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  • Can I change class types in a setter with an object-oriented language?

    - by user214626
    Hello, Here is the problem statement : Calling a setter on the object should result in the object to change to an object of a different class, which language can support this ? Ex. I have a class called "Man" (Parent Class), and two children namely "Toddler" and "Old Man", they are its children because they override a behaviour in Man called as walk.( i.e Toddler sometimes walks using both his hands and legs kneeled down and the Old man uses a stick to support himself). The Man class has a attribute called age, I have a setter on Man,say it is called setAge(int ageValue). I have 3 objects, 2 toddlers, 1 old-Man. (The system is up and running,i guess when we say objects it is obvious) .I will make this call, toddler.setAge(80), I expect the toddler to change to an object of type Old Man. Is this possible.Please suggest. Thanks,

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  • How do I read an attribute on a class at runtime?

    - by Zaff
    I am trying to create a generic method that will read an attribute on a class and return that value at runtime. How do would I do this? Note: DomainName attribute is of class DomainNameAttribute. [DomainName(“MyTable”)] Public class MyClass : DomianBase {} What I am trying to generate: //This should return “MyTable” String DomainNameValue = GetDomainName<MyClass>();

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  • C# - Custom Attributes - Setting an attribute property to the type of the decorated class.

    - by cmaduro
    Is it possible to get the decorated class' type inside of the custom attribute's class? For example: [MetadataAttribute] [AttributeUsage(AttributeTargets.Class | AttributeTargets.Property, AllowMultiple = false)] public class ViewAttribute : ExportAttribute { public object TargetRegion { get; set; } public Type ViewModel { get; set; } public Type Module { get; set; } public ViewAttribute() : base(typeof(UserControl)) { Module = GetDecoratedClassType(); //I need this method } } In the following example GetDecoratedClassType() would return HomeView [View] HomeView MyHomeView { get; set; }

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  • Should enumerations be placed in a separate file or within another class?

    - by Icono123
    I currently have a class file with the following enumeration: using System; namespace Helper { public enum ProcessType { Word = 0, Adobe = 1, } } Or should I include the enumeration in the class where it's being used? I noticed Microsoft creates a new class file for DockStyle: using System; using System.ComponentModel; using System.Drawing.Design; namespace System.Windows.Forms { public enum DockStyle { None = 0, Top = 1, Bottom = 2, Left = 3, Right = 4,. Fill = 5, } }

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  • Can a custom MFC window/dialog be a class template instantiation?

    - by John
    There's a bunch of special macros that MFC uses when creating dialogs, and in my quick tests I'm getting weird errors trying to compile a template dialog class. Is this likely to be a big pain to achieve? Here's what I tried: MyDlg.h template <class W> class CMyDlg : public CDialog { typedef CDialog super; DECLARE_DYNAMIC(CMyDlg <W>) public: CMyDlg (CWnd* pParent); // standard constructor virtual ~CMyDlg (); // Dialog Data enum { IDD = IDD_MYDLG }; protected: virtual void DoDataExchange(CDataExchange* pDX); // DDX/DDV support DECLARE_MESSAGE_MAP() private: W *m_pWidget; //W will always be a CDialog }; IMPLEMENT_DYNAMIC(CMyDlg<W>, super) <------------------- template <class W> CMyDlg<W>::CMyDlg(CWnd* pParent) : super(CMyDlg::IDD, pParent) { m_pWidget = new W(this); } I get a whole bunch of errors but main one appears to be: error C2955: 'CMyDlg' : use of class template requires template argument list I tried using some specialised template versions of macros but it doesn't help much, other errors change but this one remains. Note my code is all in one file, since C++ templates don't like .h/.cpp like normal. I'm assuming someone must have done this in the past, possibly creating custom versions of macros, but I can't find it by searching, since 'template' has other meanings.

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  • How can i encrypt a function or its contents in a php class?

    - by jane
    How can i encrypt a function or its contents in a php class ? e.g. Take a look at below class, i would like to encrypt the function test1() so the code inside will never be revealed but executes as normal class test { var $x; var $y; function test1() { return $this->x; } function test2() { return $this->y; } } Thanks in advance

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  • Is there a way to check if a div has the same class as an ancestor in jQuery?

    - by T.R.
    I'm looking to dynamically highlight a tab, if it represents the current page. I have: <style> #tabs li{bg-color: white;} body.Page1 #tabs .Page1, body.Page2 #tabs .Page2, body.Page3 #tabs .Page3{bg-color: orange;} </style> <body class="Page1 ADifferentClass"> <ul id="tabs"> <li class="Page1 SomeClass"> <li class="Page2 SomeOtherClass"> <li class="Page3 AnotherClass"> </ul> </body> As you can see, there needs to be CSS for each tab, so adding another page involves modifying both the HTML and the CSS. Is there a simple (DRY) way to check if two divs have the same class already built into jQuery? I ultimately went with this: <script> $(document).ready(function(){ var classRE = /Page\d+/i; var pageType = $('body').attr('className').match(classRE); $('li.'+pageType).addClass('Highlight'); }); </script> <style> #tabs li{bg-color: white;} #tabs li.Highlight{bg-color: orange;} </style>

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  • Resharper: how to force introducing new private fields at the bottom of the class?

    - by Igor Brejc
    Resharper offers a very useful introduce and initialize field xxx action when you specify a new parameter in a constructor like: Constructor (int parameter) The only (minor) nuisance is that it puts the new field at the beginning of the class - and I'm a fan of putting private parts as far away as possible from the prying eyes of strangers ;). If, however, you already have some private fields in the class, Resharper will put the new field "correctly" (note the quotes, I don't want to start a flame war over this issue) next to those, even if they are at the end of the class. Is there a way to force Resharper to always put new fields at the end of the class? UPDATE: OK, I forgot to mention I know about the "Type Members Layout in Options" feature, but some concrete help on how to modify the template to achieve fields placement would be nice.

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  • access EF classes from a Class Library - exactly how do configure/test the connection string in the

    - by Greg
    Hi, I'm getting very confused about how to call my EF classes in a Class Library from the Client Project I have? Things worked fine when they were in the same project. Now I'm getting errors such as "Unable to load the specified metadata resource ". I've see various ideas / suggestions re how to fix the connection string (e.g. create an App.config in your client project & copy the connection string config from your class library, something about change the connection settings to copy to output, etc) QUESTION - Can someone provide a solid way on how to get EF class access from a separate project working? (i.e. how to get the correct connection information to the client somehow) thanks

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  • Is it possible to specify a return type of "Derivative(of T)" for a MustOverride sub in VB.NET?

    - by Casey
    VB.NET 2008 .NET 3.5 I have two base classes that are MustInherit (partial). Let's call one class OrderBase and the other OrderItemBase. A specific type of order and order item would inherit from these classes. Let's call these WebOrder (inherits from OrderBase) and WebOrderItem (inherits from OrderItemBase). Now, in the grand scheme of things WebOrder is a composite class containing a WebOrderItem, like so: Public Class WebOrder Inherits OrderBase Public Property OrderItem() as WebOrderItem End Property End Class Public Class WebOrderItem Inherits OrderItemBase End Class In order to make sure any class that derives from OrderBase has the OrderItem property, I would like to do something like this in the OrderBase class: Public MustInherit Class OrderBase Public MustOverride Property OrderItem() as Derivative(Of OrderItemBase) End Class In other words, I want the derived class to be forced to contain a property that returns a derivative of OrderItemBase. Is this possible, or should I be using an entirely different approach?

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  • Is it possible to avoid C++ compiler error (C2757) where 2 different header files contain same symbol for namespace & class?

    - by dharmendra
    Hi, I am facing a problem when implementing some new code to an existing library. This library already references a class with a name say 'foo'. The same name is used as a namespace in the other header file which has to be included to implement the new functionality. Since both the header files are a part of legacy code libraries I cannot amend them. So here I am looking for any way so as to avoid the Compiler Error (C2757: a symbol with this name already exists and therefore this name cannot be used as a namespace name). I am not sure whether it is possible or not. Hence, Any help shall be appreciated. Thanks For clarity here is the sample code illustration for the issue: HeaderA.h class foo {} HeaderB.h namespace foo { class ABC{} } HeaderC.h #include <HeaderA.h> #include <HeaderB.h> using namespace foo; class Toimplement{ ABC a; //Throws Error C2757 }

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  • C++ Why am I unable to use an enum declared globally outside of the class it was declared in?

    - by VGambit
    Right now, my project has two classes and a main. Since the two classes inherit from each other, they are both using forward declarations. In the first object, right underneath the #include statement, I initialize two enums, before the class definition. I can use both enums just fine inside that class. However, if I try to use those enums in the other class, which inherits from the first one, I get an error saying the enum has not been declared. If I try to redefine the enum in the second class, I get a redefinition error. I have even tried using a trick I just read about, and putting each enum in its own namespace; that didn't change anything.

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  • What is a good naming convention to differentiate a class name from a property in C#?

    - by Andy Stampor
    I run into this frequently enough that I thought I'd see what others had to say about it. Using the StyleCop conventions, I find that I often have a property name that is hard to make different than the class name it is accessing. For example: public class ProjectManager { // Stuff here } public class OtherClass { private ProjectManager ProjectManager { get; set; } } It compiles and runs, but seems like it would be an easy way to confuse things, even with the use of "this".

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  • Why do I have to specify pure virtual functions in the declaration of a derived class in Visual C++?

    - by neuviemeporte
    Given the base class A and the derived class B: class A { public: virtual void f() = 0; }; class B : public A { public: void g(); }; void B::g() { cout << "Yay!"; } void B::f() { cout << "Argh!"; } I get errors saying that f() is not declared in B while trying do define void B::f(). Do I have to declare f() explicitly in B? I think that if the interface changes I shouldn't have to correct the declarations in every single class deriving from it. Is there no way for B to get all the virtual functions' declarations from A automatically? EDIT: I found an article that says the inheritance of pure virtual functions is dependent on the compiler: http://www.objectmentor.com/resources/articles/abcpvf.pdf I'm using VC++2008, wonder if there's an option for this.

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  • What's the Difference Between These Two Ruby Class Initialaztion Definitions?

    - by michaelmichael
    I'm working through a book on Ruby, and the author used a slightly different form for writing a class initialization definition than he has in previous sections of the book. It looks like this: class Ticket attr_accessor :venue, :date def initialize(venue, date) self.venue = venue self.date = date end end In previous sections of the book, it would've been defined like this: class Ticket attr_accessor :venue, :date def initialize(venue, date) @venue = venue @date = date end end Is there any functional difference between using the setter method, as in the first example vs. using the instance variable in the second? They both seem to work. Even mixing them up seems to work: class Ticket attr_accessor :venue, :date def initialize(venue, date) @venue = venue self.date = date end end

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  • What's the Difference Between These Two Ruby Class Initialization Definitions?

    - by michaelmichael
    I'm working through a book on Ruby, and the author used a slightly different form for writing a class initialization definition than he has in previous sections of the book. It looks like this: class Ticket attr_accessor :venue, :date def initialize(venue, date) self.venue = venue self.date = date end end In previous sections of the book, it would've been defined like this: class Ticket attr_accessor :venue, :date def initialize(venue, date) @venue = venue @date = date end end Is there any functional difference between using the setter method, as in the first example, vs. using the instance variable as in the second? They both seem to work. Even mixing them up works: class Ticket attr_accessor :venue, :date def initialize(venue, date) @venue = venue self.date = date end end

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  • jQuery select image in div if image parent does't have a certain class.

    - by Alex
    Wordpress wraps images with captions in a div with a class of .wp-caption. I'm looking for a way to select images that don't have this div so I can wrap them in different div. (to keep a consistent border around all the images) <div class="blog-post-content"> <div id="attachment_220" class="wp-caption alignleft" style="width: 310px"> <a href="/somewhere/"><img class="size-medium wp-image-220" src="/path/to/image" alt="" width="300" height="280" /></a> <p class="wp-caption-text">Caption Text</p> </div> <p>This is the body of the post</p> </div> To test my selector, I'm just trying to add a green border. I can handle the .wrap() once the selector is working. The most promising of my attempts is: $('.blog-post-content img').parent('div:not(".wp-caption")').css('border', '2px solid green'); ... but no luck.

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  • Can a custom MFC window/dialog be a template class?

    - by John
    There's a bunch of special macros that MFC uses when creating dialogs, and in my quick tests I'm getting weird errors trying to compile a template dialog class. Is this likely to be a big pain to achieve? Here's what I tried: MyDlg.h template <class W> class CMyDlg : public CDialog { typedef CDialog super; DECLARE_DYNAMIC(CMyDlg <W>) public: CMyDlg (CWnd* pParent); // standard constructor virtual ~CMyDlg (); // Dialog Data enum { IDD = IDD_MYDLG }; protected: virtual void DoDataExchange(CDataExchange* pDX); // DDX/DDV support DECLARE_MESSAGE_MAP() private: W *m_pWidget; //W will always be a CDialog }; IMPLEMENT_DYNAMIC(CMyDlg<W>, super) <------------------- template <class W> CMyDlg<W>::CMyDlg(CWnd* pParent) : super(CMyDlg::IDD, pParent) { m_pWidget = new W(this); } I get a whole bunch of errors but main one appears to be: error C2955: 'CMyDlg' : use of class template requires template argument list I tried using some specialised template versions of macros but it doesn't help much, other errors change but this one remains. Note my code is all in one file, since C++ templates don't like .h/.cpp like normal.

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  • When mocking a class with Moq, how can I CallBase for just specific methods?

    - by Daryn
    I really appreciate Moq's Loose mocking behaviour that returns default values when no expectations are set. It's convenient and saves me code, and it also acts as a safety measure: dependencies won't get unintentionally called during the unit test (as long as they are virtual). However, I'm confused about how to keep these benefits when the method under test happens to be virtual. In this case I do want to call the real code for that one method, while still having the rest of the class loosely mocked. All I have found in my searching is that I could set mock.CallBase = true to ensure that the method gets called. However, that affects the whole class. I don't want to do that because it puts me in a dilemma about all the other properties and methods in the class that hide call dependencies: if CallBase is true then I have to either Setup stubs for all of the properties and methods that hide dependencies -- Even though my test doesn't think it needs to care about those dependencies, or Hope that I don't forget to Setup any stubs (and that no new dependencies get added to the code in the future) -- Risk unit tests hitting a real dependency. Q: With Moq, is there any way to test a virtual method, when I mocked the class to stub just a few dependencies? I.e. Without resorting to CallBase=true and having to stub all of the dependencies? Example code to illustrate (uses MSTest, InternalsVisibleTo DynamicProxyGenAssembly2) In the following example, TestNonVirtualMethod passes, but TestVirtualMethod fails - returns null. public class Foo { public string NonVirtualMethod() { return GetDependencyA(); } public virtual string VirtualMethod() { return GetDependencyA();} internal virtual string GetDependencyA() { return "! Hit REAL Dependency A !"; } // [... Possibly many other dependencies ...] internal virtual string GetDependencyN() { return "! Hit REAL Dependency N !"; } } [TestClass] public class UnitTest1 { [TestMethod] public void TestNonVirtualMethod() { var mockFoo = new Mock<Foo>(); mockFoo.Setup(m => m.GetDependencyA()).Returns(expectedResultString); string result = mockFoo.Object.NonVirtualMethod(); Assert.AreEqual(expectedResultString, result); } [TestMethod] public void TestVirtualMethod() // Fails { var mockFoo = new Mock<Foo>(); mockFoo.Setup(m => m.GetDependencyA()).Returns(expectedResultString); // (I don't want to setup GetDependencyB ... GetDependencyN here) string result = mockFoo.Object.VirtualMethod(); Assert.AreEqual(expectedResultString, result); } string expectedResultString = "Hit mock dependency A - OK"; }

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