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  • Does Ivy's url resolver support transitive retrieval?

    - by Sean
    For some reason I can't seem to resolve the dependencies of my dependencies when using a url resolver to specify a repository's location. However, when using the ibiblio resolver, I am able to retrieve them. For example: <!-- Ivy File --> <ivy-module version="1.0"> <info organisation="org.apache" module="chained-resolvers"/> <dependencies> <dependency org="commons-lang" name="commons-lang" rev="2.0" conf="default"/> <dependency org="checkstyle" name="checkstyle" rev="5.0"/> </dependencies> </ivy-module> <!-- ivysettings file --> <ivysettings> <settings defaultResolver="chained"/> <resolvers> <chain name="chained"> <url name="custom-repo"> <ivy pattern="http://my.internal.domain.name/ivy/[organisation]/[module]/[revision]/ivy-[revision].xml"/> <artifact pattern="http://my.internal.domain.name/ivy/[organisation]/[module]/[revision]/[artifact]-[revision].[ext]"/> </url> <url name="ibiblio-mirror" m2compatible="true"> <artifact pattern="http://mirrors.ibiblio.org/pub/mirrors/maven2/[organisation]/[module]/[revision]/[artifact]-[revision].[ext]" /> </url> <ibiblio name="ibiblio" m2compatible="true"/> </chain> </resolvers> </ivysettings> <!-- checkstyle ivy.xml file generated from pom via ivy:install task --> <?xml version="1.0" encoding="UTF-8"?> <ivy-module version="1.0" xmlns:m="http://ant.apache.org/ivy/maven"> <info organisation="checkstyle" module="checkstyle" revision="5.0" status="release" publication="20090509202448" namespace="maven2" > <license name="GNU Lesser General Public License" url="http://www.gnu.org/licenses/lgpl.txt" /> <description homepage="http://checkstyle.sourceforge.net/"> Checkstyle is a development tool to help programmers write Java code that adheres to a coding standard </description> </info> <configurations> <conf name="default" visibility="public" description="runtime dependencies and master artifact can be used with this conf" extends="runtime,master"/> <conf name="master" visibility="public" description="contains only the artifact published by this module itself, with no transitive dependencies"/> <conf name="compile" visibility="public" description="this is the default scope, used if none is specified. Compile dependencies are available in all classpaths."/> <conf name="provided" visibility="public" description="this is much like compile, but indicates you expect the JDK or a container to provide it. It is only available on the compilation classpath, and is not transitive."/> <conf name="runtime" visibility="public" description="this scope indicates that the dependency is not required for compilation, but is for execution. It is in the runtime and test classpaths, but not the compile classpath." extends="compile"/> <conf name="test" visibility="private" description="this scope indicates that the dependency is not required for normal use of the application, and is only available for the test compilation and execution phases." extends="runtime"/> <conf name="system" visibility="public" description="this scope is similar to provided except that you have to provide the JAR which contains it explicitly. The artifact is always available and is not looked up in a repository."/> <conf name="sources" visibility="public" description="this configuration contains the source artifact of this module, if any."/> <conf name="javadoc" visibility="public" description="this configuration contains the javadoc artifact of this module, if any."/> <conf name="optional" visibility="public" description="contains all optional dependencies"/> </configurations> <publications> <artifact name="checkstyle" type="jar" ext="jar" conf="master"/> </publications> <dependencies> <dependency org="antlr" name="antlr" rev="2.7.6" force="true" conf="compile->compile(*),master(*);runtime->runtime(*)"/> <dependency org="apache" name="commons-beanutils-core" rev="1.7.0" force="true" conf="compile->compile(*),master(*);runtime->runtime(*)"/> <dependency org="apache" name="commons-cli" rev="1.0" force="true" conf="compile->compile(*),master(*);runtime->runtime(*)"/> <dependency org="apache" name="commons-logging" rev="1.0.3" force="true" conf="compile->compile(*),master(*);runtime->runtime(*)"/> <dependency org="com.google.collections" name="google-collections" rev="0.9" force="true" conf="compile->compile(*),master(*);runtime->runtime(*)"/> </dependencies> </ivy-module> Using the "ibiblio" resolver I have no problem resolving my project's two dependencies (commons-lang 2.0 and checkstyle 5.0) and checkstyle's dependencies. However, when attempting to exclusively use the "custom-repo" or "ibiblio-mirror" resolvers, I am able to resolve my project's two explicitly defined dependencies, but not checkstyle's dependencies. Is this possible? Any help would be greatly appreciated.

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  • library for octree or kdtree

    - by Will
    Are there any robust performant libraries for indexing objects? It would need frustum culling and visiting objects hit by a ray as well as neighbourhood searches. I can find lots of articles showing the math for the component parts, often as algebra rather than simple C, but nothing that puts it all together (apart from perhaps Ogre, which has rather more involved and isn't so stand-alone). Surely hobby game makers don't all have to make their own octrees? (Python or C/C++ w/bindings preferred)

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  • I need to move an entity to the mouse location after i rightclick

    - by I.Hristov
    Well I've read the related questions-answers but still cant find a way to move my champion to the mouse position after a right-button mouse-click. I use this code at the top: float speed = (float)1/3; And this is in my void Update: //check if right mouse button is clicked if (mouse.RightButton == ButtonState.Released && previousButtonState == ButtonState.Pressed) { // gets the position of the mouse in mousePosition mousePosition = new Vector2(mouse.X, mouse.Y); //gets the current position of champion (the drawRectangle) currentChampionPosition = new Vector2(drawRectangle.X, drawRectangle.Y); // move champion to mouse position: //handles the case when the mouse position is really close to current position if (Math.Abs(currentChampionPosition.X - mousePosition.X) <= speed && Math.Abs(currentChampionPosition.Y - mousePosition.Y) <= speed) { drawRectangle.X = (int)mousePosition.X; drawRectangle.Y = (int)mousePosition.Y; } else if (currentChampionPosition != mousePosition) { drawRectangle.X += (int)((mousePosition.X - currentChampionPosition.X) * speed); drawRectangle.Y += (int)((mousePosition.Y - currentChampionPosition.Y) * speed); } } previousButtonState = mouse.RightButton; What that code does at the moment is on a click it brings the sprite 1/3 of the distance to the mouse but only once. How do I make it move consistently all the time? It seems I am not updating the sprite at all. EDIT I added the Vector2 as Nick said and with speed changed to 50 it should be OK. I tried it with if ButtonState.Pressed and it works while pressing the button. Thanks. However I wanted it to start moving when single mouse clicked. It should be moving until reaches the mousePosition. The Edit of Nick's post says to create another Vector2, But I already have the one called mousePosition. Not sure how to use another one. //gets a Vector2 direction to move *by Nick Wilson Vector2 direction = mousePosition - currentChampionPosition; //make the direction vector a unit vector direction.Normalize(); //multiply with speed (number of pixels) direction *= speed; // move champion to mouse position if (currentChampionPosition != mousePosition) { drawRectangle.X += (int)(direction.X); drawRectangle.Y += (int)(direction.Y); } } previousButtonState = mouse.RightButton;

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  • efficient collision detection - tile based html5/javascript game

    - by Tom Burman
    Im building a basic rpg game and onto collisions/pickups etc now. Its tile based and im using html5 and javascript. i use a 2d array to create my tilemap. Im currently using a switch statement for whatever key has been pressed to move the player, inside the switch statement. I have if statements to stop the player going off the edge of the map and viewport and also if they player is about to land on a tile with tileID 3 then the player stops. Here is the statement: canvas.addEventListener('keydown', function(e) { console.log(e); var key = null; switch (e.which) { case 37: // Left if (playerX > 0) { playerX--; } if(board[playerX][playerY] == 3){ playerX++; } break; case 38: // Up if (playerY > 0) playerY--; if(board[playerX][playerY] == 3){ playerY++; } break; case 39: // Right if (playerX < worldWidth) { playerX++; } if(board[playerX][playerY] == 3){ playerX--; } break; case 40: // Down if (playerY < worldHeight) playerY++; if(board[playerX][playerY] == 3){ playerY--; } break; } viewX = playerX - Math.floor(0.5 * viewWidth); if (viewX < 0) viewX = 0; if (viewX+viewWidth > worldWidth) viewX = worldWidth - viewWidth; viewY = playerY - Math.floor(0.5 * viewHeight); if (viewY < 0) viewY = 0; if (viewY+viewHeight > worldHeight) viewY = worldHeight - viewHeight; }, false); My question is, is there a more efficient way of handling collisions, then loads of if statements for each key? The reason i ask is because i plan on having many items that the player will need to be able to pickup or not walk through like walls cliffs etc. Thanks for your time and help Tom

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  • How to implement smooth flocking

    - by Craig
    I'm working on a simple survival game, avoid the big guy and chase the the small guys to stay alive for as long as possible. I have taken the chase and evade example from MSDN create and drawn 20 mice on the screen. I want the small guys to flock when they arent evading. They are doing this, but it isnt as smooth as I would like it to be. How do i make the movement smoother? Its very jittery.# Below is what I have going at the moment, flocking code is within the IF statement, when it isnt set to evading. Any help would be greatly appreciated! :) namespace ChaseAndEvade { class MouseSprite { public enum MouseAiState { // evading the cat Evading, // the mouse can't see the "cat", and it's wandering around. Wander } // how fast can the mouse move? public float MaxMouseSpeed = 4.5f; // and how fast can it turn? public float MouseTurnSpeed = 0.20f; // MouseEvadeDistance controls the distance at which the mouse will flee from // cat. If the mouse is further than "MouseEvadeDistance" pixels away, he will // consider himself safe. public float MouseEvadeDistance = 100.0f; // this constant is similar to TankHysteresis. The value is larger than the // tank's hysteresis value because the mouse is faster than the tank: with a // higher velocity, small fluctuations are much more visible. public float MouseHysteresis = 60.0f; public Texture2D mouseTexture; public Vector2 mouseTextureCenter; public Vector2 mousePosition; public MouseAiState mouseState = MouseAiState.Wander; public float mouseOrientation; public Vector2 mouseWanderDirection; int separationImpact = 4; int cohesionImpact = 6; int alignmentImpact = 2; int sensorDistance = 50; public void UpdateMouse(Vector2 position, MouseSprite [] mice, int numberMice, int index) { Vector2 catPosition = position; int enemies = numberMice; // first, calculate how far away the mouse is from the cat, and use that // information to decide how to behave. If they are too close, the mouse // will switch to "active" mode - fleeing. if they are far apart, the mouse // will switch to "idle" mode, where it roams around the screen. // we use a hysteresis constant in the decision making process, as described // in the accompanying doc file. float distanceFromCat = Vector2.Distance(mousePosition, catPosition); // the cat is a safe distance away, so the mouse should idle: if (distanceFromCat > MouseEvadeDistance + MouseHysteresis) { mouseState = MouseAiState.Wander; } // the cat is too close; the mouse should run: else if (distanceFromCat < MouseEvadeDistance - MouseHysteresis) { mouseState = MouseAiState.Evading; } // if neither of those if blocks hit, we are in the "hysteresis" range, // and the mouse will continue doing whatever it is doing now. // the mouse will move at a different speed depending on what state it // is in. when idle it won't move at full speed, but when actively evading // it will move as fast as it can. this variable is used to track which // speed the mouse should be moving. float currentMouseSpeed; // the second step of the Update is to change the mouse's orientation based // on its current state. if (mouseState == MouseAiState.Evading) { // If the mouse is "active," it is trying to evade the cat. The evasion // behavior is accomplished by using the TurnToFace function to turn // towards a point on a straight line facing away from the cat. In other // words, if the cat is point A, and the mouse is point B, the "seek // point" is C. // C // B // A Vector2 seekPosition = 2 * mousePosition - catPosition; // Use the TurnToFace function, which we introduced in the AI Series 1: // Aiming sample, to turn the mouse towards the seekPosition. Now when // the mouse moves forward, it'll be trying to move in a straight line // away from the cat. mouseOrientation = ChaseAndEvadeGame.TurnToFace(mousePosition, seekPosition, mouseOrientation, MouseTurnSpeed); // set currentMouseSpeed to MaxMouseSpeed - the mouse should run as fast // as it can. currentMouseSpeed = MaxMouseSpeed; } else { // if the mouse isn't trying to evade the cat, it should just meander // around the screen. we'll use the Wander function, which the mouse and // tank share, to accomplish this. mouseWanderDirection and // mouseOrientation are passed by ref so that the wander function can // modify them. for more information on ref parameters, see // http://msdn2.microsoft.com/en-us/library/14akc2c7(VS.80).aspx ChaseAndEvadeGame.Wander(mousePosition, ref mouseWanderDirection, ref mouseOrientation, MouseTurnSpeed); // if the mouse is wandering, it should only move at 25% of its maximum // speed. currentMouseSpeed = .25f * MaxMouseSpeed; Vector2 separate = Vector2.Zero; Vector2 moveCloser = Vector2.Zero; Vector2 moveAligned = Vector2.Zero; // What the AI does when it sees other AIs for (int j = 0; j < enemies; j++) { if (index != j) { // Calculate a vector towards another AI Vector2 separation = mice[index].mousePosition - mice[j].mousePosition; // Only react if other AI is within a certain distance if ((separation.Length() < this.sensorDistance) & (separation.Length()> 0) ) { moveAligned += mice[j].mouseWanderDirection; float distance = Math.Abs(separation.Length()); if (distance == 0) distance = 1; moveCloser += mice[j].mousePosition; separation.Normalize(); separate += separation / distance; } } } if (moveAligned.LengthSquared() != 0) { moveAligned.Normalize(); } if (moveCloser.LengthSquared() != 0) { moveCloser.Normalize(); } moveCloser /= enemies; mice[index].mousePosition += (separate * separationImpact) + (moveCloser * cohesionImpact) + (moveAligned * alignmentImpact); } // The final step is to move the mouse forward based on its current // orientation. First, we construct a "heading" vector from the orientation // angle. To do this, we'll use Cosine and Sine to tell us the x and y // components of the heading vector. See the accompanying doc for more // information. Vector2 heading = new Vector2( (float)Math.Cos(mouseOrientation), (float)Math.Sin(mouseOrientation)); // by multiplying the heading and speed, we can get a velocity vector. the // velocity vector is then added to the mouse's current position, moving him // forward. mousePosition += heading * currentMouseSpeed; } } }

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  • What are some good game development programs for kids?

    - by John Giotta
    I know a very bright little boy who excels in math, but at home he's glued to his Nintendo DS. When I asked him what he wanted to do when he grew up he said "Make video games!" I remember a few years there was mention of a MIT software called Scratch and thought maybe this kid can do want he wants to do. Has anyone used any of the "game development" for kids softwares out there? Can you recommend any?

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  • Are there any jobs for software developers with a BA and no previous employment? [closed]

    - by IDWMaster
    Are there any careers available for developers who have never been employed before in the industry, and who have a BA, rather than a BS in computer science? I'm currently pursuing a BS in computer science but realized that the math is too difficult for me. Someone suggested switching to a BA instead but I have not been able to find any jobs in my state (Minnesota) which take a BA. I was wondering if a BA is worth pursuing if I cannot get a BS.

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  • How do I create a bounding frustrum from a view & projection matrix?

    - by Narf the Mouse
    Given a left-handed Projection matrix, a left-handed View matrix, a ViewProj matrix of View * Projection - How do I create a bounding Frustum comprised of near, far, left, right and top, bottom planes? The only example I could find on Google (Tutorial 16: Frustum Culling) seems to not work; for example, if the math is used as given, the near-plane's distance is a negative. This places the near-plane behind the camera...

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  • With AMD style modules in JavaScript is there any benefit to namespaces?

    - by gman
    Coming from C++ originally and seeing lots of Java programmers doing the same we brought namespaces to JavaScript. See Google's closure library as an example where they have a main namespace, goog and under that many more namespaces like goog.async, goog.graphics But now, having learned the AMD style of requiring modules it seems like namespaces are kind of pointless in JavaScript. Not only pointless but even arguably an anti-pattern. What is AMD? It's a way of defining and including modules that removes all direct dependencies. Effectively you do this // some/module.js define([ 'name/of/needed/module', 'name/of/someother/needed/module', ], function( RefToNeededModule, RefToSomeOtherNeededModule) { ...code... return object or function }); This format lets the AMD support code know that this module needs name/of/needed/module.js and name/of/someother/needed/module.js loaded. The AMD code can load all the modules and then, assuming no circular dependencies, call the define function on each module in the correct order, record the object/function returned by the module as it calls them, and then call any other modules' define function with references to those modules. This seems to remove any need for namespaces. In your own code you can call the reference to any other module anything you want. For example if you had 2 string libraries, even if they define similar functions, as long as they follow the AMD pattern you can easily use both in the same module. No need for namespaces to solve that. It also means there's no hard coded dependencies. For example in Google's closure any module could directly reference another module with something like var value = goog.math.someMathFunc(otherValue) and if you're unlucky it will magically work where as with AMD style you'd have to explicitly include the math library otherwise the module wouldn't have a reference to it since there are no globals with AMD. On top of that dependency injection for testing becomes easy. None of the code in the AMD module references things by namespace so there is no hardcoded namespace paths, you can easily mock classes at testing time. Is there any other point to namespaces or is that something that C++ / Java programmers are bringing to JavaScript that arguably doesn't really belong?

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  • Should I go back to college and graduate with a poor GPA or try to jump into an entry-level development position? [closed]

    - by jshin47
    I once attended a top-10 American university but I am currently not in school for several different reasons. Chief among them is that I did very poorly two semesters and even failed one of them (got two F's) which put me in automatic suspension. My major is not CS but math. I am in a pickle at the moment. After I was suspended I got a job at a niche IT company in the area. I am employed as something of an IT generalist; my primary responsibilities are Windows systems administration/networking but I also do some Android, iOS, and .NET development. I have released a few apps to the app store under my name and my company's name, and we have done work for a few big clients. I started working at my job about 1.5 years ago and I am somewhat happily employed but I do not see it as a long-term fit because it is a small company with little opportunity to advance. I would like to move out to California and particularly to the Bay Area to get a job at a more reputable or exciting company, even at a lower rate of pay, but I am not sure if I should do that or try to go back to school. If I went back to school, it would take 1-1.5 years to graduate and some $. Best case scenario I would graduate with a 2.9 or 3.0 GPA. It is a top-10 school, but that's a crappy GPA. If I do not go back to school, I will be a field where most people have degrees, without a degree. If anything goes wrong I could be really screwed as I feel I will get no respect without a degree. On the other hand I really would like to get started in the field and get more serious about developing good development practices, learning new languages/frameworks, and working with people who know a lot more than I so I can learn and grow as a developer and eventually do my own thing. Basically, I am wondering: Should I just go back to school? How much does the bad GPA / good school reputation weigh in? What about the fact that I am a Math major and not a CS major (have never taken a CS course)? Does my skill set as something of a generalist bode well for me finding work at a start up in the Bay Area? If not (2), should I hunker down and focus on producing a really good (or a few medicore) iOS apps? Android apps? etc... How would you look at someone who did great in HS, kind of goofed off in college and eventually quit, and got into development? Thanks for any thoughts or input.

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  • 2D camera perspective projection from 3D coordinates -- HOW?

    - by Jack
    I am developing a camera for a 2D game with a top-down view that has depth. It's almost a 3D camera. Basically, every object has a Z even though it is in 2D, and similarly to parallax layers their position, scale and rotation speed vary based on their Z. I guess this would be a perspective projection. But I am having trouble converting the objects' 3D coordinates into the 2D space of the screen so that everything has correct perspective and scale. I never learned matrices though I did dig the topic a bit today. I tried without using matrices thanks to this article but every attempt gave awkward results. I'm using ActionScript 3 and Flash 11+ (Starling), where the screen coordinates work like this: Left-handed coordinates system illustration I can explain further what I did if you want to help me sort out what's wrong, or you can directly tell me how you would do it properly. In case you prefer the former, read on. These are images showing the formulas I used: upload.wikimedia.org/math/1/c/8/1c89722619b756d05adb4ea38ee6f62b.png upload.wikimedia.org/math/d/4/0/d4069770c68cb8f1aa4b5cfc57e81bc3.png (Sorry new users can't post images, but both are from the wikipedia article linked above, section "Perspective projection". That's where you'll find what all variables mean, too) The long formula is greatly simplified because I believe a normal top-down 2D camera has no X/Y/Z rotation values (correct ?). Then it becomes d = a - c. Still, I can't get it to work. Maybe you could explain what numbers I should put in a(xyz), c(xyz), theta(xyz), and particularly, e(xyz) ? I don't quite get how e is different than c in my case. c.z is also an issue to me. If the Z of the camera's target object is 0, should the camera's Z be something like -600 ? ( = focal length of 600) Whatever I do, it's wrong. I only got it to work when I used arbitrary calculations that "looked" right, like most cameras with parallax layers seem to do, but that's fake! ;) If I want objects to travel between Z layers I might as well do it right. :) Thanks a lot for your help!

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  • What library for octrees or kd-trees?

    - by Will
    Are there any robust performant libraries for indexing objects? It would need frustum culling and visiting objects hit by a ray as well as neighbourhood searches. I can find lots of articles showing the math for the component parts, often as algebra rather than simple C, but nothing that puts it all together (apart from perhaps Ogre, which has rather more involved and isn't so stand-alone). Surely hobby game makers don't all have to make their own octrees? (Python or C/C++ w/bindings preferred)

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  • career planning advice [closed]

    - by JDB
    Possible Duplicate: Are certifications worth it? I am at the point in my career where people start to veer off into either management-type roles or they focus on solidifying their technical skills to stay in the development game for the long-haul. Here's my story: I've got a degree in economics, an MA in Political Science and an MBA in Finance and Management. In addition, I've done coursework in advanced math and software development (although no degree in math or software). All-in-all, I've got 13 years of post-secondary education under my belt. I, however, currently work as a software developer using C# for desktop, Silverlight, Flex and javascript for web, and objective c for mobile. I've been in software development for the past 3.3 years, and it seems like it comes pretty easy to me. I work in a field called "geospatial information systems," which just involves customization and manipulation of geospatial data. Right now I am looking at one of several certifications. Given this background, which of these certifications has the highest ceiling? CFA PMP various development/technological certifications from Microsoft, etc. Other? My academic and work experience are all heavy on the analytical/development side, esp. so given the MBA and the B.S. in Econ. The political science degree was really a lot of stats. So it seems that I would be good pursuing more of the CFA/analytical role. This is a difficult path, however, because I have no work experience in the financial sector, and the developers in finance are all "quants," which again, I am OK with, but I haven't done much statistical modeling in the past 3.3 years. The PMP would require knowledge of best practices as it pertains explicitly to software development. I also don't enjoy a lot of business travel, a common theme for most PMP jobs I've seen. If certifications is the route, which would you recommend? Anything else? I've thought about going back to try to knock out a B.S. in C.S., but I wasn't sure how long that would take, or what would be involved. Thoughts or recommendations? Thanks in advance! I turn 32 this weekend, which is what has forced me to think about these issues.

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  • Could someone explain in detail simplex /or perlin noise?

    - by Ryan Szemplinski
    I am really interested in perlin/simplex noise but I am having a difficult time understanding it. I am not very good at math but I am willing to learn because it interests me greatly. If someone is willing to dedicate there time into this I would be immensely appreciative of this. To be more concise, an explanation of functions and some calculation inside the functions would be nice to understand. Thanks in advance!

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  • Per-pixel collision detection - why does XNA transform matrix return NaN when adding scaling?

    - by JasperS
    I looked at the TransformCollision sample on MSDN and added the Matrix.CreateTranslation part to a property in my collision detection code but I wanted to add scaling. The code works fine when I leave scaling commented out but when I add it and then do a Matrix.Invert() on the created translation matrix the result is NaN ({NaN,NaN,NaN},{NaN,NaN,NaN},...) Can anyone tell me why this is happening please? Here's the code from the sample: // Build the block's transform Matrix blockTransform = Matrix.CreateTranslation(new Vector3(-blockOrigin, 0.0f)) * // Matrix.CreateScale(block.Scale) * would go here Matrix.CreateRotationZ(blocks[i].Rotation) * Matrix.CreateTranslation(new Vector3(blocks[i].Position, 0.0f)); public static bool IntersectPixels( Matrix transformA, int widthA, int heightA, Color[] dataA, Matrix transformB, int widthB, int heightB, Color[] dataB) { // Calculate a matrix which transforms from A's local space into // world space and then into B's local space Matrix transformAToB = transformA * Matrix.Invert(transformB); // When a point moves in A's local space, it moves in B's local space with a // fixed direction and distance proportional to the movement in A. // This algorithm steps through A one pixel at a time along A's X and Y axes // Calculate the analogous steps in B: Vector2 stepX = Vector2.TransformNormal(Vector2.UnitX, transformAToB); Vector2 stepY = Vector2.TransformNormal(Vector2.UnitY, transformAToB); // Calculate the top left corner of A in B's local space // This variable will be reused to keep track of the start of each row Vector2 yPosInB = Vector2.Transform(Vector2.Zero, transformAToB); // For each row of pixels in A for (int yA = 0; yA < heightA; yA++) { // Start at the beginning of the row Vector2 posInB = yPosInB; // For each pixel in this row for (int xA = 0; xA < widthA; xA++) { // Round to the nearest pixel int xB = (int)Math.Round(posInB.X); int yB = (int)Math.Round(posInB.Y); // If the pixel lies within the bounds of B if (0 <= xB && xB < widthB && 0 <= yB && yB < heightB) { // Get the colors of the overlapping pixels Color colorA = dataA[xA + yA * widthA]; Color colorB = dataB[xB + yB * widthB]; // If both pixels are not completely transparent, if (colorA.A != 0 && colorB.A != 0) { // then an intersection has been found return true; } } // Move to the next pixel in the row posInB += stepX; } // Move to the next row yPosInB += stepY; } // No intersection found return false; }

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  • "static" as a semantic clue about statelessness?

    - by leoger
    this might be a little philosophical but I hope someone can help me find a good way to think about this. I've recently undertaken a refactoring of a medium sized project in Java to go back and add unit tests. When I realized what a pain it was to mock singletons and statics, I finally "got" what I've been reading about them all this time. (I'm one of those people that needs to learn from experience. Oh well.) So, now that I'm using Spring to create the objects and wire them around, I'm getting rid of static keywords left and right. (If I could potentially want to mock it, it's not really static in the same sense that Math.abs() is, right?) The thing is, I had gotten into the habit of using static to denote that a method didn't rely on any object state. For example: //Before import com.thirdparty.ThirdPartyLibrary.Thingy; public class ThirdPartyLibraryWrapper { public static Thingy newThingy(InputType input) { new Thingy.Builder().withInput(input).alwaysFrobnicate().build(); } } //called as... ThirdPartyLibraryWrapper.newThingy(input); //After public class ThirdPartyFactory { public Thingy newThingy(InputType input) { new Thingy.Builder().withInput(input).alwaysFrobnicate().build(); } } //called as... thirdPartyFactoryInstance.newThingy(input); So, here's where it gets touchy-feely. I liked the old way because the capital letter told me that, just like Math.sin(x), ThirdPartyLibraryWrapper.newThingy(x) did the same thing the same way every time. There's no object state to change how the object does what I'm asking it to do. Here are some possible answers I'm considering. Nobody else feels this way so there's something wrong with me. Maybe I just haven't really internalized the OO way of doing things! Maybe I'm writing in Java but thinking in FORTRAN or somesuch. (Which would be impressive since I've never written FORTRAN.) Maybe I'm using staticness as a sort of proxy for immutability for the purposes of reasoning about code. That being said, what clues should I have in my code for someone coming along to maintain it to know what's stateful and what's not? Perhaps this should just come for free if I choose good object metaphors? e.g. thingyWrapper doesn't sound like it has state indepdent of the wrapped Thingy which may itself be mutable. Similarly, a thingyFactory sounds like it should be immutable but could have different strategies that are chosen among at creation. I hope I've been clear and thanks in advance for your advice!

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  • Accessing your web server via IPv6

    Being able to run your systems on IPv6, have automatic address assignment and the ability to resolve host names are the necessary building blocks in your IPv6 network infrastructure. Now, that everything is in place it is about time that we are going to enable another service to respond to IPv6 requests. The following article will guide through the steps on how to enable Apache2 httpd to listen and respond to incoming IPv6 requests. This is the fourth article in a series on IPv6 configuration: Configure IPv6 on your Linux system DHCPv6: Provide IPv6 information in your local network Enabling DNS for IPv6 infrastructure Accessing your web server via IPv6 Piece of advice: This is based on my findings on the internet while reading other people's helpful articles and going through a couple of man-pages on my local system. Surfing the web - IPv6 style Enabling IPv6 connections in Apache 2 is fairly simply. But first let's check whether your system has a running instance of Apache2 or not. You can check this like so: $ service apache2 status Apache2 is running (pid 2680). In case that you got a 'service unknown' you have to install Apache to proceed with the following steps: $ sudo apt-get install apache2 Out of the box, Apache binds to all your available network interfaces and listens to TCP port 80. To check this, run the following command: $ sudo netstat -lnptu | grep "apache2\W*$"tcp6       0      0 :::80                   :::*                    LISTEN      28306/apache2 In this case Apache2 is already binding to IPv6 (and implicitly to IPv4). If you only got a tcp output, then your HTTPd is not yet IPv6 enabled. Check your Listen directive, depending on your system this might be in a different location than the default in Ubuntu. $ sudo nano /etc/apache2/ports.conf # If you just change the port or add more ports here, you will likely also# have to change the VirtualHost statement in# /etc/apache2/sites-enabled/000-default# This is also true if you have upgraded from before 2.2.9-3 (i.e. from# Debian etch). See /usr/share/doc/apache2.2-common/NEWS.Debian.gz and# README.Debian.gzNameVirtualHost *:80Listen 80<IfModule mod_ssl.c>    # If you add NameVirtualHost *:443 here, you will also have to change    # the VirtualHost statement in /etc/apache2/sites-available/default-ssl    # to <VirtualHost *:443>    # Server Name Indication for SSL named virtual hosts is currently not    # supported by MSIE on Windows XP.    Listen 443</IfModule><IfModule mod_gnutls.c>    Listen 443</IfModule> Just in case that you don't have a ports.conf file, look for it like so: $ cd /etc/apache2/$ fgrep -r -i 'listen' ./* And modify the related file instead of the ports.conf. Which most probably might be either apache2.conf or httpd.conf anyways. Okay, please bear in mind that Apache can only bind once on the same interface and port. So, eventually, you might be interested to add another port which explicitly listens to IPv6 only. In that case, you would add the following in your configuration file: Listen 80Listen [2001:db8:bad:a55::2]:8080 But this is completely optional... Anyways, just to complete all steps, you save the file, and then check the syntax like so: $ sudo apache2ctl configtestSyntax OK Ok, now let's apply the modifications to our running Apache2 instances: $ sudo service apache2 reload * Reloading web server config apache2   ...done. $ sudo netstat -lnptu | grep "apache2\W*$"                                                                                               tcp6       0      0 2001:db8:bad:a55:::8080 :::*                    LISTEN      5922/apache2    tcp6       0      0 :::80                   :::*                    LISTEN      5922/apache2 There we have two daemons running and listening to different TCP ports. Now, that the basics are in place, it's time to prepare any website to respond to incoming requests on the IPv6 address. Open up any configuration file you have below your sites-enabled folder. $ ls -al /etc/apache2/sites-enabled/... $ sudo nano /etc/apache2/sites-enabled/000-default <VirtualHost *:80 [2001:db8:bad:a55::2]:8080>        ServerAdmin [email protected]        ServerName server.ios.mu        ServerAlias server Here, we have to check and modify the VirtualHost directive and enable it to respond to the IPv6 address and port our web server is listening to. Save your changes, run the configuration test and reload Apache2 in order to apply your modifications. After successful steps you can launch your favourite browser and navigate to your IPv6 enabled web server. Accessing an IPv6 address in the browser That looks like a successful surgery to me... Note: In case that you received a timeout, check whether your client is operating on IPv6, too.

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  • Rotation angle based on touch move

    - by Siddharth
    I want to rotate my stick based on the movement of the touch on the screen. From my calculation I did not able to find correct angle in degree. So please provide guidance, my code snippet for that are below. if (pSceneTouchEvent.isActionMove()) { pValueX = pSceneTouchEvent.getX(); pValueY = CAMERA_HEIGHT - pSceneTouchEvent.getY(); rotationAngle = (float) Math.atan2(pValueX, pValueY); stick.setRotation((float) MathUtils.radToDeg(rotationAngle)); }

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  • What are some good game development programs for kids?

    - by John Giotta
    I know a very bright little boy who excels in math, but at home he's glued to his Nintendo DS. When I asked him what he wanted to do when he grew up he said "Make video games!" I remember a few years there was mention of a MIT software called Scratch and thought maybe this kid can do want he wants to do. Has anyone used any of the "game development" for kids softwares out there? Can you recommend any?

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  • why there is no power operator in java / c ++?

    - by RanZilber
    While there is such operator - ** in Python , i was wondering why java and c++ havent got one too. It is easy to make one for classes you define in C++ with operator overloading ( and i believe such thing is possible also in java) , but when talking about primitive types such as int, double and so on , you'll have to use library function like Math.power (and usaully have to cast both to double). So - why not define such operator for primitive types ?

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  • Working with SQL Agent Durations

    SQL Agent stores duration in HHMMSS format - not always useful. Discover how to use Powershell, some basic math, and T-SQL to tame these unruly values. Learn Agile Database Development Best PracticesAgile database development experts Sebastian Meine and Dennis Lloyd are running day-long classes designed to complement Red Gate’s SQL in the City US tour. Classes will be held in San Francisco, Chicago, Boston and Seattle. Register Now.

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  • Andengine. Put bullet to pool, when it leaves screen

    - by Ashot
    i'm creating a bullet with physics body. Bullet class (extends Sprite class) has die() method, which unregister physics connector, hide sprite and put it in pool public void die() { Log.d("bulletDie", "See you in hell!"); if (this.isVisible()) { this.setVisible(false); mPhysicsWorld.unregisterPhysicsConnector(physicsConnector); physicsConnector.setUpdatePosition(false); body.setActive(false); this.setIgnoreUpdate(true); bulletsPool.recyclePoolItem(this); } } in onUpdate method of PhysicsConnector i executes die method, when sprite leaves screen physicsConnector = new PhysicsConnector(this,body,true,false) { @Override public void onUpdate(final float pSecondsElapsed) { super.onUpdate(pSecondsElapsed); if (!camera.isRectangularShapeVisible(_bullet)) { Log.d("bulletDie","Dead?"); _bullet.die(); } } }; it works as i expected, but _bullet.die() executes TWICE. what i`m doing wrong and is it right way to hide sprites? here is full code of Bullet class (it is inner class of class that represents player) private class Bullet extends Sprite implements PhysicsConstants { private final Body body; private final PhysicsConnector physicsConnector; private final Bullet _bullet; private int id; public Bullet(float x, float y, ITextureRegion texture, VertexBufferObjectManager vertexBufferObjectManager) { super(x,y,texture,vertexBufferObjectManager); _bullet = this; id = bulletId++; body = PhysicsFactory.createCircleBody(mPhysicsWorld, this, BodyDef.BodyType.DynamicBody, bulletFixture); physicsConnector = new PhysicsConnector(this,body,true,false) { @Override public void onUpdate(final float pSecondsElapsed) { super.onUpdate(pSecondsElapsed); if (!camera.isRectangularShapeVisible(_bullet)) { Log.d("bulletDie","Dead?"); Log.d("bulletDie",id+""); _bullet.die(); } } }; mPhysicsWorld.registerPhysicsConnector(physicsConnector); $this.getParent().attachChild(this); } public void reset() { final float angle = canon.getRotation(); final float x = (float) ((Math.cos(MathUtils.degToRad(angle))*radius) + centerX) / PIXEL_TO_METER_RATIO_DEFAULT; final float y = (float) ((Math.sin(MathUtils.degToRad(angle))*radius) + centerY) / PIXEL_TO_METER_RATIO_DEFAULT; this.setVisible(true); this.setIgnoreUpdate(false); body.setActive(true); mPhysicsWorld.registerPhysicsConnector(physicsConnector); body.setTransform(new Vector2(x,y),0); } public Body getBody() { return body; } public void setLinearVelocity(Vector2 velocity) { body.setLinearVelocity(velocity); } public void die() { Log.d("bulletDie", "See you in hell!"); if (this.isVisible()) { this.setVisible(false); mPhysicsWorld.unregisterPhysicsConnector(physicsConnector); physicsConnector.setUpdatePosition(false); body.setActive(false); this.setIgnoreUpdate(true); bulletsPool.recyclePoolItem(this); } } }

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  • Review: 6 Advanced OpenOffice.org Extensions

    The open source OpenOffice productivity suite is a cross-platform powerhouse, and you can can add additional functionality by installing extensions. Eric Geier offers six OpenOffice extensions for analyzing readability, special text effects, advanced math functions, and more.

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  • How to calculate direction from initial point and another point?

    - by Dvole
    I'm making a simple game where I shoot things from a certain point on screen (A). I tap the screen and shoot the projectile from initial point(A) to the tap point(B). But I want the projectile to move along the same path instead and fly out of bounds of the screen. How do I calculate a point that is on the same line that these two points, but further away? This is a simple math, but I can't figure it out.

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