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  • How to manually render a Django template for an inlineformset_factory with can_delete = True / False

    - by chefsmart
    I have an inlineformset with a custom Modelform. So it looks something like this: MyInlineFormSet = inlineformset_factory(MyMainModel, MyInlineModel, form=MyCustomInlineModelForm) I am rendering this inlineformset manually in a template so that I have more control over widgets and javascript. So I go in a loop like {% for form in myformset.forms %} and then manually render each field as described on this page http://docs.djangoproject.com/en/dev/topics/forms/#customizing-the-form-template The formset has can_delete = True or can_delete = False depending on whether the user is creating new objects or editing existing ones. Question is, how do I manually render the can_delete checkbox?

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  • Django: Prefill a ManytoManyField

    - by Emile Petrone
    I have a ManyToManyField on a settings page that isn't rendering. The data was filled when the user registered, and I am trying to prefill that data when the user tries to change it. Thanks in advance for the help! The HTML: {{form.types.label}} {% if add %} {{form.types}} {% else %} {% for type in form.types.all %} {{type.description}} {% endfor %} {% endif %} The View: @csrf_protect @login_required def edit_host(request, host_id, template_name="host/newhost.html"): host = get_object_or_404(Host, id=host_id) if request.user != host.user: return HttpResponseForbidden() form = HostForm(request.POST) if form.is_valid(): if request.method == 'POST': if form.cleaned_data.get('about') is not None: host.about = form.cleaned_data.get('about') if form.cleaned_data.get('types') is not None: host.types = form.cleaned_data.get('types') host.save() form.save_m2m() return HttpResponseRedirect('/users/%d/' % host.user.id) else: form = HostForm(initial={ "about":host.about, "types":host.types, }) data = { "host":host, "form":form } return render_to_response(template_name, data, context_instance=RequestContext(request)) Form: class HostForm(forms.ModelForm): class Meta: model = Host fields = ('types', 'about', ) types = forms.ModelMultipleChoiceField( widget=forms.CheckboxSelectMultiple, queryset=Type.objects.all(), required=True) about = forms.CharField( widget=forms.Textarea(), required=True) def __init__(self, *args, **kwargs): super(HostForm, self).__init__(*args, **kwargs) self.fields['about'].widget.attrs = { 'placeholder':'Hello!'}

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  • Select a subset of foreign key elements in inlineformset_factory in Django

    - by Enis Afgan
    Hello, I have a model with two foreign keys: class Model1(models.Model): model_a = models.ForeignKey(ModelA) model_b = models.ForeignKey(ModelB) value = models.IntegerField() Then, I create an inline formset class, like so: an_inline_formset = inlineformset_factory(ModelA, Model1, fk_name="model_a") and then instantiate it, like so: a_formset = an_inline_formset(request.POST, instance=model_A_object) Once this formset gets rendered in a template/page, there is ChoiceField associated with the model_b field. The problem I'm having is that the elements in the resulting drop down menu include all of the elements found in ModelB table. I need to select a subset of those based on some criteria from ModelB. At the same time, I need to keep the reference to the instance of model_A_object when instantiating inlineformset_factory and, therefore, I can't just use this example. Any suggestions?

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  • Default value for hidden field in Django model

    - by Daniel Garcia
    I have this Model: class Occurrence(models.Model): id = models.AutoField(primary_key=True, null=True) reference = models.IntegerField(null=True, editable=False) def save(self): self.collection = self.id super(Occurrence, self).save() I want for the reference field to be hidden and at the same time have the same value as id. This code works if the editable=True but if i want to hide it it doesnt change the value of reference. how can i fix that?

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  • Django models avaoid duplicates

    - by Hulk
    In models, class Getdata(models.Model): title = models.CharField(max_length=255) state = models.CharField(max_length=2, choices=STATE, default="0") name = models.ForeignKey(School) created_by = models.ForeignKey(profile) def __unicode__(self): return self.id() In templates <form> <input type="submit" save the data/> </form> If the user clicks on the save button and the above data is saved in the table how to avoid the duplicates,i.e, if the user again clicks on the same submit button there should not be another entry for the same values.Or is it some this that has to be handeled in views Thanks..

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  • Django make model field name a link

    - by Daniel Garcia
    what Im looking to do is to have a link on the name of a field of a model. So when im filling the form using the admin interface i can access some information. I know this doesn't work but shows what i want to do class A(models.Model): item_type = models.CharField(max_length=100, choices=ITEMTYPE_CHOICES, verbose_name="<a href='http://www.quackit.com/html/codes'>Item Type</a>") Other option would be to put a description next to the field. Im not even sure where to start from.

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  • Django models avoid duplicates

    - by Hulk
    In models, class Getdata(models.Model): title = models.CharField(max_length=255) state = models.CharField(max_length=2, choices=STATE, default="0") name = models.ForeignKey(School) created_by = models.ForeignKey(profile) def __unicode__(self): return self.id() In templates <form> <input type="submit" save the data/> </form> If the user clicks on the save button and the above data is saved in the table how to avoid the duplicates,i.e, if the user again clicks on the same submit button there should not be another entry for the same values.Or is it some this that has to be handeled in views Thanks..

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  • Multiple model forms with some pre-populated fields

    - by jimbocooper
    Hi! Hope somebody can help me, since I've been stuck for a while with this... I switched to another task, but now back to the fight I still can't figure out how to come out from the black hole xD The thing is as follows: Let's say I've got a product model, and then a set of Clients which have rights to submit data for the products they've been subscribed (Many to Many from Client to Product). Whenever my client is going to submit data, I need to create as many forms as products he's subscribed, and pre-populate each one of them with the "product" field as long as perform a quite simple validation (some optional fields have to be completed if it's client's first submission). I would like one form "step" for each product submission, so I've tried formWizards... but the problem is you can't pre-assign values to the forms... this can be solved afterwards when submitting, though... but not the problem that it doesn't allow validation either, so at the end of each step I can check some data before rendering next step. Then I've tried model formsets, but then there's no way to pre-populate the needed fields. I came across some django plugins, but I'm not confident yet if any of them will make it.... Did anybody has a similar problem so he can give me a ray of light? Thanks a lot in advance!! :) edit: The code I used in the formsets way is as follows: prods = Products.objects.filter(Q(start_date__lte=today) & Q(end_date__gte=today), requester=client) num = len(prods) PriceSubmissionFormSet = modelformset_factory(PriceSubmission, extra=num) formset = PriceSubmissionFormSet(queryset=PriceSubmission.objects.none())

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  • Django: What's an awesome plugin to maintain images in the admin?

    - by meder
    I have an articles entry model and I have an excerpt and description field. If a user wants to post an image then I have a separate ImageField which has the default standard file browser. I've tried using django-filebrowser but I don't like the fact that it requires django-grappelli nor do I necessarily want a flash upload utility - can anyone recommend a tool where I can manage image uploads, and basically replace the file browse provided by django with an imagepicking browser? In the future I'd probably want it to handle image resizing and specify default image sizes for certain article types. Edit: I'm trying out adminfiles now but I'm having issues installing it. I grabbed it and added it to my python path, added it to INSTALLED_APPS, created the databases for it, uploaded an image. I followed the instructions to modify my Model to specify adminfiles_fields and registered but it's not applying in my admin, here's my admin.py for articles: from django.contrib import admin from django import forms from articles.models import Category, Entry from tinymce.widgets import TinyMCE from adminfiles.admin import FilePickerAdmin class EntryForm( forms.ModelForm ): class Media: js = ['/media/tinymce/tiny_mce.js', '/media/tinymce/load.js']#, '/media/admin/filebrowser/js/TinyMCEAdmin.js'] class Meta: model = Entry class CategoryAdmin(admin.ModelAdmin): prepopulated_fields = { 'slug': ['title'] } class EntryAdmin( FilePickerAdmin ): adminfiles_fields = ('excerpt',) prepopulated_fields = { 'slug': ['title'] } form = EntryForm admin.site.register( Category, CategoryAdmin ) admin.site.register( Entry, EntryAdmin ) Here's my Entry model: class Entry( models.Model ): LIVE_STATUS = 1 DRAFT_STATUS = 2 HIDDEN_STATUS = 3 STATUS_CHOICES = ( ( LIVE_STATUS, 'Live' ), ( DRAFT_STATUS, 'Draft' ), ( HIDDEN_STATUS, 'Hidden' ), ) status = models.IntegerField( choices=STATUS_CHOICES, default=LIVE_STATUS ) tags = TagField() categories = models.ManyToManyField( Category ) title = models.CharField( max_length=250 ) excerpt = models.TextField( blank=True ) excerpt_html = models.TextField(editable=False, blank=True) body_html = models.TextField( editable=False, blank=True ) article_image = models.ImageField(blank=True, upload_to='upload') body = models.TextField() enable_comments = models.BooleanField(default=True) pub_date = models.DateTimeField(default=datetime.datetime.now) slug = models.SlugField(unique_for_date='pub_date') author = models.ForeignKey(User) featured = models.BooleanField(default=False) def save( self, force_insert=False, force_update= False): self.body_html = markdown(self.body) if self.excerpt: self.excerpt_html = markdown( self.excerpt ) super( Entry, self ).save( force_insert, force_update ) class Meta: ordering = ['-pub_date'] verbose_name_plural = "Entries" def __unicode__(self): return self.title Edit #2: To clarify I did move the media files to my media path and they are indeed rendering the image area, I can upload fine, the <<<image>>> tag is inserted into my editable MarkItUp w/ Markdown area but it isn't rendering in the MarkItUp preview - perhaps I just need to apply the |upload_tags into that preview. I'll try adding it to my template which posts the article as well.

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  • Problem with messages framework in Django 1.2

    - by Konstantin
    Hello! I'm running Django 1.2 beta and trying out the new feature: message framework. http://docs.djangoproject.com/en/dev/ref/contrib/messages/ Everything seems to work, but when I try to output the messages, I get nothing. Seems that messages variable is empty. I double checked all the settings, they seem to be just like in the manual. What could be wrong? settings.py MIDDLEWARE_CLASSES = ( 'django.middleware.common.CommonMiddleware', 'django.contrib.sessions.middleware.SessionMiddleware', 'django.contrib.messages.middleware.MessageMiddleware', #send messages to users 'django.middleware.locale.LocaleMiddleware', 'django.contrib.auth.middleware.AuthenticationMiddleware', #debug tool 'debug_toolbar.middleware.DebugToolbarMiddleware', ) TEMPLATE_CONTEXT_PROCESSORS = ( 'django.contrib.messages.context_processors.messages', #send messages to users 'django.core.context_processors.auth', ) #Store messages in sessions MESSAGE_STORAGE = 'django.contrib.messages.storage.session.SessionStorage'; INSTALLED_APPS = ( 'django.contrib.auth', 'django.contrib.contenttypes', 'django.contrib.sessions', #'django.contrib.sites', 'django.contrib.admin', 'django.contrib.messages', 'debug_toolbar', #my apps #... ) views.py def myview(request): from django.contrib import messages messages.error(request, 'error test'); messages.success(request, 'success test'); return render_to_response('mytemplate.html', locals()); mytemplate.html {% for message in messages %} {{ message }}<br /> {% endfor %} In template nothing is outputted.

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  • Django 1.4.1 error loading MySQLdb module when attempting 'python manage.py shell'

    - by Paul
    I am trying to set up MySQL, and can't seem to be able to enter the Django manage.py shell interpreter. Getting the output below: rrdhcp-10-32-44-126:django pavelfage$ python manage.py shell Traceback (most recent call last): File "manage.py", line 10, in <module> execute_from_command_line(sys.argv) File "/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/site-packages/django/core/management/__init__.py", line 443, in execute_from_command_line utility.execute() File "/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/site-packages/django/core/management/__init__.py", line 382, in execute self.fetch_command(subcommand).run_from_argv(self.argv) File "/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/site-packages/django/core/management/base.py", line 196, in run_from_argv self.execute(*args, **options.__dict__) File "/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/site-packages/django/core/management/base.py", line 232, in execute output = self.handle(*args, **options) File "/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/site-packages/django/core/management/base.py", line 371, in handle return self.handle_noargs(**options) File "/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/site-packages/django/core/management/commands/shell.py", line 45, in handle_noargs from django.db.models.loading import get_models File "/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/site-packages/django/db/__init__.py", line 40, in <module> backend = load_backend(connection.settings_dict['ENGINE']) File "/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/site-packages/django/db/__init__.py", line 34, in __getattr__ return getattr(connections[DEFAULT_DB_ALIAS], item) File "/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/site-packages/django/db/utils.py", line 92, in __getitem__ backend = load_backend(db['ENGINE']) File "/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/site-packages/django/db/utils.py", line 24, in load_backend return import_module('.base', backend_name) File "/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/site-packages/django/utils/importlib.py", line 35, in import_module __import__(name) File "/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/site-packages/django/db/backends/mysql/base.py", line 16, in <module> raise ImproperlyConfigured("Error loading MySQLdb module: %s" % e) django.core.exceptions.ImproperlyConfigured: Error loading MySQLdb module: No module named _mysql Any suggestions really appreciated.

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  • How to resolve user registration and activation email error in Django registration?

    - by user2476295
    So I was just trying to setup a basic user authentication in Django and downloaded a django registration app with templates. Now when I run the server at 127.0.0.1:8000/accounts/register/ I get a basic registration page, I fill in the details and when I click submit I get this error "NoReverseMatch at /accounts/register/" Error during template rendering In template Users/sudhasinha/mysite/mysite/registration/templates/registration/activation_email.txt, error at line 4 'url' requires a non-empty first argument. The syntax changed in Django 1.5, see the docs. 1 {% load i18n %} 2 {% trans "Activate account at" %} {{ site.name }}: 3 4 http://{{ site.domain }}{**% url registration_activate activation_key %**} 5 6 {% blocktrans %}Link is valid for {{ expiration_days }} days.{% endblocktrans %} 7 This is what my activation_email.txt looks like: {% load i18n %} {% trans "Activate account at" %} {{ site.name }}: http://{{ site.domain }}{% url registration_activate activation_key %} {% blocktrans %}Link is valid for {{ expiration_days }} days.{% endblocktrans %} And this is what my registration_form.html looks like: {% extends "base.html" %} {% load i18n %} {% block content %} <form method="post" action="."> {{ form.as_p }} <input type="submit" value="{% trans 'Submit' %}" /> </form> {% endblock %} I have very minimal experience with Django and would appreciate some help to resolve this error. My urls seem to be setup correctly but I will post it if needed. Also pardon my horrible formatting

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  • Can Django admin handle a one-to-many relationship via related_name?

    - by Mat
    The Django admin happily supports many-to-one and many-to-many relationships through an HTML <SELECT> form field, allowing selection of one or many options respectively. There's even a nice Javascript filter_horizontal widget to help. I'm trying to do the same from the one-to-many side through related_name. I don't see how it's much different from many-to-many as far as displaying it in the form is concerned, I just need a multi-select SELECT list. But I cannot simply add the related_name value to my ModelAdmin-derived field list. Does Django support one-to-many fields in this way? My Django model something like this (contrived to simplify the example): class Person(models.Model): ... manager = models.ForeignKey('self', related_name='staff', null=True, blank=True, ) From the Person admin page, I can easily get a <SELECT> list showing all possible staff to choose this person's manager from. I also want to display a multiple-selection <SELECT> list of all the manager's staff. I don't want to use inlines, as I don't want to edit the subordinates details; I do want to be able to add/remove people from the list. (I'm trying to use django-ajax-selects to replace the SELECT widget, but that's by-the-by.)

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  • Django - no module named app

    - by Koran
    Hi, I have been trying to get an application written in django working - but it is not working at all. I have been working on for some time too - and it is working on dev-server perfectly. But I am unable to put in the production env (apahce). My project name is apstat and the app name is basic. I try to access it as following Blockquote http://hostname/apstat But it shows the following error: MOD_PYTHON ERROR ProcessId: 6002 Interpreter: 'domU-12-31-39-06-DD-F4.compute-1.internal' ServerName: 'domU-12-31-39-06-DD-F4.compute-1.internal' DocumentRoot: '/home/ubuntu/server/' URI: '/apstat/' Location: '/apstat' Directory: None Filename: '/home/ubuntu/server/apstat/' PathInfo: '' Phase: 'PythonHandler' Handler: 'django.core.handlers.modpython' Traceback (most recent call last): File "/usr/lib/python2.6/dist-packages/mod_python/importer.py", line 1537, in HandlerDispatch default=default_handler, arg=req, silent=hlist.silent) File "/usr/lib/python2.6/dist-packages/mod_python/importer.py", line 1229, in _process_target result = _execute_target(config, req, object, arg) File "/usr/lib/python2.6/dist-packages/mod_python/importer.py", line 1128, in _execute_target result = object(arg) File "/usr/lib/pymodules/python2.6/django/core/handlers/modpython.py", line 228, in handler return ModPythonHandler()(req) File "/usr/lib/pymodules/python2.6/django/core/handlers/modpython.py", line 201, in __call__ response = self.get_response(request) File "/usr/lib/pymodules/python2.6/django/core/handlers/base.py", line 134, in get_response return self.handle_uncaught_exception(request, resolver, exc_info) File "/usr/lib/pymodules/python2.6/django/core/handlers/base.py", line 154, in handle_uncaught_exception return debug.technical_500_response(request, *exc_info) File "/usr/lib/pymodules/python2.6/django/views/debug.py", line 40, in technical_500_response html = reporter.get_traceback_html() File "/usr/lib/pymodules/python2.6/django/views/debug.py", line 114, in get_traceback_html return t.render(c) File "/usr/lib/pymodules/python2.6/django/template/__init__.py", line 178, in render return self.nodelist.render(context) File "/usr/lib/pymodules/python2.6/django/template/__init__.py", line 779, in render bits.append(self.render_node(node, context)) File "/usr/lib/pymodules/python2.6/django/template/debug.py", line 81, in render_node raise wrapped TemplateSyntaxError: Caught an exception while rendering: No module named basic Original Traceback (most recent call last): File "/usr/lib/pymodules/python2.6/django/template/debug.py", line 71, in render_node result = node.render(context) File "/usr/lib/pymodules/python2.6/django/template/debug.py", line 87, in render output = force_unicode(self.filter_expression.resolve(context)) File "/usr/lib/pymodules/python2.6/django/template/__init__.py", line 572, in resolve new_obj = func(obj, *arg_vals) File "/usr/lib/pymodules/python2.6/django/template/defaultfilters.py", line 687, in date return format(value, arg) File "/usr/lib/pymodules/python2.6/django/utils/dateformat.py", line 269, in format return df.format(format_string) File "/usr/lib/pymodules/python2.6/django/utils/dateformat.py", line 30, in format pieces.append(force_unicode(getattr(self, piece)())) File "/usr/lib/pymodules/python2.6/django/utils/dateformat.py", line 175, in r return self.format('D, j M Y H:i:s O') File "/usr/lib/pymodules/python2.6/django/utils/dateformat.py", line 30, in format pieces.append(force_unicode(getattr(self, piece)())) File "/usr/lib/pymodules/python2.6/django/utils/encoding.py", line 71, in force_unicode s = unicode(s) File "/usr/lib/pymodules/python2.6/django/utils/functional.py", line 201, in __unicode_cast return self.__func(*self.__args, **self.__kw) File "/usr/lib/pymodules/python2.6/django/utils/translation/__init__.py", line 62, in ugettext return real_ugettext(message) File "/usr/lib/pymodules/python2.6/django/utils/translation/trans_real.py", line 286, in ugettext return do_translate(message, 'ugettext') File "/usr/lib/pymodules/python2.6/django/utils/translation/trans_real.py", line 276, in do_translate _default = translation(settings.LANGUAGE_CODE) File "/usr/lib/pymodules/python2.6/django/utils/translation/trans_real.py", line 194, in translation default_translation = _fetch(settings.LANGUAGE_CODE) File "/usr/lib/pymodules/python2.6/django/utils/translation/trans_real.py", line 180, in _fetch app = import_module(appname) File "/usr/lib/pymodules/python2.6/django/utils/importlib.py", line 35, in import_module __import__(name) ImportError: No module named basic My settings.py is as follows: INSTALLED_APPS = ( 'django.contrib.auth', 'django.contrib.contenttypes', 'django.contrib.sessions', 'django.contrib.sites', 'apstat.basic', 'django.contrib.admin', ) If I remove the apstat.basic, it goes through, but that is not a solution. Is it something I am doing in apache? My apache - settings are - <VirtualHost *:80> ServerAdmin webmaster@localhost DocumentRoot /home/ubuntu/server/ <Directory /> Options None AllowOverride None </Directory> <Directory /home/ubuntu/server/apstat> AllowOverride None Order allow,deny allow from all </Directory> <Location "/apstat"> SetHandler python-program PythonHandler django.core.handlers.modpython SetEnv DJANGO_SETTINGS_MODULE apstat.settings PythonOption django.root /home/ubuntu/server/ PythonDebug On PythonPath "['/home/ubuntu/server/'] + sys.path" </Location> </VirtualHost> I have now sat for more than a day on this. If someone can help me out, it would be very nice.

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  • Error after installing Django (supposed PATH or PYTHONPATH "error")

    - by illuminated
    Hi all, I guess this is a PATH/PYTHONPATH error, but my attempts failed so far to make django working. System is Ubuntu 10.04, 64bit: mx:~/webapps$ cat /etc/lsb-release DISTRIB_ID=Ubuntu DISTRIB_RELEASE=10.04 DISTRIB_CODENAME=lucid DISTRIB_DESCRIPTION="Ubuntu 10.04 LTS" Python version: 2.6.5: @mx:~/webapps$ python -V Python 2.6.5 When I run django-admin.py, the following happens: mx:~/webapps$ django-admin.py Traceback (most recent call last): File "/usr/local/bin/django-admin.py", line 2, in <module> from django.core import management ImportError: No module named django.core Similar when I import django in python shell: mx:~/webapps$ python Python 2.6.5 (r265:79063, Apr 16 2010, 13:09:56) [GCC 4.4.3] on linux2 Type "help", "copyright", "credits" or "license" for more information. >>> import django Traceback (most recent call last): File "<stdin>", line 1, in <module> ImportError: No module named django >>> quit() More details: mx:~/webapps$ python -c "from distutils.sysconfig import get_python_lib; print get_python_lib()" /usr/lib/python2.6/dist-packages Within python shell: Python 2.6.5 (r265:79063, Apr 16 2010, 13:09:56) [GCC 4.4.3] on linux2 Type "help", "copyright", "credits" or "license" for more information. >>> import sys >>> print sys.path ['', '/usr/lib/python2.6/dist-packages/django', '/usr/local/lib/python2.6/dist-packages/django/bin', '/usr/local/lib/python2.6/dist-packages/django', '/home/petra/webapps', '/usr/lib/python2.6', '/usr/lib/python2.6/plat-linux2', '/usr/lib/python2.6/lib-tk', '/usr/lib/python2.6/lib-old', '/usr/lib/python2.6/lib-dynload', '/usr/lib/python2.6/dist-packages', '/usr/lib/python2.6/dist-packages/PIL', '/usr/lib/pymodules/python2.6'] django-admin.py can be found here: mx:~/webapps$ locate django-admin.py ~/install/sources/Django-1.2.1/build/lib.linux-i686-2.6/django/bin/django-admin.py ~/install/sources/Django-1.2.1/build/scripts-2.6/django-admin.py ~/install/sources/Django-1.2.1/django/bin/django-admin.py /usr/local/bin/django-admin.py /usr/local/lib/python2.6/dist-packages/django/bin/django-admin.py /usr/local/lib/python2.6/dist-packages/django/bin/django-admin.pyc and in the end this doesn't help: export PYTHONPATH="/usr/lib/python2.6/dist-packages/django:$PYTHONPATH" nor this: export PYTHONPATH="/usr/local/lib/python2.6/dist-packages/django:$PYTHONPATH" How to solve this !? Thanks all in advance! :)

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  • Django Foreign key queries

    - by Hulk
    In the following model: class header(models.Model): title = models.CharField(max_length = 255) created_by = models.CharField(max_length = 255) def __unicode__(self): return self.id() class criteria(models.Model): details = models.CharField(max_length = 255) headerid = models.ForeignKey(header) def __unicode__(self): return self.id() class options(models.Model): opt_details = models.CharField(max_length = 255) headerid = models.ForeignKey(header) def __unicode__(self): return self.id() If there is a row in the database for table header as Id=1, title=value-mart , createdby=CEO How do i query criteria and options tables to get all the values related to header table id=1 Also can some one please suggest a good link for queries examples, Thanks..

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  • Djangoo Foreign key queries

    - by Hulk
    In the following model: class header(models.Model): title = models.CharField(max_length = 255) created_by = models.CharField(max_length = 255) def __unicode__(self): return self.id() class criteria(models.Model): details = models.CharField(max_length = 255) headerid = models.ForeignKey(header) def __unicode__(self): return self.id() class options(models.Model): opt_details = models.CharField(max_length = 255) headerid = models.ForeignKey(header) def __unicode__(self): return self.id() If there is a row in the database for table header as Id=1, title=value-mart , createdby=CEO How do i query criteria and options tables to get all the values related to header table id=1 Also can some one please suggest a good link for queries examples, Thanks..

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  • django internationalization doesn't work

    - by xRobot
    I have: created translation strings in the template and in the application view. run this command: django-admin.py makemessages -l it and the file it/LC_MESSAGES/django.po has been created run this command: django-admin.py compilemessages and I receive: processing file django.po in /home/jobber/Desktop/library/books/locale/it/LC_MESSAGES set the language code in settings.py: LANGUAGE_CODE = 'it-IT' but.... translation doesn't work !! I always see english text. Why ?

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  • ** EDITED ** 'NoneType' object has no attribute 'day'

    - by Asinox
    Hi guy, i dont know where is my error, but Django 1.2.1 is give this error: 'NoneType' object has no attribute 'day' when i try to save form from the Administrator Area models.py from django.db import models from django.contrib.auth.models import User class Editorial(models.Model): titulo = models.CharField(max_length=250,help_text='Titulo del editorial') editorial = models.TextField(help_text='Editorial') slug = models.SlugField(unique_for_date='pub_date') autor = models.ForeignKey(User) pub_date = models.DateTimeField(auto_now_add=True) activa = models.BooleanField(verbose_name="Activa") enable_comments = models.BooleanField(verbose_name="Aceptar Comentarios",default=False) editorial_html = models.TextField(editable=False,blank=True) def __unicode__(self): return unicode(self.titulo) def get_absolute_url(self): return "/editorial/%s/%s/" % (self.pub_date.strftime("%Y/%b/%d").lower(), self.slug) class Meta: ordering=['-pub_date'] verbose_name_plural ='Editoriales' def save(self,force_insert=False, force_update=False): from markdown import markdown if self.editorial: self.editorial_html = markdown(self.editorial) super(Editorial,self).save(force_insert,force_update) i dont know why this error, COMPLETED ERROR: Traceback: File "C:\wamp\bin\Python26\lib\site-packages\django\core\handlers\base.py" in get_response 100. response = callback(request, *callback_args, **callback_kwargs) File "C:\wamp\bin\Python26\lib\site-packages\django\contrib\admin\options.py" in wrapper 239. return self.admin_site.admin_view(view)(*args, **kwargs) File "C:\wamp\bin\Python26\lib\site-packages\django\utils\decorators.py" in _wrapped_view 76. response = view_func(request, *args, **kwargs) File "C:\wamp\bin\Python26\lib\site-packages\django\views\decorators\cache.py" in _wrapped_view_func 69. response = view_func(request, *args, **kwargs) File "C:\wamp\bin\Python26\lib\site-packages\django\contrib\admin\sites.py" in inner 190. return view(request, *args, **kwargs) File "C:\wamp\bin\Python26\lib\site-packages\django\utils\decorators.py" in _wrapper 21. return decorator(bound_func)(*args, **kwargs) File "C:\wamp\bin\Python26\lib\site-packages\django\utils\decorators.py" in _wrapped_view 76. response = view_func(request, *args, **kwargs) File "C:\wamp\bin\Python26\lib\site-packages\django\utils\decorators.py" in bound_func 17. return func(self, *args2, **kwargs2) File "C:\wamp\bin\Python26\lib\site-packages\django\db\transaction.py" in _commit_on_success 299. res = func(*args, **kw) File "C:\wamp\bin\Python26\lib\site-packages\django\contrib\admin\options.py" in add_view 777. if form.is_valid(): File "C:\wamp\bin\Python26\lib\site-packages\django\forms\forms.py" in is_valid 121. return self.is_bound and not bool(self.errors) File "C:\wamp\bin\Python26\lib\site-packages\django\forms\forms.py" in _get_errors 112. self.full_clean() File "C:\wamp\bin\Python26\lib\site-packages\django\forms\forms.py" in full_clean 269. self._post_clean() File "C:\wamp\bin\Python26\lib\site-packages\django\forms\models.py" in _post_clean 345. self.validate_unique() File "C:\wamp\bin\Python26\lib\site-packages\django\forms\models.py" in validate_unique 354. self.instance.validate_unique(exclude=exclude) File "C:\wamp\bin\Python26\lib\site-packages\django\db\models\base.py" in validate_unique 695. date_errors = self._perform_date_checks(date_checks) File "C:\wamp\bin\Python26\lib\site-packages\django\db\models\base.py" in _perform_date_checks 802. lookup_kwargs['%s__day' % unique_for] = date.day Exception Type: AttributeError at /admin/editoriales/editorial/add/ Exception Value: 'NoneType' object has no attribute 'day' thanks guys sorry with my English

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  • So now that Django 1.2 is officially out...

    - by Fedor
    Since I have Django 1.1x on my Debian setup - how can I use virtualenv or similar and not have it mess up my system's default django version which in turn would break all my sites? Detailed instructions or a great tutorial link would very much be appreciated - please don't offer vague advice since I'm still a noob. Currently I store all my django projects in ~/django-sites and I am using Apache2 + mod_wsgi to deploy.

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  • Django-Registration & Django-Profile, using your own custom form

    - by Issy
    Hey All, I am making use of django-registration and django-profile to handle registration and profiles. I would like to create a profile for the user at the time of registration. I have created a custom registration form, and added that to the urls.py using the tutorial on: http://dewful.com/?p=70 The basic idea in the tutorial is to override the default registration form to create the profile at the same time. forms.py - In my profiles app from django import forms from registration.forms import RegistrationForm from django.utils.translation import ugettext_lazy as _ from profiles.models import UserProfile from registration.models import RegistrationProfile attrs_dict = { 'class': 'required' } class UserRegistrationForm(RegistrationForm): city = forms.CharField(widget=forms.TextInput(attrs=attrs_dict)) def save(self, profile_callback=None): new_user = RegistrationProfile.objects.create_inactive_user(username=self.cleaned_data['username'], password=self.cleaned_data['password1'], email=self.cleaned_data['email']) new_profile = UserProfile(user=new_user, city=self.cleaned_data['city']) new_profile.save() return new_user In urls.py from profiles.forms import UserRegistrationForm and url(r'^register/$', register, {'backend': 'registration.backends.default.DefaultBackend', 'form_class' : UserRegistrationForm}, name='registration_register'), The form is displayed, and i can enter in City, however it does not save or create the entry in the DB.

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  • django error ,about django-sphinx

    - by zjm1126
    from django.db import models from djangosphinx.models import SphinxSearch class MyModel(models.Model): search = SphinxSearch() # optional: defaults to db_table # If your index name does not match MyModel._meta.db_table # Note: You can only generate automatic configurations from the ./manage.py script # if your index name matches. search = SphinxSearch('index_name') # Or maybe we want to be more.. specific searchdelta = SphinxSearch( index='index_name delta_name', weights={ 'name': 100, 'description': 10, 'tags': 80, }, mode='SPH_MATCH_ALL', rankmode='SPH_RANK_NONE', ) queryset = MyModel.search.query('query') results1 = queryset.order_by('@weight', '@id', 'my_attribute') results2 = queryset.filter(my_attribute=5) results3 = queryset.filter(my_other_attribute=[5, 3,4]) results4 = queryset.exclude(my_attribute=5)[0:10] results5 = queryset.count() # as of 2.0 you can now access an attribute to get the weight and similar arguments for result in results1: print result, result._sphinx # you can also access a similar set of meta data on the queryset itself (once it's been sliced or executed in any way) print results1._sphinx and Traceback (most recent call last): File "D:\zjm_code\sphinx_test\models.py", line 1, in <module> from django.db import models File "D:\Python25\Lib\site-packages\django\db\__init__.py", line 10, in <module> if not settings.DATABASE_ENGINE: File "D:\Python25\Lib\site-packages\django\utils\functional.py", line 269, in __getattr__ self._setup() File "D:\Python25\Lib\site-packages\django\conf\__init__.py", line 38, in _setup raise ImportError("Settings cannot be imported, because environment variable %s is undefined." % ENVIRONMENT_VARIABLE) ImportError: Settings cannot be imported, because environment variable DJANGO_SETTINGS_MODULE is undefined.

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  • Django TemplateSyntaxError only on live server (templates exist)

    - by Tom
    I'm getting a strange error that only occurs on the live server. My Django templates directory is set up like so base.html two-column-base.html portfolio index.html extranet base.html index.html The portfolio pages work correctly locally on multiple machines. They inherit from either the root base.html or two-column-base.html. However, now that I've posted them to the live box (local machines are Windows, live is Linux), I get a TemplateSyntaxError: "Caught TemplateDoesNotExist while rendering: base.html" when I try to load any portfolio pages. It seems to be a case where the extends tag won't work in that root directory (???). Even if I do a direct_to_template on two-column-base.html (which extends base.html), I get that error. The extranet pages all work perfectly, but those templates all live inside the /extranet folder and inherit from /extranet/base.html. Possible issues I've checked: file permissions on the server are fine the template directory is correct on the live box (I'm using os.path.dirname(os.path.realpath(__file__)) to make things work across machines) files exist and the /templates directories exactly match my local copy removing the {% extends %} block from the top of any broken template causes the templates to render without a problem manually starting a shell session and calling get_template on any of the files works, but trying to render it blows up with the same exception on any of the extended templates. Doing the same with base.html, it renders perfectly (base.html also renders via direct_to_template) Django 1.2, Python 2.6 on Webfaction. Apologies in advance because this is my 3rd or 4th "I'm doing something stupid" question in a row. The only x-factor I can think of is this is my first time using Mercurial instead ofsvn. Not sure how I could have messed things up via that. EDIT: One possible source of problems: local machine is Python 2.5, live is 2.6. Here's a traceback of me trying to render 'two-column-base.html', which extends 'base.html'. Both files are in the same directory, so if it can find the first, it can find the second. c is just an empty Context object. >>> render_to_string('two-column-base.html', c) Traceback (most recent call last): File "<console>", line 1, in <module> File "/home/lightfin/webapps/django/lib/python2.6/django/template/loader.py", line 186, in render_to_string return t.render(context_instance) File "/home/lightfin/webapps/django/lib/python2.6/django/template/__init__.py", line 173, in render return self._render(context) File "/home/lightfin/webapps/django/lib/python2.6/django/template/__init__.py", line 167, in _render return self.nodelist.render(context) File "/home/lightfin/webapps/django/lib/python2.6/django/template/__init__.py", line 796, in render bits.append(self.render_node(node, context)) File "/home/lightfin/webapps/django/lib/python2.6/django/template/debug.py", line 72, in render_node result = node.render(context) File "/home/lightfin/webapps/django/lib/python2.6/django/template/loader_tags.py", line 103, in render compiled_parent = self.get_parent(context) File "/home/lightfin/webapps/django/lib/python2.6/django/template/loader_tags.py", line 100, in get_parent return get_template(parent) File "/home/lightfin/webapps/django/lib/python2.6/django/template/loader.py", line 157, in get_template template, origin = find_template(template_name) File "/home/lightfin/webapps/django/lib/python2.6/django/template/loader.py", line 138, in find_template raise TemplateDoesNotExist(name) TemplateSyntaxError: Caught TemplateDoesNotExist while rendering: base.html I'm wondering if this is somehow related to the template caching that was just added to Django. EDIT 2 (per lazerscience): template-related settings: import os PROJECT_ROOT = os.path.dirname(os.path.realpath(__file__)) TEMPLATE_DIRS = ( os.path.join(PROJECT_ROOT, 'templates'), ) sample view: def project_list(request, jobs, extra_context={}): context = { 'jobs': jobs, } print context context.update(extra_context) return render_to_response('portfolio/index.html', context, context_instance=RequestContext(request)) The templates in reverse-order are: http://thosecleverkids.com/junk/index.html http://thosecleverkids.com/junk/portfolio-base.html http://thosecleverkids.com/junk/two-column-base.html http://thosecleverkids.com/junk/base.html though in the real project the first two live in a directory called "portfolio".

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  • Mobile Friendly Websites with CSS Media Queries

    - by dwahlin
    In a previous post the concept of CSS media queries was introduced and I discussed the fundamentals of how they can be used to target different screen sizes. I showed how they could be used to convert a 3-column wide page into a more vertical view of data that displays better on devices such as an iPhone:     In this post I'll provide an additional look at how CSS media queries can be used to mobile-enable a sample site called "Widget Masters" without having to change any server-side code or HTML code. The site that will be discussed is shown next:     This site has some of the standard items shown in most websites today including a title area, menu bar, and sections where data is displayed. Without including CSS media queries the site is readable but has to be zoomed out to see everything on a mobile device, cuts-off some of the menu items, and requires horizontal scrolling to get to additional content. The following image shows what the site looks like on an iPhone. While the site works on mobile devices it's definitely not optimized for mobile.     Let's take a look at how CSS media queries can be used to override existing styles in the site based on different screen widths. Adding CSS Media Queries into a Site The Widget Masters Website relies on standard CSS combined with HTML5 elements to provide the layout shown earlier. For example, to layout the menu bar shown at the top of the page the nav element is used as shown next. A standard div element could certainly be used as well if desired.   <nav> <ul class="clearfix"> <li><a href="#home">Home</a></li> <li><a href="#products">Products</a></li> <li><a href="#aboutus">About Us</a></li> <li><a href="#contactus">Contact Us</a></li> <li><a href="#store">Store</a></li> </ul> </nav>   This HTML is combined with the CSS shown next to add a CSS3 gradient, handle the horizontal orientation, and add some general hover effects.   nav { width: 100%; } nav ul { border-radius: 6px; height: 40px; width: 100%; margin: 0; padding: 0; background: rgb(125,126,125); /* Old browsers */ background: -moz-linear-gradient(top, rgba(125,126,125,1) 0%, rgba(14,14,14,1) 100%); /* FF3.6+ */ background: -webkit-gradient(linear, left top, left bottom, color-stop(0%,rgba(125,126,125,1)), color-stop(100%,rgba(14,14,14,1))); /* Chrome,Safari4+ */ background: -webkit-linear-gradient(top, rgba(125,126,125,1) 0%, rgba(14,14,14,1) 100%); /* Chrome10+,Safari5.1+ */ background: -o-linear-gradient(top, rgba(125,126,125,1) 0%, rgba(14,14,14,1) 100%); /* Opera 11.10+ */ background: -ms-linear-gradient(top, rgba(125,126,125,1) 0%, rgba(14,14,14,1) 100%); /* IE10+ */ background: linear-gradient(top, rgba(125,126,125,1) 0%, rgba(14,14,14,1) 100%); /* W3C */ filter: progid:DXImageTransform.Microsoft.gradient( startColorstr='#7d7e7d', endColorstr='#0e0e0e',GradientType=0 ); /* IE6-9 */ } nav ul > li { list-style: none; float: left; margin: 0; padding: 0; } nav ul > li:first-child { margin-left: 8px; } nav ul > li > a { color: #ccc; text-decoration: none; line-height: 2.8em; font-size: 0.95em; font-weight: bold; padding: 8px 25px 7px 25px; font-family: Arial, Helvetica, sans-serif; } nav ul > li a:hover { background-color: rgba(0, 0, 0, 0.1); color: #fff; }   When mobile devices hit the site the layout of the menu items needs to be adjusted so that they're all visible without having to swipe left or right to get to them. This type of modification can be accomplished using CSS media queries by targeting specific screen sizes. To start, a media query can be added into the site's CSS file as shown next: @media screen and (max-width:320px) { /* CSS style overrides for this screen width go here */ } This media query targets screens that have a maximum width of 320 pixels. Additional types of queries can also be added – refer to my previous post for more details as well as resources that can be used to test media queries in different devices. In that post I emphasize (and I'll emphasize again) that CSS media queries only modify the overall layout and look and feel of a site. They don't optimize the site as far as the size of the images or content sent to the device which is important to keep in mind. To make the navigation menu more accessible on devices such as an iPhone or Android the CSS shown next can be used. This code changes the height of the menu from 40 pixels to 100%, takes off the li element floats, changes the line-height, and changes the margins.   @media screen and (max-width:320px) { nav ul { height: 100%; } nav ul > li { float: none; } nav ul > li a { line-height: 1.5em; } nav ul > li:first-child { margin-left: 0px; } /* Additional CSS overrides go here */ }   The following image shows an example of what the menu look like when run on a device with a width of 320 pixels:   Mobile devices with a maximum width of 480 pixels need different CSS styles applied since they have 160 additional pixels of width. This can be done by adding a new CSS media query into the stylesheet as shown next. Looking through the CSS you'll see that only a minimal override is added to adjust the padding of anchor tags since the menu fits by default in this screen width.   @media screen and (max-width: 480px) { nav ul > li > a { padding: 8px 10px 7px 10px; } }   Running the site on a device with 480 pixels results in the menu shown next being rendered. Notice that the space between the menu items is much smaller compared to what was shown when the main site loads in a standard browser.     In addition to modifying the menu, the 3 horizontal content sections shown earlier can be changed from a horizontal layout to a vertical layout so that they look good on a variety of smaller mobile devices and are easier to navigate by end users. The HTML5 article and section elements are used as containers for the 3 sections in the site as shown next:   <article class="clearfix"> <section id="info"> <header>Why Choose Us?</header> <br /> <img id="mainImage" src="Images/ArticleImage.png" title="Article Image" /> <p> Post emensos insuperabilis expeditionis eventus languentibus partium animis, quas periculorum varietas fregerat et laborum, nondum tubarum cessante clangore vel milite locato per stationes hibernas. </p> </section> <section id="products"> <header>Products</header> <br /> <img id="gearsImage" src="Images/Gears.png" title="Article Image" /> <p> <ul> <li>Widget 1</li> <li>Widget 2</li> <li>Widget 3</li> <li>Widget 4</li> <li>Widget 5</li> </ul> </p> </section> <section id="FAQ"> <header>FAQ</header> <br /> <img id="faqImage" src="Images/faq.png" title="Article Image" /> <p> <ul> <li>FAQ 1</li> <li>FAQ 2</li> <li>FAQ 3</li> <li>FAQ 4</li> <li>FAQ 5</li> </ul> </p> </section> </article>   To force the sections into a vertical layout for smaller mobile devices the CSS styles shown next can be added into the media queries targeting 320 pixel and 480 pixel widths. Styles to target the display size of the images in each section are also included. It's important to note that the original image is still being downloaded from the server and isn't being optimized in any way for the mobile device. It's certainly possible for the CSS to include URL information for a mobile-optimized image if desired. @media screen and (max-width:320px) { section { float: none; width: 97%; margin: 0px; padding: 5px; } #wrapper { padding: 5px; width: 96%; } #mainImage, #gearsImage, #faqImage { width: 100%; height: 100px; } } @media screen and (max-width: 480px) { section { float: none; width: 98%; margin: 0px 0px 10px 0px; padding: 5px; } article > section:last-child { margin-right: 0px; float: none; } #bottomSection { width: 99%; } #wrapper { padding: 5px; width: 96%; } #mainImage, #gearsImage, #faqImage { width: 100%; height: 100px; } }   The following images show the site rendered on an iPhone with the CSS media queries in place. Each of the sections now displays vertically making it much easier for the user to access them. Images inside of each section also scale appropriately to fit properly.     CSS media queries provide a great way to override default styles in a website and target devices with different resolutions. In this post you've seen how CSS media queries can be used to convert a standard browser-based site into a site that is more accessible to mobile users. Although much more can be done to optimize sites for mobile, CSS media queries provide a nice starting point if you don't have the time or resources to create mobile-specific versions of sites.

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  • Odd behavior in Django Form (readonly field/widget)

    - by jamida
    I'm having a problem with a test app I'm writing to verify some Django functionality. The test app is a small "grade book" application that is currently using Alex Gaynor's readonly field functionality http://lazypython.blogspot.com/2008/12/building-read-only-field-in-django.html There are 2 problems which may be related. First, when I flop the comment on these 2 lines below: # myform = GradeForm(data=request.POST, instance=mygrade) myform = GradeROForm(data=request.POST, instance=mygrade) it works like I expect, except of course that the student field is changeable. When the comments are the shown way, the "studentId" field is displayed as a number (not the name, problem 1) and when I hit submit I get an error saying that studentId needs to be a Student instance. I'm at a loss as to how to fix this. I'm not wedded to Alex Gaynor's code. ANY code will work. I'm relatively new to both Python and Django, so the hints I've seen on websites that say "making a read-only field is easy" are still beyond me. // models.py class Student(models.Model): name = models.CharField(max_length=50) parent = models.CharField(max_length=50) def __unicode__(self): return self.name class Grade(models.Model): studentId = models.ForeignKey(Student) finalGrade = models.CharField(max_length=3) # testbed.grades.readonly is alex gaynor's code from testbed.grades.readonly import ReadOnlyField class GradeROForm(ModelForm): studentId = ReadOnlyField() class Meta: model=Grade class GradeForm(ModelForm): class Meta: model=Grade // views.py def modifyGrade(request,student): student = Student.objects.get(name=student) mygrade = Grade.objects.get(studentId=student) if request.method == "POST": # myform = GradeForm(data=request.POST, instance=mygrade) myform = GradeROForm(data=request.POST, instance=mygrade) if myform.is_valid(): grade = myform.save() info = "successfully updated %s" % grade.studentId else: # myform=GradeForm(instance=mygrade) myform=GradeROForm(instance=mygrade) return render_to_response('grades/modifyGrade.html',locals()) // template <p>{{ info }}</p> <form method="POST" action=""> <table> {{ myform.as_table }} </table> <input type="submit" value="Submit"> </form> // Alex Gaynor's code from django import forms from django.utils.html import escape from django.utils.safestring import mark_safe from django.forms.util import flatatt class ReadOnlyWidget(forms.Widget): def render(self, name, value, attrs): final_attrs = self.build_attrs(attrs, name=name) if hasattr(self, 'initial'): value = self.initial return mark_safe("<span %s>%s</span>" % (flatatt(final_attrs), escape(value) or '')) def _has_changed(self, initial, data): return False class ReadOnlyField(forms.FileField): widget = ReadOnlyWidget def __init__(self, widget=None, label=None, initial=None, help_text=None): forms.Field.__init__(self, label=label, initial=initial, help_text=help_text, widget=widget) def clean(self, value, initial): self.widget.initial = initial return initial

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