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  • Comparing fields of one table to other fields of another table

    - by chupinette
    Hello! I have a function called add_item which actually inserts values in a field item_name of temporary table called temp having fields temp_id and item_name. I have another table calleed item which consists of fields item_id, item_name, price. I have another table called quotation which consists of fields q_id, item_id,item_name,price. Now I cant figure out how do i compare the item_name from temp to the field item_name from item. And then, insert the values of item in quoatation table. Can anyone guide me please?

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  • Need Advice on building the database. all in one table or split?

    - by Ibrahim Azhar Armar
    hello, i am developing an application for a real-estate company. the problem i am facing is about implementing the database. however i am just confused on which way to adopt i would appreciate if you could help me out in reasoning the database implementation. here is my situation. a) i have to store the property details in the database. b) the properties have approximately 4-5 categories to which it will belong for ex : resedential, commnercial, industrial etc. c) now the categories have sub-categories. for example. a residential category will have sub category such as. Apartment / Independent House / Villa / Farm House/ Studio Apartment etc. and hence same way commercial and industrial or agricultural will too have sub-categories. d) each sub-categories will have to store the different values. like a resident will have features like Bedrooms/ kitchens / Hall / bathroom etc. the features depends on the sub categories. for an example on how i would want to implement my application you can have a look at this site. http://www.magicbricks.com/bricks/postProperty.html i could possibly think of the solution like this. a) create four to five tables depending upon the categories which will be existing(the problem is categories might increase in the future). b) create different tables for all the features, location, price, description and merge the common property table into one. for example all the property will have the common entity such as location, total area, etc. what would you advice for me given the current situation. thank you

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  • Drupal db_query error need help

    - by Gobi
    Hi drupal pals, im using drupal 6.15 and doing my first project in drupal . i got an issue while running the below query with db_query i have drupal,delhi keywords in column 'tag' with table name tagging. db_query(SELECT * FROM {tagging} WHERE tag LIKE '%drup%') wont retrieve the correct output. it show null but the query modified like this, db_query(SELECT * FROM {tagging} WHERE tag LIKE 'drup%') retrieve "drupal" as output finally i used the php core mysql_query mysql_query(SELECT * FROM tagging WHERE tag LIKE '%drup%') it retrieve the exact n correct output "drupal" . is any one have solution , Thanxs, Gobi

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  • Zend_Table_Db and Zend_Paginator and Zend_Paginator_Adapter_DbSelect

    - by Uffo
    I have the following query: $this->select() ->where("`name` LIKE ?",'%'.mysql_escape_string($name).'%') Now I have the Zend_Paginator code: $paginator = new Zend_Paginator( // $d is an instance of Zend_Db_Select new Zend_Paginator_Adapter_DbSelect($d) ); $paginator->getAdapter()->setRowCount(200); $paginator->setItemCountPerPage(15) ->setPageRange(10) ->setCurrentPageNumber($pag); $this->view->data = $paginator; As you see I'm passing the data to the view using $this->view->data = $paginator Before I didn't had $paginator->getAdapter()->setRowCount(200);I could determinate If I have any data or not, what I mean with data, if the query has some results, so If the query has some results I show the to the user, if not, I need to show them a message(No results!) But in this moment I don't know how can I determinate this, since count($paginator) doesn't work anymore because of $paginator->getAdapter()->setRowCount(200);and I'm using this because it taks about 7 sec for Zend_Paginator to count the page numbers. So how can I find If my query has any results?

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  • Database design in blogging systems

    - by Peter
    As a learning exercise I'm trying to put myself a blogging system. The goal is to code something that will let me create multiple blogs, like blogger.com or wordpress.com, but much simplified. I would like to ask you, what do you think is best database design for this type of script. Is it better to have one big table, containing posts from all blogs of all users (like friendfeed) or would it be better to create separate table for each blog's posts? Big thanks in advance for your help, Peter.

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  • Python MySQLdb placeholders syntax

    - by ensnare
    I'd like to use placeholders as seen in this example: cursor.execute (""" UPDATE animal SET name = %s WHERE name = %s """, ("snake", "turtle")) Except I'd like to have the query be its own variable as I need to insert a query into multiple databases, as in: query = """UPDATE animal SET name = %s WHERE name = %s """, ("snake", "turtle")) cursor.execute(query) cursor2.execute(query) cursor3.execute(query) What would be the proper syntax for doing something like this?

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  • PHP throws 'Allowed memory exhausted' errors while migrating data in Drupal.

    - by Stan
    I'm trying to setup a tiny sandbox on a local machine to play around with Drupal. I created a few CCK types; in order to create a few nodes I wrote the following script: chdir('C:\..\drupal'); require_once '.\includes\bootstrap.inc'; drupal_bootstrap(DRUPAL_BOOTSTRAP_FULL); module_load_include('inc', 'node', 'node.pages'); $node = array('type' => 'my_type'); $link = mysql_connect(..); mysql_select_db('my_db'); $query_bldg = ' SELECT stuff FROM table LIMIT 10 '; $result = mysql_query($query_bldg); while ($row = mysql_fetch_object($result)) { $form_state = array(); $form_state['values']['name'] = 'admin'; $form_state['values']['status'] = 1; $form_state['values']['op'] = t('Save'); $form_state['values']['title'] = $row->val_a; $form_state['values']['my_field'][0]['value'] = $row->val_b; ## About another dozen or so of similar assignments... drupal_execute('node_form', $form_state, (object)$node); } Here are a few relevant lines from php_errors.log: [12-Jun-2010 05:02:47] PHP Notice: Undefined index: REMOTE_ADDR in C:\..\drupal\includes\bootstrap.inc on line 1299 [12-Jun-2010 05:02:47] PHP Notice: Undefined index: REMOTE_ADDR in C:\..\drupal\includes\bootstrap.inc on line 1299 [12-Jun-2010 05:02:47] PHP Warning: session_start(): Cannot send session cookie - headers already sent by (output started at C:\..\drupal\includes\bootstrap.inc:1299) in C:\..\drupal\includes\bootstrap.inc on line 1143 [12-Jun-2010 05:02:47] PHP Warning: session_start(): Cannot send session cache limiter - headers already sent (output started at C:\..\drupal\includes\bootstrap.inc:1299) in C:\..\drupal\includes\bootstrap.inc on line 1143 [12-Jun-2010 05:02:47] PHP Warning: Cannot modify header information - headers already sent by (output started at C:\..\drupal\includes\bootstrap.inc:1299) in C:\..\drupal\includes\bootstrap.inc on line 709 [12-Jun-2010 05:02:47] PHP Warning: Cannot modify header information - headers already sent by (output started at C:\..\drupal\includes\bootstrap.inc:1299) in C:\..\drupal\includes\bootstrap.inc on line 710 [12-Jun-2010 05:02:47] PHP Warning: Cannot modify header information - headers already sent by (output started at C:\..\drupal\includes\bootstrap.inc:1299) in C:\..\drupal\includes\bootstrap.inc on line 711 [12-Jun-2010 05:02:47] PHP Warning: Cannot modify header information - headers already sent by (output started at C:\..\drupal\includes\bootstrap.inc:1299) in C:\..\drupal\includes\bootstrap.inc on line 712 [12-Jun-2010 05:02:47] PHP Notice: Undefined index: REMOTE_ADDR in C:\..\drupal\includes\bootstrap.inc on line 1299 [12-Jun-2010 05:02:48] PHP Fatal error: Allowed memory size of 239075328 bytes exhau sted (tried to allocate 261904 bytes) in C:\..\drupal\includes\form.inc on line 488 [12-Jun-2010 05:03:22] PHP Fatal error: Allowed memory size of 239075328 bytes exhausted (tried to allocate 261904 bytes) in C:\..\drupal\includes\form.inc on line 488 [12-Jun-2010 05:04:34] PHP Fatal error: Allowed memory size of 262144 bytes exhausted (tried to allocate 261904 bytes) in Unknown on line 0 At this point any action php takes results in the last error shown above. I tried increasing the value of memory_limit in php.ini before the final Fatal error which obviously didn't help. How can the error be eliminated? Am I on a correct path to migrating data into Drupal or should the cck tables be operated on directly? Windows XP PHP 5.3.2 VC6 Apache 2.2

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  • SugarCRM installation frozen

    - by Tom S.
    Hi there. I'm trying to install SugarCRM version 5.5.1. on a webhost. Everything goes nice until the step when the installation begins. The output is this one: Creating Sugar configuration file (config.php) Creating Sugar application tables, audit tables and relationship metadata ............. And never moves on! I check the database and can see that there are tables missing. The install.log file doesnt have any errors, and the last line in the file is: 2010-04-27 22:17:03...creating Relationship Meta for Bug It seems the installation stopped here, but i cant get why! Iv searched in the foruns, etc, but cant get it... Anyone had this issue? Any clues about whats happening? Thanks a lot

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  • remote database connection with my iphone application using cocos2d

    - by Rana
    MCPResult *theResult; MCPConnection *mySQLConnection; //initialize connection string vars NSString *dbURL = @"192.168.0.16"; NSString *userName = @""; NSString *pass = @""; int port = 3306; //open connection to database mySQLConnection = [[MCPConnection alloc] initToHost: dbURL withLogin:userName password:pass usingPort:port]; if ([mySQLConnection isConnected]) { NSLog(@"The connection to database was successfull"); } else { NSLog(@"The connection to database was failed"); } //selection to database if([mySQLConnection selectDB:@"blackjack_DB"]) { NSLog(@"Database found"); } else { NSLog(@"Database not found"); } //selection to Table theResult = [mySQLConnection queryString:@"select * from test"]; //theResult = [mySQLConnection queryString:@"select * from test where id='1'"]; //theResult = [mySQLConnection queryString:@"select id from test"]; //theResult = [mySQLConnection queryString:@"select name from test where pass='main_pass'"]; NSArray *m= [theResult fetchRowAsArray]; NSLog(@"%@", m); NSLog(@"%@", [m objectAtIndex:2]); Use this code for connecting & receive information from remotedatabase. And also use some framework. AppKit.framework, Cocoa.framework, Carbon.framework, MCPKit_bundled.framework. But stile i didn't connect my application with remort database.

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  • LIMIT then RAND rather than RAND then LIMIT

    - by Larry
    I'm using full text search to pull rows. I order the rows based on score (ORDER BY SCORE) , then of the top 20 rows (LIMIT 20), I want to rand (RAND) the result set. So for any specific search term, I want to randomly show 5 of the top 20 results. My workaround is code based- where I put the top 20 into an array then randomly select 5. Is there sql way to do this?

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  • Codeigniter active record select, left join, count

    - by sea_1987
    Hi There, I have a form that shows results from a database query, these results can have many other assets ajoined to them and I wanting to find a way of showing how many assets each elemement has. For example my table is of areas of england an other table has where the users live I current have this code, $this->db->select('*'); $this->db->from('places'); $this->db->join('users, places.place_id = user.place_id, left'); $this->db->get(); The issue I am having is getting the query to return the place name and the number of users living in that place, it is possible?

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  • Join 2 children tables with a parent tables without duplicated

    - by user1847866
    Problem I have 3 tables: People, Phones and Emails. Each person has an UNIQUE ID, and each person can have multiple numbers or multiple emails. Simplified it looks like this: +---------+----------+ | ID | Name | +---------+----------+ | 5000003 | Amy | | 5000004 | George | | 5000005 | John | | 5000008 | Steven | | 8000009 | Ashley | +---------+----------+ +---------+-----------------+ | ID | Number | +---------+-----------------+ | 5000005 | 5551234 | | 5000005 | 5154324 | | 5000008 | 2487312 | | 8000009 | 7134584 | | 5000008 | 8451384 | +---------+-----------------+ +---------+------------------------------+ | ID | Email | +---------+------------------------------+ | 5000005 | [email protected] | | 5000005 | [email protected] | | 5000008 | [email protected] | | 5000008 | [email protected] | | 5000008 | [email protected] | | 8000009 | [email protected] | | 5000004 | [email protected] | +---------+------------------------------+ I am trying to joining them together without duplicates. It works great, when I try to join only Emails with People or only Phones with People. SELECT People.Name, People.ID, Phones.Number FROM People LEFT OUTER JOIN Phones ON People.ID=Phones.ID ORDER BY Name, ID, Number; +----------+---------+-----------------+ | Name | ID | Number | +----------+---------+-----------------+ | Steven | 5000008 | 8451384 | | Steven | 5000008 | 24887312 | | John | 5000005 | 5551234 | | John | 5000005 | 5154324 | | George | 5000004 | NULL | | Ashley | 8000009 | 7134584 | | Amy | 5000003 | NULL | +----------+---------+-----------------+ SELECT People.Name, People.ID, Emails.Email FROM People LEFT OUTER JOIN Emails ON People.ID=Emails.ID ORDER BY Name, ID, Email; +----------+---------+------------------------------+ | Name | ID | Email | +----------+---------+------------------------------+ | Steven | 5000008 | [email protected] | | Steven | 5000008 | [email protected] | | Steven | 5000008 | [email protected] | | John | 5000005 | [email protected] | | John | 5000005 | [email protected] | | George | 5000004 | [email protected] | | Ashley | 8000009 | [email protected] | | Amy | 5000003 | NULL | +----------+---------+------------------------------+ However, when I try to join Emails and Phones on People - I get this: SELECT People.Name, People.ID, Phones.Number, Emails.Email FROM People LEFT OUTER JOIN Phones ON People.ID = Phones.ID LEFT OUTER JOIN Emails ON People.ID = Emails.ID ORDER BY Name, ID, Number, Email; +----------+---------+-----------------+------------------------------+ | Name | ID | Number | Email | +----------+---------+-----------------+------------------------------+ | Steven | 5000008 | 8451384 | [email protected] | | Steven | 5000008 | 8451384 | [email protected] | | Steven | 5000008 | 8451384 | [email protected] | | Steven | 5000008 | 24887312 | [email protected] | | Steven | 5000008 | 24887312 | [email protected] | | Steven | 5000008 | 24887312 | [email protected] | | John | 5000005 | 5551234 | [email protected] | | John | 5000005 | 5551234 | [email protected] | | John | 5000005 | 5154324 | [email protected] | | John | 5000005 | 5154324 | [email protected] | | George | 5000004 | NULL | [email protected] | | Ashley | 8000009 | 7134584 | [email protected] | | Amy | 5000003 | NULL | NULL | +----------+---------+-----------------+------------------------------+ What happens is - if a Person has 2 numbers, all his emails are shown twice (They can not be sorted! which means they can not be removed by @last) What I want: Bottom line, playing with the @last, I want to end up with somethig like this, but @last won't work if I don't arrange ORDER columns in the righ way - and this seems like a big problem..Orderin the email column. Because seen from the example above: Steven has 2 phone number and 3 emails. The JOIN Emails with Numbers happens with each email - thus duplicated values that can not be sorted (SORT BY does not work on them). **THIS IS WHAT I WANT** +----------+---------+-----------------+------------------------------+ | Name | ID | Number | Email | +----------+---------+-----------------+------------------------------+ | Steven | 5000008 | 8451384 | [email protected] | | | | 24887312 | [email protected] | | | | | [email protected] | | John | 5000005 | 5551234 | [email protected] | | | | 5154324 | [email protected] | | George | 5000004 | NULL | [email protected] | | Ashley | 8000009 | 7134584 | [email protected] | | Amy | 5000003 | NULL | NULL | +----------+---------+-----------------+------------------------------+ Now I'm told that it's best to keep emails and number in separated tables because one can have many emails. So if it's such a common thing to do, what isn't there a simple solution? I'd be happy with a PHP Solution aswell. What I know how to do by now that satisfies it, but is not as pretty. If I do it with GROUP_CONTACT I geat a satisfactory result, but it doesn't look as pretty: I can't put a "Email type = work" next to it. SELECT People.Ime, GROUP_CONCAT(DISTINCT Phones.Number), GROUP_CONCAT(DISTINCT Emails.Email) FROM People LEFT OUTER JOIN Phones ON People.ID=Phones.ID LEFT OUTER JOIN Emails ON People.ID=Emails.ID GROUP BY Name; +----------+----------------------------------------------+---------------------------------------------------------------------+ | Name | GROUP_CONCAT(DISTINCT Phones.Number) | GROUP_CONCAT(DISTINCT Emails.Email) | +----------+----------------------------------------------+---------------------------------------------------------------------+ | Steven | 8451384,24887312 | [email protected],[email protected],[email protected] | | John | 5551234,5154324 | [email protected],[email protected] | | George | NULL | [email protected] | | Ashley | 7134584 | [email protected] | | Amy | NULL | NULL | +----------+----------------------------------------------+---------------------------------------------------------------------+

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  • A rails migration that specifies the distance between two months..?

    - by Trip
    I would like to make two drop downs. a start time, and an end time. Specifically, I only need months. I would like to, for example, choose January, and then March, and then have the database read that it is the these two months plus February. Is there any out of the box migration that could work? I'm guessing.. script/generate migration AddMonthsToClass beginDate:datetime #through endDate:datetime I apologize ahead of time if my question sounds retarded! Sorry! :D

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  • A little bit of Ajax goes a long way

    - by Holland
    ..except when you're having problems. My problem is this: I have a hierarchical list of categories stored in a database which I wish to output in a dropdown list. The hierarchy comes into place when the subcategories are to be displayed, which are dependent on a parent id (which equals out to the first seven or so main categories listed). My thoughts are relatively simple: when the user clicks the dynamically allocated list of main categories, they are clicking on an option tag. For each option tag, an id (i.e., the parent) is listed in the value attribute, as well as an argument which is sent to a Javascript function which then uses AJAX to get the data via PHP and sends it to my 'javascript.php' file. The file then does magic, and populates the subcategory list, which is dependent on the main category selected. I believe I have the idea down, it's just that I'm implementing the solution improperly, for some reason. Here's what I have so far: from javascript.php <script type="text/javascript" src=<?=JPATH_BASE.DS.'includes'.DS.'jquery.js';?>> var ajax = { ajax.sendAjaxData = function(method, url, dataTitle, ajaxData) { $.ajax({ type: 'post', url: "C:/wamp/www/patention/components/com_adsmanagar/views/edit/tmpl/javascript.php", data: { 'data' : ajaxData }, success: function(result){ // we have the response alert("Your request was successful." + result); }, error: function(e){ alert('Error: ' + e); } }); } ajax.printSubCategoriesOnClick = function(parent) { alert("hello world!"); ajax.sendAjaxData('post', 'javascript.php', 'data' parent); <?php $categories = $this->formData->getCategories($_POST['data']); ?> ajax.printSubCategories(<?=$categories;?>); } ajax.printSubCategories = function(categories) { var select = document.getElementById("subcategories"); for (var i = 0; i < categories.length; i++) { var opt = document.createElement("option"); opt.text = categories['name']; opt.value = categories['id']; } } } </script> the function used to populate the form data function populateCategories($parent, FormData $formData) { $categories = $formData->getCategories($parent); echo "<pre>"; print_r($categories); echo "</pre>"; foreach($categories as $section => $row){ ?> <option value=<?=$row['id'];?> onclick="ajax.printSubCategoriesOnClick(<?=$row['id']?>)"> <? echo $row['name']; ?> </option> <?php } } The problem is that when I try to do a print_r on my $_POST variable, nothing shows up. I also receive an "undefined index" error (which refers to the key I set for the data type). I'm thinking that for some reason, the data is being sent to my form.php file, or my default.php file which includes both the form.php and javascript.php files via a function. Is there something specific that I'm missing here? Just looking up basic AJAX syntax (via jQuery) hasn't helped out, unfortunately.

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  • What is wrong with this WHERE clause?

    - by Victor
    Is there a reason why this query doesn't work? The following query will work if I just exclude the WHERE clause. I need to know what is wrong with it. I know the given values of $key exists in the table, so why doesn't this work? $q = "SELECT * WHERE t1.project=$key FROM project_technologies AS t1 JOIN languages AS t2 ON t1.language = t2.key"; Table's have the following fields: project_technologies - key - project - language languages - key - name

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  • How do I put array into columns

    - by mathew
    $db = mysql_connect("", "", "") or die("Could not connect."); mysql_select_db("",$db)or die(mysql_error()); $sql = "SELECT * FROM table where 1"; $pager = new pager($sql,'page',6); while($row = mysql_fetch_array($pager->result)) { echo $row['persons']."<br>"; } mysql_close($db); above code output : Mathew Thomas John Stewart Watson Kelvin What I need is it should split inot multiple columns say: Mathew Stewart Thomas Watson John Kelvin HOw do I do this??

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  • Implementing database redundancy with sharded tables

    - by ensnare
    We're looking to implement load balancing by horizontally sharding our tables across a cluster of servers. What are some options to implement live redundancy should a server fail? Would it be effective to do (2) INSERTS instead of one ... one to the target shard, and another to a secondary shard which could be accessed should the primary shard not respond? Or is there a better way? Thanks.

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  • Another rookie question; How to implement Count() here?

    - by Camran
    I have this query: SELECT mt.*, fordon.*, boende.*, elektronik.*, business.*, hem_inredning.*, hobby.* FROM classified mt LEFT JOIN fordon ON fordon.classified_id = mt.classified_id LEFT JOIN boende ON boende.classified_id = mt.classified_id LEFT JOIN elektronik ON elektronik.classified_id = mt.classified_id LEFT JOIN business ON business.classified_id = mt.classified_id LEFT JOIN hem_inredning ON hem_inredning.classified_id = mt.classified_id LEFT JOIN hobby ON hobby.classified_id = mt.classified_id ORDER BY modify_date DESC I need to implement a count here, to just count all rows in combination with the JOINS you see. How should I do this? SELECT COUNT(mt.*, fordon.* etc) FROM ? // This method wont work Thanks

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  • How do I show a user's credit based on their session

    - by Jamie
    Hi all - I'm developing a simple LAMP app where users can credit their account using Paypal. I suspect this is a simple issue, but have spent quite a while experimenting to no avail and would appreciate any thoughts: System has a user management system working fine using sessions, but I can't get it to display the current user's credit. But I've been trying things along the lines of: $result = mysql_query(" SELECT * FROM users INNER JOIN account ON account.UserID=account.UserID ORDER BY account.accountID"); while($_SESSION['Username'] = $row['Username'] ) { echo $row['Username']; echo $row['Credit']; } I suspect the while statement is invalid, but I want it to echo username and credit where the current session username = the username stored in the database. Thanks so much for taking a look - very much appreciated.

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  • PDO::PARAM for type decimal?

    - by dmontain
    I have 2 database fields `decval` decimal(5,2) `intval` int(3) I have 2 pdo queries that update them. The one that updates the int works ok $update_intval->bindParam(':intval', $intval, PDO::PARAM_INT); but I can't update the decimal field. I've tried the 3 ways below, but nothing works $update_decval->bindParam(':decval', $decval, PDO::PARAM_STR); $update_decval->bindParam(':decval', $decval, PDO::PARAM_INT); $update_decval->bindParam(':decval', $decval); It seems the problem is with the database type decimal? Is there a PDO::PARAM for a field of type decimal? If not, what do I use as a workaround?

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  • Help with SQL query (add 5% to users with conditions)

    - by Mestika
    Hi everyone, I’m having some difficulties with a query which purpose is to give users with more than one thread (called CS) in current year a 5% point “raise”. My relational schema looks like this: Thread = (threadid, threadname, threadLocation) threadoffering = (threadid, season, year, user) user = (name, points) Then, what I need is to check: WHERE thread.threadid = threadoffering.threadid AND where threadoffering.year AND threadoffering.season = currentDate AND where threadoffering.User 1 GIVE 5 % raise TO user.points I hope it is explained thoroughly but otherwise here it is in short text: Give a 5 % “point raise” to all users who has more than 1 thread in threadLocation CS in the current year and season (always dynamic, so for example now is year = 2010 and season is = spring). I am looking forward to your answer Sincerely, Emil

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  • Relational database question with php.

    - by Oliver Bayes-Shelton
    Hi, Not really a coding question more a little help with my idea of a Relational database. If I have 3 tables in a SQL database. In my php script I basically query the companies which are in industry "a" and then insert a row into a separate table with their details such as companyId , companyName etc is that a type of Relational database ? I have explained it in a simple way so we don't get confused what I am trying to say.

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  • XML flat file vs. relational database backend

    - by donpal
    Most projects now need some form of a database. When someone says database, I usually think relational databases, but I still hear about flat file XML databases. What parameters do you take into consideration when deciding between a "real" database and a flat-file XML database. When should one be used over the other, and under what circumstances should I never consider using a flat file (or vice versa a relational) database?

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  • Select query 2-3 times faster than view

    - by Richard Knop
    This query run alone: SELECT -- lots of columns FROM (((((((((((`table1` `t1` LEFT JOIN `table2` `t2` ON(( `t2`.`userid` = `t1`.`userid` ))) LEFT JOIN `table3` `t3` ON(( `t1`.`orderid` = `t3`.`orderid` ))) LEFT JOIN `table4` `t4` ON(( `t4`.`orderitemlicenseid` = `t3`.`orderitemlicenseid` ))) LEFT JOIN `table5` `t5` ON(( `t1`.`orderid` = `t5`.`orderid` ))) LEFT JOIN `table6` `t6` ON(( `t5`.`transactionid` = `t6`.`transactionid` ))) LEFT JOIN `table7` `t7` ON(( `t7`.`transactionid` = `t5`.`transactionid` ))) LEFT JOIN `table8` `t8` ON(( `t8`.`voucherid` = `t7`.`voucherid` ))) LEFT JOIN `table9` `t9` ON(( `t8`.`voucherid` = `t9`.`voucherid` ))) LEFT JOIN `table10` `t10` ON(( ( `t10`.`vouchergroupid` = `t9`.`vouchergroupid` ) AND ( `t2`.`territoryid` = `t10`.`territoryid` ) ))) LEFT JOIN `table11` `t11` ON(( `t11`.`voucherid` = `t8`.`voucherid` ))) LEFT JOIN `table12` `t12` ON(( `t12`.`orderid` = `t1`.`orderid` ))) GROUP BY `t5`.`transactionid` Takes about 2.5 seconds to finish. When I save it to a view and run it as: SELECT * FROM viewName; It takes 7 seconds to finish. What is the reason and how can I make the view faster?

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