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  • how can i send jquery ajax http request with php

    - by testkhan
    i have following form... <form action="http://mydomain.com/get.php" method="post"> <input type="hidden" value="thisisvalue" name="hdnvalue"> <input type="text" name="cost" id="cost"><br><br> <textarea id="msg" name="message"></textarea><br><br> <input type="submit" value="Send" id="send"> </form> the get.php file will response in 1 or 0 i.e 1 means recieved and 0 means not recieved now i want to send it to http://mydomain.com/get.php via http request with jquery ajax how can i do that get the returned value..

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  • How to find the submit button in a specific form in jQuery

    - by leifg
    I try to get jQuery object of a submit button in a specific form (there are several forms on the same page). I managed to get the form element itself. It looks something like this: var curForm = curElement.parents("form"); The current Element has the context HTMLInputElement. The several techniques I tried to get the according submit element of the form: var curSubmit = curForm.find("input[type='submit']"); var curSubmit = $(curForm).find("input[type='submit']"); var curSubmit = curForm.find(":submit"); var curSubmit = $(curForm).find(":submit"); var curSubmit = $(curSubmit, "input[type='submit']"); the result is always the same (and very strange). The result that I get is the same element as "curElement". So how can I get the right submit button?

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  • crash happens when NSMutableArray is returned?

    - by senthilmuthu
    Hi, I have coded like that(that function will be called again and again), but the returned object gives "BAD ACCESS", the NSLog prints correct string, but toReturn sometimes(i called again and again) gives crashes..any help to alter this code - (NSMutableArray *)getAll:(NSString *)type { NSLog(@"Type: %@", type); NSMutableArray *toReturn = [[NSMutableArray alloc] initWithCapacity:0] ; rs = [db executeQuery:Query1]; while ([rs next]) { [toReturn addObject:[rs stringForColumn:@"Name"]]; NSLog(@"name: %@", [rs stringForColumn:@"Name"]); } [rs close]; return toReturn; }

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  • Jquery - how i can get the video src value?

    - by 3gwebtrain
    i need to get the value of a video and need to change in to new value... for that i used this function: var video = $('#task2ResultVideo').get(0); console.log($(video).attr('poster')); // i am getting this $(video).attr('src',function(num,val){ console.log(num,val) // i am not getting this.. }) ? HTML: <video id="task2ResultVideo" autobuffer poster="img/task2-results-host-poster.jpg"> <source src="Video/webm/Task_2.4a_Host_treated.webm" type="video/webm" /> <source src="Video/ogv/Task_2.4a_Host_treated.theora.ogv" type="video/ogg" /> <source src="Video/MP4/Task_2.4a_Host_treated.mp4" type="video/mp4" /> </video>? But i am not able to get the values. what is wrong with my code? in case if i get the value how can i change the src? any suggestion please?

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  • How to get the class of an input inside a jQuery each loop?

    - by Paul Atkins
    Hi, I have function which appends inputs inside a list item when a link is clicked. I then loop through these inputs using an each loop using the code below. It is working correctly as shown, however instead of using field.name I want to use the class of the input as the array key but when i try to do this the class is shown as undefined. Here is the code I am currently using: var values = {}; $.each($('li :input').serializeArray(), function(i, field) { values[field.name] = field.value; }); Here is the code I have inside the list item once I have appended the hidden inputs using jQuery append: <li><input type="hidden" name="group" class="group" value="2"/><input type="hidden" name="condition" class="condition" value="isany"/><input type="hidden" name="value" class="value" value="1,2"/></li> I can get the name attribute fine but class is always undefined. Could anybody help with this?

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  • alternative to lag SQL command

    - by mahen
    I have a table which has a table like this. Month-----Book_Type-----sold_in_Dollars Jan----------A------------ 100 Jan----------B------------ 120 Feb----------A------------ 50 Mar----------A------------ 60 Mar----------B------------ 30 and so on I have to calculate the expected sales for each month and book type based on the last 2 months sales. So for March and type A it would be (100+50)/2 = 75 For March and type B it is 120/1 since no data for Feb is there. I was trying to use the lag function but it wouldn't work since there is data missing in a few rows. Any ideas on this?

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  • $_FILES empty on image upload

    - by zvir
    i need help, i'm programing some kind of catalogue and i have a page where clients can upload their logo or images. every page i make is included in index.php and my url looks like something like this www.url.com/index.php?s=upload where "upload" is name of upload.php file. when i create form on that upload.php file and submit it, $_FILES array is empty. echo "<form method=\"post\" enctype=\"multipart/form-data\" action=\"index.php\" />\n"; echo "<input type=\"file\" name=\"image\">\n"; echo "<input type=\"hidden\" name=\"s\" value=\"upload\">\n"; echo "<input type=\"submit\" name=\"submit\" value=\"Spremi\">\n"; echo "</form>\n"; i tried everything and nothing works. $_POST items are returned but $_FILES are empty...

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  • How do i get my search bar to actually work?

    - by Sam
    Hey guys, I've got a search bar and it looks fine, but i don't really know how to make it search the whole of my site... Here's my html code so far: <form class="search2" method="get" action="default.html" /> <input class="search2" type="text" name="serach_bar" size="31" maxlength="255" value="" style="left: 396px; top: 153px; width: 293px; height: 26px;" /> <input class="search1" type="submit" name="submition" value="Search" style=" padding- bottom:20px; left: 691px; top: 153px; height: 23px" /> <input class="search2" type="hidden" name="sitesearch" value="default.html" /> Thanks in advance guys!

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  • How to convet DataTable to List on runtype with out existin class property [closed]

    - by shamim
    Work on VS2010 C#,Have one DataTable ,want to convert this DataTable to List Suppose: Table dt; On run time want to create similar field from a datatable and fill fields in List.There is no existing class for list properties. ListName=TableName List property name=Table column name List Property type=Table column type List items=Table rows Note: Recently work on EF.To fullfill my project requirement, need to give flexibility to use to input and execute ESQL at runtime .I don’t want to put this execute result on datatable or List ,want to put this result on list. List has no existing class and property,don’t want to convert DataTable on list Type:DataRow If have any query please ask,Thanks in advanced.

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  • In Spring MVC, is it possible to have different return types in one request handler method?

    - by Bobo
    For example, if a request succeeds, I will return a View ,if not, return a String indicating error message and set the content-type to either xml or json. Based on what I read, seems like I should use "void" as the return type for handler methods. Check this out: "void if the method handles the response itself (by writing the response content directly, declaring an argument of type ServletResponse / HttpServletResponse for that purpose) or if the view name is supposed to be implicitly determined through a RequestToViewNameTranslator (not declaring a response argument in the handler method signature)."(Spring Framework reference). What I dont understand is what " the view name is supposed to be implicitly determined through a RequestToViewNameTranslator (not declaring a response argument in the handler method signature)" means? Any anyone give me an example?

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  • Which code snipplets in PHP can create a input form, which creates a new set of data in my mysql dat

    - by smiyazaki
    I am using the Google Maps API with parts in javascript and others in PHP. <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Strict//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-strict.dtd"> Google Maps AJAX + mySQL/PHP Example // var iconBlue = new GIcon(); iconBlue.image = 'icon.png'; iconBlue.shadow = ''; iconBlue.iconSize = new GSize(19, 19); iconBlue.shadowSize = new GSize(22, 20); iconBlue.iconAnchor = new GPoint(6, 20); iconBlue.infoWindowAnchor = new GPoint(5, 1); var iconRed = new GIcon(); iconRed.image = 'icon.png'; iconRed.shadow = ''; iconRed.iconSize = new GSize(19, 19); iconRed.shadowSize = new GSize(22, 20); iconRed.iconAnchor = new GPoint(6, 20); iconRed.infoWindowAnchor = new GPoint(5, 1); var customIcons = []; customIcons["restaurant"] = iconBlue; customIcons["bar"] = iconRed; function load() { if (GBrowserIsCompatible()) { var map = new GMap2(document.getElementById("map")); map.setMapType(G_SATELLITE_MAP); map.addControl(new GSmallMapControl()); map.addControl(new GMapTypeControl()); map.setCenter(new GLatLng(47.614495, -122.341861), 13); // Change this depending on the name of your PHP file GDownloadUrl("phpsqlajax_genxml.php", function(data) { var xml = GXml.parse(data); var markers = xml.documentElement.getElementsByTagName("marker"); for (var i = 0; i < markers.length; i++) { var name = markers[i].getAttribute("name"); var address = markers[i].getAttribute("address"); var type = markers[i].getAttribute("type"); var point = new GLatLng(parseFloat(markers[i].getAttribute("lat")), parseFloat(markers[i].getAttribute("lng"))); var marker = createMarker(point, name, address, type); map.addOverlay(marker); } }); } } function createMarker(point, name, address, type) { var marker = new GMarker(point, customIcons[type]); var html = "<b>" + name + "</b> <br/>" + address; GEvent.addListener(marker, 'click', function() { marker.openInfoWindowHtml(html); }); return marker; } //]]> (I suppose the php will be called by "GDownloadUrl("phpsqlajax_genxml.php", function(data) { ..." in the javascript part of the sourcecode of phpsqlajax_map.htm) Now I need another php file and the code snipplets for it, which creates an input form where I can add some new locations to the google map. Following code is used to create the xml file here: http://detektors.de/maptest/phpsqlajax_genxml.php The next step would be, trying to make an plugin for wordpress that I could easily post a blog entry with a new location on the same map, which displays already some other locations stored in the mysql database. thanks! <?php require("phpsqlajax_dbinfo.php"); function parseToXML($htmlStr) { $xmlStr=str_replace('<','<',$htmlStr); $xmlStr=str_replace('','>',$xmlStr); $xmlStr=str_replace('"','"',$xmlStr); $xmlStr=str_replace("'",''',$xmlStr); $xmlStr=str_replace("&",'&',$xmlStr); return $xmlStr; } // Opens a connection to a MySQL server $connection=mysql_connect ($host, $username, $password); if (!$connection) { die('Not connected : ' . mysql_error()); } // Set the active MySQL database $db_selected = mysql_select_db($database, $connection); if (!$db_selected) { die ('Can\'t use db : ' . mysql_error()); } // Select all the rows in the markers table $query = "SELECT * FROM markers WHERE 1"; $result = mysql_query($query); if (!$result) { die('Invalid query: ' . mysql_error()); } header("Content-type: text/xml"); // Start XML file, echo parent node echo ''; // Iterate through the rows, printing XML nodes for each while ($row = @mysql_fetch_assoc($result)){ // ADD TO XML DOCUMENT NODE echo ''; } // End XML file echo ''; ?

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  • php random image file name

    - by bush man
    Okay im using a snippet I found on google to take a users uploaded image and put it in my directory under Content But Im worried about duplicates so I was going have it upload the image as a Random number well here is my code you can probably understand what im going for through it anyways <label for="file">Profile Pic:</label> <input type="file" name="ProfilePic" id="ProfilePic" /><br /> <input type="submit" name="submit" value="Submit" /> $ProfilePicName = $_FILES["ProfilePic"]["name"]; $ProfilePicType = $_FILES["ProfilePic"]["type"]; $ProfilePicSize = $_FILES["ProfilePic"]["size"]; $ProfilePicTemp = $_FILES["ProfilePic"]["tmp_name"]; $ProfilePicError = $_FILES["ProfilePic"]["error"]; $RandomAccountNumber = mt_rand(1, 99999); echo $RandomAccountNumber; move_uploaded_file($ProfilePicTemp, "Content/".$RandomAccountNumber.$ProfilePicType); And then basicly after all this Im going try to get it to put that random number in my database

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  • Upload files, form within form

    - by Alexd2
    Hello everyone and thanks in advance. I have a problem and I have 2 form into one another, the domestic form is to perform a file upload. As I can do to make when sending in internal form not run the main form. <form name="x" method="post" action="xxx.php"> .... <form action="" method="post" enctype="multipart/form-data" target="xxx"> <input type="file" /> <input type="submit" /> </form> <iframe id="xxx" src="process.php"> </iframe> .... <input type="submit" name="pro" value="Register user"/ > </form> Doing this does not work, as this within another form. Any help or possible solution.

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  • JQuery validation based on class?

    - by Mark Kadlec
    I have a form that will have dynamically created elements, one of those will be of date type. There can also be many fields of this type on my form, all which must be validated. I am using a strongly typed view in Asp MVC, so the name will change based on various factors. What I would like to do is validate based on a class name instead, since that will be constant for that type of field. Ie: <%= Html.TextBox("questionAnswers[" + index + "].AnswerValue", qa.AnswerValue, new { @class = "DateTypeClass" })%> So then I would need JQuery validation based on the classname DateTypeClass versus the Name. Any ideas?

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  • How to add visible menu item from php code (drupal)

    - by uta
    I have a content type with important "created" date field. And I have a menu link (in primary links) which is link to page that shows list of all nodes of my content type. (http://example.com/mycontenttype) I want to have menu links (visible in primary links) to each year when nodes of my content type are displayed (http://example.com/mycontenttype/2010). And I want to add these menu links from mymodule_nodeapi function, when the node is creating and only if it has a "created" date of new year. I know that I can create a pathes in mymodule_menu function, but it doesn't create a visible menu item. (Maybe I can somehow set parent_link_id or something else to do it?)

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  • JavaScript to enable "submit" button (doesn't work)

    - by Halst
    I need the button "submit" to be disabled unless JavaScript is on. I tried: 1. <input onLoad="this.disabled=false" id="post-comment" type="submit" value="Post Your Comment" disabled="disabled"/> 2. <input onLoad="this.removeAttribute("disabled");" id="post-comment" type="submit" value="Post Your Comment" disabled="disabled"/> 3. <input onLoad="document.getElementById("post-comment").removeAttribute("disabled");" id="post-comment" type="submit" value="Post Your Comment" disabled="disabled"/> Doesn't work. I'm new to JavaScript, but can't find answer on the net.

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  • Remove alert from a javascript

    - by albastar
    I've the below code from a tutorial,i want the action but i just want to remove the alert, here is the code: <script type="text/javascript"> setTimeout('read()', 10000); function read() { FB.api('/me/news.reads' + '?article=<?php echo $fbrdurl ?>&access_token=<?php echo $access_token ?>','post', function(response) { var msg = 'Error occured'; if (!response || response.error) { if (response.error) { msg += "\n\nType: "+response.error.type+"\n\nMessage: "+response.error.message; } alert(msg); } else { alert('Post was successful! Action ID: ' + response.id); } }); } </script> I've tried this: <script type="text/javascript"> setTimeout('read()', 10000); function read() { FB.api('/me/news.reads' + '?article=<?php echo $fbrdurl ?>&access_token=<?php echo $access_token ?>','post'; } </script> but not worked, thanks

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  • Filter Phrase Query

    - by alsuelo
    I try to filter a phrase to make a search in my website i've this query, this code working with one word but when i type wit more than one isn't working becuase the print is without spaces. $phrase = $this->getState($this->context.".filter_phrase"); printf("Original string: %s\n", $phrase); if(!empty($phrase)) { $escaped = $db->escape($phrase, true); printf("Escaped string: %s\n", $escaped); $quoted = $db->quote("%" . $escaped . "%" , false); $query->where ('a.title LIKE ' .$quoted); } Example i type king and the output is king , when i type the king the output is theking, i want to know if exist any way to conserve the blank spaces.

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  • Play 2.0 framework - POST parameters

    - by user1452715
    I'm trying to POST parameters to Action, and wrote in the routes: Home page GET / controllers.Application.index() POST /login/name:/password: controllers.Application.login(name, password) and I have an Action public static Result login(String name, String password) { return ok(name + " " + password); } my form is <form action="/login" method="post"> <input name="name" type="text" id="name"> <input name="password" type="password" id="password"> <input type="submit" value="Login"> </form> and it doesn't work For request 'POST /login' [Missing parameter: name] what am i doing wrong?

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  • Problem in populating a dictionary object using Enumerable.Range() (C#3.0)

    - by Newbie
    If I do for (int i = 0; i < appSettings.Count; i++) { string key = appSettings.Keys[i]; euFileDictionary.Add(key, appSettings[i]); } It is working fine. When I am trying the same thing using Enumerable.Range(0, appSettings.Count).Select(i => { string Key = appSettings.Keys[i]; string Value = appSettings[i]; euFileDictionary.Add(Key, Value); }).ToDictionary<string,string>(); I am getting a compile time error The type arguments for method 'System.Linq.Enumerable.Select(System.Collections.Generic.IEnumerable, System.Func)' cannot be inferred from the usage. Try specifying the type arguments explicitly. Any idea? Using C#3.0 Thanks

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  • Radio Button wont work in internet explorer but works fine in firefox

    - by Mo
    Hi i have HTML code like so: <div id="action_content" class="layout"> <input type="hidden" id="action_editing" value=""/> <div id="action_types"> <input type="radio" checked name="action_type" value="EmailActionDescription" onclick="toggle_action(this);"/><label>Email</label> <input type="radio" name="action_type" value="TicketActionDescription" onclick="toggle_action(this);"/><label>Ticket</label> </div> it works fine in firefox but dosent work in internet explorer. any ideas what it could be? the buttons basically display one of 2 options, a ticket or e mail, when clicking on the ticket it just dosent show. if you require any further information please let me know. thanks

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  • Persisting Serializable Objects in Hibernate

    - by VeeArr
    I am attempting to persist objects that contain some large Serializable types. I want Hibernate to automatically generate my DDL (using Hibernate annotations). For the most part, this works, but the default database column type used by Hibernate when persisting these types is tinyblob. Unfortunately, this causes crashes when attempting to persist my class, because these types will not fit within the length of tinyblob. However, if I manually set the type (using @Column(columnDefinition="longblob")), it works fine. Is there any way to make the default binary type longblob instead of tinyblob, so that I don't need to manually specify the @Column annotation on each field?

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  • How to get the src for a video with multiple sources?

    - by Sam Dutton
    I'd like to be able to get the src value that is actually used for a video element like the following: <video> <source src="foo.mp4" type='video/mp4; codecs="avc1.42E01E, mp4a.40.2"'> <source src="foo.webm" type='video/webm; codecs="vp8, vorbis"'> <source src="foo.ogv" type='video/ogg; codecs="theora, vorbis"'> </video> In Firefox (at least), src is defined for the source elements but not for the video element. How can I find which source is used?

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  • encode data in get request

    - by user902395
    <!DOCTYPE html> <html> <meta http-equiv="Content-Type" content="text/html; charset=utf-8"> <body onload="searchForPrograms.submit();"> <form id="searchForPrograms" name="searchForPrograms" enctype="application/x-www-form-urlencoded" method="get" action="searchingEngine.php"> <input type="text" id="query" name="query" value="MyProgram" /><br> <input type="submit" value="Search" /> </form> </body> The get request should have the form like "searchingEngine.php?query=%22MyProgram%22". How can I encode the value of the query input correctly?

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