Search Results

Search found 3674 results on 147 pages for 'django wsgi'.

Page 3/147 | < Previous Page | 1 2 3 4 5 6 7 8 9 10 11 12  | Next Page >

  • django modelformset - one form per related table row

    - by Toby
    Hello, I have two models: class Model1(): name = CharField() url = CharField() class Model2(): model1 = ForeignKey(Model1) user = ForeignKey(User) zzz = CharField() There are 5 rows for model1 in the database, these are fixed and will rarely change. I need to display a formset for model2 that allows users to enter the zzz value, the formset must always show one form per row in the model1 table, the label for each form in the formset must be the name of the related model1. If the user deletes a model2 in the formset the next time the page loads it will render an empty zzz value for that form and the user must be able to edit the previous zzz value - meaning it must be pre populated with all model2 rows associated with the user. The idea is to print each row in the model1 table as a form instead of the user selecting the related model1 name in a select box. I know its not that complicated, but I'm seriously stumped and keep going round in circles!! Many thanks in advance. Similar to http://stackoverflow.com/questions/298779/form-or-formset-to-handle-multiple-table-rows-in-django

    Read the article

  • django - dynamic form fieldsets

    - by user110029
    A form will be spitting out an unknown number of questions to be answered. each question contains a prompt, a value field, and a unit field. The form is built at runtime in the formclass's init method. I'd like each question rendered on the form as an inline: prompt, value(input-text), units (select). this seems a case perfect for iterable form fieldsets, which could be easily styled. but since fieldsets - such as those in django-form-utils are defined as tuples, they are immutable... and I can't find a way to define them at runtime. is this possible, or perhaps another solution?

    Read the article

  • Django: Adding inline formset rows without javascript

    - by Brant
    This post relates to this: http://stackoverflow.com/questions/520421/add-row-to-inlines-dynamically-in-django-admin Is there a way to achive adding inline formsets WITHOUT using javascript? Obviously, there would be a page-refresh involved. So, if the form had a button called 'add'... I figured I could do it like this: if request.method=='POST': if 'add' in request.POST: PrimaryFunctionFormSet = inlineformset_factory(Position,Function,extra=1) prims = PrimaryFunctionFormSet(request.POST) Which I thought would add 1 each time, then populate the form with the post data. However, it seems that the extra=1 does not add 1 to the post data.

    Read the article

  • How to display Django SelectDateWidget on one line using crispy forms

    - by Scott Johnson
    I am trying to display the 3 select fields that are rendered out using Django SelectDateWidget on one line. When I use crispy forms, they are all on separate rows. Is there a way to use the Layout helper to achieve this? Thank you! class WineAddForm(forms.ModelForm): hold_until = forms.DateField(widget=SelectDateWidget(years=range(1950, datetime.date.today().year+50)), required=False) drink_before = forms.DateField(widget=SelectDateWidget(years=range(1950, datetime.date.today().year+50)), required=False) helper = FormHelper() helper.form_method = 'POST' helper.form_class = 'form-horizontal' helper.label_class = 'col-lg-2' helper.field_class = 'col-lg-8' helper.add_input(Submit('submit', 'Submit', css_class='btn-wine')) helper.layout = Layout( 'name', 'year', 'description', 'country', 'region', 'sub_region', 'appellation', 'wine_type', 'producer', 'varietal', 'label_pic', 'hold_until', 'drink_before', ) class Meta: model = wine exclude = ('user', 'slug', 'likes')

    Read the article

  • Django loading mysql data into template correctly

    - by user805981
    I'm new to django and I'm trying to get display a list of buildings and sort them alphabetically, then load it into an html document. Is there something that I am not doing correctly? below is models.py class Class(models.Model): building = models.CharField(max_length=20) class Meta: db_table = u'class' def __unicode__(self): return self.building below is views.py views.py def index(request): buildinglist = Class.objects.all().order_by('building') c = {'buildinglist': buildinglist} t = loader.get_template('index.html') return HttpResponse(t.render(c)) below is index.html index.html {% block content%} <h3>Buildings:</h3> <ul> {% for building in buildinglist %} <li> <a href='www.{% building %}.com'> # ex. www.searstower.com </li> {% endfor %} </ul> {% endblock %} Can you guys point me in the right direction? Thank you in advance guys! I appreciate your help very much.

    Read the article

  • Django admin interface upload failing on request data read error

    - by Jake
    Hi All, This is an updated version of an old question I asked. I've now done a lot more testing, plus the old question got hijacked. I'm getting a request data read error when trying to upload files to the Django admin interface. Files under about 150k work, but bigger files always fail and almost always at around 192k (that's 3 chunks) completed, sometimes at around 160k. The Exception I get is below. File "/usr/lib/python2.4/site-packages/django/http/multipartparser.py", line 405, in read return self._file.read(num_bytes) IOError: request data read error I've tried Chrome and Firefox on Windows and Firefox on Mac - Same results. I can upload to other sites so I don't think it's my connection. I'm running python 2.4, django 1.1, mod_wsgi, on CentOS (a media temple DV server) Locally it's fine (Django development server) Everything I've found on this issue says it's a mod_python issue and that changing to mod_wsgi will fix it, but I am running mod_wsgi. Can anyone help?

    Read the article

  • model not showing up in django admin.

    - by Zayatzz
    Hi. I have ceated several django apps and stuffs for my own fund and so far everything has been working fine. Now i just created new project (django 1.2.1) and have run into trouble from 1st moments. I created new app - game and new model Game. i created admin.py and put related stuff into it. Ran syncdb and went to check into admin. Model did not show up there. I proceeded to check and doublecheck and read through previous similar threads: http://stackoverflow.com/questions/1839927/registered-models-do-not-show-up-in-admin http://stackoverflow.com/questions/1694259/django-app-not-showing-up-in-admin-interface But as far as i can tell, they dont help me either. Perhaps someone else can point this out for me. models.py in game app: # -*- coding: utf-8 -*- from django.db import models class Game(models.Model): type = models.IntegerField(blank=False, null=False, default=1) teamone = models.CharField(max_length=100, blank=False, null=False) teamtwo = models.CharField(max_length=100, blank=False, null=False) gametime = models.DateTimeField(blank=False, null=False) admin.py in game app: # -*- coding: utf-8 -*- from jalka.game.models import Game from django.contrib import admin class GameAdmin(admin.ModelAdmin): list_display = ['type', 'teamone', 'teamtwo', 'gametime'] admin.site.register(Game, GameAdmin) project settings.py: MIDDLEWARE_CLASSES = ( 'django.middleware.common.CommonMiddleware', 'django.contrib.sessions.middleware.SessionMiddleware', 'django.middleware.csrf.CsrfViewMiddleware', 'django.contrib.auth.middleware.AuthenticationMiddleware', 'django.contrib.messages.middleware.MessageMiddleware', ) ROOT_URLCONF = 'jalka.urls' TEMPLATE_DIRS = ( "/home/projects/jalka/templates/" ) INSTALLED_APPS = ( 'django.contrib.auth', 'django.contrib.contenttypes', 'django.contrib.sessions', 'django.contrib.sites', 'django.contrib.messages', 'django.contrib.admin', 'game', ) urls.py: from django.conf.urls.defaults import * # Uncomment the next two lines to enable the admin: from django.contrib import admin admin.autodiscover() urlpatterns = patterns('', # Example: # (r'^jalka/', include('jalka.foo.urls')), (r'^admin/', include(admin.site.urls)), ) Alan.

    Read the article

  • Django Admin Page missing CSS

    - by super9
    I saw this question and recommendation from Django Projects here but still can't get this to work. My Django Admin pages are not displaying the CSS at all. This is my current configuration. settings.py ADMIN_MEDIA_PREFIX = '/media/admin/' httpd.conf <VirtualHost *:80> DocumentRoot /home/django/sgel ServerName ec2-***-**-***-***.ap-**********-1.compute.amazonaws.com ErrorLog /home/django/sgel/logs/apache_error.log CustomLog /home/django/sgel/logs/apache_access.log combined WSGIScriptAlias / /home/django/sgel/apache/django.wsgi <Directory /home/django/sgel/media> Order deny,allow Allow from all </Directory> <Directory /home/django/sgel/apache> Order deny,allow Allow from all </Directory> LogLevel warn Alias /media/ /home/django/sgel/media/ </VirtualHost> <VirtualHost *:80> ServerName sgel.com Redirect permanent / http://www.sgel.com/ </VirtualHost> In addition, I also ran the following to create (I think) the symbolic link ln -s /home/djangotest/sgel/media/admin/ /usr/lib/python2.6/site-packages/django/contrib/admin/media/ UPDATE In my httpd.conf file, User django Group django When I run ls -l in my /media directory drwxr-xr-x 2 root root 4096 Apr 4 11:03 admin -rw-r--r-- 1 root root 9 Apr 8 09:02 test.txt Should that root user be django instead? UPDATE 2 When I enter ls -la in my /media/admin folder total 12 drwxr-xr-x 2 root root 4096 Apr 13 03:33 . drwxr-xr-x 3 root root 4096 Apr 8 09:02 .. lrwxrwxrwx 1 root root 60 Apr 13 03:33 media -> /usr/lib/python2.6/site-packages/django/contrib/admin/media/ The thing is, when I navigate to /usr/lib/python2.6/site-packages/django/contrib/admin/media/, the folder was empty. So I copied the CSS, IMG and JS folders from my Django installation into /usr/lib/python2.6/site-packages/django/contrib/admin/media/ and it still didn't work

    Read the article

  • Django apache-wsgi configuration problem

    - by omat
    Hi, I am trying to get my Django project running on the production server. I setup the environment using pip, so it is identical to the development environment where everything is running fine. The only difference is that I don't use virtualenv on production, because this project is the only one that is going to run on production. Also on production, there is an Nginx reverse proxy to serve static content, and passes dynamic requests to Apache2. The Apache wsgi file is as follows: import sys, os sys.path.append('/home/project/src') os.environ['DJANGO_SETTINGS_MODULE'] = 'settings' import django.core.handlers.wsgi application = django.core.handlers.wsgi.WSGIHandler() When I access the server, I get an import error: ImproperlyConfigured: Error importing middleware middleware: "cannot import name UserProfile" Which refers to the middleware.py under src/ folder which is referred by the settings. But I can import both the middleware and the UserProfile class from within ./manage.py shell prompt. It seems like a problem with paths in wsgi file but I cannot see what. The directory structure is: /home/project /home/project/src (which contains the settings.py, middleware.py and app folders) /home/apache/apache.wsgi Any help is greatly appreciated. Thanks, oMat

    Read the article

  • Django website on Apache with wsgi failing

    - by notagain
    I have a website I've built in django that I'm trying to get working on our corporate Apache server (on debian) for our intranet at my workplace. Unfortunately, Apache keeps returning server errors whenever I try to navigate to my site. Although I can navigate to the statics folder. My Apache config and wsgi script look like the following... lbirdf.wsgi import os import sys sys.path.append('/home/lbi/rdfweb/web') sys.path.append('/home/lbi/rdfweb/lbirdf') os.environ['DJANGO_SETTINGS_MODULE'] = 'lbirdf.settings_production' import django.core.handlers.wsgi application = django.core.handlers.wsgi.WSGIHandler() Apache config Listen 8080 <VirtualHost *:8080> ServerName server1 WSGIScriptAlias /rdfweb /home/lbi/rdfweb/web/lbirdf/apache/lbirdf.wsgi Alias /statics /home/lbi/rdfweb/web/lbirdf/statics Alias /admin_media /home/lbi/rdfweb/web/lbirdf/admin_media <Directory /home/lbi/rdfweb/web/lbirdf/apache> Order allow,deny Allow from all </Directory> <Directory /home/lbi/rdfweb/web/lbirdf/admin_media> Order allow,deny Allow from all </Directory> </VirtualHost> Any ideas on where I might be going wrong?

    Read the article

  • Incorrect deployment of WSGI app to AWS using Elastic Beanstalk

    - by Dzmitry Zhaleznichenka
    cross-link to AWS forums I have developed a simple Python web service using WSGI and would like to deploy it to AWS cloud using Elastic Beanstalk. My problem is I cannot make all the options I specify in Elastic Beanstalk configuration to be correctly configured in the cloud. For deployment, I use Elastic Beanstalk CLI utility. I have run eb init command and set up the required parameters. After this, a directory named .elasticbeanstalk was created in my source tree. It has two config files that are used for deployment, namely config and optionsettings. The latter one among the other options contains the WSGI configuration that has to update /etc/httpd/conf.d/wsgi.conf at the instances. After some of my adjustments the file has the following settings: [aws:elasticbeanstalk:application:environment] DJANGO_SETTINGS_MODULE = PARAM1 = PARAM2 = PARAM4 = PARAM3 = PARAM5 = [aws:elasticbeanstalk:container:python] WSGIPath = handler.py NumProcesses = 2 StaticFiles = /static= NumThreads = 10 [aws:elasticbeanstalk:container:python:staticfiles] /static = static/ [aws:elasticbeanstalk:hostmanager] LogPublicationControl = false [aws:autoscaling:launchconfiguration] InstanceType = t1.micro EC2KeyName = zmicier-aws [aws:elasticbeanstalk:application] Application Healthcheck URL = [aws:autoscaling:asg] MaxSize = 10 MinSize = 1 Custom Availability Zones = [aws:elasticbeanstalk:monitoring] Automatically Terminate Unhealthy Instances = true [aws:elasticbeanstalk:sns:topics] Notification Endpoint = Notification Protocol = email It turns out that not all of these options are considered when I start the environment or update it. Thus, when I update NumThreads or NumProcesses, the respective parameters get changed in wsgi.conf as expected. But whatever I write to the WSGIPath and StaticFiles parameters, I'm not able to automatically change the respective values of wsgi.conf, they remain Alias /static /opt/python/current/app/ WSGIScriptAlias / /opt/python/current/app/application.py which drives me nuts. Moreover, when I deploy my application using git aws.push and having the following contents of .ebextensions/python.config file, neither of options I specify in it affects the deployment. option_settings: - namespace: aws:elasticbeanstalk:container:python option_name: WSGIPath value: mysite/wsgi.py - namespace: aws:elasticbeanstalk:container:python option_name: NumProcesses value: 5 - namespace: aws:elasticbeanstalk:container:python option_name: NumThreads value: 25 - namespace: aws:elasticbeanstalk:container:python:staticfiles option_name: /static/ value: app/static/ I wonder what I should do to force AWS use all the parameters I specify in the configuration, namely the WSGI Path and path to my static data.

    Read the article

  • Django FileField not saving to upload_to location

    - by Erik
    I have an Attachment model that has a FileField in a Django 1.4.1 app. This FileField has a callable upload_to parameter which, per the Django docs should be called when the form (and therefore the model) is saved. When I run FormTest below, the upload_to callable is never called and the file therefore does not appear in the location provided by the upload_to method. What am I doing wrong? Notice that in the passing tests in ModelTest (also below), the upload_to method works as expected. Test: from core.forms.attachments import AttachmentForm from django.test import TestCase import unittest from django.core.files.uploadedfile import SimpleUploadedFile from django.core.files.storage import default_storage def suite(): return unittest.TestSuite( [ unittest.TestLoader().loadTestsFromTestCase(FormTest), ] ) class FormTest(TestCase): def test_form_1(self): filename = 'filename' f = file(filename) data = {'name':'name',} file_data = {'attachment_file':SimpleUploadedFile(f.name,f.read()),} form = AttachmentForm(data=data,files=file_data) self.assertTrue(form.is_valid()) attachment = form.save() root_directory = 'attachments' upload_location = root_directory + '/' + attachment.directory + '/' + filename self.assertTrue(attachment.attachment_file) # Fails self.assertTrue(default_storage.exists(upload_location)) # Fails Attachment Model: from django.db import models from parent_mixins import Parent_Mixin import uuid from django.db.models.signals import pre_delete,pre_save from dirtyfields import DirtyFieldsMixin def upload_to(instance,filename): return 'attachments/' + instance.directory + '/' + filename def uuid_directory_name(): return uuid.uuid4().hex class Attachment(DirtyFieldsMixin,Parent_Mixin,models.Model): attachment_file = models.FileField(blank=True,null=True,upload_to=upload_to) directory = models.CharField(blank=False,default=uuid_directory_name,null=False,max_length=32) name = models.CharField(blank=False,default=None,null=False,max_length=128) class Meta: app_label = 'core' def __str__(self): return unicode(self).encode('utf-8') def __unicode__(self): return unicode(self.name) @models.permalink def get_absolute_url(self): return('core_attachments_update',(),{'pk': self.pk}) # def save(self,*args,**kwargs): # super(Attachment,self).save(*args,**kwargs) def pre_delete_callback(sender, instance, *args, **kwargs): if not isinstance(instance, Attachment): return if not instance.attachment_file: return instance.attachment_file.delete(save=False) def pre_save_callback(sender, instance, *args, **kwargs): if not isinstance(instance, Attachment): return if not instance.attachment_file: return if instance.is_dirty(): dirty_fields = instance.get_dirty_fields() if 'attachment_file' in dirty_fields: old_attachment_file = dirty_fields['attachment_file'] old_attachment_file.delete() pre_delete.connect(pre_delete_callback) pre_save.connect(pre_save_callback) Attachment Form: from ..models.attachments import Attachment from crispy_forms.helper import FormHelper from crispy_forms.layout import Div,Layout,HTML,Field,Fieldset,Button,ButtonHolder,Submit from django import forms class AttachmentFormHelper(FormHelper): form_tag=False layout = Layout( Div( Div( Field('name',css_class='span4'), Field('attachment_file',css_class='span4'), css_class='span4', ), css_class='row', ), ) class AttachmentForm(forms.ModelForm): helper = AttachmentFormHelper() class Meta: fields=('attachment_file','name') model = Attachment class AttachmentInlineFormHelper(FormHelper): form_tag=False form_style='inline' layout = Layout( Div( Div( Field('name',css_class='span4'), Field('attachment_file',css_class='span4'), Field('DELETE',css_class='span4'), css_class='span4', ), css_class='row', ), ) class AttachmentInlineForm(forms.ModelForm): helper = AttachmentInlineFormHelper() class Meta: fields=('attachment_file','name') model = Attachment UPDATE I also do testing on the Attachment model class with these unit tests -- which all pass: from core.models.attachments import Attachment from core.models.attachments import upload_to from django.test import TestCase import unittest from django.core.files.storage import default_storage from django.core.files.base import ContentFile def suite(): return unittest.TestSuite( [ unittest.TestLoader().loadTestsFromTestCase(ModelTest), ] ) class ModelTest(TestCase): def test_model_minimum_fields(self): attachment = Attachment(name='name') attachment.attachment_file.save('test.txt',ContentFile("hello world")) attachment.save() self.assertEqual(str(attachment),'name') self.assertEqual(unicode(attachment),'name') self.assertTrue(attachment.directory) # def test_model_full_fields(self): # attachment = Attachment() # attachement.save() def test_file_operations_basic(self): root_directory = 'attachments' filename = 'test.txt' attachment = Attachment(name='name') attachment.attachment_file.save(filename,ContentFile('test')) attachment.save() upload_location = root_directory + '/' + attachment.directory + '/' + filename self.assertEqual(upload_to(attachment,filename),upload_location) self.assertTrue(default_storage.exists(upload_location)) def test_file_operations_delete(self): root_directory = 'attachments' filename = 'test.txt' attachment = Attachment(name='name') attachment.attachment_file.save(filename,ContentFile('test')) attachment.save() upload_location = upload_to(attachment,filename) attachment.delete() self.assertFalse(default_storage.exists(upload_location)) def test_file_operations_change(self): root_directory = 'attachments' filename_1 = 'test_1.txt' attachment = Attachment(name='name') attachment.attachment_file.save(filename_1,ContentFile('test')) attachment.save() upload_location_1 = upload_to(attachment,filename_1) self.assertTrue(default_storage.exists(upload_location_1)) filename_2 = 'test_2.txt' attachment.attachment_file.save(filename_2,ContentFile('test')) attachment.save() upload_location_2 = upload_to(attachment,filename_2) self.assertTrue(default_storage.exists(upload_location_2)) self.assertFalse(default_storage.exists(upload_location_1))

    Read the article

  • Django: TypeError: 'str' object is not callable, referer: http://xxx

    - by user705415
    I've been wondering why when I set the settings.py of my django project 'arvindemo' debug = Flase and deploy it on Apache with mod_wsgi, I got the 500 Internal Server Error. Env: Django 1.4.0 Python 2.7.2 mod_wsgi 2.8 OS centOS Here is the recap: Visit the homepage, go to sub page A/B/C/D, and fill some forms, then submit it to the Apache server. Once click 'submit' button, I will get the '500 Internal Server Error', and the error_log listed below(Traceback): [Tue Apr 10 10:07:20 2012] [error] [client 122.198.133.250] Traceback (most recent call last): [Tue Apr 10 10:07:20 2012] [error] [client 122.198.133.250] File "/opt/python2.7/lib/python2.7/site-packages/django/core/handlers/wsgi.py", line 241, in __call__ [Tue Apr 10 10:07:20 2012] [error] [client 122.198.133.250] response = self.get_response(request) [Tue Apr 10 10:07:20 2012] [error] [client 122.198.133.250] File "/opt/python2.7/lib/python2.7/site-packages/django/core/handlers/base.py", line 179, in get_response [Tue Apr 10 10:07:20 2012] [error] [client 122.198.133.250] response = self.handle_uncaught_exception(request, resolver, sys.exc_info()) [Tue Apr 10 10:07:20 2012] [error] [client 122.198.133.250] File "/opt/python2.7/lib/python2.7/site-packages/django/core/handlers/base.py", line 224, in handle_uncaught_exception [Tue Apr 10 10:07:20 2012] [error] [client 122.198.133.250] if resolver.urlconf_module is None: [Tue Apr 10 10:07:20 2012] [error] [client 122.198.133.250] File "/opt/python2.7/lib/python2.7/site-packages/django/core/urlresolvers.py", line 323, in urlconf_module [Tue Apr 10 10:07:20 2012] [error] [client 122.198.133.250] self._urlconf_module = import_module(self.urlconf_name) [Tue Apr 10 10:07:20 2012] [error] [client 122.198.133.250] File "/opt/python2.7/lib/python2.7/site-packages/django/utils/importlib.py", line 35, in import_module [Tue Apr 10 10:07:20 2012] [error] [client 122.198.133.250] __import__(name) [Tue Apr 10 10:07:20 2012] [error] [client 122.198.133.250] File "/opt/web/django/arvindemo/arvindemo/../arvindemo/urls.py", line 23, in <module> [Tue Apr 10 10:07:20 2012] [error] [client 122.198.133.250] url(r'^submitPage$', name=submitPage), [Tue Apr 10 10:07:20 2012] [error] [client 122.198.133.250] TypeError: url() takes at least 2 arguments (2 given) When using django runserver, I set arvindemo.settings debug = True, everything is OK. But things changed once I set debug = Flase. Here is my views.py from django.http import HttpResponseRedirect from django.http import HttpResponse, HttpResponseServerError from django.shortcuts import render_to_response import datetime, string from user_info.models import * from django.template import Context, loader, RequestContext import settings def hello(request): return HttpResponse("hello girl") def helpPage(request): return render_to_response('kktHelp.html') def server_error(request, template_name='500.html'): return render_to_response(template_name, context_instance = RequestContext(request) ) def page404(request): return render_to_response('404.html') def submitPage(request): post = request.POST Mall = 'goodsName' Contest = 'ojs' Presentation = 'addr' WeatherReport = 'city' Habit = 'task' if Mall in post: return submitMall(request) elif Contest in post: return submitContest(request) elif Presentation in post: return submitPresentation(request) elif Habit in post: return submitHabit(request) elif WeatherReport in post: return submitWeather(request) else: return HttpResponse(request.POST) return HttpResponseRedirect('404') def submitXXX(): ..... def xxxx(): .... Here comes the urls.py from django.conf.urls import patterns, include, url from views import * from django.conf import settings handler500 = 'server_error' urlpatterns = patterns('', url(r'^hello/$', hello), # hello world url(r'^$', homePage), url(r'^time/$', getTime), url(r'^time/plus/(\d{1,2})/$', hoursAhead), url(r'^Ttime/$', templateGetTime), url(r'^Mall$', templateMall), url(r'^Contest$', templateContest), url(r'^Presentation$', templatePresentation), url(r'^Habit$', templateHabit), url(r'^Weather$', templateWeather), url(r'^Help$', helpPage), url(r'^404$', page404), url(r'^500$', server_error), url(r'^submitPage$', submitPage), url(r'^submitMall$', submitMall), url(r'^submitContest$', submitContest), url(r'^submitPresentation$', submitPresentation), url(r'^submitHabit$', submitHabit), url(r'^submitWeather$', submitWeather), url(r'^terms$', terms), url(r'^privacy$', privacy), url(r'^thanks$', thanks), url(r'^about$', about), url(r'^static/(?P<path>.*)$','django.views.static.serve',{'document_root':settings.STATICFILES_DIRS}), ) I'm sure there is no syntax error in my django project,cause when I use django runserver, everything is fine. Anyone can help ? Best regards

    Read the article

  • A Django form for entering a 0 to n email addresses

    - by Erik
    I have a Django application with some fairly common models in it: UserProfile and Organization. A UserProfile or an Organization can both have 0 to n emails, so I have an Email model that has a GenericForeignKey. UserProfile and Organization Models both have a GenericRelation called emails that points back to the Email model (summary code provided below). The question: what is the best way to provide an Organization form that allows a user to enter organization details including 0 to n email addresses? My Organization create view is a Django class-based view. I'm leading towards creating a dynamic form and an enabling it with Javascript to allow the user to add as many email addresses as necessary. I will render the form with django-crispy-forms. I've thought about doing this with a formset embedded within the form, but this seems like overkill for email addresses. Embedding a formset in a form delivered by a class-based view is cumbersome too. Note that the same issue occurs with the Organization fields phone_numbers and locations. emails.py: from django.db import models from parent_mixins import Parent_Mixin class Email(Parent_Mixin,models.Model): email_type = models.CharField(blank=True,max_length=100,null=True,default=None,verbose_name='Email Type') email = models.EmailField() class Meta: app_label = 'core' organizations.py: from emails import Email from locations import Location from phone_numbers import Phone_Number from django.contrib.contenttypes import generic from django.db import models class Organization(models.Model): active = models.BooleanField() duns_number = models.CharField(blank=True,default=None,null=True,max_length=9) # need to validate this emails = generic.GenericRelation(Email,content_type_field='parent_type',object_id_field='parent_id') legal_name = models.CharField(blank=True,default=None,null=True,max_length=200) locations = generic.GenericRelation(Location,content_type_field='parent_type',object_id_field='parent_id') name = models.CharField(blank=True,default=None,null=True,max_length=200) organization_group = models.CharField(blank=True,default=None,null=True,max_length=200) organization_type = models.CharField(blank=True,default=None,null=True,max_length=200) phone_numbers = generic.GenericRelation(Phone_Number,content_type_field='parent_type',object_id_field='parent_id') taxpayer_id_number = models.CharField(blank=True,default=None,null=True,max_length=9) # need to validate this class Meta: app_label = 'core' parent_mixins.py from django.contrib.contenttypes.models import ContentType from django.contrib.contenttypes import generic from django.db import models class Parent_Mixin(models.Model): parent_type = models.ForeignKey(ContentType,blank=True,null=True) parent_id = models.PositiveIntegerField(blank=True,null=True) parent = generic.GenericForeignKey('parent_type', 'parent_id') class Meta: abstract = True app_label = 'core'

    Read the article

  • Trouble getting SSL to work with django + nginx + wsgi

    - by Kevin
    I've followed a couple of examples for Django + nginx + wsgi + ssl, but I can't get them to work. I simply get an error in my browser than I can't connect. I'm running two websites off the host. The config files are identical except for the ip addresses, server names, and directories. When neither use SSL, they work fine. When I try to listen on 443 with one of them, I can't connect to either. My config files are below, and any suggestions would be appreciated. server{ listen xxx.xxx.xxx.xxx:80; server_name sub.domain.com; access_log /home/django/logs/nginx_customerdb_http_access.log; error_log /home/django/logs/nginx_customerdb_http_error.log; location / { proxy_pass http://127.0.0.1:8080; proxy_redirect off; proxy_set_header Host $host; proxy_set_header X-Real-IP $remote_addr; proxy_set_header X-Forwarded-For $proxy_add_x_forwarded_for; client_max_body_size 10m; client_body_buffer_size 128k; proxy_connect_timeout 90; proxy_send_timeout 90; proxy_read_timeout 90; proxy_buffers 32 4k; } location /site_media/ { alias /home/django/customerdb_site_media/; } location /admin-media/ { alias /home/django/django_admin_media/; } } server{ listen xxx.xxx.xxx.xxx:443; server_name sub.domain.com; access_log /home/django/logs/nginx_customerdb_http_access.log; error_log /home/django/logs/nginx_customerdb_http_error.log; ssl on; ssl_certificate sub.domain.com.crt; ssl_certificate_key sub.domain.com.key; ssl_prefer_server_ciphers on; location / { proxy_pass http://127.0.0.1:8080; proxy_redirect off; proxy_set_header Host $host; proxy_set_header X-Real-IP $remote_addr; proxy_set_header X-Forwarded-For $proxy_add_x_forwarded_for; proxy_set_header X-Forwarded-Protocol https; client_max_body_size 10m; client_body_buffer_size 128k; proxy_connect_timeout 90; proxy_send_timeout 90; proxy_read_timeout 90; proxy_buffers 32 4k; } location /site_media/ { alias /home/django/customerdb_site_media/; } location /admin-media/ { alias /home/django/django_admin_media/; } } <VirtualHost *:8080> ServerName xxx.xxx.xxx.xxx ServerAlias xxx.xxx.xxx.xxx LogLevel warn ErrorLog /home/django/logs/apache_customerdb_error.log CustomLog /home/django/logs/apache_customerdb_access.log combined WSGIScriptAlias / /home/django/customerdb/apache/django.wsgi WSGIDaemonProcess customerdb_wsgi processes=4 threads=5 WSGIProcessGroup customerdb_wsgi SetEnvIf X-Forwarded-Protocol "^https$" HTTPS=on </VirtualHost> UDPATE: the existence of two sites (on separate IPs) on the host is the issue. if i delete the other site, the setting above mostly work. doing so also brings up another issue: chrome doesn't accept the site as secure saying that some content is not encrypted.

    Read the article

  • Deploying Django App with Nginx, Apache, mod_wsgi

    - by JCWong
    I have a django app which can run locally using the standard development environment. I want to now move this to EC2 for production. The django documentation suggests running with apache and mod_wsgi, and using nginx for loading static files. I am running Ubuntu 12.04 on an Ec2 box. My Django app, "ddt", contains a subdirectory "apache" with ddt.wsgi import os, sys apache_configuration= os.path.dirname(__file__) project = os.path.dirname(apache_configuration) workspace = os.path.dirname(project) sys.path.append(workspace) sys.path.append('/usr/lib/python2.7/site-packages/django/') sys.path.append('/home/jeffrey/www/ddt/') os.environ['DJANGO_SETTINGS_MODULE'] = 'ddt.settings' import django.core.handlers.wsgi application = django.core.handlers.wsgi.WSGIHandler() I have mod_wsgi installed from apt. My apache/httpd.conf contains NameVirtualHost *:8080 WSGIScriptAlias / /home/jeffrey/www/ddt/apache/ddt.wsgi WSGIPythonPath /home/jeffrey/www/ddt <Directory /home/jeffrey/www/ddt/apache/> <Files ddt.wsgi> Order deny,allow Allow from all </Files> </Directory> Under apache2/sites-enabled <VirtualHost *:8080> ServerName www.mysite.com ServerAlias mysite.com <Directory /home/jeffrey/www/ddt/apache/> Order deny,allow Allow from all </Directory> LogLevel warn ErrorLog /home/jeffrey/www/ddt/logs/apache_error.log CustomLog /home/jeffrey/www/ddt/logs/apache_access.log combined WSGIDaemonProcess datadriventrading.com user=www-data group=www-data threads=25 WSGIProcessGroup datadriventrading.com WSGIScriptAlias / /home/jeffrey/www/ddt/apache/ddt.wsgi </VirtualHost> If I am correct, these 3 files above should correctly allow my django app to run on port 8080. I have the following nginx/proxy.conf file proxy_redirect off; proxy_set_header Host $host; proxy_set_header X-Real-IP $remote_addr; proxy_set_header X-Forwarded-For $proxy_add_x_forwarded_for; client_max_body_size 10m; client_body_buffer_size 128k; proxy_connect_timeout 90; proxy_send_timeout 90; proxy_read_timeout 90; proxy_buffer_size 4k; proxy_buffers 4 32k; proxy_busy_buffers_size 64k; proxy_temp_file_write_size 64k; Under nginx/sites-enabled server { listen 80; server_name www.mysite.com mysite.com; access_log /home/jeffrey/www/ddt/logs/nginx_access.log; error_log /home/jeffrey/www/ddt/logs/nginx_error.log; location / { proxy_pass http://127.0.0.1:8080; include /etc/nginx/proxy.conf; } location /media/ { root /home/jeffrey/www/ddt/; } } If I am correct these two files should setup nginx to take requests on the HTTP port 80, but then direct requests to apache which is running the django app on port 8080. If i go to mysite.com, all I see is Welcome to Nginx! Any advice for how to debug this?

    Read the article

  • Deploying a Django application in a virtual Ubuntu Server

    - by mfsaint
    I have a virtualbox machine running Ubuntu Server 10.04LTS. My intention is to this machine to work like a VPS, this way I can learn and prepare for when I get a VPS service. Apache+mod_wsgi for deploying the Django app seems the right choice to me. I have the domain (marianofalcon.com.ar) but nothing else, no DNS. The problem is that I'm pretty lost with all the deployment stuff. I know how to configure mod_wsgi(with the django.wsgi file) and apache(creating a VirtualHost). Something is missing and I don't know what it is. I think that I lack networking skills ant that's the big problem. Trying to host the app on a virtualbox adds some difficulty because I don't know well what IP to use. This is what I've got: file placed at: /etc/apache2/sites-available: NameVirtualHost *:80 <VirtualHost *:80> ServerAdmin [email protected] ServerName www.my-domain.com ServerAlias my-domain.com Alias /media /path/to/my/project/media DocumentRoot /path/to/my/project WSGIScriptAlias / /path/to/your/project/apache/django.wsgi ErrorLog /var/log/apache2/error.log LogLevel warn CustomLog /var/log/apache2/access.log combined </VirtualHost> django.wsgi file: import os, sys wsgi_dir = os.path.abspath(os.path.dirname(__file__)) project_dir = os.path.dirname(wsgi_dir) sys.path.append(project_dir) project_settings = os.path.join(project_dir,'settings') os.environ['DJANGO_SETTINGS_MODULE'] = 'myproject.settings' import django.core.handlers.wsgi application = django.core.handlers.wsgi.WSGIHandler()

    Read the article

  • django+mod_wsgi on virtualenv not working

    - by jwesonga
    I've just finished setting up a django app on virtualenv, deployment went smoothly using a fabric script, but now the .wsgi is not working, I've tried every variation on the internet but no luck. My .wsgi file is: import os import sys import django.core.handlers.wsgi # put the Django project on sys.path root_path = os.path.abspath(os.path.dirname(__file__) + '../') sys.path.insert(0, os.path.join(root_path, 'kcdf')) sys.path.insert(0, root_path) os.environ['DJANGO_SETTINGS_MODULE'] = 'kcdf.settings' application = django.core.handlers.wsgi.WSGIHandler() I keep getting the same error: [Sun Apr 18 12:44:30 2010] [error] [client 41.215.123.159] mod_wsgi (pid=16938): Exception occurred processing WSGI script '/home/kcdfweb/webapps/kcdf.web/releases/current/kcdf/apache/kcdf.wsgi'. [Sun Apr 18 12:44:30 2010] [error] [client 41.215.123.159] Traceback (most recent call last): [Sun Apr 18 12:44:30 2010] [error] [client 41.215.123.159] File "/usr/local/lib/python2.6/dist-packages/django/core/handlers/wsgi.py", line 230, in __call__ [Sun Apr 18 12:44:30 2010] [error] [client 41.215.123.159] self.load_middleware() [Sun Apr 18 12:44:30 2010] [error] [client 41.215.123.159] File "/usr/local/lib/python2.6/dist-packages/django/core/handlers/base.py", line 33, in load_middleware [Sun Apr 18 12:44:30 2010] [error] [client 41.215.123.159] for middleware_path in settings.MIDDLEWARE_CLASSES: [Sun Apr 18 12:44:30 2010] [error] [client 41.215.123.159] File "/usr/local/lib/python2.6/dist-packages/django/utils/functional.py", line 269, in __getattr__ [Sun Apr 18 12:44:30 2010] [error] [client 41.215.123.159] self._setup() [Sun Apr 18 12:44:30 2010] [error] [client 41.215.123.159] File "/usr/local/lib/python2.6/dist-packages/django/conf/__init__.py", line 40, in _setup [Sun Apr 18 12:44:30 2010] [error] [client 41.215.123.159] self._wrapped = Settings(settings_module) [Sun Apr 18 12:44:30 2010] [error] [client 41.215.123.159] File "/usr/local/lib/python2.6/dist-packages/django/conf/__init__.py", line 75, in __init__ [Sun Apr 18 12:44:30 2010] [error] [client 41.215.123.159] raise ImportError, "Could not import settings '%s' (Is it on sys.path? Does it have syntax errors?): %s" % (self.SETTINGS_MODULE, e) [Sun Apr 18 12:44:30 2010] [error] [client 41.215.123.159] ImportError: Could not import settings 'kcdf.settings' (Is it on sys.path? Does it have syntax errors?): No module named kcdf.settings my virtual environment is on /home/user/webapps/kcdfweb my app is /home/user/webapps/kcdf.web/releases/current/project_name my wsgi file home/user/webapps/kcdf.web/releases/current/project_name/apache/project_name.wsgi

    Read the article

  • CentOS: make python 2.6 see django

    - by NP
    In a harrowing attempt to get mod_wsgi to run on CentOS 5.4, I've added python 2.6 as an optional library following the instructions here. The configuration seems fine except that when trying to ping the server the Apache log prints this error: mod_wsgi (pid=20033, process='otalo', application='127.0.0.1|'): Loading WSGI script '...django.wsgi'. [Sat Mar 27 16:11:45 2010] [error] [client 171.66.52.218] mod_wsgi (pid=20033): Target WSGI script '...django.wsgi' cannot be loaded as Python module. [Sat Mar 27 16:11:45 2010] [error] [client 171.66.52.218] mod_wsgi (pid=20033): Exception occurred processing WSGI script '...django.wsgi'. [Sat Mar 27 16:11:45 2010] [error] [client 171.66.52.218] Traceback (most recent call last): [Sat Mar 27 16:11:45 2010] [error] [client 171.66.52.218] File "...django.wsgi", line 8, in [Sat Mar 27 16:11:45 2010] [error] [client 171.66.52.218] import django.core.handlers.wsgi [Sat Mar 27 16:11:45 2010] [error] [client 171.66.52.218] ImportError: No module named django.core.handlers.wsgi when I go to my python2.6 install's command line and try 'import django', the module is not found (ImportError). However, my default python 2.4 installation (still working fine) is able to import successfully. How do I point python 2.6 to django? Thanks in advance.

    Read the article

  • Django admin site populated combo box based on imput

    - by user292652
    hi i have to following model class Match(models.Model): Team_one = models.ForeignKey('Team', related_name='Team_one') Team_two = models.ForeignKey('Team', related_name='Team_two') Stadium = models.CharField(max_length=255, blank=True) Start_time = models.DateTimeField(auto_now_add=False, auto_now=False, blank=True, null=True) Rafree = models.CharField(max_length=255, blank=True) Judge = models.CharField(max_length=255, blank=True) Winner = models.ForeignKey('Team', related_name='winner', blank=True) updated = models.DateTimeField('update date', auto_now=True ) created = models.DateTimeField('creation date', auto_now_add=True ) def save(self, force_insert=False, force_update=False): pass @models.permalink def get_absolute_url(self): return ('view_or_url_name') class MatchAdmin(admin.ModelAdmin): list_display = ('Team_one','Team_two', 'Winner') search_fields = ['Team_one','Team_tow'] admin.site.register(Match, MatchAdmin) i was wondering is their a way to populated the winner combo box once the team one and team two is selected in admin site ?

    Read the article

  • Django one form for two models

    - by martinthenext
    Hello! I have a ForeignKey relationship between TextPage and Paragraph and my goal is to make front-end TextPage creating/editing form as if it was in ModelAdmin with 'inlines': several field for the TextPage and then a couple of Paragraph instances stacked inline. The problem is that i have no idea about how to validate and save that: @login_required def textpage_add(request): profile = request.user.profile_set.all()[0] if not (profile.is_admin() or profile.is_editor()): raise Http404 PageFormSet = inlineformset_factory(TextPage, Paragraph, extra=5) if request.POST: try: textpageform = TextPageForm(request.POST) # formset = PageFormSet(request.POST) except forms.ValidationError as error: textpageform = TextPageForm() formset = PageFormSet() return render_to_response('textpages/manage.html', { 'formset' : formset, 'textpageform' : textpageform, 'error' : str(error), }, context_instance=RequestContext(request)) # Saving data if textpageform.is_valid() and formset.is_valid(): textpageform.save() formset.save() return HttpResponseRedirect(reverse(consults)) else: textpageform = TextPageForm() formset = PageFormSet() return render_to_response('textpages/manage.html', { 'formset' : formset, 'textpageform' : textpageform, }, context_instance=RequestContext(request)) I know I't a kind of code-monkey style to post code that you don't even expect to work but I wanted to show what I'm trying to accomplish. Here is the relevant part of models.py: class TextPage(models.Model): title = models.CharField(max_length=100) page_sub_category = models.ForeignKey(PageSubCategory, blank=True, null=True) def __unicode__(self): return self.title class Paragraph(models.Model): article = models.ForeignKey(TextPage) title = models.CharField(max_length=100, blank=True, null=True) text = models.TextField(blank=True, null=True) def __unicode__(self): return self.title Any help would be appreciated. Thanks!

    Read the article

  • Django ForeignKey TemplateSyntaxError and ProgrammingError

    - by Daniel Garcia
    This is are my models i want to relate. i want for collection to appear in the form of occurrence. class Collection(models.Model): id = models.AutoField(primary_key=True, null=True) code = models.CharField(max_length=100, null=True, blank=True) address = models.CharField(max_length=100, null=True, blank=True) collection_name = models.CharField(max_length=100) def __unicode__(self): return self.collection_name class Meta: db_table = u'collection' ordering = ('collection_name',) class Occurrence(models.Model): id = models.AutoField(primary_key=True, null=True) reference = models.IntegerField(null=True, blank=True, editable=False) collection = models.ForeignKey(Collection, null=True, blank=True, unique=True), modified = models.DateTimeField(null=True, blank=True, auto_now=True) class Meta: db_table = u'occurrence' Every time i go to check the Occurrence object i get this error TemplateSyntaxError at /admin/hotiapp/occurrence/ Caught an exception while rendering: column occurrence.collection_id does not exist LINE 1: ...LECT "occurrence"."id", "occurrence"."reference", "occurrenc.. And every time i try to add a new occurrence object i get this error ProgrammingError at /admin/hotiapp/occurrence/add/ column occurrence.collection_id does not exist LINE 1: SELECT (1) AS "a" FROM "occurrence" WHERE "occurrence"."coll... What am i doing wrong? or how does ForeignKey works?

    Read the article

  • Django Formset validation with an optional ForeignKey field

    - by Camilo Díaz
    Having a ModelFormSet built with modelformset_factory and using a model with an optional ForeignKey, how can I make empty (null) associations to validate on that form? Here is a sample code: ### model class Prueba(models.Model): cliente = models.ForeignKey(Cliente, null = True) valor = models.CharField(max_length = 20) ### view def test(request): PruebaFormSet = modelformset_factory(model = Prueba, extra = 1) if request.method == 'GET': formset = PruebaFormSet() return render_to_response('tpls/test.html', {'formset' : formset}, context_instance = RequestContext(request)) else: formset = PruebaFormSet(request.POST) # dumb tests, just to know if validating if formset.is_valid(): return HttpResponse('0') else: return HttpResponse('1') In my template, i'm just calling the {{ form.cliente }} method which renders the combo field, however, I want to be able to choose an empty (labeled "------") value, as the FK is optional... but when the form gets submitted it doesn't validate. Is this normal behaviour? How can i make this field to skip required validation?

    Read the article

  • Django MultiWidget Phone Number Field

    - by Birdman
    I want to create a field for phone number input that has 2 text fields (size 3, 3, and 4 respectively) with the common "(" ")" "-" delimiters. Below is my code for the field and the widget, I'm getting the following error when trying to iterate the fields in my form during initial rendering (it happens when the for loop gets to my phone number field): Caught an exception while rendering: 'NoneType' object is unsubscriptable class PhoneNumberWidget(forms.MultiWidget): def __init__(self,attrs=None): wigs = (forms.TextInput(attrs={'size':'3','maxlength':'3'}),\ forms.TextInput(attrs={'size':'3','maxlength':'3'}),\ forms.TextInput(attrs={'size':'4','maxlength':'4'})) super(PhoneNumberWidget, self).__init__(wigs, attrs) def decompress(self, value): return value or None def format_output(self, rendered_widgets): return '('+rendered_widgets[0]+')'+rendered_widgets[1]+'-'+rendered_widgets[2] class PhoneNumberField(forms.MultiValueField): widget = PhoneNumberWidget def __init__(self, *args, **kwargs): fields=(forms.CharField(max_length=3), forms.CharField(max_length=3), forms.CharField(max_length=4)) super(PhoneNumberField, self).__init__(fields, *args, **kwargs) def compress(self, data_list): if data_list[0] in fields.EMPTY_VALUES or data_list[1] in fields.EMPTY_VALUES or data_list[2] in fields.EMPTY_VALUES: raise fields.ValidateError(u'Enter valid phone number') return data_list[0]+data_list[1]+data_list[2] class AdvertiserSumbissionForm(ModelForm): business_phone_number = PhoneNumberField(required=True)

    Read the article

< Previous Page | 1 2 3 4 5 6 7 8 9 10 11 12  | Next Page >