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  • get foreign key objects in a single query - Django

    - by John
    Hi I have 2 models in my django code: class ModelA(models.Model): name = models.CharField(max_length=255) description = models.CharField(max_length=255) created_by = models.ForeignKey(User) class ModelB(models.Model): category = models.CharField(max_length=255) modela_link = models.ForeignKey(ModelA, 'modelb_link') functions = models.CharField(max_length=255) created_by = models.ForeignKey(User) Say ModelA has 100 records, all of which may or may not have links to ModelB Now say I want to get a list of every ModelA record along with the data from ModelB I would do: list_a = ModelA.objects.all() Then to get the data for ModelB I would have to do for i in list_a: i.additional_data = i.modelb_link.all() However this runs a query on every instance of i. Thus making 101 queries to run. Is there any way of running this all in just 1 query. Or at least less than the 101 queries. I've tried putting in ModelA.objects.select_related().all() but this didn't seem to have any effect. Thanks

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  • Django Template - Convert python list into a javascript object

    - by amcashcow
    I am working on a django / python website I have a page where I want to display a table of search results The list of results is passed in to the template as normal I also want to make this list of objects accessible to the javascript code My first solution was just create another view that returned json format. But each page load required calling the query twice. So then I tried only downloading the data using the json view and printing the table using javascript. but this is also not desirable as now the presentation layer is mixed into the javascript code. is there a way to create a javascript object from the python list as the page is rendered?

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  • Django: Converting an entire Model into a single dictionary

    - by LarrikJ
    Is there a good way in Django to convert an entire model to a dictionary? I mean, like this: class DictModel(models.Model): key = models.CharField(20) value = models.CharField(200) DictModel.objects.all().to_dict() ... with the result being a dictionary with the key/value pairs made up of records in the Model? Has anyone else seen this as being useful for them? Thanks. Update I just wanted to add is that my ultimate goal is to be able to do a simple variable lookup inside a Template. Something like: {{ DictModel.exampleKey }} With a result of DictModel.objects.get(key__exact=exampleKey).value Overall, though, you guys have really surprised me with how helpful allof your responses are, and how different the ways to approach it can be. Thanks a lot.

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  • Is fish or zsh better for shell programming?

    - by Julien Nicoulaud
    I'm a bash user willing to switch to a more friendly and advanced shell. I read a lot of good things about zsh, but I gave a quick test at fish and it seems great too. Both seem very close in term of features, what is your opinion about those two shells especially as regards shell programming?

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  • shell script to start multiple Java programs from a directory at boot

    - by zcourts
    I'm not sure if this is the best approach to this, It's my first time doing all of this (including writing shell scripts). OS: Centos My problem: I want to start multiple shell scripts at boot. One of the shell scripts is to start my own services and 3 others are for third party services. The shell script to start my own services will be looking for jar files. I currently have two services (will change), written in Java. All services are named under convention prefix-service-servicename What I've done: I created the following directory structure /home/username/scripts init.sh boot/ boot/startthirdprtyservice1.sh boot/startthirdprtyservice2.sh boot/startthirdprtyservice3.sh boot/startmyservices.sh /home/username/services prefix-lib-libraryname.jar prefix-lib-libraryname.jar prefix-service-servicename.jar prefix-service-servicename.jar prefix-service-servicename.jar In init.sh I have the following: #!/bin/sh #This scripts run all executable scripts in the boot directory at boot #done by adding this script to the file /etc/rc.d/rc.local #nohup #run-parts /home/username/scripts/boot/* #for each file in the boot dir... # ignore the HUP (hangup) signal for s in ./boot/*;do if [ -x $s ]; then echo "Starting $s" nohup $s & fi done echo "Done starting bootup scripts " echo "\n" In the script boot/startmyservices.sh I have #!/bin/sh fnmatch () { case "$2" in $1) return 0 ;; esac ; return 1 ; } ##sub strin to match for SUBSTRING="prefix-service" for s in /home/username/services/*;do if [ -x $s ]; then #match service in the filename , i.e. only services are started if fnmatch "$SUBSTRING" "$s" ; then echo "Starting $s " nohup $s & fi fi done echo "Done starting Services" echo "\n" Finally: Usually you can stick a program in /etc/rc.d/rc.local for it to be run at boot but I don't think this works in this case, or rather I don't know what to put in there I've just learnt how to do this by reading up a bit so I'm not sure its particularly the best thing to do so any advice is appreciated. When I run init.sh nohup.out contains Starting the thirdparty daemon... thirdparty started... .... but nothing from myservices.sh and my Java services aren't running I'm not sure where to start debugging or what could be going wrong. Edit Found some issues and got it to work, used -x instead of -n to check if the string is none zero, needed the sub string check to also be if [[ $s = $SUBSTRING ]] ; then and this last one was just stupid, missing java -jar in front of $s Still unsure of how to get init.sh to run at boot though

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  • command to show the shell command prompt

    - by LinuxPenseur
    Hi, Is there a shell command to display the command prompt. I will explain what i want through the illustration below. When i execute script.sh, i should get the following output $sh script.sh $ /* command prompt and then print hi */ hi My script.sh is like this #! /bin/bash <command to display the shell command prompt> echo "hi" exit 0 what should the code that has to go in the place of angle brackets to get an output like above? Thanks

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  • command to show the shell command prompt

    - by LinuxPenseur
    Hi, Is there a shell command to display the command prompt. I will explain what i want through the illustration below. When i execute script.sh, i should get the following output $sh script.sh $ /* command prompt and then print hi */ hi My script.sh is like this #! /bin/bash <command to display the shell command prompt> echo "hi" exit 0 what should the code that has to go in the place of angle brackets to get an output like above? Thanks

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  • Can I use REG_EXPAND_SZ for the locations of shell folders instead of REG_SZ

    - by Jherico
    I'm working on re-arranging a number of the shell folders in windows 7 to utilize Dropbox to keep a set of machines in sync. I'd like to create a .reg file which I can use to update the locations of these folders rather than manually changing them from the UI, but I don't want to rely on the path to the home folder being the same each time. So my question is, is it possible to replace the REG_SZ values in HKCU\Software\Microsoft\Windows\CurrentVersion\Explorer\Shell Folders with REG_EXPAND_SZ values specifying an offset from %HOME% instead of an exact path?

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  • Running a shell script in *nix

    - by Ben
    Bit of a newb using *nix (I'm actually using a bash shell in OS X 10.5) and I wondered what the probably very simple answer is to this... When I write a script (called, say, my_script) and I've saved it to the current directory, why do I have to put a period and a forward slash in front of its name to run it? Like this: ./my_script Can't the shell tell that I want to run it from the current directory? Windows seems to handle that situation. Cheers Ben

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  • What to use for Shell Access?

    - by Aristotle
    I just purchased a virtual dedicated server-plan that comes with shell access. It's been a while since I've actually used shell access remotely, so I'm a bit behind the times. Years ago I used PuTTY, but I'm curious if there are any better options that I should consider for establishing that connection, and managing my server remotely. I figured this question would be most appropriately asked here since it is regarding tools.

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  • Disable default Gnome Shell Super Key Mapping

    - by soares
    Gnome Shell by default uses the Super (Windows) key to display the activities overview. But I'd prefer to use the Super key to invoke Synapse. Right now I have to press Super+Super+Spacebar in order to invoke Synapse which is annoying (Super+Spacebar is the binding to invoke Synapse). Is there any way to remove the default Gnome Shell mapping? In the keyboard shortcuts system settings, only the Alt+F1 binding appears for the activities overview action.

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  • ksh93 as default shell via ssh

    - by jessem
    Howdy, I'm a big fan of ksh93. My hosts' shell account does not allow me to configure .login .profile or chsh to change my default shell. As it is, I am dropped into jailshell-3.2 and I have to invoke /bin/ksh93 manually. Is there some work around for this? Thanks in advance.

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  • Scroll shell output with mouse in tmux

    - by user31494
    Mouse scrolling doesn't work in tmux the way it works when I run shell without tmux (in Gnome Terminal). It seems tmux sends mouse scroll events as if I pressed Up/Down keys. But I want it to scroll though the shell output history. Is there a way to make tmux work like this? Note: I know how to scroll with keyboard (thanks to another question here). Tried mouse scrolling in two versions of tmux: 0.8-5hardy1 (on Ubuntu Hardy) 1.3-1 (on Ubuntu Maverick)

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  • Mac Remote Shell

    - by Jamza
    I am trying to create a remote shell on OS X with NC. I tried nc -l 1337 -e /bin/bash but it seems that the Mac version of NC does not support the -e option. Does anyone know how I can achieve a remote shell on OS X preferably only using the built in tools? Thank you.

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  • Deploying a Django application in a virtual Ubuntu Server

    - by mfsaint
    I have a virtualbox machine running Ubuntu Server 10.04LTS. My intention is to this machine to work like a VPS, this way I can learn and prepare for when I get a VPS service. Apache+mod_wsgi for deploying the Django app seems the right choice to me. I have the domain (marianofalcon.com.ar) but nothing else, no DNS. The problem is that I'm pretty lost with all the deployment stuff. I know how to configure mod_wsgi(with the django.wsgi file) and apache(creating a VirtualHost). Something is missing and I don't know what it is. I think that I lack networking skills ant that's the big problem. Trying to host the app on a virtualbox adds some difficulty because I don't know well what IP to use. This is what I've got: file placed at: /etc/apache2/sites-available: NameVirtualHost *:80 <VirtualHost *:80> ServerAdmin [email protected] ServerName www.my-domain.com ServerAlias my-domain.com Alias /media /path/to/my/project/media DocumentRoot /path/to/my/project WSGIScriptAlias / /path/to/your/project/apache/django.wsgi ErrorLog /var/log/apache2/error.log LogLevel warn CustomLog /var/log/apache2/access.log combined </VirtualHost> django.wsgi file: import os, sys wsgi_dir = os.path.abspath(os.path.dirname(__file__)) project_dir = os.path.dirname(wsgi_dir) sys.path.append(project_dir) project_settings = os.path.join(project_dir,'settings') os.environ['DJANGO_SETTINGS_MODULE'] = 'myproject.settings' import django.core.handlers.wsgi application = django.core.handlers.wsgi.WSGIHandler()

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  • Komodo Edit 5.2 Django Template Syntax Error - Info: <head> previously mentioned

    - by Lance McNearney
    I am using Komodo Edit 5.2 for editing html and Django template files. It always shows a single syntax error inside the first {% block %} area on the first tag of my template. For example: {% extends "base.html" %} {% load i18n %} {% block title %}Hello{% endblock %} {% block content %} <p>Hello</p> <-- Syntax error on this single line <p>Other lines have no errors</p> {% endblock %} {% block footer %} <p>No errors here</p> {% endblock %} The syntax error given is: Info: <head> previously mentioned I know for a fact that the error has nothing to do with my <head> tag since it occurs in the base template and in child templates (and the IDE isn't smart enough to process the base templates when in a child, etc.) All of my html tags are closed properly and everything validates for XHTML strict. This forum post mentions a similar problem but offers no solution (and may be specific to Smarty syntax highlighting). Any ideas on how to resolve this error (or disable it from being shown)?

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  • django-mptt: how to successfully move nodes around

    - by Parand
    django-mptt seems determined to drive me out of my mind. I'm trying to do something relatively simple: I'm going to delete a node, and need to do something reasonable with the node's children. Namely, I'd like to move them up one level so they're children of their current parent's parent. That is, if the tree looks like: Root | Grandpa | Father | | C1 C2 I'm going to delete Father, and would like C1 and C2 to be children of Grandpa. Here's the code I'm using: class Node(models.Model): first_name = models.CharField(max_length=80, blank=True) parent = models.ForeignKey('self', null=True, blank=True, related_name='children') def reparent_children(self, parent): print "Reparenting" for child in self.get_children(): print "Working on", child.first_name, "to parent", parent.email parent = Node.objects.get(id=parent.id) child.move_to(parent, 'last-child') child.save() So I'd call: father.reparent_children(grandpa) father.parent = None father.save() This works - almost. The children report their parents as Grandpa: c1.parent == grandpa # True Grandpa counts C1 and C2 among its children c1 in grandpa.children.all() # True However, Root disowns these kids. c1.get_root() == father # c1's root is father, instead of Root c1 in root.get_descendants() # False How do I get the children to move and their root not get corrupted?

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  • Limiting choices from an intermediary ManyToMany junction table in Django

    - by Matthew Rankin
    Background I've created three Django models—Inventory, SalesOrder, and Invoice—to model items in inventory, sales orders for those items, and invoices for a particular sales order. Each sales order can have multiple items, so I've used an intermediary junction table—SalesOrderItems—using the through argument for the ManyToManyField. Also, partial billing of a sales orders is allowed, so I've created a ForeignKey in the Invoice model related to the SalesOrder model, so that a particular sales order can have multiple invoices. Here's where I deviate from what I've normally seen. Instead of relating the Invoice model to the Item model via a ManyToManyField, I've related the Invoice model to the SalesOrderItem intermediary junction table through the intermediary junction table InvoiceItem. I've done this because it better models reality—our invoices are tied to sales orders and can only include items that are tied to that sales order as opposed to any item in inventory. I will admit that it does seem strange having the intermediary junction table of a ManyToManyField related to the intermediary junction table of another ManyToManyField. Question How can I limit the choices available for the invoice_items in the Invoice model to just the sales_order_items of the SalesOrder model for that particular Invoice? (I tried using limit_choices_to= {'sales_order': self.invoice.sales_order}) as part of the item = models.ForeignKey(SalesOrderItem) in the InvoiceItem model, but that didn't work. Am I correct in thinking that limiting the choices for the invoice_items should be handled in the model instead of in a form? Code class Item(models.Model): item_num = models.SlugField(unique=True) default_price = models.DecimalField(max_digits=10, decimal_places=2, blank=True, null=True) class SalesOrderItem(models.Model): item = models.ForeignKey(Item) sales_order = models.ForeignKey('SalesOrder') unit_price = models.DecimalField(max_digits=10, decimal_places=2) quantity = models.DecimalField(max_digits=10, decimal_places=4) class SalesOrder(models.Model): customer = models.ForeignKey(Party) so_num = models.SlugField(max_length=40, unique=True) sales_order_items = models.ManyToManyField(Item, through=SalesOrderItem) class InvoiceItem(models.Model): item = models.ForeignKey(SalesOrderItem) invoice = models.ForeignKey('Invoice') unit_price = models.DecimalField(max_digits=10, decimal_places=2) quantity = models.DecimalField(max_digits=10, decimal_places=4) class Invoice(models.Model): invoice_num = models.SlugField(max_length=25) sales_order = models.ForeignKey(SalesOrder) invoice_items = models.ManyToManyField(SalesOrderItem, through='InvoiceItem')

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  • Left Join with a OneToOne field in Django

    - by jamida
    I have 2 tables, simpleDB_all and simpleDB_some. The "all" table has an entry for every item I want, while the "some" table has entries only for some items that need additional information. The Django models for these are: class all(models.Model): name = models.CharField(max_length=40) important_info = models.CharField(max_length=40) class some(models.Model): all_key = models.OneToOneField(all) extra_info = models.CharField(max_length=40) I'd like to create a view that shows every item in "all" with the extra info if it exists in "some". Since I'm using a 1-1 field I can do this with almost complete success: allitems = all.objects.all() for item in allitems: print item.name, item.important_info, item.some.extra_info but when I get to the item that doesn't have a corresponding entry in the "some" table I get a DoesNotExist exception. Ideally I'd be doing this loop inside a template, so it's impossible to wrap it around a "try" clause. Any thoughts? I can get the desired effect directly in SQL using a query like this: SELECT all.name, all.important_info, some.extra_info FROM all LEFT JOIN some ON all.id = some.all_key_id; But I'd rather not use raw SQL.

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  • Custom template for Django's comments application does not display fields

    - by Jannis
    Hi, I want to use django.contrib.comments in a blogging application and customize the way the form is displayed. My problem is that I can't get the fields to display although displaying the hidden fields works just fine. I had a look at the docs and compared it with the regular way of displaying forms but honestly I don't know why the following doesn't work out: {% get_comment_form for comments_object as form %} <form action="{% comment_form_target %}" method="POST"> […] {% for hidden in form.hidden_fields %} {{ hidden }} {% endfor %} {% for field in form.fields %} {{field}} {% endfor %} […] </form> The output looks like this: <form action="/comments/post/" method="POST"> <input type="hidden" name="content_type" value="flatpages.flatpage" id="id_content_type" /> <input type="hidden" name="object_pk" value="1" id="id_object_pk" /> <input type="hidden" name="timestamp" value="1269522506" id="id_timestamp" /> <input type="hidden" name="security_hash" value="ec4…0fd" id="id_security_hash" /> content_type object_pk timestamp security_hash name email url comment honeypot […] </form> </div> Can you tell me what I'm doing wrong? Thanks in advance

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  • Django: how to cleanup form fields and avoid code duplication

    - by Alexander Konstantinov
    Quite often I need to filter some form data before using it (saving to database etc.) Let's say I want to strip whitespaces and replace repeating whitespaces with a single one in most of the text fields, in many forms. It's not difficult to do this using clean_<fieldname> methods: # Simplified model with two text fields class MyModel(models.Model): title = models.CharField() description = models.CharField() # Model-based form class MyForm(forms.ModelForm): class Meta: model = MyModel def clean_title(self): title = self.cleaned_data['title'] return re.sub(r'\s{2,}', ' ', title.strip()) def clean_description(self): description = self.cleaned_data['description'] return re.sub(r'\s{2,}', ' ', description.strip()) It does exactly what I need, and has a nice side effect which I like: if user enters only whitespaces, the field will be considered empty and therefore invalid (if it is required) and I don't even have to throw a ValidationError. The obvious problem here is code duplication. Even if I'll create some function for that, say my_text_filter, I'll have to call it for every text field in all my forms: from myproject.filters import my_text_filter class MyForm(forms.ModelForm): class Meta: model = MyModel def clean_title(self): return my_text_filter(self.cleaned_data['title']) def clean_description(self): return my_text_filter(self.cleaned_data['description']) The question: is there any standard and simple way in Django (I use version 1.2 if that matters) to do this (like, for example, by adding property validators = {'title': my_text_filter, 'description': my_text_filter} to MyModel), or at least some more or less standard workaround? I've read about form validation and validators in the documentation, but couldn't find what I need there.

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