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  • How do I use a .NET class in VBA? Syntax help!

    - by Jordan S
    ok I have couple of .NET classes that I want to use in VBA. So I must register them through COM and all that. I think I have the COM registration figured out (finally) but now I need help with the syntax of how to create the objects. Here is some pseudo code showing what I am trying to do. EDIT: Changed Attached Objects to return an ArrayList instead of a List The .NET classes look like this... public class ResourceManagment { public ResourceManagment() { // Default Constructor } public static List<RandomObject> AttachedObjects() { ArrayList list = new ArrayList(); return list; } } public class RandomObject { // public RandomObject(int someParam) { } } OK, so this is what I would like to do in VBA (demonstrated in C#) but I don't know how... public class VBAClass { public void main() { ArrayList myList = ResourceManagment.AttachedObjects(); foreach(RandomObject x in myList) { // Do something with RandomObject x like list them in a Combobox } } } One thing to note is that RandomObject does not have a public default constructor. So I can not create an instance of it like Dim x As New RandomObject. MSDN says that you can not instantiate an object that doesn't have a default constructor through COM but you can still use the object type if it is returned by another method... Types must have a public default constructor to be instantiated through COM. Managed, public types are visible to COM. However, without a public default constructor (a constructor without arguments), COM clients cannot create an instance of the type. COM clients can still use the type if the type is instantiated in another way and the instance is returned to the COM client. You may include overloaded constructors that accept varying arguments for these types. However, constructors that accept arguments may only be called from managed (.NET) code. Added: Here is my attempt in VB: Dim count As Integer count = 0 Dim myObj As New ResourceManagment For Each RandomObject In myObj.AttachedObjects count = count + 1 Next RandomObject

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  • Simple way to decrease values without making a new attribute?

    - by Jam
    I'm making a program where you're firing a 'blaster', and I have 5 ammo. I'm blasting an alien who has 5 health. At the end I instantiate the player and make him blast 6 times to check that the program works correctly. But the way I've done it makes it so that the amount won't decrease. Is there an easy fix to this, or do I just have to make a new attribute for ammo and health? Here's what I have: class Player(object): """ A player in a shooter game. """ def blast(self, enemy, ammo=5): if ammo>=1: ammo-=1 print "You have blasted the alien." print "You have", ammo, "ammunition left." enemy.die(5) else: print "You are out of ammunition!" class Alien(object): """ An alien in a shooter game. """ def die(self, health=5): if health>=1: health-=1 print "The alien is wounded. He now has", health, "health left." elif health==0: health-=1 print "The alien gasps and says, 'Oh, this is it. This is the big one. \n" \ "Yes, it's getting dark now. Tell my 1.6 million larvae that I loved them... \n" \ "Good-bye, cruel universe.'" else: print "The alien's corpse sits up momentarily and says, 'No need to blast me, I'm dead already!" # main print "\t\tDeath of an Alien\n" hero = Player() invader = Alien() hero.blast(invader) hero.blast(invader) hero.blast(invader) hero.blast(invader) hero.blast(invader) hero.blast(invader) raw_input("\n\nPress the enter key to exit.")

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  • Instantiating and starting a Scala Actor in a Map

    - by Bruce Ferguson
    I'm experimenting with a map of actors, and would like to know how to instantiate them and start them in one fell swoop... import scala.actors.Actor import scala.actors.Actor._ import scala.collection.mutable._ abstract class Message case class Update extends Message object Test { val groupings = "group1" :: "group2" :: "group3":: Nil val myActorMap = new HashMap[String,MyActor] def main(args : Array[String]) { groupings.foreach(group => myActorMap += (group -> new MyActor)) myActorMap("group2").start myActorMap("group2") ! Update } } class MyActor extends Actor { def act() { loop { react { case Update => println("Received Update") case _ => println("Ignoring event") } } } } The line: myActorMap("group2").start will grab the second instance, and let me start it, but I would like to be able to do something more like: groupings.foreach(group => myActorMap += (group -> (new MyActor).start)) but no matter how I wrap the new Actor, the compiler complains with something along the lines of: type mismatch; found : scala.actors.Actor required: com.myCompany.test.MyActor or various other complaints. I know it must be something simple to do with anonymous classes, but I can't see it right now. Any suggestions? Thanks in advance!!

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  • Insane SmartGWT + GWT situation... Error on instantiating ListGridRecord?

    - by Xandel
    Hi all, I am asking this here in the hope that someone has maybe come across this situation too... I have posted this on the SmartGWT forum: I am having an issue when trying to instantiate a ListGridRecord object on my server side. I am using the ListGrid on the client side, I want to use GWT's RPC to pass back an array of ListGridRecord objects to populate the grid with. I know that SmartGWT is designed to link to a datasource but I want full control over when I populate the grid and this shouldn't be as much of a nightmare as it is to do. I have searched high and low and cannot find anyone complaining about the same thing. The exception however (listed below) has come up (in my search findings) as a possible memory error - where increasing the memory (-Xmx512m argument) has apparently solved the problem. It did not, however, sort out mine. If anyone can shed any light on this I would greatly appreciate it! Here are my details: Developing using Eclipse Galileo on Ubuntu 9.04 (Jaunty) and GWT 2.0.3, I built the initial GWT project using the webAppCreator bundled with the GWT 2.0.3 release and imported the project into Eclipse as described on the GWT Getting Started Page (as using the GWT Eclipse plugin caused even more nightmares when trying to connect to a database - this is apparently due to using the Google App Engine and turning it off as all the posts suggested only causes ClassNotFound exceptions). The line that causes the error is literally: ListGridRecord a = new ListGridRecord(); The error I get is the following: 00:00:25.916 [WARN] Exception while dispatching incoming RPC call com.google.gwt.user.server.rpc.UnexpectedException : Service method 'public abstract java.lang.String za.co.company.product.client.service.EmployeeServi ce.getAllEmployeeAsListGridRecord()' threw an unexpected exception: java.lang.UnsatisfiedLinkError: com.smartgwt.client.util.LogUtil.setJSNIErrorHandl er()V at com.google.gwt.user.server.rpc.RPC.encodeResponseF orFailure(RPC.java:378) at com.google.gwt.user.server.rpc.RPC.invokeAndEncode Response(RPC.java:581) at com.google.gwt.user.server.rpc.RemoteServiceServle t.processCall(RemoteServiceServlet.java:188) at com.google.gwt.user.server.rpc.RemoteServiceServle t.processPost(RemoteServiceServlet.java:224) at com.google.gwt.user.server.rpc.AbstractRemoteServi ceServlet.doPost(AbstractRemoteServiceServlet.java :62) at javax.servlet.http.HttpServlet.service(HttpServlet .java:637) at javax.servlet.http.HttpServlet.service(HttpServlet .java:717) at org.mortbay.jetty.servlet.ServletHolder.handle(Ser vletHolder.java:487) at org.mortbay.jetty.servlet.ServletHandler.handle(Se rvletHandler.java:362) at org.mortbay.jetty.security.SecurityHandler.handle( SecurityHandler.java:216) at org.mortbay.jetty.servlet.SessionHandler.handle(Se ssionHandler.java:181) at org.mortbay.jetty.handler.ContextHandler.handle(Co ntextHandler.java:729) at org.mortbay.jetty.webapp.WebAppContext.handle(WebA ppContext.java:405) at org.mortbay.jetty.handler.HandlerWrapper.handle(Ha ndlerWrapper.java:152) at org.mortbay.jetty.handler.RequestLogHandler.handle (RequestLogHandler.java:49) at org.mortbay.jetty.handler.HandlerWrapper.handle(Ha ndlerWrapper.java:152) at org.mortbay.jetty.Server.handle(Server.java:324) at org.mortbay.jetty.HttpConnection.handleRequest(Htt pConnection.java:505) at org.mortbay.jetty.HttpConnection$RequestHandler.co ntent(HttpConnection.java:843) at org.mortbay.jetty.HttpParser.parseNext(HttpParser. java:647) at org.mortbay.jetty.HttpParser.parseAvailable(HttpPa rser.java:211) at org.mortbay.jetty.HttpConnection.handle(HttpConnec tion.java:380) at org.mortbay.io.nio.SelectChannelEndPoint.run(Selec tChannelEndPoint.java:395) at org.mortbay.thread.QueuedThreadPool$PoolThread.run (QueuedThreadPool.java:488) Caused by: java.lang.UnsatisfiedLinkError: com.smartgwt.client.util.LogUtil.setJSNIErrorHandl er()V at com.smartgwt.client.util.LogUtil.setJSNIErrorHandl er(Native Method) at com.smartgwt.client.core.JsObject.(JsObjec t.java:30) at za.co.company.product.server.service.EmployeeServi ceImpl.getAllEmployeeAsListGridRecord(EmployeeServ iceImpl.java:83) at sun.reflect.NativeMethodAccessorImpl.invoke0(Nativ e Method) at sun.reflect.NativeMethodAccessorImpl.invoke(Native MethodAccessorImpl.java:39) at sun.reflect.DelegatingMethodAccessorImpl.invoke(De legatingMethodAccessorImpl.java:25) at java.lang.reflect.Method.invoke(Method.java:597) at com.google.gwt.user.server.rpc.RPC.invokeAndEncode Response(RPC.java:562) at com.google.gwt.user.server.rpc.RemoteServiceServle t.processCall(RemoteServiceServlet.java:188) at com.google.gwt.user.server.rpc.RemoteServiceServle t.processPost(RemoteServiceServlet.java:224) at com.google.gwt.user.server.rpc.AbstractRemoteServi ceServlet.doPost(AbstractRemoteServiceServlet.java :62) at javax.servlet.http.HttpServlet.service(HttpServlet .java:637) at javax.servlet.http.HttpServlet.service(HttpServlet .java:717) at org.mortbay.jetty.servlet.ServletHolder.handle(Ser vletHolder.java:487) at org.mortbay.jetty.servlet.ServletHandler.handle(Se rvletHandler.java:362) at org.mortbay.jetty.security.SecurityHandler.handle( SecurityHandler.java:216) at org.mortbay.jetty.servlet.SessionHandler.handle(Se ssionHandler.java:181) at org.mortbay.jetty.handler.ContextHandler.handle(Co ntextHandler.java:729) at org.mortbay.jetty.webapp.WebAppContext.handle(WebA ppContext.java:405) at org.mortbay.jetty.handler.HandlerWrapper.handle(Ha ndlerWrapper.java:152) at org.mortbay.jetty.handler.RequestLogHandler.handle (RequestLogHandler.java:49) at org.mortbay.jetty.handler.HandlerWrapper.handle(Ha ndlerWrapper.java:152) at org.mortbay.jetty.Server.handle(Server.java:324) at org.mortbay.jetty.HttpConnection.handleRequest(Htt pConnection.java:505) at org.mortbay.jetty.HttpConnection$RequestHandler.co ntent(HttpConnection.java:843) at org.mortbay.jetty.HttpParser.parseNext(HttpParser. java:647) at org.mortbay.jetty.HttpParser.parseAvailable(HttpPa rser.java:211) at org.mortbay.jetty.HttpConnection.handle(HttpConnec tion.java:380) at org.mortbay.io.nio.SelectChannelEndPoint.run(Selec tChannelEndPoint.java:395) at org.mortbay.thread.QueuedThreadPool$PoolThread.run (QueuedThreadPool.java:488) Thanks in advance! Xandel

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  • Reinstantiating a GUI (JFrame) object

    - by Alex
    Hi guys, basically I want my JFrame to become a completely new JFrame object when an event is triggered. I have some code that basically calls [CODE]GUI gui = new GUI(x, y)[/CODE] the only problem I'm having is that as well as creating the new GUI object, it is not deleting the old window. Can anyone tell me how to get rid of the old window. Thanks.

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  • When not to use Spring to instantiate a bean?

    - by Rishabh
    I am trying to understand what would be the correct usage of Spring. Not syntactically, but in term of its purpose. If one is using Spring, then should Spring code replace all bean instantiation code? When to use or when not to use Spring, to instantiate a bean? May be the following code sample will help in you understanding my dilemma: List<ClassA> caList = new ArrayList<ClassA>(); for (String name : nameList) { ClassA ca = new ClassA(); ca.setName(name); caList.add(ca); } If I configure Spring it becomes something like: List<ClassA> caList = new ArrayList<ClassA>(); for (String name : nameList) { ClassA ca = (ClassA)SomeContext.getBean(BeanLookupConstants.CLASS_A); ca.setName(name); caList.add(ca); } I personally think using Spring here is an unnecessary overhead, because The code the simpler to read/understand. It isn't really a good place for Dependency Injection as I am not expecting that there will be multiple/varied implementation of ClassA, that I would like freedom to replace using Spring configuration at a later point in time. Am I thinking correct? If not, where am I going wrong?

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  • Where best to instantiate and close a Silverlight-enabled WCF Service from the Silverlight app?

    - by Yttrium
    When using a Silverlight-enabled WCF service, where is the best place to instantiate the service and to call the CloseAsync() method? Should you say, instantiate an instance each time you need to make a call to the service, or is it better to just instantiate an instance as a variable of the UserControl that will be making the calls? Then, where is it better to call the CloseAsync method? Should you call it in each of the "someServiceCall_completed" event methods? Or, if created as a variable of the UserControl class, is there a single place to call it? Like a Dispose method, or something equivalent for the UserControl class. Thanks, Jeff

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  • How can a collection class instantiate many objects with one database call?

    - by Buttle Butkus
    I have a baseClass where I do not want public setters. I have a load($id) method that will retrieve the data for that object from the db. I have been using static class methods like getBy($property,$values) to return multiple class objects using a single database call. But some people say that static methods are not OOP. So now I'm trying to create a baseClassCollection that can do the same thing. But it can't, because it cannot access protected setters. I don't want everyone to be able to set the object's data. But it seems that it is an all-or-nothing proposition. I cannot give just the collection class access to the setters. I've seen a solution using debug_backtrace() but that seems inelegant. I'm moving toward just making the setters public. Are there any other solutions? Or should I even be looking for other solutions?

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  • Should I pass an object into a constructor, or instantiate in class?

    - by Prisoner
    Consider these two examples: Passing an object to a constructor class ExampleA { private $config; public function __construct($config) { $this->config = $config; } } $config = new Config; $exampleA = new ExampleA($config); Instantiating a class class ExampleB { private $config; public function __construct() { $this->config = new Config; } } $exampleA = new ExampleA(); Which is the correct way to handle adding an object as a property? When should I use one over the other? Does unit testing affect what I should use?

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  • How can I instantiate a base class and then convert it to a derived class?

    - by Eric
    I was wondering how to do this, consider the following classes public class Fruit { public string Name { get; set; } public Color Color { get; set; } } public class Apple : Fruit { public Apple() { } } How can I instantiate a new fruit but upcast to Apple, is there a way to instantiate a bunch of Fruit and make them apples with the name & color set. Do I need to manually deep copy? Of course this fails Fruit a = new Fruit(); a.Name = "FirstApple"; a.Color = Color.Red; Apple wa = a as Apple; System.Diagnostics.Debug.Print("Apple name: " + wa.Name); Do I need to pass in a Fruit to the AppleCTor and manually set the name and color( or 1-n properties) Is there an better design to do this?

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  • What's the correct way to instantiate an IRepository class from the Controller?

    - by GenericTypeTea
    I have the following project layout: MVC UI |...CustomerController (ICustomerRepository - how do I instantiate this?) Data Model |...ICustomerRepository DAL (Separate Data access layer, references Data Model to get the IxRepositories) |...CustomerRepository (inherits ICustomerRepository) What's the correct way to say ICustomerRepository repository = new CustomerRepository(); when the Controller has no visibility to the DAL project? Or am I doing this completely wrong?

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  • C#: Dynamically instantiate different classes in the same statement?

    - by C. Griffin
    Here is a simplified version of what I'm trying to do: Without having multiple if..else clauses and switch blocks, can I mimic the behavior of Javascript's eval() shudder to instantiate a class in C#? // Determine report orientation -- Portrait or Landscape // There are 2 differently styled reports (beyond paper orientation) string reportType = "Portrait"; GenericReport report; report = new eval(reportType + "Report()"); // Resolves to PortraitReport() The need stems from the fact that I have 6 types of Crystal Reports (that do the same thing, but look drastically different) for 50 states. There are 3 styles each, rather than entertain the notion of a giant switch block with nested if..else statements determining which of 900 reports to use, I was hoping for an eval-like solution.

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  • How do I dynamically instantiate a class in javascript?

    - by Adam
    I'm starting out with classes in Javascript and have hit a wall. I've looked all over for a tutorial that goes a little further than simply how to construct a class (usually Animal) then extend the class and have a Method do something (Dog alert('Bark');). I have created a class that I want a user to be able to instantiate (is that the right word)? For example the first stage in my program is for the user to give the class a name, and then start to populate the various variables in the class. When they've done that they may do it again many times. So if: var className = new MyObject(); How do I dynamically create the name of the new object className and then refer to it later in the code?

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  • How to instantiate objects of classes that have dependencies injected?

    - by chester89
    Let's say I have some class with dependency injected: public class SomeBusinessCaller { ILogger logger; public SomeBusinessCaller(ILogger logger) { this.logger = logger; } } My question is, how do I instantiate an object of that class? Let's say I have an implementation for this, called AppLogger. After I say ObjectFactory.For<ILogger>().Use<AppLogger>(); how do I call constructor of SomeBusinessCaller? Am I calling SomeBusinessCaller caller = ObjectFactory.GetInstance<SomeBusinessCaller>(); or there is a different strategy for that?

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  • Can I serialize an object if I didn't write the class used to instantiate that object?

    - by Richard77
    Hello, I've a simple class [Serializable] public class MyClass { public String FirstName { get; set: } public String LastName { get; set: } //Bellow is what I would like to do //But, it's not working //I get an exception ContactDataContext db = new ContactDataContext(); public void Save() { Contact contact = new Contact(); contact.FirstName = FirstName; contact.LastName = LastName; db.Contacts.InsertOnSubmit(contact); db.SubmitChanges(); } } I wanted to attach a Save method to the class so that I could call it on each object. When I introduced the above statement which contains ContactDataContext, I got the following error "In assembly ... PublicKeyToken=null' is not marked as serializable" It's clear that the DataContext class is generated by the framework (). I checked and did not see where that class was marked serialize. What can I do to overcome that? What's the rule when I'm not the author of a class? Just go ahead and mark the DataContext class as serializable, and pretend that everything will work? Thanks for helping

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  • JQuery: is it possible to instantiate a class on client and pass it to $.ajax to post?

    - by nisardotnet
    what i mean by that is: i have a class called Customer: public class Customer { private string _firstName; private string _lastName; public string FirstName { get { return _firstName; } set { _firstName = value; } } public string LastName { get { return _lastName; } set { _lastName = value; } } } how do i instantitate the class "Customer" on the client code and add the data and post it? (not sure if this is possible) here is my client code: var customer = { "firstName": escape($('#txtFirstName').val()), "lastName": escape($('#txtLastName').val()) }; var jsonText = JSON.stringify({ customer: customer }); $.ajax( { type: "POST", url: "VisitorWS.asmx/AddCustomer", data: jsonText , //data: JSON.stringify(params), contentType: "application/json; charset=utf-8", dataType: "json", ...........

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  • How do I initialize attributes when I instantiate objects in Rails?

    - by nfm
    Clients have many Invoices. Invoices have a number attribute that I want to initialize by incrementing the client's previous invoice number. For example: @client = Client.find(1) @client.last_invoice_number > 14 @invoice = @client.invoices.build @invoice.number > 15 I want to get this functionality into my Invoice model, but I'm not sure how to. Here's what I'm imagining the code to be like: class Invoice < ActiveRecord::Base ... def initialize(attributes = {}) client = Client.find(attributes[:client_id]) attributes[:number] = client.last_invoice_number + 1 client.update_attributes(:last_invoice_number => client.last_invoice_number + 1) end end However, attributes[:client_id] isn't set when I call @client.invoices.build. How and when is the invoice's client_id initialized, and when can I use it to initialize the invoice's number? Can I get this logic into the model, or will I have to put it in the controller?

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  • How to instantiate a particular view controller with storyboard in iOS at early stage of loading?

    - by dmirkitanov
    When using tabs with storyboard in iOS 5, some of them may take quite a long time to initialize when switching to it (for example, a tab containing GLKViewController). This happens because an amount of work in viewDidLoad method in this controller could be very big. Is there a way to initialize particular view controller (and call it's viewDidLoad method) defined in the storyboard at early stage - when an application starts? Having done this, the delay should be eliminated.

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