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  • SQL SERVER – Finding Different ColumnName From Almost Identitical Tables

    - by pinaldave
    I have mentioned earlier on this blog that I love social media – Facebook and Twitter. I receive so many interesting questions that sometimes I wonder how come I never faced them in my real life scenario. Well, let us see one of the similar situation. Here is one of the questions which I received on my social media handle. “Pinal, I have a large database. I did not develop this database but I have inherited this database. In our database we have many tables but all the tables are in pairs. We have one archive table and one current table. Now here is interesting situation. For a while due to some reason our organization has stopped paying attention to archive data. We did not archive anything for a while. If this was not enough we  even changed the schema of current table but did not change the corresponding archive table. This is now becoming a huge huge problem. We know for sure that in current table we have added few column but we do not know which ones. Is there any way we can figure out what are the new column added in the current table and does not exist in the archive tables? We cannot use any third party tool. Would you please guide us?” Well here is the interesting example of how we can use sys.column catalogue views and get the details of the newly added column. I have previously written about EXCEPT over here which is very similar to MINUS of Oracle. In following example we are going to create two tables. One of the tables has extra column. In our resultset we will get the name of the extra column as we are comparing the catalogue view of the column name. USE AdventureWorks2012 GO CREATE TABLE ArchiveTable (ID INT, Col1 VARCHAR(10), Col2 VARCHAR(100), Col3 VARCHAR(100)); CREATE TABLE CurrentTable (ID INT, Col1 VARCHAR(10), Col2 VARCHAR(100), Col3 VARCHAR(100), ExtraCol INT); GO -- Columns in ArchiveTable but not in CurrentTable SELECT name ColumnName FROM sys.columns WHERE OBJECT_NAME(OBJECT_ID) = 'ArchiveTable' EXCEPT SELECT name ColumnName FROM sys.columns WHERE OBJECT_NAME(OBJECT_ID) = 'CurrentTable' GO -- Columns in CurrentTable but not in ArchiveTable SELECT name ColumnName FROM sys.columns WHERE OBJECT_NAME(OBJECT_ID) = 'CurrentTable' EXCEPT SELECT name ColumnName FROM sys.columns WHERE OBJECT_NAME(OBJECT_ID) = 'ArchiveTable' GO DROP TABLE ArchiveTable; DROP TABLE CurrentTable; GO The above query will return us following result. I hope this solves the problems. It is not the most elegant solution ever possible but it works. Here is the puzzle back to you – what native T-SQL solution would you have provided in this situation? Reference: Pinal Dave (http://blog.sqlauthority.com) Filed under: PostADay, SQL, SQL Authority, SQL Query, SQL Server, SQL System Table, SQL Tips and Tricks, T SQL, Technology

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  • Samba does not reload user group members

    - by xato
    I am running a simple samba server setup where users connect to a share which contains folders for specific user groups. The folders are chmod 2770, so only users which are in the correct group can read/write in them. The problem is that if I change group memberships (i.e. remove user from group / add user to group; changes are in sync between clients and server!) samba does not automatically reload the group memberships for the user, so they can still write to groups that they are no longer a member of etc. I either have to reconnect to the share or to restart samba to apply the changes. Is there any way to prevent group caching and/or enable group membership reload in samba? My smb.conf: https://gist.github.com/anonymous/ca7c10a3b3e2168d7a03

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  • Taking user out of MACHINENAME\Users group does not disallow them from authenticating with IIS site

    - by jayrdub
    I have a site that has anonymous access disabled and uses only IIS basic authentication. The site's home directory only has the MACHINENAME\Users group with permissions. I have one user that I don't want to be able to log-in to this site, so I thought all I would need to do is take that user out of the Users group, but doing so still allows him to authenticate. I know it is the Users group that is allowing authentication because if I remove that group's permissions on the directory, he is not allowed to log in. Is there something special about the Users group that makes it so you are actually always a part of it? Is the only solution to revoke the Users group's permissions on the site's home directory and grant a new group access that contains only the allowed users?

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  • Linux program unable to access files in group

    - by user1064665
    I'm having trouble configuring things on linux so that a program can access certain files. Let's call it pgm A. It has uid uA and gid gA. In addition, uid uA is listed in /etc/group as a member of group gX. The problem is that pgm A cannot access files for which the uid is root and the gid is gX, but only when pgm A is called from another program, pgm B, which also runs as user uA. If I su as user uA and run pgm A from bash, it has no problem accessing files in group gX. But if another program, pgm B, which also runs as user uA, forks and execs pgm A, pgm A cannot access the files. I've verified that pgm A is indeed running as user uA, group gA, when launched from pgm B. So, if uA is a member of group gX, why can't the program access files which are readable by group gX? It's as if the operating system is ignoring the fact that user uA is also in group gX.

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  • How can I find the names of AD Group policies that a user/pc is using?

    - by Russ
    I am having trouble locating some settings in group policy so I can make changes due to the convoluted nature of our policies. What I would like to be able to do is go to a specific PC and see what group policies are being applied, so I can focus on those policies. My goal would be to clean up the GP's a bit, while allowing me to "walk the tree" to see what people have implemented and what is worthless. Thanks. EDIT: In this specific case, I am looking to find which GP maped drives are configured in. (User Configuration -- Preferences -- Windows Settings -- Drive Maps)

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  • MySQL "ERROR 1005 (HY000): Can't create table 'foo.#sql-12c_4' (errno: 150)"

    - by Ankur Banerjee
    Hi, I was working on creating some tables in database foo, but every time I end up with errno 150 regarding the foreign key. Firstly, here's my code for creating tables: CREATE TABLE Clients ( client_id CHAR(10) NOT NULL , client_name CHAR(50) NOT NULL , provisional_license_num CHAR(50) NOT NULL , client_address CHAR(50) NULL , client_city CHAR(50) NULL , client_county CHAR(50) NULL , client_zip CHAR(10) NULL , client_phone INT NULL , client_email CHAR(255) NULL , client_dob DATETIME NULL , test_attempts INT NULL ); CREATE TABLE Applications ( application_id CHAR(10) NOT NULL , office_id INT NOT NULL , client_id CHAR(10) NOT NULL , instructor_id CHAR(10) NOT NULL , car_id CHAR(10) NOT NULL , application_date DATETIME NULL ); CREATE TABLE Instructors ( instructor_id CHAR(10) NOT NULL , office_id INT NOT NULL , instructor_name CHAR(50) NOT NULL , instructor_address CHAR(50) NULL , instructor_city CHAR(50) NULL , instructor_county CHAR(50) NULL , instructor_zip CHAR(10) NULL , instructor_phone INT NULL , instructor_email CHAR(255) NULL , instructor_dob DATETIME NULL , lessons_given INT NULL ); CREATE TABLE Cars ( car_id CHAR(10) NOT NULL , office_id INT NOT NULL , engine_serial_num CHAR(10) NULL , registration_num CHAR(10) NULL , car_make CHAR(50) NULL , car_model CHAR(50) NULL ); CREATE TABLE Offices ( office_id INT NOT NULL , office_address CHAR(50) NULL , office_city CHAR(50) NULL , office_County CHAR(50) NULL , office_zip CHAR(10) NULL , office_phone INT NULL , office_email CHAR(255) NULL ); CREATE TABLE Lessons ( lesson_num INT NOT NULL , client_id CHAR(10) NOT NULL , date DATETIME NOT NULL , time DATETIME NOT NULL , milegage_used DECIMAL(5, 2) NULL , progress CHAR(50) NULL ); CREATE TABLE DrivingTests ( test_num INT NOT NULL , client_id CHAR(10) NOT NULL , test_date DATETIME NOT NULL , seat_num INT NOT NULL , score INT NULL , test_notes CHAR(255) NULL ); ALTER TABLE Clients ADD PRIMARY KEY (client_id); ALTER TABLE Applications ADD PRIMARY KEY (application_id); ALTER TABLE Instructors ADD PRIMARY KEY (instructor_id); ALTER TABLE Offices ADD PRIMARY KEY (office_id); ALTER TABLE Lessons ADD PRIMARY KEY (lesson_num); ALTER TABLE DrivingTests ADD PRIMARY KEY (test_num); ALTER TABLE Applications ADD CONSTRAINT FK_Applications_Offices FOREIGN KEY (office_id) REFERENCES Offices (office_id); ALTER TABLE Applications ADD CONSTRAINT FK_Applications_Clients FOREIGN KEY (client_id) REFERENCES Clients (client_id); ALTER TABLE Applications ADD CONSTRAINT FK_Applications_Instructors FOREIGN KEY (instructor_id) REFERENCES Instructors (instructor_id); ALTER TABLE Applications ADD CONSTRAINT FK_Applications_Cars FOREIGN KEY (car_id) REFERENCES Cars (car_id); ALTER TABLE Lessons ADD CONSTRAINT FK_Lessons_Clients FOREIGN KEY (client_id) REFERENCES Clients (client_id); ALTER TABLE Cars ADD CONSTRAINT FK_Cars_Offices FOREIGN KEY (office_id) REFERENCES Offices (office_id); ALTER TABLE Clients ADD CONSTRAINT FK_DrivingTests_Clients FOREIGN KEY (client_id) REFERENCES Clients (client_id); These are the errors that I get: mysql> ALTER TABLE Applications ADD CONSTRAINT FK_Applications_Cars FOREIGN KEY (car_id) REFERENCES Cars (car_id); ERROR 1005 (HY000): Can't create table 'foo.#sql-12c_4' (errno: 150) I ran SHOW ENGINE INNODB STATUS which gives a more detailed error description: ------------------------ LATEST FOREIGN KEY ERROR ------------------------ 100509 20:59:49 Error in foreign key constraint of table practice9/#sql-12c_4: FOREIGN KEY (car_id) REFERENCES Cars (car_id): Cannot find an index in the referenced table where the referenced columns appear as the first columns, or column types in the table and the referenced table do not match for constraint. Note that the internal storage type of ENUM and SET changed in tables created with >= InnoDB-4.1.12, and such columns in old tables cannot be referenced by such columns in new tables. See http://dev.mysql.com/doc/refman/5.1/en/innodb-foreign-key-constraints.html for correct foreign key definition. ------------ I searched around on StackOverflow and elsewhere online - came across a helpful blog post here with pointers on how to resolve this error - but I can't figure out what's going wrong. Any help would be appreciated!

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  • CSS: Labels in table columns

    - by hello
    Hello. BACKGROUND: I would like to have small labels in columns of a table. I'm using some implemented parts of HTML5/CSS3 in my project, and this section specifically is for mobile devices. While both facts are not necessarily relevant, the bottom line is that I don't have to support Internet Explorer or even Firefox for that matter (just WebKit). THE PROBLEM With my current CSS approach, the vertical padding of the cell comes from the <span element (set to display: block with top/bottom margins), which contains the "value" of the column. As a result there's no padding when the <span> is empty or missing (no value) and the label is not in place. The "full" coulmns should give you the idea of where I want the labels to be, even if there's no value, and the <span> is not there. I realize that I could use "non-breaking-space", but I would really like to avoid it. I wonder if any of you have a fix / better way to do this? current code is below. Thank you for any help. <!DOCTYPE html> <html lang="en"> <head> <title>ah</title> <style> body { width: 320px; } /* TABLE */ table { width: 100%; border-collapse: collapse; font-family: arial; } th, td { border: 1px solid #ccc; border-width: 0px 0px 1px 1px; } th:last-child, td:last-child { border-right-width: 1px; } tr:first-child th { border-top-width: 1px; background: #efefef; } /* RELEVANT STUFF */ td { padding: 3px; } td sup { display: block; } td span { display: block; margin: 3px 0px; text-align: center; } </style> </head> <body> <table> <tr> <th colspan="3">something</th> </tr> <tr> <td><sup>some label</sup><span>any content</span></td> <td><sup>some label</sup><span>any content</span></td> <td><sup>some label</sup><span></span></td><!-- No content, just a label --> </tr> </table> </body> </html>

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  • PHP: table structure

    - by A3efan
    I'm developing a website that has some audio courses, each course can have multiple lessons. I want to display each course in its own table with its different lessons. This is my sql statement: Table: courses id, title Table: lessons id, cid (course id), title, date, file $sql = "SELECT lessons.*, courses.title AS course FROM lessons INNER JOIN courses ON courses.id = lessons.cid GROUP BY lessons.id ORDER BY lessons.id" ; Can someone help me with the PHP code? This is the I code I have written: mysql_select_db($database_config, $config); mysql_query("set names utf8"); $sql = "SELECT lessons.*, courses.title AS course FROM lessons INNER JOIN courses ON courses.id = lessons.cid GROUP BY lessons.id ORDER BY lessons.id" ; $result = mysql_query($sql) or die(mysql_error()); while ($row = mysql_fetch_assoc($result)) { echo "<p><span class='heading1'>" . $row['course'] . "</span> </p> "; echo "<p class='datum'>Posted onder <a href='*'>*</a>, latest update on " . strftime("%A %d %B %Y %H:%M", strtotime($row['date'])); } echo "</p>"; echo "<class id='text'>"; echo "<p>...</p>"; echo "<table border: none cellpadding='1' cellspacing='1'>"; echo "<tr>"; echo "<th>Nr.</th>"; echo "<th width='450'>Lesso</th>"; echo "<th>Date</th>"; echo "<th>Download</th>"; echo "</tr>"; echo "<tr>"; echo "<td>" . $row['nr'] . "</td>"; echo "<td>" . $row['title'] . "</td>"; echo "<td>" . strftime("%d/%m/%Y", strtotime($row['date'])) . "</td>"; echo "<td><a href='audio/" . rawurlencode($row['file']) . "'>MP3</a></td>"; echo "</tr>"; echo "</table>"; echo "<br>"; } ?>

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  • West Palm Beach .Net User Group Meeting - April 27th 2010 - Ted Neward - MVP & INETA Speaker

    - by Sam Abraham
    Ted Neward, MVP & INETA Speaker spoke to us at the West Palm Beach .Net User Group meeting at CompTec about Microsoft OSLO and DSLs on Tuesday April 27th 2010. Ted kept the audience well engaged throughout his presentation and shared his experience with DSLs in a humorous and fun setting. At the conclusion of the talk, we had our free raffle and concluded the evening with networking while enjoying the pizza and soda brought to us by Sherlock Technology (www.sherstaff.com) This meeting was also Vishal Shukla's last appearance at the West Palm Beach .Net User Group as he will be leaving for India in mid-May. Vishal has worked hard side-by-side with the Fladotnet leadership to run the West Palm Beach Group and will sure be missed by all of us. On behalf of the group, I would like to wish Vishal best of luck on his future endeavors and we are all looking forward to seeing him again soon. Thank you Ted for making such a long trip from Redmond to FL to share with us your expertise and knowledge of DSLs and thank you INETA for making this happen with your support of user groups. You can get in touch with Ted through his website (www.tedneward.com)

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  • WPB .Net User Group 11/29 Meeting - Kinect SDK with Joe Healy - New Meeting Location

    - by Sam Abraham
    We are excited to share great news and updates regarding the West Palm Beach .Net User Group. Our upcoming meeting will feature Joe Healy from Microsoft as speaker for the November 29th, 2011 6:30 PM meeting.   He will be covering the Kinect SDK and answering all our questions regarding the latest Windows Phone 7 Release. We will be also raffling many valuable items as part of our usual free raffle and hope each of our members leaves with a freebie.   We are also honored to share that we will be hosting our special meeting at a new location:   PC Professor 6080 Okeechobee Blvd.,  #200 West Palm Beach, FL 33417 Phone: 561-684-3333.   This is right by the Florida Turnpike entrance on Okeechobee Blvd.   PC Professor will be also providing our free pizza/soda and some additional surprise items for this meeting to mark the debut of our meetings at their location!   We would like to use this opportunity to thank our current host, CompTec, for its generous support and for hosting us for the past 2 years and look forward to their continued support and sponsorship.   A lot of work and effort is put into hosting a meeting that we hope translates into added value and benefit for our membership. We always welcome your feedback and participation as we strive to continuously improve the group.   Special thanks to our group member, Zack Weiner, for helping us find this new location.   For more details and to register please visit: http://www.fladotnet.com/Reg.aspx?EventID=536   Hope to see you all there.   --Sam Abraham & Venkat Subramanian Site Directors – West Palm Beach .Net User Group

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  • How to Navigate Directly From One Table to Another in Word 2013

    - by Lori Kaufman
    Jumping to a specific page in Word is a common task and easy to do using the Find and Replace dialog box. You can also use this same tab to jump from one table directly to the next table in your document. Your cursor does not have to be in a table to jump to the next table. Put the cursor in any paragraph or table and press F5 or use the Ctrl + G keystroke combination to open the Find and Replace dialog box. The Go To tab is automatically selected. Select Table from the Go to what list and click Next. The next table in your document is selected and the Find and Replace dialog box stays open.    

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  • Reorganizing MySQL table to multiple rows by timestamp.

    - by Ben Burleson
    OK MySQL Wizards: I have a table of position data from multiple probes defined as follows: +----------+----------+------+-----+---------+-------+ | Field | Type | Null | Key | Default | Extra | +----------+----------+------+-----+---------+-------+ | time | datetime | NO | | NULL | | | probe_id | char(3) | NO | | NULL | | | position | float | NO | | NULL | | +----------+----------+------+-----+---------+-------+ A simple select outputs something like this: +---------------------+----------+----------+ | time | probe_id | position | +---------------------+----------+----------+ | 2010-05-05 14:16:42 | 00A | 0.0045 | | 2010-05-05 14:16:42 | 00B | 0.0005 | | 2010-05-05 14:16:42 | 00C | 0.002 | | 2010-05-05 14:16:42 | 01A | 0 | | 2010-05-05 14:16:42 | 01B | 0.001 | | 2010-05-05 14:16:42 | 01C | 0.0025 | | 2010-05-05 14:16:43 | 00A | 0.0045 | | 2010-05-05 14:16:43 | 00B | 0.0005 | | 2010-05-05 14:16:43 | 00C | 0.002 | | 2010-05-05 14:16:43 | 01A | 0 | | . | . | . | | . | . | . | | . | . | . | +---------------------+----------+----------+ However, I'd like to output something like this: +---------------------+--------+--------+-------+-----+-------+--------+ | time | 00A | 00B | 00C | 01A | 01B | 01C | +---------------------+--------+--------+-------+-----+-------+--------+ | 2010-05-05 14:16:42 | 0.0045 | 0.0005 | 0.002 | 0 | 0.001 | 0.0025 | | 2010-05-05 14:16:43 | 0.0045 | 0.0005 | 0.002 | 0 | 0.001 | 0.0025 | | 2010-05-05 14:16:44 | 0.0045 | 0.0005 | 0.002 | 0 | 0.001 | 0.0025 | | 2010-05-05 14:16:45 | 0.0045 | 0.0005 | 0.002 | 0 | 0.001 | 0.0025 | | 2010-05-05 14:16:46 | 0.0045 | 0.0005 | 0.002 | 0 | 0.001 | 0.0025 | | 2010-05-05 14:16:47 | 0.0045 | 0.0005 | 0.002 | 0 | 0.001 | 0.0025 | | . | . | . | . | . | . | . | | . | . | . | . | . | . | . | | . | . | . | . | . | . | . | +---------------------+--------+--------+-------+-----+-------+--------+ Ideally, the different probe position columns are dynamically generated based on data in the table. Is this possible, or am I pulling my hair out for nothing? I've tried GROUP BY time with GROUP_CONCAT that roughly gets the data out, but I can't separate that output into probe_id columns. mysql SELECT time, GROUP_CONCAT(probe_id), GROUP_CONCAT(position) FROM MG41 GROUP BY time LIMIT 10; +---------------------+-------------------------+------------------------------------+ | time | GROUP_CONCAT(probe_id) | GROUP_CONCAT(position) | +---------------------+-------------------------+------------------------------------+ | 2010-05-05 14:16:42 | 00A,00B,00C,01A,01B,01C | 0.0045,0.0005,0.002,0,0.001,0.0025 | | 2010-05-05 14:16:43 | 01C,01B,01A,00C,00B,00A | 0.0025,0.001,0,0.002,0.0005,0.0045 | | 2010-05-05 14:16:44 | 01C,01B,01A,00C,00B,00A | 0.0025,0.001,0,0.002,0.0005,0.0045 | | 2010-05-05 14:16:45 | 01C,01B,01A,00C,00B,00A | 0.0025,0.001,0,0.002,0.0005,0.0045 | | 2010-05-05 14:16:46 | 01C,01B,01A,00C,00B,00A | 0.0025,0.001,0,0.002,0.0005,0.0045 | | 2010-05-05 14:16:47 | 01C,01B,01A,00C,00B,00A | 0.0025,0.001,0,0.002,0.0005,0.0045 | | 2010-05-05 14:16:48 | 01C,01B,01A,00C,00B,00A | 0.0025,0.001,0,0.002,0.0005,0.0045 | | 2010-05-05 14:16:49 | 01C,01B,01A,00C,00B,00A | 0.0025,0.001,0,0.002,0.0005,0.0045 | | 2010-05-05 14:16:50 | 01C,01B,01A,00C,00B,00A | 0.0025,0.001,0,0.002,0.0005,0.0045 | | 2010-05-05 14:16:51 | 01C,01B,01A,00C,00B,00A | 0.0025,0.001,0,0.002,0.0005,0.0045 | +---------------------+-------------------------+------------------------------------+

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  • T-SQL select where and group by date

    - by bconlon
    T-SQL has never been my favorite language, but I need to use it on a fairly regular basis and every time I seem to Google the same things. So if I add it here, it might help others with the same issues, but it will also save me time later as I will know where to look for the answers!! 1. How do I SELECT FROM WHERE to filter on a DateTime column? As it happens this is easy but I always forget. You just put the DATE value in single quotes and in standard format: SELECT StartDate FROM Customer WHERE StartDate >= '2011-01-01' ORDER BY StartDate 2. How do I then GROUP BY and get a count by StartDate? Bit trickier, but you can use the built in DATEADD and DATEDIFF to set the TIME part to midnight, allowing the GROUP BY to have a consistent value to work on: SELECT DATEADD (d, DATEDIFF(d, 0, StartDate),0) [Customer Creation Date], COUNT(*) [Number Of New Customers] FROM Customer WHERE StartDate >= '2011-01-01' GROUP BY DATEADD(d, DATEDIFF(d, 0, StartDate),0) ORDER BY [Customer Creation Date] Note: [Customer Creation Date] and [Number Of New Customers] column alias just provide more readable column headers. 3. Finally, how can you format the DATETIME to only show the DATE part (after all the TIME part is now always midnight)? The built in CONVERT function allows you to convert the DATETIME to a CHAR array using a specific format. The format is a bit arbitrary and needs looking up, but 101 is the U.S. standard mm/dd/yyyy, and 103 is the U.K. standard dd/mm/yyyy. SELECT CONVERT(CHAR(10), DATEADD(d, DATEDIFF(d, 0, StartDate),0), 103) [Customer Creation Date], COUNT(*) [Number Of New Customers] FROM Customer WHERE StartDate >= '2011-01-01' GROUP BY DATEADD(d, DATEDIFF(d, 0, StartDate),0) ORDER BY [Customer Creation Date]  #

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  • Allow non-sudo group to control Upstart job

    - by Angle O'Saxon
    I'm trying to set up an Upstart job to run on system startup, and that can also be started/stopped by members of a group other than sudo. With a previous version, I usedupdate-rc.d and scripts stored in /etc/init.d/ to get this working by adding %Group ALL = NOPASSWD: /etc/init.d/scriptname to my sudoers file, but I can't seem to get an equivalent working for Upstart. I tried adding %Group ALL = NOPASSWD: /sbin/initctl start jobname to the sudoers file, but trying to run the command start jobname produces this error: start: Rejected send message, 1 matched rules; type="method_call", sender=":1.21" (uid=1000 pid=5148 comm="start jobname " interface="com.ubuntu.Upstart0_6.Job" member="Start" error name="(unset)" requested_reply="0" destination="com.ubuntu.Upstart" (uid=0 pid=1 comm="/sbin/init") As near as I can tell, that's a complaint about how my user account isn't given the power to send 'Start' messages in the D-Bus config file for Upstart. I haven't been able to actually find any information on how to edit that file to give a group permission to access a specific service--does such an option exist? Is there a way to edit the Sudoers file so I can run the job without editing the config file? Am I better off just sticking with the previous version?

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  • Subquery using derived table in Hibernate HQL

    - by Vladimir
    I have a Hibernate HQL question. I'd like to write a subquery as a derived table (for performance reasons). Is it possible to do that in HQL? Example: FROM Customer WHERE country.id in (SELECT id FROM (SELECT id FROM Country where type='GREEN') derivedTable) (btw, this is just a sample query so don't give advices on rewriting it, is just the derived table concept I'm interested in) Thanks.

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  • ExtJS: Adding table inside a dynamically added tab

    - by esskar
    Hi, i'm fairly new to ExtJS. I adopted some examples and added the functionality to add tabs to a tab-control by clicking on some link. so far so good. now i want to load a ExtJS table into on of the new tabs. the items (rows, columns) are defined in a database on the server side. can you give me some hints how to add the table automatically when the tab is created?

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  • SQLite3, "ALTER TABLE" and durability

    - by Bill
    I'd like to run some ALTER TABLE statements on a sqlite3 database. What happens if the user kills the process or the power is cut while the ALTER TABLE is running? Will the database be left in a corrupt intermediate state?

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  • Table-Valued Parameter in Stored Procedure and the Entity Framework 4.0

    - by Fabio
    Hi there, I have a stored procedure called 'GetPrices' with a Table-Valued Parameter called 'StoreIDs' and I would like to call it from my Entity Framework. But when I try to add the Stored Procedure to the EDM, i get the following error: The function 'GetPrices' has a parameter 'StoreIDs' at parameter index 2 that has a data type 'table type' which is not supported. The function was excluded. Is there any workaround this? Any thoughts? Fabio

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  • Flex: How to most effectively tavere a table column

    - by Maik
    I have a table "template" which is used in various "instances". All instances have checkboxes in the second column (for record-delete). What would be the most effective way of traversing the table and check if at least one checkbox is selected (to enable a "delete" button)? Thanks! Maik

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  • table with black outer, but grey inner border

    - by Jan-Frederik Carl
    Hello, I want to create a html table with a 1pt black outer border and the same border around every td. Should look like this (only the borders, of course) link text I use <table border="1" style="border-collapse:collapse; border-color:Black; border-style:solid; border-width:1pt"> As a result I get a black outer, but grey inner borders.

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  • mysql create table help with unique

    - by Matt
    I'm trying to create a table, and can't figure out how to assign two columns to be unique.. I know how to alter a table thats already created, but how do you do it in the create.. im after a create if not exist col1 TEXT, col2 TEXT, col3 TEXT unique(col1, col2) ^very rough basic but you get the idea

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