong? var engine = new Bloodhound({ name: "blackboard-names", prefetch: { url: "../CFC/Login.cfc?method=Search&returnformat=json&term=%QUERY", ajax: { contentType: "json", cache: false } }, remote: { url: "../CFC/Login.cfc?method=Search&returnformat=json&term=%QUERY", ajax: { contentType: "json", cache: false }, }, datumTokenizer: Bloodhound.tokenizers.obj.whitespace('value'), queryTokenizer: Bloodhound.tokenizers.whitespace }); var promise = engine.initialize(); promise .done(function() { console.log("done"); }) .fail(function() { console.log("fail"); }); $("#Impersonate").typeahead({ minLength: 2, highlight: true}, { name: "blackboard-names", displayKey: 'value', source: engine.ttAdapter() }).bind("typeahead:selected", function(obj, datum, name) { console.log(obj, datum, name); alert(datum.id); }); Data: [ { "id": "1", "value": "Adams, Abigail", "tokens": [ "Adams", "A", "Ad", "Ada", "Abigail", "A", "Ab", "Abi" ] }, { "id": "2", "value": "Adams, Alan", "tokens": [ "Adams", "A", "Ad", "Ada", "Alan", "A", "Al", "Ala" ] }, { "id": "3", "value": "Adams, Alison", "tokens": [ "Adams", "A", "Ad", "Ada", "Alison", "A", "Al", "Ali" ] }, { "id": "4", "value": "Adams, Amber", "tokens": [ "Adams", "A", "Ad", "Ada", "Amber", "A", "Am", "Amb" ] }, { "id": "5", "value": "Adams, Amelia", "tokens": [ "Adams", "A", "Ad", "Ada", "Amelia", "A", "Am", "Ame" ] }, { "id": "6", "value": "Adams, Arik", "tokens": [ "Adams", "A", "Ad", "Ada", "Arik", "A", "Ar", "Ari" ] }, { "id": "7", "value": "Adams, Ashele", "tokens": [ "Adams", "A", "Ad", "Ada", "Ashele", "A", "As", "Ash" ] }, { "id": "8", "value": "Adams, Brady", "tokens": [ "Adams", "A", "Ad", "Ada", "Brady", "B", "Br", "Bra" ] }, { "id": "9", "value": "Adams, Brandon", "tokens": [ "Adams", "A", "Ad", "Ada", "Brandon", "B", "Br", "Bra" ] } ]

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  • How do I create Twitter style URL's for my app - Using existing application or app redesign - Ruby o

    - by bgadoci
    I have developed a blog application of sorts that I am trying to allow other users to take advantage of (for free and mostly for family). I wondering if the authentication I have set up will allow for such a thing. Here is the scenario. Currently the application allows for users to sign up for an account and when they do so they can create blog posts and organize those posts via tags. The application displays no data publicly (another words, you have to login to see anything). To gain access you have to create an account and even after you do, you cannot see anyone else's information as the applications filters using the current_user method and displays in the /posts/index.html.erb page. This would be great if a user only wanted to blog and share it with themselves, not really what I am looking for. My question has two parts (hopefully I won't make anyone mad by not putting these into two questions) Is it possible for a particular users data to live at www.myapplication.com/user without moving everything to the /user/show.html.erb file? Is it possible to make some of that information (living at the URL) public but still require login for create and destroy actions. Essentially, exactly like twitter. I am just curious if I can get from where I am (using the current_user methods across controllers to display in /posts/index.html.erb) to where I want to be. My fear is that I have to redesign the app such that the user data lives in the /user/show.html.erb page. Thoughts?

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  • How do I create Twitter style URLs for my app - Using existing application or app redesign - Ruby on

    - by bgadoci
    I have developed a blog application of sorts that I am trying to allow other users to take advantage of (for free and mostly for family). I wondering if the authentication I have set up will allow for such a thing. Here is the scenario. Currently the application allows for users to sign up for an account and when they do so they can create blog posts and organize those posts via tags. The application displays no data publicly (another words, you have to login to see anything). To gain access you have to create an account and even after you do, you cannot see anyone else's information as the applications filters using the current_user method and displays in the /posts/index.html.erb page. This would be great if a user only wanted to blog and share it with themselves, not really what I am looking for. My question has two parts (hopefully I won't make anyone mad by not putting these into two questions) Is it possible for a particular users data to live at www.myapplication.com/user without moving everything to the /user/show.html.erb file? Is it possible to make some of that information (living at the URL) public but still require login for create and destroy actions. Essentially, exactly like twitter. I am just curious if I can get from where I am (using the current_user methods across controllers to display in /posts/index.html.erb) to where I want to be. My fear is that I have to redesign the app such that the user data lives in the /user/show.html.erb page. Thoughts? UPDATE: I am using Clearance for authentication by Thoughtbot. I wonder if there is something I can set in the vendored gem path to represent the /posts/index.html.erb code as the /user/id code and replace id with the user name.

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  • question about InnoDB deadlock in MySQL?

    - by WilliamLou
    I found this kind of interesting problem in MySQL InnoDB engine, could anyone explain why the engine always claim it's a deadlock. First, I created a table with a single row, single column: CREATE TABLE `SeqNum` (`current_seq_num` bigint(30) NOT NULL default '0', PRIMARY KEY (`current_seq_num`) ) ENGINE=InnoDB DEFAULT CHARSET=utf8 | Now, I have two MySQL connector threads, In thread1: mysql> begin; Query OK, 0 rows affected (0.00 sec) mysql> select `current_seq_num` into @curr_seq FROM SeqNum FOR UPDATE; Query OK, 1 row affected (0.00 sec) Now, in thread2, I did the exactly same: mysql> begin; Query OK, 0 rows affected (0.00 sec) mysql> select `current_seq_num` into @curr_seq FROM SeqNum FOR UPDATE; before the default innodb_lock_wait_timeout, the thread2 just wait for thread1 to release its exclusive lock on the table, and it's normal. However, in thread1, if I input the following update query: mysql> update SeqNum set `current_seq_num` = 8; ERROR 1213 (40001): Deadlock found when trying to get lock; try restarting transaction Now, thread2 get the select query finished because thread1 quits. In addition, in thread1, if I input the update query with a where clause, it can be executed very well: mysql> update SeqNum set `current_seq_num` = 8 where `current_seq_num` =5 Query OK, 1 row affected (0.00 sec) Could anyone explain this?

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  • PHP unit tests for controller returns no errors and no success message.

    - by Mallika Iyer
    I'm using the zend modular director structure, i.e. application modules users controllers . . lessons reports blog I have a unit test for a controller in 'blog' that goes something like the below section of code: I'm definitely doing something very wrong, or missing something - as when i run the test, i get no error, no success message (that goes usually like ...OK (2 tests, 2 assertions)). I get all the text from layout.phtml, where i have the global site layout. This is my first endeavor writing a unittest for zend-M-V-C structure so probably I'm missing something important? Here goes.... require_once '../../../../public/index.php'; require_once '../../../../application/Bootstrap.php'; require_once '../../../../application/modules/blog/controllers/BrowseController.php'; require_once '../../../TestConfiguration.php'; class Blog_BrowseControllerTest extends Zend_Test_PHPUnit_ControllerTestCase { public function setUp() { $this->bootstrap = array($this, 'appBootstrap'); Blog_BrowseController::setUp(); } public function appBootstrap() { require_once dirname(__FILE__) . '/../../bootstrap.php'; } public function testAction() { $this->dispatch('/'); $this->assertController('browse'); $this->assertAction('index'); } public function tearDown() { $this->resetRequest(); $this->resetResponse(); Blog_BrowseController::tearDown(); } }

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  • org.hibernate.hql.ast.QuerySyntaxException: TABLE NAME is not mapped

    - by Coronatus
    I have two models, Item and ShopSection. They have a many-to-many relationship. @Entity(name = "item") public class Item extends Model { @ManyToMany(cascade = CascadeType.PERSIST) public Set<ShopSection> sections; } @Entity(name = "shop_section") public class ShopSection extends Model { public List<Item> findActiveItems(int page, int length) { return Item.find("select distinct i from Item i join i.sections as s where s.id = ?", id).fetch(page, length); } } findActiveItems is meant to find items in a section, but I get this error: org.hibernate.hql.ast.QuerySyntaxException: Item is not mapped [select distinct i from Item i join i.sections as s where s.id = ?] at org.hibernate.hql.ast.util.SessionFactoryHelper.requireClassPersister(SessionFactoryHelper.java:180) at org.hibernate.hql.ast.tree.FromElementFactory.addFromElement(FromElementFactory.java:111) at org.hibernate.hql.ast.tree.FromClause.addFromElement(FromClause.java:93) at org.hibernate.hql.ast.HqlSqlWalker.createFromElement(HqlSqlWalker.java:322) at org.hibernate.hql.antlr.HqlSqlBaseWalker.fromElement(HqlSqlBaseWalker.java:3441) at org.hibernate.hql.antlr.HqlSqlBaseWalker.fromElementList(HqlSqlBaseWalker.java:3325) at org.hibernate.hql.antlr.HqlSqlBaseWalker.fromClause(HqlSqlBaseWalker.java:733) at org.hibernate.hql.antlr.HqlSqlBaseWalker.query(HqlSqlBaseWalker.java:584) at org.hibernate.hql.antlr.HqlSqlBaseWalker.selectStatement(HqlSqlBaseWalker.java:301) at org.hibernate.hql.antlr.HqlSqlBaseWalker.statement(HqlSqlBaseWalker.java:244) at org.hibernate.hql.ast.QueryTranslatorImpl.analyze(QueryTranslatorImpl.java:254) at org.hibernate.hql.ast.QueryTranslatorImpl.doCompile(QueryTranslatorImpl.java:185) at org.hibernate.hql.ast.QueryTranslatorImpl.compile(QueryTranslatorImpl.java:136) at org.hibernate.engine.query.HQLQueryPlan.<init>(HQLQueryPlan.java:101) at org.hibernate.engine.query.HQLQueryPlan.<init>(HQLQueryPlan.java:80) at org.hibernate.engine.query.QueryPlanCache.getHQLQueryPlan(QueryPlanCache.java:124) at org.hibernate.impl.AbstractSessionImpl.getHQLQueryPlan(AbstractSessionImpl.java:156) at org.hibernate.impl.AbstractSessionImpl.createQuery(AbstractSessionImpl.java:135) at org.hibernate.impl.SessionImpl.createQuery(SessionImpl.java:1770) at org.hibernate.ejb.AbstractEntityManagerImpl.createQuery(AbstractEntityManagerImpl.java:272) ... 8 more What am I doing wrong?

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  • django url user id versus userprofile id problem

    - by dana
    hello there, i have a mini comunity where each user can search and find another user profile. Userprofile is a class model, indexed differently compared to user model class (user id is not equal to userprofile id) But i cannot see a user profile by typing in the url the corresponding id. I only see the profile of the currently logged in user. Why is that? I'd also want to have in my url the username (a primary key of the user table also) and NOT the id (a number). The guilty part of the code is: what can i replace that request.user with so that it wil actually display the user i searched for, and not the currently logged in? def profile_view(request, id): u = UserProfile.objects.get(pk=id) cv = UserProfile.objects.filter(created_by = request.user) blog = New.objects.filter(created_by = request.user) return render_to_response('profile/publicProfile.html', { 'u':u, 'cv':cv, 'blog':blog, }, context_instance=RequestContext(request)) in urls (of the accounts app): url(r'^profile_view/(?P<id>\d+)/$', profile_view, name='profile_view'), and in template: <h3>Recent Entries:</h3> {% load pagination_tags %} {% autopaginate list 10 %} {% paginate %} {% for object in list %} <li>{{ object.post }} <br /> Voted: {{ vote.count }} times.<br /> {% for reply in object.reply_set.all %} {{ reply.reply }} <br /> {% endfor %} <a href=''> {{ object.created_by }}</a> <br /> {{object.date}} <br /> <a href = "/vote/save_vote/{{object.id}}/">Vote this</a> <a href="/replies/save_reply/{{object.id}}/">Comment</a> </li> {% endfor %} thanks in advance!

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  • Trying to use Rhino, getEngineByName("JavaScript") returns null in OpenJDK 7

    - by Yuval
    When I run the following piece of code, the engine variable is set to null when I'm using OepnJDK 7 (java-7-openjdk-i386). import javax.script.ScriptEngine; import javax.script.ScriptEngineManager; import javax.script.ScriptException; public class TestRhino { /** * @param args */ public static void main(String[] args) { // TODO Auto-generated method stub ScriptEngineManager factory = new ScriptEngineManager(); ScriptEngine engine = factory.getEngineByName("JavaScript"); try { System.out.println(engine.eval("1+1")); } catch (ScriptException e) { // TODO Auto-generated catch block e.printStackTrace(); } } } It runs fine with java-6-openjdk and Oracle's jre1.7.0. Any idea why? I'm using Ubuntu 11.10. All JVMs are installed under /usr/lib/jvm. I noticed OpenJDK 7 has a different directory structure. Perhaps something is not installed right? $ locate rhino.jar /usr/lib/jvm/java-6-openjdk/jre/lib/rhino.jar /usr/lib/jvm/java-7-openjdk-common/jre/lib/rhino.jar /usr/lib/jvm/java-7-openjdk-i386/jre/lib/rhino.jar Edit Since ScriptEngineManager uses a ServiceProvider to find the available script engines, I snooped around resources.jar's META-INF/services. I noticed that in OpenJDK 6, resources.jar has a META-INF/services/javax.script.ScriptEngineFactory entry which is missing from OpenJDK 7. Any idea why? I suspect this is a bug? Here is the contents of that entry (from OpenJDK 6): #script engines supported com.sun.script.javascript.RhinoScriptEngineFactory #javascript Another edit Apparently, according to this thread, the code simply isn't there, perhaps because of merging issues between Sun and Mozilla code. I still don't understand why it was present in OpenJDK 6 and not 7. The class com.sun.script.javascript.RhinoScriptEngineFactory exists in 6's rt.jar but not in 7's. If it was not meant to be included, why is there a OpenJDK 7 rhino.jar then; and why is the source still in the OpenJDK source tree (here)?

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  • Hibernate Auto-Increment Setup

    - by dharga
    How do I define an entity for the following table. I've got something that isn't working and I just want to see what I'm supposed to do. USE [BAMPI_TP_dev] GO SET ANSI_NULLS ON GO SET QUOTED_IDENTIFIER ON GO SET ANSI_PADDING ON GO CREATE TABLE [dbo].[MemberSelectedOptions]( [OptionId] [int] NOT NULL, [SeqNo] [smallint] IDENTITY(1,1) NOT NULL, [OptionStatusCd] [char](1) NULL ) ON [PRIMARY] GO SET ANSI_PADDING OFF This is what I have already that isn't working. @Entity @Table(schema="dbo", name="MemberSelectedOptions") public class MemberSelectedOption extends BampiEntity implements Serializable { @Embeddable public static class MSOPK implements Serializable { private static final long serialVersionUID = 1L; @Column(name="OptionId") int optionId; @GeneratedValue(strategy=GenerationType.IDENTITY) @Column(name="SeqNo", unique=true, nullable=false) BigDecimal seqNo; //Getters and setters here... } private static final long serialVersionUID = 1L; @EmbeddedId MSOPK pk = new MSOPK(); @Column(name="OptionStatusCd") String optionStatusCd; //More Getters and setters here... } I get the following ST. [5/25/10 15:49:40:221 EDT] 0000003d JDBCException E org.slf4j.impl.JCLLoggerAdapter error Cannot insert explicit value for identity column in table 'MemberSelectedOptions' when IDENTITY_INSERT is set to OFF. [5/25/10 15:49:40:221 EDT] 0000003d AbstractFlush E org.slf4j.impl.JCLLoggerAdapter error Could not synchronize database state with session org.hibernate.exception.SQLGrammarException: could not insert: [com.bob.proj.ws.model.MemberSelectedOption] at org.hibernate.exception.SQLStateConverter.convert(SQLStateConverter.java:90) at org.hibernate.exception.JDBCExceptionHelper.convert(JDBCExceptionHelper.java:66) at org.hibernate.persister.entity.AbstractEntityPersister.insert(AbstractEntityPersister.java:2285) at org.hibernate.persister.entity.AbstractEntityPersister.insert(AbstractEntityPersister.java:2678) at org.hibernate.action.EntityInsertAction.execute(EntityInsertAction.java:79) at org.hibernate.engine.ActionQueue.execute(ActionQueue.java:279) at org.hibernate.engine.ActionQueue.executeActions(ActionQueue.java:263) at org.hibernate.engine.ActionQueue.executeActions(ActionQueue.java:167) at org.hibernate.event.def.AbstractFlushingEventListener.performExecutions(AbstractFlushingEventListener.java:321) at org.hibernate.event.def.DefaultFlushEventListener.onFlush(DefaultFlushEventListener.java:50) at org.hibernate.impl.SessionImpl.flush(SessionImpl.java:1028) at org.hibernate.impl.SessionImpl.managedFlush(SessionImpl.java:366) at org.hibernate.transaction.JDBCTransaction.commit(JDBCTransaction.java:137) at com.bcbst.bamp.ws.dao.MemberSelectedOptionDAOImpl.saveMemberSelectedOption(MemberSelectedOptionDAOImpl.java:143) at com.bcbst.bamp.ws.common.AlertReminder.saveMemberSelectedOptions(AlertReminder.java:76) at sun.reflect.NativeMethodAccessorImpl.invoke0(Native Method) at sun.reflect.NativeMethodAccessorImpl.invoke(NativeMethodAccessorImpl.java:39)

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  • How do i write this jpql query? java

    - by Nitesh Panchal
    Hello, Say i have 5 tables, tblBlogs tblBlogPosts tblBlogPostComment tblUser tblBlogMember BlogId BlogPostsId BlogPostCommentId UserId BlogMemberId BlogTitle BlogId CommentText FirstName UserId PostTitle BlogPostsId BlogId BlogMemberId Now i want to retrieve only those blogs and posts for which blogMember has actually commented. So in short, how do i write this plain old sql :- Select b.BlogTitle, bp.PostTitle, bpc.CommentText from tblBlogs b Inner join tblBlogPosts bp on b.BlogId = bp.BlogId Inner Join tblBlogPostComment bpc on bp.BlogPostsId = bpc.BlogPostsId Inner Join tblBlogMember bm On bpc.BlogMemberId = bm.BlogMemberId Where bm.UserId = 1; As you can see, everything is Inner join, so only that row will be retrieved for which the user has commented on some post of some blog. So, suppose he has joined 3 blogs whose ids are 1,2,3 (The blogs which user has joined are in tblBlogMembers) but the user has only commented in blog 2 (of say BlogPostId = 1). So that row will be retrieved and 1,3 won't as it is Inner Join. How do i write this kind of query in jpql? In jpql, we can only write simple queries like say :- Select bm.blogId from tblBlogMember Where bm.UserId = objUser; Where objUser is supplied using :- em.find(User.class,1); Thus once we get all blogs(Here blogId represents a blog object) which user has joined, we can loop through and do all fancy things. But i don't want to fall in this looping business and write all this things in my java code. Instead, i want to leave that for database engine to do. So, how do i write the above plain sql into jpql? and what type of object the jpql query will return? because i am only selecting few fields from all table. In which class should i typecast the result to? I think i posted my requirement correctly, if i am not clear please let me know. Thanks in advance :).

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  • Flash/Flex sending XML to Rails App

    - by bdicasa
    I'm trying to send some XML to a rails app in Flex. I'm using the URLRequest and URLLoader objects. However, I'm having trouble determining how to send the XML and _method parameter to the rails app using these flash objects. Below is how I'm currently trying to achieve this. var request:URLRequest = new URLRequest(); request.method = URLRequestMethod.POST; request.data = new Object(); request.data.xml = Blog.xml.toXMLString(); request.contentType = "text/xml"; var loader:URLLoader = new URLLoader(); loader.addEventListener(Event.COMPLETE, saveCompleteHandler); var saveUrl:String = ""; saveUrl = BASE_URL; if (Blog.isNewBlog) { // Set the rails REST method. request.data._method = "POST"; saveUrl += "blogs.xml"; } else { // Set the rails REST method. request.data._method = "PUT"; saveUrl += "blogs/" + Blog.id.toString() + ".xml"; } request.url = saveUrl; //trace(request.data.toString()); loader.load(request); However the only data that is getting sent to the server is [Object object]. If some one could let me know where I'm going wrong I'd greatly appreciate it. Thanks.

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  • sqlalchemy relation through another (declarative)

    - by clayg
    Is anyone familiar with ActiveRecord's "has_many :through" relations for models? I'm not really a Rails guy, but that's basically what I'm trying to do. As a contrived example consider Projects, Programmers, and Assignments: from sqlalchemy import create_engine from sqlalchemy.orm import sessionmaker from sqlalchemy import Column, ForeignKey from sqlalchemy.types import Integer, String, Text from sqlalchemy.orm import relation from sqlalchemy.ext.declarative import declarative_base Base = declarative_base() class Assignment(Base): __tablename__ = 'assignment' id = Column(Integer, primary_key=True) description = Column(Text) programmer_id = Column(Integer, ForeignKey('programmer.id')) project_id = Column(Integer, ForeignKey('project.id')) def __init__(self, description=description): self.description = description def __repr__(self): return '<Assignment("%s")>' % self.description class Programmer(Base): __tablename__ = 'programmer' id = Column(Integer, primary_key=True) name = Column(String(64)) assignments = relation("Assignment", backref='programmer') def __init__(self, name=name): self.name = name def __repr__(self): return '<Programmer("%s")>' % self.name class Project(Base): __tablename__ = 'project' id = Column(Integer, primary_key=True) name = Column(String(64)) description = Column(Text) assignments = relation("Assignment", backref='project') def __init__(self, name=name, description=description): self.name = name self.description = description def __repr__(self): return '<Project("%s", "%s...")>' % (self.name, self.description[:10]) engine = create_engine('sqlite://') Base.metadata.create_all(engine) Session = sessionmaker(bind=engine) session = Session() Projects have many Assignments. Programmers have many Assignments. (understatement?) But in my office at least, Programmers also have many Projects - I'd like this relationship to be inferred through the Assignments assigned to the Programmer. I'd like the Programmer model to have a attribute "projects" which will return a list of Projects associated to the Programmer through the Assignment model. me = session.query(Programmer).filter_by(name='clay').one() projects = session.query(Project).\ join(Project.assignments).\ join(Assignment.programmer).\ filter(Programmer.id==me.id).all() How can I describe this relationship clearly and simply using the sqlalchemy declarative syntax? Thanks!

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  • what libraries or platforms should I use to build web apps that provide real-time, asynchronous data

    - by Daniel Sterling
    This is a less a question with a simple, practical answer and more a question to foster discussion on the real-time data exchange topic. I'll begin with an example: Google Wave is, at its core, a real-time asynchronous data synchronization engine. Wave supports (or plans to support) concurrent (real-time) document collaboration, disconnected (offline) document editing, conflict resolution, document history and playback with attribution, and server federation. A core part of Wave is the Operational Transformation engine: http://www.waveprotocol.org/whitepapers/operational-transform The OT engine manages document state. Changes between clients are merged and each client has a sane and consistent view of the document at all times; the final document is eventually consistent between all connected clients. My question is: is this system abstract or general enough to be used as a library or generic framework upon which to build web apps that synchronize real-time, asynchronous state in each client? Is the Wave protocol directly used by any current web applications (besides Google's client)? Would it make sense to directly use it for generic state synchronization in a web app? What other existing libraries or frameworks would you consider using when building such a web app? How much code in such an app might be domain-specific logic vs generic state synchronization logic? Or, put another way, how leaky might the state synchronization abstractions be? Comments and discussion welcomed!

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  • How does jquery display an image received from an ajax request?

    - by Gnee
    I have this working great, but I'd like a deeper understanding of what is actually going on behind the scenes. I am using Jquery's Ajax method to pull 5 blog posts (returning only the title and first photo). A PHP script grabs the blog posts' title and first photo and sticks it in an array and sends it back to my browser as JSON. Upon receiving the JSON object, Jquery grabs the first member of the JSON object and displays it's title and photo. In a gallery I made, using buttons – the user can iterate the 1-5 posts. So the actual AJAX call happens right away, and only once. I am basically using this kind of setup: $('my_div').html(json_obj[i]) and each click does a i++. So jquery is plucking these blog posts from my computers memory, my web browsers cache, or some kind of cache in the Javascript engine? One of the things it's returning is a pretty gnarly animated gif. I just wonder if it constantly running in the background (but not visible), stealing processing cycles...etc. Or Javascript just inserting (say a flash movie) into the DOM, but before hand does nothing but take up a little memory (no processing). Anyway, I'm just curious. If someone is a guru on this, I'd love to hear your take. Thanks!!

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  • SEO: Where do I start?

    - by James
    Hi, I am primarily a software developer however I tend to delve in some web development from time to time. I have recently been asked to have a look at a friends website as they are wanting to improve their position in search engine results i.e. google/yahoo etc. I am aware there is no guarentee that their position will change, however, I do know there are techniques/ways to make your website more visible to search engine spiders and to consequently improve your position in the rankings i.e. performing SEO. Before I started looking at the SEO of the site I did the following prerequsite checks: Ran the website through the W3C Markup Validator and the W3C CSS Validator services. Looked through the markup code manually (check for meta tags etc) Performed a thorough cross browser compatibility test. From those checks, the following was evident: No SEO has been performed on the site before. The website has been developed using a visual editing tool such as dreamweaver (as it failed the validation services miserably and tables where being used everywhere!) The site is fairly cross browser compatibile (only some slight issues with IE8 which are easily resolved). How the site navigation is, isn't very search engine friendly (e.g. index.php?page=home) I can see right away a major improvement for SEO (or I at least think) would be to change the way the website is structured i.e. change from using dynamic pages such as "index.php?page=home" and actually having pages called "home.html". Other area's would be to add meta tags to identify keywords, and then sprinkling these keywords over the pages. As I am a rookie in this department, could anyone give me some advice on how I could perform thorough SEO on this website? Thanks in advance.

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  • Creating self-referential tables with polymorphism in SQLALchemy

    - by Jace
    I'm trying to create a db structure in which I have many types of content entities, of which one, a Comment, can be attached to any other. Consider the following: from datetime import datetime from sqlalchemy import create_engine from sqlalchemy import Column, ForeignKey from sqlalchemy import Unicode, Integer, DateTime from sqlalchemy.orm import relation, backref from sqlalchemy.ext.declarative import declarative_base Base = declarative_base() class Entity(Base): __tablename__ = 'entities' id = Column(Integer, primary_key=True) created_at = Column(DateTime, default=datetime.utcnow, nullable=False) edited_at = Column(DateTime, default=datetime.utcnow, onupdate=datetime.utcnow, nullable=False) type = Column(Unicode(20), nullable=False) __mapper_args__ = {'polymorphic_on': type} # <...insert some models based on Entity...> class Comment(Entity): __tablename__ = 'comments' __mapper_args__ = {'polymorphic_identity': u'comment'} id = Column(None, ForeignKey('entities.id'), primary_key=True) _idref = relation(Entity, foreign_keys=id, primaryjoin=id == Entity.id) attached_to_id = Column(Integer, ForeignKey('entities.id'), nullable=False) #attached_to = relation(Entity, remote_side=[Entity.id]) attached_to = relation(Entity, foreign_keys=attached_to_id, primaryjoin=attached_to_id == Entity.id, backref=backref('comments', cascade="all, delete-orphan")) text = Column(Unicode(255), nullable=False) engine = create_engine('sqlite://', echo=True) Base.metadata.bind = engine Base.metadata.create_all(engine) This seems about right, except SQLAlchemy doesn't like having two foreign keys pointing to the same parent. It says ArgumentError: Can't determine join between 'entities' and 'comments'; tables have more than one foreign key constraint relationship between them. Please specify the 'onclause' of this join explicitly. How do I specify onclause?

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  • A little confusion about AJAX and inserting into DOM..

    - by Gnee
    I have this working great, but I'd like a deeper understanding of what is actually going on behind the scenes. I am using Jquery's Ajax method to pull 5 blog posts (returning only the title and first photo). A PHP script grabs the blog posts' title and first photo and sticks it in an array and sends it back to my browser as JSON. Upon receiving the JSON object, Jquery grabs the first member of the JSON object and displays it's title and photo. In a gallery I made, using buttons – the user can iterate the 1-5 posts. So the actual AJAX call happens right away, and only once. I am basically using this kind of setup: $('my_div').html(json_obj[i]) and each click does a i++. So jquery is plucking these blog posts from my computers memory, my web browsers cache, or some kind of cache in the Javascript engine? One of the things it's returning is a pretty gnarly animated gif. I just wonder if it constantly running in the background (but not visible), stealing processing cycles...etc. Or Javascript just inserting (say a flash movie) into the DOM, but before hand does nothing but take up a little memory (no processing). Anyway, I'm just curious. If someone is a guru on this, I'd love to hear your take. THanks!!

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  • Modeling objects with multiple table relationships in Zend Framework

    - by andybaird
    I'm toying with Zend Framework and trying to use the "QuickStart" guide against a website I'm making just to see how the process would work. Forgive me if this answer is obvious, hopefully someone experienced can shed some light on this. I have three database tables: CREATE TABLE `users` ( `id` int(11) NOT NULL auto_increment, `email` varchar(255) NOT NULL, `username` varchar(255) NOT NULL default '', `first` varchar(128) NOT NULL default '', `last` varchar(128) NOT NULL default '', `gender` enum('M','F') default NULL, `birthyear` year(4) default NULL, `postal` varchar(16) default NULL, `auth_method` enum('Default','OpenID','Facebook','Disabled') NOT NULL default 'Default', PRIMARY KEY (`id`), UNIQUE KEY `email` (`email`), UNIQUE KEY `username` (`username`) ) ENGINE=MyISAM DEFAULT CHARSET=latin1 CREATE TABLE `user_password` ( `user_id` int(11) NOT NULL, `password` varchar(16) NOT NULL default '', PRIMARY KEY (`user_id`), UNIQUE KEY `user_id` (`user_id`) ) ENGINE=MyISAM DEFAULT CHARSET=latin1 CREATE TABLE `user_metadata` ( `user_id` int(11) NOT NULL default '0', `signup_date` datetime default NULL, `signup_ip` varchar(15) default NULL, `last_login_date` datetime default NULL, `last_login_ip` varchar(15) default NULL, PRIMARY KEY (`user_id`), UNIQUE KEY `user_id` (`user_id`) ) ENGINE=MyISAM DEFAULT CHARSET=latin1 I want to create a User model that uses all three tables in certain situations. E.g., the metadata table is accessed if/when the meta data is needed. The user_password table is accessed only if the 'Default' auth_method is set. I'll likely be adding a profile table later on that I would like to be able to access from the user model. What is the best way to do this with ZF and why?

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