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  • How to set up a specific registration on Database

    - by ymorenz
    I'm creating a database so I can access names of people from a university. But I would like to create a registration ID for each person like 1012607, of which the first 2 numbers would be the year (11 for 2011) and the third digit would be the semester they registered (1 in the beginning of the year and 2 in the end of the year). The other 4 digits would be incremental. I don't know how to code a prefixed number in MySQL that can change only the last 4 digits and after a year change the first 2 digits every time you have a new registration. Can someone please help me?

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  • SQL - Query to display average as either "longer than" or "shorter than"

    - by user1840801
    Here are the tables I've created: CREATE TABLE Plane_new (Pnum char(3), Feature varchar2(20), Ptype varchar2(15), primary key (Pnum)); CREATE TABLE Employee_new (eid char(3), ename varchar(10), salary number(7,2), mid char(3), PRIMARY KEY (eid), FOREIGN KEY (mid) REFERENCES Employee_new); CREATE TABLE Pilot_new (eid char(3), Licence char(9), primary key (eid), foreign key (eid) references Employee_new on delete cascade); CREATE TABLE FlightI_new (Fnum char(4), Fdate date, Duration number(2), Pid char(3), Pnum char(3), primary key (Fnum), foreign key (Pid) references Pilot_new (eid), foreign key (Pnum) references Plane_new); And here is the query I must complete: For each flight, display its number, the name of the pilot who implemented the flight and the words ‘Longer than average’ if the flight duration was longer than average or the words ‘Shorter than average’ if the flight duration was shorter than or equal to the average. For the column holding the words ‘Longer than average’ or ‘Shorter than average’ make a header Length. Here is what I've come up with - with no luck! SELECT F.Fnum, E.ename, CASE Length WHEN F.Duration>(SELECT AVG(F.Duration) FROM FlightI_new F) THEN "Longer than average" WHEN F.Duration<=(SELECT AVG(F.Duration) FROM FlightI_new F) THEN 'Shorter than average' END FROM FlightI_new F LEFT OUTER JOIN Employee_new E ON F.Pid=E.eid GROUP BY F.Fnum, E.ename; Where am I going wrong?

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  • Which of these queries is more efficient?

    - by Brian
    Which of these queries are more efficient? select 1 as newAndClosed from sysibm.sysdummy1 where exists ( select 1 from items where new = 1 ) and not exists ( select 1 from status where open = 1 ) select 1 as newAndClosed from items where new = 1 and not exists ( select 1 from status where open = 1 )

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  • MySQLi - Should every statement be prepared?

    - by Kerry
    I know its supposed to improve performance and clean strings, but lets say there are no variables? Might just be a SELECT COUNT( `column` ) AS count FROM `table` Should that be prepared? Is there any case that a SELECT statement should not be prepared?

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  • PHP - Get value of imput box, without a form?

    - by Dodi300
    Hello. Does anyone know how I can get the value of an imput box, without having a form? I want a sumbit button, but instead of submiting a form, I want it to change data in a MySQL database. Something like this maybe? $img1="WHAT DO I PUT HERE?" $idx=1 $sql="INSERT INTO games SET img1='$img1' WHERE id=$idx"; $result=mysql_query($sql); Could I use that code on a "onclick" event? The imput box is named "img1". Thanks for the help!

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  • Updating multiple rows with an array

    - by Copephobia
    I have a table that holds user information. One of the columns holds the position of the user in the game they are in. When a game is being created, I need to update the positions of the users of each team. Here is an example: Game id : 7 Team 1 users : 1,2 Team 2 users : 3,4 team1_position : array(1,2) team2_position : array(13,14) What I want to do is update the user table using the array of positions in the SET area. My goal is to be able to update the users without the need for their id (I have different size game boards, so I have multiple position arrays for each board size) How can I do something like this: UPDATE user SET position='(team1_position)' WHERE game = '7' AND team = '1' I feel like it would be a waste of resources to select all the id's of each team and update them separately.

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  • SELECT * , COUNT( * ) FROM GROUP BY ORDER BY DESC

    - by quanganh_developer
    I have a table like: gold gold_city | gold_type | gold_selltime ------------------------------------- city1 | type 1 | 2012-01-01 city1 | type 1 | 2012-02-02 city1 | type 1 | 2012-03-03 city2 | type 2 | 2012-01-01 city2 | type 2 | 2012-02-02 city2 | type 2 | 2012-03-03 city3 | type 3 | 2012-01-01 city3 | type 3 | 2012-02-02 city3 | type 3 | 2012-03-03 How can I get 1 last result order by gold_selltime desc each group by gold_city and gold_type I used this: SELECT * , COUNT( * ) FROM gold_2012 GROUP BY gold_type , gold_city ORDER BY gold_selltime DESC but it did work. I only have result like: gold_city | gold_type | gold_selltime ------------------------------------- city1 | type 1 | 2012-01-01 city2 | type 2 | 2012-01-01 city3 | type 3 | 2012-01-01 but I need it like: gold_city | gold_type | gold_selltime ------------------------------------- city1 | type 1 | 2012-03-03 city2 | type 2 | 2012-03-03 city3 | type 3 | 2012-03-03

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  • LOAD DATA LOCAL INFILE custom value

    - by NR03
    How to add a custom value using LOAD DATA LOCAL INFILE? The column time_added is the 7th column and the file has only 2 values for the first and the second column. For the 7th column, time_added I want to use the unix timestamp when loading from file. This code isn't working: $result = mysql_query("LOAD DATA LOCAL INFILE '{$myFile}' INTO TABLE {$table} FIELDS TERMINATED BY ':' LINES TERMINATED BY '\n' SET `time_added`=unix_timestamp()");

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  • Help optimizing a query with 16 subqueries

    - by Webnet
    I have indexes/primaries on all appropriate ID fields for each type. I'm wondering though how I could make this more efficient. It takes a while to load the page with only 15,000 rows and that'll quickly grow to 500k. The $whereSql variable simply has a few more parameters for the main ebay_archive_listing table. NOTE: This is all done in a single query because I have ASC/DESC sorting for each subquery value. NOTE: I've converted some of the sub queries to INNER JOIN's SELECT product_master.product_id, ( SELECT COUNT(listing_id) FROM ebay_archive_product_listing_assoc '.$listingCountJoin.' WHERE ebay_archive_product_listing_assoc.product_id = product_master.product_id) as listing_count, sku, type_id, ( SELECT AVG(ebay_archive_listing.current_price) FROM ebay_archive_listing INNER JOIN ebay_archive_product_listing_assoc ON ( ebay_archive_product_listing_assoc.listing_id = ebay_archive_listing.id AND ebay_archive_product_listing_assoc.product_id = product_master.product_id ) WHERE '.$whereSql.' AND ebay_archive_listing.current_price > 0 ) as average_bid_price, ( SELECT AVG(ebay_archive_listing.buy_it_now_price) FROM ebay_archive_listing INNER JOIN ebay_archive_product_listing_assoc ON ( ebay_archive_product_listing_assoc.listing_id = ebay_archive_listing.id AND ebay_archive_product_listing_assoc.product_id = product_master.product_id ) WHERE '.$whereSql.' AND ebay_archive_listing.buy_it_now_price > 0 ) as average_buyout_price, ( SELECT MIN(ebay_archive_listing.current_price) FROM ebay_archive_listing INNER JOIN ebay_archive_product_listing_assoc ON ( ebay_archive_product_listing_assoc.listing_id = ebay_archive_listing.id AND ebay_archive_product_listing_assoc.product_id = product_master.product_id ) WHERE '.$whereSql.' AND ebay_archive_listing.current_price > 0 ) as lowest_bid_price, ( SELECT MAX(ebay_archive_listing.current_price) FROM ebay_archive_listing INNER JOIN ebay_archive_product_listing_assoc ON ( ebay_archive_product_listing_assoc.listing_id = ebay_archive_listing.id AND ebay_archive_product_listing_assoc.product_id = product_master.product_id ) WHERE '.$whereSql.' AND ebay_archive_listing.current_price > 0 ) as highest_bid_price, ( SELECT MIN(ebay_archive_listing.buy_it_now_price) FROM ebay_archive_listing INNER JOIN ebay_archive_product_listing_assoc ON ( ebay_archive_product_listing_assoc.listing_id = ebay_archive_listing.id AND ebay_archive_product_listing_assoc.product_id = product_master.product_id ) WHERE '.$whereSql.' AND ebay_archive_listing.current_price > 0 ) as lowest_buyout_price, ( SELECT MAX(ebay_archive_listing.buy_it_now_price) FROM ebay_archive_listing INNER JOIN ebay_archive_product_listing_assoc ON ( ebay_archive_product_listing_assoc.listing_id = ebay_archive_listing.id AND ebay_archive_product_listing_assoc.product_id = product_master.product_id ) WHERE '.$whereSql.' AND ebay_archive_listing.current_price > 0 ) as highest_buyout_price, round((( SELECT COUNT(ebay_archive_listing.id) FROM ebay_archive_listing INNER JOIN ebay_archive_product_listing_assoc ON ( ebay_archive_product_listing_assoc.listing_id = ebay_archive_listing.id AND ebay_archive_product_listing_assoc.product_id = product_master.product_id ) WHERE '.$whereSql.' AND ebay_archive_listing.status_id = 2 ) / ( SELECT COUNT(listing_id) FROM ebay_archive_product_listing_assoc '.$listingCountJoin.' WHERE ebay_archive_product_listing_assoc.product_id = product_master.product_id ) * 100), 1) as sold_percent FROM product_master '.$joinSql.' WHERE product_master.product_id IN ( SELECT product_id FROM ebay_archive_product_listing_assoc INNER JOIN ebay_archive_listing ON ( ebay_archive_listing.id = ebay_archive_product_listing_assoc.listing_id AND '.$whereSql.' ) )

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  • Android-SQLite: How to Count specific value from Column?

    - by sanpatil
    I have two table (TABLE_EXAM,TABLE_RESULT). Here is value of my TABLE_RESULT. result_id exam_id question_id correct_answer 1 2 4 y 2 2 5 y 3 2 6 n 4 2 7 y I need to count how many correct_answer='y' where exam_id=2. I try following code but it return 0. public int calculateResult(int examId,String confirmAnswer) { int correctAnswer=0; try { SQLiteDatabase db=this.getWritableDatabase(); String selectQuery=("select count(correctAnswer) from result where exam_id ='" + examId + "' and correctAnswer ='" + 'y' +"'" ); // String selectQuery=("SELECT COUNT(*)FROM result WHERE exam_id ='" + examId + "' and correctAnswer ='" + confirmAnswer +"'" ); Cursor cursor = db.rawQuery(selectQuery, null); if(cursor.moveToLast()) { correctAnswer=cursor.getInt(3); } } catch(Exception e) { e.printStackTrace(); } return correctAnswer; } In variable confirm_answer i pass "y". Give me some hint or reference. Any help is appreciated. Thanks in Advance

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  • Show the specific field on mysql table based on active date

    - by mrjimoy_05
    Suppose that I have 3 tables: A) Table UsrHeader ----------------- UsrID | UsrName ----------------- 1 | Abc 2 | Bcd B) Table UsrDetail ------------------------------- UsrID | UsrLoc | Date ------------------------------- 1 | LocA | 10 Aug 2012 1 | LocB | 15 Aug 2012 2 | LocA | 10 Aug 2012 C) Table Trx ----------------------------- TrxID | TrxDate | UsrID ----------------------------- 1 | 10 Aug 2012 | 1 2 | 16 Aug 2012 | 1 3 | 11 Aug 2012 | 2 What I want to do is to show the table like: --------------------------------------- TrxID | TrxDate | UsrID | UsrLoc --------------------------------------- 1 | 10 Aug 2012 | 1 | LocA 2 | 16 Aug 2012 | 1 | LocB 3 | 11 Aug 2012 | 2 | LocA Notice that there is one user but different location. That's based on the UsrDetail table that the user on a specified date has moved to another location. So, it should be show the user specific location on that date on every transaction. I have try this code but it is no luck: SELECT trx.TrxID, trx.TrxDate, trx.UsrID, User.UsrName, User.UsrLoc FROM trx INNER JOIN ( SELECT UsrHeader.UsrID, UsrHeader.UsrName, UserDetail.UsrLoc FROM UsrHeader INNER JOIN ( SELECT UsrDetail.UsrID, UsrDetail.UsrLoc, UsrDetail.Date FROM UsrDetail ) AS UserDetail ON UserDetail.UsrID = UsrHeader.UsrID ) AS User ON User.UsrID = trx.UsrID AND trx.TrxDate >= User.Date How to do that? Thanks..

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  • Problem with RewriteCond %{QUERY_STRING}, backreference not dispaying in final URL

    - by eb_Dev
    Hi, I have the following in my .htaccess file: RewriteCond %{QUERY_STRING} ^route\=product\/category\&path\=35\&page\=([0-9]+)$ RewriteRule ^index.php$ http://%{HTTP_HOST}/product/category/35/page_$1? [R=301,L] It's not behaving as expected though, when I enter the URL: http://mywebsite.com/index.php?route=product/category&path=35&page=2 It gets rewritten to: http://mywebsite.com/product/category/35/page_ Could someone tell me what I have done wrong please? Thanks, eb_dev

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  • mysql select when matching multiple rows

    - by user1735943
    I have a project where I need to select only the users that answered to some questions in a certain way (based on a filter). The filter table (filter) looks like this question | answer Q1 | A Q2 | B The user table (answers) looks like this user | question | answer 1 | Q1 | A 1 | Q2 | D 2 | Q1 | A 2 | Q2 | B How can I select from the user table only the user(s) that match the filter? I tried "SELECT user FROM answers WHERE (question = Q1 AND answer = A) AND (question = Q2 AND answer = B)" and it doesn't work -- I get an empty result. Thank you.

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  • Fix Corrupted Ruby in Mac OS X Lion

    - by luckyb56
    I screwed up my ruby buy executing the command sudo easy_install pip> /usr/bin/ruby -e "$(/usr/bin/curl -fksSL https://raw.github.com/mxcl/homebrew/master/Library/Contributions/install_homebrew.rb)" It showed error: Couldn't find index page for '-e' (maybe misspelled?) No local packages or download links found for -e error: Could not find suitable distribution for Requirement.parse('-e') After that when I tried to install Brew by: /usr/bin/ruby -e "$(/usr/bin/curl -fksSL https://raw.github.com/mxcl/homebrew/master/Library/Contributions/install_homebrew.rb)" It shows error which I have no idea: /usr/bin/ruby: line 1: Searching: command not found /usr/bin/ruby: line 2: Best: command not found /usr/bin/ruby: line 3: Processing: command not found Usage: pip COMMAND [OPTIONS] pip: error: No command by the name pip 1.1 (maybe you meant "pip install 1.1") /usr/bin/ruby: line 5: Installing: command not found /usr/bin/ruby: line 6: Installing: command not found /usr/bin/ruby: line 8: Using: command not found /usr/bin/ruby: line 9: Processing: command not found /usr/bin/ruby: line 10: Finished: command not found /usr/bin/ruby: line 11: Searching: command not found /usr/bin/ruby: line 12: Reading: command not found /usr/bin/ruby: line 13: syntax error near unexpected token `(' /usr/bin/ruby: line 13: `Scanning index of all packages (this may take a while)' Can this be fixed?

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  • Why can't execute GRUB command on Debian Squeeze 2.6 with GRUB already installed?

    - by Mikalaj
    I installed Debian Squeeze 2.6 (on a recently bought server) with a software RAID1. During installation I installed GRUB loader (1.9 version). System boots OK with GRAB loader BUT right after authorization it cannot execute GRUB command (I want to copy the GRUB from the SDA to SDB). System warning right after GRUB command invocation looks as: root@servername:~# grub -bash: grub: command not found How it could be? (GRUB already installed and no any other OS was installed at all)

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  • How to start "explorer" process using command line (Vista)?

    - by Amby
    Is there a way to start windows "explorer" process from command line? Because of some problem in my Vista OS, explorer process crashes frequently (i can not see TaskBar after that) but using the open windows i can access the cmd.exe ( ctrl+alt+delete does not work). If there could be a command to start "explorer" process again or to start the Task manager then that would help a lot. Thanks Edit: explorer command starts the explorer process, but alt+ctrl+del is still not working, any help?

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  • How can I assign the keyboard shortcut ?x to the command move to trash?

    - by Fra
    In the Finder in Leopard I used to have the command "move to trash" associated with the keyboard shortcut ?x which was very handy because you could input the command with one hand. Moreover on the keyboard x is near to c, s and a which are other shortcuts often used in Finder. Now in Lion the command "move to trash" is associated to ? ? but I don't like it. How can I assign the keyboard shortcut ?x to the command "move to trash"?

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  • How to solve "command not found" on Ubuntu bash shell?

    - by redcoder
    I am very new to Ubuntu, struggling to find the proper command to install Zend Server on my Ubuntu 9.10 Server. After downloading the ZF Server and extracting it, I try to run this command: install_zs.sh 5.3 This is the ls of the extracted ZF archive: install_zs.sh README upgrade_zs_php.sh zend.deb.repo zend.rpm.repo But it says command not found. Any idea?

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  • How can I use '{}' to redirect the output of a command run through find's -exec option?

    - by pkaeding
    I am trying to automate an svnadmin dump command for a backup script, and I want to do something like this: find /var/svn/* \( ! -name dir -prune \) -type d -exec svnadmin dump {} > {}.svn \; This seems to work, in that it looks through each svn repository in /var/svn, and runs svnadmin dump on it. However, the second {} in the exec command doesn't get substituted for the name of the directory being processed. It basically just results a single file named {}.svn. I suspect that this is because the shell interprets > to end the find command, and it tries redirecting stdout from that command to the file named {}.svn. Any ideas?

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  • How to execute a multiple line configure command using Mac OS X terminal?

    - by skiabox
    I am reading a nice article about upgrading php on mac os x mountain lion. At the Install part of the document the author says that the user must execute a multiple line configure command. What is the easiest way to do it, using mac os terminal? Thank you. PS : I have executed yesterday the configure command without the parameters. Can this action cause any problems with the re-execution of configure command (with parameters this time)?

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  • Started an application through SSH, command line now gone, what happens next?

    - by Chris Dutrow
    Context: This is a very basic question Using Putty and SSH for the first time to do some serious server setup and run into the situation where I have started a process that I do not want to stop. The process is the gunicorn WSGI HTTP Server (running on Centos 6.3). The command I used to start the process is (as per their Quick Start): gunicorn -w 4 myapp:app At this point in the work session, I have lost the command prompt. This must be such a non-issue that it doesn't even enter into an experienced user's consciousness. But unfortunately at my level of experience, I am left with several fundamental questions: Does the fact that I have lost the command prompt mean that the process is still running? How do I get back to the command prompt without killing the process? How do I come back and monitor the process later? How do I eventually kill the process? Any help is appreciated, thanks so much!

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