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  • Reversing Django URLs With Extra Options

    - by Justin Voss
    Suppose I have a URLconf like below, and 'foo' and 'bar' are valid values for page_slug. urlpatterns = patterns('', (r'^page/(?P<page_slug>.*)/', 'myapp.views.someview'), ) Then, I could reconstruct the URLs using the below, right? >>> from django.core.urlresolvers import reverse >>> reverse('myapp.views.someview', kwargs={'page_slug': 'foo'}) '/page/foo/' >>> reverse('myapp.views.someview', kwargs={'page_slug': 'bar'}) '/page/bar/' But what if I change my URLconf to this? urlpatterns = patterns('', (r'^foo-direct/', 'myapp.views.someview', {'page_slug': 'foo'}), (r'^my-bar-page/', 'myapp.views.someview', {'page_slug': 'bar'}), ) I expected this result: >>> from django.core.urlresolvers import reverse >>> reverse('myapp.views.someview', kwargs={'page_slug': 'foo'}) '/foo-direct/' >>> reverse('myapp.views.someview', kwargs={'page_slug': 'bar'}) '/my-bar-page/' However, this throws a NoReverseMatch exception. I suspect I'm trying to do something impossible. Any suggestions on a saner way to accomplish what I want? Named URLs aren't an option, since I don't want other apps that link to these to need to know about the specifics of the URL structure (encapsulation and all that).

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  • Django User M2M relationship

    - by Antonio
    When trying to syncdb with the following models: class Contact(models.Model): user_from = models.ForeignKey(User,related_name='from_user') user_to = models.ForeignKey(User, related_name='to_user') class Meta: unique_together = (('user_from', 'user_to'),) User.add_to_class('following', models.ManyToManyField('self', through=Contact, related_name='followers', symmetrical=False)) I get the following error: Error: One or more models did not validate: auth.user: Accessor for m2m field 'following' clashes with related m2m field 'User.followers'. Add a related_name argument to the definition for 'following'. auth.user: Reverse query name for m2m field 'following' clashes with related m2m field 'User.followers'. Add a related_name argument to the definition for 'following'. auth.user: The model User has two manually-defined m2m relations through the model Contact, which is not permitted. Please consider using an extra field on your intermediary model instead. auth.user: Accessor for m2m field 'following' clashes with related m2m field 'User.followers'. Add a related_name argument to the definition for 'following'. auth.user: Reverse query name for m2m field 'following' clashes with related m2m field 'User.followers'. Add a related_name argument to the definition for 'following'.

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  • installing paramiko

    - by fixxxer
    This may sound like a repeated question on SF, but I could not find a clear answer to it, yet.So. I installed Paramiko 1.7 with "setup.py install" command and while running the demo.py program, I got this error: Traceback (most recent call last): File "C:\Documents and Settings\fixavier\Desktop\paramiko-1.7\demos\demo.py", line 33, in <module> import paramiko File "C:\Python26\lib\site-packages\paramiko\__init__.py", line 69, in <module> from transport import randpool, SecurityOptions, Transport File "C:\Python26\lib\site-packages\paramiko\transport.py", line 32, in <module> from paramiko import util File "C:\Python26\lib\site-packages\paramiko\util.py", line 31, in <module> from paramiko.common import * File "C:\Python26\lib\site-packages\paramiko\common.py", line 99, in <module> from Crypto.Util.randpool import PersistentRandomPool, RandomPool ImportError: No module named Crypto.Util.randpool I'm getting this error even after installing PyCrypto 2.1. On running test.py(which comes with the installation), I got the following error - Traceback (most recent call last): File "C:\Documents and Settings\fixavier\Desktop\pycrypto-2.0.1\pycrypto-2.0.1\test.py", line 18, in <module> from Crypto.Util import test File "C:\Documents and Settings\fixavier\Desktop\pycrypto-2.0.1\pycrypto-2.0.1\build/lib.win32-2.6\Crypto\Util\test.py", line 17, in <module> import testdata File "C:\Documents and Settings\fixavier\Desktop\pycrypto-2.0.1\pycrypto-2.0.1\test\testdata.py", line 450, in <module> from Crypto.Cipher import AES ImportError: cannot import name AES I don't have the confidence to go ahead and install AES after all this, for all I know I may get another ImportError! Please advice.Is it the way of installation thats problematic?

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  • Django OpenID django-openid-auth Login Error.

    - by gramware
    I get the following error when attempting to use django-openid-auth OpenID discovery error: No usable OpenID services found for *******@gmail.com I have followed the instructions that come with it, though it seems there is something I am missing. the installation is on my localhost.

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  • Distance by sea calculator, intermediate coordinates?

    - by Lucian2k
    How do I calculate distance between 2 coordinates by sea? I also want to be able to draw a route between the two coordinates. Only solution I found so far is to split a map into pixels, identify each pixel as LAND or SEA and then try to find the path using A* algorithm. Then transform pixels to relative coordinates. There are some software packages I could buy but none have online extensions. A service that calculates distances between sea ports and plots the path on a map is searates.com

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  • Django-registration and ReCaptcha integration - how to pass the user's IP

    - by knuckfubuck
    New to django and trying to setup django-registration 0.8 with recaptcha-client. I followed the advice posted in the answer to this question. I used the custom form and custom backend from that post and the widget and field from this tutorial. My form is displaying properly with the recaptcha widget but when I submit it throws the error about the missing IP. What's the best way to pass the IP using django-registration?

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  • Migrating data from Plone to Liferay, or how could I retrieve information from Plone's Data.fs

    - by brandizzi
    Hello, all. I need to migrate data from a Plone-based portal to Liferay. Has anyone some idea on how to do it? Anyway, I am trying to retrieve data from Data.fs and store it in a representation easier to work, such as JSON. To do it, I need to know which objects I should get from Plone's Data.fs. I already got the Products.CMFPlone.Portal.PloneSite instance from the Data.fs, but I cannot get anything from it. I would like to get the PloneSite instance and do something like this: >>> import ZODB >>> from ZODB import FileStorage, DB >>> path = r"C:\Arquivos de programas\Plone\var\filestorage\Data.fs" >>> storage = FileStorage.FileStorage(path) >>> db = DB(storage) >>> conn = db.open() >>> root = conn.root() >>> app = root['Application'] >>> plone_site = app.getChildNodes()[13] # 13 would be index of PloneSite object >>> a = plone_site.get_articles() >>> for article in a: ... print "Title:", a.title ... print "Content:", a.content Title: <some title> Conent: <some content> Title: <some title> Conent: <some content> Of course, it did not need to be so straightforward. I just want some information about the structure of PloneSite and how to recover its data. Has anyone some idea? Thank you in advance!

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  • OpenGL basics: calling glDrawElements once per object

    - by Bethor
    Hi all, continuing on from my explorations of the basics of OpenGL (see this question), I'm trying to figure out the basic principles of drawing a scene with OpenGL. I am trying to render a simple cube repeated n times in every direction. My method appears to yield terrible performance : 1000 cubes brings performance below 50fps (on a QuadroFX 1800, roughly a GeForce 9600GT). My method for drawing these cubes is as follows: done once: set up a vertex buffer and array buffer containing my cube vertices in model space set up an array buffer indexing the cube for drawing as 12 triangles done for each frame: update uniform values used by the vertex shader to move all cubes at once done for each cube, for each frame: update uniform values used by the vertex shader to move each cube to its position call glDrawElements to draw the positioned cube Is this a sane method ? If not, how does one go about something like this ? I'm guessing I need to minimize calls to glUniform, glDrawElements, or both, but I'm not sure how to do that. Full code for my little test : (depends on gletools and pyglet) I'm aware that my init code (at least) is really ugly; I'm concerned with the rendering code for each frame right now, I'll move to something a little less insane for the creation of the vertex buffers and such later on. import pyglet from pyglet.gl import * from pyglet.window import key from numpy import deg2rad, tan from gletools import ShaderProgram, FragmentShader, VertexShader, GeometryShader vertexData = [-0.5, -0.5, -0.5, 1.0, -0.5, 0.5, -0.5, 1.0, 0.5, -0.5, -0.5, 1.0, 0.5, 0.5, -0.5, 1.0, -0.5, -0.5, 0.5, 1.0, -0.5, 0.5, 0.5, 1.0, 0.5, -0.5, 0.5, 1.0, 0.5, 0.5, 0.5, 1.0] elementArray = [2, 1, 0, 1, 2, 3,## back face 4, 7, 6, 4, 5, 7,## front face 1, 3, 5, 3, 7, 5,## top face 2, 0, 4, 2, 4, 6,## bottom face 1, 5, 4, 0, 1, 4,## left face 6, 7, 3, 6, 3, 2]## right face def toGLArray(input): return (GLfloat*len(input))(*input) def toGLushortArray(input): return (GLushort*len(input))(*input) def initPerspectiveMatrix(aspectRatio = 1.0, fov = 45): frustumScale = 1.0 / tan(deg2rad(fov) / 2.0) fzNear = 0.5 fzFar = 300.0 perspectiveMatrix = [frustumScale*aspectRatio, 0.0 , 0.0 , 0.0 , 0.0 , frustumScale, 0.0 , 0.0 , 0.0 , 0.0 , (fzFar+fzNear)/(fzNear-fzFar) , -1.0, 0.0 , 0.0 , (2*fzFar*fzNear)/(fzNear-fzFar), 0.0 ] return perspectiveMatrix class ModelObject(object): vbo = GLuint() vao = GLuint() eao = GLuint() initDone = False verticesPool = [] indexPool = [] def __init__(self, vertices, indexing): super(ModelObject, self).__init__() if not ModelObject.initDone: glGenVertexArrays(1, ModelObject.vao) glGenBuffers(1, ModelObject.vbo) glGenBuffers(1, ModelObject.eao) glBindVertexArray(ModelObject.vao) initDone = True self.numIndices = len(indexing) self.offsetIntoVerticesPool = len(ModelObject.verticesPool) ModelObject.verticesPool.extend(vertices) self.offsetIntoElementArray = len(ModelObject.indexPool) ModelObject.indexPool.extend(indexing) glBindBuffer(GL_ARRAY_BUFFER, ModelObject.vbo) glEnableVertexAttribArray(0) #position glVertexAttribPointer(0, 4, GL_FLOAT, GL_FALSE, 0, 0) glBindBuffer(GL_ELEMENT_ARRAY_BUFFER, ModelObject.eao) glBufferData(GL_ARRAY_BUFFER, len(ModelObject.verticesPool)*4, toGLArray(ModelObject.verticesPool), GL_STREAM_DRAW) glBufferData(GL_ELEMENT_ARRAY_BUFFER, len(ModelObject.indexPool)*2, toGLushortArray(ModelObject.indexPool), GL_STREAM_DRAW) def draw(self): glDrawElements(GL_TRIANGLES, self.numIndices, GL_UNSIGNED_SHORT, self.offsetIntoElementArray) class PositionedObject(object): def __init__(self, mesh, pos, objOffsetUf): super(PositionedObject, self).__init__() self.mesh = mesh self.pos = pos self.objOffsetUf = objOffsetUf def draw(self): glUniform3f(self.objOffsetUf, self.pos[0], self.pos[1], self.pos[2]) self.mesh.draw() w = 800 h = 600 AR = float(h)/float(w) window = pyglet.window.Window(width=w, height=h, vsync=False) window.set_exclusive_mouse(True) pyglet.clock.set_fps_limit(None) ## input forward = [False] left = [False] back = [False] right = [False] up = [False] down = [False] inputs = {key.Z: forward, key.Q: left, key.S: back, key.D: right, key.UP: forward, key.LEFT: left, key.DOWN: back, key.RIGHT: right, key.PAGEUP: up, key.PAGEDOWN: down} ## camera camX = 0.0 camY = 0.0 camZ = -1.0 def simulate(delta): global camZ, camX, camY scale = 10.0 move = scale*delta if forward[0]: camZ += move if back[0]: camZ += -move if left[0]: camX += move if right[0]: camX += -move if up[0]: camY += move if down[0]: camY += -move pyglet.clock.schedule(simulate) @window.event def on_key_press(symbol, modifiers): global forward, back, left, right, up, down if symbol in inputs.keys(): inputs[symbol][0] = True @window.event def on_key_release(symbol, modifiers): global forward, back, left, right, up, down if symbol in inputs.keys(): inputs[symbol][0] = False ## uniforms for shaders camOffsetUf = GLuint() objOffsetUf = GLuint() perspectiveMatrixUf = GLuint() camRotationUf = GLuint() program = ShaderProgram( VertexShader(''' #version 330 layout(location = 0) in vec4 objCoord; uniform vec3 objOffset; uniform vec3 cameraOffset; uniform mat4 perspMx; void main() { mat4 translateCamera = mat4(1.0f, 0.0f, 0.0f, 0.0f, 0.0f, 1.0f, 0.0f, 0.0f, 0.0f, 0.0f, 1.0f, 0.0f, cameraOffset.x, cameraOffset.y, cameraOffset.z, 1.0f); mat4 translateObject = mat4(1.0f, 0.0f, 0.0f, 0.0f, 0.0f, 1.0f, 0.0f, 0.0f, 0.0f, 0.0f, 1.0f, 0.0f, objOffset.x, objOffset.y, objOffset.z, 1.0f); vec4 modelCoord = objCoord; vec4 positionedModel = translateObject*modelCoord; vec4 cameraPos = translateCamera*positionedModel; gl_Position = perspMx * cameraPos; }'''), FragmentShader(''' #version 330 out vec4 outputColor; const vec4 fillColor = vec4(1.0f, 1.0f, 1.0f, 1.0f); void main() { outputColor = fillColor; }''') ) shapes = [] def init(): global camOffsetUf, objOffsetUf with program: camOffsetUf = glGetUniformLocation(program.id, "cameraOffset") objOffsetUf = glGetUniformLocation(program.id, "objOffset") perspectiveMatrixUf = glGetUniformLocation(program.id, "perspMx") glUniformMatrix4fv(perspectiveMatrixUf, 1, GL_FALSE, toGLArray(initPerspectiveMatrix(AR))) obj = ModelObject(vertexData, elementArray) nb = 20 for i in range(nb): for j in range(nb): for k in range(nb): shapes.append(PositionedObject(obj, (float(i*2), float(j*2), float(k*2)), objOffsetUf)) glEnable(GL_CULL_FACE) glCullFace(GL_BACK) glFrontFace(GL_CW) glEnable(GL_DEPTH_TEST) glDepthMask(GL_TRUE) glDepthFunc(GL_LEQUAL) glDepthRange(0.0, 1.0) glClearDepth(1.0) def update(dt): print pyglet.clock.get_fps() pyglet.clock.schedule_interval(update, 1.0) @window.event def on_draw(): with program: pyglet.clock.tick() glClear(GL_COLOR_BUFFER_BIT|GL_DEPTH_BUFFER_BIT) glUniform3f(camOffsetUf, camX, camY, camZ) for shape in shapes: shape.draw() init() pyglet.app.run()

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  • LXML E builder for java?

    - by directedition
    There is one thing I really love about LXML, and that the E builder. I love that I can throw XML together like this: message = E.Person( E.Name( E.First("jack") E.Last("Ripper") ) E.PhoneNumber("555-555-5555") ) To make: <Person> <Name> <First>Jack</First> <Last>Ripper</Last> </Name> <PhoneNumber>555-555-5555</PhoneNumber> </Person> As opposed to the painstaking way DOM works. I am going to be moving a bunch of my software to Java soon and it is very very heavy on its usage of E. Does Java have anything near equivalent to that usage?

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  • Disable Plone Archetypes index/convert doc/pdf files

    - by hosting-schuppen
    Hi Stackoverflowers, if i rebuild my catalog in plone i get many of this infos: 2010-02-18T11:26:09 INFO Archetypes Error while trying to convert file contents to 'text/plain' in .getIndexable() of : Unable to find binary "wvHtml" in /sbin:/usr/sbin:/usr/local/sbin:/usr/local/bin:/usr/bin:/bin:/usr/X11R6/bin:/usr/games:/usr/lib/jvm/jre/bin This happens to doc and pdf files. I don't wanna convert docs or pdfs. How can i disable it completly? Thanks for the help!

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  • Urllib's urlopen broken on some sites (StackApps api)

    - by Edan Maor
    I'm using urllib2's urlopen function to try and get a JSON result from the StackOverflow api. The code I'm using: >>> import urllib2 >>> conn = urllib2.urlopen("http://api.stackoverflow.com/0.8/users/") >>> conn.readline() The result I'm getting: '\x1f\x8b\x08\x00\x00\x00\x00\x00\x04\x00\xed\xbd\x07`\x1cI\x96%&/m\xca{\x7fJ\... I'm fairly new to urllib, but this doesn't seem like the result I should be getting. I've tried it in other places and I get what I expect (the same as visiting the address with a browser gives me: a JSON object). Using urlopen on other sites (e.g. "http://google.com") works fine, and gives me actual html. I've also tried using urllib and it gives the same result. I'm pretty stuck, not even knowing where to look to solve this problem. Any ideas?

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  • Urllib's urlopen broken on some sites (e.g. StackApps api)

    - by Edan Maor
    I'm using urllib2's urlopen function to try and get a JSON result from the StackOverflow api. The code I'm using: >>> import urllib2 >>> conn = urllib2.urlopen("http://api.stackoverflow.com/0.8/users/") >>> conn.readline() The result I'm getting: '\x1f\x8b\x08\x00\x00\x00\x00\x00\x04\x00\xed\xbd\x07`\x1cI\x96%&/m\xca{\x7fJ\... I'm fairly new to urllib, but this doesn't seem like the result I should be getting. I've tried it in other places and I get what I expect (the same as visiting the address with a browser gives me: a JSON object). Using urlopen on other sites (e.g. "http://google.com") works fine, and gives me actual html. I've also tried using urllib and it gives the same result. I'm pretty stuck, not even knowing where to look to solve this problem. Any ideas?

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  • Django admin site auto populate combo box based on input

    - by user292652
    hi i have to following model class Match(models.Model): Team_one = models.ForeignKey('Team', related_name='Team_one') Team_two = models.ForeignKey('Team', related_name='Team_two') Stadium = models.CharField(max_length=255, blank=True) Start_time = models.DateTimeField(auto_now_add=False, auto_now=False, blank=True, null=True) Rafree = models.CharField(max_length=255, blank=True) Judge = models.CharField(max_length=255, blank=True) Winner = models.ForeignKey('Team', related_name='winner', blank=True) updated = models.DateTimeField('update date', auto_now=True ) created = models.DateTimeField('creation date', auto_now_add=True ) def save(self, force_insert=False, force_update=False): pass @models.permalink def get_absolute_url(self): return ('view_or_url_name') class MatchAdmin(admin.ModelAdmin): list_display = ('Team_one','Team_two', 'Winner') search_fields = ['Team_one','Team_tow'] admin.site.register(Match, MatchAdmin) i was wondering is their a way to populated the winner combo box once the team one and team two is selected in admin site ?

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  • django: search forms and redirect

    - by gruszczy
    After processing form from POST I should redirect, to prevent user from hitting back. However, I am using form to determine search query on a database, so I need to either pass params to the redirected site or the result of a search. Or maybe there is some other good practice, how to solve this problem? Maybe in this situation I am allowed not to redirect (nothing happens, if user performs search again).

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  • Django Foreign key queries

    - by Hulk
    In the following model: class header(models.Model): title = models.CharField(max_length = 255) created_by = models.CharField(max_length = 255) def __unicode__(self): return self.id() class criteria(models.Model): details = models.CharField(max_length = 255) headerid = models.ForeignKey(header) def __unicode__(self): return self.id() class options(models.Model): opt_details = models.CharField(max_length = 255) headerid = models.ForeignKey(header) def __unicode__(self): return self.id() If there is a row in the database for table header as Id=1, title=value-mart , createdby=CEO How do i query criteria and options tables to get all the values related to header table id=1 Also can some one please suggest a good link for queries examples, Thanks..

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  • Hidden features of PyCharm

    - by WooYek
    I know PyCharm is young IDE but id like to know if you guys have found some candy while using it. I know from experience that JetBrains IDE's are filled with candy and can't wait to find it all. Please list your tips, perhaps something you did not first expected to be there.

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  • How can I show figures separately in matplotlib?

    - by Federico Ramponi
    Say that I have two figures in matplotlib, with one plot per figure: import matplotlib.pyplot as plt f1 = plt.figure() plt.plot(range(0,10)) f2 = plt.figure() plt.plot(range(10,20)) Then I show both in one shot plt.show() Is there a way to show them separately, i.e. to show just f1? Or better: how can I manage the figures separately like in the following 'wishful' code (that doesn't work): f1 = plt.figure() f1.plot(range(0,10)) f1.show()

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  • Remove linebreak at specific position in textfile

    - by williamx
    I have a large textfile, which has linebreaks at column 80 due to console width. Many of the lines in the textfile are not 80 characters long, and are not affected by the linebreak. In pseudocode, this is what I want: Iterate through lines in file If line matches this regex pattern: ^(.{80})\n(.+) Replace this line with a new string consisting of match.group(1) and match.group(2). Just remove the linebreak from this line. If line doesn't match the regex, skip! Maybe I don't need regex to do this?

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  • Urllib's urlopen breaking on some sites (e.g. StackApps api): returns garbage results

    - by Edan Maor
    I'm using urllib2's urlopen function to try and get a JSON result from the StackOverflow api. The code I'm using: >>> import urllib2 >>> conn = urllib2.urlopen("http://api.stackoverflow.com/0.8/users/") >>> conn.readline() The result I'm getting: '\x1f\x8b\x08\x00\x00\x00\x00\x00\x04\x00\xed\xbd\x07`\x1cI\x96%&/m\xca{\x7fJ\... I'm fairly new to urllib, but this doesn't seem like the result I should be getting. I've tried it in other places and I get what I expect (the same as visiting the address with a browser gives me: a JSON object). Using urlopen on other sites (e.g. "http://google.com") works fine, and gives me actual html. I've also tried using urllib and it gives the same result. I'm pretty stuck, not even knowing where to look to solve this problem. Any ideas?

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  • Parsing srt subtitles

    - by Vojtech R.
    Hi, I want to parse srt subtitles: 1 00:00:12,815 --> 00:00:14,509 Chlapi, jak to jde s tema pracovníma svetlama?. 2 00:00:14,815 --> 00:00:16,498 Trochu je zesilujeme. 3 00:00:16,934 --> 00:00:17,814 Jo, sleduj. Every item into structure. With this regexs: A: RE_ITEM = re.compile(r'''(?P<index>\d+).(?P<start>\d{2}:\d{2}:\d{2},\d{3}) --> (?P<end>\d{2}:\d{2}:\d{2},\d{3}).(?P<text>.*?)''', re.DOTALL) B: RE_ITEM = re.compile(r'''(?P<index>\d+).(?P<start>\d{2}:\d{2}:\d{2},\d{3}) --> (?P<end>\d{2}:\d{2}:\d{2},\d{3}).(?P<text>.*)''', re.DOTALL) And this code: for i in Subtitles.RE_ITEM.finditer(text): result.append((i.group('index'), i.group('start'), i.group('end'), i.group('text'))) With code B I have only one item in array (because of greedy .*) and with code A I have empty 'text' because of no-greedy .*? How to cure this? Thanks

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  • Boto - How to delete a record set from route53 -Tried to delete resource record set but it was not found

    - by Tampa
    I am using the following to delete route53 records. I get no error messages. conn = Route53Connection(aws_access_key_id, aws_secret_access_key) changes = ResourceRecordSets(conn, zone_id) change = changes.add_change("DELETE",sub_domain, "A", 60,weight=weight,identifier=identifier) change.add_value(ip_old) changes.commit() all required fields are present and they match..weight, identifier, ttl=60 etc.\ e.g. test.com. A 111.111.111.111 60 1 id1 test.com. A 111.111.111.222 60 1 id2 I want to delete 111.111.111.222 and the record set. So, what is the proper way to delete a record set? For a record set, I will have multiple values that are distinguished by a unique identifier. When an ip address becomes in active I want to remove from route53. I am using a a poor mans load balancing. Here is the meta of the record want to delete. {'alias_dns_name': None, 'alias_hosted_zone_id': None, 'identifier': u'15754-1', 'name': u'hui.com.', 'resource_records': [u'103.4.xxx.xxx'], 'ttl': u'60', 'type': u'A', 'weight': u'1'} Traceback (most recent call last): File "/home/ubuntu/workspace/rtbopsConfig/classes/redis_ha.py", line 353, in <module> deleteRedisSubDomains(aws_access_key_id, aws_secret_access_key,platform=platform,sub_domain=sub_domain,redis_domain=redis_domain,zone_id=zone_id,ip_address=ip_address,weight=1,identifier=identifier) File "/home/ubuntu/workspace/rtbopsConfig/classes/redis_ha.py", line 341, in deleteRedisSubDomains changes.commit() File "/usr/local/lib/python2.7/dist-packages/boto-2.3.0-py2.7.egg/boto/route53/record.py", line 131, in commit return self.connection.change_rrsets(self.hosted_zone_id, self.to_xml()) File "/usr/local/lib/python2.7/dist-packages/boto-2.3.0-py2.7.egg/boto/route53/connection.py", line 291, in change_rrsets body) boto.route53.exception.DNSServerError: DNSServerError: 400 Bad Request <?xml version="1.0"?> <ErrorResponse xmlns="https://route53.amazonaws.com/doc/2011-05-05/"><Error><Type>Sender</Type><Code>InvalidChangeBatch</Code><Message>Tried to delete resource record set hui.com., type A, SetIdentifier 15754-1 but it was not found</Message></Error><RequestId>9972af89-cb69-11e1-803b-7bde5b9c457d</RequestId></ErrorResponse> Thanks

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  • Diophantine Equation [closed]

    - by ANIL
    In mathematics, a Diophantine equation (named for Diophantus of Alexandria, a third century Greek mathematician) is a polynomial equation where the variables can only take on integer values. Although you may not realize it, you have seen Diophantine equations before: one of the most famous Diophantine equations is: X^n+Y^n=Z^n We are not certain that McDonald's knows about Diophantine equations (actually we doubt that they do), but they use them! McDonald's sells Chicken McNuggets in packages of 6, 9 or 20 McNuggets. Thus, it is possible, for example, to buy exactly 15 McNuggets (with one package of 6 and a second package of 9), but it is not possible to buy exactly 16 nuggets, since no non- negative integer combination of 6's, 9's and 20's adds up to 16. To determine if it is possible to buy exactly n McNuggets, one has to solve a Diophantine equation: find non-negative integer values of a, b, and c, such that 6a + 9b + 20c = n. Problem 1 Show that it is possible to buy exactly 50, 51, 52, 53, 54, and 55 McNuggets, by finding solutions to the Diophantine equation. You can solve this in your head, using paper and pencil, or writing a program. However you chose to solve this problem, list the combinations of 6, 9 and 20 packs of McNuggets you need to buy in order to get each of the exact amounts. Given that it is possible to buy sets of 50, 51, 52, 53, 54 or 55 McNuggets by combinations of 6, 9 and 20 packs, show that it is possible to buy 56, 57,..., 65 McNuggets. In other words, show how, given solutions for 50-55, one can derive solutions for 56-65. Problem 2 Write an iterative program that finds the largest number of McNuggets that cannot be bought in exact quantity. Your program should print the answer in the following format (where the correct number is provided in place of n): "Largest number of McNuggets that cannot be bought in exact quantity: n" Hints: Hypothesize possible instances of numbers of McNuggets that cannot be purchased exactly, starting with 1 For each possible instance, called n, a. Test if there exists non-negative integers a, b, and c, such that 6a+9b+20c = n. (This can be done by looking at all feasible combinations of a, b, and c) b. If not, n cannot be bought in exact quantity, save n When you have found six consecutive values of n that in fact pass the test of having an exact solution, the last answer that was saved (not the last value of n that had a solution) is the correct answer, since you know by the theorem that any amount larger can also be bought in exact quantity

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