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  • Why are a visual studio project's command-line settings stored per user? Is it OK to check-in (and

    - by DanO
    We're creating an application that understands some command-line parameters. There are some default's we would like to supply on the command-line when debugging, and these are easily set in the project settings as explained here. The thing is visual studio stores these settings in a *.csproj.user file, and the default settings for integrated source control do not check-in *.user files. We would like to just have these default command-line parameters in everyone's IDE when debugging this project. Often (but not always) when visual studio guides you into doing things a certain way it is for good reason. We probably don't want to just check-in someone's .csproj.user file... right? This question is has a few parts: Why does Visual Studio store this particular setting per user? Is there a way to alter this behavior? - Would doing so bring bad juju? Under these circumstances is it OK to check-in and share a .user file? Is there a better way to accomplish what we are trying to do here? Thank you -

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  • Draw a never-ending line in XNA

    - by user2236165
    I am drawing a line in XNA which I want to never end. I also have a tool that moves forward in X-direction and a camera which is centered at this tool. However, when I reach the end of the viewport the lines are not drawn anymore. Here are some pictures to illustrate my problem: At the start the line goes across the whole screen, but as my tool moves forward, we reach the end of the line. Here are the method which draws the lines: private void DrawEvenlySpacedSprites (Texture2D texture, Vector2 point1, Vector2 point2, float increment) { var distance = Vector2.Distance (point1, point2); // the distance between two points var iterations = (int)(distance / increment); // how many sprites with be drawn var normalizedIncrement = 1.0f / iterations; // the Lerp method needs values between 0.0 and 1.0 var amount = 0.0f; if (iterations == 0) iterations = 1; for (int i = 0; i < iterations; i++) { var drawPoint = Vector2.Lerp (point1, point2, amount); spriteBatch.Draw (texture, drawPoint, Color.White); amount += normalizedIncrement; } } Here are the draw method in Game. The dots are my lines: protected override void Draw (GameTime gameTime) { graphics.GraphicsDevice.Clear(Color.Black); nyVector = nextVector (gammelVector); GraphicsDevice.SetRenderTarget (renderTarget); spriteBatch.Begin (); DrawEvenlySpacedSprites (dot, gammelVector, nyVector, 0.9F); spriteBatch.End (); GraphicsDevice.SetRenderTarget (null); spriteBatch.Begin (SpriteSortMode.Deferred, BlendState.AlphaBlend, null, null, null, null, camera.transform); spriteBatch.Draw (renderTarget, new Vector2 (), Color.White); spriteBatch.Draw (tool, new Vector2(toolPos.X - (tool.Width/2), toolPos.Y - (tool.Height/2)), Color.White); spriteBatch.End (); gammelVector = new Vector2 (nyVector.X, nyVector.Y); base.Draw (gameTime); } Here's the next vector-method, It just finds me a new point where the line should be drawn with a new X-coordinate between 100 and 200 pixels and a random Y-coordinate between the old vector Y-coordinate and the height of the viewport: Vector2 nextVector (Vector2 vector) { return new Vector2 (vector.X + r.Next(100, 200), r.Next ((int)(vector.Y - 100), viewport.Height)); } Can anyone point me in the right direction here? I'm guessing it has to do with the viewport.width, but I'm not quite sure how to solve it. Thank you for reading!

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  • Punch Line Marketing

    - by jackman
    There are so many "punch line" websites like: http://www.thatswhyyoufail.com www.canrailsscale.com/ www.nooooooooooooooo.com/ but it's a mystery how they ever get so popular. I have an idea for a punch line website too, but I want to make it BIG! Does anyone have any tips for marketing these kinds of sites? p.s. and no, I do not own any of these sites, and am not disguising it as a question to market them lol.

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  • Access a mounted Windows share from the command line

    - by Bryan
    Hello All, I use the "Connect to Server..." option under the "Places" menu to connect to a Windows share in my work environment. When I do so, I can access the Windows share via Nautilus, but I can't figure out how to access the share from the command line without using smbclient. For example, the share isn't mounted under /mnt or /media. Is it possible to access the mounted Windows share from the command line without using smbclient?

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  • 12.04 How to go back to command line only ubuntu

    - by Ne0
    I was attempting to install a command line only version of Ubuntu and followed the instructions here. I downloaded the alternate CD and went through the installation, but never got an "Install a command-line system." option. 12.04 is now up and running, though i don't need the desktop GUI. From what i have read i can set it back into text mode using grub, but what packages should i remove that i don't need any more?

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  • Using ASCMD to run command line scripts for SQL Server Analysis Services

    Sometimes it would be helpful to run scripts from a command line for Analysis Services. This would be useful for things like creating backups, processing data or running other tasks. Is there a command line tool like sqlcmd for multidimensional databases and Data Mining? What are your servers really trying to tell you? Find out with new SQL Monitor 3.0, an easy-to-use tool built for no-nonsense database professionals.For effortless insights into SQL Server, download a free trial today.

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  • Drawing a line using openGL does not work

    - by vikasm
    I am a beginner in OpenGL and tried to write my first program to draw some points and a line. I can see that the window opens with white background but no line is drawn. I was expecting to see red colored (because glColor3f(1.0, 0.0, 0.0);) dots (pixels) and line. But nothing is seen. Here is my code. void init2D(float r, float g, float b) { glClearColor(r,g,b,0.0); glMatrixMode(GL_PROJECTION); gluOrtho2D(0.0, 200.0, 0.0, 150.0); } void display() { glClear(GL_COLOR_BUFFER_BIT); glColor3f(1.0, 0.0, 0.0); glBegin(GL_POINTS); for(int i = 0; i < 10; i++) { glVertex2i(10+5*i, 110); } glEnd(); //draw a line glBegin(GL_LINES); glVertex2i(10,10); glVertex2i(100,100); glEnd(); glFlush(); } int main(int argc, char** argv) { //Initialize Glut glutInit(&argc, argv); //setup some memory buffers for our display glutInitDisplayMode(GLUT_DOUBLE | GLUT_RGB); //set the window size glutInitWindowSize(500, 500); //create the window with the title 'points and lines' glutCreateWindow("Points and Lines"); init2D(0.0, 0.0, 0.0); glutDisplayFunc(display); glutMainLoop(); } I wanted to verify that the glcontext was opening properly and used this code: int main(int argc, char **argv) { glutInit(&argc, argv); //setup some memory buffers for our display glutInitDisplayMode(GLUT_DOUBLE | GLUT_RGB); //set the window size glutInitWindowSize(500, 500); //create the window with the title 'points and lines' glutCreateWindow("Points and Lines"); char *GL_version=(char *)glGetString(GL_VERSION); puts(GL_version); char *GL_vendor=(char *)glGetString(GL_VENDOR); puts(GL_vendor); char *GL_renderer=(char *)glGetString(GL_RENDERER); puts(GL_renderer); getchar(); return 0; } And the ouput I got was: 3.1.0 - Build 8.15.10.2345 Intel Intel(R) HD Graphics Family Can someone point out what I am doing wrong ? Thanks.

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  • Spawn a multi-threaded Java program from a Windows command line program, spawner won't end until spa

    - by Ross Patterson
    Short version: How can I prevent a spawned Java process in Windows from blocking the spawning process from ending? Long version: I'm trying to spawn a multi-threaded Java program (Selenium RC, not that it should matter) from a program launched from the Windows command line (NAnt's <exec> task, again, not that it should matter). I'm doing it using the Windows "start" command, and the spawned process is started and runs correctly. The spawning process receives control back and finishes (NAnt says "BUILD SUCCEEDED"), but doesn't actually exit to the command line. When the spawned process finally terminates (could be hours later), the command process returns and the command line prompt occurs. For example: <target name="start_rc"> <exec program="cmd" failonerror="false" workingdir="${ross.p5.dir}\Tools\selenium\selenium-server-1.0.1" verbose="true"> <arg value="/C"/> <arg value="start"/> <arg value="java"/> <arg value="-jar"/> <arg path="${ross.p5.dir}\Tools\selenium\selenium-server-1.0.1\selenium-server.jar"/> <arg value="-userExtensions"/> <arg path="${ross.p5.dir}\Tools\selenium\selenium-server-1.0.1\user-extensions.js"/> <arg value="-browserSideLog"/> <arg value="-log"/> <arg value="${ross.p5.dir}\artifacts\selenium.log"/> <arg value="-debug"/> </exec> </target> Produces: C :\Ross>nant start_rc NAnt 0.86 (Build 0.86.2898.0; beta1; 12/8/2007) Copyright (C) 2001-2007 Gerry Shaw http://nant.sourceforge.net Buildfile: file:///C:/Ross/ross.build Target framework: Microsoft .NET Framework 3.5 Target(s) specified: start_rc start_rc: [exec] Starting 'cmd (/C start java -jar C:\p5\Tools\selenium\selenium-server-1.0.1\selenium-server.jar -userExtensions C:\p5\Tools\selenium\selenium-server-1.0.1\user-extensions.js -browserSideLog -log C:\p5\artifacts\selenium.log -debug)' in 'C:\p5\Tools\selenium\selenium-server-1.0.1' BUILD SUCCEEDED Total time: 4.1 seconds. ... and then nothing until I close the window where Java is running, then ... C:\Ross> Obviously something is preventing the nant process from terminating, but shouldn't the Windows START command prevent that?

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  • Algorithm to Render a Horizontal Binary-ish Tree in Text/ASCII form

    - by Justin L.
    It's a pretty normal binary tree, except for the fact that one of the nodes may be empty. I'd like to find a way to output it in a horizontal way (that is, the root node is on the left and expands to the right). I've had some experience expanding trees vertically (root node at the top, expanding downwards), but I'm not sure where to start, in this case. Preferably, it would follow these couple of rules: If a node has only one child, it can be skipped as redundant (an "end node", with no children, is always displayed) All nodes of the same depth must be aligned vertically; all nodes must be to the right of all less-deep nodes and to the left of all deeper nodes. Nodes have a string representation which includes their depth. Each "end node" has its own unique line; that is, the number of lines is the number of end nodes in the tree, and when an end node is on a line, there may be nothing else on that line after that end node. As a consequence of the last rule, the root node should be in either the top left or the bottom left corner; top left is preferred. For example, this is a valid tree, with six end nodes (node is represented by a name, and its depth): [a0]------------[b3]------[c5]------[d8] \ \ \----------[e9] \ \----[f5] \--[g1]--------[h4]------[i6] \ \--------------------[j10] \-[k3] Which represents the horizontal, explicit binary tree: 0 a / \ 1 g * / \ \ 2 * * * / \ \ 3 k * b / / \ 4 h * * / \ \ \ 5 * * f c / \ / \ 6 * i * * / / \ 7 * * * / / \ 8 * * d / / 9 * e / 10 j (branches folded for compactness; * representing redundant, one-child nodes; note that *'s are actual nodes, storing one child each, just with names omitted here for presentation sake) (also, to clarify, I'd like to generate the first, horizontal tree; not this vertical tree) I say language-agnostic because I'm just looking for an algorithm; I say ruby because I'm eventually going to have to implement it in ruby anyway. Assume that each Node data structure stores only its id, a left node, and a right node. A master Tree class keeps tracks of all nodes and has adequate algorithms to find: A node's nth ancestor A node's nth descendant The generation of a node The lowest common ancestor of two given nodes Anyone have any ideas of where I could start? Should I go for the recursive approach? Iterative?

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  • How do you draw a line from one corner of the stage to the other?

    - by George Edison
    I am completely perplexed. I asked this question and it (any mentioned solution) doesn't seem to be working at all. All I want is to draw a line from one corner to the other. Here again is the link to the SWF file I have (it's embedded in an HTML document): test.html Here is the source: package { import flash.display.Sprite; import flash.events.Event; public class Main extends Sprite { public function Main():void { if (stage) init(); else addEventListener(Event.ADDED_TO_STAGE, init); } private function init(e:Event = null):void { removeEventListener(Event.ADDED_TO_STAGE, init); // entry point graphics.clear(); graphics.lineStyle(10, 0x000000); graphics.moveTo(0, 0); graphics.lineTo(stage.stageWidth, stage.stageHeight); } } } It just doesn't work! The line goes from somewhere offscreen to about the middle of the stage. What on earth am I doing wrong?

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  • How can I highlight the line of text that is closest to the mouse?

    - by Aaron Digulla
    I have a long text and I'd like to offer the user a reading help: The current line should be highlighted. To make it easier, I'll just use the Y coordinate of the mouse (this way, the mouse pointer isn't going to get in the way). I have a big DIV with the id content which fills the whole width and a small DIV with the class content for the text (see here for an example). I'm using jQuery 1.4. How can I highlight the line of text that is closest to the current mouse position?

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  • How do I bypass GUI in MFC app if command line options exist?

    - by Brandon
    I've got an existing simple MFC app that the user specifies the input file, output file, and then a "Process" button. I'd like to just add the capability so that the input/output files are command line parameters. But, if they exist, I don't want the GUI to show up. I just want the "Process" to execute. I see where I can get the command line parameters (m_lpCmdLine) but how can I bypass the displaying of the GUI? If I step into the app, it goes directly to winmain.cpp and displays the GUI without stepping into any of my code.

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  • Run Iphone app in simulator from the terminal : how to set up iPhoneSim ?

    - by user142764
    Hi, I found this project which seems to make it possible to run an iPhone app from command line ! http://github.com/jhaynie/iphonesim Unfortunately there is almost no documentation and i'm stuck at building this project : I download all sources I run MakeFile and i get these errors : admin$ ./Makefile ./Makefile: line 4: -Werror: command not found ./Makefile: line 5: AppKit: command not found ./Makefile: line 6: Source/main.o: No such file or directory ./Makefile: line 11: .SUFFIXES:: command not found ./Makefile: line 12: .m.o:: command not found ./Makefile: line 13: -o: No such file or directory ./Makefile: line 15: all:: command not found ./Makefile: line 17: iphonesim:: command not found gcc-4.2: argument to '-o' is missing ./Makefile: line 20: clean:: command not found As anybody been able to build and use this project ? Thanks, Vincent

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  • How to avoid the Windows (XP) Security Warning when launching a "DOS" command line within C#?

    - by Will Marcouiller
    This question is related to this initial question asked a little while ago. Now, that I have chosen the extracting tool, I'm iterating through a given in command line parameter directory and subdirectories to extract the compressed .zip files. private static void ExtractAll(DirectoryInfo _workingFolder) { if(_workingFolder == null) { Console.WriteLine("Répertoire inexistant."); return; } foreach (DirectoryInfo subFolder in _workingFolder.GetDirectories("*", SearchOption.AllDirectories)) foreach(FileInfo zippedFile in subFolder.GetFiles("*.zip", SearchOption.AllDirectories)) { if(zippedFile.Exists) { ProcessStartInfo task = new ProcessStartInfo(@".\Tools\7za.exe", string.Format("x {0}", zippedFile.FullName)); Process.Start(task); } } } But everytime I start a 7za process, the Windows Security Warning prompts. I would like to avoid such annoying behaviour, so here's my question: How to avoid the Windows (XP) Security Warning when launching a "DOS" command line within C#?

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  • If a command line program is unsure of stdout's encoding, what encoding should it output?

    - by mackstann
    I have a command line program written in Python, and when I pipe it through another program on the command line, sys.stdout.encoding is None. This makes sense, I suppose -- the output could be another program, or a file you're redirecting it into, or whatever, and it doesn't know what encoding is desired. But neither do I! This program will be used by many different people (humor me) in different ways. Should I play it safe and output only ascii (replacing non-ascii chars with question marks)? Or should I output UTF-8, since it's so widespread these days?

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  • Multiplying numbers on horizontal, vertial, and diagonal lines

    - by untwisted
    I'm currently working on a project Euler problem (www.projecteuler.net) for fun but have hit a stumbling block. One of the problem provides a 20x20 grid of numbers and asks for the greatest product of 4 numbers on a straight line. This line can be either horizontal, vertical, or diagonal. Using a procedural language I'd have no problem solving this, but part of my motivation for doing these problems in the first place is to gain more experience and learn more Haskell. As of right now I'm reading in the grid and converting it to a list of list of ints, eg -- [[Int]]. This makes the horizontal multiplication trivial, and by transposing this grid the vertical also becomes trivial. The diagonal is what is giving me trouble. I've thought of a few ways where I could use explicit array slicing or indexing, to get a solution, but it seems overly complicated and hackey. I believe there is probably an elegant, functional solution here, and I'd love to hear what others can come up with.

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  • "sudo cd ..." one-liner?

    - by j-g-faustus
    Occasionally I want to cd into a directory where my user does not have permission, so I resort to sudo. The obvious command sudo cd somedir doesn't work: $ sudo mkdir test $ sudo chmod go-rxw test $ ls -l drwx------ 2 root root [...snip...] test $ cd test -bash: cd: test: Permission denied $ sudo cd test sudo: cd: command not found Using sudo su works: $ sudo su # cd test Is it possible to make this into a one-liner? (Not a big deal, just idle curiosity :) The variations I tried didn't work: $ sudo "cd test" sudo: cd: command not found $ sudo -i cd test -bash: line 0: cd: test: No such file or directory $ sudo -s cd test The last one doesn't give an error, but it cd's within a new shell that exits by the end of the line, so it doesn't actually take me anywhere. Can someone enlighten me as to why this happens? Why is sudo cd not found, when for example sudo ls ... works fine?

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  • After the update today no graphical interface anymore - 12.04

    - by Mark
    I installed the updates through the update manager today. I shut down my Laptop and now after starting it up again, I only get terminal access to advices. Grub is loading fine and after I picked Ubuntu 12.04 the screen get blank and I am asked to log in with my username and password in command line mode. If I log in I am still in command line mode. How do I get the "normal (graphical)" Ubuntu back? I hope you know what I mean. Since English is not my first language I can't explain this the way I would like to. Mark

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  • Could not write bytes: broken pipe - looking for log of removed packages

    - by user288987
    I have a dual boot system with 12.04 and windows 7. Ubuntu worked fine yesterday but this morning upon boot I get subject. Searched the forums and unsuccessful with recovery. I tried sudo gedit /var/log/apt/history.log to see the log of removed packages, but get the following... ** (gedit:976): WARNING **: Command line 'dbus-launch --autolaunch=2d7d18532e9953bc8a2b852e00000007 --binary-syntax --close-stderr' exited with non-zero exit status 1: Autolaunch error: X11 initialization failed.\n Cannot open display: Run 'gedit --help' to see a full list of available command line options. Anyone have any suggestions for a fix? Please let me know if you require any additional information. Thanks! Mark

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