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  • Error in django using Apache & mod_wsgi

    - by Ignacio
    Hey, I've been doing some changes to my django develpment env, as some of you suggested. So far I've managed to configure and run it successfully with postgres. Now I'm trying to run the app using apache2 and mod_wsgi, but I ran into this little problem after I followed the guidelines from the django docs. When I access localhost/myapp/tasks this error raises: Request Method: GET Request URL: http://localhost/myapp/tasks/ Exception Type: TemplateSyntaxError Exception Value: Caught an exception while rendering: argument 1 must be a string or unicode object Original Traceback (most recent call last): File "/usr/local/lib/python2.6/dist-packages/django/template/debug.py", line 71, in render_node result = node.render(context) File "/usr/local/lib/python2.6/dist-packages/django/template/defaulttags.py", line 126, in render len_values = len(values) File "/usr/local/lib/python2.6/dist-packages/django/db/models/query.py", line 81, in __len__ self._result_cache = list(self.iterator()) File "/usr/local/lib/python2.6/dist-packages/django/db/models/query.py", line 238, in iterator for row in self.query.results_iter(): File "/usr/local/lib/python2.6/dist-packages/django/db/models/sql/query.py", line 287, in results_iter for rows in self.execute_sql(MULTI): File "/usr/local/lib/python2.6/dist-packages/django/db/models/sql/query.py", line 2369, in execute_sql cursor.execute(sql, params) File "/usr/local/lib/python2.6/dist-packages/django/db/backends/util.py", line 19, in execute return self.cursor.execute(sql, params) TypeError: argument 1 must be a string or unicode object ... ... ... And then it highlights a {% for t in tasks %} template tag, like the source of the problem is there, but it worked fine on the built-in server. The view associated with that page is really simple, just fetch all Task objects. And the template just displays them on a table. Also, some pages get rendered ok. Don't want to fill this Question with code, so if you need some more info I'd be glad to provide it. Thanks

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  • Building a formset dynamically

    - by vorpyg
    I initially wrote code to build a form dynamically, based on data from the DB, similar to what I described in my previous SO post. As SO user Daniel Roseman points out, he would use a formset for this, and now I've come to the realization that he must be completely right. :) My approach works, basically, but I can't seem to get validation across the entire form to be working properly (I believe it's possible, but it's getting quite complex, and there has to be a smarter way of doing it = Formsets!). So now my question is: How can I build a formset dynamically? Not in an AJAX way, I want each form's label to be populated with an FK value (team) from the DB. As I have a need for passing parameters to the form, I've used this technique from a previous SO post. With the former approach, my view code is (form code in previous link): def render_form(request): teams = Team.objects.filter(game=game) form_collection = [] for team in teams: f = SuggestionForm(request.POST or None, team=team, user=request.user) form_collection.append(f) Now I want to do something like: def render_form(request): teams = Team.objects.filter(game=game) from django.utils.functional import curry from django.forms.formsets import formset_factory formset = formset_factory(SuggestionForm) for team in teams: formset.form.append(staticmethod(curry(SuggestionForm, request.POST or None, team=team, user=request.user))) But the append bit doesn't work. What's the proper way of doing this? Thanks!

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  • How should I plan the inheritance structure for my game?

    - by Eric Thoma
    I am trying to write a platform shooter in C++ with a really good class structure for robustness. The game itself is secondary; it is the learning process of writing it that is primary. I am implementing an inheritance tree for all of the objects in my game, but I find myself unsure on some decisions. One specific issue that it bugging me is this: I have an Actor that is simply defined as anything in the game world. Under Actor is Character. Both of these classes are abstract. Under Character is the Philosopher, who is the main character that the user commands. Also under Character is NPC, which uses an AI module with stock routines for friendly, enemy and (maybe) neutral alignments. So under NPC I want to have three subclasses: FriendlyNPC, EnemyNPC and NeutralNPC. These classes are not abstract, and will often be subclassed in order to make different types of NPC's, like Engineer, Scientist and the most evil Programmer. Still, if I want to implement a generic NPC named Kevin, it would nice to be able to put him in without making a new class for him. I could just instantiate a FriendlyNPC and pass some values for the AI machine and for the dialogue; that would be ideal. But what if Kevin is the one benevolent Programmer in the whole world? Now we must make a class for him (but what should it be called?). Now we have a character that should inherit from Programmer (as Kevin has all the same abilities but just uses the friendly AI functions) but also should inherit from FriendlyNPC. Programmer and FriendlyNPC branched away from each other on the inheritance tree, so inheriting from both of them would have conflicts, because some of the same functions have been implemented in different ways on the two of them. 1) Is there a better way to order these classes to avoid these conflicts? Having three subclasses; Friendly, Enemy and Neutral; from each type of NPC; Engineer, Scientist, and Programmer; would amount to a huge number of classes. I would share specific implementation details, but I am writing the game slowly, piece by piece, and so I haven't implemented past Character yet. 2) Is there a place where I can learn these programming paradigms? I am already trying to take advantage of some good design patterns, like MVC architecture and Mediator objects. The whole point of this project is to write something in good style. It is difficult to tell what should become a subclass and what should become a state (i.e. Friendly boolean v. Friendly class). Having many states slows down code with if statements and makes classes long and unwieldy. On the other hand, having a class for everything isn't practical. 3) Are there good rules of thumb or resources to learn more about this? 4) Finally, where does templating come in to this? How should I coordinate templates into my class structure? I have never actually taken advantage of templating honestly, but I hear that it increases modularity, which means good code.

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  • Deploying Django at Dreamhost

    - by Imran
    I'm trying to get the Poll tutorial working at my Dreamhost account (I don't have any prior experience of deploying Django). I downloaded the script I found here (http://gabrielfalcao.com/2008/12/02/hosting-and-deploying-django-apps-on-dreamhost/) at my home directory and executed it. Now I have Python 2.5 and Django in ~/.myroot/ and my Django projects directory is ~/projects/ Here's the content of ~/projects/ directory (I copied the polls/ and and templates/polls/ directories myself). projects/ |-- admin_media -> /home/imran2140/.myroot/usr/lib/python2.5/site-packages/django/contrib/admin/media |-- dispatch.fcgi |-- polls | |-- __init__.py | |-- __init__.pyc | |-- admin.py | |-- admin.pyc | |-- models.py | |-- models.pyc | |-- polls.db | |-- urls.py | |-- urls.pyc | |-- views.py | `-- views.pyc |-- script_templates | |-- dispatch.template | `-- htaccess.template `-- templates `-- polls |-- detail.html |-- index.html `-- results.html 5 directories, 17 files Now what should I do to get the Polls app working? Update I finally got a "Hello World" Django app working with Passanger WSGI. It worked fine with both Server's default Python 2.3.5 and my installed Python 2.5.2. Passanger WSGI - Django at Dreamhost Wiki

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  • django internationalization and translations problem

    - by Zayatzz
    I have a problem with django translations. Problem 1 - i updated string in django.po file, but the change does not appear on the webpage. Problem 2 - i have created my own locale file with django-admin.py makemessages -l et, added the translation string into file, but they too do not appear on the page. I do not think this is setting problem, because the translations from django.po file do appear on the website, its just the changes and the translations from my own generated file that do not appear. Edit: My settings.py contains this: gettext = lambda s: s LANGUAGE_CODE = 'et' LANGUAGES = ( ('et', gettext('Estonian')), ) my own locale files are in /path/to/project/locale/et/LC_MESSAGES/ and the files are django.mo and django.po the file i refer to in problem 1 is django own et transaltion, which i changed.

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  • Why can't I use 'django-admin.py makemessages -l cn'

    - by zjm1126
    print : D:\zjm_code\register2>python D:\Python25\Lib\site-packages\django\bin\django-adm in.py makemessages -l cn Error: This script should be run from the Django SVN tree or your project or app tree. If you did indeed run it from the SVN checkout or your project or applica tion, maybe you are just missing the conf/locale (in the django tree) or locale (for project and application) directory? It is not created automatically, you ha ve to create it by hand if you want to enable i18n for your project or applicati on. 2.i made a locale directory ,and D:\zjm_code\register2>python D:\Python25\Lib\site-packages\django\bin\django-adm in.py makemessages -l cn processing language cn Error: errors happened while running xgettext on __init__.py 'xgettext' ?????????,????????? ??????? D:\Python25\lib\site-packages\django\core\management\base.py:234: RuntimeWarning : tp_compare didn't return -1 or -2 for exception sys.exit(1) 3. ok http://hi.baidu.com/zjm1126/blog/item/f28e09deced15353ccbf1a82.html

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  • How do I make a project in Django? Beginner

    - by ggfan
    Okay I just started with Django and it's totally different from PHP. I installed Python 2.6 and Django. Both are located in my C drive. C: Django build django docs Python26 I am doing the django site tutorial and when they say to write django-admin.py startproject mysite from my Python command line, I keep getting: Syntax error: invalid syntax >>>django-admin.py startproject mysite FILE "<stdin>", line 1 django-admin.py startproject mysite ^ My django-admin.py is in the django/bin folder. I installed Python via python setup.py. Am I suppose to use my window's CP? When I do that, I get window's can't open a .py file. I thought I was just creating a folder? How do I create a project with django? Thanks :)

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  • Question about Virtual Inheritance hierarchy

    - by Summer_More_More_Tea
    Hi there: I encounter this problem when tackling with virtual inheritance. I remember that in a non-virtual inheritance hierarchy, object of sub-class hold an object of its direct super-class. What about virtual inheritance? In this situation, does object of sub-class hold an object of its super-class directly or just hold a pointer pointing to an object of its super-class? By the way, why the output of the following code is: sizeof(A): 8 sizeof(B): 20 sizeof(C): 20 sizeof(C): 36 Code: #include <iostream> using namespace std; class A{ char k[ 3 ]; public: virtual void a(){}; }; class B : public virtual A{ char j[ 3 ]; public: virtual void b(){}; }; class C : public virtual B{ char i[ 3 ]; public: virtual void c(){}; }; class D : public B, public C{ char h[ 3 ]; public: virtual void d(){}; }; int main( int argc, char *argv[] ){ cout << "sizeof(A): " << sizeof( A ) << endl; cout << "sizeof(B): " << sizeof( B ) << endl; cout << "sizeof(C): " << sizeof( C ) << endl; cout << "sizeof(D): " << sizeof( D ) << endl; return 0; } Thanks in advance. Kind regards.

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  • WCF data services (OData), query with inheritance limitation?

    - by Mathieu Hétu
    Project: WCF Data service using internally EF4 CTP5 Code-First approach. I configured entities with inheritance (TPH). See previous question on this topic: Previous question about multiple entities- same table The mapping works well, and unit test over EF4 confirms that queries runs smoothly. My entities looks like this: ContactBase (abstract) Customer (inherits from ContactBase), this entity has also several Navigation properties toward other entities Resource (inherits from ContactBase) I have configured a discriminator, so both Customer and Resource map to the same table. Again, everythings works fine on the Ef4 point of view (unit tests all greens!) However, when exposing this DBContext over WCF Data services, I get: - CustomerBases sets exposed (Customers and Resources sets seems hidden, is it by design?) - When I query over Odata on Customers, I get this error: Navigation Properties are not supported on derived entity types. Entity Set 'ContactBases' has a instance of type 'CodeFirstNamespace.Customer', which is an derived entity type and has navigation properties. Please remove all the navigation properties from type 'CodeFirstNamespace.Customer'. Stacktrace: at System.Data.Services.Serializers.SyndicationSerializer.WriteObjectProperties(IExpandedResult expanded, Object customObject, ResourceType resourceType, Uri absoluteUri, String relativeUri, SyndicationItem item, DictionaryContent content, EpmSourcePathSegment currentSourceRoot) at System.Data.Services.Serializers.SyndicationSerializer.WriteEntryElement(IExpandedResult expanded, Object element, ResourceType expectedType, Uri absoluteUri, String relativeUri, SyndicationItem target) at System.Data.Services.Serializers.SyndicationSerializer.<DeferredFeedItems>d__b.MoveNext() at System.ServiceModel.Syndication.Atom10FeedFormatter.WriteItems(XmlWriter writer, IEnumerable`1 items, Uri feedBaseUri) at System.ServiceModel.Syndication.Atom10FeedFormatter.WriteFeedTo(XmlWriter writer, SyndicationFeed feed, Boolean isSourceFeed) at System.ServiceModel.Syndication.Atom10FeedFormatter.WriteFeed(XmlWriter writer) at System.ServiceModel.Syndication.Atom10FeedFormatter.WriteTo(XmlWriter writer) at System.Data.Services.Serializers.SyndicationSerializer.WriteTopLevelElements(IExpandedResult expanded, IEnumerator elements, Boolean hasMoved) at System.Data.Services.Serializers.Serializer.WriteRequest(IEnumerator queryResults, Boolean hasMoved) at System.Data.Services.ResponseBodyWriter.Write(Stream stream) Seems like a limitation of WCF Data services... is it? Not much documentation can be found on the web about WCF Data services (OData) and inheritance specifications. How can I overpass this exception? I need these navigation properties on derived entities, and inheritance seems the only way to provide mapping of 2 entites on the same table with Ef4 CTP5... Any thoughts?

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  • symfony + doctrine + inheritance, how to make them work?

    - by imac
    I am beginning to work with Symfony, I've found some documentation about inheritance. But also found this discouraging article, which make me doubt if Doctrine handles inheritance any good at all... Has anyone find a smart solution for inheritance in Symfony+Doctrine? As an example, I have already structured the database something like this: CREATE TABLE `poster` ( `poster_id` int(11) NOT NULL AUTO_INCREMENT, `user_name` varchar(50) NOT NULL, PRIMARY KEY (`poster_id`), UNIQUE KEY `id` (`poster_id`), ) ENGINE=InnoDB AUTO_INCREMENT=3 DEFAULT CHARSET=latin1; CREATE TABLE `user` ( `user_id` int(11) NOT NULL, `real_name` varchar(50) DEFAULT NULL, PRIMARY KEY (`user_id`), UNIQUE KEY `user_id` (`user_id`), CONSTRAINT `user_fk` FOREIGN KEY (`user_id`) REFERENCES `poster` (`poster_id`) ) ENGINE=InnoDB DEFAULT CHARSET=latin1; From that, Doctrine generated this "schema.yml": Poster: connection: doctrine tableName: poster columns: poster_id: type: integer(4) fixed: false unsigned: false primary: true autoincrement: true user_name: type: string(50) fixed: false unsigned: false primary: false notnull: true autoincrement: false relations: Post: local: poster_id foreign: poster_id type: many User: local: poster_id foreign: user_id type: many Version: local: poster_id foreign: poster_id type: many User: connection: doctrine tableName: user columns: user_id: type: integer(4) fixed: false unsigned: false primary: true autoincrement: false real_name: type: string(50) fixed: false unsigned: false primary: false notnull: false autoincrement: false relations: Poster: local: user_id foreign: poster_id type: one User creation for this structure with Doctrine auto-generated forms does not work. Any clue will be appreciated.

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  • Login and Redirect

    - by xRobot
    This is my login views: def login(request): redirect_to = request.REQUEST.get("next") if request.method == 'POST': formL = LoginForm(data=request.POST) if formL.is_valid(): if not redirect_to or '//' in redirect_to or ' ' in redirect_to: redirect_to = "/blogs/" from django.contrib.auth import login login(request, formL.get_user()) if request.session.test_cookie_worked(): request.session.delete_test_cookie() return HttpResponseRedirect(redirect_to) else: formL = LoginForm(request) request.session.set_test_cookie() return render_to_response('blogs.html', { 'formL': formL, }, context_instance=RequestContext(request)) login = never_cache(login) When I go, for example, to example.com/myblog/ then I have been redirect to example.com/accounts/login/?next=/myblog/ but when I insert user and psw for login then I have been redirect to /blogs/ and not /myblog/ Why ?

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  • Possible form field types per model field type

    - by Jonathan
    Django's documentation specifies for each model field type the corresponding default form field type. Alas, I couldn't find in the documentation, or anywhere else, what form field types are possible per model field type. Not all combinations are possible, right? Same question for widgets...

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  • Locating file path from a <InMemoryUploadedFile> Djnago object

    - by PirosB3
    Hi all I have a Django app which, submitting a package, should return values that are inside it.. Submitted the form to a view called "insert": request.FILES['file'] returns the file objects, but it is of kind < InMemoryUploadedFile. What i need is a way to get the absolute path of the uploaded file, so that i can feed it to a method that will return the values needed Anyone know how i can accomplish this? Thanks

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  • Could I use urlize filter in this way ?

    - by xRobot
    Could I use urlize filter in this way? : from django.utils.html import urlize def save(self, force_insert=False, force_update=False): self.body = urlize(self.body) super(Post, self).save(force_insert, force_update) body is a TextField.

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  • Assigning a group while adding user in django-admin

    - by Lokharkey
    In my application, I have models that have the Users model as a Foreign key, eg: class Doctor(models.Model): username=models.ForeignKey(User, unique=True) ... In the admin site, when adding a new Doctor, I have the option of adding a new User next to the username field. This is exactly what I want, but in the dialog that opens, it asks for a username and password for the new user; I would also like to be able to assign a group to this new user. What would be the best way of doing this ? Thanks, lokharkey

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  • django deleting models and overriding delete method

    - by Mike
    I have 2 models class Vhost(models.Model): dns = models.ForeignKey(DNS) user = models.ForeignKey(User) extra = models.TextField() class ApplicationInstalled(models.Model): user = models.ForeignKey(User) added = models.DateTimeField(auto_now_add=True) app = models.ForeignKey(Application) ver = models.ForeignKey(ApplicationVersion) vhost = models.ForeignKey(Vhost) path = models.CharField(max_length=100, default="/") def delete(self): # # remove the files # print "need to remove some files" super(ApplicationInstalled, self).delete() If I do the following >>> vhost = Vhost.objects.get(id=10) >>> vhost.id 10L >>> ApplicationInstalled.objects.filter(vhost=vhost) [<ApplicationInstalled: http://wiki.jy.com/>] >>> vhost.delete() >>> ApplicationInstalled.objects.filter(vhost=vhost) [] As you can see there is an applicationinstalled object linked to vhost but when I delete the vhost, the applicationinstalled object is gone but the print never gets called. Any easy way to do this without iterating through the objects in the vhost delete?

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  • Django disable editing (but allow adding) in TabularInline view

    - by VoteyDisciple
    I want to disable editing ALL objects within a particular TabularInline instance, while still allowing additions and while still allowing editing of the parent model. I have this trivial setup: class SuperviseeAdmin(admin.TabularInline): model = Supervisee class SupervisorAdmin(admin.ModelAdmin): inlines = [SuperviseeAdmin] admin.site.register(Supervisor, SupervisorAdmin) I have tried adding a has_change_permission function to SuperviseeAdmin that returns False unconditionally, but it had no effect. I have tried setting actions = None in SuperviseeAdmin but it had no effect. What might I be overlooking that could get this to work?

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  • Django Admin: OneToOne Relation as an Inline?

    - by Jim Robert
    I am putting together the admin for a satchmo application. Satchmo uses OneToOne relations to extend the base Product model, and I'd like to edit it all on one page. It is possible to have a OneToOne relation as an Inline? If not, what is the best way to add a few fields to a given page of my admin that will eventually be saved into the OneToOne relation? for example: class Product(models.Model): name = models.CharField(max_length=100) ... class MyProduct(models.Model): product = models.OneToOne(Product) ... I tried this for my admin but it does not work, and seems to expect a Foreign Key: class ProductInline(admin.StackedInline): model = Product fields = ('name',) class MyProductAdmin(admin.ModelAdmin): inlines = (AlbumProductInline,) admin.site.register(MyProduct, MyProductAdmin) Which throws this error: <class 'satchmo.product.models.Product'> has no ForeignKey to <class 'my_app.models.MyProduct'> Is the only way to do this a Custom Form? edit: Just tried the following code to add the fields directly... also does not work: class AlbumAdmin(admin.ModelAdmin): fields = ('product__name',)

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  • Good example usage of get_or _create in Django views and raising a Form error

    - by Rik Wade
    I would like to use get_or_create to check whether an object already exists in my database. If it does not, then it will be created. If it does exist, then I will not create the new object, but need to raise a form error to inform the user that they need to enter different data (for example, a different username). The view contains: p, created = Person.objects.get_or_create( email = registration_form.cleaned_data['email'], defaults = { 'creationDate': datetime.datetime.now(), 'dateOfBirth': datetime.date(1970,1,1) }) So 'p' will contain the existing Person if it exists, or the new Person if not. I would like to act on the boolean value in 'created' in order to skip over saving the Person and re-display the registration_form and raise an appropriate form validation error. The alternative I'm considering is doing a check in a custom Form validation method to see whether a Person exists with the data in the provided 'email' field, and just raising a validation error.

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  • Django User M2M relationship

    - by Antonio
    When trying to syncdb with the following models: class Contact(models.Model): user_from = models.ForeignKey(User,related_name='from_user') user_to = models.ForeignKey(User, related_name='to_user') class Meta: unique_together = (('user_from', 'user_to'),) User.add_to_class('following', models.ManyToManyField('self', through=Contact, related_name='followers', symmetrical=False)) I get the following error: Error: One or more models did not validate: auth.user: Accessor for m2m field 'following' clashes with related m2m field 'User.followers'. Add a related_name argument to the definition for 'following'. auth.user: Reverse query name for m2m field 'following' clashes with related m2m field 'User.followers'. Add a related_name argument to the definition for 'following'. auth.user: The model User has two manually-defined m2m relations through the model Contact, which is not permitted. Please consider using an extra field on your intermediary model instead. auth.user: Accessor for m2m field 'following' clashes with related m2m field 'User.followers'. Add a related_name argument to the definition for 'following'. auth.user: Reverse query name for m2m field 'following' clashes with related m2m field 'User.followers'. Add a related_name argument to the definition for 'following'.

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  • Django select distinct sum

    - by yoshi
    I have the following (greatly simplified) table structure: Order: order_number = CharField order_invoice_number = CharField order_invoice_value = CharField An invoice number can be identical on more than one order (order O1 has invoice number I1, order O2 has invoice number I1, etc.). All the orders with the same invoice number have the same invoice value. For example: Order no. Invoice no. Value O1 I1 200 O2 I1 200 O3 I1 200 04 I2 50 05 I2 100 What I am trying to do is do a sum over all the invoice values, but don't add the invoices with the same number more than once. The sum for the above items would be: 200+50+100. I tried doing this using s = orders.values('order_invoice_id').annotate(total=Sum('order_invoice_value')).order_by() and s = orders.values('order_invoice_id').order_by().annotate(total=Sum('order_invoice_value')) but I didn't get the desired result. I tried a few different solutions from similar questions around here but I couldn't get the desired result. I can't figure out what I'm doing wrong and what I actually should do to get a sum that uses each invoice value just once.

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  • Break nested loop in Django views.py with a function

    - by knuckfubuck
    I have a nested loop that I would like to break out of. After searching this site it seems the best practice is to put the nested loop into a function and use return to break out of it. Is it acceptable to have functions inside the views.py file that are not a view? What is the best practice for the location of this function? Here's the example code from inside my views.py @login_required def save_bookmark(request): if request.method == 'POST': form = BookmarkSaveForm(request.POST) if form.is_valid(): bookmark_list = Bookmark.objects.all() for bookmark in bookmark_list: for link in bookmark.link_set.all(): if link.url == form.cleaned_data['url']: # Do something. break else: # Do something else. else: form = BookmarkSaveForm() return render_to_response('save_bookmark_form.html', {'form': form})

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