Search Results

Search found 11190 results on 448 pages for 'metasyntactic variable'.

Page 30/448 | < Previous Page | 26 27 28 29 30 31 32 33 34 35 36 37  | Next Page >

• Use Javascript variable in PHP

  - by Rhepungus

  I have seen some answers to this question in previous posts, but no one has given a real working example, just psuedo code. Has anyone ever done this before? Basically, what i have is a variable in javascript (jquery), and i want to use this variable to drive a query (for an overlay window) i am going to run in php. From what i have read you can do this using an ajax call to the same page so it doesnt refresh itself, but i must be missing something because i can't get it working... Any examples out there? Thanks.

  Read the article

• Actionscript 2 call function from variable

  - by NebNeb

  How can i call a function form a variable. var upfunction = init; //or var upfunction = init(); I have tried the above code and it does not work. I want to be able to call that variable from a keypress and change the variables function. For example. function init(){ //Do whatever } function init2(){ //Do another thing } var upfunction = init(); if (Key.getCode() == Key.UP) { upfunction; } Then later doing upfunction = init2(); That way i could change the function without having much code. Sorry if this is a noob question but all i do is copy and paste code i have found.

  Read the article

• How to refresh site if $_SESSION variable has changed

  - by 4ndro1d

  I'm writing in my $_SESSION variable from a database, when i clicked a link. public function getProjectById($id){ $query="SELECT * FROM projects WHERE id=\"$id\""; $result=mysql_query($query); $num=mysql_numrows($result); while ($row = mysql_fetch_object($result)) { $_SESSION['projectid'] = $row->id; $_SESSION['projecttitle'] = $row->title; $_SESSION['projectinfo'] = $row->info; $_SESSION['projecttext'] = $row->text; $_SESSION['projectcategory'] = $row->category; } } Now my variable is overwritten and I want to show these variables in my index.php like this: <div id="textContent"> <?php if(isset($_SESSION['projecttext']) && !empty($_SESSION['projecttext'])) { echo $_SESSION['projecttext']; }else { echo 'No text'; } ?></div> But of course, my page will not refresh automatically. How can I do that?

  Read the article

• Shell variable - of limited size?

  - by Helper Method

  Are shall variables limited in size? And which is the max size a variable can hold?

  Read the article

• [Android] Pass variable/intent to an activity when launched from a Widget

  - by Pelly

  Hi, Currently within an activity in my application I can call another activity and pass a variable to it in the following manner: Intent myIntent = new Intent(parentView.getContext(), ShowStations.class); myIntent.putExtra("stationName", stations[position].StationName); startActivity(myIntent); This works fine, but now I want to be able to do the same from my Widget. Currently this code works fine for launching a specific activity from my widget: Intent WidgetIntent = new Intent(Intent.ACTION_MAIN).addCategory(Intent.CATEGORY_LAUNCHER).setComponent(new ComponentName("grell.com", "grell.com.FavStations")); PendingIntent pendingIntent = PendingIntent.getActivity(context, 0, WidgetIntent, 0); updateViews.setOnClickPendingIntent(R.id.widget_main, pendingIntent); So now I am wondering how can I launch the same activity as shown in the first example but also pass through the 'stationName' variable. Any help would be greatly appreciated. Cheers

  Read the article

• Keep a javascript variable after an ajax call

  - by Guillaume le Floch

  I'm new in javascript and jQuery. I'm using ajax calls to get data from my server. The fact is, I'm losing my javascript variables after the call .. Here is what I did : the variable is define outside any function and treat in an other function. var a = 0; function myfunction(url){ $.ajax({ url: url, timeout: 20000, success: function(data){ // Do some stuff // The a variable is now undefined }, error: function(){ // Do some stuff } }); } Everything is working fine, the only thing is that I need to keep my variables ... but it looks like it's gone .. Does anyone know why? Thanks

  Read the article

• Static variable for optimization

  - by keithjgrant

  I'm wondering if I can use a static variable for optimization: public function Bar() { static $i = moderatelyExpensiveFunctionCall(); if ($i) { return something(); } else { return somethingElse(); } } I know that once $i is initialized, it won't be changed by by that line of code on successive calls to Bar(). I assume this means that moderatelyExpensiveFunctionCall() won't be evaluated every time I call, but I'd like to know for certain. Once PHP sees a static variable that has been initialized, does it skip over that line of code? In other words, is this going to optimize my execution time if I make a lot of calls to Bar(), or am I wasting my time?

  Read the article

• C++ Array of Variable sized Arrays

  - by adam

  I am very new to C++ and I realise the following is not necessarily as easy as I'd like it to be, but I'd really appreciate a more expert opinion. I am essentially trying to achieve a dynamic iteration over a variable sized array of variable sized arrays similar to the following. String *2d_array[][] = {{"A1","A2"},{"B1","B2","B3"},{"C1"}}; for (int i=0; i<2d_array.length; i++) { for (int j=0; j<2d_array[i].length; j++) { print(2d_array[i][j]); } } Is there a reasonable way to do this? Perhaps by using a vector, or another struct? Thanks :)

  Read the article

• How can I evaluate variable to another variable before assigning?

  - by HH

  #!/usr/bin/python # # Description: trying to evaluate array -value to variable before assignment # but it overwrites the variable # # How can I evaluate before assigning on the line 16? #Initialization, dummy code? x=0 y=0 variables = [x, y] data = ['2,3,4', '5,5,6'] # variables[0] should be evaluted to `x` here, i.e. x = data[0], how? variables[0] = data[0] if ( variables[0] != x ): print("It does not work, why?"); else: print("It works!");

  Read the article

• How to print size_t variable portably?

  - by ArunSaha

  I have a variable of type size_t, and I want to print it using printf(). What format specifier do I use to print it portably? In 32-bit machine, %u seems right. I compiled with g++ -g -W -Wall -Werror -ansi -pedantic, and there was no warning. But when I compile that code in 64-bit machine, it produces warning. size_t x = <something>; printf( "size = %u\n", x ); warning: format '%u' expects type 'unsigned int', but argument 2 has type 'long unsigned int' The warning goes away, as expected, if I change that to %lu. The question is, how can I write the code, so that it compiles warning free on both 32- and 64- bit machines? Edit: I guess one answer might be to "cast" the variable into an unsigned long, and print using %lu. That would work in both cases. I am looking if there is any other idea. (C, C++)

  Read the article

• how to pass variable arguments from one function to other in tcl

  - by vaichidrewar

  I want to pass variable arguments obtained in one function to other function but I am not able to do so. Function gets even number of variable arguments and then it has to be converted in array. Below is the example. Procedure abc1 gets two arguments (k k) and not form abc1 procedure these have to be passed to proc abc where list to array conversion it to be done. List to array conversion works in proc1 i.e. abc1 but not in second proc i.e. abc Error obtained is given below proc abc {args} { puts "$args" array set arg $args } proc abc1 {args} { puts "$args" array set arg $args set l2 [array get arg] abc $l2 } abc1 k k abc k k Output: k k {k k} list must have an even number of elements while executing "array set arg $l1" (procedure "abc" line 8) invoked from within "abc $l2" (procedure "abc1" line 5) invoked from within "abc1 k k" (file "vfunction.tcl" line 18)

  Read the article

• how to set and access variable values from another classess

  - by BittenApple

  I am modifying QuartzDemo example app and want to do set and read values of integer type variables in other classes which are already included. For example, in MainViewController.m I want to set a numeric value (simple numbers from 1-100) to a variable which is then going to be called (read) in file QuartzImages.m. Question is how to define variable properly, set and access (read) the value. I am a beginner with Obj C and iPhone SDK in general and have some experience with Delphi and VB but this doesn't help at all :) Thank you, whoever and wherever you are, person who will take me out of this endless googling loop.

  Read the article

• update value of a variable outside a class in VB.NET

  - by dpp

  I have a class derived from a Form, it has textbox for username and password and an OK button. I want it to behave like an InputBox so I can use it like this: Dim Username As String = "" Dim Password As String = "" Dim authorization As New Authorization(Username, Password) authorization.ShowDialog() 'The user will click OK and I will expect the Username and Password to change based on the user input MsgBox(Username & " " & Password) The Authorization class: Public Class Authorization Dim RefUsername As String Dim RefPassword As String Public Sub New(ByRef Username As String, ByRef Password As String) InitializeComponent() RefUsername = Username 'I'm trying to pass reference instead of value RefPassword = Password 'I'm trying to pass reference instead of value End Sub Private Sub OKButton_Click(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles AuthorizeButton.Click RefUsername = Username.Text 'I'm trying to change value of variable outside the class RefPassword = Password.Text 'I'm trying to change value of variable outside the class Me.Close() End Sub End Class In short, I want to change the value of variables outside the class when the user clicks the OK, how am I going to accomplish that?

  Read the article

• Release variable and assigning it again

  - by David Gonrab

  What is the preferred and/or correct way to release an NSMutableString (or any other class for that matter) instance and assign a new instance to the same variable in Objective-C on the iPhone? Currently I'm using [current release]; current = [NSMutableString new]; but I understand that the following works, too. NSMutableString *new = [NSMutableString new]; [current release]; current = [new retain]; [new release]; The variable current is declared in the interface definition of my class and gets released in dealloc.

  Read the article

• Execute query stored in variable in a very specific way

  - by niao

  Greetings, I have a problem as follows: I have an SQL variable declared: DECLARE @myVariable nvarchar(max) a third party library set a value for this variable. To simplify, lets say that the value is as follows: SET @myVariable = 'Select ROWGUID from MySampleTable' Now, I want to execute the following query: SELECT ROWGUID FROM myTable WHERE ROWGUID in (exec sp_executesql @myVariable ) However, the above statement does not work because it returns an error telling me that I can't execute stored procedure in that way. I made a workaround and this is what I wrote: create table #temptable (ID uniqueidentifier null) if(@myVariable is not null AND @myVariable !='') insert into #temptable exec sp_executesql @myVariable SELECT ROWGUID FROM myTable WHERE ROWGUID in (select * from #temptable) DROP TABLE #temptable This works fine.However I don't think it is a good idea to use temporary table. How can I achieve the same result without necessity of creating temporary tables? I am using SQL SERVER 2005

  Read the article

• how to get data in the variable CURLOPT_FOLLOWLOCATION

  - by cinek1lol

  how to get data in the variable CURLOPT_FOLLOWLOCATION? curl_easy_setopt(curl, CURLOPT_FOLLOWLOCATION,1);

  Read the article

• Objective-C: Cannot Change Value of Instance Variable Inside a Function

  - by user262325

  Hello everyone, I cannot change the value of an instance variable inside a function. I have defined a class: // info.h #import <Foundation/Foundation.h> @interface NSMyObject : NSObject { NSInteger i; } -(void) setI:(NSInteger)v; @end #import "info.h" @implementation NSMyObject -(void) setI:(NSInteger)v ; { i=v; } - (void)dealloc { [super dealloc]; } @end I call a function 'myFunction' with parameter temObj which is a NSMyObject instance. myFunction(temObj);//temObj is NSMyObject In the function, I can change the value of the instance variable of parameter obj. -(void)myFunction:(NSMyObject*) obj; { [obj setI:0]; } ... expecting this to change the content of temObj. But when I check the results of operation on obj in function myFunction the value of temObj.i has not changed. Welcome any comment Thanks

  Read the article

• ruby confusing -- local variable or instance_method ?

  - by boblu

  I have the following program. module C def self.included(base) base.extend(ClassMethods) end module ClassMethods def test_for class_eval <<-DEFINECLASSMETHODS def self.my_method(param_a) puts "SELF is: #{self.inspect}" puts param_a puts "#{param_a}" end DEFINECLASSMETHODS end end end class A include C end class B < A test_for end when I run B.new.my_method("aaa"), I got this error NameError: undefined local variable or method `param_a' for B:Class I am quite confused. I define param_a as a local variable in class method my_method, puts param_a runs good, and will output the "aaa". however, puts "#{param_a}" output that error. why? Can anyone explain this?

  Read the article

• How to set PATH to another variable value with spaces in Windows batch file

  - by Evgeny

  I've got a Windows batch script issue that I'm bashing my head against (no pun intended). The problematic script looks like this: if defined _OLD_VIRTUAL_PATH ( set PATH=%_OLD_VIRTUAL_PATH% ) When I run it and _OLD_VIRTUAL_PATH is set I get: \Microsoft was unexpected at this time. _OLD_VIRTUAL_PATH is a variable that was originally set from PATH and it contains spaces - I'm pretty sure that's the problem. But what's the solution? It runs successfully if I enclose it in quotes, but I don't think the entire value of the PATH variable is supposed to be in quotes.

  Read the article

• Random password variable disappears

  - by snaken

  Hi, I'm using the following to generate a random password in a shell script: DBPASS=</dev/urandom tr -dc A-Za-z0-9| (head -c $1 > /dev/null 2>&1 || head -c 8) When i run this in a file on its own like this: #!/bin/sh DBPASS=</dev/urandom tr -dc A-Za-z0-9| (head -c $1 > /dev/null 2>&1 || head -c 8) echo $DBPASS A password is echoed. When i incorporate it into a larger script though the variable never seems to get created for some reason, so for example this doesn't work: DBPASS=</dev/urandom tr -dc A-Za-z0-9| (head -c $1 > /dev/null 2>&1 || head -c 8) sed -i s/oldpass/$DBPASS/ mysql_connect.php If i manually set the variable though everything is fine.. can anyone see why?

  Read the article

• Template variable in ASP.NET

  - by williamrichards

  Hi, I have to add a Page's variable into a ItemTemplate but dont know how. For example: <rad:RadMenuItem ID="f" runat="server" Text="Products"> <ItemTemplate> <div class="pitem"><%= MyText %></div> </ItemTemplate> </rad:RadMenuItem> The MyText variable does exist in the context and has value but the text does not show up Another question: How can I add MyText to the ASP.NET page like the following? <asp:Button Text="<%=MyText%>" .../>

  Read the article

• Flex Application for PlayBook Text Input Variable

  - by user568128

  I know this is probably a very simple question, but can someone please walk me through how to take what a user inputs into a s:TextInput and use that as a variable in a JSON data request? Basically, I want to have a user enter a search term, like "math" and then have that placed into a variable so I can use it in a JSON request. Something like public var q:String, except that my search box (and hence user input) is on another "view" of the application. I've just started with Flex Mobile applications and I might be way out of my league. Does anyone know how to do this?

  Read the article

• Local variable and Try/Catch

  - by 3D-kreativ

  I get an error, a red line below the variable intAge in the if-statement in the code. It says the variable is local, but how could it be local when it is declared in the beginning of the code? Does it have to do with the Try/Catch part? The reason why my code looks like it does, is just beacuse I have to use a Try/Catch in the code for this task. Preciate some suggestions to solve this in a similiar and correct way? Thanks! int intAge; try { intAge = int.Parse(age); } catch (Exception) { MessageBox.Show("Enter an age in numbers!","Error!"); } finally { } // Check input if (intAge < 1) { inputOk = false; errorMessage = "Please enter 1 or higher!"; }

  Read the article

• Passing a variable that can be updated

  - by Rob Bonner

  This seems like a simple thing, but can't get it to work. I pass a variable into a UIViewController thourgh a standard property: [aViewController setProposedDate:proposedWorkLog.entryDate]; which is retained by the controller, and possible changed. I have verified that in the controller, the data is modified. But, after it is popped off the stack and I look in the calling view, the data has not been updated. Is there a way to pass this variable and have it retain the new value, or a way to pass back a response from a closing view controller? Thanks!

  Read the article

• How do I declare a variable? [closed]

  - by Guy

  How do I declare a variable? Thanks.

  Read the article

< Previous Page | 26 27 28 29 30 31 32 33 34 35 36 37  | Next Page >