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  • How to fix Jersey POST request parameters warning?

    - by Brabster
    I'm building a very simple REST API using Jersey, and I've got a warning in my log files that I'm not sure about. WARNING: A servlet POST request, to the URI http://myserver/mycontext/myapi/users/12345?action=delete, contains form parameters in the request body but the request body has been consumed by the servlet or a servlet filter accessing the request parameters. Only resource methods using @FormParam will work as expected. Resource methods consuming the request body by other means will not work as expected. My webapp only has the Jersey servlet defined, mapped to /myapi/* How can I stop these warnings?

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  • Form Validation Options

    The steps involved in transmitting form data from the client to the Web server User loads web form. User enters data in to web form fields User clicks submit On submit page validates fields using JavaScript. If validation errors are found then the validation script stops the browser from canceling posting the data to the web server and displays error messages as needed. If the form passes the data validation process then the browser will URL encode the values of every field and post it to the server.  The server reads the posted data from the query string and then again validates the data just to ensure data consistency and to prevent any non-validated data because JavaScript was turned off on the clients browser from being inserted in to a database or passed on to other process. If the data passes the second validation check then the server side code will continue with the requested processes. In my opinion, it is mandatory to validate data using client side and server side validation as a fail over process. The client side validation allows users to correct any error before they are sent to the web server for processing, and this allows for an immediate response back to the user regarding data that is not correct or in the proper format that is desired. In addition, this prevents unnecessary interaction between the user and the web server and will free up the server over time compared to doing only server side validation. Server validation is the last line of defense when it comes to validation because you can check to ensure the user’s data is correct before it is used in a business process or stored to a database. Honestly, I cannot foresee a scenario where I would only want to use one form of validation over another especially with the current cost of creating and maintaining data. In my opinion, the redundant validation is well worth the overhead.

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  • Submitting a multidimensional array via POST with php

    - by Fireflight
    I have a php form that has a known number of columns (ex. top diameter, bottom diameter, fabric, colour, quantity), but has an unknown number of rows, as users can add rows as they need. I've discovered how to take each of the fields(columns) and place them into an array of their own. <input name="topdiameter['+current+']" type="text" id="topdiameter'+current+'" size="5" /> <input name="bottomdiameter['+current+']" type="text" id="bottomdiameter'+current+'" size="5" /> So what I end up with in the HTML is: <tr> <td><input name="topdiameter[0]" type="text" id="topdiameter0" size="5" /></td> <td><input name="bottomdiameter[0]" type="text" id="bottomdiameter0" size="5" /></td> </tr> <tr> <td><input name="topdiameter[1]" type="text" id="topdiameter0" size="5" /></td> <td><input name="bottomdiameter[1]" type="text" id="bottomdiameter0" size="5" /></td> </tr> ...and so on. What I would like to do now is take all the rows and columns put them into a multidimensional array and email the contents of that to the client (preferably in a nicely formatted table). I haven't been able to really comprehend how to combine all those inputs and selects into a nice array. At this point, I'm going to have to try to use several 1D arrays, although I have the idea that using a single 2D array would be a better practice than using several 1D arrays.

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  • Bypass django form validation on new form instance

    - by Thomas Schultz
    Hello! I have a situation where we are trying to autofill some form data on the second page of a signup and I was wondering if there's a way to bypass the entire form validation when we pass in only a couple of fields? so we have something like form = NewForm(request.POST) Where request.POST only contains some of the fields in NewForm(). So the page loads and there is feedback about how some fields are not filled in yet. This all happens from the GET request of the second page. Is there a way to do something like... form = NewForm(request.POST, validate=False)

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  • how to submit a form without loosing values already selected at the same form

    - by kawtousse
    Hi everyone, I am using jstl with dropdown lists. When i click submit button i success the specification but values int dropdownlists are reinitialized. So I want to submit form without loosing the values already selected in the form because I need to stay always at the same level in the form.To be more clear, user choose a value from ddl and click edit button to show other options and fill them at the same form without loosing what he has selected. I have tried to deal like that: but it doesn't work. think you for your help.

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  • Passing variables to a Custom Zend Form Element

    - by user322003
    Hi, I'm trying to create a custom form element which extends Zend_Form_Element_Text with a validator (so I don't have to keep setting up the validator when I use certain elements). Anyway, I'm having trouble passing $maxChars variable to it when I instantiate it in my Main form. I've provided my shortened code below This is my custom element below class My_Form_Custom_Element extends Zend_Form_Element_Text { public $maxChars public function init() { $this->addValidator('StringLength', true, array(0, $this->maxChars)) } public function setProperties($maxChars) { $this->maxChars= $maxChars; } } This is where I instantiate my custom form element. class My_Form_Abc extends Zend_Form { public function __construct($options = null) { parent::__construct($options); $this->setName('abc'); $customElement = new My_Form_Custom_Element('myCustomElement'); $customElement->setProperties(100); //**<----This is where i set the $maxChars** $submit = new Zend_Form_Element_Submit('submit'); $submit -> setAttrib('id', 'submitbutton'); $this->addElements(array($customElement ,$submit)); } } When I try to pass '100' using $customElement-setProperties(100) in my Form, it doesnt get passed properly to my StringLength validator. I assume it's because the validator is getting called in Init? How can I fix this?

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  • Handling form from different view and passing form validation through session in django

    - by Mo J. Mughrabi
    I have a requirement here to build a comment-like app in my django project, the app has a view to receive a submitted form process it and return the errors to where ever it came from. I finally managed to get it to work, but I have doubt for the way am using it might be wrong since am passing the entire validated form in the session. below is the code comment/templatetags/comment.py @register.inclusion_tag('comment/form.html', takes_context=True) def comment_form(context, model, object_id, next): """ comment_form() is responsible for rendering the comment form """ # clear sessions from variable incase it was found content_type = ContentType.objects.get_for_model(model) try: request = context['request'] if request.session.get('comment_form', False): form = CommentForm(request.session['comment_form']) form.fields['content_type'].initial = 15 form.fields['object_id'].initial = 2 form.fields['next'].initial = next else: form = CommentForm(initial={ 'content_type' : content_type.id, 'object_id' : object_id, 'next' : next }) except Exception as e: logging.error(str(e)) form = None return { 'form' : form } comment/view.py def save_comment(request): """ save_comment: """ if request.method == 'POST': # clear sessions from variable incase it was found if request.session.get('comment_form', False): del request.session['comment_form'] form = CommentForm(request.POST) if form.is_valid(): obj = form.save(commit=False) if request.user.is_authenticated(): obj.created_by = request.user obj.save() messages.info(request, _('Your comment has been posted.')) return redirect(form.data.get('next')) else: request.session['comment_form'] = request.POST return redirect(form.data.get('next')) else: raise Http404 the usage is by loading the template tag and firing {% comment_form article article.id article.get_absolute_url %} my doubt is if am doing the correct approach or not by passing the validated form to the session. Would that be a problem? security risk? performance issues? Please advise Update In response to Pol question. The reason why I went with this approach is because comment form is handled in a separate app. In my scenario, I render objects such as article and all I do is invoke the templatetag to render the form. What would be an alternative approach for my case? You also shared with me the django comment app, which am aware of but the client am working with requires a lot of complex work to be done in the comment app thats why am working on a new one.

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  • Creating form object for variable kind of form.

    - by Bunny Rabbit
    i want to create a form for users to submit questions in django ..so far the models i have created are class Question(models.Model): statement=models.CharField(max_length=100) class Choice(models.Model): statement=models.CharField(max_length=100) value=models.IntegerField() question=models.ForeignKey(Question) Now i want to write a Form class for creating a above form but the problem is the number of choices are variable,a user can decide how many choices a question must have .How do i do that in django?

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  • Display small form while main form is "locked"

    - by daemonsvk
    Hi there, i'm thinking about writing a WPF program that would require login and password at the app startup. I thought about small form with two textboxes as a login form. User will have to fill in his details and then the main form of the application will be unlocked. How will you solve this? Thanks for your answers, daemonsvk

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  • POST attack on my website

    - by benhowdle89
    Hi, I have a site (humanisms.co.uk) which incorporates a voting system, ie. user clicks "Up" and it sends a parameter to a PHP script via AJAX, the PHP inserts vote into MYSQL db and the new "Up" vote is sent back to the page to update the vote count. This is working great but i've noticed that the number of votes for one of my questions shot up last night. I viewed my webhosts access logs and saw this line: 108.27.195.232 - - [03/Mar/2011:15:20:18 +0000] "POST /vote.php HTTP/1.1" 200 2 "http://www.humanisms.co.uk/" "Mozilla/5.0 (Macintosh; U; Intel Mac OS X 10_6_6; en-US) AppleWebKit/534.16 (KHTML, like Gecko) Chrome/10.0.648.114 Safari/534.16" This is repeated well over 100 times and sometimes more than once a second. Now i know they probably arent sitting there clicking Vote but running some sort of PHP loop? I'm not worried about SQL injection but what can i do to prevent this same IP address from doing this or what can i do in general to avoid this scenario. I should also say that there's no login so anyone can click using the voting system. Thanks

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  • JSON Post To Rails From Android

    - by Stealthnh
    I'm currently working on an android app that interfaces with a Ruby on Rails app through XML and JSON. I can currently pull all my posts from my website through XML but I can't seem to post via JSON. My app currently builds a JSON object from a form that looks a little something like this: { "post": { "other_param": "1", "post_content": "Blah blah blah" } } On my server I believe the Create method in my Posts Controller is set up correctly: def create @post = current_user.posts.build(params[:post]) respond_to do |format| if @post.save format.html { redirect_to @post, notice: 'Post was successfully created.' } format.json { render json: @post, status: :created, location: @post } format.xml { render xml: @post, status: :created, location: @post } else format.html { render action: "new" } format.json { render json: @post.errors, status: :unprocessable_entity } format.xml { render xml: @post.errors, status: :unprocessable_entity } end end end And in my android app I have a method that takes that JSON Object I posted earlier as a parameter along with the username and password for being authenticated (Authentication is working I've tested it, and yes Simple HTTP authentication is probably not the best choice but its a quick and dirty fix) and it then sends the JSON Object through HTTP POST to the rails server. This is that method: public static void sendPost(JSONObject post, String email, String password) { DefaultHttpClient client = new DefaultHttpClient(); client.getCredentialsProvider().setCredentials(new AuthScope(null,-1), new UsernamePasswordCredentials(email,password)); HttpPost httpPost = new HttpPost("http://mysite.com/posts"); JSONObject holder = new JSONObject(); try { holder.put("post", post); StringEntity se = new StringEntity(holder.toString()); Log.d("SendPostHTTP", holder.toString()); httpPost.setEntity(se); httpPost.setHeader("Content-Type","application/json"); } catch (UnsupportedEncodingException e) { Log.e("Error",""+e); e.printStackTrace(); } catch (JSONException js) { js.printStackTrace(); } HttpResponse response = null; try { response = client.execute(httpPost); } catch (ClientProtocolException e) { e.printStackTrace(); Log.e("ClientProtocol",""+e); } catch (IOException e) { e.printStackTrace(); Log.e("IO",""+e); } HttpEntity entity = response.getEntity(); if (entity != null) { try { entity.consumeContent(); } catch (IOException e) { Log.e("IO E",""+e); e.printStackTrace(); } } } Currently when I call this method and pass it the correct JSON Object it doesn't do anything and I have no clue why or how to figure out what is going wrong. Is my JSON still formatted wrong, does there really need to be that holder around the other data? Or do I need to use something other than HTTP POST? Or is this just something on the Rails end? A route or controller that isn't right? I'd be really grateful if someone could point me in the right direction, because I don't know where to go from here.

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  • How to give new life into a five years old, simple but reliable PHP form?

    - by Sam
    Hi all. I have a script in php 5.2. I want to use a simple form. I found something a programmer made for me about 5 years ago. When I use it, PHP outputs an error now unless I set register_long_arrays = On, then it works fine. On the PHP website, however, it says: Warning This feature has been DEPRECATED as of PHP 5.3.0. Relying on this feature is highly discouraged. It's recommended to turn them off, for performance reasons. Instead, use the superglobal arrays, like $_GET. Should I listen to PHP's warning, or just enable the option and keep using my old form happily? If the former, then how/where do I change this simple form, so it does not rely on the deprecated setting? Your answer is much appreciated. form.htm <html><body> <form method="POST" action="form_sent.php"> ... </form> </body></html> form_sent.php <html><body> <?php $email = $HTTP_POST_VARS[email]; $mailto = "[email protected]"; $mailsubj = "A Form was Sent from Website!"; $mailhead = "From: $email\n"; reset ($HTTP_POST_VARS); $mailbody = "Values submitted from web site form:\n"; while (list($key, $val) = each ($HTTP_POST_VARS)){$mailbody .= "$key : $val\n";} if (!eregi("\n",$HTTP_POST_VARS[email])) { mail($mailto, $mailsubj, $mailbody, $mailhead); } ?> <b>Form Sent. Thank you.</b> </body></html>

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  • CSS Hidden DIV Form Submit

    - by Michael
    Using CSS, when a link is clicked it brings up a hidden DIV that contains a form. The user will then enter information and then submit the form. I'd like the hidden DIV to remain visisble, and a 'success message' to be displayed after submission. Then the user will have the option of closing the DIV. I can't get it to work without reloading the page, which causes the DIV to become hidden again. Any ideas? <body> <a href="javascript:showDiv()" style="color: #fff;">Click Me</a> <!--POPUP--> <div id="hideshow" style="visibility:hidden;"> <div id="fade"></div> <div class="popup_block"> <div class="popup"> <a href="javascript:hideDiv()"> <img src="images/icon_close.png" class="cntrl" title="Close" /> </a> <h3>Remove Camper</h3> <form method="post" onsubmit="email.php"> <p><input name="Name" type="text" /></p> <p><input name="Submit" type="submit" value="submit" /></p> </form> <div id="status" style="display:none;">success</div> </div> </div> </div> <!--END POPUP--> <script language=javascript type='text/javascript'> function hideDiv() { if (document.getElementById) { // DOM3 = IE5, NS6 document.getElementById('hideshow').style.visibility = 'hidden'; } else { if (document.layers) { // Netscape 4 document.hideshow.visibility = 'hidden'; } else { // IE 4 document.all.hideshow.style.visibility = 'hidden'; } } } function showDiv() { if (document.getElementById) { // DOM3 = IE5, NS6 document.getElementById('hideshow').style.visibility = 'visible'; } else { if (document.layers) { // Netscape 4 document.hideshow.visibility = 'visible'; } else { // IE 4 document.all.hideshow.style.visibility = 'visible'; } } } </script> </body>

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  • POST data not being received

    - by Alexander
    I've got an iPhone App that is supposed to send POST data to my server to register the device in a MySQL database so we can send notifications etc... to it. It sends it's unique identifier, device name, token, and a few other small things like passwords and usernames as a POST request to our server. The problem is that sometimes the server doesn't receive the data. And by this I mean, its not just receiving blank values for the POST inputs but, its not receiving ANY post data at all. I am logging all POST inputs to my server into some log files and when the script that relies on the POST data from the device fails (detects no data) I notice that its because NO POST data was sent. Is this a problem on the server, like refusing data or something or does this have to be on the client's side? What could be causing this?

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  • Reorder inputs before submiting form

    - by Jason
    Is there any way to reorder or manipulate a set of inputs before posting to a script for processing? I'm able to reorder the elements in the DOM no problem, but getting this to happen after the user presses the submit button and before the browser makes the POST is a bit tricky. I'm using the ajaxForm plugin in jQuery. There is a beforeSubmit callback, but this doesn't seem to allow me to reorded the inputs.

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  • Form graphics not set when form loads

    - by Jimmy
    My form has a group box which contains two overlapping rectangles. The form's other controls are two sets of four numeric up down controls to set the rectangles' colors. (nudF1,2,3 and 4 set the rectangle that's in front, and nudB1,2,3 and 4 set the rectangle that's behind.) Everything works fine, except that the rectangles do not display the colors set in the numeric up downs when the form first loads. The numeric up down controls' ChangeValue events all call the ShowColors() method. The form's Load event calls the csColorsForm_Load() method. Any suggestions? namespace csColors { public partial class csColorsForm : Form { public csColorsForm() { InitializeComponent(); } private void csColorsForm_Load(object sender, EventArgs e) { this.BackColor = System.Drawing.Color.DarkBlue; SetColors(sender, e); } private void SetColors(object sender, EventArgs e) { Control control = (Control)sender; String ctrlName = control.Name; Graphics objGraphics; Rectangle rect1, rect2; int colorBack, colorFore; objGraphics = this.grpColor.CreateGraphics(); // If calling control is not a forecolor control, paint backcolor rectangle if (ctrlName.Substring(0,4)!="nudF") { colorBack = int.Parse(SetColorsB("nudB"), NumberStyles.HexNumber); SolidBrush BrushB = new SolidBrush(Color.FromArgb(colorBack)); rect1 = new Rectangle(this.grpColor.Left, this.grpColor.Top, this.grpColor.Width, this.grpColor.Height); objGraphics.FillRectangle(BrushB, rect1); } // Always paint forecolor rectangle colorFore = int.Parse(SetColorsB("nudF"), NumberStyles.HexNumber); SolidBrush BrushF = new SolidBrush(Color.FromArgb(colorFore)); rect2 = new Rectangle(this.grpColor.Left, this.grpColor.Top, this.grpColor.Width, this.grpColor.Height); objGraphics.FillRectangle(BrushF, rect2); objGraphics.Dispose(); } private string SetColorsB(string nam) { string txt=""; for (int n = 1; n <= 4; ++n) { var ud = Controls[nam + n] as NumericUpDown; int hex = (int)ud.Value; txt += hex.ToString("X2"); } return txt; } private void btnClose_Click(object sender, EventArgs e) { this.Close(); } } }

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  • Problem retrieving values from Zend_Form_SubForms - no values returned

    - by anu iyer
    I have a Zend_Form that has 4 or more subforms. /** Code Snippet **/ $bigForm = new Zend_Form(); $littleForm1 = new Form_LittleForm1(); $littleForm1->setMethod('post'); $littleForm2 = new Form_LittleForm2(); $littleForm2->setMethod('post'); $bigForm->addSubForm($littleForm1,'littleForm1',0); $bigForm->addSubForm($littleForm2,'littleForm2',0); On clicking the 'submit' button, I'm trying to print out the values entered into the forms, like so: /** Code snippet, currently not validating, just printing **/ if($this-_request-getPost()){ $formData = array(); foreach($bigForm->getSubForms() as $subForm){ $formData = array_merge($formData, $subForm->getValues()); } /* Testing */ echo "<pre>"; print_r($formData); echo "</pre>"; } The end result is that - all the elements in the form do get printed, but the values entered before posting the form don't get printed. Any thoughts are appreciated...I have run around circles working on this! Thanks in advance!

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  • Using JS to POST a form in an iframe.

    - by Stavros Korokithakis
    I would like to POST a form in an iframe, generated like so: My JS loads an iframe inside the page, adds a form to the iframe and submits the form. What I would like to happen is the iframe to load the result of that request. So, I would effectively like to post a form and render the result inside the iframe, without touching the parent (apart from putting the iframe up for display in the first place). I am using the code from this answer: http://stackoverflow.com/questions/133925/javascript-post-request-like-a-form-submit/134003#134003 but I can't get it to not reload the parent. I post the form, and instead of the iframe refreshing, the entire parent refreshes. I don't know why that is, since the url it's posting to is different and would at least redirect there. Can anyone help me with this problem? I just want a post inside an iframe and only within the iframe, basically.

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  • adding Form Validation Javacript of jquery???

    - by user634599
    How can I add inline Validation to make sure a choice of radio input must be selected <script type="text/javascript"> function choosePage() { if(document.getElementById('weightloss').form1_option1.checked) { window.location.replace( "http://google.com/" ); } if(document.getElementById('weightloss').form1_option2.checked) { window.location.replace( "http://yahoo.com/" ); } } </script> <form id="weightloss"> <input type="radio" id="form1_option1" name="weight-loss" value="5_day" class="plan"> <label for="form1_option1"> 5 Day - All Inclusive Price</label><br> <input type="radio" id="form1_option2" name="weight-loss" value="7_day"> <label for="form1_option2"> 7 Day - All Inclusive Price</label><br> <input type="button" value="Place Order" alt="Submit button" class="orange_btn" onclick="choosePage()"> </form>

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  • Apache & SVN on Ubuntu - Post-commit hook fails silently, pre-commit hook “Permission Denied”

    - by 113169587962668775787
    I've been struggling for the past couple days to get post-commit email notifications working on my SVN server (running via HTTP with Apache2 on Ubuntu 9.10). SVN commits work fine, but for some reason the hooks are not being properly executed. Here are the configuration settings: - Users access the repo via HTTP with the apache dav_svn module (I created users/passwords via htpasswd in a dav_svn.passwd file). dav_svn.conf: <Location /svn/repos> DAV svn SVNPath /home/svn/repos AuthType Basic AuthName "Subversion Repository" AuthUserFile /etc/apache2/dav_svn.passwd Require valid-user </Location> I created a post-commit hook file that writes a simple message to a file in the repository root: /home/svn/repos/hooks/post-commit: #!/bin/sh REPOS="$1" REV="$2" /bin/echo 'worked' > ${REPOS}/postcommit.log I set the entire repository to be owned by www-data (the apache user), and assigned 755 permissions to the post-commit script when I test the post-commit script using the www-data user in an empty environment, it works: sudo -u www-data env - /home/svn/repos/hooks/post-commit /home/svn/repos 7 But when I commit on a client machine, the commit is successful, but the post-commit script does not seem to be executed. I also tried running a simple script for the pre-commit hook, and I get an error, even with an empty pre-commit script: "Commit failed (details follow): Can't create null stdout for hook '/home/svn/repos/hooks/pre-commit': Permission denied" I did a few searches on Google for this error and I presume that this is an issue with the apache user (www-data) not having adequate permissions, specifically to execute /dev/null. I also read that the reason post-commit fails silently is because that it doesn't report with stdout. Anyway, I've also tried giving the apache user (www-data) ownership of the entire repository, and edited the apache virtualhost to allow operations on the server root, and I'm still getting permission denied /etc/apache2/sites-available/primarydomain.conf <Directory /> Options FollowSymLinks AllowOverride None Order allow,deny Allow from all </Directory> Any ideas/suggestions would be greatly appreciated! Thanks

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  • What is the best way to post data from web browser to server?

    - by Kronass
    Hi, I want to know what is the best way to send data from web browser to server using post method. I've seen a practice where they wrap all the elements data in XML, convert it into Base64 string and then post it to the server (via Ajax or hidden field). this way will not work if the Javascript is disabled, any how if I ignored this. is it a good practice to wrap elements into XML (or create my custom wrapper in general) and post them to server saying it will enhance the maintainability of the code or just stick with the classical way and no need to add unnecessary text in the post.

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  • Subversion multi checkout post-commit hook?

    - by FLX
    The title must sound strange but I'm trying to achieve the following: SVN repo location: /home/flx/svn/flxdev SVN repo "flxdev" structure: + Project1 ++ files + Project2 + Project3 + Project4 I'm trying to set up a post-commit hook that automatically checks out on the other end when I do a commit. The post-commit doc explicitly lists the following: # POST-COMMIT HOOK # # The post-commit hook is invoked after a commit. Subversion runs # this hook by invoking a program (script, executable, binary, etc.) # named 'post-commit' (for which this file is a template) with the # following ordered arguments: # # [1] REPOS-PATH (the path to this repository) # [2] REV (the number of the revision just committed) So I made the following command to test: REPOS="$1" REV="$2" echo "Updated project $REPOS to $REV" However when I edit files in Project1 for example, this outputs "Updated project /home/flx/svn/flxdev to 1016" I'd like this to be: "Updated project Project1 to 1016" Having this variable allows me to specify to do different actions per project post-commit. How can I specify the project parameter? Thanks! Dennis

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