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  • Detect WebKit Version 525 and Below With RegEx

    - by Jay
    I'm no good at Regular Expressions, really! I would like to specifically detect WebKit browsers below version 525. I have a regular expression [/WebKit\/[\d.]+/.exec(navigator.appVersion)] that correctly returns WebKit/5….…, really, I'd like it to return only the version number, but if the browser isn't WebKit, return null, or better still 0. For example, if the browser was Trident, Presto or Gecko, return null, whereas if the browser is WebKit, return it's version number. To clarify, I would like the regular expression to check if navigator.appVersion contains WebKit and if it does not, return null, if it does, return the version number. I appreciate all your help! Please let's keep this focused, let's not flirt with jQuery or the sort, it's overkill in this scenario.

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  • how to prevent white spaces in a regular expression regex validation

    - by Rees
    i am completely new to regular expressions and am trying to create a regular expression in flex for a validation. using a regular expression, i am going to validate that the user input does NOT contain any white-space and consists of only characters and digits... starting with digit. so far i have: expression="[A-Za-z][A-Za-z0-9]*" this correctly checks for user input to start with a character followed by a possible digit, but this does not check if there is white space...(in my tests if user input has a space this input will pass through validation - this is not desired) can someone tell me how i can modify this expression to ensure that user input with whitespace is flagged as invalid?

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  • Regex validate dates like "Sun, 20 Jun 10"

    - by Trindaz
    Hi, I'm working on a regular expression that will only return true when a date string is in a format something like 'ddd, dd mmm yy'. Valid matches would be values like "Sun, 20 Jun 10" or "Mon, 21 Jun 10" but not "Sunday, 20 Jun 10" or "20 Jun 10". This will be used with mb_ereg in PHP. My attempts so far have only got me half way there. Any help appreciated! Thanks, Dave

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  • Regex: Matching a space-joined list of words, excluding last whitespace

    - by Jesper
    How would I match a space separated list of words followed by whitespace and some optional numbers? I have this: >>> import re >>> m = re.match('(?P<words>(\w+\s+)+)(?P<num>\d+)?\r\n', 'Foo Bar 12345\r\n') >>> m.groupdict() {'num': '12345', 'words': 'Foo Bar '} I'd like the words group to not include the last whitespace(s) but I can't figure this one out. I could do a .strip() on the result but that's not as much fun :) Some strings to test and wanted result: 'Foo & Bar 555\r\n' => {'num': '555', 'words': 'Foo & Bar'} 'Hello World\r\n' => {'num': None, 'words': 'Hello World'} 'Spam 99\r\n' => {'num': 99, 'words': 'Spam'} 'Number 1 666\r\n' => {'num': 666, 'words': 'Number 1'}

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  • Ignoring Whitespace with Regex(perl)

    - by Zerobu
    Hello, I am using Perl Regular expressions. How would i go about ignoring white space and still perform a test to see if a string match. For example. $var = " hello "; #I want var to igonore whitespace and still match if($var =~ m/hello/) { }

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  • jQuery Validate plugin - password check - minimum requirements - Regex

    - by QviXx
    I've got a little problem with my password-checker. There's got a registration form with some fields. I use jQuery Validate plugin to validate user-inputs. It all works except the password-validation: The password should meet some minimum requirements: minimum length: 8 - I just use 'minlength: 8' at least one lower-case character at least one digit Allowed Characters: A-Z a-z 0-9 @ * _ - . ! At the moment I use this code to validate the password: $.validator.addMethod("pwcheck", function(value, element) { return /^[A-Za-z0-9\d=!\-@._*]+$/.test(value); }); This Code works for the allowed characters but not for minimum requirements. I know that you can use for example (?=.*[a-z]) for a lower-case-requirement. But I just don't get it to work. If I add (?=.*[a-z]) the whole code doesn't work anymore. I need to know how to properly add the code to the existing one. Thank you for your answers! This is the complete code <script> $(function() { $("#regform").validate({ rules: { forename: { required: true }, surname: { required: true }, username: { required: true }, password: { required: true, pwcheck: true, minlength: 8 }, password2: { required: true, equalTo: "#password" }, mail1: { required: true, email: true }, mail2: { required: true, equalTo: "#mail1" } }, messages: { forename: { required: "Vornamen angeben" }, surname: { required: "Nachnamen angeben" }, username: { required: "Usernamen angeben" }, password: { required: "Passwort angeben", pwcheck: "Das Passwort entspricht nicht den Kriterien!", minlength: "Das Passwort entspricht nicht den Kriterien!" }, password2: { required: "Passwort wiederholen", equalTo: "Die Passwörter stimmen nicht überein" }, mail1: { required: "Mail-Adresse angeben", email: "ungültiges Mail-Format" }, mail2: { required: "Mail-Adresse wiederholen", equalTo: "Die Mail-Adressen stimmen nicht überein" } } }); $.validator.addMethod("pwcheck", function(value, element) { return /^[A-Za-z0-9\d=!\-@._*]+$/.test(value); }); }); </script>

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  • regex php: find everything in div

    - by Fifth-Edition
    I'm trying to find eveything inside a div using regexp. I'm aware that there probably is a smarter way to do this - but I've chosen regexp. so currently my regexp pattern looks like this: $gallery_pattern = '/([\s\S]*)<\/div/'; And it does the trick - somewhat. the problem is if i have two divs after each other - like this. <div class="gallery">text to extract here</div> <div class="gallery">text to extract from here as well</div> I want to extract the information from both divs, but my problem, when testing, is that im not getting the text in between as a result but instead: "text to extract here text to extract from here as well" So . to sum up. It skips the first end of the div. and continues on to the next. The text inside the div can contain "<", "/" and linebreaks. just so you know! Does anyone have a simple solution to this problem? Im still a regexp novice.

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  • jQuery: select all inputs with unique id (Regex/Wildcard Selectors)

    - by d3020
    I have some textboxes on a webform that have ids like this: txtFinalDeadline_1 txtFinalDeadline_2 txtFinalDeadline_3 txtFinalDeadline_4 In my jQuery how do I find all of those in order to assign a value to them. Before I had the underscore and they were all named txtFinalDeadline I could do this and it worked. $(this).find("#txtFinalDeadline").val(formatDate); However, that was when they were all named the same thing. Now I have the _x after the name and I'm not sure how to go about assigning that same value as before to them. Thanks.

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  • initial caps in actionScript using Regex

    - by Deyon
    I'm trying to do initial caps in actionScript with no loops but now i'm stuck. I wanted to select the first letter or every word then apply uppercase on that letter. Well I got the selection part right, but at a dead end right now, any ideas? I was trying to do this with out loops and cutting up strings. //replaces with x cant figure out how to replace with the found result as uppercase public function initialcaps():void { var pattern:RegExp=/\b[a-z]/g; var myString:String="yes that is my dog dancing on the stage"; var nuString:String=myString.replace(pattern,"x"); trace(nuString); }

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  • String format or REGEX.

    - by ThePower
    I need an simple way to check whether a string that is sent to my function is of the form: (x + n)(x + m) //the +'s can be minus' //n and m represent a double //x represents the char 'x' Is there a simple string format that I can use to check that this is the form. As opposed to checking each character singularly. The whitespace will be removed to save any confusion. Regards Lloyd

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  • Java String.replaceAll regex

    - by atomsfat
    I want to replace the first context of web/style/clients.html with the java String.replaceFirst method so I can get: ${pageContext.request.contextPath}/style/clients.html I tried String test = "web/style/clients.html".replaceFirst("^.*?/", "hello/"); And this give me: hello/style/clients.html but when I do String test = "web/style/clients.html".replaceFirst("^.*?/", "${pageContext.request.contextPath}/"); gives me java.lang.IllegalArgumentException: Illegal group reference

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  • StackOverflowError occured as using java.util.regex.Matcher

    - by Captain Kidd
    Hi guys I try to catch text by Regular Expression. I list codes as follows. Pattern p=Pattern.compile("<@a>(?:.|\\s)+?</@a>"); Matcher m = p.matcher(fileContents.toString()); while(m.find()) { //Error will be thrown at this point System.out.println(m.group()); } If the length of text I want to catch is too long, system will throw me a StackOverflowError. Otherwise, the codes work well. Please help me how to solve this problem.

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  • Need Flex Regex Validation Expression for password that allows for only alphanumeric values and requ

    - by BlueDude
    Hi I'm trying to setup a RegexpValidator that only accepts a string of alphanumeric characters between 6-30 characters long and requires one number. I'm new to Regular Expressions and everything I've tried seems to keep returning an invalid ValidationRsultEvent. Here's a chunk of code: <mx:RegExpValidator id="regexValidator" source="{passwordInput}" property="text" triggerEvent="" valid="onPasswordValidate(event)" invalid="onPasswordValidate(event)" /> private function validateRegister():void { regexValidator.expression = "^(?=.*(\d|\W)).{6,30}$"; regexValidator.validate(); }

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  • Regex - Modifying strings except in specified enclosures - PHP

    - by Kovo
    I have found similar answers to my current needs on SO, however I am still trying to grasp modifying strings based on a rule, except in certain enclosures within those strings. Example of what Im trying to accomplish now: preg_replace("/\s*,\s*/", ",", $text) I found the above in many places. It will remove spaces before and after all commas in a string. That works great. However, if I want to exclude modifying commas found within " ", I am not sure how that rule has to be modified. Any help? Thanks! EDIT: I want to clarify my question: I would like all whitespace before and after the commas in the following sentence removed, except commas found in double or single quotes: a, b , c "d, e f g , " , h i j ,k lm,nop Expected result: a,b,c "d, e f g , ",h i j,k lm,nop

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  • What is proper RegEx expession for SWIFT codes?

    - by abatishchev
    I have to filter user input to on my web ASP.NET page: <asp:TextBox runat="server" ID="recipientBankIDTextBox" MaxLength="11" /> <asp:RegularExpressionValidator runat="server" ValidationExpression="?" ControlToValidate="recipientBankIDTextBox" ErrorMessage="*" /> As far is I know SWIFT code must contain 5 or 6 letters and other symbols up to total length 11 are alphanumeric. How to implement such rule properly? TIO

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  • Need to add underscore to my regex

    - by TaMeR
    I suck at regular expression and just can't seem to figure this out. '/^[A-Za-z0-9](?:.[A-Za-z0-9]+)*$/' As it's right now it allows dots anytime after the first char and I like to add _ so that it allows both. Thanks

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  • Ruby RegEx not matching valid expression

    - by Matthew Carriere
    I have the following expression: ^\w(\s(+|-|\/|*)\s\w)*$ This simply looks to match a mathematical expression, where a user is prompted for terms separated by basic operators (ex: price + tax) The user may enter more than just 2 terms and one operator (ex: price + tax + moretax) I tested this expression in Rubular http://rubular.com/ With the terms: a + a (MATCH) a + a + a (MATCH) a + a + a + a a a + a a Everything works, but when I use it in Ruby it does not work! expression =~ /^\w(\s(+|-|\/|*)\s\w)*$/ I started picking the expression apart and noticed that if I remove the start of line caret it finds matches but isn't correct. a + a (MATCH) a a (MATCH) <-- this is not correct Why is this expression not working in Ruby code? (I am using Ruby 1.8.7 p174)

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  • What is proper RegEx expression for SWIFT codes?

    - by abatishchev
    I have to filter user input to on my web ASP.NET page: <asp:TextBox runat="server" ID="recipientBankIDTextBox" MaxLength="11" /> <asp:RegularExpressionValidator runat="server" ValidationExpression="?" ControlToValidate="recipientBankIDTextBox" ErrorMessage="*" /> As far is I know SWIFT code must contain 5 or 6 letters and other symbols up to total length 11 are alphanumeric. How to implement such rule properly? TIO

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  • Javascript how many characters replaced in a regex?

    - by macca1
    I am sanitizing an input field and manually getting and setting the caret position in the process. With some abstraction, here's the basic idea: <input type="text" onkeyup"check(this)"> And javascript... function check(element) { var charPosition = getCaretPosition(element); $(element).val( sanitize( $(element).val() ) ); setCaretPosition(element, charPosition); } function sanitize(s) { return s.replace(/[^a-zA-Z0-9\s]/g, ''); } This is working fine except when a character does actually get sanitized, my caret position is off by one. Basically I'd like a way to see if the sanitize function has actually replaced a character (and at what index) so then I can adjust the charPosition if necessary. Any ideas?

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  • Java Regex for matching quoted string with escaped quotes

    - by kayahr
    I know there are already many questions like mine but I found no answer which works in Java. So I write a new question. I have text files with content like this: key1 = "This is a \"test\" text with escapes using '\\' characters"; key2 = 'It must work with \'single\' quotes and "double" quotes'; I need a regular expression which matches the values in the double-quotes (or single-quotes). This regular expression must support the escaped quotes and escaped backslashes. The regular expression must work with Java standard Pattern/Matcher classes.

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