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  • Does Socket open another thread? Does it return something?

    - by Roman
    In the client application I call new Socket(serverIP,serverPort). As a result the client application sends a request to the server application to open a socket. Does it start a new thread? I mean which of the following is true? Client application sends a request and immediately starts to execute following commands (not weighting for the answer). Client sends the request and weights for the answer. As soon as the answer is obtained, the client application continues to execute following commands. The second case seems to be more realistic and logical for me. However, I do not understand what happens if the server does not open a socket and it does not say that it does not "want" to open the second (it can happen if the server does not exist or network is broken). What will happen in this case? Will server weight forever? In general it would be nice for the client to know what is the result of its request for the socket. For example I can imagine the following situations: The socket is opened by the server. The server refuses to open a socket. So, server exists, it got the request from the client but it says "no". There is no response from the server. I know that new Socket(serverIP,serverPort) does not "return" this kind of information. But it throws exceptions. One of them is "UnkownHostException". When it is thrown? When the server is not responding for a while (for how long)? ADDED: I just found out that UnknownHostException is thrown to indicate that the IP address of a host could not be determined. So, it is unrelated with the above described situations (server is not responding, server refuses to open a socket).

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  • how run Access 2007 module in Vb6?

    - by Mahmoud
    I have created a module in access 2007 that will update linked tables, but I wanted to run this module from vb6. I have tried this code from Microsoft, but it didnt work. Sub AccessTest1() Dim A As Object Set A = CreateObject("Access.Application") A.Visible = False A.OpenCurrentDatabase (App.Path & "/DataBase/acc.accdb") A.DoCmd.RunMacro "RefreshLinks" End Sub What I am aiming to do, is to allow my program to update all linked tables to new links, in case the program has been used on other computer In case you want to take a look at the module program, here it is: Sub CreateLinkedJetTable() Dim cat As ADOX.Catalog Dim tbl As ADOX.Table Set cat = New ADOX.Catalog ' Open the catalog. cat.ActiveConnection = CurrentProject.Connection Set tbl = New ADOX.Table ' Create the new table. tbl.Name = "Companies" Set tbl.ParentCatalog = cat ' Set the properties to create the link. tbl.Properties("Jet OLEDB:Link Datasource") = CurrentProject.Path & "/db3.mdb" tbl.Properties("Jet OLEDB:Remote Table Name") = "Companies" tbl.Properties("Jet OLEDB:Create Link") = True ' To link a table with a database password set the Link Provider String ' tbl.Properties("Jet OLEDB:Link Provider String") = "MS Access;PWD=Admin;" ' Append the table to the tables collection. cat.Tables.Append tbl Set cat = Nothing End Sub Sub RefreshLinks() Dim cat As ADOX.Catalog Dim tbl As ADOX.Table Set cat = New ADOX.Catalog ' Open the catalog. cat.ActiveConnection = CurrentProject.Connection Set tbl = New ADOX.Table For Each tbl In cat.Tables ' Verify that the table is a linked table. If tbl.Type = "LINK" Then tbl.Properties("Jet OLEDB:Link Datasource") = CurrentProject.Path & "/db3.mdb" ' To refresh a linked table with a database password set the Link Provider String 'tbl.Properties("Jet OLEDB:Link Provider String") = "MS Access;PWD=Admin;" End If Next End Sub

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  • Dealing with big IF statements in PHP

    - by Industrial
    Hi everyone, Is there any good alternative for the plain if statements in PHP? I know about switch, but I'll guess that there's some more refined alternative out there that comes handy when working with really big if statements. Thanks a lot,

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  • One iPhone, two developer machines

    - by willcodejavaforfood
    Hi all, I switch between my iMac and MacBook when working on my apps. I've always used my iMac to test the apps on the actual device, but I would like to be able to do this from both computers. I cannot seem to use the profile on my MacBook as it does not have the correct Certificate Signing Request in the KeyChain. Is there a way to copy these between machines and KeyChains? :)

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  • git-svn on Windows. Where to get binaries?

    - by divo
    Hi, I want to use git as a local repository against a remote SVN repository. I installed version 1.6.0.2 from http://code.google.com/p/msysgit/downloads/list. According to the documentation synchronization is done via the command git svn or a separate command wrapper called git-svn Neither of them is available in my installation and I could not find a separate download for Windows binaries. I'm currenty using the MSYS build. Must I switch to cygwin?

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  • How can I find the common ancestor of two nodes in a binary tree?

    - by Siddhant
    The Binary Tree here is not a Binary Search Tree. Its just a Binary Tree. The structure could be taken as - struct node { int data; struct node *left; struct node *right; }; The maximum solution I could work out with a friend was something of this sort - Consider this binary tree (from http://lcm.csa.iisc.ernet.in/dsa/node87.html) : The inorder traversal yields - 8, 4, 9, 2, 5, 1, 6, 3, 7 And the postorder traversal yields - 8, 9, 4, 5, 2, 6, 7, 3, 1 So for instance, if we want to find the common ancestor of nodes 8 and 5, then we make a list of all the nodes which are between 8 and 5 in the inorder tree traversal, which in this case happens to be [4, 9, 2]. Then we check which node in this list appears last in the postorder traversal, which is 2. Hence the common ancestor for 8 and 5 is 2. The complexity for this algorithm, I believe is O(n) (O(n) for inorder/postorder traversals, the rest of the steps again being O(n) since they are nothing more than simple iterations in arrays). But there is a strong chance that this is wrong. :-) But this is a very crude approach, and I'm not sure if it breaks down for some case. Is there any other (possibly more optimal) solution to this problem?

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  • Does any body see a reson in DesignForExtension Check in Checkstyle?

    - by Roman Ivanov
    Check: http://checkstyle.sourceforge.net/config_design.html#DesignForExtension False positives: Checkstyle "Method Not Designed For Extension" error being incorrectly issued? checkstyle Method is not designed for extension - needs to be abstract, final or empty https://sourceforge.net/p/checkstyle/bugs/688/ Look like all switch that Check off in their configurations. Does anybody could show real code example where this Check is useful ? and good for developers.

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  • error catching exception while System.out.print

    - by user1702633
    I have 2 classes, one that implements a double lookup( int i); and one where I use that lookup(int i) in solving a question, or in this case printing the lookup values. This case is for an array. So I read the exception documentation or google/textbook and come with the following code: public double lookup(int i) throws Exception { if( i > numItems) throw new Exception("out of bounds"); return items[i]; } and take it over to my class and try to print my set, where set is a name of the object type I define in the class above. public void print() { for (int i = 0; i < set.size() - 1; i++) { System.out.print(set.lookup(i) + ","); } System.out.print(set.lookup(set.size())); } I'm using two print()'s to avoid the last "," in the print, but am getting an unhandled exception Exception (my exception's name was Exception) I think I have to catch my exception in my print() but cannot find the correct formatting online. Do I have to write catch exception Exception? because that gives me a syntax error saying invalid type on catch. Sources like http://docs.oracle.com/javase/tutorial/essential/exceptions/ are of little help to me, I'm can't seem to grasp what the text is telling me. I'm also having trouble finding sources with multiple examples where I can actually understand the coding in the examples. so could anybody give me a source/example for the above catch phrase and perhaps a decent source of examples for new Java programmers? my book is horrendous and I cannot seem to find an understandable example for the above catch phrase online.

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  • Setting Image.Source doesn't update when loading from a resource.

    - by ChrisF
    I've got this definition in my XAML: <Image Name="AlbumArt" Source="/AlbumChooser2;component/Resources/help.png" /> The image is display OK on startup. In my code I'm looking for mp3's to play and I display the associated album art in this Image. Now if there's no associated image I want to display a "no image" image. So I've got one defined and I load it using: BitmapImage noImage = new BitmapImage( new Uri("/AlbumChooser2;component/Resources/no_image.png", UriKind.Relative)); I've got a helper class that finds the image if there is one (returning it as a BitmapImage), or returns null if there isn't one: if (findImage.Image != null) { this.AlbumArt.Source = findImage.Image; // This works } else { this.AlbumArt.Source = noImage; // This doesn't work } In the case where an image is found the source is updated and the album art gets displayed. In the case where an image isn't found I don't get anything displayed - just a blank. I don't think that it's the setting of AlbumArt.Source that's wrong, but the loading of the BitmapImage. If I use a different image it works, but if I recreate the image it doesn't work. What could be wrong with the image?

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  • Changing image domain / path in css for production?

    - by Neil
    Currently, for things like background images, our css files have no domain specified. This works both in our development and production environments. background-image: url(/images/bg.png); For performance reasons (cookie-less domain), we'd like to switch this: background-image: url(http://staticimagedomain.com/images/bg.png); Ideally, we don't hard code those, so our development environments can still pull locally. Any thoughts on how to best achieve this?

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  • Which language coders are paid highest.?

    - by user338322
    I am an iPhone/iPad developer. Can I know which language coders are paid highest wages. ? I am thinking to switch to C++. Any suggestions if I should move to another language. If Yes please let me know which one.? or should I continue with iPhone/iPad development.

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  • reset TextView scroll to top

    - by JayAvon
    Okay well I apologize for how sloppy this code is, but I still cant figure out how to post a code tag on here correctly. So I am making an Android application (Java) and i have a scrolling text field. If the user scrolls a long row down and stays at the end when they click the next row and if it is short, it will be scrolled down on that element too even though it may be a 1 line(and non scrollable) row. I was wondering if there is any way I can call something to right after txtLvlInfo.setText to reset the x-scroll value to 0 or something so it is always reset to the top of the content, long or short. Thanks for any help with this and please let me know if I need to clarify more. TextView txtLvlInfo = (TextView) findViewById(R.id.txtLevelInfo); txtLvlInfo.setMovementMethod(new ScrollingMovementMethod()); switch (v.getId()){ case R.id.row1: txtLvlInfo.setText("1: My text view is only two lines max and so I set it to scroll, if the user clicks row2 to load that text while having me scrolled down they have to click and pull to drag back down to the top of text view 2 row."); break; case R.id.row2: txtLvlInfo.setText("I only fill line 1 of the two."); break; android:textColor="#052027" android:text="" android:id="@+id/txtLevelInfo" android:scrollbars="vertical" android:layout_alignParentLeft="true" android:layout_width="fill_parent" android:layout_height="fill_parent" android:layout_toRightOf="@+id/minimizeBtn" android:layout_marginRight="38dip"

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  • MVC + Is validation attributes enough?

    - by ebb
    My ViewModel has validation attributes that ensure that it wont be empty etc. - Is that enough or should I let my the code contracts I have made be in the ActionResult too? Example: // CreateCaseViewModel.cs public class CreateCaseViewModel { [Required] public string Topic { get; set; } [Required] public string Message { get; set; } } // CaseController.cs [AuthWhere(AuthorizeRole.Developer)] [HttpPost] public ActionResult Create(CreateCaseViewModel model) { if(!ModelState.IsValid) { // TODO: some cool stuff? } if (string.IsNullOrWhiteSpace(model.Message)) { throw new ArgumentException("Message cannot be null or empty", model.Message); } if (string.IsNullOrWhiteSpace(model.Topic)) { throw new ArgumentException("Topic cannot be null or empty", model.Topic); } var success = false; string message; var userId = new Guid(_membershipService.GetUserByUserName(User.Identity.Name).ProviderUserKey.ToString()); if(userId == Guid.Empty) { throw new ArgumentException("UserId cannot be empty"); } Case createCase = _caseService.CreateCase(model.Topic, model.Message); if(createCase == null) { throw new ArgumentException("Case cannot be null"); } if(_caseService.AddCase(createCase, userId)) { message = ControllerResources.CaseCreateFail; } else { success = true; message = ControllerResources.CaseCreateSuccess; } return Json(new { Success = success, Message = message, Partial = RenderPartialViewToString(ListView, GetCases) }); }

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  • what is the relation between SIGTSTP and SIGCHLD

    - by Rawhi
    I have tow handlers for each one of them (SIGTSTP, SIGCHLD), the thing is that when I pause a process using SIGTSTP the handler function of SIGCHLD run too. what should I do to prevent this . void ExeExternal(char *args[MAX_ARG], char* cmdString, LIST_ELEMENT** pList, int *Susp_Bg_Pid, int *susp) { int pID, status, w; switch (pID = fork()) { case -1: perror("smash error: >"); break; case 0: // Child Process setpgrp(); execv(args[0], args); execvp(args[0], args); perror("error"); exit(EXIT_FAILURE); break; default: if (cmdString[strlen(cmdString) - 1] != '&') { *Susp_Bg_Pid = pID; *susp = 1; while(*susp); } else { InsertElem(pList, args[0], getpid(), pID, 0); } break; } } signal handlers : void signalHandler(int signal) { int pid, cstatus; if (signal == SIGCHLD) { susp = 0; pid = waitpid(-1, &cstatus, WNOHANG); printf("[[child %d terminated]]\n", pid); DelPID(&JobsList, pid); } } void ctrlZsignal(int signal){ kill(Susp_Bg_Pid, SIGTSTP); susp = 0; printf("\nchild %d suspended\n", Susp_Bg_Pid); } Susp_Bg_Pid used to save the paused process id. susp indicates the state of the "smash" the parent process if it is suspended or not .

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  • how to make the vim plugin "Project" and "Mini Buffer Explorer" work together?

    - by SunLiWei
    As the title says, I need to make these plugins work together well. The mini buffer explorer just automatically opens after I open the second file(press Enter in project plugin window), then Mini Buffer Explorer opens as the third window on the top of my screen. But after I switch back to project plugin window and press Enter to open the third file, a fourth window opened! It seems project plugin can't overwrite the second file's window. Project plugin 1.4.1 Mini Buffer Explorer plugin 6.4.0

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  • button onclick not working

    - by nsw1475
    I have a javascript where I need to hide (and eventually show) some text by clicking a button. However, when I click the button, it does not call the function specified in the onclick parameter, and so nothing happens. Here is my source code: <script type="text/javascript"> $(document).ready(function(){ var tip = 1; $(".tip1").hide(); $(".tip2").hide(); switch (tip) { case 1: $(".tip1").show(); break; case 2: $(".tip2").show(); break; } function nextTip() { $(".tip1").hide(); return; } }); </script> <br/> <div id='bg_container' style='background-image: url("<?=$PICS?>trackingpage_middle.jpg")' > <img style='z-index:-1;' width='737px' src='<?=$PICS?>trackingpage_top.jpg'> <div id='main_container' > <form> <input type="button" onClick="nextTip()" value = "Next Tip" /> </form> <div class="tip1"> ... and so on.

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  • How to make it easier when using the vim command in unix?

    - by Mitral
    Recently i try to learn something about the unix. when i try to edit something using the vi command, it is very difficult for me since i have to switch the edit mode and control mode time by time. It is very inconvenient. Is it that i miss something or it is originally like that? Is there anyway to improve that? Thank you :)

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  • ProgressDialog won't show, even in onPreExecute of AsyncTask

    - by Geltrude
    In my class, Main extends Activity, I've this: @Override protected void onActivityResult(int requestCode, int resultCode, Intent data) { super.onActivityResult(requestCode, resultCode, data); switch (requestCode) { case ... case CREDENTIAL_VIEW: new SetStatusProgressBar(this).execute(); And there is this nested class: private class SetStatusProgressBar extends AsyncTask<String, Void, Boolean> { private ProgressDialog dialog; private Main ctx; public SetStatusProgressBar(Main ctx) { this.ctx = ctx; dialog = new ProgressDialog(ctx); } // progress dialog to show user that contacting server. protected void onPreExecute() { this.dialog = ProgressDialog.show(ctx, null, "Refreshing data from server...", true, false); } @Override protected void onPostExecute(final Boolean success) { //... //statements that refresh UI //... if (dialog.isShowing()) { dialog.dismiss(); timerProgressBarStop(); } } protected Boolean doInBackground(final String... args) { //... //statements to download data from server //... return true; } } In the Main class I open a second Activity, in this way: Intent myIntent = new Intent(Main.this, Credentials.class); startActivityForResult(myIntent, CREDENTIAL_VIEW); That second Activity returns to the Main activity in this way: Intent intent = new Intent(); setResult(RESULT_OK, intent); finish(); I don't understand why when I navigate from the second Activity to the Main, the ProgressDialog will show ONLY AFTER that the UI refreshes... In this way the Progress Dialog stays on the screen only for half second... and then hides! :( I'd like to see the ProgressDialog on top during all the download time! Help, please. Thank you all

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  • What is the best way to wait for a GPS location fix?

    - by qtips
    Hi, Using my Android application, when a user does a certain action, a background service is started that fetches the current GPS location and saves it in a database in addition of doing some other stuff. In that service, I use the requestLocationUpdates() from the LocationManager class and wait until the onLocationChanged() of my LocationListener (which is implemented by the service) is fired. But what is the best way to wait for the onLocationChanged to fire? Should I simply poll on a variable and wait until it is set? Any tips? Note: I cannot simply write to the database in the onLocationChanged() because of some other stuff. EDIT: To clearfy my situation, I can present an example similar to my case: Let's say user pushes a button and a method myMethod is fired which will return some object. Then, in this myMethod I will register for location updates from the GPS (using requestLocationChanged) and in addition wait for the users location and use it for something. In other words, myMethod cannot return before the location is present. I don't know how I can use onLocationChanged in this case.

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  • Merging ILists to bind on datagridview to avoid using a database view

    - by P.Bjorklund
    In the form we have this where IntaktsBudgetsType is a poorly named enum that only specifies wether to populate the datagridview after customer or product (You do the budgeting either after product or customer) private void UpdateGridView() { bs = new BindingSource(); bs.DataSource = intaktsbudget.GetDataSource(this.comboBoxKundID.Text, IntaktsBudgetsType.PerKund); dataGridViewIntaktPerKund.DataSource = bs; } This populates the datagridview with a database view that merge the product, budget and customer tables. The logic has the following method to get the correct set of IList from the repository which only does GetTable<T>.ToList<T> public IEnumerable<IntaktsBudgetView> GetDataSource(string id, IntaktsBudgetsType type) { IList<IntaktsBudgetView> list = repository.SelectTable<IntaktsBudgetView>(); switch (type) { case IntaktsBudgetsType.PerKund: return from i in list where i.kundId == id select i; case IntaktsBudgetsType.PerProdukt: return from i in list where i.produktId == id select i; } return null; } Now I don't want to use a database view since that is read-only and I want to be able to perform CRUD actions on the datagridview. I could build a class that acts as a wrapper for the whole thing and bind the different table values to class properties but that doesn't seem quite right since I would have to do this for every single thing that requires "the merge". Something pretty important (and probably basic) is missing the the thought process but after spending a weekend on google and in books I give up and turn to the SO community.

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  • How to avoid notice in php when one of the conditions is not true

    - by user225269
    I've notice that when one of the two conditions in a php if statement is not true. You get an undefined index notice for the statement that is not true. And the result in my case is a distorted web page. For example, this code: <?php session_start(); if (!isset($_SESSION['loginAdmin']) && ($_SESSION['loginAdmin'] != '')) { header ("Location: loginam.php"); } else { include('head2.php'); } if (!isset($_SESSION['login']) && ($_SESSION['login'] != '')) { header ("Location: login.php"); } else { include('head3.php'); } ?> If one of the if statements is not true. The one that is not true will give you a notice that it is undefined. In my case it says that the session 'login' is not defined. If session 'LoginAdmin' is used. What can you recommend that I would do in order to avoid these undefined index notice.

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