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  • Sum two rows in one - My Sql

    - by user303832
    I have found some similar posts, but I didn't find them useful. But I didn't know how to group them. I would like to Sum 'No' and 'Not Set' to one row, and to lose 'Not Set' row. So : 'No' = 'No' + 'Not Set' I have something like this : TEST TestCount Month 'Yes' 123 March 'No' 432 March 'Not Set' 645 March 'Yes' 13 April 'No' 42 April 'Not Set' 45 April 'Yes' 133 May 'No' 41 May 'Not Set' 35 May .... And I would like something like this : TEST TestCount Month 'Yes' 423 March 'No' 410 March 'Yes' 154 April 'No' 192 April 'Yes' 130 May 'No' 149 May .... Can anybody help me with this, tnx in advance

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  • writting an sql query

    - by Praveen Prasad
    iam having 2 tables table Items Table (this table holds all items iam having) itemId --------- Item1 Item2 Item3 Item4 Item5 table 2 users_item relation UserId || ItemId 1 || Item1 1 || Item2 userId one has stored 2 items Item1,Item2. Now i want to write a query on table1 (Items table) so that it displays all items which user1 has NOT chosen.

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  • Need MYSQL query for finding lowest score per game player

    - by Chris Barnhill
    I have a game on Facebook called Rails Across Europe. I have a Best Scores page where I show the players with the best 20 scores, which in game terms refers to the lowest winning turn. The problem is that there are a small number of players who play frequently, and their scores dominate the page. I'd like to make the scores page open to more players. So I thought that I could display the single lowest winning turn for each player instead of displaying all of the lowest winning turns for all players. The problem is that the query for this eludes me. So I hope that one of you brilliant StackOverflow folks can help me with this. I have included the relevant MYSQL table schemas below. Here are the the table relationships: player_stats contains statistics for either a game in progress or a completed game. If a game is in progress, winning_turn is zero (which means that games with a winning_turn of zero should not be included in the query). player_stats has a game_player table id reference. game_player contains data describing games currently in progress. game_player has a player table id reference. player contains data describing a person who plays the game. Here's the query I'm currently using: 'SELECT p.fb_user_id, ps.winning_turn, gp.difficulty_level, c.name as city_name, g.name as goods_name, d.cost FROM game_player as gp, player as p, player_stats as ps, demand as d, city as c, goods as g WHERE p.status = "ACTIVE" AND gp.player_id = p.id AND ps.game_player_id = gp.id AND d.id = ps.highest_demand_id AND c.id = d.city_id AND g.id = d.goods_id AND ps.winning_turn > 0 ORDER BY ps.winning_turn ASC, d.cost DESC LIMIT '.$limit.';'; Here are the relevant table schemas: -- -- Table structure for table `player_stats` -- CREATE TABLE IF NOT EXISTS `player_stats` ( `id` int(11) NOT NULL auto_increment, `game_player_id` int(11) NOT NULL, `winning_turn` int(11) NOT NULL, `highest_demand_id` int(11) NOT NULL, PRIMARY KEY (`id`), KEY `game_player_id` (`game_player_id`,`highest_demand_id`) ) ENGINE=InnoDB DEFAULT CHARSET=utf8 AUTO_INCREMENT=3814 ; -- -- Table structure for table `game_player` -- CREATE TABLE IF NOT EXISTS `game_player` ( `id` int(10) unsigned NOT NULL auto_increment, `game_id` int(10) unsigned NOT NULL, `player_id` int(10) unsigned NOT NULL, `player_number` int(11) NOT NULL, `funds` int(10) unsigned NOT NULL, `turn` int(10) unsigned NOT NULL, `difficulty_level` enum('STANDARD','ADVANCED','MASTER','ULTIMATE') NOT NULL, `date_last_used` datetime NOT NULL, PRIMARY KEY (`id`), KEY `game_id` (`game_id`,`player_id`) ) ENGINE=InnoDB DEFAULT CHARSET=utf8 AUTO_INCREMENT=3814 ; -- -- Table structure for table `player` -- CREATE TABLE IF NOT EXISTS `player` ( `id` int(11) NOT NULL auto_increment, `fb_user_id` char(255) NOT NULL, `fb_proxied_email` text NOT NULL, `first_name` char(255) NOT NULL, `last_name` char(255) NOT NULL, `birthdate` date NOT NULL, `date_registered` datetime NOT NULL, `date_last_logged_in` datetime NOT NULL, `status` enum('ACTIVE','SUSPENDED','CLOSED') NOT NULL, PRIMARY KEY (`id`), KEY `fb_user_id` (`fb_user_id`) ) ENGINE=InnoDB DEFAULT CHARSET=utf8 AUTO_INCREMENT=1646 ;

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  • Get latest record from second table left joined to first table

    - by codef0rmer
    I have a candidate table say candidates having only id field and i left joined profiles table to it. Table profiles has 2 fields namely, candidate_id & name. e.g. Table candidates: id 1 2 and Table `profiles`: candidate_id name 1 Foobar 1 Foobar2 2 Foobar3 i want the latest name of a candidate in a single query which is given below: SELECT C.id, P.name FROM candidates C LEFT JOIN profiles P ON P.candidate_id = C.id GROUP BY C.id ORDER BY P.name; But this query returns: 1 Foobar 2 Foobar3 Instead of: 1 Foobar2 2 Foobar3

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  • Substitute Items on Internal Sales Orders

    - by ChristineS-Oracle
    Oracle Order Management now enables you to substitute items on internal sales order lines to manage item availability.  Oracle Order Management enables you to substitute items on internal sales order lines to manage item availability. Source organizations can decide to ship a substitute item in case the original item is not available to be shipped. The application supports manual (using Related Items window) and automatic (using ATP functionality) substitutions.To substitute an item on ISO, you must ensure that the value of the Item Substitution on Internal Order system parameter is set to a value other than None. In addition, you must ensure to define substitute item relationships and automatic item substitution setup in the system. The application provides the option to not send the notifications when any change happens on the ISO related to quantity, schedule arrival date, or item. You can control these notifications using the OM: Send Notifications of Internal Order Change profile option. For additional information refer to the Oracle Order Management Release Notes for Release 12.2.4 (Doc ID 1906521.1).

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  • MySQL Hibernate sort on 2 columns

    - by sammichy
    I have a table as follows Table item { ID - Primary Key content - String published_date - When the content was published create_date - When this database entry was created } Every hour (or specified time interval) I run a process to update this table with data from different sources (websites). I want to display the results according to the following rules. 1. The entries created each time the process runs should be grouped together. So the entries from the 2nd process run will always be after the entries from the first process run even if the published_date of an entry from the first run is after the published_date of an entry from the 2nd run. 2. Within the grouping by run, the entries by sorted by published_date 3. Another restriction is that I prefer that data from the same source not be grouped together. If I do the sort by create_date, published_date I will end up with data from source a, data from source b etc. I prefer that the data within each hour be mixed up for better presentation If I add a column to this table and store a counter which increments each time the process is run, it is possible to create a query to sort first by counter and then by published_dt. Is there a way to do it without adding a field? I'm using Hibernate over MySQL. e.g. Hour 1 (run 1) 4 rows collected from site a (rows 1-4) 3 rows collected from site b (rows 5-7) hour 2 (run 2) 2 row collected from site a (rows 8-9) 3 rows collected from site b (rows 10-12) ... After each run, new records are added to the database from each website. The create date is the time when the record was created in the database. The published date is part of the content and is read in from the external source. When the results are displayed I would like rows to be grouped together based on the hour they were published in. So rows 1-7 would be displayed before rows 8-12. Within each hourly grouping, I would like to sort the results by published date (timestamp). This is necessary so that the posts from all the sites collected in that hour are not grouped together but rather mixed in with each other.

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  • Table character encoding - exception in application

    - by zgnilec
    I have a code: CREATE TABLE IF NOT EXISTS Person ( name varchar(24) ... ) CHARACTER SET utf8 COLLATE utf8_polish_ci; This works OK in my application, but I read if someone put in name field a string that contains character wchich code is greater than 127, database will use 2 bytes (or more) to store this character. So i think, i will change character set to utf16: CHARACTER SET utf16 COLLATE utf16_polish_ci; But now when I run my application, exception apears: KeyNotFoundException. It apears exactly at these instructions: MySqlCommand komenda = baza.Polaczenie.CreateCommand (); komenda.CommandText = zapytanie; MySqlDataReader dr = komenda.ExecuteReader (); // HERE, at execute reader method if (dr.Read ()) ... 1) Anyone had similar problem? 2) Any idea how to use always 2 bytes/char in database field?

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  • Query to find all bars that sell three different beers at the same price

    - by Eternal Learner
    Query to find "All bars that sell three different beers at the same price?" My Tables are Sells(bar,beer,price) - bar - foreign Key.. Bars(name,addr) - name primary key. I thought of something like this but that dosent seem to work ... Select A.bar As bar , B.bar as bar From Sells AS A, Sells AS B Where A.bar = B.bar and A.beer <> B.beer Group By(A.beer) Having Count(Distinct A.beer) >= 2 Is this the correct SQL query ?

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  • Oracle CRM On Demand Release 16

    Sandi Main Director, Oracle CRM On Demand Product Management provides an update on the features of this exciting new release. Learn how you can leverage Oracle CRM On Demand Release 16 to increase productivity and maximize your business needs.

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  • Lesetipp: Der TDAzlan Exadata Value Guide

    - by Alliances & Channels Redaktion
    Fast 20 Jahre sind Oracle und TDAzlan schon erfolgreiche Partner. Als VAD unterstützt TDAzlan Oracle Partner bei deren Business, zum Beispiel durch Sales- und Marketing-Support, Webcasts, Zertifizierungstrainings oder Enablement Workshops bis hin zur Spezialisierung. Jetzt wurde der Exadata Value Guide von Azlan für Partner und Kunden aktualisiert auf aktuelle 12c und X4 Technologien. Die Broschüre bündelt Fakten und Tipps rund um die Themen Exadata und Engineered Systems. Sie schlüsselt technische Details zu Oracle Software- und Hardware-Komponenten auf und bietet Verkaufsargumente sowie hilfreiche Erläuterungen zum Salesprozess. Außerdem wird das Oracle Authorized Solution Center (OASC) von TDAzlan in München vorgestellt. Dort haben Partner die Möglichkeit, Oracle Gesamtlösungen zu testen und Ihren Kunden zu präsentieren. Den Exadata Value Guide können sie auch auf der Oracle Informations-Webseite von TDAzlan herunterladen.

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  • October 2012 Security "Critical Patch Update" (CPU) information and downloads released

    - by user12244672
    The October 2012 security "Critical Patch Update" information and downloads are now available from My Oracle Support (MOS). See http://www.oracle.com/technetwork/topics/security/alerts-086861.html and in particular Document 1475188.1 on My Oracle Support (MOS), http://support.oracle.com, which includes security CVE mappings for Oracle Sun products. For Solaris 11, Doc 1475188.1 points to the relevant SRUs containing the fixes for each issue.  SRU12.4 was released on the CPU date and contains the current cumulative security fixes for the Solaris 11 OS. For Solaris 10, we take a copy of the Recommended Solaris OS patchset containing the relevant security fixes and rename it as the October CPU patchset on MOS.  See link provided from Doc 1475188.1 Doc 1475188.1 also contains references for Firmware, etc., and links to other useful security documentation, including information on Userland/FOSS vulnerabilities and fixes in https://blogs.oracle.com/sunsecurity/

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  • How to concatinate text on existing database entry?

    - by Starx
    I am a table, whose structure is somewhat like this id, name, link the link holds the name of the page like "link" = "index.php". Now I want to update this field and add "page=" in front of "index.php". Using this method I would like to update every entry in my table. My desired SQL syntax need to be something like this UPDATE mytable set link= 'page=' + <existing value of link> WHERE 1; I am using Where 1; to denote every other rows Anyone know what to accomplish this?

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  • Please verify the trigger created below for delete is correct or not?

    - by Parth
    Please verify the trigger created below for delete is correct or not? Its for the insertion of every field of deleted row in audit table.. Please reply whether this trigger will work for me? delimiter // CREATE TRIGGER audit_menu BEFORE DELETE ON menu FOR EACH ROW BEGIN INSERT INTO audit (menuid, field, oldvalue, changedone) VALUES (OLD.menuid, 'name', OLD.name, UNIX_TIMESTAMP() ), (OLD.menuid, 'age', OLD.age, UNIX_TIMESTAMP() ), (OLD.menuid, 'address', OLD.address, UNIX_TIMESTAMP() ), (OLD.menuid, 'sex', OLD.sex, UNIX_TIMESTAMP() ), (OLD.menuid, 'town', OLD.town, UNIX_TIMESTAMP() ) END;// delimiter ;

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  • Evaluate column value into rows

    - by Hugo Palma
    I have a column whose value is a json array. For example: [{"att1": "1", "att2": "2"}, {"att1": "3", "att2": "4"}, {"att1": "5", "att2": "6"}] What i would like is to provide a view where each element of the json array is transformed into a row and the attributes of each json object into columns. Keep in mind that the json array doesn't have a fixed size. Any ideas on how i can achieve this ?

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  • Complex data ordering...

    - by Povylas
    Hi, I have one tables ids in an array and they are ordered in the way I want and I have to select data from another table using those ids and in a order they are listen in the array. Pretty confusing but I was thinking of two solutions giving ORDER BY parameter the array but I do not know if that possible and another is to get all the necessary data and then turn it to array (mysql_fetch_assoc) then compare those two and somehow order the new array using the ids array. But I also do not know how to do this... Any ideas?

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  • New Video: Oracle and Intel Collaboration

    - by Cinzia Mascanzoni
    We just published a webcast discussing the technical collaboration between Oracle and Intel. The panel highlights the recent collaborations on elastic computing, Oracle Database In-Memory, and the newly announced products Exadata Database Machine X4-8 and Sun Server X4-8. In addition, panelists reflect on the specific technical advances that have resulted from over twenty years of partnership.

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  • How can this SQL be wrong? What am I not seeing?

    - by ropstah
    Can anybody please spot my error, this should be a legal query in SQL shouldn't it?? Unknown column u.usr_auto_key in the ON clause This is the database schema: User: (usr_auto_key, name, etc...) Setting: (set_auto_key, name etc..) User_Setting: (usr_auto_key, set_auto_key, value) And this is the query... SELECT `u`.`usr_auto_key` AS `u__usr_auto_key`, `s`.`set_auto_key` AS `s__set_auto_key`, `u2`.`usr_auto_key` AS `u2__usr_auto_key`, `u2`.`set_auto_key` AS `u2__set_auto_key`, `u2`.`value` AS `u2__value` FROM `User` `u`, `Setting` `s` LEFT JOIN `User_Setting` `u2` ON `u`.`usr_auto_key` = `u2`.`usr_auto_key` WHERE (`s`.`sct_auto_key` = 1 AND `u`.`usr_auto_key` = 1 AND admin_property is null)

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  • php code is not fetching data from mysql database using wamp server

    - by john
    I want to display a table from database in phpMyAdmin by putting the following conditions that in every different options in drop down menu it displays different table from database by pressing the button of search. But it is not doing so. <p class="h2">Quick Search</p> <div class="sb2_opts"> <p></p> <form method="post" action="" > <p>Enter your source and destination.</p> <p>From:</p> <select name="from"> <option value="Islamabad">Islamabad</option> <option value="Lahore">Lahore</option> <option value="murree">Murree</option> <option value="Muzaffarabad">Muzaffarabad</option> </select> <p>To:</p> <select name="To"> <option value="Islamabad">Islamabad</option> <option value="Lahore">Lahore</option> <option value="murree">Murree</option> <option value="Muzaffarabad">Muzaffarabad</option> </select> <input type="submit" value="search" /> </form> </form> </table> <?php $con=mysqli_connect("localhost","root","","test"); if (mysqli_connect_errno()) { echo "Failed to connect to MySQL: " . mysqli_connect_error(); } if(isset($_POST['from']) and isset($_POST['To'])) { $from = $_POST['from'] ; $to = $_POST['To'] ; $table = array($from, $to); switch ($table) { case array ("Islamabad", "Lahore") : $result = mysqli_query($con,"SELECT * FROM flights"); echo "</flights>"; //table name is flights break; case array ("Islamabad", "Murree") : $result = mysqli_query($con,"SELECT * FROM isb to murree"); echo "</isb to murree>"; //table name isb to murree ; break; case array ("Islamabad", "Muzaffarabad") : $result = mysqli_query($con,"SELECT * FROM isb to muzz"); echo "</isb to muzz>"; break; //..... //...... default: echo "Your choice is nor valid !!"; } } mysqli_close($con); ?>

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  • one query instead of four - is it possible?

    - by Syom
    i must get data from four tables. i wrote the script with four queries, but i use it in ajax, and i wan't to do it by one query. here is queries... $query1 = "SELECT `id`,`name_ar` FROM `tour_type` ORDER BY `order`"; $query2 = "SELECT `id`,`name_ar` FROM `hotel_type` ORDER BY `order`"; $query3 = "SELECT `id`,`name_ar` FROM `food_type` ORDER BY `order`"; $query4 = "SELECT `id`,`name_ar` FROM `cities` WHERE `id_parrent` = '$id_parrent' ORDER BY `name_ar`"; is it possible to write in one query? thanks

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  • Data from two tables without repeating data from the first?

    - by Aran
    I have two tables. Users table and Users Meta Table I am looking for a way to get all the information out of both tables with one query. But without repeating the information from Users table. This is all information relating to the users id number as well. So for example user_id = 1. Is there a way to query the database and collect all the information I from both tables without repeating the information from the first?

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