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  • How to get corresponding build artifacts of a job in jenkins ?

    - by kaleeswaran14
    I create Jenkins jobs using hudson.cli.CLI jar. I have selected "Archive the artifacts" option in the "Post-build steps" section. It archives the artifacts on each succesfull build. I am using jenkins remote access api http://localhost:8080/job/job_name/api/json to get details about jobs. and http://localhost:8080/job/job_name/job_number/api/json to get details about builds. When I delete a build corresponding archived artifacts are not deleted. I'd like to make sure that they are deleted. When I use jenkins remote access api http://localhost:8080/job/[job_name]/[job_number]/api/json for a build, it returns json data which contains all previously archived artifacts (other successful builds artifacts) with this (running build) build artifact. How do I get related artifact of a build (a successful build should return its artifact, not all previous successfull artifacts). Any suggestions or ideas ?

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  • how a thread can signal when it's finished?

    - by Kyle
    #include <iostream> #include <boost/thread.hpp> using std::endl; using std::cout; using namespace boost; mutex running_mutex; struct dostuff { volatile bool running; dostuff() : running(true) {} void operator()(int x) { cout << "dostuff beginning " << x << endl; this_thread::sleep(posix_time::seconds(2)); cout << "dostuff is done doing stuff" << endl; mutex::scoped_lock running_lock(running_mutex); running = false; } }; bool is_running(dostuff& doer) { mutex::scoped_lock running_lock(running_mutex); return doer.running; } int main() { cout << "Begin.." << endl; dostuff doer; thread t(doer, 4); if (is_running(doer)) cout << "Cool, it's running.\n"; this_thread::sleep(posix_time::seconds(3)); if (!is_running(doer)) cout << "Cool, it's done now.\n"; else cout << "still running? why\n"; // This happens! :( return 0; } Why is the output of the above program: Begin.. Cool, it's running. dostuff beginning 4 dostuff is done doing stuff still running? why How can dostuff correctly flag when it is done? I do not want to sit around waiting for it, I just want to be notified when it's done.

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  • Best boost to productivity : SSD or second screen ?

    - by jfoucher
    Within the same budget, which do you think would be the best boost to productivity for general web development : An SSD as boot drive, or a second screen ? I currently use a 16.4" laptop with full HD screen and 7200 RPM HDD Thanks EDIT: In light of the answers so far, I add that I work at home and while I have a home office with a proper desk, I'm just as often coding sitting on the sofa in the living room.

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  • 5 Easy Ways to Get High PR Links to Boost Your Site in Google

    High PR links are some of the most valuable aspects in any link-building & SEO campaign. Not only do these links make Google respect your site more, but they can also boost your site's ranking overnight. Here are 5 places to get high quality links that will do a lot of good to your site's ranking in Google.

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  • How SEO Services by a SEO Company Can Boost Your Sales

    If we look at the present scenario the importance of growing your business and expanding your online brand recognition using all the strategic SEO elements available can just not be overstated. Today to be the very best at marketing the business or even the websites has to reach to its potential customers and hiring SEO companies and SEO experts is proving best method to keep track of the latest developments in search engine optimization. In this article, know how taking help of SEO services from any SEO company can actually boost up your sales.

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  • How SEO Services by a SEO Company Can Boost Your Sales

    If we look at the present scenario the importance of growing your business and expanding your online brand recognition using all the strategic SEO elements available can just not be overstated. Today to be the very best at marketing the business or even the websites has to reach to its potential customers and hiring SEO companies and SEO experts is proving best method to keep track of the latest developments in search engine optimization. In this article, know how taking help of SEO services from any SEO company can actually boost up your sales.

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  • Advanced SEO Strategy Guaranteed to Boost Your SEO

    One of the main factors for optimising your website for page 1 on Google is to get incoming links from other web pages, and to boost the effectiveness of those links there are a few things to consider, including the relevance of the page where your link is coming from, plus the link itself needs to be relevant to the keywords that you are targeting on Google. Here's one strategy you can use for getting great incoming links to help you achieve higher Google rankings.

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  • Boost Profits on Your Website

    By now you may have already built a website but are still not raking in profits from it. Your next step is to use some SEO strategies to boost its search rankings and convince site visitors to either buy something from you or avail of an offer.

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  • Forum Sites - Boost Your Search Marketing

    Forum sites boost your search marketing. Why? Finding the right site for your business is essential to boosting your online marketing; find the right community, one that deals with your specific services. Don't waste your time in a site that has no relevance to what you're offering. Find out the hub sites for your services by using keywords related to you.

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  • How does versioning work when using Boost Serialization for Derived Classes?

    - by Venkata Adusumilli
    When a Client serializes the following data: InternationalStudent student; student.id("Client ID"); student.firstName("Client First Name"); student.country("Client Country"); the Server receives the following: ID = "Client ID" Country = "Client First Name" instead of the following: ID = "Client ID" Country = "Client Country" The only difference between the Server and Client classes is the First Name of the Student. How can we make the Server ignore First Name recieved from the Client and process the Country? Server Side Classes class Student { public: Student(){} virtual ~Student(){} public: std::string id() { return idM; } void id(std::string id) { idM = id; } protected: friend class boost::serialization::access; protected: std::string idM; protected: template<class A> void serialize(A& archive, const unsigned int /*version*/) { archive & BOOST_SERIALIZATION_NVP(idM); } }; class InternationalStudent : public Student { public: InternationalStudent() {} ~InternationalStudent() {} public: std::string country() { return countryM; } void country(std::string country) { countryM = country; } protected: friend class boost::serialization::access; protected: std::string countryM; protected: template<class A> void serialize(A& archive, const unsigned int /*version*/) { archive & BOOST_SERIALIZATION_NVP(boost::serialization::base_object<Student>(*this)); archive & BOOST_SERIALIZATION_NVP(countryM); } }; Client Side Classes class Student { public: Student(){} virtual ~Student(){} public: std::string id() { return idM; } void id(std::string id) { idM = id; } std::string firstName() { return firstNameM; } void firstName(std::string name) { firstNameM = name; } protected: friend class boost::serialization::access; protected: std::string idM; std::string firstNameM; protected: template<class A> void serialize(A& archive, const unsigned int /*version*/) { archive & BOOST_SERIALIZATION_NVP(idM); if (version >=1) { archive & BOOST_SERIALIZATION_NVP(firstNameM); } } }; BOOST_CLASS_VERSION(Student, 1) class InternationalStudent : public Student { public: InternationalStudent() {} ~InternationalStudent() {} public: std::string country() { return countryM; } void country(std::string country) { countryM = country; } protected: friend class boost::serialization::access; protected: std::string countryM; protected: template<class A> void serialize(A& archive, const unsigned int /*version*/) { archive & BOOST_SERIALIZATION_NVP(boost::serialization::base_object<Student>(*this)); archive & BOOST_SERIALIZATION_NVP(countryM); } };

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  • How can I implement a database TableView like thing in C++?

    - by Industrial-antidepressant
    How can I implement a TableView like thing in C++? I want to emulating a tiny relation database like thing in C++. I have data tables, and I want to transform it somehow, so I need a TableView like class. I want filtering, sorting, freely add and remove items and transforming (ex. view as UPPERCASE and so on). The whole thing is inside a GUI application, so datatables and views are attached to a GUI (or HTML or something). So how can I identify an item in the view? How can I signal it when the table is changed? Is there some design pattern for this? Here is a simple table, and a simple data item: #include <string> #include <boost/multi_index_container.hpp> #include <boost/multi_index/member.hpp> #include <boost/multi_index/ordered_index.hpp> #include <boost/multi_index/random_access_index.hpp> using boost::multi_index_container; using namespace boost::multi_index; struct Data { Data() {} int id; std::string name; }; struct row{}; struct id{}; struct name{}; typedef boost::multi_index_container< Data, indexed_by< random_access<tag<row> >, ordered_unique<tag<id>, member<Data, int, &Data::id> >, ordered_unique<tag<name>, member<Data, std::string, &Data::name> > > > TDataTable; class DataTable { public: typedef Data item_type; typedef TDataTable::value_type value_type; typedef TDataTable::const_reference const_reference; typedef TDataTable::index<row>::type TRowIndex; typedef TDataTable::index<id>::type TIdIndex; typedef TDataTable::index<name>::type TNameIndex; typedef TRowIndex::iterator iterator; DataTable() : row_index(rule_table.get<row>()), id_index(rule_table.get<id>()), name_index(rule_table.get<name>()), row_index_writeable(rule_table.get<row>()) { } TDataTable::const_reference operator[](TDataTable::size_type n) const { return rule_table[n]; } std::pair<iterator,bool> push_back(const value_type& x) { return row_index_writeable.push_back(x); } iterator erase(iterator position) { return row_index_writeable.erase(position); } bool replace(iterator position,const value_type& x) { return row_index_writeable.replace(position, x); } template<typename InputIterator> void rearrange(InputIterator first) { return row_index_writeable.rearrange(first); } void print_table() const; unsigned size() const { return row_index.size(); } TDataTable rule_table; const TRowIndex& row_index; const TIdIndex& id_index; const TNameIndex& name_index; private: TRowIndex& row_index_writeable; }; class DataTableView { DataTableView(const DataTable& source_table) {} // How can I implement this? // I want filtering, sorting, signaling upper GUI layer, and sorting, and ... }; int main() { Data data1; data1.id = 1; data1.name = "name1"; Data data2; data2.id = 2; data2.name = "name2"; DataTable table; table.push_back(data1); DataTable::iterator it1 = table.row_index.iterator_to(table[0]); table.erase(it1); table.push_back(data1); Data new_data(table[0]); new_data.name = "new_name"; table.replace(table.row_index.iterator_to(table[0]), new_data); for (unsigned i = 0; i < table.size(); ++i) std::cout << table[i].name << std::endl; #if 0 // using scenarios: DataTableView table_view(table); table_view.fill_from_source(); // synchronization with source table_view.remove(data_item1); // remove item from view table_view.add(data_item2); // add item from source table table_view.filter(filterfunc); // filtering table_view.sort(sortfunc); // sorting // modifying from source_able, hot to signal the table_view? // FYI: Table view is atteched to a GUI item table.erase(data); table.replace(data); #endif return 0; }

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  • Scala project does not automatically build in Eclipse

    - by stacker
    I copied the examples folder from scala-2.7.7.final-devel-docs to the src folder of a scala project. But the source files will not compiled unless I change them manually. "Project/Build automatically" is checked. I'm using the Scala Eclipse Plugin 2.7.7-final How can I achieve that this works like in java projects?

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  • How to build jars from IntelliJ properly?

    - by ripper234
    I have a project that contains a single module, and some dependencies. I'd like to create a jar, in a separate directory, that contains the compiled module. In addition, I'd like to have the dependencies present beside my module. No matter how I twist IntelliJ's "build jar" process, the output of my module appears empty (besides a META-INF file).

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  • Specify build folder for iphone application

    - by Martin KS
    I've written an app that uses some of the user's camera roll images, and while it does so it stores them in the application root directory. The problem I have is that whenever I re-compile my application it changes the folder to which the application is installed. Is there any way I can specify which folder it should build to, so that any path information stored during it's last run will still be valid?

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  • Using in the same time Boost in release and debug mode

    - by Oodini
    Hello, The title is just for teasing. :-) I know it isn't possible, but here is my problem. My app (a DLL, actually) uses Boost. It also uses an external API, which also uses Boost. The external API is of course provided in a release binary, anlong the needed release Boost binaries. When I compile/link my DLL in release mode, I have no problem. I precise I link my app to Boost in a dynamic way (BOOST_ALL_DYN_LINK). In debug mode, I can't load my DLL. I am not sure it is because of Boost, but I suspect Windows doesn't like working with two Boost (the release one called by the external lib, and the debug one called by my code). Will it work better if I link my code statically with the release Boost ? I don't think it is related to CRT, because I have nothing in the Events Viewer. I use Visual Studio 2005 SP1. Thanks.

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  • Equvalent c++0x program withought using boost threads..

    - by Eternal Learner
    I have the below simple program using boost threads, what would be the changes needed to do the same in c++0X #include<iostream> #include<boost/thread/thread.hpp> boost::mutex mutex; struct count { count(int i): id(i){} void operator()() { boost::mutex::scoped_lock lk(mutex); for(int i = 0 ; i < 10000 ; i++) { std::cout<<"Thread "<<id<<"has been called "<<i<<" Times"<<std::endl; } } private: int id; }; int main() { boost::thread thr1(count(1)); boost::thread thr2(count(2)); boost::thread thr3(count(3)); thr1.join(); thr2.join(); thr3.join(); return 0; }

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