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  • "No database selected" even when db clearly selected

    - by Someone
    One of my webpages gets a recurring error: "No database selected", even though the DB is selected. Right about now it's a 50-50 chance whether the page will load just fine, or whether I receive this error. After one or two reloads, the page works again. I am including the exact same connection file on my other pages, and I don't have this problem. What could be the cause of this? I'm using ensim pro for webhosting. TIA.

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  • Help with grasping (INNER?) JOIN

    - by Greenie
    I'm having trouble building a query. I can do what I want in 3 different queries. SELECT id FROM table1 WHERE url LIKE '%/$downloadfile' put that in $url_id SELECT item_id FROM table2 WHERE rel_id = '$url_id'" put that in $item_id SELECT rel_id FROM table2 WHERE rel_id = '$item_id' AND field_id = '42'" put that in $user_id But from reading examples on joins and inner joins I think there's a more elegant way. I cant wrap my brain around writing a better query (but would like to) I can describe how it should go: table1 fields: id, url table2 fields item_id, rel_id, field_id I know the last part of table1.url (LIKE '%/$filename') with that I select table1.id. table1.id is equal to one entry in table2.rel_id. So get that and select the table2.item_id. In table2 there is another entry which has the same table2.item_id and it will have a table2.field_id = '42' And finally the value I need is the table2.rel_id where the table2.field_id was 42. I will fetch that value and put it in $user_id Can this be done with one query using joins/inner joins?

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  • Critical Patch Update for October 2012 Now Available

    - by Steven Chan (Oracle Development)
    The Critical Patch Update (CPU) for October 2012 was released on July 16, 2012. Oracle strongly recommends applying the patches as soon as possible. The Critical Patch Update Advisory is the starting point for relevant information. It includes a list of products affected, pointers to obtain the patches, a summary of the security vulnerabilities, and links to other important documents. Supported products that are not listed in the "Supported Products and Components Affected" Section of the advisory do not require new patches to be applied. Also, it is essential to review the Critical Patch Update supporting documentation referenced in the Advisory before applying patches, as this is where you can find important pertinent information. The Critical Patch Update Advisory is available at the following location: Oracle Technology Network The next four Critical Patch Update release dates are: January 15, 2013 April 16, 2013 July 16, 2013 October 15, 2013 E-Business Suite Releases 11i and 12 Reference Oracle E-Business Suite Releases 11i and 12 Critical Patch Update Knowledge Document (October 2012) (Note 1486535.1)

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  • How do I echo out something different when reached last row?

    - by Josh Brown
    I am wanting to not echo out the comma at the end of the echo after the last row. How can I do that? Here is my code: <?php header("Content-type: application/json"); echo '{"points":['; mysql_connect("localhost", "user", "password"); mysql_select_db("database"); $q = "SELECT venues.id, venues.lat, venues.lon, heat_indexes.temperature FROM venues, heat_indexes WHERE venues.id = heat_indexes.venue_id"; $res = mysql_query($q) or die(mysql_error()); while ($point = mysql_fetch_assoc($res)) { echo $point['lat'] . "," . $point['lon'] . "," . $point['temperature'] . ","; } mysql_free_result($res); echo ']}'; ?>

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  • I could use some help with my SQL command

    - by SuperSpy
    I've got a database table called 'mesg' with the following structure: receiver_id | sender_id | message | timestamp | read Example: 2 *(«me)* | 6 *(«nice girl)* | 'I like you, more than ghoti' | yearsago | 1 *(«seen it)* 2 *(«me)* | 6 *(«nice girl)* | 'I like you, more than fish' | now | 1 *(«seen it)* 6 *(«nice girl)* | 2 *(«me)* | 'Hey, wanna go fish?' | yearsago+1sec | 0 *(«she hasn't seen it)* It's quite a tricky thing that I want to achieve. I want to get: the most recent message(=ORDER BY time DESC) + 'contact name' + time for each 'conversation'. Contact name = uname WHERE uid = 'contact ID' (the username is in another table) Contact ID = if(sessionID*(«me)*=sender_id){receiver_id}else{sender_id} Conversation is me = receiver OR me = sender For example: From: **Bas Kreuntjes** *(« The message from bas is the most recent)* Hey $py, How are you doing... From: **Sophie Naarden** *(« Second recent)* Well hello, would you like to buy my spam? ... *(«I'll work on that later >p)* To: **Melanie van Deijk** *(« My message to Melanie is 3th)* And? Did you kiss him? ... That is a rough output. QUESTION: Could someone please help me setup a good SQL command. This will be the while loup <?php $sql = "????"; $result = mysql_query($sql); while($fetch = mysql_fetch_assoc($result)){ ?> <div class="message-block"> <h1><?php echo($fetch['uname']); ?></h1> <p><?php echo($fetch['message']); ?></p> <p><?php echo($fetch['time']); ?></p> </div> <?php } ?> I hope my explanation is good enough, if not, please tell me. Please don't mind my English, and the Dutch names (I am Dutch myself) Feel free to correct my English UPDATE1: Best I've got until now: But I do not want more than one conversation to show up... u=user table m=message table SELECT u.uname, m.message, m.receiver_uid, m.sender_uid, m.time FROM m, u WHERE (m.receiver_uid = '$myID' AND u.uid = m.sender_uid) OR (m.sender_uid = '$myID' AND u.uid = m.receiver_uid) ORDER BY time DESC;

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  • mysql_real_escape_string() just makes an empty string?

    - by James P
    I am using a jQuery AJAX request to a page called like.php that connects to my database and inserts a row. This is the like.php code: <?php // Some config stuff define(DB_HOST, 'localhost'); define(DB_USER, 'root'); define(DB_PASS, ''); define(DB_NAME, 'quicklike'); $link = mysql_connect(DB_HOST, DB_USER, DB_PASS) or die('ERROR: ' . mysql_error()); $sel = mysql_select_db(DB_NAME, $link) or die('ERROR: ' . mysql_error()); $likeMsg = mysql_real_escape_string(trim($_POST['likeMsg'])); $timeStamp = time(); if(empty($likeMsg)) die('ERROR: Message is empty'); $sql = "INSERT INTO `likes` (like_message, timestamp) VALUES ('$likeMsg', $timeStamp)"; $result = mysql_query($sql, $link) or die('ERROR: ' . mysql_error()); echo mysql_insert_id(); mysql_close($link); ?> The problematic line is $likeMsg = mysql_real_escape_string(trim($_POST['likeMsg']));. It seems to just return an empty string, and in my database under the like_message column all I see is blank entries. If I remove mysql_real_escape_string() though, it works fine. Here's my jQuery code if it helps. $('#like').bind('keydown', function(e) { if(e.keyCode == 13) { var likeMessage = $('#changer p').html(); if(likeMessage) { $.ajax({ cache: false, url: 'like.php', type: 'POST', data: { likeMsg: likeMessage }, success: function(data) { $('#like').unbind(); writeLikeButton(data); } }); } else { $('#button_container').html(''); } } }); All this jQuery code works fine, I've tested it myself independently. Any help is greatly appreciated, thanks.

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  • Oracle’s Primavera Inspire for SAP: Aligning Business Priorities with Project Priorities

    Oracle’s Primavera Inspire for SAP integrates schedule, financial and resource information between Oracle’s Primavera project portfolio management applications and SAP’s enterprise resource planning solutions. Join Tracy Bowman, Principal Product Manager and learn how Primavera Inspire for SAP can help utilities and oil and gas companies’ complete projects on-time and within budget by providing them with a single access point for all project and portfolio related information.

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  • SQL SELECT across two tables

    - by Brett Spurrier
    Hi there, I am a little confused as to how to approach this SQL query. I have two takes (equal number of records), and I would like to return a column with which is the division between the two. In other words, here is my not-working-correctly query: SELECT( (SELECT v FROM Table1) / (SELECT DotProduct FROM Table2) ); How would I do this? All I want it a column where each row equals the same row in Table1 divided by the same row in Table2. The resulting table should have the same number of rows, but I am getting something with a lot more rows than the original two tables. I am at a complete loss. Any advice?

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  • The Benefits of Oracle's Compliance Architecture

    Fred chats with Deborah Hamilton, Senior Compliance Product Marketing Director at Oracle about what the Oracle Compliance Architecture is, how customers are benefiting from its integrated approach to compliance - of technology, people and processes - and how it helps with organizations meet multiple compliance mandates.

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  • A better way to delete a list of elements from multiple tables

    - by manyxcxi
    I know this looks like a 'please write the code' request, but some basic pointer/principles for doing this the right way should be enough to get me going. I have the following stored procedure: CREATE PROCEDURE `TAA`.`runClean` (IN idlist varchar(1000)) BEGIN DECLARE EXIT HANDLER FOR NOT FOUND ROLLBACK; DECLARE EXIT HANDLER FOR SQLEXCEPTION ROLLBACK; DECLARE EXIT HANDLER FOR SQLWARNING ROLLBACK; START TRANSACTION; DELETE FROM RunningReports WHERE run_id IN (idlist); DELETE FROM TMD_INDATA_INVOICE WHERE run_id IN (idlist); DELETE FROM TMD_INDATA_LINE WHERE run_id IN (idlist); DELETE FROM TMD_OUTDATA_INVOICE WHERE run_id IN (idlist); DELETE FROM TMD_OUTDATA_LINE WHERE run_id IN (idlist); DELETE FROM TMD_TEST WHERE run_id IN (idlist); DELETE FROM RunHistory WHERE id IN (idlist); COMMIT; END $$ It is called by a PHP script to clean out old run history. It is not particularly efficient as you can see and I would like to speed it up. The PHP script gathers the ids to remove from the tables with the following query: $query = "SELECT id, stop_time FROM RunHistory WHERE config_id = $configId AND save = 0 AND NOT(stop_time IS NULL) ORDER BY stop_time"; It keeps the last five run entries and deletes all the rest. So using this query to bring back all the IDs, it determines which ones to delete and keeps the 'newest' five. After gathering the IDs it sends them to the stored procedure to remove them from the associated tables. I'm not very good with SQL, but I ASSUME that using an IN statement and not joining these tables together is probably the least efficient way I can do this, but I don't know enough to ask anything but "how do I do this better?" If possible, I would like to do this all in my stored procedure using a query to gather all the IDs except for the five 'newest', then delete them. Another twist, run entries can be marked save (save = 1) and should not be deleted. The RunHistory table looks like this: CREATE TABLE `TAA`.`RunHistory` ( `id` int(11) NOT NULL auto_increment, `start_time` datetime default NULL, `stop_time` datetime default NULL, `config_id` int(11) NOT NULL, [...] `save` tinyint(1) NOT NULL default '0', PRIMARY KEY (`id`) ) ENGINE=InnoDB AUTO_INCREMENT=0 DEFAULT CHARSET=utf8;

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  • How Can i Create This Complicated Query ?

    - by mTuran
    Hi, I have 3 tables: projects, skills and project_skills. In projects table i hold project's general data. Second table skills i hold skill id and skill name also i have projects_skills table which is hold project's skill relationships. Here is scheme of tables: CREATE TABLE IF NOT EXISTS `project_skills` ( `project_id` int(11) NOT NULL, `skill_id` int(11) NOT NULL, KEY `project_id` (`project_id`), KEY `skill_id` (`skill_id`) ) ENGINE=MyISAM DEFAULT CHARSET=utf8 COLLATE=utf8_turkish_ci; CREATE TABLE IF NOT EXISTS `projects` ( `id` int(11) NOT NULL AUTO_INCREMENT, `employer_id` int(11) NOT NULL, `project_title` varchar(100) COLLATE utf8_turkish_ci NOT NULL, `project_description` text COLLATE utf8_turkish_ci NOT NULL, `project_budget` int(11) NOT NULL, `project_allowedtime` int(11) NOT NULL, `project_deadline` datetime NOT NULL, `total_bids` int(11) NOT NULL, `average_bid` int(11) NOT NULL, `created` datetime NOT NULL, `active` tinyint(1) NOT NULL, PRIMARY KEY (`id`), KEY `created` (`created`), KEY `employer_id` (`employer_id`), KEY `active` (`active`), FULLTEXT KEY `project_title` (`project_title`,`project_description`) ) ENGINE=MyISAM DEFAULT CHARSET=utf8 COLLATE=utf8_turkish_ci AUTO_INCREMENT=3 ; CREATE TABLE IF NOT EXISTS `skills` ( `id` int(11) NOT NULL AUTO_INCREMENT, `category` int(11) NOT NULL, `name` varchar(100) COLLATE utf8_turkish_ci NOT NULL, `seo_name` varchar(100) COLLATE utf8_turkish_ci NOT NULL, `total_projects` int(11) NOT NULL, PRIMARY KEY (`id`), KEY `seo_name` (`seo_name`) ) ENGINE=MyISAM DEFAULT CHARSET=utf8 COLLATE=utf8_turkish_ci AUTO_INCREMENT=224 ; I want to select projects with related skill names. I think i have to use JOIN but i don't know how can i do. Thanks

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  • Commercial web application--scalable database design

    - by Rob Campbell
    I'm designing a set of web apps to track scientific laboratory data. Each laboratory has several members, each of whom will access both their own data and that of their laboratory as a whole. Many typical queries will thus be expected to return records of multiple members (e.g. my mouse, joe's mouse and sally's mouse). I think I have the database fairly well normalized. I'm now wondering how to ensure that users can efficiently access both their own data and their lab's data set when it is mixed among (hopefully) a whole ton of records from other labs. What I've come up with so far is that most tables will end with two fields: user_id and labgroup_id. The WHERE clause of any SELECT statement will include the appropriate reference to one of the id fields ("...WHERE 'labroup_id=n..." or "...WHERE user_id=n..."). My questions are: Is this an approach that will scale to 10^6 or more records? If so, what's the best way to use these fields in a query so that it most efficiently searches the relevant subset of the database? e.g. Should the first step in querying be to create a temporary table containing just the labgroup's data? Or will indexing using some combination of the id, user_id, and labroup_id fields be sufficient at that scale? I thank any responders very much in advance.

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  • Oracle’s Visual CRM Solution

    Visual CRM adds the powerful visualization and document centric collaboration capabilities of Oracle’s AutoVue to Oracle’s best-in-class CRM solutions. By introducing a visual aspect to call center, field service, and ordering processes, Visual CRM helps teams provide faster responses to customer issues, optimize field service performance, and shorten ordering cycles while minimizing order errors.With Visual CRM, organizations can achieve improved customer service levels and field service operations which help drive margin, top line revenue, and customer retention.

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  • Oracle moves to Java technology to embedded middleware

    - by hinkmond
    Here's another article pointing out our move to Java Embedded Middleware with our launch of Oracle Java Embedded Suite 7.0 See: Oracle moves to Java embedded middleware Here's a quote: At the JavaOne Embedded conference, a wafer thin embedded device that was smaller than a Ritz cracker was loaded up with the Java Embedded Suite. I like that: "a wafer thin embedded device". Just one thin wafer. Reminds me of the scene from Monty Python's, The Meaning of Life. "Better?" Hinkmond

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  • The MySQL Community talks in Japan, Tokyo

    - by Lenka Kasparova
    There will be 2 community meetups in Tokyo in Japan scheduled for June 2014. Please check and join following:  MySQL Casual Talks vol.6 Date: June 11th, 2014 Time: 19:00 Place: Oracle office, Oracle Aoyama Center, 2-5-8 Kita-Aoyama, Minato-ku, Tokyo, Japan More info & Registration MySQL Cluster Casual Talk #2 Date: June 25th, 2014 Time: 19:00 Place: GMO Yours, Cerulean Tower 11F, Shibuya-kuy, Tokyo, Japan More info & registration

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  • UK Oracle User Group Event: Trends in Identity Management

    - by B Shashikumar
    As threat levels rise and new technologies such as cloud and mobile computing gain widespread acceptance, security is occupying more and more mindshare among IT executives. To help prepare for the rapidly changing security landscape, the Oracle UK User Group community and our partners at Enline/SENA have put together an User Group event in London on Apr 19 where you can learn more from your industry peers about upcoming trends in identity management. Here are some of the key trends in identity management and security that we predicted at the beginning of last year and look how they have turned out so far. You have to admit that we have a pretty good track record when it comes to forecasting trends in identity management and security. Threat levels will grow—and there will be more serious breaches:   We have since witnessed breaches of high value targets like RSA and Epsilon. Most organizations have not done enough to protect against insider threats. Organizations need to look for security solutions to stop user access to applications based on real-time patterns of fraud and for situations in which employees change roles or employment status within a company. Cloud computing will continue to grow—and require new security solutions: Cloud computing has since exploded into a dominant secular trend in the industry. Cloud computing continues to present many opportunities like low upfront costs, rapid deployment etc. But Cloud computing also increases policy fragmentation and reduces visibility and control. So organizations require solutions that bridge the security gap between the enterprise and cloud applications to reduce fragmentation and increase control. Mobile devices will challenge traditional security solutions: Since that time, we have witnessed proliferation of mobile devices—combined with increasing numbers of employees bringing their own devices to work (BYOD) — these trends continue to dissolve the traditional boundaries of the enterprise. This in turn, requires a holistic approach within an organization that combines strong authentication and fraud protection, externalization of entitlements, and centralized management across multiple applications—and open standards to make all that possible.  Security platforms will continue to converge: As organizations move increasingly toward vendor consolidation, security solutions are also evolving. Next-generation identity management platforms have best-of-breed features, and must also remain open and flexible to remain viable. As a result, developers need products such as the Oracle Access Management Suite in order to efficiently and reliably build identity and access management into applications—without requiring security experts. Organizations will increasingly pursue "business-centric compliance.": Privacy and security regulations have continued to increase. So businesses are increasingly look for solutions that combine strong security and compliance management tools with business ready experience for faster, lower-cost implementations.  If you'd like to hear more about the top trends in identity management and learn how to empower yourself, then join us for the Oracle UK User Group on Thu Apr 19 in London where Oracle and Enline/SENA product experts will come together to share security trends, best practices, and solutions for your business. Register Here.

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  • How to select parent row only if has at least one child?

    - by Matt McCormick
    I have a simple one-to-many relationship. I would like to select rows from the parent only when they have at least one child. So, if there are no children, then the parent row is not returned in the result set. Eg. Parent: +--+---------+ |id| text | +--+---------+ | 1| Blah | | 2| Blah2 | | 3| Blah3 | +--+---------+ Children +--+------+-------+ |id|parent| other | +--+------+-------+ | 1| 1 | blah | | 2| 1 | blah2 | | 3| 2 | blah3 | +--+------+-------+ I want the results to be: +----+------+ |p.id|p.text| +----+------+ | 1 | Blah | | 2 | Blah2| +----+------+

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  • Create a nested list

    - by sico87
    How would I create a nested list, I currently have this public function getNav($cat,$subcat){ //gets all sub categories for a specific category if(!$this->checkValue($cat)) return false; //checks data $query = false; if($cat=='NULL'){ $sql = "SELECT itemID, title, parent, url, description, image FROM p_cat WHERE deleted = 0 AND parent is NULL ORDER BY position;"; $query = $this->db->query($sql) or die($this->db->error); }else{ //die($cat); $sql = "SET @parent = (SELECT c.itemID FROM p_cat c WHERE url = '".$this->sql($cat)."' AND deleted = 0); SELECT c1.itemID, c1.title, c1.parent, c1.url, c1.description, c1.image, (SELECT c2.url FROM p_cat c2 WHERE c2.itemID = c1.parent LIMIT 1) as parentUrl FROM p_cat c1 WHERE c1.deleted = 0 AND c1.parent = @parent ORDER BY c1.position;"; $query = $this->db->multi_query($sql) or die($this->db->error); $this->db->store_result(); $this->db->next_result(); $query = $this->db->store_result(); } return $query; } public function getNav($cat=false, $subcat=false){ //gets a list of all categories form this level, if $cat is false it returns top level nav if($cat==false || strtolower($cat)=='all-products') $cat='NULL'; $ds = $this->data->getNav($cat, $subcat); $nav = $ds ? $ds : false; $html = ''; //create html if($nav){ $html = '<ul>'; //var_dump($nav->fetch_assoc()); while($row = $nav->fetch_assoc()){ $url = isset($row['parentUrl']) ? $row['parentUrl'].'/'.$row['url'] : $row['url']; $current = $subcat==$row['url'] ? ' class="current"' : ''; $html .= '<li'.$current.'><a href="/'.$url.'/">'.$row['title'].'</a></li>'; } $html .='</ul>'; } return $html; } The sql returns parents and children, for each parent I need the child to nest in a list.

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  • GROUP BY ID range?

    - by d0ugal
    Given a data set like this; +-----+---------------------+--------+ | id | date | result | +-----+---------------------+--------+ | 121 | 2009-07-11 13:23:24 | -1 | | 122 | 2009-07-11 13:23:24 | -1 | | 123 | 2009-07-11 13:23:24 | -1 | | 124 | 2009-07-11 13:23:24 | -1 | | 125 | 2009-07-11 13:23:24 | -1 | | 126 | 2009-07-11 13:23:24 | -1 | | 127 | 2009-07-11 13:23:24 | -1 | | 128 | 2009-07-11 13:23:24 | -1 | | 129 | 2009-07-11 13:23:24 | -1 | | 130 | 2009-07-11 13:23:24 | -1 | | 131 | 2009-07-11 13:23:24 | -1 | | 132 | 2009-07-11 13:23:24 | -1 | | 133 | 2009-07-11 13:23:24 | -1 | | 134 | 2009-07-11 13:23:24 | -1 | | 135 | 2009-07-11 13:23:24 | -1 | | 136 | 2009-07-11 13:23:24 | -1 | | 137 | 2009-07-11 13:23:24 | -1 | | 138 | 2009-07-11 13:23:24 | 1 | | 139 | 2009-07-11 13:23:24 | 0 | | 140 | 2009-07-11 13:23:24 | -1 | +-----+---------------------+--------+ How would I go about grouping the results by day 5 records at a time. The above results is part of the live data, there is over 100,000 results rows in the table and its growing. Basically I want to measure the change over time, so want to take a SUM of the result every X records. In the real data I'll be doing it ever 100 or 1000 but for the data above perhaps every 5. If i could sort it by date I would do something like this; SELECT DATE_FORMAT(date, '%h%i') ym, COUNT(result) 'Total Games', SUM(result) as 'Score' FROM nn_log GROUP BY ym; I can't figure out a way of doing something similar with numbers. The order is sorted by the date but I hope to split the data up every x results. It's safe to assume there are no blank rows. Doing it above with the data you could do multiple selects like; SELECT SUM(result) FROM table LIMIT 0,5; SELECT SUM(result) FROM table LIMIT 5,5; SELECT SUM(result) FROM table LIMIT 10,5; Thats obviously not a very good way to scale up to a bigger problem. I could just write a loop but I'd like to reduce the number of queries.

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  • True Excel Templates for BI Publisher

    - by Annemarie Provisero
    ADVISOR WEBCAST: True Excel Templates for BI Publisher PRODUCT FAMILY: EBS/ATG/BI Publisher July 12, 2011 at 7am PT, 8 am MT, 10 am ET This one-hour session is recommended for technical and functional users who want to learn how to code Excel formatted layouts for use with BI Publisher to generate binary Excel output. TOPICS WILL INCLUDE: Creating a simple template Formatting Dates Creating Functions A short, live demonstration (only if applicable) and question and answer period will be included. Oracle Advisor Webcasts are dedicated to building your awareness around our products and services. This session does not replace offerings from Oracle Global Support Services. Click here to register for this session ------------------------------------------------------------------------------------------------------------- The above webcast is a service of the E-Business Suite Communities in My Oracle Support. For more information on other webcasts, please reference the Oracle Advisor Webcast Schedule.Click here to visit the E-Business Communities in My Oracle Support Note that all links require access to My Oracle Support.

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  • FORBES.COM: Oracle's message is loud & clear – “we've got the cloud”

    - by Richard Lefebvre
    In a two-part series on Oracle's cloud strategy, Bob Evans reports on the October 4 meeting where Wall Street analysts questioned Mark Hurd and Safra Catz about the company's positioning for the shift to cloud computing. Check out Bob's related Forbes.com piece "The Dumbest Idea of 2013," in response to the preposterous chatter that Larry Ellison and Oracle don't "get" the cloud. His powerful six-point argument unravels our competitors' spin. Read the "Dumbest Idea."

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  • mysqli real_escape_string problem

    - by tridat
    When im inserting to the database on my dev server the text goes in fine, for example "that's" is "that's" in the db. when uploading the exact same code to production server (hosted on a reseller account at bluehost) "that's" becomes "that\'s", im not double escaping, its exactly the same code, what could be the issue here?

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  • Enable Seamless Transformation and Effective Adoption of Change with Oracle User Productivity Kit

    Organizations go through continuous transformation and change - whether it is through mergers and acquisitions, standardizations of systems, a rollout of a new application or business process improvements. With Oracle User Productivity Kit, project teams can capture and deploy best practices to streamline efficiency, reduce cost, and ensure successful change adoption. Discover how organizations can leverage the multiple outputs of Oracle UPK for all phases of the project from blueprinting/design/configuration to testing/training/go-live as well as maintenance and support.

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  • PHP While Loops from Arrays

    - by Michael
    I have a table that contains members names and a field with multiple ID numbers. I want to create a query that returns results where any values in the ID fields overlap with any values in the array. For example: lastname: Smith firstname: John id: 101, 103 I have Array #1 with the values 101, 102, 103 I want the query to output all members who have the values 101 or 102 or 103 listed in their id field with multiple ids listed. Array ( [0] => 101 [1] => 102 [2] => 103 ) $sql="SELECT firstname, lastname, id FROM members WHERE id LIKE '%".$array_num_1."%'"; $result=mysql_query($sql); while ($rows=mysql_fetch_array($result)) { echo $rows['lastname'].', '.$rows['firstname'].'-'.$rows['id']; }

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